Calculate the molar mass of each of the following:
(b) BaF₂

The option that isn't a reason why the actual yield is less than theoretical yield is B. conservation of mass.

It should be noted that the formula for the percent yield is given as:

= Actual yield / Theoretical Yield × 100

Actual yield can be less than theoretical yield due to the presence of impure reactants ,competing side reactions, and loss of product during purification.

In conclusion, the correct option is B.

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Ammonium ion and phosphate ion can form an ionic compound. The chemical formula of ammonium ion is NH4+ and that of phosphate ion is PO43-. Since both these ions are polyatomic ions, they contain a group of atoms bonded covalently. Ionic compounds are formed through the transfer of electrons from one atom to another.

The formula unit of the ionic compound formed between ammonium ion and phosphate ion can be determined using the criss-cross method.The criss-cross method involves writing the charges of the two ions in such a way that they balance each other out. For example, the charge of ammonium ion is +1 and the charge of phosphate ion is -3. In order to balance the charges, three ammonium ions combine with two phosphate ions to form the compound. The criss-cross method can be written as:NH4+ PO43-3 NH4+PO43-The molecular formula for an ionic compound cannot be determined since there are no molecules present in an ionic compound. Instead, ionic compounds are made up of formula units. The formula unit is the smallest repeating unit of the compound and it represents the empirical formula. The empirical formula represents the relative ratios of the atoms present in the compound.

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Answer:

A) Scandium

B)

C) Gallium

D

The acid mostly dissociates when dissolves in water.

option C.

A strong acid is an acid that is completely dissociated in an aqueous solution such as water when it is dissolved in it.  Strong acid is a chemical species with a high capacity to lose a proton, H+.

In other words, a strong acid is one which is virtually 100% ionized in solution.

Thus, when a compound is described as a strong acid it means that: the acid mostly dissociates when dissolves in water.

So option C is the correct answer as it explains the meaning of a strong acid.

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Answer: 0.37 M

Explanation:

\(M_{A}V_{A}=M_{B}V_{B}\\(20.4)(0.650)=M_{B}(36)\\M_{B}=\frac{(20.4)(0.650)}{36}=\boxed{0.37 \text{ M}}\)

Answer:

All elements, and compounds, all matter in point of fact, are composed of atoms. In a compound, there are 2 or more different types of atoms present that are chemically bound. In an element, there is only the one type of atom.

Explanation:

Answer:

84%

Explanation:

Fossil Fuels Supply 84 Percent Of Worlds Electricity

The question is missing. Here is the complete question.

One light beam has wavelength, \(\lambda_{1}\), and frequency, f₁. Another light beam has wavelength, \(\lambda_{2}\), and frequency, f₂. Write a proportion that shows how the ratio of the wavelengths of these two light beams is related to the ratio of the frequencies.

Answer: \(\frac{f_{1}}{f_{2}} =\frac{\lambda_{2}}{\lambda_{1}}\)

Explanation: In vacuum, eletromagnetic waves travels at a constant speed called "speed of light", whose symbol is [c] and magnitude is 3x10⁸m/s.

Speed of light, frequency and wavelength are related by the formula:

\(c=\lambda.f\)

So, if one light beam has wavelength and frequency, \(\lambda_{1}\) and f₁, respectively, the second beam has wavelength \(\lambda_{2}\) and frequency f₂ and both travel at speed of light:

\(\lambda_{1}f_{1}=\lambda_{2}f_{2}\)

\(\frac{f_{1}}{f_{2}}=\frac{\lambda_{2}}{\lambda_{1}}\)

Then, the ratio that shows the relation between frequencies and wavelengths of these light beams is \(\frac{f_{1}}{f_{2}}=\frac{\lambda_{2}}{\lambda_{1}}\)

Out of all the given subshells it is 2d shell which doesn't have real existence as an atom.

(i) If d-subshell l=2, the values of sof l in the second shell (jn=2) are 0 and 1. Consequently, the third shell cannot contain any d-subshell. As a result, we can conclude that the second subshell does not actually exist as atom.

(ii) In the third shell (n=3), the values of l are 0, 1, and 2 in the case of the f-subshell, where l=3. There is no actual existence of 3f-subhsell because there cannot be any f-subshell in this shell.

(iii) In the fourth shell (n=4), where l=4, the values of l are 0, 1, 2, and 3. There is no actual 4g subshell because there cannot be any g sub shell in this shell.

