Can a binomial be multiplied by a monomial such that the product is a monomial? If so, give an example.(1 point)

Yes. 0(2x+y)=0

No. A binomial can never be multiplied by a monomial such that the product is a monomial.

Yes. 1(2x+y)=2x+y

Yes. 2(2x+y)=4x+2y

Answers

Answer 1

No, you can’t multiply a monomial and binomial together and have a product of a monomial.


Related Questions

PLEASE HELP I’LL GIVE BRAINLIEST!

Questions:
1. How do you solve for a specific variable?
2. Why would you want to solve for a specific variable?
3. Show an example of solving for a specific variable.

Answers

Here the first one, One goal in solving an equation is to have only variables on one side of the equal sign and numbers on the other side of the equal sign. The other goal is to have the number in front of the variable equal to one. The strategy for getting the variable by itself with a coefficient of 1 involves using opposite

A survey of shoppers at a grocery store found that 40% of shoppers were buying food for a week or more. If 50 shoppers were surveyed, how many shoppers were buying food for a week or more?(1 point)

(blank) shoppers were buying food for a week or more.

ITS DUE IN 30 MINUTES PLEASE HELP!!

GIVING AWAY 20 POINTS!!

Answers

The number of shoppers that were buying food for a week or more is 20 shoppers.

How to calculate the percentage?

It was as illustrated that the survey of shoppers at a grocery store found that 40% of shoppers were buying food for a week or more.

Since 50 shoppers were surveyed, the number of people buying the food will be:

= Percentage × Total shoppers

= 40% × 50

= 0.4 × 50

= 20

Therefore, the number is 20.

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-16<8/3t solve the inequality


PLEASE DO IT QUICK

Answers

Answer: (-6, infinty)

Step-by-step explanation:

Please anyone help I’m stuck

Please anyone help Im stuck

Answers

Answer:

a=10.35

Step-by-step explanation:

Hey There!

All you have to do is plug in the L and W value

a= 4.5(2.3)

4.5x2.3=10.35

so a=10.35

What is the a50 of -4, 1,6, 11

Answers

is:

an = a1 + (n-1)d

Where:
n is the term number (n = 1, 2, 3, ...)
an is the nth term in the sequence
a1 is the first term in the sequence = -4
d is the common difference
To find the common difference, subtract any two successive terms: 1 - (-4) = 5, 6 - 1 = 5, 11 - 6 = 5. So we have d = 5. Hence the explicit form for this sequence is:

an = -4 + (n-1)5

To find a50, set n = 50 in the above formula and compute the answer.

Which equation represents a linear function?
y = 4x³ + 1
y = x²
y = 2x +4
y = 2x² - 5

Answers

I think it’s x^2. If I’m not mistaken, Linear is a straight line. y=x^2 is a straight line.

what is the vaule 7 to the 6 power

Answers

Answer:

117,649

Step-by-step explanation:

Good luck! <3

Answer:

7 to the 6th power is conventionally written as 76, with superscript for the exponent, but the notation using the caret symbol ^ can also be seen frequently: 7^6.

76 stands for the mathematical operation exponentiation of seven by the power of six.

As the exponent is a positive integer, exponentiation means a repeated multiplication:

The exponent of the number 7, 6, also called index or power, denotes how many times to multiply the base (7).

Thus, we can answer what is 7 to the 6th power as

7 to the power of 6 = 76 = 117649.

What is the parent function of the following function: f(x) = |x - 31| – 2
o linear
o absolute value
O constant
o quadratic​

What is the parent function of the following function: f(x) = |x - 31| 2 o linearo absolute valueO constant

Answers

Absolute value is the answer to this question!



After forming a line, every even member of a marching band turns to face the home team's end zone and marches 5 paces straight forward. At the same time, every odd member turns in the opposite direction and marches 5 paces straight forward. Assuming that each band member covers the same distance, what formation should result? Justify your answer.

Answers

The geometric formation that should result after the described marching sequence is a rectangle.

In the given scenario, every even member of the marching band turns to face the home team's end zone and marches 5 paces straight forward, while every odd member turns in the opposite direction and marches 5 paces straight forward. Since each band member covers the same distance, it implies that the even and odd members will end up at the same distance from their starting point.

Consider the initial arrangement of the band members in a straight line. As the even members move forward, they form one side of the rectangle, while the odd members moving in the opposite direction form the adjacent side. The remaining sides of the rectangle are formed by the band members at the ends of the line who continue marching straight forward.

