The depth below the surface of the ocean where the total pressure is 1.105-108 Pa is 1.076 × 10⁶ meters.
Understanding the Depth and Density of Ocean waterUsing hydrostatic pressure equation, which relates pressure, density, and depth in a fluid:
P = P₀ + ρgh
Where:
P is the total pressure at depth h,
P₀ is the atmospheric pressure (assuming it is negligible),
ρ is the density of the fluid (ocean water),
g is the acceleration due to gravity.
Given:
ρ = 1.025 g/cm³ * (1000 kg/1 g) * (1 m/100 cm)³
= 1025 kg/m³
g = 9.8 m/s².
Now, we can rearrange the equation to solve for the depth h:
h = (P - P₀) / (ρg)
Substituting the given values:
h = (1.105 × 10⁸ Pa) / (1025 kg/m³ * 9.8 m/s²)
Calculating this expression:
h ≈ 1.105 × 10⁸ Pa / (1025 kg/m³ * 9.8 m/s²)
≈ 1.105 × 10⁸ m²/(kg·s²) / (1025 kg/m³ * 9.8 m/s²)
≈ 1.105 × 10⁸ m / (1025 * 9.8) m
≈ 1.076 × 10⁶ m
Therefore, the depth below the surface of the ocean where the total pressure is 1.105-108 Pa is approximately 1.076 × 10⁶ meters.
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"The greater the height of an object, the *BLANK* its gravitational potential energy."
please help thank u!
Answer:
the greater the height of an object the *greater* its gravitational potential energy
greater
ayuden ha resolver este ejercicio porfa
Answer:
un café y a seguir pensando porque no se la respuesta xd
if you are driving 110 km/h along a straight road and you look to the side for 2.0 s , how far do you travel during this inattentive period ? explain.
Explanation:
hope this helps, have a good one :D
Answer:
60.12m
Explanation:
Distance = Velocity x Time
To use this formula we must first convert 110km/h to m/s, which we can do by dividing the value by 3.6:
110/3.6 = 30.56m/s (2dp)
Velocity = 30.56m/s
Time = 2s
Distance = 30.56x2
Distance = 61.12m
You travel 60.12m during this inattentive period.
Hope this helped!
Which formula describes
acceleration?
O m/s
O m²
O m/s²
O s/m
Answer:
the answer is the formula of acceleration is m/s²
A generator produces 60 000 J of electric energy every minute. How many watts does it produce?
Answer:
\(1000\; {\rm W}\).
Explanation:
Joule is a unit for work, while watt is a unit for power- the rate at which work is being done. Divide work by time to find power.
By definition, one watt is equivalent to one joule-per-second. In other words: \(1\; {\rm W} = 1\; {\rm J \cdot s^{-1}}\). Note that the unit of time in this question is "minute", not second.
Apply unit conversion and ensure that the unit of time is "second":
\(\begin{aligned} 1\; \text{minute} &= 1\; \text{minute} \times \frac{60\; {\rm s}}{1\; \text{minute}} = 60\; {\rm s}\end{aligned}\).
The power of this generator would thus be:
\(\begin{aligned} \text{power} &= \frac{\text{work}}{\text{time}} \\ &= \frac{60\, 000\; {\rm J}}{60\; {\rm s}} \\ &= 1\, 000\; {\rm W} \end{aligned}\).
What is the mass of an object that requires 15 n to accelerate at a rate of 1. 5 m/s/s?.
Answer:
Explanation:
Force = mass*acceleration
15=mass*5
mass=3kg
BRAINLIEST!!!
YOU HAVE 5 MINUTES!!!!
Design an easy do-it-yourself compost bin that can be put (exnfe ffpao)
together at home. You can describe it, draw and label it, or both!
Include the following in your design:
• drawing or description of design
• materials used for the bin
• size of the bin
• substances used to fill it
• household items that can go in it
• how long it takes before it is ready
• how you use the compost
2)
Compost bin design: Add these household items to
your compost bin:
Compost is ready to use in this
much time:
Use your compost this way:
The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.
