Can someone help me with this please

Answer:

x = 5

Step-by-step explanation:

I'm assuming the question is asking to solve for variable x.

The two red arrows signify the two lines are congruent, meaning they equal the same measurement.

In other words:

23x - 5 = 21x + 5

Isolate the variable x

Add 5 to both sides to cancel 5 from the left side

23x - 5 + 5 = 21x + 5 + 5

23x + 0 = 21x + 10

23x = 21x + 10

Subtract 21x from both sides to cancel 21x from the right side

23x - 21x = 21x - 21x + 10

2x = 0x + 10

2x = 10

Divide both sides by 2 to isolate the variable x

2x ÷ 2 = 10 ÷ 2

x = 5

When solving for these types of problems, always isolate the variable. Also, keep in mind that whatever you do to one side, you must do to the other (such as how I added 5 to both sides).

Answer:

X = 6

Step-by-step explanation:

Am tired 2 show the work

Answer:

=-6

Step-by-step explanation:

Move all terms containing x to the left side of the equation.

x−4=−10

Move all terms not containing x to the right side of the equation.

Add 4 to both sides of the equation.

x=−10+4

Add −10 and 4

X=-6

Answer: A.897.5 */* 100

Step-by-step explanation:

Answer:

There are no solutions.

Step-by-step explanation:

−2(4x−2)<−8x+4

Step 1: Simplify both sides of the inequality.

−8x+4<−8x+4

Step 2: Add 8x to both sides.

−8x+4+8x<−8x+4+8x

4<4

Step 3: Subtract 4 from both sides.

4−4<4−4

0<0

Answer:

7.5

Step-by-step explanation:

-(-1.5) = 1.5 + 6 = 7.5

1. Independent random samples arise when one random sample is split into groups differing by an observed feature is incorrect.

2. The margin of error of a confidence interval about the difference between the means of two populations is equal to half the width of the confidence interval.

1. Independent random samples arise when individuals in a sample are randomly assigned to experimental groups, data is recorded repeatedly on a random sample of individuals, or random samples are selected separately. The statement that one random sample is split into groups differing by an observed feature does not accurately describe independent random samples.

2. The margin of error in a confidence interval represents the range of values within which the true population parameter is likely to fall. It is calculated by taking half of the width of the confidence interval. Therefore, the correct answer is that the margin of error is equal to half the width of the confidence interval.

In summary, the incorrect statement is that independent random samples arise when one random sample is split into groups differing by an observed feature. The margin of error of a confidence interval about the difference between the means of two populations is equal to half the width of the confidence interval.

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Answer:

looks like 30

Step-by-step explanation:

Answer:

Step-by-step explanation:

is this in college?

By answering the given question, we may state that Therefore, the value equation of x is 15 degrees. Answer: 15.

Using the equals symbol (=) to indicate equivalence, a math equation links two statements. Algebraic equations prove the equality of two mathematical expressions by a mathematical assertion. The equal sign, for example, provides a gap between the numbers 3x + 5 and 14 in the equation 3x + 5 = 14. You can use a mathematical formula to understand the connection between the two phrases that are written on opposite sides of a letter. Most of the time, the logo and the particular software match. e.g., 2x - 4 = 2 is an example.

By definition of complementary angles, ∠1 and ∠2 add up to 90 degrees:

∠1 + ∠2 = 90°

x + (3x + 30) = 90

4x + 30 = 90

4x = 60

x = 15

Therefore, the value of x is 15 degrees. Answer: 15.

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The value of m and n from the obtained probability is equal to 3 and 14 respectively.

As given in the question,

Nine tiles numbered 1, 2, .....9

Number of odd numbered tiles are 1,3,5,7,9 = 5

Number of even numbered tiles are 2,4,6,8 = 4

Number of players =3

Possibility to choose 3 tiles by first player out of 9 tiles = ⁹C₃

                                                                                            = 84 ways

Possibility to choose 3 tiles by second player out of 6 tiles = ⁶C₃

                                                                                                 =20 ways

Possibility to choose 3 tiles by third player out of 3 tiles = ³C₃

                                                                                             = 1 way

Total number of ways = 84× 20 ×1

                                     = 1680

To have a sum of 3 tiles is odd number at least one tile should be odd.

Chances of first player all the 3 tiles are 0dd out of 5 = ⁵C₃

Next two players must 2 even tiles and 1 odd tile.= ²C₁

One player can be selected in ³C₁ way

Remaining 4 even tiles distributed equally = (4!)(2!)/ (2!)² ( 2!)