Therefore, the marching sequence described will result in a rectangular formation.

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The formula h = rt – 16t ^2 gives a good approximation of the height h in feet that an object will reach in t seconds, when it is projected upward with an initial speed of r feet per second. Write a model for each of the following situations in problem. Solve each equation, and then use your graphing calculator to sketch the function and verify your answer.
An object is thrown upward from the ground with an initial velocity of 32 ft/sec. Find the number of seconds it takes the object to reach the ground. What is the maximum height obtained by this object?

Answers

The object reaches a maximum height of 16 feet and hits the ground at 2 seconds after being thrown upward.

To model the situation, we can use the formula h = rt – 16t^2, where r = 32 ft/sec is the initial velocity. Since the object is thrown upward, the initial height is h = 0.

To find the number of seconds it takes the object to reach the ground, we need to find the value of t when h = 0.

0 = 32t – 16t^2

Simplifying the equation, we get

0 = 16t(2 – t)

So, t = 0 or t = 2.

Since t = 0 corresponds to the initial position, the object hits the ground at t = 2 seconds.

To find the maximum height, we need to find the vertex of the parabolic function h = rt – 16t^2. The vertex of the parabola is located at t = -b/2a, where a = -16 and b = r = 32. So, t = -32/(2(-16)) = 1.

We can substitute t = 1 into the equation to find the maximum height:

h = 32(1) – 16(1)^2 = 16 ft

Using a graphing calculator, we can graph the function h = 32t – 16t^2 and confirm our results. The graph shows that the object reaches a maximum height of 16 feet at t = 1 and hits the ground at t = 2, as we calculated analytically.

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210 students for 6 teachers​

Answers

Answer: 35

Step-by-step explanation: 210 divided by 6 = 35

Not sure if this is the answer you are looking for or not.

Find the volume v of the described solid s. The base of a solid s is the triangular region with vertices (0, 0), (4, 0), and (0, 4). Cross-sections perpendicular to the y-axis are equilateral triangles.

Answers

The volume of the solid S in the given question is 5.48unit³.

What is volume?

A three-dimensional space's occupied volume is measured.

It is frequently expressed numerically in a variety of imperial or US-standard units as well as SI-derived units.

The definition of length and volume are connected.

So, the volume of the solid S:
An equilateral triangle's sides are shown as a cross-section.

An equilateral triangle's height is determined by:

\(h = sSin60 = \frac{\sqrt{3} }{2} s\)

Consequently, one triangle's area is:

\(A=\frac{1}{2} s h=\frac{1}{2} s \cdot \frac{\sqrt{3}}{2} s=\frac{\sqrt{3}}{4} s^2\)

The line equation that depicts the diagonal is:

\(\begin{aligned}& x+y=1 \\& y=-x+1 \\& x=-y+1\end{aligned}\)

This will indicate the s value integrate from 0 to 2 if we integrate along the y-axis.

\(\begin{aligned}& V=\int_0^2 \frac{\sqrt{3}}{4} s^2 d x \\& =\frac{\sqrt{3}}{4} \int_0^2(-y+1)^2 d x \\& =\frac{\sqrt{3}}{4} \int_0^2\left(y^2-2 y+1\right) d x \\& =\frac{\sqrt{3}}{4}\left[\frac{1}{3} y^3-y^2+y\right] \\& \left.=\frac{\sqrt{3}}{4}\left[\frac{1}{3}(2)^3-(2)^2+2\right)\right] \\& =5.48\end{aligned}\)

Therefore, the volume of the solid S in the given question is 5.48unit³.

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Correct question:
Find the volume V of the described solid S. The base of S is the triangular region with vertices (0, 0), (2, 0), and (0, 2). Cross-sections perpendicular to the y-axis are equilateral triangles.

A circle with centre C(-3, 2) has equation x² + y² + 6x - 4y = 12 (a) Find the y-coordinates of the points where the circle crosses the y-axis. (b) Find the radius of the circle. (c) The point P(2,5) lies outside the circle. (i) Find the length of CP, giving your answer in the form √n, where n is an integer. (ii) The point Q lies on the circle so that PQ is a tangent to the circle. Find the length of PQ.

Answers

a) The circle crosses the y-axis at the points (0, 6) and (0, -2). b) the radius of the circle is 5. c) (i) The length of CP is √34. (ii) The length of PQ is 10.