(iv) The fifth shell (n=5) has l values of 0, 1, 2, 3, and 4, which proves that the d-sub shell is actually present

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Answer:

both are a number group of 12

Explanation:

dozen=12

Answer:

A hydrogen bond is the electromagnetic attraction created between a partially positively charged hydrogen atom attached to a highly electronegative atom and another nearby electronegative atom. A hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond.

Explanation:

Answer:

the third

Explanation:

when you remove the first the nucleur attraction becomes greater pulling the other valence electron closer thus the more you remove the harder it gets because the pull from the nucleus increases.

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Option C is correct option.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

The elements that belongs to Group 2A metals are alkaline earth metals, their electronic configurations is [noble gas ]ns² so, it is easy to remove first electron and then second electron but it is very difficult to remove the third electron because after removing two electron we get noble gas configuration and effective nuclear charge also increases after removal of second electron.

Therefore, the correct option is option C.

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Answer:. that contains the same number of entities as there are atoms in 12 g of carbon-12. ... the same as the mass of one mole of the compound in grams. • Skill 3-1 Calculate the ... Molar mass has units of grams per mole (g/mol). Concept 3. ... of moles to mass: •We can do the reverse with 1/M, and convert any mass in grams to.

Explanation:

The number of atoms in a mole of boron and carbon is required.

A mole of carbon and a mole of boron have the same number of atoms.

The unit of amount of substance is called mole.

\(1\ \text{mole}=6.022\times 10^{23}\ \text{atoms, molecules, ions, or electrons}\)

So, 1 mole of any element, whether it be carbon or boron has the same number of atoms which is \(6.022\times 10^{23}\).

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We should take into account what happens when NaOH is added to a reference solution. When a base (NaOH) is added to an acidic solution (reference solution), it will neutralize the acidic solution. So, if 6 M NaOH is used instead of 6 M NH when testing the reference solution, it will also neutralize the acidic solution.

When NaOH is added to the reference solution, it will turn the solution yellow. Because a yellow color would be observed if NaOH is used to test the reference solution, it is not an acceptable substitute for NH3. The presence of NaOH indicates the absence of NH3.The balanced equation for the reaction between NH3 and HCl is:NH3 + HCl → NH4ClThe balanced equation for the reaction between NaOH and HCl is:NaOH + HCl → NaCl + H2OTherefore, since 6 M NaOH is a strong base and 6 M HCl is a strong acid, the reaction will be vigorous, and lots of heat will be generated. Since NH3 is not present, NaOH will react with HCl in the reference solution and neutralize it (yellow color). This indicates the absence of NH3, which is not the goal of the experiment. As a result, NaOH is not an acceptable substitute for NH3 in this situation.

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MnO4- acts as an oxidizing agent, whereas SO2 acts as a reducing agent.

An oxidizing agent is a chemical species that causes oxidation in another substance by receiving electrons from it. To put it another way, it is a chemical that makes it easier for electrons to move from the object being oxidized to itself.

When an oxidation occurs, electrons are lost or the oxidation state is increased; when a reduction occurs, electrons are gained or the oxidation state is decreased.

In this equation, MnO4- + SO2 + H2O → Mn2+ + SO42- + 2H+

Because it causes SO2 to undergo oxidation (i.e., lose electrons) and goes through reduction itself, MnO4- is the oxidizing agent in this equation (i.e., gains electrons).

Due of its ability to both reduce MnO4- and oxidize itself, SO2 is the reducing agent.

Mn2+ is not an oxidizing agent because it is the end result of the reduction of MnO4-.

As SO42- is a byproduct of SO2 oxidation, it cannot act as a reducing agent.

MnO4- is therefore the oxidizing agent, whereas SO2 is the reducing agent.

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A primary explosive is a sensitive explosive that almost always explodes with a single ignition from a primary heat source of sufficient intensity, such as a spark, flame, impact, or other primary heat source.

Primary explosives can explode as a result of a spark or a relatively weak mechanical stress. They start the primary explosive when used as blasting caps (detonators). Additionally, they are loaded with friction-mixed materials and other ingredients in percussion caps.

A highly brisant starting explosive with a high triggering velocity is required. Mercury fulminate, lead azide, lead trinitroresorcinate, silver azide, diazodinitrophenol, and tetrazene, which is a primer additive, are the most significant primary explosives.

Only if they have already been pressed into capsules must initiation charges be transported.

Therefore, A primary explosive is a sensitive explosive that almost always explodes with a single ignition from a primary heat source of sufficient intensity, such as a spark, flame, impact, or other primary heat source.

