can someone pls help me with this?

Can Someone Pls Help Me With This?

Answers

Answer 1
C because they are both going in a constant speed

Related Questions

The apparent brightness of stars in general tells us nothing about their distances; we cannot assume that the dimmer stars are farther away. In order for the apparent brightness of a star to be a good indicator of its distance, all the stars would have to be:__________.
a. at the same distance
b. the same composition
c. the same luminosity
d. by themselves instead of in binary or double-star systems
e. a lot farther away than they presently are

Answers

The answer is have the same luminosity

37. A baseball is pitched at a speed of 40 m/s. How long does it take the ball to travel 27
meters from the pitcher's mound to home plate?

Answers

Answer:

0.675

Explanation:

hope you get it right

Answer:

\(0.675\:\mathrm{s}\)

Explanation:

Displacement can be given as \(\Delta x=v_x\cdot t\)

Substituting given values, we have:

\(27=40t,\\t=\frac{27}{40}=\boxed{0.675\:\mathrm{s}}\)

The curved section of a speedway is a circular arc having a radius of 190 m. this curve is properly banked for racecars moving at 34 m/s. at what angle with the horizontal is the curved part of the speedway banked?

Answers

The banking angle of the curved part of the speedway is determined as 32⁰.

Banking angle of the curved road

The banking angle of the curved part of the speedway is calculated as follows;

V(max) = √(rg tanθ)

where;

r is radius of the pathg is acceleration due to gravity

V² = rg tanθ

tanθ = V²/rg

tanθ = (34²)/(190 x 9.8)

tanθ = 0.62

θ = arc tan(0.62)

θ = 31.8

θ ≈ 32⁰

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Taylor kicks a soccer ball with a force of 5 N. The soccer ball moves away from Taylor with a force _____.

greater than 5 N
less than 5 N
equal to 5 N

Answers

Answer:

greater then five

Explanation:

Answer:

Equal to 5

Explanation:

Newton's third law. Hit the baseball or kick the soccer ball with a small amount of force. The ball will not travel very far. Then, hit or kick the ball with a large amount of force and watch what happens. The ball will have an equal and opposite reaction to the amount of force it his hit with.

How do we find an electric potential from a plot of the electric field?.

Answers

Answer:

The field is the negative of the slope of the plot of the electric potential.

Explanation:

thanks for question

Daryl uses a microphone connected to an oscilloscope to study sound waves. He finds that higher pitched sounds have higher frequencies and shorter wavelengths while lower pitched sounds have lower frequencies and longer wavelengths. Daryl concludes that the relationship between the frequency and the wavelength of sound waves in air is the result of causation and not correlation. In two to three sentences, describe whether Daryl’s conclusion is correct and explain why or why not.

Answers

Daryl’s conclusion that the relationship between the frequency and the wavelength of sound waves in air is the result of causation is correct.

What is Causation?

This is defined as the relationship between successive events when the first event brings about the other.

The higher frequencies brings about shorter wavelengths which is why it is termed as being  a result of causation.

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Objects x and y are connected by a string of negligible mass and suspended vertically over a pulley of negligible mass, creating an atwood’s machine, as shown in the figure. The objects are initially at rest, and the mass of object y is greater than the mass of object x. As object y falls, how does the gravitational potential energy of the object x-object y-earth system change? all frictional forces are considered to be negligible.

Answers

We have that the  gravitational potential energy  effect on the system is mathematically given as

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.

Option C

From the question we are told

The objects are initially at rest, and the mass of object y is greater than the mass of object x. As object y falls, how does the gravitational potential energy of the object x-object y-earth system change? all frictional forces are considered to be negligible.

Centre of mass

Due to reduce in top of Y, doable strength will limit and due to amplify in peak of X, achievable power will increase.

Now, PE = mgh.

Generally the equation for the Velocity of centre of mass  is mathematically given as

\(V =\frac{ m1v1 + m2v2}{ m1 + m2}\\\\Therefore \\\\V =\frac{ (m1 - m2) v}{ m1 + m2}\)

Hence, V is positive as m1 > m2

Therefore

centre of mass of system moves downwards.

The conclusion

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.

Option C

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Complete Question

Objects X and Y are connected by a string of negligible mass and suspended vertically over a pulley of negligible mass, creating an Atwood’s machine, as shown in the figure.