(a) To find the y-coordinates of the points where the circle crosses the y-axis, we substitute x = 0 into the equation of the circle:

0² + y² + 6(0) - 4y = 12

y² - 4y = 12

y² - 4y - 12 = 0

To solve this quadratic equation, we can factor it:

(y - 6)(y + 2) = 0

Setting each factor to zero, we find two possible values for y:

y - 6 = 0 => y = 6

y + 2 = 0 => y = -2

Therefore, the circle crosses the y-axis at the points (0, 6) and (0, -2).

(b) To find the radius of the circle, we can complete the square to rewrite the equation of the circle in standard form:

x² + y² + 6x - 4y = 12

(x² + 6x) + (y² - 4y) = 12

(x² + 6x + 9) + (y² - 4y + 4) = 12 + 9 + 4

(x + 3)² + (y - 2)² = 25

Comparing this equation with the standard form of a circle, (x - h)² + (y - k)² = r², we can see that the center of the circle is at (-3, 2) and the radius is √25 = 5.

Therefore, the radius of the circle is 5.

(c) (i) To find the length of CP, we can use the distance formula between two points. The coordinates of C are (-3, 2), and the coordinates of P are (2, 5).

The distance formula is given by:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

Substituting the coordinates into the formula, we have:

CP = √((2 - (-3))² + (5 - 2)²)

= √(5² + 3²)

= √(25 + 9)

= √34

Therefore, the length of CP is √34.

(ii) To find the length of PQ, we can use the fact that PQ is a tangent to the circle. The radius of the circle is 5, and the line segment CP is perpendicular to PQ.

Since CP is perpendicular to PQ, CP is the radius of the circle. Therefore, CP = 5.

Therefore, the length of PQ is equal to 2 times the length of CP:

PQ = 2 * CP

= 2 * 5

= 10

Therefore, the length of PQ is 10.

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For the function F(x)=1/x+1 which of these could be a value of F(x) when x is close to -1

For the function F(x)=1/x+1 which of these could be a value of F(x) when x is close to -1

Answers

The value of the function as x tends to -1 is an infinite value.

Given the function f(x) = 1/(x+1)

The value of f(x) as x tends to -1, is gotten by substituting the value of x given into the function as shown:

f(-1) = 1/(-1+1)

f(-1) = 1/0

f(-1) = \(\infty\)

From the result, we can see that the value of the function as x tends to -1 is an infinite value.

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To determine chilling hours for an area count the cumulative number of hours between November 1st and February 15th that the air temperatures is between 32 and 45 degrees F. Group of answer choices True False

Answers

The statement "To determine chilling hours for an area, count the cumulative number of hours between November 1st and February 15th that the air temperature is between 32 and 45 degrees F" is true.

In horticulture, chilling hours are the number of hours in which the air temperature is between 32 and 45 degrees Fahrenheit and are commonly used in fruit crop production to determine the required winter rest period. It is calculated between November 1st and February 15th since these months are considered the winter season and are known for their cool temperatures.

Chilling hours are an essential factor in determining the growth, development, and yield of fruit trees, which require a particular amount of chilling hours to flower and bear fruit.

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Find all real zeros of the function. \[ f(x)=3\left(x^{2}+49\right)(x-4)(x+7)^{2} \] If there is more than one answer, separate them with commas.

Answers

The real zeros of the function are \(x = 4\) and \(x = -7\).

To find the real zeros of the function \[ f(x)=3\left(x^{2}+49\right)(x-4)(x+7)^{2} \], we need to set the function equal to zero and solve for x.

Setting the function equal to zero, we have:
\[ 3\left(x^{2}+49\right)(x-4)(x+7)^{2} = 0 \]

Since we are looking for real zeros, we can ignore the term \((x^{2}+49)\) because it is always positive and does not affect the zeros of the function.

Now, let's examine each factor separately:

1. \((x-4)\):
Setting \((x-4)\) equal to zero, we get \(x = 4\).

2. \((x+7)^{2}\):
Setting \((x+7)^{2}\) equal to zero, we get \(x = -7\) (double zero).

Therefore, the real zeros of the function are \(x = 4\) and \(x = -7\).

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A function is a fifth-degree polynomial. how many turning points can it have? exactly four exactly five four or less five or less

Answers

A fifth-degree polynomial function can have five turning points in its graph.

