Answer:
4.90 moles of \(Mg(ClO_4)_2\) will produce (9.8) moles of \(Cl^{-}\) ,
(4.90) moles of \(Mg^{2+}\) and
(39.2) moles of \(O^{2-}\)
Explanation:
From the question we are told that
The number of moles of is \(n = 4.90 \ mols\)
The formation reaction of \(Mg(ClO_4)_2\) is
\(Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2\)
From the reaction we see that
1 mole of \(Mg(ClO_4)_2\) is formed by 2 moles of \(Cl^{-}\) 1 mole of \(Mg^{2+}\) and 4 \(O^{2-}\)
This implies that
4.90 moles of \(Mg(ClO_4)_2\) will produce (2 * 4.90) moles of \(Cl^{-}\) ,
(1 * 4.90) moles of \(Mg^{2+}\) and
(8 * 4.90) moles of \(O^{2-}\)
So
4.90 moles of \(Mg(ClO_4)_2\) will produce (9.8) moles of \(Cl^{-}\) ,
(4.90) moles of \(Mg^{2+}\) and
(39.2) moles of \(O^{2-}\)
Answer:
- \(n_{Mg}=4.90molMg\)
- \(n_{Cl}=9.6molCl\)
- \(n_{O}=38.4molO\)
Explanation:
Hello,
In this case, for the given 4.90 moles of magnesium perchlorate, we can compute the moles of each atom by identifying the subscript each atom has in the molecule as shown below:
- Moles of magnesium atoms: here, one mole of magnesium perchlorate has only one mole of magnesium atom (subscript is one), this the moles of magnesium atoms are also 4.90 moles.
- Moles of chlorine atoms: here, one mole of magnesium perchlorate has two moles of chlorine atoms as it has a two out of the parenthesis enclosing the perchlorate anion, thus, we have:
\(n_{Cl}=4.80molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2} =9.6molCl\)
- Moles of oxygen atoms: here, one mole of magnesium perchlorate has eight moles of oxygen atoms as it has a four in the oxygen subscript and a two out of the parenthesis enclosing the perchlorate anion, thus, we have:
\(n_{O}=4.80molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2} =38.4molO\)
Best regards.
technetium -99m has a half life of 6 hours
80mg of technetium was prepared
How many mg will remain after 1.5 days?
After 1.5 days, only 1.25 mg of technetium-99m will remain out of the original 80 mg that was prepared.
Technetium-99m (99mTc) is a radioactive isotope that is used in medical imaging.
It has a half-life of 6 hours, which means that after 6 hours, half of the original amount of technetium-99m will have decayed.
Therefore, after another 6 hours (12 hours total), half of the remaining technetium-99m will have decayed, leaving only 25% of the original amount.
After another 6 hours (18 hours total), half of the remaining technetium-99m will have decayed again, leaving only 12.5% of the original amount.
After 1.5 days, which is 36 hours total, we can use the formula for radioactive decay to calculate how much technetium-99m will remain: amount remaining = original amount x \((1/2)^{t/h}\) where t is the time elapsed and h is the half-life.
Plugging in the given values, we get: amount remaining = 80 mg x (1/2)^(36/6) amount remaining = 80 mg x \((1/2)^{6}\) amount remaining = 80 mg x 0.015625 amount remaining = 1.25 mg
Therefore, after 1.5 days, only 1.25 mg of technetium-99m will remain out of the original 80 mg that was prepared.
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If 22.4 mL of 0.25 M sodium hydroxide are required
neutralize 15.0 mL of a hydroiodic acid solution, how
many grams of hydrogen iodide were dissolved in the
solution?
According to the concept of molar concentration,0.715 g of hydrogen iodide are dissolved in the solution.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.
Using the formula of M₁V₁=M₂V₂ molarity of HI is determined,that is ,M₂=0.25×22.4/15=0.373 M.
For determining the mass is determined by using the formula,mass=0.373×127.911×0.015=0.715 g
Thus, 0.715 g of hydrogen iodide are required for making the solution.
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Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.
How many moles of tin, Sn, are in 2500 atoms of tin?
