calculate equilibrium constant of new equation which is the inverse of original divided across by two

The Ksp of the salt AB at 25 °C is 1.8 x 10^-7 M^2. Option A is the correct answer.

The given information states that only 0.0450 mol of the salt AB is soluble in 1.00 L of water at 25 °C. Using this information, we can determine the molar solubility of AB, which is the amount of AB that dissolves per liter of water. In this case, the molar solubility is 0.0450 M.

The Ksp (solubility product constant) is a measure of the equilibrium between the dissolved ions and the undissolved solid in a saturated solution. For the dissociation of AB into A+ and B- ions, the equilibrium expression is [A+][B-]. Since the stoichiometry of the reaction is 1:1, the Ksp can be calculated as the square of the molar solubility: Ksp = (0.0450)^2 = 1.8 x 10^-7 M^2.

Therefore, the Ksp of the salt AB at 25 °C is 1.8 x 10^-7 M^2, which corresponds to option A).

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A "complaint" is the legal instrument used to charge a defendant in adult court, while a "petition" is the legal instrument used to charge a child in juvenile court.

If a defendant is found guilty in adult court, they are "convicted," whereas a child is "adjudicated delinquent" in juvenile court.

Federal courts handle disputes concerning federal law, whereas state courts hear cases involving state law. Because most crimes are violations of municipal or state law, state courts typically hear criminal cases.

All cases that are not particularly chosen for federal courts are heard by them. State courts interpret state laws in a manner similar to how federal courts do. It is up to each state to enact and interpret its own laws. This aids in maintaining state dominance.

Criminal cases are often pursued by state officials, but civil actions are conducted between plaintiffs, or private individuals or organizations, and this is the primary distinction between civil and criminal law.

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Answer:

D. The change in velocity divided by the time during which the change occurs.

Explanation: I took the quiz on Accelerate and it was correct

Answer:

D. The change in velocity divided by the time during which the change occurs.

Explanation:

When placed in a solution, HNO3 dissociates into H+ and NO3-. The compound HNO3 must be an acid.

Acids are substances that can donate protons (H+) to a solution. In the case of HNO3, it readily dissociates into H+ and NO3- ions when dissolved in water. The H+ ion is responsible for the acidic properties of HNO3. It can combine with water molecules to form hydronium ions (H3O+), contributing to the acidity of the solution. HNO3, also known as nitric acid, is a strong acid commonly used in various chemical processes and laboratory experiments.

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Answer:

B. One element changes into another.

Explanation:

We can see from the equation that uranium is changed to thorium and helium. Transmutation is the process by which one element is changed to another through radioactive decay, nuclear bombardment, or other similar processes.

Answer:b

Explanation:

Electron domains around a central atom determine molecular geometry. Variations include trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral, each with unique shapes and symmetry. Therefore,

a) Three electron domains: trigonal planar geometry - flat, triangular arrangement.

b) Four electron domains: tetrahedral geometry - pyramid with a triangular base.

c) Five electron domains: trigonal bipyramidal geometry - two connected pyramids.

d) Six electron domains: octahedral geometry - two square-based pyramids together.

a) For three electron domains, the characteristic electron-domain geometry is trigonal planar. This means that the electron domains are arranged in a flat, triangular shape around the central atom.

b) For four electron domains, the characteristic electron-domain geometry is tetrahedral. In this geometry, the electron domains are arranged in a three-dimensional shape, resembling a pyramid with a triangular base.

c) For five electron domains, the characteristic electron-domain geometry is trigonal bipyramidal. This means that the electron domains are arranged in a three-dimensional shape, resembling two pyramids connected at their bases.

d) For six electron domains, the characteristic electron-domain geometry is octahedral. In this geometry, the electron domains are arranged in a three-dimensional shape, resembling two square-based pyramids placed base-to-base.

These characteristic electron-domain geometries describe the overall arrangement of electron domains around a central atom, considering both bonding and non-bonding electron pairs.

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Complete question :

Describe the characteristic electron-domain geometry of each of the following numbers of electron domains about a central atom: a) 3, b) 4, c) 5, d) 6.

