Answer:
it's the first choice. The Great egret.
plzzzzzzzzzzzz helpppppppppppppp
Answer: No it takes a long time to form a fossil. Fossils don’t form within a few weeks. It probably took at least a decade for the dinosaur fossils to form, maybe even a century.
Explanation:
19. the binding energy per nucleon of a nucleus is 3 mev. what is the minimum energy needed to completely separate the nucleons of ?
The minimum energy needed to completely separate the nucleons of the nucleus is known as the binding energy of the nucleus.
The energy needed to completely disassemble a nucleus into its component protons and neutrons is known as the binding energy of a nucleus.
Given that each nucleon in a nucleus has a binding energy of 3 MeV, the total binding energy of the nucleus would be equal to three times the number of nucleons.
This indicates that the total binding energy of the nucleus is equal to the minimal energy needed to entirely separate the nucleons of the nucleus.
The energy required to separate the nucleons of the nucleus must be at least 3 MeV per nucleon, which is the same as the nucleus's binding energy.
Complete Question:
The binding energy per nucleon of a nucleus is 3 MeV. What is the minimum energy needed to completely separate the nucleons of the nucleus?
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The history of Earth is represented on which scale?
Hutton scale
Steno scale
geological time scale
Mercator scale
Answer:
The history of Earth is represented on the geological time scale.
Match the substance with its chemical formula H+. H3O+. OH-
H+: Hydrogen ion
H3O+: Hydronium ion
OH-: Hydroxide ion
A hydrogen ion (H+) is a positively charged ion that consists of a single proton. It is the most important ion in acid-base chemistry.
Hydronium ion (H3O+) is a positively charged ion that consists of a hydrogen ion bonded to a water molecule. It is the form of a hydrogen ion that exists in solution.
A hydroxide ion (OH-) is a negatively charged ion that consists of an oxygen atom and one or more hydroxide (OH) groups. It is the conjugate base of water.
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As carbon dioxide gas levels in the atmosphere increase, the temperature will
1. decrease
2. increase
3. stay the same.
4. The temperature on Earth is not affected by carbon dioxide gas.
Answer:
2. Increase
Explanation:
Carbon dioxide acts as a greenhouse gas that keeps the heat of the Earth from escaping back into space, much like how the glass of a greenhouse makes it nice and warm and steamy for plants.
Answer:
INCREASE
Explanation:
when carbon dioxide concentrations rise, air temperatures go up, and more water vapor evaporates into the atmosphere—which then amplifies greenhouse heating.
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To get a pure bred colored, you choose several colored flower plants, and let them self-fertilize,
then you plant and grow the seeds. Many of the self-fertilized plants have some colored and
some white flower offspring. You choose one of the plants from a family of all colored flower
plants, let it self-fertilize, then you plant and grow its seeds. All the plants you get have colored
flowers. Now what?
A. This colored flower
plant is pure-bred.
B. This isn't a pure-bred plant, you
need to start all over again.
C. The white flower plant (after it self-
fertilizes) will give pure-bred colored
flowers in the next generation.
Answer:
They are easy to grow & they have many traits that distinguish strains of pea ... Choose several of the colored flower plants, self-fertilize them, then plant and ... To get a pure-bred colored, you choose several colored flower plants, and let ... Many of the self-fertilized plants have some colored and some white flower offspring.
Explanation:
In human species, the allele responsible for myopia is dominant over
the allele responsible for normal vision.
A heterozygous myopic man marries a woman with normal vision.
1- Designate, by symbols, the corresponding alleles.
Answer:
'M' for dominant whereas 'm' for recessive allele.
Explanation:
Allele used for myopic man is 'M' whereas the allele used for normal vision is 'm'. The 'M' represents that the allele is dominant and the 'm' refers to the recessive allele. When the dominant allele combine with recessive allele, the organisms have physical features from the dominant organisms while on the other hand, the recessive allele hide and do not appear in the physical appearance of that organisms.
humans have 46 chromosomes. guinea pigs have 64 chromosomes. kiwis have 174 chromosomes. bananas have 33 chromosomes. strawberries has 16 chromosomes. what connection exists between the numbers of chromosomes and the complexity of an organism? explain your thinking
Answer:
There is no correlation/connection between number of chromosomes and complexity of an organism.
