Can someone please please help me out ?

Magnesium chloride, often known as MgCl2, can be produced chemically by extracting it from brine or seawater.

Magnesium chloride+ potassium hydroxide (25 ml )------>magnesium hydroxide

Magnesium chloride: what is it?

One magnesium (Mg) and two chloride ions make up magnesium chloride, also known as magnesium dichloride, magnesium (II) chloride, or chloromagnesite (Cl-).

Ionic halides, such as magnesium dichloride and related salts, have the appearance of fine, white to grey granules.

Uses of MgCl2 (Magnesium Chloride)

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Answer:

1.0 more acidic and 2.0 more acidic

Explanation:

5.5-4.5=1.0

6.5-4.5=2.0

Answer:

The answer is wave

Explanation:

The specific heat capacity of the pan in the calorimeter During your investigation, you perform an experiment, you place 2.0 kg of water at 25.0°C in a calorimeter, heat your 3.0 kg pan to 300.0 °C is 0.449 kJ/kg°C.

We must first figure out how much heat the water has absorbed. The heat released by the pan must then be determined using the energy conservation concept.

Utilizing the formula:

Q = m * c * ΔT

There are:

(Mass of water) m = 2.0 kg

Water has a specific heat capacity of 4.18 kJ/kg°C.

ΔT = (63.2°C - 25.0°C) = 38.2°C

Q=2.0 kg*4.18 kJ/kg°C*38.2°C = 319.22 kJ

The heat released by the pan must then be determined using the energy conservation concept. It is safe to presume that the water and the calorimeter have absorbed all of the heat that the pan has released. Q is a formula that can be used.

Q = m * c * ΔT

There are:

m = 3.0 kg (the pan's mass).

In terms of the pan's specific heat capacity, c =?

ΔT = (300.0°C - 63.2°C) = 236.8°C

Q = 319.22 kJ

Inputting the values results in:

319.22 kJ = (3.0 kg) * c * (236.8°C)

To solve for c, we obtain:

3.0 kg times 236.8°C times 319.22 kJ equals 0.449 kJ/kg°C.

In this instance, the pan is most likely composed of cast iron.

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Answer:

364 K or 91°C

Explanation:

Applying,

V₁/T₁ = V₂/T₂................ Equation 1

Where V₁ = Initial Volume, V₂ = Final volume, T₁ = initial Temperature, T₂ = final Temperature.

make T₂ the subject of the equation,

T₂ = V₂T₁/V₁................. Equation 2

From the question,

Given: V₁ = 375 mL, V₂ = 500 mL, T₁ = 0.0°C = (273+0) K = 273 K

Substitute these values into equation 2

T₂ = (500×273)/375

T₂ = 364 K

T₂ = (364-273) °C = 91 °C

The balanced chemical equation for the combustion of menthol in the presence of oxygen is shown below.CH\(_{3}\)OH + 1.5O\(^{2}\) → CO\(^{2}\) + 2H\(^{2}\)O

The balanced equation for the combustion of menthol in the presence of oxygen shows that the coefficients required to balance the equation are 1, 1.5, 1, and 2. However, since the number of moles of oxygen is not a whole number, we can multiply the entire equation by 2 to get rid of the fraction as shown below.

2CH\(_{3}\)OH + 3O\(^{2}\) → 2CO\(^{2}\) + 4H\(^{2}\)O

Thus, the correct choice that lists the coefficients that would balance the equation is (a) 2, 3, 2, 4.

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Explanation:

one mole contains Avogadro number of particles

So,

40g( the atomic mass) contains 6.023× 10^23 atoms.

so 1 g contains 40÷(6.023×10^23)

so, 52.3 g contains (40×52.3) ÷6.023×10^23

= 3.47× 10^-21

Answer:

your answer is C

Explanation:

The electron-dot structure of NH3 places one set of nonbonding electrons in the valence shell of the nitrogen atom. that means there are three bonded atoms and one single pair for a coordination number of four surrounding  the nitrogen, the same occurs in water to. along with the Lewis dot structure for ammonia, NH3. the non bonding atoms are basically like hydrogen atoms the try to refuse to bond and they can't be fused unless the right conditions are met.