4.2 × 10⁻²¹ moles Sn
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:Step 1: Define
2500 atoms Sn
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
Set up: \(\displaystyle 2500 \ atoms \ Sn (\frac{1 \ mol \ Sn}{6.022 \cdot 10^{23} \ atoms \ Sn})\)Multiply: \(\displaystyle 4.15144 \cdot 10^{-21} \ moles \ Sn\)Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
4.15144 × 10⁻²¹ moles Sn ≈ 4.2 × 10⁻²¹ moles Sn
Hexane burns according to the following equation:
2C6H14(g) + 19O2(g) ----------> 12CO2(g)+14H2O(g)
What volume of CO2 forms when 8.00 L of hexane burn, assuming the two volumes are measured under the same conditions? What volume of oxygen will be needed?
The volume of carbon dioxide gas forms is equal to 48 L and The volume of oxygen gas needed is 76 L.
What is the combustion reaction?A combustion reaction can be explained as a reaction that forms fire and takes place at a high temperature. Combustion Reaction is the combustion of hydrocarbon reacts with oxygen gas to give carbon dioxide and water molecules.
Given the chemical reaction of the combustion reaction of hexane:
\(2C_6H_{14}(g) + 19O_2(g) \longrightarrow 12CO_2(g)+14H_2O(g)\)
Given the volume of hexane = 8.00 L
The number of moles of hexane = 8/22.4 = 0.357 mol
The moles of oxygen required to react with 0.357 mol of Hexane is equal to :
= (19/2) × 0.357
= 3.39 mol
The volume of oxygen gas = 3.39 × 22.4 = 76 L
The moles of CO₂ produced from 0.357 mol of Hexane is equal to :
= (12/2) × 0.357
= 2.14 mol
The volume of carbon dioxide gas forms = 2.14 × 22.4 = 48 L
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How many grams are in 23 moles of Magnesium nitride?
Answer:2523.75 g
Explanation:
(25 mols)* (100.95g/1 mol)= 2523.75g magnesium nitride
- molar mass of magnesium nitride is 100.95 g/mol
2. A company makes mixtures of acetic acid and water such that the acetic acid is 15% of the total mass (weight) of the mixture. Let A be an unspecified number of grams of acetic acid, which can vary and let W be the corresponding number of grams of water in this type of mixture.
An equation that relates A and W is A = (3/17) W.
The equation that relates A and W, considering the desired 15% acetic acid concentration, is 3W = 2.55M.
The equation A = (3/17)W represents the relationship between the mass of acetic acid (A) and the mass of water (W) in the mixture. It states that the mass of acetic acid is equal to three seventeenths (3/17) of the mass of water.
Since the company wants the acetic acid to be 15% of the total mass of the mixture, we can set up another equation to represent this requirement. Let M be the total mass of the mixture. The mass of acetic acid (A) is 15% of the total mass, so we have A = 0.15M.
Now we can substitute A in terms of W from the first equation into the second equation: (3/17)W = 0.15M. We can simplify this equation by multiplying both sides by 17 to get 3W = 2.55M.
This equation allows the company to calculate the mass of water (W) required for a given mass of acetic acid (A) to maintain the desired concentration in the mixture.
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The odor of fish is due primarily to amines, especially methylamine
(CH3NH2). Fish is often served with a wedge of
lemon, which contains citric acid. The amine and the acid
react forming a product with no odor, thereby making
the less-than-fresh fish more appetizing. Calculate the equilibrium constant for the reaction of citric acid with methylamine, if only the first
proton of the citric acid (Ka1) is important in the neutralization
reaction.
The unpleasant odour of fish is due to the presence of amines, particularly methylamine. To eliminate this odour, fish is often served with lemon wedges, which contain citric acid. Citric acid can react with methylamine to form a product with no odour, making the fish more appetizing.
As per the question given,
The reaction between citric acid and methylamine can be written as follows:
CH3NH2 + H3C6H5O7 ⇌ CH3NH3+C6H5O7-
The equilibrium constant for this reaction can be expressed as:
K = [CH3NH3+][C6H5O7-] / [CH3NH2][H3C6H5O7]
Since only the first proton of the citric acid is important in the neutralization reaction, we can assume that citric acid behaves as a monoprotic acid, and its dissociation constant (Ka1) is given as:
Ka1 = [H+][C6H5O7-] / [H3C6H5O7]
Since the reaction is a neutralization reaction, the concentration of H+ can be assumed to be equal to the concentration of CH3NH3+.