Explanation:
If the number of chromosomes determined the complexity of an organism, we could say that the kiwi in this problem is more complex than the human, however, this is not true. A chromosome is like a container for the genetic material (genes) of an organism, it doesn't matter how many containers there are, but rather what's inside the containers that determine genotype and phenotype.
Answer:
Not much.
Explanation:
Considering the fact that banannas have like half of the chromosomes that a living animal has, and the fact that an animal somehow has more chromosomes than a human, leads me to believe there is little to no correlation with the amount of chromosomes someone has and their complexity.
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According to the base-pairing rules for DNA, which of the following statements
NOT true?
A always pairs with T
C always pairs with G
T always pairs with G
T always pairs with A
Answer:
T always pairs with A
Explanation:
I think so I'm super sorry if its wrong :)
According to the base pairing rule, guanine always forms a bond with cytosine, while adenine always pairs with thymine, T is not paired with G, hence option C is correct.
What is base-pairing in DNA?Because it is RNA, there is no complementary base pairing between the bases adenine and thymine in DNA. Uracil, which has a structure remarkably similar to that of thymine, is present in place of thymine.
Base pairing rule, guanine always forms a bond with cytosine, while adenine always pairs with thymine structure of DNA is created by the binding of these base pairs
Although they keep the two strands of DNA together, they are not strong enough to withstand replication.
Therefore, the base pairing rule, guanine always forms a bond with cytosine, while adenine always pairs with thymine, hence option C is correct.
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. Which structure manufactures proteins and is located on the Rough ER and in the cytosol of the cell? a. Golgi apparatus c. Vacuole b. Mitochondrion d. Ribosome
Answer: d. Ribosome
Explanation:
Ribosomes are the protein factories of the cell. Composed of two subunits, they can be found floating freely in the cell's cytoplasm or embedded within the endoplasmic reticulum.
Help on the second question pls
Answer:
metabolic activity
Explanation:
Describe the effect of increasing the number of tablets dissolved in water on the number of new leaves in four weeks. 25 points
What five conditions must be happening in order for evolution not to occur in an ecosystem?
answer:
1,no mutation
2,random mating
3,no gene flow
4,infinite population size
5,no selection.
The stability of actin microfilaments can only be modified by proteins.
a. true
b. false
The stability of actin microfilaments can only be modified by proteins.- TRUE.
Microfilaments are the smallest of the cytoskeleton's three different kinds of protein fibers. They are formed of several connected actin monomers, which are assembled into a structure that resembles a double helix, and have a diameter of around 7 nm. Microfilaments are also referred to as actin filaments because they are composed of actin monomers.Actin filaments play a variety of significant tasks in cells. They act as tracks for myosin, a motor protein that can also form filaments, to move along. Actin participates in a variety of cellular processes that call for mobility because of its connection to myosin.learn more about actin here: https://brainly.com/question/23185374
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During the initiation step of translation, the fmet charged trna assembles in which site of the ribosome?
P site, initiation step of translation, the fmet charged tRNA assembles in this site of the ribosome.The small ribosomal subunit, mRNA, initiator tRNA, and large ribosomal subunit come together to form the initiation complex. The P site of the completed ribosome is where the initiator tRNA is located.
When an amino acid, tRNA, and mRNA come together inside the ribosome, translation begins. The process of translation continues as the mRNA passes through the ribosome after it has started. Each codon pairs with a new tRNA anticodon, bringing in new amino acid to lengthen the chain.
At the subunit interface, tRNA molecules bind to the ribosome in a solvent-accessible channel. The big and small subunits each feature three tRNA binding sites known as the aminoacyl site (A site), peptidyl site (P site), and exit site (E site). The expanding polypeptide chain of amino acids is held in place by the tRNA by the P site, also known as the peptidyl site. The new amino acid that will be added to the polypeptide chain is stored in the aminoacyl tRNA, to which the A site (acceptor site) binds.