Number of favourable outcomes =  ⁵C₃ × ²C₁ ׳C₁  × (4!)(2!)/ (2!)² ( 2!)

                                                       = 10 × 2 × 3 × 6

                                                       = 360

Probability (m/n) =  360 /1680

                            = 3/14

m = 3 and n = 14.

Therefore, from the probability that all three players obtain an odd sum is m/n , the value m = 3 and n = 14.

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Answer:

b

Step-by-step explanation:

add all of his assets together

his assets are the numbers listed in the right side of the chart.

4,091 + 25,800 + 3,940 + 2,143 + 9,400 + 21,500 + 34,805

= 101,679

the answer is b

good luck!

Answer:

300° - 720°

Step-by-step explanation:

Co-terminal angles:  Angles that have the same initial side and the same terminal sides.

The co-terminal angle is found by adding or subtracting 360°n (or 2πn if working in radians) to the given angle.

Given angle:

Therefore, co-terminal angles of 300° are:

⇒ 300° + 360°n = 660°, 1020°, ...

⇒ 300° - 360°n = -60°, -420°, ...

Therefore, the expression that finds the measure of an angle that is co-terminal with a 300° angle is one that adds or subtracts a multiple of 360°:

300° - 2(360°) = 300° - 720°

Answer:

-25

Step-by-step explanation:

-3b-75=0

    +75 +75

-3b=75

/-3    /-3

b=-25

There isn't 2 solutions

---

hope it helps

To solve a differential equation with exponential equations, start by isolating the dependent variable and any coefficients that may exist on either side of the equation. Next, take the natural logarithm of both sides of the equation and use the properties of logarithms to simplify the equation. Solve for the dependent variable. Finally, take the exponential of both sides of the equation and simplify it to get the solution.

For example, consider the differential equation dy/dx = 2y.

Isolate the dependent variable to get y = dx/2.

Then, take the natural logarithm of both sides to get ln(y) = ln(dx/2).

Use the property ln(a/b) = ln(a) - ln(b) to get ln(y) = ln(dx) - ln(2).

Solve for ln(y) to get ln(y) = ln(dx) - ln(2).

Then, take the exponential of both sides to get \(y = e^{ln(dx) - ln(2)}\) and simplify to get the solution \(y = (dx/2) e^{ln(dx)}\).

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Limit of the given function does not exist.

Hence, option C is correct.

In the given graph;

The limit of x is tending towards 2

When limit x approaches  2 from right side,

The function becomes

F(x) = -2

When limit x approaches  2 from left side,

The function becomes

F(x) = 3

Since both limit are not equal,

Therefore,

Limit of f(x) does not exist.

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The complete question is:

Find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x..

A.) Does not exist; does not exist

B.)1;1

C.)-2;3

D.)3;-2

The volume of the solid, obtained by revolving the region bounded by xy = 1, y = 0, x = 1, and x = 2, using the washer method, is: a) π/2 cubic units when revolved about the axis x = -1 and b) 7π/6 cubic units when revolved about the x-axis.

What is washer method?

The washer method is a technique used to calculate the volume of a solid of revolution. It involves integrating the cross-sectional area of the solid, which is obtained by subtracting the inner area from the outer area of a "washer" or "annulus" shape.

a) To find the volume when revolved about the axis x = -1, we consider the slices perpendicular to the x-axis. Each slice will have a radius equal to the distance from the axis of revolution to the curve, which is x + 1. The differential thickness of the slice is dx.

Thus, the volume of each washer-shaped slice is π(radius_outer² - radius_inner²)dx. Integrating this expression from x = 1 to x = 2, we get the volume as π/2 cubic units.

b) When revolved about the x-axis, we consider the slices perpendicular to the y-axis. The radius of each slice is y, and the differential thickness is dy. The limits of integration are y = 1 and y = 2. Using the washer method and integrating π(radius_outer² - radius_inner²)dy, we find the volume to be 7π/6 cubic units.

Therefore, the volume of the solid when revolved about the axis x = -1 is π/2 cubic units, and when revolved about the x-axis is 7π/6 cubic units.

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The task requires analyzing a list of departments and performing several tasks related to relationship codes, activity relationship diagrams, reason codes, a worksheet, and a dimensionless block diagram.

We need to consider the number of departments. Since we have 7 departments listed, the number of relationship codes can be calculated using the formula: (n * (n-1)) / 2, where n is the number of departments.

