Hello!
We can graph by finding critical points - intersections, y-intercepts, x-intercepts.
Find the intersection point by setting the two equations equal to each other:
-4x + 3 = x - 2
Subtract x from both sides:
-5x + 3 = - 2
Subtract 3 from both sides:
-5x = -5
Divide both sides by -5:
-5x/(-5) = -5/(-5)
x = 1
Find the y-value of intersection by plugging in x = 1 into an equation:
y = 1 - 2 = -1
Intersection at (1, -1)
Find the x and y intercepts of each equation:
y = -4x + 3
Set x to 0 to find the y-intercept:
y = -4(0) + 3 = 3
Set y to 0 to find the x-intercept:
0 = -4x + 3
-3 = -4x
x = 3/4
Therefore, this equation has a y-intercept at (0, 3) and and x-intercept at (3/4, 0).
y = x - 2
Set x to 0 to find the y-intercept:
y = 0 - 2 = -2
Set y to 0 to find the x-intercept:
0 = x - 2
x = 2
Therefore, this equation has a y-intercept at (0, -2) and and x-intercept at (2, 0).
Graph the two equations with the solved critical points:
y = -4x + 3
--> (1, -1)
--> (0, 3)
--> (3/4, 0)
y = x - 2
--> (1, -1)
--> (0, -2)
--> (2, 0)
**Graphed below**
4. Which of the following angles is vertical to angle /DEB?
A
C
109°
E
D
B
Answer:
A
Step-by-step explanation:
In Exercises 9 to 14, find the limit of each function at the given point, or explain why it does not exist. 10. f(z) = Arg z at Zo--1 11. f(z) = (1-Im z)-1 at z,-8 and then at zo-8 +1 12.f(z) = (z _ 2) log(z-21 at zo = 2 13, f(z) =-, z#0 at zo = 0 14. f(z) = 2+21,
Previous question
The limit of each function at the given point i n the question 10 to 14, is explained below.
Limit Of A function:A function may get close to two distinct limits. There are two scenarios: one in which the variable approaches its limit by values larger than the limit, and the other by values smaller than the limit. Although the right- and left-hand limits are present in this scenario, the limit is not defined.
When a variable approaches its limit from the right, the function's right-hand limit is the value that approaches.a
10). The limit of f(z) = Arg z as z approaches Zo = 1 does not exist. This is because the argument function is not continuous at the point z = 1, where there is a branch cut.
11). The limit of f(z) = \((1 - lm z)^{-1}\) as z approaches z0 = -8 does not exist. This is because the function approaches infinity as z approaches -8 from the left, and negative infinity as z approaches -8 from the right.
However, if we consider the limit of f(z) as z approaches z0 = -8 + i from both the left and the right, the limit exists and is equal to 0. This is because in the complex plane, the value of Im z cannot exceed 1, so as z approaches -8 + i, the denominator (1 - Im z) approaches 0, and the function approaches infinity. However, the numerator approaches a finite value of 1, which cancels out the denominator, and the overall limit is equal to 0.
12). The limit of f(z) = (z - 2) log(z - 2) as z approaches z0 = 2 is 0. This is because the term (z - 2) approaches 0 as z approaches 2, and log(z - 2) approaches 0 as well because log(z - 2) is continuous at z = 2. Therefore, the limit is equal to 0.
13). The limit of f(z) = -1/z as z approaches z0 = 0 does not exist. This is because as z approaches 0, the magnitude of 1/z approaches infinity, but the direction of approach depends on which quadrant the limit is approached from. Since the limit does not approach a unique value from all directions, the limit does not exist.
14). The limit of f(z) = 2 + \(2^{1/z}\) as z approaches infinity does not exist. This is because as z approaches infinity, the term \(2^{1/z}\) approaches 1, and the limit approaches 2 + 1 = 3. However, if we approach infinity along the real axis, the limit of \(2^{1/z}\) approaches 1, but if we approach infinity along the imaginary axis, the limit of \(2^{1/z}\) approaches infinity. Therefore, the limit of f(z) does not exist.