Therefore, we can substitute [H+][C6H5O7-] / [H3C6H5O7] with [CH3NH3+][C6H5O7-] in the equation for Ka1, to get:
Ka1 = [CH3NH3+][C6H5O7-] / [H3C6H5O7]
Rearranging the equation, we get:
[CH3NH3+][C6H5O7-] = Ka1[H3C6H5O7]
Substituting this into the equation for the equilibrium constant (K), we get:
K = [CH3NH3+][C6H5O7-] / [CH3NH2][H3C6H5O7]
= (Ka1[H3C6H5O7]) / ([CH3NH2][H3C6H5O7])
= Ka1 / [CH3NH2]
The concentration of CH3NH2 is not given in the problem, so we cannot calculate the numerical value of K. However, we can conclude that the equilibrium constant is directly proportional to the dissociation constant (Ka1) of citric acid and inversely proportional to the concentration of methylamine.
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A solution is made by dissolving 38.81 grams of nickel (II) sulfate, NiSO4, in enough water to make 0.467
liters of solution. Calculate the molarity of this solution.
The molarity of the NiSO₄ solution made by dissolving 38.81 grams of nickel (ii) sulfate, NiSO₄, in enough water to make 0.467 liters of solution is 0.535 M
How do i determine the molarity of the solution?First, we shall obtain the mole of 38.81 grams of nickel (ii) sulfate, NiSO₄. Details below:
Mass of NiSO₄ = 38.81 grams Molar mass of NiSO₄ = 154.75 g/molMole of NiSO₄ = ?Mole of NiSO₄ = mass / molar mass
= 38.81 / 154.75
= 0.25 mole
Now, we shall determine the molarity of the solution. Details below:
Mole of NiSO₄ = 0.25 moleVolume of solution = 10.467 LMolarity of solution = ?Molarity of solution = mole / volume
= 0.25 / 0.467
= 0.535 M
Thus, the molarity of the solution is 0.535 M
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Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g)-2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. if 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
Taking into account the definition of enthalpy of a chemical reaction, the quantity of heat released when 2 g of nitrogen are reacted is 13.23 kJ.
Definition of enthalpy of a chemical reactionThe enthalpy of a chemical reaction as the heat absorbed or released in a chemical reaction when it occurs at constant pressure. That is, the heat of reaction is the energy that is released or absorbed when chemicals are transformed into a chemical reaction.
The enthalpy is an extensive property, that is, it depends on the amount of matter present.
Heat produced in this caseIn this case, the balanced reaction is:
3 H₂ (g) + N₂ (g) → 2 NH₃ (g)
and the enthalpy reaction ∆H° has a value of -92.6 kJ/mol.
This equation indicates that when 3 moles or 6 grams of H₂ (being the molar mass of the compound 2 g/mole) reacts with 1 mole or 14 grams of N₂ (being the molar mass of the compound 14 g/mole), 92.6 kJ of heat is released.
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 6 grams of H₂ reacts with 14 grams of N₂, 1 gram of H₂ reacts with how much mass of N₂?
mass of N₂= (1 gram of H₂× 14 grams of N₂)÷6 gram of H₂
mass of N₂= 2.333 grams
But 2.333 grams of N₂ are not available, 2 grams are available. Since you have less mass than you need to react with 1 gram of H₂, N₂ will be the limiting reagent.
Taking into account the limiting reagent, when 2 grams of N₂ are burned, you can apply the following rule of three: if 14 grams of N₂ releases 92.6 kJ of heat, 2 grams of N₂ releases how much heat?
heat= (2 grams of N₂× 92.6 kJ) ÷14 grams of N₂
heat= 13.23 kJ
Finally, the quantity of heat released is 13.23 kJ.
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PLEASE HELPPPPPPPPPP
Answer:
Explanation
I am sorry but please give detailed question
5. When it is winter in Japan, what season is it in Australia?
Answer:
i think its the exact opposite so summer
..A 1.00 L balloon is filled with helium at 1.20 atm. If the balloon is squeezed into a 0.500 L
beaker and doesn't burst, what is the pressure of the helium?
Write out the answer
Answer:
P₂ = 2.4 atm
Explanation:
Given data:
Initial volume = 1.00 L
Initial pressure = 1.20 atm
Final volume = 0.500 L
Final pressure = ?