The objects are initially at rest, and the mass of Object Y is greater than the mass of Object X. As Object Y falls, how does the gravitational potential energy of the Object Y-Object Y-Earth system change? All frictional forces are considered to be negligible.

a

The gravitational potential energy increases because the center of mass of Object X and Object Y moves upward.

b

The gravitational potential energy increases because the center of mass of Object X and Object Y moves downward.

c

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves downward.

d

The gravitational potential energy decreases because the center of mass of Object X and Object Y moves upward.

Two spacecraft
and
are traveling directly towards each other, intending to meet to dock together. Mission control on Earth initially sees spacecraft
moving with a speed of 154. 5 m/s and spacecraft
moving with a speed of 133. 0 m/s. Each spacecraft will need to come to a complete stop when they meet, and each will slow down using its rockets. The rockets on spacecraft
cause it to slow down at a constant rate of 17. 1 m/s2, and the rockets on spacecraft
cause it to slow down at a constant rate of 22. 2 m/s2. Spacecraft
turns on its rockets first. At what distance
from spacecraft
should spacecraft
turn on its rockets in order for the two spacecraft to meet, have zero velocity relative to the Earth, and arrive at the same time?

Answers

Solving for d using the calculated values for t, we find that the distance from spacecraft at which spacecraft should turn on its rockets is approximately 8670.7 meters.

To determine the distance from spacecraft at which spacecraft should turn on its rockets, we need to consider the motion of each spacecraft as it slows down.

Let's call the time elapsed from the moment spacecraft turns on its rockets until it comes to a complete stop t1. The initial velocity of spacecraft is 154.5 m/s and it slows down at a rate of 17.1 m/s^2, so its velocity after time t1 is given by:

v1 = 154.5 m/s - 17.1 m/s^2 * t1

The distance traveled by spacecraft during this time can be calculated as:

d1 = 154.5 m/s * t1 - (1/2) * 17.1 m/s^2 * t1^2

Next, let's call the time elapsed from the moment spacecraft turns on its rockets until it comes to a complete stop t2. The initial velocity of spacecraft is 133.0 m/s and it slows down at a rate of 22.2 m/s^2, so its velocity after time t2 is given by:

v2 = 133.0 m/s - 22.2 m/s^2 * t2

The distance traveled by spacecraft during this time can be calculated as:

d2 = 133.0 m/s * t2 - (1/2) * 22.2 m/s^2 * t2^2

Since the two spacecraft are moving towards each other, their relative velocity is the sum of their initial velocities:

v_rel = 154.5 m/s + 133.0 m/s = 287.5 m/s

The time elapsed until they meet, have zero relative velocity, and arrive at the same time, t, can be calculated as:

t = v_rel / (17.1 m/s^2 + 22.2 m/s^2)

The distance traveled by each spacecraft during this time can be calculated using the equations for velocity and distance given above. The total distance between the two spacecraft when they meet is the sum of these distances, so the distance from spacecraft at which spacecraft should turn on its rockets is given by:

d = d1 + d2 = (154.5 m/s * t - (1/2) * 17.1 m/s^2 * t^2) + (133.0 m/s * t - (1/2) * 22.2 m/s^2 * t^2)

Solving for d using the calculated values for t, we find that the distance from spacecraft at which spacecraft should turn on its rockets is approximately 8670.7 meters.

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Carlos listed some advantages and disadvantages of using nonrenewable resources. Which best describes Carlos's error? Coal is not plentiful anywhere. Coal generates very little energy. Ores do not make many useful products. Ores must be processed.

Answers

Answer:

This question is incomplete as it lacks the table that shows the advantages and disadvantages of the two mentioned nonrenewable source of energy (coal and ore). However, the question can be answered based on general understanding.

The answer is D. Ores must be processed.

Explanation:

Energy can be of two major sources namely: renewable and nonrenewable sources. Based on the mentioned area in this question, NONRENEWABLE SOURCES OF ENERGY are those sources of energy that cannot be replenished or replaced when exhausted. They are utilized faster than they form. Examples of nonrenewable sources of energy are coal, ores, fuel etc.

According to this question, Carlos listed some advantages and disadvantages of using nonrenewable resources. However, among the listed disadvantages, Carlo's error is that he included that: ORES MUST Be PROCESSED.

Ores are rock materials that contain metals, which are extracted and purified in a series of processing techniques. Hence, ORES NEED PROCESSING making Carlo's claim erroneous.

