Cami starts with $7 and saves $13 each week.
Maggie starts with $11 and saves $13 each week. After how many weeks will Cami and Margaret have the same amount of
money?

Answer:

Move all terms not containing

x

to the right side of the inequality.

Inequality Form:

x > 48

Interval Notation:

(48,∞)

Hope this helps

\(~~~~~12x+4y = -36\\\\\implies 3x +y = -9\\\\\implies y = -3x -9\)

         - - - - - - - - - - - - - - - - - - - -- - - - - - - - - - -- - - - - - -- - - - - - - - --

\(\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\)

Write 12x+4y=-36 in slope intercept form.

\(\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\)

Slope intercept form looks like so:-

y=mx+b

Right now the line's equation is written in standard form, ax+by=c.

First, subtract 12x on both sides:-

4y=-36-12x

Now divide by 4 on both sides:-

y=-9-3x

On further simplification,

switch -9 and -3x places (it's not mandatory)

y=-3x-9

That's our equation in slope intercept form.

          - - - - - - - - - - - - - - - - - - - -- - - - - - - - - - - - - - - - - - - - - - -- - - -

Answer:

A

Step-by-step explanation:

(a) Using the Trapezoidal rule, T8 = (1/16)[cos(0) + 2cos(1/16) + 2cos(2/16) + ... + 2cos(7/16) + cos(1)].

Using the Midpoint rule, M8 = (1/8)[cos(1/16) + cos(3/16) + ... + cos(15/16)].

(b) The error in the Trapezoidal rule is bounded by (1/2880)(1-0)^3(max|f''(x)|), where f''(x) = -4x^2sin(x^2) and 0 <= x <= 1. Therefore, the error in T8 is approximately 0.00014. The error in the Midpoint rule is bounded by (1/1920)(1-0)^3(max|f''(x)|), which gives an approximate error of 0.00011 for M8.

(c) Let n be the number of intervals in the approximation.

Then, the error bound for the Trapezoidal rule is (1/2880)(1-0)^3(max|f''(x)|)(1/n^2), and the error bound for the Midpoint rule is (1/1920)(1-0)^3(max|f''(x)|)(1/n^2).

Setting these equal to 0.0001 and solving for n, we get n >= 129 and n >= 160 for the Trapezoidal and Midpoint rules, respectively. Therefore, we should choose n >= 160 to ensure that both approximations are accurate to within 0.0001.
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Answer:  3 meters downward per second

Step-by-step explanation:

If it moved downward 15 meters for every 5 seconds and to find the change in the elevation each second then divide the meters by 5.

15/5 =  3  

3 meters  per second

Answer:

eme I sh na d9 si me 08 met sup Auburndale el sn ap7 42

Answer:

Photo.

Step-by-step explanation:

A: The graph of the system is all points in the graph that suit 4x-2<y</=-5/2x-2

B: The point (-2,-2) is not included in the solution area. While it suits the second equation, it doesn't suit the first, ruling it out as a possible solution. If you plug in -2 as both y and x in the equation 4x-2>y, you'll get -8>-2, which is false. So, it is not a solution.

In space, there can be infinitely many planes that are perpendicular to a given line at a given point on that line.

The correct answer is Option D.

The key concept here is that a plane is defined by having at least three non-collinear points.

When a line is given, we can choose any two points on that line, and then construct a plane that contains both the line and those two points. By doing so, we ensure that the plane is perpendicular to the given line at the chosen point.

Since we can select an infinite number of points on the given line, we can construct an infinite number of planes that are perpendicular to the line at various points.

Thus, the correct answer is D. infinitely many planes can be perpendicular to a given line at a given point in space.

The correct answer is Option D.

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If 09 people can complete the job in 75 days then 25 people needs 45 days to complete the job.

Let T be the time and L be the Labor (Number of people working on the bridge).

T ∞ 1/√L  (Inverse relationship)

T = K/√L                   ----------------------------- (1)

Since, Constant "K" is introduced once the variation sign (∞) changes to equality (=) sign.

According to the question,

Time (T) = 75 days    and

labor (L) = 09

From the equation (1), we get,

    T = K / √L

⇒ 75   = K/√9

⇒ 75= K/3

⇒ K= 225

First, the relationship between these variables is:

                       T = 225/√L

Therefore, how long it will take 25 people to do it means that we should look for the time.

                           T=225/√L

                      ⇒  T= 225/√25

                      ⇒  T= 225/5

                      ⇒  T= 45 days.

therefore, 25 people needs 45 days to complete the job.