What is a quintic function?In other terms, a polynomial of degree 5 defines a quintic function. When graphed, normal quintic functions resemble normal cubic functions since they have an odd degree, with the possible exception that they might contain an extra local maximum and/or local minimum. 9x5– 2x + 3x4– 2 – A leading term to the fifth degree and a term to the fourth degree are both included in this four-term polynomial. It is known as a polynomial of fifth degree.The given polynomial must be factored as much as feasible in order to solve a polynomial equation of degree 5. We can solve for the variable after factoring by equating factors to zero.Examples of polynomials with degrees include the following: The degree of the polynomial 5x5+4x2-4x+3 is 5

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Answer:

The correct is answer is option C: "four or less"

The answers to the next  part of the question on Edge are options A and C :)

Step-by-step explanation:

Hope this helped!

Brainliest would be greatly appreciated - Have a great day :3

in a reaction time study involving 12 participants, the number of participants whose average time is between 400 and 600 milliseconds

Answers

Using the concepts of continuous and discrete variables it is found that the reaction time of students would be a continuous variable.

What is the missing information?

This problem is incomplete, but researching it on a search engine, it asks to classify the variable reaction time of students as discrete or continuous.

What are continuous and discrete variables?

Continuous variables: Can assume decimal values.Discrete variables: Assume only countable values, such as 0, 1, 2, 3, …

A reaction time of 500.5 milliseconds is a valid reaction time, hence a decimal value is accepted, meaning that the reaction time of students would be a continuous variable.

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How and when National Assembly formed and what was its significance?

Answers

During the French Revolution, the National Assembly, which existed from 17 June 1789 to 29 September 1791, was a revolutionary assembly of the Kingdom of France formed by the representatives of the Third Estate of the Estates-General.

The parliament during the French Revolution was formed by the people of the Third Estate who sought proportional representation in the assembly of King Louis XVI walked out of their meeting and assembled themselves into a parliament, which they called the National Assembly.

Significance

1) It issued decrees abolishing obligations and taxes .

2) Privileges of the Nobles and the Clergy were taken away.

3)It was an innovative association established by the delegates of the Third Estate which was also recognized as   National Constituent Assembly .

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market classes and grades encompass descriptive terminology of carcasses and products for the understanding of different groups or buyers.

Answers

Market classes and grades are used to describe the quality and characteristics of agricultural products, including meat, poultry, fruits, and vegetables.  True

They provide a common language for buyers and sellers to communicate about the characteristics, such as the age, sex, fat content, and muscling, of the product. Market classes and grades help ensure that buyers receive products that meet their quality standards and help sellers receive a fair price for their products. For example, beef is graded based on marbling, maturity, and lean color, with the highest grade being USDA Prime, followed by USDA Choice and USDA Select.

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Full Question: market classes and grades encompass descriptive terminology of carcasses and products for the understanding of different groups or buyers. T/F

This standardized system of classification allows for easier communication and understanding between buyers and sellers, and ensures consistency and fairness in the marketplace.

Market classes and grades refer to the categorization and labeling of carcasses and products based on their quality and characteristics. These classifications use descriptive terminology that is understood by different groups of buyers, such as meat packers, wholesalers, retailers, and consumers. Market classes typically group animals based on their intended use, such as beef cattle for slaughter, while grades are assigned based on factors such as maturity, marbling, and fat content. This standardized system of classification allows for easier communication and understanding between buyers and sellers, and ensures consistency and fairness in the marketplace.

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Rocky Mountain Tire Center sells 10,000 ​go-cart tires per year. The ordering cost for each order is ​$35​, and the holding cost is 40​% of the purchase price of the tires per year. The purchase price is ​$25 per tire if fewer than 200 tires are​ ordered,​$17 per tire if 200 or​ more, but fewer than 8,000​, tires are​ ordered, and ​$13 per tire if 8,000 or more tires are ordered.

a) How many tires should Rocky Mountain order each time it places an​ order?

​b) What is the total cost of this​ policy?

Answers

a) Rocky Mountain should order 200 tires each time it places an order.

b) The total cost of this policy is $17,160.

a) To determine how many tires Rocky Mountain should order each time, we need to consider the different price levels and find the point where it is most cost-effective to order. Let's analyze the three price levels:

If fewer than 200 tires are ordered: The purchase price is $25 per tire.

If 200 or more, but fewer than 8,000 tires are ordered: The purchase price is $17 per tire.

If 8,000 or more tires are ordered: The purchase price is $13 per tire.

