Calculate the surface area of a sphere with a diameter of 28

Answer:

Answer: (2, 1)

Step-by-step explanation:

y = 6x - 11

-2x - 3y = -7

Substitute y into the equation;

-2x - 3(6x - 11) = -7

Distribute;

-2x - 18x + 33 = -7

Collect like terms;

-20x + 33 = -7

Subtract 33 from both sides;

-20x = -40

Divide both sides by -20

x = 2

Substitute x into the equation;

y = 6(2) - 11

y = 12 - 11

y = 1

Answer: (2, 1)

The time in hours for the Tran family's sprinkler will be 30 hours.

The time in hours for the Campbell family's sprinkler will be 35 hours.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The water output rate for the Tran family's sprinkler was 35 L per hour.

The water output rate for the Campbell family's sprinkler was 25 L per hour.

And, The families used sprinklers for a combined total of 65 hours, which is resulting in a total water output of 1925 L.

Now,

Let time in hours for the Tran family's sprinkler = t

And, The time in hours for the Campbell family's sprinkler = 65 - t

So, We can formulate by the given condition,

⇒ 35t + 25 (65 - t) = 1925

Solve for t as;

⇒ 35t + 25 (65 - t) = 1925

⇒ 35t + 1625 - 25t = 1925

⇒ 10t + 1625 = 1925

⇒ 10t = 1925 - 1625

⇒ 10t = 300

⇒ t = 30

Thus, The time in hours for the Tran family's sprinkler = t

                                                                                   = 30 hours

And, The time in hours for the Campbell family's sprinkler = 65 - t

                                                                                          = 65 - 30

                                                                                          = 35 hours.

Therefore, we get;

The time in hours for the Tran family's sprinkler will be 30 hours.

The time in hours for the Campbell family's sprinkler will be 35 hours.

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Answer:

-2

Step-by-step explanation:

when x= 0

f(0)= 3*(0)² + 2*0 - 2

= 0 + 0-2

= -2

Answer:

m<ABC > m<ACB (angle property of a triangle)

Step-by-step explanation:

Given that: ΔABC

                  AB = AX

Prove: m<ABC > m<ACB

From the given diagram,

ΔABX is an isosceles triangle (two congruent sides and angles)

<AXB = m<ABX = \(90^{o}\) (isosceles triangle property)

AC = AX + XC

Thus,

AC > AB

m<ABC = m1 + m3 ≥  \(90^{o}\)

m<ACB < \(90^{o}\) (acute angle property)

Therefore since in a triangle the longest side is opposite to the greatest angle, then;

m<ABC > m<ACB (angle property of a triangle)

Yes , the confidence interval still valid because the sample size is large ( n = 100 is greater than 30 ).

Given :

Monica delivers pizza. She takes a simple random sample of 100 of her deliveries from the first 11 months of 2020 and finds that her tips average $3.66 with an SD of $2.19.The 90% confidence interval for Monica’s average tip size for these months has the form A + - B * C .

if the histogram of monica's tips does not follow the normal curve, is the confidence interval still valid .

Here

sample size n = 100

The sample size is a term used in market research for defining the number of subjects included in a sample size.

here

n > 30

Hence the confidence interval is still valid .

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Full question:

Monica delivers pizza. She takes a simple random sample of 100 of her deliveries from the first 11 months of 2020 and finds that her tips average $3.66 with an SD of $2.19.The 90% confidence interval for Monica’s average tip size for these months has the form A + - B * C .

if the histogram of monica's tips does not follow the normal curve, is the confidence interval still valid?

Angle of elevation would be 66 degrees

We can use the analysis of variance procedure to test hypotheses about three or more groups and their mean differences. ANOVA is a powerful tool for testing hypotheses about differences among group means, variability within and between groups, and interaction effects in multifactor studies.

The procedure compares the variability between the groups to the variability within the groups, and determines whether the observed differences in means are statistically significant. This can be used to test hypotheses about the effect of a treatment, the comparison of multiple groups, or the relationship between an independent variable and a dependent variable. Overall, the analysis of variance procedure provides a powerful tool for hypothesis testing in research, and can be used to draw conclusions about the population from a sample of data. The analysis of variance (ANOVA) procedure is a statistical method used to test hypotheses about:

Differences among group means: ANOVA helps to determine if there are significant differences among three or more group means, enabling researchers to compare multiple groups simultaneously. Variability within and between groups: ANOVA compares the variability of data points within each group to the variability between groups. This analysis helps identify if the variation is due to factors of interest or random chance. Interaction effects: In a multifactor ANOVA, the procedure can test for interaction effects between independent variables. This helps to understand if the effect of one factor on the dependent variable is dependent on the levels of another factor.

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Answer:

The inequality for the perimeter to be atleast 300 feet is

Step-by-step explanation:

\(x\geq 142\)

Answer:

The company has 70 falvors

The speed of the object is 12121 m per week.

What does it mean to do speed?

The object is moving at a speed of 2 centimeters every 7 seconds.

We need to find the speed in m per week.