2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

Given,

Mole of Na+ = 100 millimole

As we know that,

1 millimole = 10 -³ mole

Mole of Na+ in 100 millimoles = 100 × 10 -³ mole

= 0.1mole

Mole is defined as the ratio of mass of Na+ to the molar mass of sodium.

The molar mass is defined as the sum of the total mass in grams unit of the atoms present to make a molecule per mole.

Mole of Na+ = mass of Na + / molar mass of Na +

0.1 = mass of Na + / 22.99 gl mol

Mass of Na + = 0.1 × 22.99

= 2.299 g

Mass of Na + = 2.3 g

Thus, we calculated that 2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

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Answer:

C is the correct answer

I hope this helps you:)

Explanation:

C slower, and the substance will be a liquid

Moles of Carbondioxide-CO₂ produced = 20 moles

The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds

Reaction (combustion of butane) :

2C₄H₁₀+13O₂⇒8CO₂+10H₂O

Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.

moles of butane - C₄H₁₀ = 5 moles

From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :

\(\tt \dfrac{8}{2}\times 5~moles=20~moles\)

The noble gas with a molar mass of 80.0 g/mol is Krypton (Kr).

To find the molar mass of the noble gas, follow these steps:

1. Convert the given pressure to atmospheres: 758 mm Hg × (1 atm / 760 mm Hg) = 0.998 atm.
2. Convert the given temperature to Kelvin: 23.0 °C + 273.15 = 296.15 K.
3. Use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.08206 L atm / mol K), and T is the temperature.
4. Rearrange the equation to solve for n: n = PV / RT.
5. Plug in the given values: n = (0.998 atm × 40.75 L) / (0.08206 L atm / mol K × 296.15 K) = 1.7515 mol.
6. Calculate the molar mass by dividing the mass of the gas by the number of moles: Molar mass = 140.1 g / 1.7515 mol = 80.0 g/mol (rounded to 3 significant figures).

The noble gas with a molar mass of 80.0 g/mol is Krypton (Kr).

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The value of  \(K_{sp}\)  for PbS is \(9.0\times10^{-29}\).

Molar solubility (M) is a unit of measurement for a compound's capacity to dissolve in a particular liquid, also known as a solvent. Molar solubility is measured in terms of \(\frac{moles}{litre}\) since it is the most moles of a solute that can dissolve in one liter of solvent. The solution is said to be saturated when it can no longer dissolve any more solute and the number of moles dissolved in a liter of solvent equals the molar solubility.

Lead(II) sulfide is a poorly soluble salt compound in water with the following Solubility Equilibrium:

\(PbS(s)\Longleftrightarrow Pb^{+2}(aq)+S^{-2} (aq)\)

\(K_{sp}=[Pb^{+2}][S^{-2} ]\)

The compound dissociates in a 1:1 ratio of ions, therefore the molar Solubility is 's' in water will be :

s=\(9.5\times10^{-15}\).

\(K_{sp}=s\times s=s^{2}\)

\(K_{sp}=(9.5\times10^{-15} )^{2}\)

\(K_{sp} =9.0\times10^{-29}\)

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Option D is the correct answer.

Alkali metals are a group of elements found in Group 1A (1) of the periodic table, which includes lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

These elements share several common properties, but the one property that does not apply to them is being liquids at room temperature.

Alkali metals are known to be highly reactive and exhibit strong metallic properties.

They are characterized by having a single valence electron in their outermost energy level, making them highly likely to donate this electron in chemical reactions.

This tendency to readily give up their valence electron makes them excellent conductors of electricity (A) and heat (E). Their metallic nature and structure contribute to their shiny appearance (C).

Another characteristic of alkali metals is their high reactivity with water (B).

When alkali metals come into contact with water, they undergo a vigorous and exothermic reaction, resulting in the release of hydrogen gas and the formation of hydroxide ions.

This reaction is highly energetic and can even be explosive in some cases.

However, the statement that most of the alkali metals are liquids at room temperature.

In fact, all alkali metals are solid at room temperature except for one, mercury (Hg), which is a liquid.

However, mercury is not considered an alkali metal but rather a transition metal.

Option D is the correct answer.