Answer:

an

Explanation:

It is AN because investigation starts with I ( i is a vowel). When there are vowels we use An.

Pls mark me brainliest!

Answer:

1d and 2d is the answer. Hope it helps

Given a heterogeneous mixture with 75% realgar, the percentage of realgar in the mixture is 75%. This calculation is based on the mass percentages of realgar and orpiment and the total arsenic content.

The percentage of realgar in the mixture is 75%.

Here's the solution:

Realgar has a mass percent of 70.029%.

Orpiment has a mass percent of 60.903%.

The mixture is 61.4% arsenic.

To calculate the percentage of realgar in the mixture, we can use the following equation:

percentage of realgar = (70.029 * 61.4) / 130.932

= 75.0

Therefore, the percentage of realgar in the mixture is 75%.

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Answer:

John Dalton

Explanation:

Answer:

John Dalton, an English chemist, inferred that atoms had certain characteristics. He began to propose an atomic the- ory and model for atoms. The main ideas of Dalton's theory are summarized in Figure 2. With only a few changes, Dalton's atomic theory is still accepted today.

Explanation:

Answer:

The composition of air this is because it vmade up of oxygen, nitrogen, Nobel gages and Carbon dioxide

The masses of the components are obtained as;

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

\(2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)\)

Now, the loss in  mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g -  8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

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The balanced chemical equation for this reaction is:
Ba(OH)2(aq) + (NH4)2SO4(aq) → BaSO4(s) + 2H2O(l) + 2NH3(g)

Based on the provided description, the balanced chemical equation for the reaction between aqueous barium hydroxide and aqueous ammonium sulfate is:
Ba(OH)2 (aq) + (NH4)2SO4 (aq) → BaSO4 (s) + 2H2O (l) + 2NH3 (g)
In this reaction, aqueous barium hydroxide (Ba(OH)2) and aqueous ammonium sulfate ((NH4)2SO4) react to produce solid barium sulfate (BaSO4), liquid water (H2O), and ammonia gas (NH3). The balanced chemical equation for this reaction is:
Ba(OH)2(aq) + (NH4)2SO4(aq) → BaSO4(s) + 2H2O(l) + 2NH3(g)

Ba(OH)2 (aq) + (NH4)2SO4 (aq) → BaSO4 (s) + 2H2O (l) + 2NH3 (g)
In this reaction, aqueous barium hydroxide (Ba(OH)2) and aqueous ammonium sulfate ((NH4)2SO4) react to produce solid barium sulfate (BaSO4), liquid water (H2O), and ammonia gas (NH3).

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Answer:

Iron(3+) sulfide

Explanation:

Answer:

• Abogado

• Administrador o conservacionista de campo

• Agrícola o agrónomo

• Apiculturísta

• Arquitecto

• Arquitecto ambiental

• Asistente de investigación

• Astrónomo

• Bioquímico

• Científico animal

• Científico avícola

• Científico de suelo

• Consejero vocacional

• Contador

• Criador animal

• Economista

• Entomólogo

• Epidemiólogo

• Farmacólogo

• Físico

• Fitogenetista

• Forestal

• Genetista

• Geoquímico

• Geofísico

• Horticultor

• Ingeniero

• Matemático (incluyendo estadístico)

• Meteorólogo

• Nutriólogo

• Profesor

• Químico

• Silviculturiasta (incluyendo forestalista)

• Terapeuta recreativo

• Topógrafo

• Trabajador social

• Urbanista (incluyendo geógrafo)

• Zoologísta

• Técnico científico de cualquiera de las siguientes disciplinas: ciencias agrícolas, astronomía, biología, química, ingeniería, silvicultura, geología, geofísica, meteorología o física

Explanation:

Answer:

 a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

Answer:

see explanation

Explanation:

Question

A(n) ACID is a compound that dissolves in water to produce hydrogen ions in solution. A(n) _BASE__ URhydroxide ions. Acids have a SOUR___ taste and bases have a BITTER____ taste. Both acids and bases conduct _ELECTRICITY___ and are _REACTIVE___. A pH of7 ____ is neutral. A pH of 6 is _ACIDIC__ and a pH of 14 is a BASIC__

Answer:

Percent Yield K₂O  =  59.2%

Explanation:

Before you can calculate the percent yield, you need to find the theoretical yield. This value is the amount of product produced using the balanced chemical equation and molar masses. However, the question does not specify which reactant is the limiting reagent. Therefore, you have to calculate the mass of the product starting from both values.

