Answer:
CuCO3Cu(OH)2 overlapping yield calculate itCuCO3Cu(OH)2 overlapping yield calculate it
holy sheesh dude
Explanation:
CuCO3Cu(OH)2 overlapping yield calculate it
How to solve , how many grams of KI are in 25. 0 ml of a 3. 0%(m/v) KI solution
The grams of the KI are in the 25.0 ml of a 3.0 % m/v of the KI solution is 0.75 g.
The volume of the solution = 25 mL
The mass by volume of KI = 3 % m/v
The potassium iodide solution will contain the 3.0 g of the potassium iodide for the every 100 mL of the solution.
The amount of the KI in grams is as follows :
The mass of the KI in grams = (25 mL× 3 g ) / 100 mL
The mass of the KI in grams = 0.75 g
Thus, the amount of the KI in the grams is 0.75 g in the volume of the 25 mL.
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The HI molecule may be treated as a stationary I atom around which an H atom moves. Assuming that the H atom circulates in a plane at a distance of 161 pm from the 1 atom, calculate (i) the moment of inertia of the molecule and (ii) the greatest wavelength of the radiation that can excite the molecule into rotation, (b) Assuming that the H atom oscillates toward and away from the I atom and that the force constant of the HI bond is 314 N m-1, calculate (i) the vibrational frequency of the molecule and (ii) the wavelength required to excite the molecule into vibration, (c) By what factor will the vibrational frequency of HI change when H is replaced by deuterium?
The vibrational frequency of HD is about 10 times lower than that of HI, since the reduced mass of HD is about twice that of HI.
(i) To calculate the moment of inertia of the molecule, we can use the formula:
I = µr²
where µ is the reduced mass of the system, which is given by:
µ = (m1m2)/(m1 + m2)
Here, m1 is the mass of the H atom and m2 is the mass of the I atom. Since the H atom is much lighter than the I atom, we can approximate the reduced mass as:
µ ≈ mH
where mH is the mass of the H atom. The distance of the H atom from the I atom is given as 161 pm = 161 × 10⁻¹² m, so the moment of inertia is:
I = mHr² = (1.0079 u)(161 × 10⁻¹² m)² = 2.754 × 10⁻⁴ kg m²
(ii) The greatest wavelength of the radiation that can excite the molecule into rotation is given by the formula:
λ = 2πc/I
where c is the speed of light. Substituting the values, we get:
λ = 2π(3.00 × 10⁸ m/s)/(2.754 × 10⁻⁴ kg m²) = 2.27 mm
(b) (i) The vibrational frequency of the molecule is given by the formula:
ν = (1/2π)√(k/µ)
where k is the force constant of the HI bond. Substituting the values, we get:
ν = (1/2π)√(314 N m⁻¹/1.0079 u) = 1.19 × 10¹³ Hz
(ii) The wavelength required to excite the molecule into vibration is given by the formula:
λ = c/ν
Substituting the values, we get:
λ = (3.00 × 10⁸ m/s)/(1.19 × 10¹³ Hz) = 0.252 µm
(c) The vibrational frequency of HI when H is replaced by deuterium (D) is given by the formula:
νD = (1/2π)√(k/µD)
where µD is the reduced mass of the HD molecule, which is given by:
µD = (mHmD)/(mH + mD) ≈ 0.5mH
Substituting the values, we get:
νD = (1/2π)√(314 N m⁻¹/(0.5 × 1.0079 u)) = 9.49 × 10¹² Hz
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3. A helium laser emits light with a wavelength of 6.33 x 10^-7m. What is
the frequency of the light? *
2.11 X10^15 Hz
O 4.74 x 10^14 Hz
O 18.99 Hz
N
Answer:
4.52 x 10¹⁴ cycles/s
Explanation:
From c = f·λ => f = c/λ = (3.0 x 10⁸ m/s)/(6.63 x 10⁻⁷m) = 4.52 x 10¹⁴ cycles/s.
f = frequency = ?
λ = wavelength = 6.63 x 10⁻⁷ meter
c = speed of light in vacuum = 3.0 x 10⁸ meters/s
A helium laser emits light with a wavelength of 6.33 x 10⁻⁷m. The frequency is 4.74 x 10¹⁴ cycles/s.
What is wavelength?Wavelength is defined as the separation between similar points (adjacent crests) in successive waves of a waveform signal that have traveled across space or along a wire. The length of a "sine wave's" shortest repeating segment is known as its wavelength. Sine waves can be combined to create any type of wave. That is, a Fourier analysis can be used to determine that every wave is made up entirely of sine waves.