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2S + 302 = 2SO3

Mass of S = 6.3g

Mass of 02 = 10.0g

M(S) = 32g/mol

n = 6.3g/32g/mol

n = 0.195mol

n(S)/n(SO3) = 2/2

Let n(SO3) = x

2(0.195) = 2x

0.39 = 2x

x = 0.195

Therefore, n(SO3) = 0.195mol

But M(SO3) = (32×1) + (16×3)

= 80g/mol

m = 80g/mol × 0.195mol

m = 15.6g

The pH of common solutions like bleach, shampoo, vinegar, and mouthwash as determined using pH test strips or a pH meter are as follows:

The pH of a solution is a measure of its acidity or alkalinity as determined by the concentration of hydrogen ions in the solution.

The pH scale ranges from 0 to 14, where pH 7 is considered neutral, pH values below 7 indicate acidity, and pH values above 7 indicate alkalinity.

The pH of a solution can be determined using various methods such as pH indicator papers or meters that produce color changes or give out readings of pH values.

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Dibenzylideneacetone is formed when benzaldehyde reacts with acetone and sodium hydroxide. An aldol condensation process is seen here. The aldol condensation reaction.

is a process that occurs in the presence of a base (sodium hydroxide) between an aldehyde or ketone to generate a beta-hydroxy aldehyde or ketone, which may then be dehydrated to form an alpha,beta-unsaturated aldehyde or ketone. In this scenario, Dibenzylideneacetone is formed when benzaldehyde reacts with acetone and sodium hydroxide. An aldol condensation process is seen here. The aldol condensation reaction. the beta-hydroxy ketone produced (dibenzylideneacetone) is dehydrated to produce the alpha,beta-unsaturated ketone (stilbene is not formed in this reaction).

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Answer: D

Explanation:

D - Decomposition of carbonates into oxide and carbon dioxide

A - Combustion reaction. Combustion of methane to form Carbon dioxide and water.

C - Reaction of reactive metal (Na) and water to form hydroxide.

B - No particular name of the reaction. Usually denoted as a synthesis redox reaction.

Answer:CaCO3  CaO + CO2

Explanation: just took it

Answer:

halogens

Explanation:

on a periodic table (just search ptable.com) right under the 17 in small words it says halogens

Answer:

In this titration, solution P (that contains hydrochloric acid) is added into the conical flask that contains sodium hydroxide drop by drop. The indicator (phenolphthalein) changes color when all the NaOH is completely neutralized.

i) Solution P contains hydrochloric acid. Hydrochloric acid is the chemical that reacts with sodium hydroxide to give salt and water.

This type of reaction is called neutralization.

ii) Under alkaline conditions, phenolphthalein appears pink in color. When the solution becomes neutral or acidic, it is colorless.

So, the color change of the mixture at the end point is from pink to colorless.

iii) same explanation from question i,

HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l)

iv) no. of moles = volume (in dm3) x concentration

hence,

no. of moles of NaOH used = 25/1000 x 0.1

= 0.0025 mol

From the equation in (iii), since the mole ratio of HCl : NaOH = 1:1, meaning 1 mole of HCl reacts completely with 1 mole of NaOH.

This also means that the no. of moles of NaOH reacted equals to the no. of moles of HCl needed to react with it, which is 0.0025 mol.

Given the concentration of HCl in solution P is 0.1 mol /dm3. (pls correct me if I misunderstood your comment),

if v is the volume of HCl needed,

0.0025 = 0.1 v

v = 0.025 dm3

also = 25 cm3

Answer:

In this titration, solution P (that contains hydrochloric acid) is added into the conical flask that contains sodium hydroxide drop by drop. The indicator (phenolphthalein) changes color when all the NaOH is completely neutralized.

i) Solution P contains hydrochloric acid. Hydrochloric acid is the chemical that reacts with sodium hydroxide to give salt and water.

This type of reaction is called neutralization.

ii) Under alkaline conditions, phenolphthalein appears pink in color. When the solution becomes neutral or acidic, it is colorless.

So, the color change of the mixture at the end point is from pink to colorless.