Answer:

Carlos listed some advantages and disadvantages of using nonrenewable resources.

Which best describes Carlos’s error?

Coal is not plentiful anywhere.

Coal generates very little energy.

Ores do not make many useful products.

Ores must be processed.

Explanation:

the answer is D

ou are examining a flea with a converging lens that has a focal length of 3.70cm .
Part A
If the image of the flea is 6.00 times the size of the flea, how far is the flea from the lens?
s = cm
Part B
Where, relative to the lens, is the image?
s? = cm

Answers

Part A- the flea is 5.29 cm in front of the lens.

Part b- The image of the flea is located 2.22 cm behind the lens.

Part A: We can use the magnification equation to find the object distance:

m = -i/o

where m is the magnification, i is the image distance, and o is the object distance.

We are given that the image is 6.00 times the size of the flea, which means that m = 6.00.

We also know that the lens has a focal length of f = 3.70 cm.

Substituting these values into the magnification equation, we get:

6.00 = -i/o

To solve for o, we can rearrange this equation to get:

o = -i/6.00

We also know that the lens equation is:

1/f = 1/o + 1/i

Substituting the values we have, we get:

1/3.70 = 1/o + 1/i

Solving for i, we get:

i = 1/((1/3.70) - (1/o))

i = 1/((1/3.70) - (1/(-i/6.00)))

Simplifying this expression, we get:

i = 2.22 cm

Therefore, the image distance is i = 2.22 cm.

We can now use the lens equation to find the object distance:

1/3.70 = 1/o + 1/2.22

Solving for o, we get:

o = 5.29 cm

Part B:

Since the image is real and inverted, it must be located on the opposite side of the lens from the object. Therefore, the image is located 2.22 cm behind the lens.

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Calculate the mass of a lorry that has a momentum of 4600 kg m/s and a velocity of 15m/s. Give your answer to two decimal places
PLZZZ HELP

Answers

Mass = momentum / velocity = 4600 / 15 = ..... Kg

1. The sun radiates light from space to heat a swimming pool on Earth.
a. Sound energy to light energy
b. Kinetic energy to nuclear energy
c. Light energy to thermal energy
Vesna bauoz of ya
visne ismert
d. Chemical energy to mechanical energy

Answers

Answer:

c. Light energy to thermal energy

Explanation:

The energy from the sun comes in the form of light energy but is converted to thermal energy.

You throw a dodge ball with a mass of 2.1 kg. The ball leaves your hand with a speed of 25 m/s. Identify the energy (PE or KE) and calculate it.

Answers

Given,

The mass of the object, m=2.1 kg

The speed of the object, v=25 m/s

Kinetic energy is the energy that an object possesses due to its motion. And potential energy is the energy that an object possesses due to its position.

The gravitational potential energy depends on the height of the object. As the change in the height of the object is not mentioned in the question, let us assume that there is no change in the potential energy.

The velocity of the object, however, changes. Thus the energy possessed by the object is the kinetic energy.

And the kinetic is given by

\(E_K=\frac{1}{2}mv^2\)

On substituting the known values,

\(\begin{gathered} E_K=\frac{1}{2}\times2.1\times25^2 \\ =656.25\text{ J} \end{gathered}\)

Thus the kinetic energy of the ball is 656.25 J

A platypus foraging for prey can detect an electric field as small as 0.002 N/C. to give an idea of sensitivity of the platypus's electric sense, how far from a 40 nc point charge does the field have this magnitude?

Answers

The field has a magnitude of 0.002 N/C when you are 1.8 meters away from a 40 NC point charge.

In order to find out how far away from a 40 NC point charge the field has a magnitude of 0.002 N/C, we can make use of Coulomb’s law which states that the electric field intensity is directly proportional to the inverse of the square of the distance from the point charge.

The formula for Coulomb’s law is:E = k q / r²Where E is the electric field intensity, k is Coulomb’s constant (9 x 10^9 N m² C^-2), q is the charge and r is the distance from the charge. We can use algebra to rearrange this formula to find the distance (r) from the charge: r = √(k q / E)

Plugging in the values we know, we get:r = √(9 x 10^9 x 40 x 10^-9 / 0.002)Simplifying this, we get:r = 1.8 m

Therefore, the field has a magnitude of 0.002 N/C when you are 1.8 meters away from a 40 NC point charge.