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.20 atm × 1.00 L = P₂ × 0.500 L
P₂ = 1.20 atm. L /0.500 L
P₂ = 2.4 atm
Khpo4 is mono basic salt but when I write potassium phosphate mono basic then I get kh2po4
It is a salt formed from the potassium cation (K+) and the phosphate anion (H2PO4-). This salt is considered monobasic because it contains one replaceable hydrogen ion (H+).
KH2PO4 is actually potassium dihydrogen phosphate, not potassium phosphate monobasic. Potassium phosphate monobasic, or monopotassium phosphate, is correctly represented by the chemical formula KH2PO4. It is a salt formed from the potassium cation (K+) and the phosphate anion (H2PO4-). This salt is considered monobasic because it contains one replaceable hydrogen ion (H+).
On the other hand, potassium dihydrogen phosphate, or K2HPO4, is a different compound. It is formed from the potassium cation (K+) and the hydrogen phosphate anion (HPO4^2-). This compound is considered dibasic because it contains two replaceable hydrogen ions (H+).
Therefore, KH2PO4 is correctly identified as potassium phosphate monobasic, while K2HPO4 is potassium dihydrogen phosphate.
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Define, giving examples of
Binary ionic Compound:
Answer:
A binary ionic compound contains an ion that is a metal (cation) and an ion that is a nonmetal (anion).
Explanation:
Tell me if its wrong
The meaning of the word symptom:
The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.
Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.
Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.
It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.
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the # molecules in 52.1 grams of NH4OH
Answer:
Explanation:
Hey there!
From question;
The molecular mass of NH₄OH is 35.
Avogadro number = 6.023*10²³ molecules.
Then,
From mole concept,
Molecular mass = Avogadro number
So, 35 grams contains 6.023*10²³ molecules.
1 gram contains \(\frac{ 6.023*10^{23} }{35}\) molecules.
52.1 grams contains \(\frac{6.023*10^{23} }{35} *52.1\) molecules.
Therefore, 52.1 grams contains 8.96*10²³ molecules.
Hope it helps!
FOR 100 PLEASE HELP A legend is a traditional story that explains something in real life. Sometimes they are accepted as true, but sometimes they are fantastical and just plain fun. There are many legends that surround the North Star explaining its creation as well as why it is stationary.
Take some time to research some of the legends of the North Star. After you have had a chance to read several of them, create your own fantastical story of the North Star. It can be how it came to be or explain why it is stationary.
The north star are stationary because it is positioned close to earth axis.it is the brightest star in the constellation.
Star is a luminous celestial body of gas which are mostly hydrogen and helium that shines and radiate energy sources. north star named as north star because its location is exactly above north pole. north star having some spiritual meaning , it is also called as polaris. north star is in the same location every night unlike all the other star. it is the brightest star in the constellation.
Thus, The north star are stationary because it is positioned close to earth axis.it is the brightest star in the constellation.
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All voltmeters have two probes attached to make a measurement explain why you cannot make a voltmeter with a single probe to measure the voltage of a wire
As voltages is a potential in relation to a reference, one probe must be on the reference or "zero" planes and the other must be on the point being measured.
Why does a voltmeter not accurately read voltage?because the voltmeter uses some of the main circuit's current. Main present in the circuit diminishes as a result, and the voltmeter's reading of the potential difference does not correspond to its true value.
Why are there two probes on a voltmeter?Nothing is measured at a specific point by the voltmeter. It gauges the voltage (V) differential between two circuit locations. Thus, a multimeter has two leads rather than one.
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Which monomer gives a greater yield of polymer, 5-hydroxypentanoic acid or 6-hydroxyhexanoic acid? Explain your choice.
Answer:
6-hydroxyhexanoic acid
Explanation:
5-hydroxypentanoic acid will form a 7 member group, while 6-hydroxyhexanoic acid will form a 6 member group.
In polymerization, polymers with 6 member groups are more stable than the ones with 7 member groups. This means that 6-hydroxyhexanoic acid will have a higher chance of polymerization, and therefore give a greater yield of polymers, than 5-hydroxypentanoic acid.