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Answer:

A Chemical reaction involves changes in energy in the form of absorbtion and release of heat due to the formation and breakdown of chemical bonds. A chemical reaction is categoried as endothermic reaction in which heat energy is take in or absorbed and exothermic reaction in which energy is released.

A model can be created by following below details:

So, the decrease in temperature shows it is an endothermic reaction in which heat energy is absorbed.

Energy change in the reaction has been stored in the products and the reactants. The change in the reactant to product results in a change in energy.

According to the law of conservation of energy, energy can neither be created nor destroyed in a chemical reaction. The chemical reaction has been resulted in the energy change by the endothermic and exothermic reactions.

The project model for energy change can be:

Reactant + Energy = Products.

The ice cube has been placed in a beaker. It has been consisted of the stored potential energy. WIth the application of heat energy there has been the conversion of ice cubes to the water, and the potential energy of the ice cubes has been converted to the kinetic energy of the moving liquid particles.

Reactant = Product + Energy

The model has consisted of matching the light with a matchstick. The chemical energy of the stored matchstick has been converted to light and heat energy.

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The volume of 6.25 × 10⁻⁴ molar ferroin solution needed to prepare   10 ml of 2.50 × 10 ⁻⁵ molar solution with deionized water is 0.4 ml.

Molarity is a term used to express the concentration of a solution. It is the ratio of number of moles of solute to the volume of solution in liters. The number of moles of the solute is thus the product of its molarity and volume in liters.

Let V1 and M1 be the volume and molarity of the stoke solution and V2 and M2 be the volume and molarity of the solution to be prepared from its. Then,

M1 V1 = M2 V2.

Given the molarity and volume of the solution to be prepared is  10 ml and 2.50 × 10 ⁻⁵ m respectively. The molarity of stoke solution is 6.25 × 10⁻⁴ molar. Thus, the volume of stoke solution needed to be added is calculated as follows:

volume = molarity of solution to be prepared × volume / molarity of stoke solution

            =  (2.50 × 10 ⁻⁵ m × 10 ml ) /6.25 × 10⁻⁴

            = 0.4 ml

Therefore, the volume of ferroin solution  needed to be added is 0.4 ml.

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Answer:

The 500kg boulder

Explanation:

An ionic equation is a chemical equation in which the electrolytes in aqueous solution are described as dissociated ions.

3FeSO4(aq) + 2K3PO4(aq) = Fe3(PO4)2(s) + 3K2SO4(aq)

ionic equation : 3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

net ionic equation: 3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)  

K2CO3(aq) + CdI2(aq) = 2KI(aq) + CdCO3(s)

net ionic equation for K2CO3(aq) + CdI2(aq) = 2KI(aq) + CdCO3(s).

2HNO3 + CaCO3 = Ca(NO3)2 + H2O + CO2

ionic equation :  CaCO3(s) + 2H+(aq) → Ca2+(aq) + CO2(g) + H2O()

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The temperature at which 37 g of both copper(II) sulfate and potassium chloride dissolve in 100 g of water is approximately 38 ⁰C.

The solubility of a substance is its ability to be dissolved in water.

The solubility of 37 g of Copper (II) sulfate is determined from the solubility curve of Copper (II) sulfate.

The solubility of 37 g of potassium chloride is determined from the solubility of potassium chloride.

Thus, from the solubility charts, the temperature at which 37 g of both copper(II) sulfate and potassium chloride dissolve in 100 g of water is approximately 38 ⁰C.

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Hydrogen chloride (HCl) and sodium bicarbonate (NaHCO3) are the reactants. The substances produced as a result of this reaction are CO2(g), H2O(l), and NaCl(aq).

The reactants in the following equation:

HCl (a q) + NaHCO3(a q) → CO2(g) + H2O(l) + Na C l (aq) are hydrogen chloride (HC l) and sodium bicarbonate (NaHCO3).

Explanation:

A reactant is a substance that undergoes change during a chemical reaction. A reaction equation includes the symbols and formulas of reactants and products, along with the physical states of the substances, as they appear before and after the reaction.

The chemical reaction in this question is: HC l(a q) + NaHCO3(a q) → CO2(g) + H2O(l) + Na Cl (a q)In this equation, the reactants are H Cl (a q) and NaHCO3(a q), which are in an aqueous state.

Therefore, hydrogen chloride (H Cl) and sodium bicarbonate (NaHCO3) are the reactants. The substances produced as a result of this reaction are CO2(g), H2O(l), and Na Cl (a q).