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pls help 15 pointssss

pls help 15 pointssss

Answers

Answer:

4.d 5.c

Explanation:

A butterfly is flying around and its velocity(v) as a function of time(t) is given in the graph below where rightwards is the positive velocity direction. What is the butterfly's displacement x from t=2 to 4s? Answer with two significant digits.

A butterfly is flying around and its velocity(v) as a function of time(t) is given in the graph below

Answers

Answer: 19 meters.

Explanation:

We want to find the total displacement between t = 2s and t = 4s.

To do it, we can integrate our function, first write our velocity equation.

for t ≤ 3s, we have a linear equation, let's write it:

A linear relationship can be written as:

y = a*t + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Now we can see that our line passes through the points (1, 0) and (0, -2)

then the slope is:

a = (0 -(-2)/(1 - 0) = 2/1 = 2

and knowing that when t = 0s, v(0s) = -2m/s, then our equation is:

v(t) = (2m/s^2)*t - 2m/s for t ≤ 3s

now, for t ≥3s the equation is constant, v(t) = 4m/s.

then we have

v(t) = (2m/s^2)*t - 2m/s -------if t ≤ 3s

v(t) = 4m/s ----- if t ≥ 3s

Now we integrate over time to get the position:

for t ≤ 3s we have:

p(t) = (1/2)*(2m/s^2)*t^2 - 2m/s*t + C

where C is a constant of integration, as we are calculating the displacement  this constant actually does not matter, so we can use C = 0m

p(t) = (1m/s^2)*t^2 - 2m/s*t  for t ≤ 3s

and p(3s) =  (1m/s^2)*3s^2 - 2m/s*3s = 9m - 6m = 3m is the initial position of the other part of the function.

for t ≥ 3s we have:

p(t) = 4m/s*t + p(3s) = 4m/s*t + 3m

then the position equation is:

p(t) = (1m/s^2)*t^2 - 2m/s*t  ---- t ≤ 3s

p(t) = 4m/s*t + 3m --- if t ≥ 3s

Now the displacement will be:

p(4s) - p(2s) where for each time, you need to use the correct function:

p(4s) = 4m/s*4s + 3m = 16m + 3m = 19m

p(2s) =  (1m/s^2)*2s^2 - 2m/s*2s = 4m - 4m = 0m

p(4s) - p(2s) = 19m - 0m = 19m

The butterfly displacement x from t=2 to 4s is 19 meters.

What is displacement?

The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolised as d or s), commonly known as length or distance.

The total displacement between t = 2s and t = 4s.

Integrate our function, the velocity equation.

for t ≤ 3s, we have a linear equation, let's write it:

A linear relationship can be written as:

y = a x t + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

The line passes through the points (1, 0) and (0, -2)

The slope is:

a = (0 -(-2)/(1 - 0) = 2/1 = 2

When t = 0s, v(0s) = -2m/s, then our equation is:

v(t) = (2m/s²) x t - 2m/s for t ≤ 3s

now, for t ≥3s the equation is constant, v(t) = 4m/s.

v(t) = (2m/s²) x t - 2m/s -------if t ≤ 3s

v(t) = 4m/s ----- if t ≥ 3s

Now we integrate over time to get the position:

for t ≤ 3s we have:

p(t) = (1/2) x (2m/s²) x t^2 - 2m/s x t + C

where C is a constant of integration, to calculate the displacement  this constant actually does not matter,

p(t) = (1m/s²)*t^2 - 2m/s x t  for t ≤ 3s

and p(3s) =  (1m/s^2) x 3s² - 2m/s x 3s = 9m - 6m = 3m is the initial position of the other part of the function.

for t ≥ 3s we have:

p(t) = 4m/s x t + p(3s) = 4m/s x t + 3m

then the position equation is:

p(t) = (1m/s^2) x t² - 2m/s x t  ---- t ≤ 3s

p(t) = 4m/s x t + 3m --- if t ≥ 3s

Now the displacement will be:

p(4s) - p(2s) where for each time, you need to use the correct function:

p(4s) = 4m/s x 4s + 3m = 16m + 3m = 19m

p(2s) =  (1m/s²) x 2s²- 2m/s x 2s = 4m - 4m = 0m

p(4s) - p(2s) = 19m - 0m = 19m

Thus, the displacement is 19 m.