Substances Used to Fill It:
A mixture of "brown" and "green" organic materials such as leaves, grass clippings, fruit and vegetable scraps, coffee grounds, and shredded paper can be used to fill the bin.
Household Items That Can Go in It:
Most fruit and vegetable scraps, eggshells, tea bags, coffee grounds, yard waste such as grass clippings and leaves, and shredded paper can be added to the compost bin. Meat, dairy, and fatty foods should be avoided.
How Long It Takes Before It Is Ready:
The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.
How You Use the Compost:
The finished compost can be used as a nutrient-rich soil amendment for planting and gardening.
Compost Bin Design:
To add household items to your compost bin, simply add any of the following organic materials to the bin: fruit and vegetable scraps, coffee grounds and filters, tea bags, eggshells, yard waste such as leaves and grass clippings, and shredded paper.
Compost is ready to use in this much time:
The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.
Use your compost this way:
The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.
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Why do you think the Founders divided the process into two steps (impeachment and conviction)?
The impeachment process is described in Article I of the United States Constitution. Impeachment is the process by which senior political officials of the government can be removed from office, for reasons of treason, bribery or serious misconduct in the exercise of their functions.
The first step in this process is carried out by the House of Representatives, which is in charge of determining the origin of the impeachment, assessing the grounds and evidence that allow or not to prosecute the politician in question through a simple majority vote. Then, the Senate is in charge of the trial itself, determining the guilt or not of the official.
Ur pfp cute no cap
The Founders divided the process into two steps which are impeachment
and conviction to ensure the affected person has a fair judgement and
subsequent trial.
The house of representatives are in charge of the impeach process if an
office holder commits an offence in which impeachment can suffice. The
members of the house of representatives vote and the office holder is
impeached if the majority vote in that direction.
The Senate then takes over and the person faces trial and the judgement is
passed according to the available evidences.
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Two stars of masses M and 6M are separated by a distance D. Determine the distance (measured from M) to a point at which the net gravitational force on a third mass would be zero.
Answer:
0.29D
Explanation:
Given that
F = G M m / r2
F = GM(6m) / (D-r)2
G Mm/r2 = GM(6m) / (D-r)2
1/r2 = 6 / (D-r)2
r = D / (Ö6 + 1)
r = 0.29 D
See diagram in attached file
HELP PLS!!
What are open, closed and isolated systems?
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Energy from a battery powers an electromagnet Which of the
following energy transformations takes place?
a
magnetic to heat
b magnetic to electrical
С
electrical to magnetic
d light to sound
Answer: it’s actually C, electrical to magnetic
Explanation:
An electricit bulb of 80W is used for 8h per day to caluculate the units of energy consumed one day by the bulb!?
Power of electric tube light = 80W=0.08kW
Time used = 8 hour
Energy = Power x time taken =0.08×8=0.64kWh=0.64units.
The energy consumed per day = 0.64units
Answer:
Hence, a total of 0.8 electrical units of energy is consumed in one day by the bulb.
A sphere of radius 10cm carries a charge of 1uC.Calculate the electric field.
The electric field is 9 * 10^6 N/m
What is the electric field of a sphere?The electric field of a sphere can be calculated using Coulomb's law, which states that the magnitude of the electric field at a point in space is proportional to the electric charge at that point and inversely proportional to the square of the distance between the point and the charge.
For a uniformly charged sphere, the electric field inside the sphere is zero, and the electric field outside the sphere is given by:
E = kQ / r^2
where:
E is the electric field strength, measured in units of volts per meter (V/m)
k is the Coulomb constant, with a value of approximately 9 x 10^9 N·m^2/C^2
Q is the total charge of the sphere, measured in units of Coulombs (C)
r is the distance from the center of the sphere to the point where the electric field is being measured, measured in units of meters (m).
Given that;
E = Kq/r^2
E = 9 * 10^9 * 1 * 10^-6/(10 * 10^-2)^2
E = 9 * 10^6 N/m
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One of the motors in a long freight train has a power output of 160 kilowatts. If the current provided to the motors is 5.2 amps, what is the voltage across each motor?