Since the ordering cost is $35 per order, it is most cost-effective to order the maximum quantity that falls within the second price level, which is 200 tires.

b) To calculate the total cost of this policy, we need to consider the ordering cost and the holding cost. The holding cost is 40% of the purchase price per tire per year. Let's calculate the total cost:

Total holding cost = (Purchase price per tire * Quantity ordered * Holding cost rate) / 2 = (($17 * 10,000 * 0.4) / 2) + (($13 * 2,000 * 0.4) / 2) = $34,000 + $5,200 = $39,200

Total cost = Total ordering cost + Total holding cost = (Ordering cost per order * Number of orders) + Total holding cost = ($35 * (10,000 / 200)) + $39,200 = $1,750 + $39,200 = $40,950

Therefore, the total cost of this policy is $40,950.

Rocky Mountain Tire Center should order 200 tires each time it places an order, resulting in a total cost of $40,950 for this policy. This ordering quantity and cost analysis allows Rocky Mountain to make efficient and cost-effective decisions in managing their inventory.

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Help plsssssssss i don't know this!!!!!!!!!!!!!!!!

Help plsssssssss i don't know this!!!!!!!!!!!!!!!!

Answers

Answer: a

Step-by-step explanation: I did the test

Answer:

The total cost is $6.25

Step-by-step explanation:

3/4 of 1 kilo of rect

4/5 of 1 kilo of square

3/5 of 1 kilo of flower

rect = 3 per kilo

square = 3 per kilo

flower = 3 per kilo

First rectangle beads:

3x = y where x is number of kilos and y is full cost

3(3/4) = y

9/4 = y = 2 1/4 = $2.25

Second square beads:

3x = y where x is number of kilos and y is full cost

3(4/5) = y

12/5 = y = 2 2/5 = $2.20

Third flower beads:

3(x) = y where x is number of kilos and y is full cost

3(3/5) = y

9/5 = y = 1 4/5 = $1.80

Add costs together

1.80 + 2.20 + 2.25 = 6.25

The total cost is $6.25

What is the decimal equivalent of 18/5

Answers

The correct answer is 3.6 because you only divide 18 by 5 and you'll get your answer.

The decimal equivalent of 18/5 is 3.6.

What is the decimal equivalent of 18/5?

To convert a fraction to a decimal, you divide the top number by the bottom number. In this situation, you take the number 18 and divide it by the number 5.

When you divide, you get 3 as your answer and you have 3 left over. So, the decimal equivalent is 3. 6

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A researcher claims that the amounts of acetaminophen in a certain brand of cold tablets have a standard deviation different from the Sigma= 3.3 mg claimed by the manufacturer. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is a failure to reject the null hypothesis, state the conclusion in nontechnical terms.

a) There is not sufficient evidence to support the claim that the standard deviation is different from 3.3 mg.

b) There is sufficient evidence to support the claim that the standard deviation is equal to 3.3 mg.

c) There is sufficient evidence to support the claim that the standard deviation is different from 3.3 mg.

d) There is not sufficient evidence to support the claim that the standard deviation is equal to 3.3 mg

Answers

The conclusion for the hypothesis test of the claim regarding the standard deviation of acetaminophen in cold tablets is that 'There is not sufficient evidence to support the claim that the standard deviation is different from 3.3 mg'. Therefore, the correct option is option A.

The reasoning behind this conclusion is that the hypothesis test failed to reject the null hypothesis, which means there was not enough evidence to prove that the standard deviation is different from the manufacturer's claimed value of 3.3 mg. Therefore, we cannot support the researcher's claim, and we stick with the original assumption that the standard deviation is indeed 3.3 mg.

Hence, the correct answer is option A: There is not sufficient evidence to support the claim that the standard deviation is different from 3.3 mg.

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need help with this. This is all one problem. The directions are numbered 1-6

need help with this. This is all one problem. The directions are numbered 1-6
need help with this. This is all one problem. The directions are numbered 1-6

Answers

Given the inequality:

\(2-|3x-5|>-7\)

To find x, follow the steps below.

Step 01: Isolate the absolute value.

To do it, first, subtract 2 from both sides of the inequality.

\(\begin{gathered} 2-|3x-5|-2>-7-2 \\ 2-2-|3x-5|>-9 \\ -|3x-5|>-9 \end{gathered}\)

Now, multiply the equation by -1:

\(|3x-5|<9\)

If |3x - 5| < 9, then 3x - 5 < 9 or -(3x - 5) < 9.

Step 02: Find the interval in which 3x - 5 < 9.