To find the theoretical yield, you need to (1) convert grams K/O₂ to moles K/O₂ (via molar masses), then (2) convert moles K/O₂ to moles K₂O (via mole-to-mole ratio from balanced equation coefficients), and then (3) convert moles K₂O to grams K₂O (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given values.

Molar Mass (K): 39.098 g/mol

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

Molar Mass (K₂O): 2(39.098 g/mol) + 15.998 g/mol

Molar Mass (K₂O): 94.194 g/mol

The balanced equation:

4 K + O₂ -----> 2 K₂O

8.92 g K          1 mole             2 moles K₂O         94.194 g
--------------  x  -----------------  x  --------------------  x  ----------------  =  10.7 g K₂O
                       39.098 g           4 moles K             1 mole

3.28 g O₂          1 mole           2 moles K₂O         94.194 g
----------------  x  ---------------  x  ---------------------  x  --------------  =  19.3 g K₂O
                         31.996 g           1 mole O₂              1 mole

Because potassium produces the smaller amount of product, it is the limiting reagent. This means that all the potassium reactant is used up before the oxygen gas runs out. So, the theoretical yield of potassium oxide is 10.7 grams.

Now, you can use the theoretical yield and actual yield to determine the percent yield.

                                   Actual Yield
Percent Yield  =  ------------------------------  x  100%
                               Theoretical Yield

                                 6.36 g K₂O
Percent Yield  =  ------------------------  x  100%
                                 10.7 g K₂O

Percent Yield  =  59.2%

The ΔHvap of ethyl acetate in the given conditions is 35.08 kJ/mol.

Enthalpy of vaporization:

To find the ΔHvap (enthalpy of vaporization) of ethyl acetate in kJ/mol, you can use the Clausius-Clapeyron equation, which is:

ln(P1/P2) = (ΔHvap/R) * (1/T2 - 1/T1)

Given:
Normal boiling point (T2) = 77°C = 350.15 K (converting to Kelvin by adding 273.15)
Vapor pressure at 20°C (P1) = 73 Torr
Temperature at P1 (T1) = 20°C = 293.15 K (converting to Kelvin)
P2 = 760 Torr (normal atmospheric pressure at boiling point)
R = 8.314 J/(mol*K) (universal gas constant)

First, plug the values into the equation:

ln(73/760) = (ΔHvap/8.314) * (1/350.15 - 1/293.15)

Now, solve for ΔHvap:

ΔHvap = 8.314 * (ln(73/760) / (1/350.15 - 1/293.15))

ΔHvap ≈ 35079 J/mol (rounded to the nearest whole number)

Finally, convert ΔHvap to kJ/mol:

ΔHvap ≈ 35.08 kJ/mol (rounded to two decimal places)

So, the ΔHvap of ethyl acetate is approximately 35.08 kJ/mol.

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Answer:

yes

Explanation:

because they will bond in order to gain more stability which is gained by forming a full electron shell

In biology, a system is a collection of organs (each made of multicellular tissues) that together perform a major function.

In biology, a system refers to a collection of organs that work together to perform a specific function or set of functions. Organs are structures made of multiple types of tissues that work together to perform a specific task.

These tasks can be related to maintaining homeostasis, such as the circulatory system which transports oxygen and nutrients throughout the body, or to a specific function, such as the reproductive system which is responsible for the production of offspring.

Therefore, Organs within a system are highly specialized and have specific functions, but they also work together in concert to achieve the overall function of the system. For example, the digestive system is made up of several organs including the mouth, esophagus, stomach, small intestine, and large intestine.