If an object is placed at a distance of 12 cm from a convex lens of focal length 16 cm then calculate the image distance from the lens?
Answer:
-48cm
Explanation:
For a convex lens f is +ve and V is +ve
Using the formula 1/f=1/v+1/u
u=12cm and f=16cm
1/16-1/12=1/v
1/v=-1/48
v=-48cm
Is Saturn less dense than water which has a
density of 997 kg/m³? Find out by calculating the density of Saturn in kg/m³. The mass of Saturn is 5.68 x 1026 kg, and its radius is 5.6 x 107 m.
Density of Saturn:
The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.
To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).
Saturn's density can be computed using the following formula:
density equals mass divided by volume
Saturn's mass and volume may be computed given its mass and radius.
The volume of Saturn can be determined using the sphere volume formula:
volume =\((4/3) \pi (r^3)\)
where r is Saturn's radius.
Filling in the blanks:
volume = \((4/3) \pi (5.6 \times 107) m^3\)
8.27 x 1023 \(m^3\)volume
Saturn's mass is given as \(5.68 \times 10^{26} kg.\)
We can now compute Saturn's density:
density equals mass divided by volume
density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)
This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.
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How long will it take a person walking at 3.2 m/s to travel 16 m? *
Answer:
5.0 s
Explanation:
The equation for time is:
\(t = \frac{d}{s} \)
We plug in the given values into the equation
\(t=\frac{16\ m}{3.2\ m/s^}\)
\(t=5.0 \ s\)
what is the principle of simple machine?
Answer:
The principle of simple machine states that "if there is no friction in a simple machine, work output and work input are found equal in that machine.
Explanation:
Answer:
Usually, the term refers to the six classical simple machines which were defined by Renaissance scientists:
LeverWheel and axlePulleyInclined planeWedgescrewAlso, a simple machine uses a single applied force to do work against a single load force.
A sample of an unknown material appears to weigh 300N in air and 200N when immersed in alcohol of density 700kg/m^3 . What is the volume and density of the material
Answer:
the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.
Explanation:
To solve the problem, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
Let's first find the weight of the unknown material in air:
W_air = 300 N
Next, let's find the weight of the unknown material in alcohol:
W_alcohol = 200 N
We can find the buoyant force acting on the material by subtracting the weight in alcohol from the weight in air:
F_buoyant = W_air - W_alcohol = 300 N - 200 N = 100 N
According to Archimedes' principle, this buoyant force is equal to the weight of the alcohol displaced by the material:
F_buoyant = ρ_alcohol * V * g
where ρ_alcohol is the density of the alcohol, V is the volume of the material, and g is the acceleration due to gravity.
Substituting the values we know:
100 N = 700 kg/m^3 * V * 9.81 m/s^2
Solving for V:
V = 0.0145 m^3
Finally, we can find the density of the material by dividing its weight in air by its volume:
ρ_material = W_air / V = 300 N / 0.0145 m^3 = 20690.3 kg/m^3
Therefore, the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.
When putting the ball on the tee you want half of the golf ball to _________.
Question 1 options:
be above the club
be below the club
be in front of the club
be behind the club
Answer:
be in front of the club
Explanation:
The ball should be highest off the ground for a driver. The general recommendation is that the bottom of the golf ball on a tee should be level with the top of the driver; for long and mid-irons, push the tee into the ground so that only about a quarter-inch is above ground.
Customers take plates from the cart described above. As a result, the spring moves up to be compressed by
only 0.30 m. What is the change in elastic potential energy?
As the spring moves up to be compressed by only 0.30 m, the change in elastic potential energy will be 0.045 k J.
Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring.
Given,
The spring moves up to be compressed by a displacement = 0.30 m
And the elastic potential energy (U) for a spring can be calculated as:
\(U = \frac{1}{2} k x^{2}\)
Where k = spring constant and is measure in N/m
and x = change in length of the spring or the displacement of the spring
\(U = \frac{1}{2} k (0.30)^{2}\)
\(=\frac{1}{2} k (0.09)\)
\(=0.045 k\) J
Hence, the change in elastic potential energy is 0.045 k J.