Frequency is defined as the amount of times a repeated event occurs in one unit of time. Frequency can be expressed as
F = c / λ
Where c = speed if light = 3 x 10⁸ m/s
λ = wavelength = 6.33 x 10⁻⁷m given
F = 3 x 10⁸ / 6.33 x 10⁻⁷m
F = 4.74 x 10¹⁴ cycles/s.
Thus, a helium laser emits light with a wavelength of 6.33 x 10⁻⁷m. The frequency is 4.74 x 10¹⁴ cycles/s.
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The theoretical yield of beryllium chloride was 10.7 grams. If the reaction actually yields 4.5 grams, what was the percent yield
The percentage yield of the reaction, given that the theoretical yield of beryllium chloride was 10.7 grams is 42%
How do i determine the percentage yield of the reaction?First, we shall list out the given parameters from the question. Details below:
Theoretical yield of beryllium chloride = 10.7 gActual yield of beryllium chloride = 4.5 gPercentage yield =?The percentage yield of the reaction can be obtained as illustrated below:
Percentage yield = (Actual of beryllium chloride /Theoretical of beryllium chloride) × 100
= (4.5 / 10.7) × 100
= 42%
Thus, we can conclude from the above calculation that the percentage yield is 42%
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Nuclear reactions can be written out in equation form. When looking at equations, how can you identify a reaction as a fission reaction? Use the equation of the nuclear fission reaction below to help choose the correct answer.A nucleus with a large mass will be on the right side, and there will be neutrons in the equation. bA nucleus with a large mass will be on the right side, and there will be electrons in the equation. cA nucleus with a large mass will be on the left side, and there will be neutrons in the equation. dA nucleus with a large mass will be on the left side, and there will be electrons in the equation.
Answer:
c. A nucleus with a large mass will be on the left side, and there will be neutrons in the equation.
Explanation:
In the process of nuclear fission, a neutron collides with a nucleus with a large mass and that nucleus splits into isotopes (substances that have the same atomic number that the original substance, but different weight number).
In this case, the nucleus with a large mass is U and n represents the neutrons.
write molecular and net ionic equations for the successive neutralizations of each acidic hydrogen of sulfurous acid
Sulfurous acid is a weak acid with the molecular formula H2SO3. It has two acidic hydrogen atoms, which can be sequentially neutralized. The successive neutralizations of each acidic hydrogen of sulfurous acid are as follows:
First acidic hydrogen: H2SO3 + NaOH → NaHSO3 + H2O
The molecular equation is H2SO3 + 2NaOH → Na2SO3 + 2H2O
The net ionic equation is H2SO3 + 2OH- → SO32- + 2H2O
Second acidic hydrogen: NaHSO3 + NaOH → Na2SO3 + H2O
The molecular equation is HHSO3 + NaOH → Na2SO3 + H2O
The net ionic equation is HSO3- + OH- → SO32- + H2O
Overall reaction: H2SO3 + 2NaOH → Na2SO3 + 2H2O
The molecular equation for the overall reaction is H2SO3 + 2NaOH → Na2SO3 + 2H2O
The net ionic equation for the overall reaction is H2SO3 + 2OH- → SO32- + 2H2O
In summary, the molecular and net ionic equations for the successive neutralizations of each acidic hydrogen of sulfurous acid are given above.
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3 naoh(aq) c₆h₈o₇(aq) ⇌ na₃c₆h₅o₇(aq) 3 h₂o(l) step 3: calculate the volume of titrant required to reach the endpoint. calculate the volume in ml of a 0.200 m naoh solution needed to neutralize 345 ml of 0.0333 m c₆h₈o₇ standard solution.
Volume of NaOH solution needed to neutralize C₆H₈O₇ is 56.825 ml
In titration reaction , at equivalence point
Moles of Acid = Moles of Base
If \(M_1\) is mole of acid and \(V_1\) is volume of acid
\(M_2\) is moles of base and \(V_2\) is volume of base
Then \(M_1 V_1 = M_2 V_2\)
Here in this question
\(M_1 = 0.200 M\\ M_2 = 0.0333 MV_1 = unknown\\V_2 = 345\)
Therefore,
\(.200 * V_1 = 0.033 * 345 ml\)
\(V_1\) = \(0.033 *345 / .200\)
\(V_1 = 56.825 ml\)
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What is the formula for
Fe+2 + (SO4)-2 ?