Substituting the value of n = 7, we get:

Relationship Codes = (7 * (7-1)) / 2

= (7 * 6) / 2

= 42 / 2

= 21

Therefore, there will be 21 relationship codes in the chart.

Create an activity relationship diagram:

An activity relationship diagram visually represents the relationships between departments. Here is a basic diagram representing the given departments:

Receiving --+

           +-- Assembly & Shipping -- Offices

Fabrication--+

           +-- Painting -- Stores

Restrooms & Lockers

Populate the diagram with codes for all the relationships:

To populate the diagram with codes, we can assign a unique code to each relationship. Here's an example of assigning codes to the relationships in the diagram:

Receiving (R) --+

               +-- Assembly & Shipping (AS) -- Offices (O)

Fabrication (F)--+

               +-- Painting (P) -- Stores (S)

Restrooms & Lockers (RL)

What is the percentage of codes in each category? Does it follow the standard percentages?

To determine the percentage of codes in each category, we need to count the number of codes in each category and calculate the percentage relative to the total number of codes (21).

In this case, we have the following categories and their respective codes:

Production: R, F, AS, P (4 codes)

Administration: O, S (2 codes)

Support: RL (1 code)

Percentage of Production codes = (4 / 21) * 100 ≈ 19.05%

Percentage of Administration codes = (2 / 21) * 100 ≈ 9.52%

Percentage of Support codes = (1 / 21) * 100 ≈ 4.76%

These percentages do not necessarily follow any standard percentages. The distribution of codes among categories can vary depending on the specific organization or context.

Provide at least 3 reason codes for the chart:

Reason codes are used to provide explanations or justifications for the relationships depicted in the chart. Here are three example reason codes for the given chart:

R01: Receiving department receives raw materials and supplies from external sources.

AS01: Assembly & Shipping department assembles products and prepares them for shipment.

O01: Offices department provides administrative support and management functions for the organization.

Create a worksheet to assist in the creation of the dimensionless block diagram:

Here's an example of a worksheet that can assist in creating the dimensionless block diagram:

Relationship Code From Department To Department

R Receiving Fabrication

F Fabrication Painting

AS Assembly & Shipping Offices

P Painting Stores

RL Restrooms & Lockers -

O Offices -

S Stores -

This worksheet lists the relationship codes along with the corresponding "From" and "To" departments.

Create a dimensionless block diagram for your data B. Show the flow through the dimensionless block diagram:

A dimensionless block diagram represents the flow of activities or information between different departments. Here's an example of a dimensionless block diagram based on the given data:

Receiving --> Fabrication --> Painting --> Stores

                  |

                  v

        Assembly & Shipping --> Offices

                  |

                  v

       Restrooms & Lockers

The arrows indicate the flow of activities or information from one department to another.

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1. AABBCCDD: The probability of this happening is \(1/16\), since each parent would need to contribute a dominant allele for each gene.

2. AABBCcDD:  This genotype can be produced in two ways:

a) If both parents are homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D.

The probability of this happening is  = 1/128.

b) If one parent is homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A and B, homozygous dominant for C, and heterozygous for D.

3. The probability of this happening is 1/32.

AaBbCcDd : The probability of this happening is  1/256.

4. aaBBCcDD - This genotype can be produced in two ways:

a) If both parents are homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D. The probability of this happening is  1/128.

b) If one parent is homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A, homozygous dominant for B, homozygous dominant for C, and heterozygous for D.

The probability of this happening is  1/32.

To solve this problem, we need to use the principles of probability and Punnett squares.

For a tetrahybrid cross, we need to consider the four genes independently and combine the probabilities of each gene's alleles.

Assuming that A, B, C, and D are dominant alleles, and a, b, c, and d are recessive alleles, we can create a Punnett square for each gene, which would look like this:

A  |  A  |  a  |  a  

---|-----|-----|----

B  |  B  |  b  |  b  

---|-----|-----|----

C  |  C  |  c  |  c  

---|-----|-----|----

D  |  D  |  d  |  d  

Each box in the Punnett square represents a possible combination of alleles from the two parents.

For example, the top-left box represents offspring that inherit an A allele from the mother and an A allele from the father.

We can use these Punnett squares to calculate the probabilities of each genotype in the F2 offspring.

AABBCCDD - This genotype can only be produced if both parents are homozygous dominant for all four genes.

The probability of this happening is \((1/2)^4 = 1/16\) , since each parent would need to contribute a dominant allele for each gene.