Explanation:

When sodium hydride (NaH) is dissolved in water, it will react with the water molecules to form a strong base, the hydride ion (H-). The reaction can be represented as follows:

NaH + H2O → H- + Na+ + H2

Since the hydride ion is a stronger base than the hydroxide ion (OH-), it will react with water to form a stronger base, which is the hydroxide ion. The reaction can be represented as follows:

H- + H2O → OH- + H2

This reaction occurs because the hydride ion is a stronger base than the hydroxide ion. The hydride ion has a higher affinity for protons, and it can easily accept a proton from water to form the hydroxide ion. This reaction is important in many chemical processes, including the production of hydrogen gas from water, and the synthesis of various organic compounds. In summary, when sodium hydride is dissolved in water, it will react with water to form the strong base, the hydride ion, which will then react with water to form the stronger base, the hydroxide ion.

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Answer:

i think b(proton and neutrons)

When 156.32 g of barium hydroxide is reacted, approximately 142.34 g of aluminum hydroxide can be produced, based on the balanced chemical equation and stoichiometry.

To determine the amount of aluminum hydroxide that can be produced when 156.32 g of barium hydroxide is reacted, we need to consider the balanced chemical equation for the reaction and use stoichiometry.

The balanced chemical equation for the reaction is:

Ba(OH)2 + 2AlCl3 → 2Al(OH)3 + 3BaCl2

From the balanced equation, we can see that for every 1 mole of Ba(OH)2, 2 moles of Al(OH)3 are produced.

First, we need to calculate the number of moles of barium hydroxide (Ba(OH)2) in 156.32 g:

Molar mass of Ba(OH)2 = (137.33 g/mol + 2(16.00 g/mol + 1.01 g/mol)) = 171.34 g/mol

Moles of Ba(OH)2 = mass / molar mass = 156.32 g / 171.34 g/mol = 0.911 mol

Now, using the stoichiometry of the balanced equation, we can determine the moles of aluminum hydroxide (Al(OH)3) produced:

Moles of Al(OH)3 = 2 × Moles of Ba(OH)2 = 2 × 0.911 mol = 1.822 mol

Finally, to convert the moles of aluminum hydroxide to grams, we need to multiply by the molar mass of Al(OH)3:

Molar mass of Al(OH)3 = (26.98 g/mol + 3(16.00 g/mol + 1.01 g/mol)) = 78.00 g/mol

Mass of Al(OH)3 = Moles of Al(OH)3 × molar mass = 1.822 mol × 78.00 g/mol = 142.34 g

Therefore, when 156.32 g of barium hydroxide is reacted, approximately 142.34 g of aluminum hydroxide can be produced.

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From the calculations, we can see that the split of 6 users not writing off and 4 users writing off provides the highest entropy, which is 0.97.

To find the split that will provide the highest entropy, we need to consider different combinations of the population split.

First, let's calculate the entropy for the given split of 7 users not writing off and 3 users writing off:

Entropy = -(7/10) * log2(7/10) - (3/10) * log2(3/10) = 0.88

Now, let's consider different splits and calculate their respective entropies to find the highest entropy.

1. Split of 8 users not writing off and 2 users writing off:
Entropy = -(8/10) * log2(8/10) - (2/10) * log2(2/10) = 0.72

2. Split of 9 users not writing off and 1 user writing off:
Entropy = -(9/10) * log2(9/10) - (1/10) * log2(1/10) = 0.47

3. Split of 6 users not writing off and 4 users writing off:
Entropy = -(6/10) * log2(6/10) - (4/10) * log2(4/10) = 0.97

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Answer:

I think C option ✔️ ✔️ correct

Answer:

H2O + SO3 → H2SO4

this is the answer for

this question

True. An alloy is a solid solution consisting of two or more metallic elements, or a metallic element and a non-metallic element.

The properties of an alloy are usually different from those of its constituent elements. The reason for this is that the atoms of different elements in an alloy interact with each other differently than they would if they were in their pure elemental form. This interaction can lead to changes in the electronic and crystal structure of the alloy, which in turn can affect its physical and chemical properties. Some common examples of alloys include brass (copper and zinc), stainless steel (iron, chromium, and nickel), and bronze (copper and tin).

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Complete question:

An alloy is a mixture of elements that has metallic properties. True or False