Answer:
FeSO4 is the formula for iron(II) sulfate.
6) a mixture of two gases was allowed to effuse from a container. one of the gases escaped from the container 1.43 times as fast as the other one. the two gases could have been:
The ratio of the effusion rates of two gases is given by Graham's law, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. We need to determine the identities of the two gases in a mixture where one gas effuses 1.43 times faster than the other. To solve this, we can use Graham's law of effusion.
Graham's law states that the rate of effusion of two gases is inversely proportional to the square root of their molar masses.
Rate1 / Rate2 = (M2 / M1)
Given that one gas effuses 1.43 times faster than the other, we can set up the equation:
1.43 = √(M₂ / M₁)
Now, we need to find two gases that satisfy this equation. To do this, we can use the periodic table to check the molar masses of various gases and find a pair that fits the ratio. For example:
1.43 ≈ √(28.97 g/mol (air) / 20.18 g/mol (Ne))
Thus, the two gases could be air (a mixture of nitrogen, oxygen, and other trace gases) and neon (Ne). In summary, there are many possible combinations of gases that could have effused from the container, but one example is helium and sulfur hexafluoride.
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16) 5AI(C2H302)2
r
How many molecules are there
Answer:
The mole allows scientists to calculate the number of elementary entities (usually atoms or molecules ) in a certain mass of a given substance. Avogadro's number is an absolute number: there are 6.022×1023 elementary entities in 1 mole. This can also be written as 6.022×1023 mol-1.
Explanation:
What does the slang term "the Boards" refer to?
Answer:
It can mean "boardwalk" or a "board of a school."
~Mia Sedillo~
A 0.200 m solution of which one of the following solutes will have the highest vapor pressure?
A LiCl
B AlCl3
C CaCl2
D C6H{12}O6
E KCl
0.200 m solution of C6H12O6 will have the highest vapor pressure.
To determine which 0.200 m solution will have the highest vapor pressure, we need to consider the concept of "vapor pressure lowering" which is a result of a solute dissolving in a solvent. The solution with the lowest degree of vapor pressure lowering will have the highest vapor pressure.
Vapor pressure lowering is proportional to the mole fraction of solute particles. The more solute particles present, the lower the vapor pressure.
Here are the solutes and the number of ions they dissociate into:
A) LiCl -> Li+ + Cl- (2 ions)
B) AlCl3 -> Al3+ + 3Cl- (4 ions)
C) CaCl2 -> Ca2+ + 2Cl- (3 ions)
D) C6H12O6 -> (1 molecule, does not dissociate)
E) KCl -> K+ + Cl- (2 ions)
Since C6H12O6 does not dissociate into ions and remains as a single molecule, it contributes the least number of particles. Therefore, a 0.200 m solution of C6H12O6 will have the highest vapor pressure.
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I WILL GIVE A LOT OF EXTRA POINTS. PLEASE ANSWER ALL OF THEM
75 for all
Explanation:
Answer:
Explanation: Li= Lithium, Na= Sodium, K= Pottasium, Rb= Rubdium Cs= Cesiuna, Fr= Fransium
6. Energy levels increases as if you move down a group during the number of electrons increases again.
7. A charge with higher and effective nuclear charge makes greater attractions to the electrons, pulling the electrons cloud closer to the nucleus makes it in a smaller atomic radius.
8. Ge= Germanium, He= Helium, O=Oxygen, Barium
Is density qualitative or quantitative poetry?
ANSWER PLEASE.
a vital step in erikson's ego vs despair phase includes the older adult to participate in?
A vital step in Erikson's ego vs. despair phase includes the older adult participating in introspection and life review.
It also allows older adults to participate in activities that provide a sense of purpose and meaning, such as volunteering, mentoring, or continuing education.
This helps them to feel fulfilled and satisfied with their life, rather than feeling hopeless and regretful about missed opportunities, and allows them to achieve a sense of integrity, acceptance, and fulfillment in their life experiences, ultimately resulting in a healthy resolution of this developmental stage.
Additionally, connecting with others and building supportive relationships can help older adults maintain a positive outlook and overcome feelings of isolation or loneliness.
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at what temperature is the rms speed of hydrogen molecules, which have a molecular weight of equal to
At 51 degrees Celsius, the rms speed of hydrogen molecules with a molecular weight of 2.02 g/mol is equal to 2000 m/s.