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What is the distance between (-6,0) and (5,3)?
Answer:
\(\sqrt{130}\) or 11.4
Step-by-step explanation:
Use the distance formula:
d = \(\sqrt{(x2 - x1)^2 + (y2 - y1)^2}\)
Plug in the points:
d = \(\sqrt{(-6 - 5)^2 + (0 - 3)^2}\)
Simplify:
d = \(\sqrt{(-11)^2 + (-3)^2}\)
d = \(\sqrt{121 + 9}\)
d = \(\sqrt{130}\)
= approximately 11.4
So, the distance is \(\sqrt{130}\) or approx. 11.4
Find the open intervals on which the function f(x)= x+10sqrt(9-x) is increasing or decreasing.
The function f(x) = x + 10√(9 - x) is increasing on the interval (-∞, 9) and decreasing on the interval (9, ∞).
To determine the intervals on which the function is increasing or decreasing, we need to find the derivative of the function and analyze its sign.
Let's find the derivative of the function f(x) = x + 10√(9 - x) with respect to x.
f'(x) = 1 + 10 * (1/2) * (9 - x)^(-1/2) * (-1)
= 1 - 5√(9 - x) / √(9 - x)
= 1 - 5 / √(9 - x).
To analyze the sign of the derivative, we need to find the critical points where the derivative is equal to zero or undefined.
Setting f'(x) = 0:
1 - 5 / √(9 - x) = 0
5 / √(9 - x) = 1
(√(9 - x))^2 = 5^2
9 - x = 25
x = 9 - 25
x = -16.
The critical point is x = -16.
We can see that the derivative f'(x) is defined for all x values except x = 9, where the function is not differentiable due to the square root term.
Now, let's analyze the sign of the derivative f'(x) in the intervals (-∞, -16), (-16, 9), and (9, ∞).
For x < -16:
Plugging in a test value, let's say x = -17, into the derivative:
f'(-17) = 1 - 5 / √(9 - (-17))
= 1 - 5 / √(9 + 17)
= 1 - 5 / √26
≈ 1 - 0.97
≈ 0.03.
Since f'(-17) is positive, the function is increasing in the interval (-∞, -16).
For -16 < x < 9:
Plugging in a test value, let's say x = 0, into the derivative:
f'(0) = 1 - 5 / √(9 - 0)
= 1 - 5 / √9
= 1 - 5 / 3
≈ 1 - 1.67
≈ -0.67.
Since f'(0) is negative, the function is decreasing in the interval (-16, 9).
For x > 9:
Plugging in a test value, let's say x = 10, into the derivative:
f'(10) = 1 - 5 / √(9 - 10)
= 1 - 5 / √(-1)
= 1 - 5i,
where i is the imaginary unit.
Since the derivative is not a real number for x > 9, we cannot determine the sign.
Combining the information, we conclude that the function f(x) = x + 10√(9 - x) is increasing on the interval (-∞, 9) and decreasing on the interval (9, ∞).
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A farmer is enclosing a rectangular area for a pigpen. He wants the length of the pen to be 20 ft longer than the width. The farmer can use no more than 100 ft of fencing. What is the pen’s greatest possible length? Let w represent the width of the pen. What expression represents the length?
Answer:
Width is 15, length is 35.We can check our answer by multiplying the length by 2 and the width by two in order for the perimeter to be equal to 200.15 times 2 is 30 and 35 times two equals 70.70+30=100 so our solution satisfies our problem.
Step-by-step explanation:
Let the width be x.Then the length should be x+20.The farmer can’t use more than 100 ft of fencing and by mentioning enclosing a rectangle area for a pigpen, we can tell that 100 is the perimeter.So 2(x+20) + 2(x)=100.2x+ 40 + 2x=100.4x+40=100.4x=60.X is 15 which is the width so then the length is 35.
find the missing side. round to the nearest tenth
The required angle is 24.5°.
Given is a right triangle with perpendicular side 16 and the base = 35 we need to find an acute angle in it,
To find the acute angle in a right triangle given the lengths of the perpendicular side and the base, you can use the tangent function.