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What sentence best supports the staternent that hormones are involved in the regulation of homeostasas? The hormone melatonin induces sleep and its production is slowed by exposure to light. The hormone cortisol suppresses the immune system and is produced when the body is under stress. The hormone oxytocin promotes labor contractions of the uterus during childbirth. The hormone erythropoeitin increases the production of red blood cells when oxygen levels are low.
The sentence that supports the statement that hormones are involved in the regulation of homeostasis is: The hormone erythropoietin increases the production of red blood cells when oxygen levels are low.
Homeostasis is the condition of maintaining the adequate conditions inside the living body that are most suitable for its survival. It is the state of steady internal, physical, and chemical conditions. The correct temperature, adequate oxygen concentrations, adequate fluids inside the body are the examples of homeostasis.
Erythropoietin is the hormone produced by the kidney cells that enhances the production of RBCs in the body. This in turn enhances the oxygen concentration inside the body.
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Identify the correct term for each definition.
a. the bottom chamber of both sides of the heart
b. the dome-shaped muscle at the base of the chest cavity that contracts and lowers to draw oxygen into the lungs then relaxes and lowers to push carbon dioxide out
c. the liquid part of the blood
d. the protein that colors red blood cells and allows them to carry oxygen to the tissues
e. the passageway out of the body for urine
f. the top chamber of both sides of the heart
g. the tube that carries food to the stomach
h. the two branches of the windpipe that descend to the right and left lungs
i. muscles that operate completely outside of conscious thought
j. tiny blood vessels where pickup of wastes and delivery of oxygen and food takes place tiny filtering units in the kidneys
k. a waste product that is made up of leftover parts of used proteins and is high in nitrogen
l. urea and other waste substances that are collected in the bladder
Answer:
a-Ventricle
b-Diaphragm
c-Plasma
d-Hemoglobin
e-Urethra
f-Atria
g-Esophagus
h-Bronchi
i- Involuntary muscles
j-Glomerulus
k-Ammonia
l-Urine
csccs that develop from well-differentiated cells manifest as scaly nodes and plaques while poorly differentiated cells that become csccs develop as soft and hemorrhagic lesions
In conclusion, the degree of differentiation in csccs determines their appearance and characteristics. Well-differentiated csccs manifest as scaly nodes and plaques, while poorly differentiated csccs develop as soft and hemorrhagic lesions.
The csccs (cutaneous squamous cell carcinomas) that develop from well-differentiated cells exhibit scaly nodes and plaques, while poorly differentiated cells that become csccs result in soft and hemorrhagic lesions.
To break it down:
- Well-differentiated csccs present as scaly nodes and plaques. These types of csccs typically have cells that closely resemble normal skin cells and are organized in a more orderly manner.
- On the other hand, poorly differentiated csccs display soft and hemorrhagic lesions. In this case, the cells are less organized and resemble less mature skin cells.
In conclusion, the degree of differentiation in csccs determines their appearance and characteristics. Well-differentiated csccs manifest as scaly nodes and plaques, while poorly differentiated csccs develop as soft and hemorrhagic lesions.
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a biologist is studying how pollution affects algal growth and snail populations in a portion of lake erie. what level of the organization is she studying?
A biologist is studying how pollution affects algal growth and snail populations in a portion of lake erie. The level of the organization is she studying was the ecosystem
An ecosystem is an ecological system formed by an inseparable reciprocal relationship between living things and their environment. Ecosystems are formed from biotic and abiotic components that mutually influence each other.
The biotic component consists of all living things on this earth, including humans, animals, plants and microorganisms. While the abiotic components are all forms of inanimate objects that exist on the surface of the earth that provide benefits and also influence the life of living things. Pollution is an abiotic component that influences the biotic component, namely the growth of algae and snail populations. Therefore, it can be concluded that the researcher is studying the level of ecosystem organization because what he is studying includes biotic and abiotic components that give each other reciprocity.