Find the temperature at which the root mean square (rms) speed of hydrogen molecules, with a molecular weight of 2.02 g/mol, is equal to 2000 m/s, we can use the formula for rms speed:
v = sqrt((3 * k * T) / m)
where:
v is the rms speed,
k is the Boltzmann constant (1.38 x \(10^{-23\)J/K),
T is the temperature in Kelvin, and
m is the molecular weight of the gas in kg.
First, we need to convert the molecular weight of hydrogen from grams per mole to kilograms:
m = 2.02 g/mol = 2.02 x \(10^{-3\) kg/mol
Next, we rearrange the formula to solve for temperature:
T = (\(v^2\) * m) / (3 * k)
Substituting the given values:
T = (2000 m/s)^2 * (2.02 x\(10^{-3\) kg/mol) / (3 * 1.38 x \(10^{-23\) J/K)
Simplifying the equation:
T ≈ 5.878 x\(10^5\) K
Lastly, we convert the temperature from Kelvin to Celsius:
T_Celsius = T - 273.15
T_Celsius ≈ 5.878 x\(10^5\) K - 273.15 ≈ 51 °C
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Choose a body system and write about what kind of music it would listen to. write 2 sentences for full credit.
Answer : Music is read differently in the brain than
nonmusical tones and is connected to many different areas of the brain. Learning music
relegates a larger part of the brain to recognizing and interpreting music. Listening to
music has also been found to have an effect on learning.
Answer:
The heart would listen to music with a nice rhythm as it beats to the song.
Explanation:
Help please !!!!!! Please
Answer:
I'm not entirely sure on this one, but I would think it's 8%
Explanation:
calcium hydride (cah2) reacts with water to form hydrogen gas: cah2(s) 2h2o(l) → ca(oh)2(aq) 2h2(g) how many grams of cah2 are needed to generate 48.0 l of h2 gas at a pressure of 0.888 atm and a temperature of 32°c?
To generate 48.0 L of H2 gas at 0.888 atm and 32°C, approximately 30.3 grams of CaH2 are needed according to the given conditions and calculations using the Ideal Gas Law and stoichiometry.
To determine the grams of calcium hydride (CaH2) required to produce 48.0 L of hydrogen gas at a pressure of 0.888 atm and a temperature of 32°C, we employ the Ideal Gas Law. Firstly, converting the temperature from Celsius to Kelvin yields 305.15 K. Using the equation PV = nRT, where P represents pressure, V signifies volume, n denotes moles, R represents the ideal gas constant (0.0821 L*atm/(mol*K)), and T signifies temperature in Kelvin.
Rearranging the equation to solve for n, we find n ≈ 1.44 moles. By employing the balanced chemical equation, we determine that 0.72 moles of CaH2 are required, as 1 mole of CaH2 produces 2 moles of H2. Finally, using the molar mass of CaH2 (approximately 42.1 g/mol), we find that the quantity of CaH2 needed is roughly 30.3 grams.
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Is this equation balanced and in the lowest form? 4NH3 → 2N2 + 6H2
A.
Yes, because there are equal amounts of atoms of each element on both sides.
B.
No, because the coefficients could be reduced to 2,1, and 3.
C.
Yes, because the coefficients are in their lowest whole number ratio.
D.
No, because the coefficients could be reduced to 2, 2, and 4.
Answer:
B.) No, because the coefficients could be reduced to 2,1, and 3.
Explanation:
The equation is not in its lowest molar ratio form. In this case, all of the coefficients can be divided by 2 and still result in whole numbers.
As such, the correct balanced equation is:
2 NH₃ ----> N₂ + 3 H₂
A 3.00 L sample of paint that has a density of 4.65 g/mL is found to contain 33.1 g lead (II) nitride. Determine (A) how many grams of lead ion are in the paint sample? (B) How many ions of lead are in the paint? (C) what is mass percentage of lead in the paint/ What is the ppm?
1) Grams of lead.
Convert grams of lead (II) nitride to moles of lead (II) nitride
\(molofPb_3N_2=33.1gPb_3N_2\cdot\frac{1molPb_3N_2}{649.61gPb_3N_2}=0.0509lofPb_3N_2\)Convert moles of lead (II) nitride into moles of Pb
\(\text{molesofPb}=0.0509molPb_3N_2\cdot\frac{3\text{molPb}}{1molPb_3N_2}=0.1527\text{molPb}\)Convert moles of Pb into grams of Pb
\(\text{gofPb}=0.1527\text{molPb}\cdot\frac{207.2\text{ g Pb}}{1\text{molPb}}=31.64\text{ g Pb}\)There is 31.64 g of ions of lead in the sample of paint.