The tangent of an angle is defined as the ratio of the length of the perpendicular side to the length of the base side.
In this case, the perpendicular side is 16 and the base is 35.
Let's denote the acute angle as θ.
Using the tangent function, we can set up the equation:
tan(θ) = perpendicular side / base
tan(θ) = 16 / 35
To find the value of θ, we can take the inverse tangent of both sides:
θ = tan⁻¹(16 / 35)
θ = 24.5°
Hence the required angle is 24.5°.
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The units of an item available for sale during the year were as follows: Jan. 1 Inventory 50 units at $124 Mar. 10 Purchase 60 units at $132 Aug. 30 Purchase 20 units at $138 Dec. 12 Purchase 70 units at $142 There are 80 units of the item in the physical inventory at December 31. The periodic inventory system is used. Determine the ending inventory cost and the cost of goods sold by three methods. Round interim calculations to one decimal and final answers to the nearest whole dollar. blank Cost of Ending Inventory and Cost of Goods Sold Inventory Method Ending Inventory Cost of Goods Sold First-in, first-out (FIFO) $fill in the blank 1 $fill in the blank 2 Last-in, first-out (LIFO) fill in the blank 3 fill in the blank 4 Weighted average cost fill in the blank 5 fill in the blank 6
Ending Inventory Cost and Cost of Goods Sold using different inventory methods:
FIFO Method:
Ending Inventory Cost: $11,920
Cost of Goods Sold: $15,068
LIFO Method:
Ending Inventory Cost: $11,996
Cost of Goods Sold: $15,123
Weighted Average Cost Method:
Ending Inventory Cost: $11,974
Cost of Goods Sold: $15,087
Using the FIFO (First-In, First-Out) method, the cost of the ending inventory is determined by assuming that the oldest units (those acquired first) are sold last. In this case, the cost of the ending inventory is calculated by taking the cost of the most recent purchases (70 units at $142 per unit) plus the cost of the remaining 10 units from the March 10 purchase.
This totals to $11,920. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory at $124 per unit, 60 units from the March 10 purchase at $132 per unit, and 20 units from the August 30 purchase at $138 per unit), which totals to $15,068.
Using the LIFO (Last-In, First-Out) method, the cost of the ending inventory is determined by assuming that the most recent units (those acquired last) are sold first. In this case, the cost of the ending inventory is calculated by taking the cost of the remaining 10 units from the December 12 purchase, which amounts to $1,420, plus the cost of the 70 units from the August 30 purchase, which amounts to $10,576.
This totals to $11,996. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory, 60 units from the March 10 purchase, and 20 units from the August 30 purchase), which totals to $15,123.
Using the Weighted Average Cost method, the cost of the ending inventory is determined by calculating the weighted average cost per unit based on all the purchases. In this case, the total cost of all the purchases is $46,360, and the total number of units is 200.
Therefore, the weighted average cost per unit is $231.80. Multiplying this by the 80 units in the physical inventory at December 31 gives a total cost of $11,974 for the ending inventory. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory, 60 units from the March 10 purchase, and 20 units from the August 30 purchase), which totals to $15,087.
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Under what circumstances does the inequality hold? Why?
\(|A{\cdotp}B|=|A||B|\) (A and B are verctors).
\(\huge\bold\red{Answer:-}\)
ʀᴇꜰᴇʀ ᴛᴏ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛꜱ.ɪ ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ❤Segments RA and NY are best described as which of the following?
A. Parallel segments
B. Perpendicular lines
C. Perpendicular segments
D. Perpendicular rays
Suppose that 45% of people have dogs. If two people are randomly chosen, what is the probability that they both have a dog
Answer:
\(P(Dogs) = 0.2025\)
Step-by-step explanation:
Given
\(Proportion, p = 45\%\)
Required
Probability of two people having dog
First, we have to convert the given parameter to decimal
\(p = \frac{45}{100}\)
\(p = 0.45\)
Let P(Dogs) represent the required probability;
This is calculated as thus;
P(Dogs) = Probability of first person having a dog * Probability of second person having a dog
\(P(Dogs) = p * p\)
\(P(Dogs) = 0.45 * 0.45\)
\(P(Dogs) = 0.45^2\)
\(P(Dogs) = 0.2025\)
Hence, the probability of 2 people having a dog is \(P(Dogs) = 0.2025\)
Which value of x will make ab perpendicular to cd?