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a. the mean of the sampling distribution of the sample proportion is 0.46

b. the standard deviation of the sampling distribution of the sample proportion is 0.0498

c. he sample size is 100 in this case, we can assume that the sampling distribution of p^ is approximately normal.

d. the probability of having a z-score greater than 2.811 is equal to 1 - 0.9974 = 0.0026, or 0.26%.

e. the standard deviation of the sampling distribution by a factor is 0.0704

a. The mean of the sampling distribution of the sample proportion, denoted as μp^, is equal to the population proportion, which in this case is 46%.

μp^ = p = 0.46

the mean of the sampling distribution of the sample proportion is 0.46

b. The standard deviation of the sampling distribution of the sample proportion, denoted as σp^, can be calculated using the formula:

σp^ = √((p * (1 - p)) / n)

Where p is the population proportion (0.46) and n is the sample size (100).

σp^ = √((0.46 * (1 - 0.46)) / 100) = 0.0498

the standard deviation of the sampling distribution of the sample proportion is 0.0498

c. The sampling distribution of p^ is approximately normal due to the Central Limit Theorem (CLT). According to the CLT, when the sample size is sufficiently large (typically n ≥ 30), the sampling distribution of the sample proportion will be approximately normal, regardless of the shape of the population distribution. Since the sample size is 100 in this case, we can assume that the sampling distribution of p^ is approximately normal.

d. To find the probability that more than 60 households will own VCRs, we need to calculate the probability of getting a sample proportion greater than 0.6. We can standardize this value using the z-score formula:

z = (x - μp^) / σp^

Substituting the values, we have:

z = (0.6 - 0.46) / 0.0498 = 2.811

the probability of having a z-score greater than 2.811 is equal to 1 - 0.9974 = 0.0026, or 0.26%.

e. If the sample size is decreased from 100 to 50, the standard deviation of the sampling distribution of the sample proportion (σp^) would be multiplied by a factor of √(2), which is approximately 1.414. Therefore, the standard deviation would become:

New σp^ = σp^ * √(2) = 0.0498 * 1.414 = 0.0704

the standard deviation of the sampling distribution by a factor is 0.0704

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The mean of the sampling distribution of the sample proportion is 0.46. The standard deviation of the sampling distribution of the sample proportion is approximately 0.0498. The sampling distribution of p^ is approximately normal when the sample size is large enough. The probability that more than 60 households will own VCRs is approximately 0.0024. If the sample size is decreased from 100 to 50, the standard deviation of the sampling distribution would be multiplied by a factor of approximately 1.4142.

In statistics, a sampling distribution is the probability distribution of a given statistic based on a random sample. The sampling distribution of the sample proportion, denoted as p^, is the distribution of the proportions obtained from all possible samples of the same size taken from a population.

The mean of the sampling distribution of the sample proportion is equal to the population proportion. In this case, the population proportion is 46% or 0.46. Therefore, the mean of the sampling distribution of the sample proportion, denoted as μp^, is also 0.46.

The standard deviation of the sampling distribution of the sample proportion, denoted as σp^, is determined by the population proportion and the sample size. It can be calculated using the formula:

σp^ = √((p * (1 - p)) / n)

where p is the population proportion and n is the sample size. In this case, p = 0.46 and n = 100. Plugging in these values, we get:

σp^ = √((0.46 * (1 - 0.46)) / 100) = √((0.46 * 0.54) / 100) = √(0.2484 / 100) = √0.002484 = 0.0498

The sampling distribution of p^ is approximately normal when the sample size is large enough due to the Central Limit Theorem. This theorem states that the sampling distribution of a sample mean or proportion becomes approximately normal as the sample size increases, regardless of the shape of the population distribution. In this case, the sample size is 100, which is considered large enough for the sampling distribution of p^ to be approximately normal.

To calculate the probability that more than 60 households will own VCRs, we need to use the sampling distribution of p^ and the z-score. The z-score measures the number of standard deviations an observation is from the mean. In this case, we want to find the probability that p^ is greater than 0.6.

First, we need to standardize the value of 0.6 using the formula:

z = (x - μp^) / σp^

where x is the value we want to standardize, μp^ is the mean of the sampling distribution of p^, and σp^ is the standard deviation of the sampling distribution of p^.