\(3x-5<9\)

Isolate x by adding 5 to both sides. In sequence, divide the sides by 3:

\(\begin{gathered} 3x-5+5<9+5 \\ 3x<14 \\ \frac{3x}{3}<\frac{14}{3} \\ x<\frac{14}{3} \end{gathered}\)

Step 03: Find the interval in which -(3x - 5) < 9.

\(-3x+5<9\)

To isolate x, first, subtract 5 from both sides. Second, divide the sides by 3. Finally, multiply the inequality by -1.

\(\begin{gathered} -3x+5-5<9-5 \\ -3x<4 \\ \frac{-3x}{3}<\frac{4}{3} \\ -x<\frac{4}{3} \\ x>-\frac{4}{3} \end{gathered}\)

Step 04: Graph the interval.

Since x < 14/3 and x > -4/3:

Graphing the answer:

Step 05: Write your answer in interval notation.

\(-\frac{4}{3}In interval notation:

\((-\frac{4}{3},\frac{14}{3})\)

Step 06: Double-check the solution.

To double-check the solution, choose one point inside the interval and observe if the answer fits the equation. You can also choose a point outside the interval.

Let's choose x = 0 (inside the interval) and x = 5 (outside the interval).

\(\begin{gathered} 2-|3x-5|>-7 \\ \end{gathered}\)

Substituting x by 0.

\(\begin{gathered} 2-|3\cdot0-5|>-7 \\ 2-|0-5|>-7 \\ 2-|5|>-7 \\ 2-5>-7 \\ -3>-7 \end{gathered}\)

True.

Substituting x by 5.

\(\begin{gathered} 2-|3x-5|>-7 \\ 2-|3\cdot5-5|>-7 \\ 2-|15-5|>-7 \\ 2-|10|>-7 \\ -8>-7 \end{gathered}\)

False, since -8 is not greater than -7. It is expected since 5 is not an answer for this inequality.

Answer:

\((-\frac{4}{3},\frac{14}{3})\)

need help with this. This is all one problem. The directions are numbered 1-6

Find positive numbers x and y satisfying the equation xy such that the sum xy is as small as possible.

Answers

To find positive numbers x and y that satisfy the given condition, we need to minimize the sum x + y while keeping the product xy constant. We can use the Arithmetic Mean-Geometric Mean (AM-GM) Inequality for this problem. The AM-GM inequality states that the arithmetic mean of a set of non-negative numbers is always greater than or equal to the geometric mean of the same numbers.

In this case, we have two numbers, x and y. The arithmetic mean of x and y is (x + y)/2, and the geometric mean is √(xy). According to the AM-GM inequality, we have:

(x + y)/2 ≥ √(xy)

Multiplying both sides by 2, we get:

x + y ≥ 2√(xy)

Now, we want to minimize the sum x + y, which means we need to find the minimum value for the right-hand side of the inequality. The minimum value occurs when the inequality becomes an equality:

x + y = 2√(xy)

To achieve this equality, x must be equal to y (x = y). This is because the arithmetic mean and geometric mean are equal only when all the numbers in the set are equal. Therefore, x = y and the product xy will have the minimum sum. The exact values of x and y will depend on the given constraint for the product xy.

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Is the sum of 3+ The Square root of 7 a rational number?

Answers

Answer:

yes

Step-by-step explanation: i did a test like 2 weeks ago and this was a question and i got it right

the graph below shows the relation of the number of hay bales to wagon loads. how many bales of hay can be delivered in 8 wagon loads?

the graph below shows the relation of the number of hay bales to wagon loads. how many bales of hay can

Answers

Answer:

the answer is 8 wagons brings 16 bales of hay

Step-by-step explanation:

Hi, I can use some help wiTh this thanks!

Hi, I can use some help wiTh this thanks!

Answers

Answer:

Square root of 9 = 3 ! ^^

Step-by-step explanation:

\(3*3=9 \\3^{2}=9\\\sqrt{9} = 3\)

^^

the square root of 9 is three because 3 to the power of two, or three squared is 9

if x doesn't equal 0 and x/2=y^2 and x/4=4y then what is x​

Answers

The value of x is 128, for equations x/2=y² and x/4=4y

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given,

x/2=y²...(1) and

x/4=4y ...(2)

We need to find value of x and  x not equal to zero

x=2y²

Substitute in equation 2

2y²/4=4y

y²/2=4y

y/2=4

y=8

Now substitute in equation 2

x/4=4(8)

x/4=32

x=128

Hence the value of x is 128, for equations x/2=y² and

x/4=4y

To learn more on Equation:

https://brainly.com/question/10413253

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