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Tub and tile scrub, pH = 11.6: basic , Blood, pH = 7.38: slightly basic/neutral

Vinegar, pH = 2.8: acidic

Chemically speaking, the pH scale measures the concentration of hydrogen ions in a solution. A solution with a pH of 7 is considered neutral, while a pH less than 7 is considered acidic, and a pH greater than 7 is considered basic (or alkaline). Based on this scale, the solutions can be identified as follows:

Maple syrup, pH = 4.7: slightly acidic/neutral

Acidic solutions have a pH of less than 7.0. They are characterized by the presence of hydrogen ions (H+) in solution. Examples of acidic solutions include vinegar, which has a pH of 2.8, and lemon juice, which has a pH of 2.3.

Basic solutions have a pH greater than 7.0. They are characterized by the presence of hydroxide ions (OH-) in solution. Examples of basic solutions include household ammonia, which has a pH of 11.0, and baking soda, which has a pH of 8.3.

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Explanation:

V1/T1 = V2/T2      T  must be in Kelvin

12.78 / (-50 + 273.15)  =  V2 / ( 28+ 273.15)

V2 = 17.25 L

The pH of a 7.23 x 10⁻⁷ M solution of sodium hydroxide is approximately 7.86.

To find the pH of a solution of, we need to use the following equation pH = 14 - where is equal to -log[OH⁻], and [OH⁻] is the concentration of hydroxide ions in the solution.

Since is a strong base, it completely dissociates in water to form Na⁺ and OH⁻ ions. Therefore, the concentration of hydroxide ions in a 7.23 x 10⁻⁷ M solution of is: [OH⁻] = 7.23 x 10⁻⁷ M

Now we can calculate the pOH

pOH = -log([OH⁻])

= -log(7.23 x 10⁻⁷)

= 6.14

Finally, we can use the equation above to find the pH,

pH = 14 - pOH

= 14 - 6.14

= 7.86

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The equilibrium concentration (in M to three decimal places) of HBr for the given reaction is 0.025 M at 25 °C.

Let x be the equilibrium concentration of HBr. Then, the equilibrium concentrations of \(H_2\) and \(Br_2\) will also be x, since the stoichiometry of the reaction is 1:1:2.

Using the equilibrium constant expression for this reaction:

\(K = [HBr]^2/ ([H_2] [Br_2])\)

Substituting the initial concentrations and the equilibrium concentrations in terms of x:

0.000351 = (2x)² / (0.5 - x)²

Solving for x:

0.000351 (0.5 - x)² = 4x²

0.0001755 - 0.000702 x + 0.000351 x² = 4x²

3.99965 x² + 0.000351 x - 0.0001755 = 0

Using the quadratic formula:

x = (-0.000351 ± √(0.000351² + 4(3.99965)(0.0001755) / (2(3.99965))

x ≈ 0.025 M (rounded to three decimal places)

Therefore, the equilibrium concentration of HBr is 0.025 M.

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the answer is Te because O is oxygen.

Answer:

O

Explanation:

this is because it is oxygen

15.0 ml of .110 m HI (aq) is completely neutralized with 11.2 ml of RBOH (aq). 0.1473 M RBOH will be required to neutralize 0.110 M HI.

Let's understand this in detail:

To determine the concentration of RBOH, we need to use stoichiometry.

1. Neutralization is a type of reaction between an acid and a base, which leads to the production of water and salt. In this reaction, we have an acid and a base; thus, the product will be water and salt.

Moles of HI were present in 15.0 mL of 0.110 M HI:

Moles of HI = Concentration of HI × Volume of HI= 0.110 mol/L × 15.0 mL × 1 L/1000 mL= 0.00165 mol HI

Moles of RBOH reacted with HI in the reaction:

According to the balanced chemical reaction, HI and RBOH react in a 1:1 ratio to produce H2O and RBOH.

0.00165 mol HI reacted, so 0.00165 mol of RBOH must have reacted also.

The concentration of RBOH:

Now that we know the moles of RBOH that reacted with HI, we can determine its concentration: Moles of RBOH = 0.00165 mol

The volume of RBOH = 11.2 mL = 0.0112 L

The concentration of RBOH= moles/volume= 0.00165 mol / 0.0112 L= 0.1473 M RBOH is the answer.

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Answer: A. Catalyst

Explanation:

An catalyst is used to speed up the rate of the reaction. In a biochemical reaction an enzyme is the only catalyst which is exposed to the reactant forming the enzyme substrate or reactant complex thus forming the product. The catalyst increases the product formation from the reactant by increasing the pace of the reaction. Catalyst does not get consumed in the reaction. It can be used repeatedly for multiple reactions.