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Which of the following is a disadvantage of the Linnaean system of nomenclature? A. The classification must be logically consistent with the phylogeny that it describes. B. It requires duplicate naming of monotypic taxa at standard ranks. C. Names with the same rank have mutually exclusive content. D. Within a taxon the ranks denote relative age. E. Every clade on phylogeny must be named.
Monotypic taxa at standard ranks must be named twice.
The ideal response is b.
What are the seven categories in the Linnaean system?Seven levels make up Linnaeus' hierarchical classification scheme. Kingdom, phylum, class, order, family, genus, and species are the orderly groups, going from largest to smallest. 2. Each level is referred to as a taxon (plural: taxa) or taxonomic category in taxonomic nomenclature.
What in biology is Linnaean taxonomy?a phrase for the generic classification of organisms based on rank. Rank-based scientific classification is taxonomy in the purest sense of the word. Particularly, this phrase is used in opposition to cladistic systematics, which classifies species into clades.
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What is formed by organized groups of cells with similar structures and a common purpose?.
Answer:Tissues
Explanation:Tissues are groups of cells that have a similar structure and act together to perform a specific function. Different tissues make up organs. Different organs work together to form an organ system.
Which statement best describes chromatin associated with actively transcribed genes as compared to chromatin associated with genes which are not being actively transcribed?
More compacted and more acetylated
More relaxed and more acetylated
More relaxed and less acetylated
More compacted and less acetylated
The best statement that describes chromatin associated with actively transcribed genes as compared to chromatin associated with genes which are not being actively transcribed is "More relaxed and more acetylated".
The chromatin associated with actively transcribed genes is more relaxed and more acetylated as compared to chromatin associated with genes that are not being actively transcribed. The chromatin is composed of DNA and histones and can be modified to enable or prevent gene expression.
The relaxation of the chromatin allows transcription factors to access and interact with the DNA while the acetylation of the histones creates a less compact chromatin structure that enables easier access of the transcription machinery to the DNA template.This relationship of chromatin structure with transcription is known as epigenetics. Epigenetic modifications are changes to the DNA that affect gene expression without changing the DNA sequence. Acetylation is one of the most common epigenetic modifications that occurs on the histone tails.
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The pectoral girdle is an incomplete ring because it is open in the back between the.
The pectoral girdle is an incomplete ring because it is open in the back between the scapulae.
Where are scapulae is located?
The scapula, often known as the shoulder blade, is the name for one of the two main vertebrate shoulder girdle bones. They are triangular and situated on the upper back of humans between the second and eighth rib levels.
The clavicle and the scapula make up the pectoral girdle, which connects the upper limb to the sternum of the axial skeleton. The shoulder blade, or scapula, is located on the back of the shoulder.
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what is abc control disease method
Answer:
Active Bacterial Core surveillance (ABCs) is an active laboratory- and population-based surveillance system for invasive bacterial pathogens of public health importance.
Explanation:
Once you print, cut all the pieces apart. Then reassemble the puzzle so the the definition backs up with the card that has the term. So if one card says: double helix, the card that matches with it would say: the shape of DNA.
DNA replication is the process through which DNA duplicates. It occurs in the interphase and involves different enzymes, DNA molecules, and free nucleotides. Terms and definitions in the attached files.
What is DNA replication?
DNA replication is the process through which DNI molecule duplicates. This event takes place during the S stage of the interphase. So when the cell divides during mitosis or meiosis, each cell will get a complete set of chromosomes.
DNI replication is semi-conservative because each new molecule carries an original DNI strand and a new one. The fact that the new molecule is composed of an original strand makes it semi-conservative. The old existing strands are used to synthesize the new complementary strand.