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At the At the equivalence point of a strong acid/weak base titration, the pH is greater than 7 but less than 14.

This is because the strong acid is completely neutralized by the weak base, leading to the formation of a salt and water. The salt produced may have an acidic, basic, or neutral pH depending on the nature of the anion and cation. However, since the weak base is not completely neutralized, some of it remains in the solution, leading to the formation of a basic solution with a pH greater than 7. The exact pH at the equivalence point can be determined by looking at the dissociation constant (Ka) of the weak base and the concentration of the salt and water content loaded. The pH at the equivalence point of a strong acid/weak base titration will be less than 7. This is because the resulting solution will contain a weak acid, which contributes to a slightly acidic pH. The exact pH value depends on the specific acid and base involved in the reaction.

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Answer:

She has Saturn and Jupiter in the wrong order.

Explanation:

The binding energy of the 31P nucleus is approximately 255.1 MeV. To calculate the binding energy of the 31P nucleus, we first need to calculate its total mass.

This can be done by adding up the masses of its constituent particles, which are 15 protons and 16 neutrons:
Total mass of 31P nucleus = (15 x 1.0072764666 amu) + (16 x 1.0086649158 amu) = 30.973761 amu. This is the same as the given mass of the 31P nucleus, so we know that it is a stable nucleus. However, we can also calculate the binding energy of the nucleus, which is the amount of energy required to break it apart into its constituent particles.

The binding energy can be calculated using Einstein's famous equation, E=mc^2, where E is the energy equivalent of mass, m is the mass difference between the nucleus and its constituent particles, and c is the speed of light. In other words, the binding energy is equal to the difference in mass between the nucleus and its constituent particles, multiplied by the speed of light squared.

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Explanation:

4.1 The Chemical Equation

LEARNING OBJECTIVES

Define chemical equation.

Identify the parts of a chemical equation.

A chemical reaction expresses a chemical change. For example, one chemical property of hydrogen is that it will react with oxygen to make water. We can write that as follows:

hydrogen reacts with oxygen to make water

We can represent this chemical change more succinctly as

hydrogen + oxygen → water

where the + sign means that the two substances interact chemically with each other and the → symbol implies that a chemical reaction takes place. But substances can also be represented by chemical formulas. Remembering that hydrogen and oxygen both exist as diatomic molecules, we can rewrite our chemical change as

H2 + O2 → H2O

This is an example of a chemical equation, which is a concise way of representing a chemical reaction. The initial substances are called reactants, and the final substances are called products.

Unfortunately, it is also an incomplete chemical equation. The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. If we count the number of hydrogen atoms in the reactants and products, we find two hydrogen atoms. But if we count the number of oxygen atoms in the reactants and products, we find that there are two oxygen atoms in the reactants but only one oxygen atom in the products.

What can we do? Can we change the subscripts in the formula for water so that it has two oxygen atoms in it? No; you cannot change the formulas of individual substances because the chemical formula for a given substance is characteristic of that substance. What you can do, however, is to change the number of molecules that react or are produced. We do this one element at a time, going from one side of the reaction to the other, changing the number of molecules of a substance until all elements have the same number of atoms on each side.

To accommodate the two oxygen atoms as reactants, let us assume that we have two water molecules as products:

H2 + O2 → 2H2O

The 2 in front of the formula for water is called a coefficient. Now there is the same number of oxygen atoms in the reactants as there are in the product. But in satisfying the need for the same number of oxygen atoms on both sides of the reaction, we have also changed the number of hydrogen atoms on the product side, so the number of hydrogen atoms is no longer equal. No problem—simply go back to the reactant side of the equation and add a coefficient in front of the H2. The coefficient that works is 2:

2H2 + O2 → 2H2O

There are now four hydrogen atoms in the reactants and also four atoms of hydrogen in the product. There are two oxygen atoms in the reactants and two atoms of oxygen in the product. The law of conservation of matter has been satisfied. When the reactants and products of a chemical equation have the same number of atoms of all elements present, we say that an equation is balanced. All proper chemical equations are balanced. If a substance does not have a coefficient written in front of it, it is assumed to be 1. Also, the convention is to use all whole numbers when balancing chemical equations. This sometimes makes us do a bit more “back and forth” work when balancing a chemical equation.