Plugging in the values, we get:

z = (0.6 - 0.46) / 0.0498 = 2.8096

Next, we need to find the probability that z is greater than 2.8096 using a standard normal distribution table or a calculator. The probability is approximately 0.0024.

If the sample size is decreased from 100 to 50, the standard deviation of the sampling distribution of the sample proportion would be multiplied by a factor of:

√(n1 / n2)

where n1 is the initial sample size (100) and n2 is the final sample size (50). Plugging in the values, we get:

√(100 / 50) = √2 = 1.4142

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                     "

Answer:

b

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

I did this.

Answer:

it's

\( \frac{ \sqrt{3m} }{4m} \)

Using Lagrange multipliers, we found the critical points of F(x,y,z)=xyz subject to x^2+2y^2+3z^2=6. Evaluating the second derivative, we determined that these were maximum points (-5/27) and minimum points (5/27).

First, we need to write out the Lagrangian function, which is given by

L(x, y, z, λ) = xyz + λ(x^2 + 2y^2 + 3z^2 - 6)

where λ is the Lagrange multiplier. We want to find the critical points of this function, which means we need to find values of x, y, z, and λ that satisfy the following equations

∂L/∂x = yz + 2λx = 0

∂L/∂y = xz + 4λy = 0

∂L/∂z = xy + 6λz = 0

∂L/∂λ = x^2 + 2y^2 + 3z^2 - 6 = 0

We can solve the first three equations for x, y, and z in terms of λ

x = -yz/2λ

y = -xz/4λ

z = -xy/6λ

Substituting these expressions into the fourth equation gives

(-yz/2λ)^2 + 2(-xz/4λ)^2 + 3(-xy/6λ)^2 - 6 = 0

Multiplying through by λ^2/36 and simplifying, we get

-27x^2 + 8y^2 + 2z^2 = 24

Now we can substitute our expressions for x, y, and z back into this equation to get an expression for λ

-27(-yz/2λ)^2 + 8(-xz/4λ)^2 + 2(-xy/6λ)^2 = 24

Multiplying through by -36λ^2/xyz and simplifying, we get

27x^4 + 32y^4 + 4z^4 - 72x^2y^2 - 54x^2z^2 - 36y^2z^2 = 0

Now we can use the equation x^2 + 2y^2 + 3z^2 = 6 to eliminate one of the variables, say z. Solving for z in terms of x and y, we get

z = √((6 - x^2 - 2y^2)/3)

Substituting this expression into the equation we just derived for λ, we get a single equation in x and y

27x^4 + 32y^4 + 4(6 - x^2 - 2y^2)/3 - 72x^2y^2 - 54x^2(6 - x^2 - 2y^2)/9 - 36y^2(6 - x^2 - 2y^2)/18 = 0

Multiplying through by 27 and simplifying, we get

27x^4 + 864x^2y^2 + 576y^4 - 432x^2 - 864y^2 + 432 = 0

This is a quartic equation in x, which can be solved numerically to find the critical points. However, it is a bit messy to solve analytically, so I will just give you the solutions

x = ±√(2/3), y = ±√(1/6), z = ±√(5/3)

To determine whether these are maximum or minimum points, we need to check the second derivative of the Lagrangian at each point. If the second derivative is positive, it is a minimum point; if it is negative, it is a maximum point.

The second derivative of the Lagrangian is given by

∂^2L/∂xi∂xj = δijzλ

∂^2L/∂λ^2 = 0

where δij is the Kronecker delta, equal to 1 if i=j and 0 otherwise.

Plugging in the critical points we found, we get

At (√(2/3), √(1/6), √(5/3))

∂^2L/∂x^2 = λz = -√(5/3)

∂^2L/∂y^2 = λz = -√(5/3)

∂^2L/∂z^2 = xyλ = √(10/27)

Since the second derivative with respect to x and y is negative, and the second derivative with respect to z is positive, this is a maximum point.

At (-√(2/3), -√(1/6), -√(5/3))

∂^2L/∂x^2 = λz = -√(5/3)

∂^2L/∂y^2 = λz = -√(5/3)

∂^2L/∂z^2 = xyλ = √(10/27)

Since the second derivative with respect to x and y is negative, and the second derivative with respect to z is positive, this is also a maximum point.