AABBCcDD - This genotype can be produced in two ways:

a) If both parents are homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D.

The probability of this happening is\((1/2)^4 * 1/2 * (1/2)^3 = 1/128\)

b) If one parent is homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A and B, homozygous dominant for C, and heterozygous for D.

The probability of this happening is\(2 * (1/2)^4 * 1/2 * 1/2 * 1/2 = 1/32\)

AaBbCcDd - This genotype can be produced in 16 ways, since each gene can be inherited in two different ways (dominant or recessive).

The probability of this happening is \((1/2)^8 = 1/256.\)

aaBBCcDD - This genotype can be produced in two ways:

a) If both parents are homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D. The probability of this happening is\((1/2)^4 * 1/2 * (1/2)^3 = 1/128.\)

b) If one parent is homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A, homozygous dominant for B, homozygous dominant for C, and heterozygous for D.

The probability of this happening is \(2 * (1/2)^4 * 1/2 * 1/2 * 1/2 = 1/32.\)

Note that we have assumed independent assortment of the four genes, which means that the inheritance of one gene does not affect the inheritance of another gene.

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The volume of the right pyramid is 864 cm³.

The given parameters;

The volume of a right pyramid is one-third the product of the base and the perpendicular height.

The diagonal length of the right pyramid is calculated as follows;

\(d^2 = b^2 + b^2\\\\ d^2 = (\sqrt{288})^2 + (\sqrt{288} )^2 \\\\ d ^2 = 576\\\\ d = \sqrt{576} \\\\ d = 24 \ cm\)

The perpendicular height of the right pyramid is calculated as follows;

\((\frac{d}{2} )^2 + h^2 = 15^2\\\\ (\frac{24}{2})^2 + h^2 = 15^2\\\\ 144 + h^2 = 225\\\\ h^2 = 225-144\\\\ h^2 = 81\\\\ h = \sqrt{81} \\\\ h = 9 \ cm\)

The volume of the right pyramid is calculated as follows;

\(V = \frac{1}{3} \times b \times h\\\\ V = \frac{1}{3} \times 288 \times 9\\\\ V = 864 \ cm^3\)

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The five dealers included in the sample are: Dealer 02: 05, Dealer 06: 28, Dealer 09: 38, Dealer 03: 08, Dealer 11: 66

To select a random sample of five dealers from the given random numbers, we need to use a method known as random sampling without replacement, which ensures that no dealer is selected more than once.

Here are the steps to select a random sample of five dealers from the given random numbers:

Step 1: List all the dealers using the given random numbers in ascending order.02, 05, 08, 20, 21, 28, 29, 31, 38, 49, 59, 66

Step 2: Assign each dealer a number between 01 and 12. Dealer 01 corresponds to 02, dealer 02 corresponds to 05, dealer 03 corresponds to 08, and so on.

Step 3: Generate five random numbers between 01 and 12 using a random number generator or by drawing numbers from a hat. For instance, let's assume that the five random numbers we get are 02, 06, 09, 03, and 11.02 corresponds to dealer 05, 06 corresponds to dealer 28, 09 corresponds to dealer 38, 03 corresponds to dealer 08, and 11 corresponds to dealer 66.

Therefore, the five dealers included in the sample are: Dealer 02: 05, Dealer 06: 28, Dealer 09: 38, Dealer 03: 08, Dealer 11: 66

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Answer:

Step-by-step explanation:From the issue, we may deduce that:

x + y = 50 She desires to produce 50 ounces of the combination (because to this).

(0.35x) + (0.60y) = 0.55(x+y) (because we're calculating the amount of salt in each solution and the combination contains 55% salt)

We may take the first equation and replace it in the second equation:

(0.35x) + (0.60y) = 0.55(50) (50)

0.35x + 0.60y = 27.5 when x is substituted.

A system of two equations with two variables is now available:

x + y = 50\s0.35x + 0.60y = 27.5

To determine one of the variables in terms of the other, we may utilize the first equation. Let's figure out y:

y = 50 - x

We now change y in the second equation to the following expression:

0.35x + 0.60(50-x) = 27.5

Finding the value of x:

0.35x + 30 - 0.6x = 27.5

0.25x= -2.5

x= -10

Since the number of ounces cannot be negative, the answer is illogical. As a result, you should double-check your calculations or determine if the issue statement contains a mistake.

To get the answer, you can also try an alternative approach like substitution or elimination. Then, double-check your calculations.