The relative atomic mass of the metal, M is 65 g/mol.

The mole ratio of the metal and the sulfate is calculated from the mass of the metal and the sulfate present in the compound.

Mass of the compound = 1.61 g

Mass of the metal, M, in the compound = 0.65 g

Mass of sulfate = mass of compound - the mass of metal

Mass of sulfate = 1.61 - 0.65

Mass of sulfate = 0.96 g

The formula of the compound is MSO₄

1 mole of the metal combines with 1 mole of sulfate

Moles of sulfate in the compound = mass / molar mass

Molar mass of sulfate = 96 g/mol

Moles of sulfate = 0.96 / 96

Moles of sulfate = 0.01 moles

Hence, the moles of metal in the compound is 0.01 moles

The relative atomic mass of the metal = 0.65 / 0.01

The relative atomic mass of the metal  = 65 g/mol

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Complete question:

Calculate the relative atomic mass of a metal M given that 0.65g of the metal forms 1.61g of sulfate of formula MSO₄. (S = 32, O = 16).

Adding Na2CO3 (sodium carbonate) to water with Cu (copper) can lead to increased pollution or contamination for several reasons:

1. Dissolution of Copper: When Na2CO3 is added to water, it can dissolve the copper present in the system. Copper can react with carbonate ions from Na2CO3 to form soluble copper carbonate compounds.

This process can result in increased copper concentration in the water, leading to pollution.

2. Increased Solubility: Sodium carbonate can increase the solubility of copper compounds in water. As more Na2CO3 is added, it can facilitate the dissolution of copper-containing minerals or compounds, allowing more copper ions to enter the water and potentially pollute it.

3. pH Effect: Sodium carbonate is a basic compound, and its addition to water can increase the pH of the solution.

Higher pH levels can enhance the release of copper ions from copper-containing materials or surfaces. These released copper ions can then contaminate the water, contributing to pollution.

4. Chemical Reactions: The presence of sodium carbonate can promote chemical reactions between copper and other substances present in the water.

These reactions can result in the formation of different copper compounds, some of which may be more soluble or toxic than others, further contributing to water pollution.

It's important to note that the extent of pollution or contamination depends on various factors such as the initial copper concentration, the amount of Na2CO3 added, the water chemistry, and the presence of other contaminants.

Proper waste management and control measures are crucial to prevent or minimize pollution when dealing with substances like copper and sodium carbonate.

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The three state of matter are solid, liquid and gas.  Water exists in all these states as ice, liquid water, water vapor respectively. The level of energy will varies from each state where, gaseous particles possess highest energy.

Every substances are able to exhibit  three states of matter namely gas, liquid and solid. However, some are more stable in any one state more probably by origin.

Substances in solid state have molecules closely packed without a space to move apart each other. Hence, the energy of molecules in solid state is very low.

In liquid state, molecules have some space to move apart and thus they can flow and have no definite shape like solids.  Whereas in gases, molecules are far apart and they are free enough to move and thus have highest energy.

Therefore, water molecules in its vapor state is having highest energy than its liquid state and ice.

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The plane strain fracture toughness of the polymer is determined using the formula: K_IC = σ√(πa) with given values of σ = 25 MPa and a = 1 mm. By plugging in the values, K_IC is found to be 25√(π * 1) ≈ 44.27 MPa√m.

To determine the plane strain fracture toughness (K_IC) of a polymer with internal flaws of 1 mm in length and a failure stress of 25 MPa, we can use the formula K_IC = σ√(πa), where σ is the applied stress (25 MPa) and a is the crack length (1 mm). Assuming the stress intensity factor (f) is 1, this simplifies the formula to K_IC = 25√(π * 1). Solving for K_IC, we obtain a value of approximately 44.27 MPa√m. This value represents the polymer's ability to resist crack propagation under plane strain conditions, which is a critical property for assessing its structural performance and durability.

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