2 cm = 0.02 m

1 week = 604800 s

7 s =  \(1.65 * 10^{-6} week\)

Speed = distance/time

So,

\(v = \frac{0.02 m}{1.65 * 10^{-6 } week}\)

\(v = 12121.21 m/ week\)

or v = 12121 m/ week

So, the speed of the object is 12121 m per week.

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Answer:

Step-by-step explanation:

A company finds 5 defective toys in a sample of 600. Predict how many defective toys are in a

shipment of 24,000.

we can solve with an equation

5 : 600 = x : 24000

x = 5 * 24000 : 600

x = 200

This statement ''The proportion in the body of a normal distribution can never be less than 0.50.'' is false because the proportion in the body of a normal distribution can be less than 0.50, depending on the location of the mean and the spread of the distribution.

In fact, for a normal distribution with a mean of μ and standard deviation of σ, approximately 68% of the area under the curve falls within one standard deviation of the mean (i.e., between μ - σ and μ + σ), which means the proportion in the body of the distribution is about 0.68.

The remaining 32% is split evenly between the tails of the distribution, which means the proportion in each tail is about 0.16.

So, the proportion in the body of the distribution is greater than 0.50.

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Answer:

Step-by-step explanation:

To convert the equation r sin theta = 4 to Cartesian coordinates, we use the identities r^2 = x^2 + y^2 and y/x = tan theta. Substituting r sin theta = 4 into these identities, we get:

x^2 + y^2 = (r sin theta)^2 = 16

y/x = sin theta/ cos theta = tan theta

Squaring both sides of the second equation and substituting y^2/x^2 = 1 + tan^2 theta, we get:

y^2/x^2 = 1 + (y/x)^2

x^2 + y^2 = 16(1 + (y/x)^2)

Simplifying this equation, we get:

x^2 + y^2 = 16 + 4y^2/x^2

Multiplying both sides by x^2, we get:

x^2 y^2 + y^2 = 16x^2 + 4y^2

Bringing all the terms to one side, we get:

x^2 y^2 - 16x^2 = 3y^2

This is the Cartesian equation of the curve. To describe the curve, we can rewrite this equation as:

y^2/x^2 - 16/x^2 = 3

This is the equation of a hyperbola with center at the origin, vertical axis, and asymptotes given by y/x = ±4/sqrt(3).

Answer:

0 < x ≤ 100 and 0 < y ≤ 300

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-state students as out-of-state, and they only have space to accept 100 out-of-state students. Let x = the number of out-of-state students and y = the number in-state students. Write the constraints to represent the incoming students at the college.

0 < x ≤ 100 and 0 < y ≤ 300

x > 0 and y > 0

0 < x ≤ 100 and y > 300

0 < x and y < 100

SOLUTION

they only have space to accept 100 out-of-state students,which means that the Maximum number of out-of-state students that can be accepted is 100

Then x= 100(Maximum number of out-of-state students that can be accepted)

They plan to accept three times as many in-state students as out-of-state which means that

Y = 3x(Maximum number of in-state students)

Then we can deduced that the numbee out-of-state students that can be accepted can lyes between the range of 0 and 100 which means from interval 0 to 100

Which can be written as 0 < x ≤ 100

But we need to know the interval for the Maximum number of in-state students(Y), to do that we need to multiply the equation above by 3 since Y = 3x

0 < x ≤ 100

3× 0 = 0

3× X = X

3× 100= 300

Then 0 < 3x≤ 300

But we know that Y = 3x then substitute into last equation

We have

0 < y ≤ 300

ThenBthe constraints to represent the incoming students at the college is

0 < x ≤ 100 and 0 < y ≤ 300

Answer:

0 < x ≤ 100 and 0 < y ≤ 300

Step-by-step explanation:

took test & got it right

Answer:

1499

5

(Decimal: 299.8)

Step-by-step explanation: =

300

1

−

20

100

=

300

1

+

−20

100

=

300

1

+

−1

5

=

1500

5

+

−1

5

=

1500+−1

5

Answer:

7 5/6

Step-by-step explanation:

Reverse the operation

\(-2\frac{1}{3} - -10\frac{1}{6} = 2\frac{1}{3} + 10\frac{1}{6}\\= 2-\frac{1}{3} + 10+\frac{1}{6}\\-2 + 10 = 8(2 - 10)\\-\frac{1}{3} +\frac{1}{6}\\-\frac{2}{6}(x2) +\frac{1}{6}\\= -\frac{1}{6}\\8-\frac{1}{6}\\= 7\frac{5}{6}\)

The sample results would be somewhat expected if the null hypothesis were true.

The correct option is (b).

Given,

In the question:

The complete question is this:

Select the most appropriate response.

What does it mean when sample results are not statistically significant?

The question is based on MCQ's

Now, According to the question:

What does it mean when sample results are not statistically significant?

It means  The sample results would be somewhat expected if the null hypothesis were true.

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JL, LK, JK are the smallest angle of a triangle is located across from its smallest side. The biggest side is on the other side of the biggest side.

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Answer:

3

Step-by-step explanation:

Answer:

Step-by-step explanation:

subtract x from both sides

you get 3x-6=3

add 6 to 3

3x=9

x=3

The Analyst can use COALESCE function to eliminate the null values from the results.