Answer:

99/280

Step-by-step explanation:

24.75/70

Multiply the top and bottom by 100

2475/7000

Divide the top and bottom by 25

99/280

Answer: $\(\frac{9.9}{28}\)

Step-by-step explanation:

\(\frac{24.75}{70}\) is the fraction.

First for convenience, let us convert the decimal into a whole number by multiplying both numerator and denominator by 100. This is not necessary and the final answer will be the same but doing this step will make it easier to divide.

{\(\frac{24.75 * 100}{70 * 100}\)} = \(\frac{2475}{7000}\)

Now, since it is not in its lowest form we need to simplify it.

For ease, we can find the HCF of 2475 and 7000 which is 25 and divide both numerator and denominator with it.

After simplifying, the final answer is \(\frac{99}{280}\).

However we need to put back the decimal places.

Final answer is  $\(\frac{9.9}{28}\)

\( \bf \implies \frac{ - 4}{9} \\ \)

\( \bf \longrightarrow\frac{5}{6} ( - \frac{8}{15} ) \\ \\ \bf \longrightarrow\frac{5}{6} \times \frac{ - 8}{15} \\ \\ \bf \longrightarrow \frac{5 \times - 8}{6 \times 15} \\ \\ \bf \longrightarrow \frac{ - 40 \div 10}{90 \div 10} = \frac{ - 4}{9} \)

Alana's conclusion from the study is not appropriate.

Why is Alana's conclusion from the study is not appropriate?

What is an appropriate study?

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Answer:

Below

Step-by-step explanation:

Circumference of a circle = pi * diameter

                             circumference of ferris wheel = 3.14159 * 520=1633.6 ft

Answer:

Pro: It can give greater insight into an applicant's abilities. ...

Con: It could reveal protected information. ...

Pro: It can reveal ugly incidents. ...

Con: It isn't always reliable. ...

Pro: It can make an even better case for an employee. ...

Con: It could raise equal employment opportunity concerns.

Step-by-step explanation:

got it right

Answer:

The Value of X in 2nd one can be 14√3.

The Value of X in 1st one can be 6√3.

Step-by-step explanation:

2.)here we used tan 60° formula with P/B as x/14 respectively.

as the value of tan 60° is √3, we got,

√3= x/14

x= 14√3.

1.) Here we used sin 30° formula with 1/√2 as P/H

so we got,

6/x= 1/√2

hence the answer comes:-

x= 6√2..

Hope so it helped you........

Something and 14√3.

Steps

The person above me has calculated something.

The way to get 14√3 can be seen in the image above.

Answer: 12

Step-by-step explanation: 21-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1=12

The largest value of n for which function f(n) could be computed in one second is approximately 2.8 million. The largest value of n is 31,623. The largest value of n is 30.

If calculating f(n) takes nlog₂(n) big operations, and each bit operation is completed in \(10^{-9}\) seconds, we can calculate the largest value of n that can be computed in one second.

Let's set up the equation:

nlog₂(n) * \(10^{-9}\) seconds = 1 second

Simplifying the equation:

nlog₂(n) =  \(10^{-9}\)

To approximate the largest value of n, we can use trial and error or numerical methods. By trying different values of n, we can find that when n is around 2.8 million, the left-hand side of the equation is close to  \(10^{-9}\) .

Therefore, the largest value of n for which f(n) could be computed in one second is approximately 2.8 million.

If calculating f(n) takes n² big operations, and each bit operation is completed in  \(10^{-9}\)  seconds, we can calculate the largest value of n that can be computed in one second.

Let's set up the equation:

n² * \(10^{-9}\) seconds = 1 second

Simplifying the equation:

n² =  \(10^{-9}\)

Taking the square root of both sides:

n = √ \(10^{9}\)

Calculating the value:

n ≈ 31622.7766

Therefore, the largest value of n for which f(n) could be computed in one second is approximately 31,623.

If calculating f(n) takes \(2^{n}\) bit operations, and each bit operation is completed in  \(10^{-9}\)  seconds, we can calculate the largest value of n that can be computed in one second.

Let's set up the equation:

\(2^{n}\) *  \(10^{-9}\)  seconds = 1 second

Simplifying the equation:

\(2^{n}\) =  \(10^{9}\)

Taking the logarithm base 2 of both sides:

n = log₂( \(10^{9}\) )

Calculating the value:

n ≈ 29.897

Rounding to the nearest whole number:

n ≈ 30

Therefore, the largest value of n for which f(n) could be computed in one second is approximately 30.

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