The molar mass of copper chloride is 134.45g/mol. How many formula units of copper chloride are present in 17.6g of copper chloride
Answer:
7.88 x 10²² formula units CuCl₂
Explanation:
To find the amount of formula units, you need to (1) convert grams to moles (via the molar mass) and then (2) convert moles to formula units (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Molar Mass (CuCl₂): 134.45 g/mol
Avogadro's Number:
6.022 x 10²³ formula units = 1 mole
17.6 g CuCl₂ 1 mole 6.022 x 10²³ formula units
-------------------- x ----------------- x ------------------------------------------ =
134.45 g 1 mole
= 7.88 x 10²² formula units CuCl₂
Given the following equilibrium constants:
Na2O(s) ⇌ 2 Na(l) + 1/2 O2(g) K1= 2 x 10^–25
NaO(g) ⇌ Na(l) + 1/2 O2(g) K2= 2 x 10^–5
Na2O2(s) ⇌ 2 Na(l) + O2(g) K3= 5 x 10^–29
NaO2(s) ⇌ Na(l) + O2(g) K4= 3 x 10^–14
Determine the value for the equilibrium constants for the following reaction:
2 NaO(g) ⇌ Na2O2(s)
Answer:
K = 8x10¹⁸
Explanation:
When you sum a reaction, the result of this sum has a K equal to the multiplication of the K's of the reactions involved in the sum
The sum of two times the reaction:
NaO(g) ⇌ Na(l) + 1/2 O₂(g) K₂ = 2x10⁻⁵
2 NaO(g) ⇌ 2 Na(l) + O₂(g) K = K₂ₓK₂ = (2x10⁻⁵)² = 4x10⁻¹⁰
The result of the inverse reaction:
Na₂O₂(s) ⇌ 2 Na(l) + O₂(g) K₃= 5x10⁻²⁹
2 Na(l) + O₂(g) ⇌ Na₂O₂(s) K = 1/K₃ = 2x10²⁸
And the sum of the two bolded reactions:
2 NaO(g) + 2 Na(l) + O₂(g) ⇌ 2 Na(l) + O₂(g) + Na₂O₂(s)
2 NaO(g) ⇌ Na₂O₂(s) K = 4x10⁻¹⁰× 2x10²⁸
K = 8x10¹⁸
What is actual and theoritical yield
and give example
In chemistry, the actual yield refers to the quantity of a product that is obtained during an experiment or a chemical reaction. The theoretical yield, on the other hand, refers to the maximum amount of product that can be obtained from a given amount of reactant, assuming the reaction proceeds to completion and there are no losses due to factors such as side reactions or incomplete conversion of reactants.
The percentage yield is the ratio of the actual yield to the theoretical yield, expressed as a percentage.
For example, consider the combustion of 10.0 grams of methane gas (\(CH_4\)) in excess oxygen to produce carbon dioxide \((CO_2\)) and water (\(H_2O\)):
\(CH_4\) + 2O2 → \(CO_2\) + \(2H_2O\)
The balanced chemical equation shows that one mole of CH4 reacts with two moles of O2 to produce one mole of CO2 and two moles of \(H_2O\). Therefore, the theoretical yield of CO2 is calculated as follows:
10.0 g \(CH_4\) × (1 mol \(CH_4\)/16.0 g \(CH_4\)) × (1 mol \(CO_2\)/1 mol CH4) × (44.0 g \(CO_2\)/1 mol\(CO_2\)) = 27.5 g \(CO_2\)
If the actual yield of \(CO_2\) obtained from the reaction is 23.5 g, the percentage yield can be calculated as follows:
Percentage yield = (23.5 g CO2/27.5 g CO2) × 100% = 85.5%
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Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal, X-ray light is transmitted through the material, and visible light is reflected off the metal. Tyrel wonders if the metal will get warm if he shines the lights on it.
Answer:
Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal. X-ray light is transmitted through the metal. ... Yes, light can cause the metal to get warm because light carries energy.
Write the chemical formula for this molecule
The chemical formula for the molecule you provided is C2H5Cl.
In the molecule, the central atom is carbon (C), which is bonded to two hydrogen atoms (H) and one chlorine atom (Cl). The carbon atom forms single bonds with each of the hydrogen and chlorine atoms, resulting in a linear structure.
To write the chemical formula, we start by indicating the number of atoms of each element present in the molecule. In this case, there are two carbon atoms (C2), five hydrogen atoms (H5), and one chlorine atom (Cl1).