The SQL Coalesce functions is used to handle NULL values. During the expression evaluation process the NULL values are replaced with the user-defined value. It  returns the first non-NULL value from a series of expressions.

The SQL Coalesce function evaluates the arguments in order and always returns first non-null value from the defined argument list.

Few Properties of COALESCE Function

SYNTAX -

COALESCE ( expression [ ,...n ] )  

Hence, the analyst can use COALESCE function to eliminate the null values from the results.

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Answer:

First, remember the relation:

Distance = Speed*Time.

We know that the distance is 120mi.

A) For the biker we know that:

Time  = 8hours.

Speed = Distance/Time = 120mi/8h = 15 mi/h.

B) For the bus we know that:

Time = 2 hours.

Speed = Distance/Time = 120mi/2h = 60 mi/h.

C) For the truck we know that:

Time = 2.5 hours.

Speed = Distance/Time = 120mi/2.5h = 48 mi/h.

D) For the rider on a horse we know that:

Time = 18.75 hours.

Speed = Distance/Time = 120mi/18.75h = 6.4 mi/h.

E) The equation for the speed is:

Speed = Distance/Time.

You can see that time is in the denominator, this means that if for a fixed distance, the time increases, then the denominator increases, which would imply that the speed decreases.

Then the speed is inversely proportional to the time when the distance is fixed.

Therefore, using simple exponential smoothing with a = 0.75, the forecast for water pump sales for February through May are:- February: 26.5 units,  March: 37.63 units, April: 72.66 units.

To use simple exponential smoothing with a = 0.75, we first need to calculate the forecast for January:
F1 = 25 (given)
Next, we calculate the forecast for February using the formula:
F2 = a * Y1 + (1 - a) * F1
F2 = 0.75 * 28 + 0.25 * 25
F2 = 26.5 (rounded to one decimal place)
We repeat this process for each month, using the previous month's forecast and the actual sales data for the current month. The results are as follows:
Month      Actual Sales    Forecast
-------------------------------------
January           28          25
February          72          26.5
March             98          37.63
April            126          72.66
- May: 101.17 units
Hi, I'd be happy to help you with your question. To use simple exponential smoothing with a smoothing constant α = 0.75 to forecast the water pump sales for February through May, given that the forecast for January was 25 units, follow these steps:
Step 1: Start with the given forecast for January, which is 25 units.
Step 2: Calculate the forecast for February using the formula:
Forecast_February = α * (Actual_January) + (1 - α) * Forecast_January
Step 3: Calculate the forecast for March using the formula:
Forecast_March = α * (Actual_February) + (1 - α) * Forecast_February
Step 4: Calculate the forecast for April using the formula:
Forecast_April = α * (Actual_March) + (1 - α) * Forecast_March
Step 5: Calculate the forecast for May using the formula:
Forecast_May = α * (Actual_April) + (1 - α) * Forecast_April
Please note that you have provided sales data for air-conditioning sales, but the question is about water pump sales. If you meant to ask about air-conditioning sales, you can use the given sales data to calculate the forecasts for February through May. If you need help with water pump sales, please provide the correct sales data for January through April, and I will gladly help you with the calculations.

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Answer:

AB and BC are the sides of a parallelogram, ABCD. AB = 5 cm, BC = 7 cm and ABC = 60 degrees. Draw the lines AD and CD to complete the parallelogram.

Step-by-step explanation:

Answer:

where is the question on which topic

From multiplcation operation, Alex has enough paint to cover 1,000 ft² of his apartment. The true statement is 2 gallons of paint will cover 1068 ft², Alex have enough paint of quantity 2 gallons.

We have Mr. Alex painted his apartment. Area of his apartment'walls = 178 ft²

Quantity of paint used by him to paint his apartment'walls with area 178 ft² =\( \frac{1}{3} \: \: gallons\)

Total quantity of paint used in all

= 2 gallons

We have to check the provide paint is enough or not to cover 1,000 ft² of his apartment. Let the required paint for 1000 ft² be x gallons. Using multiplcation, 1/3 gallons quantity of paint will cover the area of apartment = 178 ft², so, 1 gallons quantity of paint will cover the area of apartment = 178 ×3 ft²= 534 ft²

Now, 2 gallons quantity of paint will cover the area of apartment = 2× 534 ft² = 1068 ft²> 1000 ft²

But he wants to paint 1000 ft² of his apartment in 2 gallons quantity (x=1.9 gal ). So, he has enough paint to paint his apartment.

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Complete question:

The above figure complete the question.

Alex painted 178 ft2 of his apartment’s walls with 1/3 gallon of paint. He has 2 gallons of paint in all. If he wants to cover 1,000 ft2 of his apartment, does he have enough paint? Complete a true statement

Answer:

4 backpacks

Step-by-step explanation:

3 backpacks can hold 30 pounds. You can't have half a backpack, so you just add another.

Answer:

4

Step-by-step explanation:

Answer:

The area of a circle is pi times the radius squared.

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