How many grams of CO₂ gas would occupy 33.7 L of volume at a temperature of
-22.2°C and a pressure of 990 mm Hg?
1.3atm
Let's see
moles of CO_2
PV=nRTn=PV/RTn=990(33.7)/(251.8)(8.314)n=15.9molMass of CO_2
Molar mass×n15.9(44)699.6gQuestion 5 of 25
Which two phrases best describe vascular tissue in plants?
A. Contain root hair cells and guard cells
B. Cover the outside of plants
c. Contain cells that connect to form pipes
D. Transport water and food
SUBMIT
predict how the surface of a sand dune would change if a river began flowing through the area over the course of 10,000 years. Write your explanation in the space
below.
Answer:
the sand dune would become flattened and eventually turn into sedementary rock
are the atoms in tin highly reactive or somewhat reactive
for brainiest IS NF A ATHEIST
it is relatively non-reactive at room temperatures
The bond enthalpy of the N-N triple bond is 418kj/mol. Which statement about the N2 molecule is correct?
The bond enthalpy of the N-N triple bond is 418kj/mol. The correct statement about the N2 molecule is correct is that It requires less energy to break the bonds in molecule A than it does in molecule B.
What is a molecule?A molecule is described as a group of two or more atoms held together by attractive forces known as chemical bonds
In chemistry, bond energy (E) or bond enthalpy (H) is the measure of bond strength in a chemical bond which means that the higher the bond enthalpy, the more energy is needed to break the bond and the stronger the bond.
The lower the bond enthalpy, the lesser energy is needed to break the bond and the weaker the bond.
So we can say that the e correct option is A. Since A has a lower energy value compared to B, it would take a lesser amount of energy to break the bonds in A.
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#completye question:
The bond enthalpy of the N-N triple bond is 418kj/mol. Which statement about the N2 molecule is correct?
A. It requires less energy to break the bonds in molecule A than it does in molecule B.
B.It requires more energy to break the bonds in molecule A than it does in molecule B.
C. Molecule A is more stable than molecule B.
D. Molecule A has stronger bonds than molecule B.
All of the following are nutrients EXCEPT:
a. fats
b. water
c. protein
d. blood
HURRY UP AND HELP ME
Answer:
\(d.blood\)
Explanation:
Hope it helps!!!
Why Doesn't The Earth Usually Feel Solar Winds?
Answer:
When the solar winds approach the Earth, the magnetosphere (part of the Earth's natural magnetic defenses) deflects/repels most of the charged particles and shields our planet's surface from the winds. Sometimes, however, the magnetosphere isn't strong enough to block the Earth from these winds, so they do hit Earth and may cause catastrophic consequences, such as ruin power grids, cut off telecommunications (cell service/calls), etc.
Hope this helps you out! Have a nice day! :)
7) Convert 8.34 x 10^-6 Kg to cg"
0.0834 cg
8340 cg
0.834 cg
0.00834 cg
0.834 x 10^-6
what is the molar concentration of a solution formed by dissolving 450.0 mg of nacl to make 100.0 ml of solution? molar mass of nacl is 58.44 g/mol.
The molar concentration of the NaCl solution formed by dissolving 450.0 mg of NaCl in 100.0 mL of solution is 0.0770 mol/L.
To determine the molar concentration of a solution formed by dissolving 450.0 mg of NaCl (sodium chloride) in 100.0 mL of solution, we need to convert the mass of NaCl to moles and then calculate the molarity (mol/L).
First, we convert the mass of NaCl to grams:
Mass of NaCl = 450.0 mg = 450.0 mg × (1 g/1000 mg) = 0.450 g
Next, we calculate the number of moles of NaCl using its molar mass:
Molar mass of NaCl = 58.44 g/mol
Number of moles of NaCl = mass of NaCl / molar mass of NaCl
Number of moles of NaCl = 0.450 g / 58.44 g/mol = 0.00770 mol
Now, we can determine the molar concentration (Molarity) of the solution using the formula:
Molarity (M) = Number of moles / Volume of solution in liters
Volume of solution = 100.0 mL = 100.0 mL × (1 L/1000 mL) = 0.100 L
Molarity (M) = 0.00770 mol / 0.100 L = 0.0770 mol/L
Therefore, the molar concentration of the NaCl solution formed by dissolving 450.0 mg of NaCl in 100.0 mL of solution is 0.0770 mol/L.
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