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The sky is dark at night: Group of answer choices because the stars in the Milky Way are far away. because the Sun is on the other side of Earth. because there are far fewer stars on the night side of Earth. because all the light from all the objects in the unive

Answers

Answer:

Sun is on the other side

Explanation:

Select the correct answer from each drop-down menu. according to the giant impact theory, a giant mars-sized object collided with earth. this collision likely resulted in the , which creates on earth.

Answers

According to the giant impact theory, a giant Mars-sized object collided with Earth. This collision likely resulted in the spinning of the earth, which creates the length of the day on Earth.

The impact of the Mars-sized object caused a tremendous release of energy and angular momentum. This led to the spinning of the early Earth, which was initially in a molten state due to the extreme heat generated by the collision. As the debris from the impact settled and formed the Moon, the spinning of the Earth continued and eventually played a crucial role in the formation and stabilization of the Earth-Moon system.

The Earth's rotation rate changed as a result of the enormous impact's momentum transfer to it, as was previously mentioned. The impact accelerated Earth's spin, shortening days compared to those we currently experience. The Earth's rotation has slowed down over time as a result of tidal interactions with the Moon and Sun, which nevertheless have an impact on the length of a day. However, the original collision had a considerable impact on the early Earth's rotation rate, which in turn affected how long a day was at that time.

Hence, According to the giant impact theory, a giant Mars-sized object collided with Earth. This collision likely resulted in the spinning of the earth, which creates the length of the day on Earth.

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#Complete question is:

According to the giant impact theory, a giant Mars-sized object collided with Earth. This collision likely resulted in the ______ which creates _______ on Earth.

1st blank options:

craters on the moon

spinning of earth

formation of mars

tilting of earth's axis

2nd blank options:

tides

seasonal changes

length of a day

rotation

When light of frequency 3 × 10&14 Hz travels through a transparent material, the wavelength of the light in the material is 600 nm.
What is the index of refraction of this material?
Group of answer choices
6/5
5/4
5/3
10/9
3/2

Answers

The index of refraction of the transparent material where light has a wavelength of 600 nm and a frequency of 3 × 10¹⁴ Hz is 5/3. The correct option is 5/3.

To find the index of refraction (n) of a material, we can use the formula:

                          n = c / v

Where c is the speed of light in vacuum and v is the speed of light in the material.

Frequency of light, f = 3 × 10¹⁴ Hz

Wavelength of light in the material, λ = 600 nm = 600 × 10⁻⁹ m

The speed of light in vacuum is a constant, approximately 3 × 10⁸ m/s.

To find the speed of light in the material, we can use the formula:

                         v = f * λ

Substituting the given values:

v = (3 × 10¹⁴ Hz) * (600 × 10⁻⁹ m)

Calculating the value of v:

v = 1.8 × 10⁸ m/s

Now we can find the index of refraction:

n = c / v

n = (3 × 10⁸ m/s) / (1.8 × 10⁸ m/s)

Simplifying the expression:

n = 1.67

Among the given answer choices, the closest value to the calculated index of refraction is 5/3.

Therefore, the correct answer is 5/3.

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\(\bold{\huge{\underline{ Hola \: Brainlians!!! }}}\)

Three particles A, B and C are situated at the vertices of an equilateral triangle ABC of side d at time t = 0. Each of the particles moves with constant speed v. A always has its velocity along AB, B along BC and C along CA. At what time will the particles meet each other ?

- Don't want spam or copied answers
- Don't be greedy for points
- Best answer will be awarded with brainliest. ​

Answers

Given :-

Three particles A, B and C are situated at the vertices of an equilateral triangle ABC.The side of the triangle is d .A always has its velocity along AB, B along BC and C along CA.

To Find :-

Time at which the particles will meet .

Solution :-

See attachment .

Firstly break the velocity of A , into it's vertical components . That will be ,

\( v_A = v_A cos60^o + v_A sin60^o \)

Now the component , \(v_A cos60^o \) coincides on side AC and is directed from A to C . Along CA, the velocity of particle C is directed . So both are in opposite directions.