Therefore, the maximum and minimum values of the function subject to the constraint x^2 + 2y^2 + 3z^2 = 6 are

Maximum value is -√(5/3)(√(2/3))(√(1/6))(√(5/3)) = -5/27

Minimum √(5/3)(-√(2/3))(-√(1/6))(-√(5/3)) = 5/27

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Answer:

3

Step-by-step explanation:

4/12 = 1/3 yepppp djdkkdkdd

The probability that at least 10 cabs pass you before you find one that is free is 0.00528665 or approximately 0.53%.

The solution to the problem is explained below:

Let, P(passes someone) = 0.15 or 15%

P(available taxi cab) = 0.85 or 85%

Let X be the number of cabs that pass before you find an available taxi cab. In order to find the probability that you see at least 10 cabs pass before you find a free one, we have to use the cumulative distribution function (CDF).

The probability that X is greater than or equal to 10 is equivalent to 1 - (the probability that X is less than 10). That is,P(X >= 10) = 1 - P(X < 10)

The probability that X is less than 10 is the probability of seeing 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9 taxis pass you by.

Hence,P(X < 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)P(X = 0) = P(find an available taxi cab on the 1st attempt) = P(available taxi cab) = 0.85

P(X = 1) = P(find an available taxi cab on the 2nd attempt) = P(passed by the 1st taxi cab) x P(available taxi cab on the 2nd attempt) = (1 - P(available taxi cab)) x P(available taxi cab) = 0.15 x 0.85 = 0.1275

P(X = 2) = P(passed by the 1st taxi cab) x P(passed by the 2nd taxi cab) x P(available taxi cab on the 3rd attempt) = (1 - P(available taxi cab))² x P(available taxi cab) = 0.15² x 0.85 = 0.01817

P(X = 3) = (1 - P(available taxi cab))³ x P(available taxi cab) = 0.15³ x 0.85 = 0.002585

P(X = 4) = (1 - P(available taxi cab))⁴ x P(available taxi cab) = 0.15⁴ x 0.85 = 0.0003704

P(X = 5) = (1 - P(available taxi cab))⁵ x P(available taxi cab) = 0.15⁵ x 0.85 = 0.00005287

P(X = 6) = (1 - P(available taxi cab))⁶ x P(available taxi cab) = 0.15⁶ x 0.85 = 0.000007550

P(X = 7) = (1 - P(available taxi cab))⁷ x P(available taxi cab) = 0.15⁷ x 0.85 = 0.0000010825

P(X = 8) = (1 - P(available taxi cab))⁸ x P(available taxi cab) = 0.15⁸ x 0.85 = 0.000000154

P(X = 9) = (1 - P(available taxi cab))⁹ x P(available taxi cab) = 0.15⁹ x 0.85 = 0.0000000221

Hence,P(X < 10) = 0.85 + 0.1275 + 0.01817 + 0.002585 + 0.0003704 + 0.00005287 + 0.000007550 + 0.0000010825 + 0.000000154 + 0.0000000221 = 0.99471335

P(X >= 10) = 1 - P(X < 10) = 1 - 0.99471335 = 0.00528665

Therefore, the probability that at least 10 cabs pass you before you find one that is free is 0.00528665 or approximately 0.53%.

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Answer: \(\cos 80^{\circ}\)

Step-by-step explanation:

Use the cosine double angle identity.

One vase of flowers contains eight purple tulips and six yellow tulips. A second vase of flowers contains five purple tulips and nine yellow tulips. An example of dependent events is selecting a purple tulip from the first vase and then selecting a yellow tulip.

The probability of selecting a purple tulip from the first vase is 8/14. Therefore, the probability of selecting a yellow tulip from the first vase is 6/14. Now, the second event is to select a tulip from the second vase. The event of choosing a purple tulip from the second vase is 5/14. Therefore, the second event would depend on the result of the first event. The answer is "yellow tulip" since the two events are dependent on each other.

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Mean of rt = 0.02,

Variance of rt = 0.02,

Lag-1 Autocorrelation (ρ1) = -0.01,

Lag-2 Autocorrelation (ρ2) = Unknown,

1-step ahead forecast = -0.005,

2-step ahead forecast = 0.02,

The standard deviation of forecast errors = √0.02.

We have,

To find the mean and variance of the return series, we can substitute the given model into the equation and calculate:

Mean of rt:

E(rt) = E(0.02 + 0.5rt-2 + et)

= 0.02 + 0.5E(rt-2) + E(et)

= 0.02 + 0.5 * 0 + 0

= 0.02

The variance of rt:

Var(rt) = Var(0.02 + 0.5rt-2 + et)

= Var(et) (since the term 0.5rt-2 does not contribute to the variance)

= 0.02

The mean of the return series rt is 0.02, and the variance is 0.02.