Next, we write the symbols for the elements in the order of their appearance. The formula is typically written with the carbon atom first, followed by hydrogen, and then any other elements in alphabetical order. Therefore, the chemical formula for the molecule is C2H5Cl.
The subscripts in the formula indicate the number of atoms of each element in the molecule. In this case, there are two carbon atoms, five hydrogen atoms, and one chlorine atom.
It's important to note that the formula represents the simplest ratio of atoms in the molecule. It does not provide information about the spatial arrangement or bonding pattern of the atoms. Additional structural information, such as the arrangement of atoms in space, would require a more detailed representation, such as a Lewis structure or a three-dimensional model.
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An unknown hydrocarbon compound was analyzed for hydrogen by elemental analysis and results show that it contains 15.88 % H. What is the empirical formula
Answer:
C4H9
Explanation:
If H = 15.88%
Then C = 100.00 – 15.88 = 84.12
Divide each % value by respective atomic mass
H = 15.88/1 = 15.88
C = 84.12/12 = 7.01
Divide through by smaller value
H = 15.88/7.01 = 2.26
C = 7.01/7.01 = 1
Remove fraction , multiply by 4
H = 9
C = 4
Empirical formula = C4H9
The hydrocarbon could be ( C4H9)2 = C8H18 = octane.
2. assign a designation of re, si, or n (not prochiral) to indicate which face we are looking down on for each of the sp2-hybridized carbons in the structure below.
For the structure below, the \(sp^{2}\)-hybridized carbons can be assigned the designations of re and si, respectively.
There designation indicates that we are looking down on the face of the carbon that is farthest away from us, while the si designation indicates that we are looking down on the face of the carbon that is closest to us.
The \(sp^{2}\)-hybridized carbons are carbon atoms that have three \(sp^{2}\) hybrid orbitals, which are a combination of s- and p-orbitals. These orbitals are used to form three covalent bonds and one unshared pair of electrons, giving the carbon atom a trigonal planar shape.
This type of hybridization is common in molecules with double bonds, such as alkene molecules, as it allows the carbon atoms to form strong double bonds with other atoms. The \(sp^{2}\)-hybridized carbons are important in organic chemistry as they allow for a wide range of reactions to take place.
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Suppose that Daniel has a 2.00L bottle that contains a mixture of O2, N2, and CO2 under a total pressure of 6.00 atm. He knows that the mixture contains 0.270mol N2 and that the partial pressure of CO2 is 0.350 atm. If the temperature is 273 K, what is the partial pressure of O2?
The partial pressure of O2 in the gas mixture is 7.91 atm.
Partial pressure problemUsing the ideal gas law, PV = nRT, the total number of moles of gas in the mixture would be:
n = PV/RTn = (6.00 atm)(2.00 L) / (0.0821 L·atm/mol·K)(273 K)n = 0.560 molMoles of N2 in the mixture = 0.270 x 0.560 = 0.1512 mol
Moles of CO2 in the mixture: n = PV/RT
= 0.350x2/0.0821 x273
= 0.00498 mol
Moles of O2 = Total moles - moles of N2 - moles of CO2
= 0.560 mol - 0.1512 mol - 0.00498 mol
= 0.404 mol
Now we can use the ideal gas law to find the partial pressure of O2:
P = nRT/V
= (0.404)(0.0821)(273) / 2
= 7.91 atm
Therefore, the partial pressure of O2 in the mixture is 7.91 atm.
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A bowl containing 70 grams of water, is heated from 10 °C to 90 °C. The specific heat of
water is 4.184 J/gºC. How much heat energy is required to heat the water?
Answer:
23430.4 J.
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 70 g
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 90 – 10
ΔT = 80 °C
Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:
Mass (M) = 70 g
Change in temperature (ΔT) = 80 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Q = MCΔT
Q = 70 × 4.184 × 80
Q = 23430.4 J
Therefore, 23430.4 J of heat energy is required to heat up the water.
3. Determine the enthalpy of formation for propane. 3C(s, gr) + 4H2(g) ---> C3H2(g) CzH3(g) AH = -2219.9 kJ C(s, gr) AH = -393.5 kJ H,(g) AH = -285.8 kJ a. -205.7 /mol b. -103.8 kJ/mol Å C. + 205.7 /mol d. + 103.8 /mol
Answer:
b I hope this is right good luck