So , the relative velocity of C with respect to A will be ,

\( v_{CA}= v_C - v_A \)

Substitute ,

\( v_{CA}= v - ( - v cos 60^o) \)

Value of cos 60° is 1/2 ,

\( v_{CA}= v + v\bigg(\dfrac{1}{2}\bigg)=v +\dfrac{v}{2}\)

Add the terms,

\( v_{CA}= \dfrac{2v + v}{2}=\dfrac{3v}{2}\)

Hence , now we can find the time taken by A and C ,to meet each other will be ,

Since the speed is constant , we can use distance = speed*time , as ;

\(s = v t \)

Substitute ,

\(d = \dfrac{3v}{2} t \)

Multiplying both sides by 2 ,

\( 2d = 3vt \)

Dividing both sides by 3v ,

\( t = \dfrac{2d}{3v} \)

Similarly , taking any two particles you will get the same time .

Hence the particles meet after 2d/3v time .

I hope this helps .

[tex]\bold{\huge{\underline{ Hola \: Brainlians!!! }}}[/tex]Three particles A, B and C are situated at

Answer:

  never

Explanation:

Particles moving on paths that don't meet at a point will be particles that never meet. Even if the paths meet at a point, which these don't, the particles may not meet if they arrive at different times.

__

Consider the diagrams in the attachments. In order, they show the positions of the particles shortly after takeoff, midway along the line, and after they have gone farther than the length of the line. The point of closest approach is shown in the second attachment, when the particles are halfway along the line.

Consider particles A and C. Their north/south direction is 'north' for each of them. They both have the same velocity in the 'north' direction, but have started at different points, so can never meet. Those two particles have opposite velocities in the east/west direction, so can pass each other (which they do in the second attachment), but cannot meet.

[tex]\bold{\huge{\underline{ Hola \: Brainlians!!! }}}[/tex]Three particles A, B and C are situated at
[tex]\bold{\huge{\underline{ Hola \: Brainlians!!! }}}[/tex]Three particles A, B and C are situated at
[tex]\bold{\huge{\underline{ Hola \: Brainlians!!! }}}[/tex]Three particles A, B and C are situated at

give two examples of human traits that are not mentioned in the section above.

Answers

Answer:

where is the section?huh,I need to know

True or false. When populations do not exceed their environment carrying capacity biology communities are stable?

Answers

Answer:
True

Explanation:
Biology communities are stable when populations do not exceed their environments carrying capacity. Their communities are also stable when the resources for survival are sustained.

Answer:

True

Explanation:

What is the magnitude of the x-component of force ?

What is the magnitude of the x-component of force ?

Answers

ANSWER

EXPLANATION

If force F keeps the object in equilibrium

Answer:

See below

Explanation:

Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)

30 cos 55  +     40 cos 205   +   50 cos 320  =  19.26    <====x component sum of all of the forces shown

F  (the x component of ) will be   Either    - 19.26   At zero degrees

                                                                 Or 19.26 at 180 degrees

6.A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of
rocks, which doubles its mass, and leaves at the same speed of 20 m/s. Compare the
kinetic energy of the truck as it left the quarry with its kinetic energy on the way to the
quarry. Explain your answer.

Answers

Explanation:

The kinetic energy is basically the energy possesses by virtue of a body's motion

1. The truck moving to the quarry

let the mass be x

and the velocity is given as 20m/s

we know that the kinetic energy is given as

KE=1/2mv^2

KE=1/2(x)*20^2

KE=1/2(x)400

KE=200x

2. The truck leaving to the quarry

let the mass be 2x

and the velocity is given as 20m/s

we know that the kinetic energy is given as

KE=1/2mv^2

KE=1/2(2x)*20^2

KE=1/2(2x)400

KE=400x

From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy

You are asked to solve a nonlinear equation f(x) = 0 on the interval [1, 5] using Newton's method. Tick ALL of the following that are true: This iterative method requires one starting point. This iterative method requires two starting points. This iterative method requires evaluation of derivatives of f. This iterative method does not require evaluation of derivatives of f. This iterative method requires the starting point(s) to be close to a simple root. This iterative method does not require the starting point(s) to be close to a simple root. If f = C([1,5]) and ƒ(1)ƒ(5) <0, then, with the starting point x₁ = 3, this iterative method converges linearly with asymptotic constant 3 = 0.5. If f(x) = 0 can be expressed as a = g(x), where g = C¹([1,5]) and there exists K = (0, 1) such that g'(x)| ≤ K for all x = (1,5), then this iterative method converges linearly with asymptotic constant

Answers

1, 3, 5, and 7 statements are true to solve a nonlinear equation using Newton's method.