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Ceres, the largest asteroid in the asteroid belt, has a mass of 9.23 x 10^20 kilograms and a radius of 474 kilometers.a. What is the magnitude of the acceleration due to gravity on the surface of Ceres? Include units in your answer.b. How much would an astronaut of mass 64.5 kilograms weigh on Ceres? Include units in your answer. All answers must be in 3 significant digits.
a)
The formula for calculating the magnitude of the acceleration due to gravity on the surface of Ceres is expressed as
g = GM/R^2
where
g is the magnitude of the acceleration due to gravity
M is the mass of Ceres
R is the radius of Ceres
G is the gravitational constant whose value is 6.67408 x 10^-11 Nm^2/kg^2
From the information given,
M = 9.23 x 10^20
R = 474 km
We would convert 474km to meters. Recall,
1 km = 1000m
474km = 474 x 1000 = 474000m
By substituting these values into the formula,
g = (6.67408 x 10^-11 x 9.23 x 10^20)/474000^2
g = 0.274 m/s^2
b) The formula for calculating weight is expressed as
W = mg
where
m = mass of object
g = acceleration due to gravity
From the information given,
m = 64.5 kg
g = 0.274 m/s^2
By substituting these values into the formula,
W = 64.5 x 0.274
W = 17.673 N
The weight of the astronaut is 17.673 N
Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. Assume free fall.
A)If the faster stone takes 11.0s to return to the ground, how long will it take the slower stone to return?
B)If the slower stone reaches a maximum height of , how high (in terms of ) will the faster stone go?
At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constant acceleration of 2.70 ms2. At the same instant, a truck, traveling with a constant speed of 14.7m/s , overtakes and passes the automobile.
How far beyond its starting point does the automobile overtake the truck?
How fast is the automobile traveling when it overtakes the truck?
In two stones thrown vertically upward problem, it will take the slower stone 3.67 seconds to return and faster to go 303.6 m high. In vehicles overtaking problem, automobile overtakes the truck 60.16m beyond, and is traveling at 14.7m/s when it overtakes the truck.
Two stones thrown vertically upward problem:
A) To solve this problem we need to use the equation of motion for free fall under gravity: h = -1/2 gt^2 + vt + h0, where h is the height of the stone, g is the acceleration due to gravity, t is the time, and h0 is the initial height. Since we know that the stone is thrown vertically upward from the ground, the initial height h0 is 0.
We also know that the stone is in free fall, so the velocity v is 0 and the final height h is also 0.
We can use this information to find the time it takes for the faster stone to return to the ground:
h = -1/2 gt^2 => 0 = -1/2 (9.8 m/s^2) t^2 => t = √(2h/g) => t = √(2*0/9.8) => t = 0
Now, we know that the faster stone takes 11.0s to return to the ground, and that the faster stone has 3 times the initial speed of the slower stone.
So, the slower stone will take (11.0s/3) = 3.67s to return to the ground.
B) If the slower stone reaches a maximum height of h, then the faster stone will go 3h high.
We can use the equation of motion for free fall under gravity to find the maximum height of the slower stone:
h = -1/2 gt^2 + vt + h0 => 0 = -1/2 gt^2 + 0 + 0 => h = -1/2 gt^2 => h = -1/2 (9.8 m/s^2) (3.67 s)^2 => h = -1/2 (9.8 m/s^2) (13.41 s^2) => h = -1/2 (9.8 m/s^2) (13.41 s^2) => h = -101.2 m
So, the faster stone will go 3*101.2 m = 303.6 m high.
Automobile and truck problem:
We can use the equations of motion for constant acceleration.
First, we need to find the time it takes for the automobile to overtake the truck. We can use the equation: v = u + at, where v is the final velocity, u is the initial velocity (0 m/s for the automobile), a is the acceleration (2.7 m/s^2) and t is the time.
So, v = 0 + 2.7t
Next, we can use the equation of motion for relative motion: v = v_t - v_a, where v_t is the velocity of the truck and v_a is the velocity of the automobile. So, v = 14.7 - 2.7t
We can now set the two equations equal to each other: 14.7 = 2.7t. So, t = 5.44 seconds.