To compute the lag-1 and lag-2 autocorrelations of rt, we need to determine the correlation between rt and rt-1, and between rt and rt-2:

Lag-1 Autocorrelation:

ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))

Lag-2 Autocorrelation:

ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))

Since we are given r100 = -0.01 and r99 = 0.02, we can substitute these values into the equations:

Lag-1 Autocorrelation:

ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))

= Cov(r100, r99) / (σ(r100) * σ(r99))

= Cov(-0.01, 0.02) / (σ(r100) * σ(r99))

Lag-2 Autocorrelation:

ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))

= Cov(r100, r98) / (σ(r100) * σ(r98))

To compute the 1- and 2-step-ahead forecasts of the return series at

t = 100, we use the given model:

1-step ahead forecast:

E(rt+1 | r100, r99) = E(0.02 + 0.5rt-1 + et+1 | r100, r99)

= 0.02 + 0.5r100

2-step ahead forecast:

E(rt+2 | r100, r99) = E(0.02 + 0.5rt | r100, r99)

= 0.02 + 0.5E(rt | r100, r99)

= 0.02 + 0.5(0.02 + 0.5r100)

The associated standard deviation of the forecast errors can be calculated as the square root of the variance of the return series, which is given as 0.02.

Thus,

Mean of rt = 0.02,

Variance of rt = 0.02,

Lag-1 Autocorrelation (ρ1) = -0.01,

Lag-2 Autocorrelation (ρ2) = Unknown,

1-step ahead forecast = -0.005,

2-step ahead forecast = 0.02,

The standard deviation of forecast errors = √0.02.

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Answer:

90 I am guessing. if it's like a square or rectangle

The expectation value of the position squared when the particle in the box is in its third excited state is equal to \(\frac{9l^2}{8}\), where l is the length of the box. This is equal to nine-eighths of the length of the box squared.

The expectation value of the position squared when the particle in the box is in its third excited state can be calculated using the formula\(\langle x^2 \rangle = \frac{l^2}{8} \left( 2n^2 + 6n + 3 \right)\),

where n is the quantum number of the state and l is the length of the box. Here, n is 3, so the expectation value is equal to

\(\frac{l^2}{8} \left( 2 \times 3^2 + 6 \times 3 + 3 \right) = \frac{9l^2}{8}\).

This can be written as nine-eighths of the length of the box squared.

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Answer:

D. 82

Step-by-step explanation:

a^2 + b^2 = c^2

80^2 + 18^2 = c^2

324 + 6400 = c^2

6724 = c^2

82 = c

Answer:

Step-by-step explanation:

d because you get 1.3 and u round it to D

Answer:

option d is a correct answer....

Ratio of rise to run between the points (-2, 8) and (4, -3) = -11/6

To find the ratio of rise to run between two points, we need to calculate the difference in the y-coordinates (rise) and the difference in the x-coordinates (run) between the two points.

Given points:

Point 1: (-2, 8)

Point 2: (4, -3)

Rise = difference in y-coordinates = y2 - y1 = -3 - 8 = -11

Run = difference in x-coordinates = x2 - x1 = 4 - (-2) = 6

Therefore, the ratio of rise to run can be calculated as:

Ratio of rise to run = Rise / Run = -11 / 6

Thus, the ratio of rise to run between the points (-2, 8) and (4, -3) is -11/6.

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Answer:

down

Step-by-step explanation:

Answer:

\(15 - 10c = 13 \\ 10c = 15 - 13 \\ 10c = 2 \\ c = \frac{2}{10} \\ c = \frac{1}{5} \)

Firstly, we need to know the speed of the object in order to calculate the distance it traveled. If we have the speed, we can use the formula distance = speed x time to find the total distance traveled during the 10.0-second time interval.

Secondly, if we don't have the speed, we can use the equation of motion: distance = (initial velocity x time) + (1/2 x acceleration x time squared). This equation takes into account the initial velocity of the object as well as any acceleration that occurred during the time interval.

Lastly, if we have information about the velocity and acceleration of the object, we can use the kinematic equations to find the distance traveled. These equations relate the velocity, acceleration, time, and distance of an object in motion.
In conclusion, to find the total distance traveled by an object during a 10.0-second time interval, we need to know the speed, initial velocity and acceleration of the object. Once we have this information, we can use the formulas and equations mentioned above to calculate the distance traveled.

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