The true statements are:

This iterative method needs one starting point.This iterative method needs the evaluation of derivatives of f.This iterative method needs the starting point(s) to be close to a simple root.If f(x) = 0 can be represented as a = g(x), where g = C¹([1,5]) and there exists K = (0, 1) such that g'(x)| ≤ K for all x = (1,5), then this iterative method combines linearly with asymptotic constant.

While other statements are false. Therefore, 1, 3, 5, and 7 statements are correct.

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the speed of an electric locomotive is 90kmh .express this speed in m/s with method​

Answers

Answer:

24.3 m/s

Explanation:

1 kmh = 0.27 m/s, that makes a conversion ratio of 0.27/1kmh

\(\frac{90 kmh}{1}\) x \(\frac{0.27 m/s}{1 kmh}\)

The "kmh" n the top and bottom cancel out. And  then you just multiply the top 90 x 0.27 and the bottom 1 x 1 to get

\(\frac{24.3 m/s}{1}\)

and since its over 1 its just 24.3 m/s

A cougar with a mass of 80 kg is standing at the edge of a cliff. Find the cougar's potential energy if the cliff is 70 m high. show your work !!!

Answers

The potential energy of the 80kg cougar at a height of 70m is 54880 Joules.

What is the potential energy of the cougar?

Potential energy is simply the energy a body possesses due to its position.

It is expressed mathematically as;

P.E = mgh

Where m is mass, h is height and g is acceleration due to gravity ( g = 9.8m/s² )

Given the data in the question;

Mass of the cougar m = 80kgHeight h = 70mPotential energy P.E = ?

Plug the given values into the potential energy formula above and solve.

P.E = mgh

P.E = 80kg × 9.8m/s² × 70m

P.E = 54880kgm²/s²

P.E = 54880 Joules.

Therefore, the potential energy of the cougar is 54880 Joules.

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Rogan claims that he can run 8 miles per hour. Use the speed formula to determine how many minutes it would take him to run one mile.

Answers

Answer:

he would have to run at a 7 and a half mile to get 8 miles in an hour

Explanation:

Answer:

7.5 minutes

Explanation:

We know that there are 60 minutes in an hour. So, we can say that Rogan can run 8 miles per 60 minutes. Now, we can create an equation to solve for how many minutes it would take per mile.

8/60 = 1/x

x = 7.5

So, it would take Rogan approximately 7.5 minutes to travel 1 mile.

During a baseball game, a batter hits a ball directly back to the pitcher who catches it. An observer flying over the stadium at a speed of 0.75c, measures 0.658 s as the time between the two events (hitting and catching the ball). What is the proper time interval between the two events? a. 0.658 s b. 0.435 s c. 0.994 s d. 0.288 s
e. 0.715 5

Answers

The proper time interval between the two events is 0.435 s. Hence, the correct option is (b) 0.435 s.

Given that an observer flying over the stadium at a speed of 0.75c, measures 0.658 s as the time between the two events (hitting and catching the ball).

To find the proper time interval between the two events.

The time interval measured by the observer is called the "dilated" time interval (t').

The proper time interval (Δt) is found using the formula,

Δt = t' / γ

where

γ = 1 / √[1 - (v/c)²] is the Lorentz factor, v is the velocity of the observer, and c is the speed of light.

Given:

v = 0.75c, t' = 0.658 s, and

c = speed of light = 3 × 10⁸ m/s

Thus,

γ = 1 / √[1 - (v/c)²]

= 1 / √[1 - (0.75)²]

= 1 / √(0.4375)

= 1 / 0.6614

= 1.5126

Therefore, Δt = t' / γ

= 0.658 / 1.5126

≈ 0.435 s

Therefore, the proper time interval between the two events is 0.435 s. Hence, the correct option is (b) 0.435 s.

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the two best means of avoiding injury from electrical devices are

Answers

1. Proper Training and Knowledge: The first and most important step in avoiding injury from electrical devices is to receive proper training and knowledge about how to safely operate and handle electrical equipment. It's essential to understand the risks and hazards associated with electrical devices, including the dangers of electric shock and the potential for fire or explosion.

2. Use of Protective Gear and Equipment: Another crucial means of avoiding injury from electrical devices is to use appropriate protective gear and equipment.

This includes wearing rubber gloves and safety glasses when working with electrical equipment, using insulated tools to prevent electric shock, and wearing appropriate clothing to reduce the risk of fire or electrical burns. Additionally, always make sure to use equipment that is properly grounded and to avoid using damaged or frayed electrical cords.

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