To find the distance the automobile travels before overtaking the truck, we can use the equation: s = ut + (1/2)at^2. Plugging in the known values, s = (1/2) (2.7 m/s^2) (5.44 s)^2 = 60.16 m
To find the velocity of the automobile when it overtakes the truck, we can use the equation: v = u + at. Plugging in the known values, v = 0 + 2.7 (5.44 s) = 14.7 m/s
So, the automobile overtakes the truck 60.16m beyond its starting point and the automobile is traveling at 14.7m/s when it overtakes the truck.
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Forgetting takes place only in short-term memory. Please select the best answer from the choices provided T F
Answer:
false
Explanation:
Answer:
false
Explanation:
edge
Two small identical conducting spheres are placed with their centers 0.30m apart. One is given a charge of 12 X 10^-9C, the other a charge of -18 X 10^-9C.
a.Find the electrostatic force exerted on one sphere by the other.
b. The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached, where both spheres have the same charge.
a. 12*10^-5 N attractive is the force exerted on one sphere by the other. b. 9*10^-7 N repulsive is the force between the two after equilibrium is reached, where both spheres have the same charge.
The force between two charged particles is calculated as
F= q1*q2*K/r^2 .......................(i)
where q1 is the charge of the first body, q2 is the charge of the second body and r is the distance between them Here K is a constant that has the values of 9*10^9.
So for the finding a.
12 X 10^-9* -18 X 10^-9*9*10^9/(o.3)^2 ............ From ( i)
9*12*18*10^-9/0.09 which results to 12*10^-5 N
And Similarly for b we need to find the total average charge of both bodies will be.
(q1+q2)/2 ......(ii) (12 - 18)/2 => -6/2 = -3 nC .................( from ii)
and using (i) (3X10^-9)^2*9*10^9/ (o.3)^2 ...... (As q1 =q2)
which results in 9*10^-7 N
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.
Calculate the distance travelled by car.
Answer:
62.5m
Explanation:
Given parameters:
Initial velocity = 0m/s
Time = 5s
Acceleration = 5m/s²
Unknown:
Distance traveled = ?
Solution:
To solve this problem, we use the motion equation given below:
S = ut + \(\frac{1}{2}\) at²
S is the distance traveled
u is the initial velocity
a is the acceleration
t is the time taken
Now, insert the parameters and solve;
S =( 0 x 5) +( \(\frac{1}{2}\) x 5 x 5²) = 62.5m
PLEASE HELP SOON! For the circuit below , the battery has 4.2V calculate power giving and power receiving
For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.
Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,
R = 55*30/(55+30)
R = 19.4 Ω
Power given to the circuit is,
P = V²/R = 4.2/19.4 = 0.9 W
Receiving power taken from 55Ω resistor
P = V²/R = 4.2/55 = 0.07 W
Receiving power taken from 30Ω resistor
P = V²/R = 4.2/30 = 0.14 W
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What is the resistance of five 10Ohm resistors in parellel?
Answer:
The equivalent resistance is 2 ohms.
Explanation:
let the first resistance = R₁ = 10 ohm
let the second resistance = R₂ = 10 ohm
let the third resistance = R₃ = 10 ohm
let the fourth resistance = R₄ = 10 ohm
let the fifth resistance = R₃ = 10 ohm
The equivalent resistance is calculated as;
\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} \\\\\frac{1}{R_T} = \frac{(R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)}{R_1R_2R_3R_4R_5} \\\\R_T = \frac{R_1R_2R_3R_4R_5}{(R_2R_3R_4R_5)+(R_1R_3R_4R_5)+(R_1R_2R_4R_5) +(R_1R_2R_3R_5)+(R_1R_2R_3R_4)} \\\\R_T = \frac{(10^5)}{(10^4)+(10^4)+(10^4)+(10^4)+(10^4)} \\\\R_T = \frac{10^5}{5(10^4)} \\\\R_T = \frac{10}{5} \\\\R_T = 2 \ ohms\)
Therefore, the equivalent resistance is 2 ohms.