The origin of the replication requires helicase enzymes to break hydrogen bonds and separate the two original strands. The topoisomerase enzyme is necessary to release tension. Other proteins are also needed to join the strains and keep them separated. Once the molecule is opened, there is a region named replication forks. DNA polymerase makes the new nucleotides enter into the fork and pairs them with the corresponding nucleotide of the original strand. Adenine pairs timine, and cytosine pairs guanine.
DNA strands are antiparallel, and replication occurs only in 5'-3' direction. So one of the strands will replicate continuously, while the other strain will be formed by short fragments known as Okazaki fragments.
Primers are needed to make the DNA polymerase work. Primers are small units of RNA and are placed at the beginning of each new fragment.
In the attached files you will find the terms and their definitions.
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Which of the following is considered the first receiver for the nicotine in a smocking person?
1.left atrium
2.right atrium
3.left ventricle
4.right ventricle
Answer:
i think nicotine travels through blood and we know blood reaches the right ventricle first
maybe right ventricle
A population of 40 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can
sustain up to 600 deer. Absent constraints, the population would grow by 60% per year. Estimate the population
after one year Pi Estimate the population after two years P2 -
The population of deer in the wildlife sanctuary can be estimated using the formula:
P(t) = P(0) * (1 + r)^t
where P(t) is the population after t years, P(0) is the initial population, r is the growth rate per year, and t is the number of years.
In this case, the initial population (P(0)) is 40 deer, the growth rate (r) is 60% per year (0.60), and we need to estimate the population after one year (P1) and two years (P2).
To calculate P1:
P(1) = 40 * (1 + 0.60)^1
P(1) = 40 * (1 + 0.60)
P(1) = 40 * 1.60
P(1) = 64
Therefore, the estimated population after one year is 64 deer.
To calculate P2:
P(2) = 40 * (1 + 0.60)^2
P(2) = 40 * (1 + 0.60)^2
P(2) = 40 * 1.60^2
P(2) = 40 * 2.56
P(2) = 102.4
Therefore, the estimated population after two years is 102.4 deer.
It's important to note that these are estimates and assume that there are no constraints on the population growth. In reality, factors like limited resources, predation, and disease can affect the growth rate and population size.
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Identify three organisms that belong in the same phylum as green algae and where they can be found.
Identify whether the cell is in interphase, prophase,
metaphase, anaphase, or telophase. All answers should
be in lowercase letters and spelling counts.
18
19
20
21
22
23
24
25
Vuvvy
IAAAA
26
27
28
29
AMMA
30
PROW
31
32
33
34
35
Answer:
Identify whether the cell is in interphase, prophase,
metaphase, anaphase, or telophase. All answers should
be in lowercase letters and spelling counts.
Explanation:
18
19
20
21
22
23
24
25
Vuvvy
IAAAA
26
27
28
29
AMMA
30
PROW
31
32
33
34
35
2. an animal cell placed in a(n) blank solution will gain water, swell, and possibly burst.target 2 of 6 3. there is a net diffusion of water out of an animal cell when it is placed in a(n) blank solution.target 3 of 6 4. the ideal osmotic environment for a plant cell is a(n) blank environment.target 4 of 6 5. a plant cell placed in a(n) blank solution will lose water and plasmolyze.target 5 of 6 6. a plant cell surrounded by a(n) blank solution will be flaccid (limp).target 6 of 6 request answer
An animal cell placed in a hypotonic blank solution will gain water swell and possibly burst.
There is a net diffusion of water out of an animal cell when it is placed in a hypertonic blank solution.
The ideal osmotic environment for a plant cell is hypotonic a blank environment.
An isotonic environment is the ideal osmotic environment for animal cells. Animal cells have the same concentration as the cytosol. The penetration rate is the same on both the inside and outside sides. There is no increase or decrease in water or solvent concentration.
Plant cells are bloated and generally healthiest in a hypotonic environment where water uptake is ultimately balanced by walls that are pressed against the cell. This is considered normal. When a plant cell is surrounded by a solution containing a higher concentration of water molecules than the solution inside the cell water enters the cell by osmosis and the plant cell swells.
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