Answer:
Step-by-step explanation:
m∠CGE = m∠FGD = (2x + 4)° [vertically opposite angles]
If m∠BGC = 90° Or AB⊥CD,
m∠CGE + m∠EGB = 90°
(2x + 4)° + (11x - 5)° = 90°
13x - 1 = 90
13x = 91
x = 7
This isnt the answer but its an example of what the equation looks like
solve simultaneously 2x - y = - 10 and 3x + 2y = - 1
The solution to the system of equations is x = -3 and y = -4.
To solve the system of equations:
Equation 1: 2x - y = -10
Equation 2: 3x + 2y = -1
We can use the method of substitution or elimination to find the values of x and y.
Let's use the method of elimination:
Multiply Equation 1 by 2 to make the coefficients of y in both equations equal:
2(2x - y) = 2(-10)
4x - 2y = -20
Now, we can eliminate y by adding Equation 2 and the modified Equation 1:
(3x + 2y) + (4x - 2y) = -1 + (-20)
7x = -21
x = -3
Substitute the value of x into Equation 1 to solve for y:
2(-3) - y = -10
-6 - y = -10
y = -10 + 6
y = -4
Therefore, the solution to the system of equations is x = -3 and y = -4.
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I need help with these, the answer options are as follows: always true, sometimes true, never true
Thank you!!
can someone help me with this
Write a numerical expression to represent the phrase "the sum of 25 and the cube of 9." Do not evaluate the expression.
Answer:
25 + 9^3
Step-by-step explanation:
What kind of multi step do I have to do to prove a is parallel to b and m parallel to n.
The proof that line n is perpendicular to both a and b is proved below using definition of right angle and perpendicular transversal theorem.
How to prove Perpendicular and Parallel Lines?
We are given that;
Line a is parallel to line b
Line m is parallel to line n.
A) We want to prove that line a is perpendicular to n.
From the image, we see that there is a right angle sign on the opposite side of ∠1 facing m.
Now, we know that by definition of a right angle that ∠1 will also be a right angle.
Since angle 1 is a right angle, then we can say the line transversal a is perpendicular to line m.
B) We want to prove that line b is perpendicular to n.
The definition of the perpendicular transversal theorem, states that if a line is perpendicular to one of two parallel lines, then it is perpendicular to the other.
Thus, b will be perpendicular to n.
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Help me find this answer please (honest and most best answers only)
The baby whale would be 35 years old.
\(7*10^3\) in standard notation is 7000
To find the whales age, you must divide 7000 by 200, which is 35.
In a fruit basket, there are 9 bananas, 7 apples, and 3 plums,
Enter a numerical value to answer the question completely.
Answer:
Bananas to apples are 9:7
Plums to apples are 3:7
apples to plums are 7:3
Bananas to plum are 3:1
Step-by-step explanation:
For every Plum there are 3 bananas.
The ratio of apples to plums are 7:3.
For every apple there are 7/9 banana.
NEED HELP ASAP PLS AND THX Picture is attached
Answer:
SVW
Step-by-step explanation:
Since we need V in the middle of the three letters, only c and d are left. But to read an angle, you ensure the center degree(in this case, the number 4) and make the letter in the middle. You extend the center out for the other two digits, so the only choice is SVW, not WVT because T is far off, and 4 is supposed to be SVW, or WVS.
Please help will mark Brainly
Answer:
A
Step-by-step explanation:
Blue = River Y
Red = River Z
River Y equation: y = 18
River Z equation: y = 10 + 2x
Graph A represents this system of equations.
IF THIS HELPED YOU GIVE ME BRAINLIEST FOR GOOD LUCK FOR 10 YEARS
Simplify the variable expression by evaluating its numerical part.
j + 16 - 48 + 4
A. j-28
B. j-36
C. -36j
D. -28j
solve square root equation.
b^2=-169
\(\\ \sf\longmapsto b^2=-169\)
\(\\ \sf\longmapsto b=\sqrt{-169}\)
\(\\ \sf\longmapsto b=\sqrt{-(13)^2}\)
\(\\ \sf\longmapsto b=13i\)
Answer:-13
Step-by-step explanation:
Evaluate when a=4 and b=9: 5ab-b
Answer:
171Step-by-step explanation:
\(\tt 5ab-b, \: when\: a=4\: and \:b=9\)
\(\tt 5(4)(9)-(9)\)
\(\tt \:5\times 4\times 9-9\)
\(\tt 180-9\)
\(\tt 171\)
Hope it helps! :)
100 Points! Algebra question. Graph the function. Photo attached. Thank you!
The cost of each pound of grass seed is $6.
A graph of the solution for the cost of each pound of grass seed is shown below.
How to determine the cost of each pound of grass seed?In order to determine the cost of each pound of grass seed, we would assign a variable to the cost of each pound of grass seed and then translate the word problem into an algebraic linear equation.
Let the variable x represent the cost of each pound of grass seed.
Since Lori bought 3.6 pounds of grass seed and she was charged $22.90, including a tax of $1.30, an algebraic linear equation that best represent this situation is given by;
3.6x + 1.30 = 22.90
3.6x = 22.90 - 1.30
3.6x = 21.60
x = 21.60/3.6
x = $6.
In conclusion, we would sue an online graphing calculator to plot the solution for the cost of each pound of grass seed as shown in the image attached below.
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PLSSS HElpppp!! DUE TODAYYY⛔️
Some children measured the lengths of their feet. The lengths are given in the line plot. What is the difference in length between the shortest and longest foot?
Answer:
Step-by-step explanation:
which of these health care plans do federal and state governments offer?
On a number line, the coordinates of X, Y, Z, and W are - 6, -2, 4, and 8, respectively. Find the lengths of the two segments below. Then tell whether they are congruent
XY and ZW
If the coordinates of X, Y, Z, and W on a number line are - 6, -2, 4, and 8, respectively, then the lengths of the segment XY is 4 and that of the segment ZW is also 4, and hence, these two segments (XY and YZ) are indeed Congruent in nature.
To increase the understandability of this question, we will go ahead a visual representation of the number line based on the condition mentioned in the question statement, attached hereby as "Number Line (-10 to 10)".
As per the figure, we can clearly see that the line segment XY begins at (-6) on the number line and ends at (-2), i.e., Length of XY is:
[(-2) - (-6)] = 4.
Similarly, we can also see that the line segment ZW begins at (4) on the number line and ends at (8), i.e., Length of ZW is:
(8 - 4) = 4.
Also, since the lengths of both XY and ZW are same, i.e., 4 Units, they are congruent in nature.
Number Line: In elementary mathematics, a number line is a picture of a graduated straight line, with real numbers, (generally integers, both positive and negative) at equal intervals on it.Congruent Lines: Two line segments of equal lengths are known to be congruent.To learn more about number line, click on the link below.
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please help so lost :(
Answer:
Step-by-step explanation:
C?
beinggreat78 is great
but that's literally her user so....♀️
anywayso
Answer:
1.2 × 10⁻⁵
Step-by-step explanation:
The exponent is negative, so the decimal was moved -5 places back, making the number a decimal.
Answer:
1.2 x 10^5
Step-by-step explanation:
All work is shown in the attached screenshot! :)
6 erasers cost $6.60. Which equation would help determine the cost of 3 erasers
I think its just 6.60 divided by six, thats how many each one costs, then multiply it by 3
Hope this helps :)
Answer:
3.3
Step-by-step explanation:
because you can divide 6.60 by 6 which is 1.1 then multiply it by 3