Answer:
c. 13
Step-by-step explanation:
\(c=\sqrt{a^{2}+b^{2}} = \sqrt{12^{2}+4^{2}}\) ≈ \(12.64911\) ≈ \(13\)
Solve the equation -25p – 2 = 48 for p.
A. -2
B. 1
C. 3
D. 8
Answer:
A. -2
Step-by-step explanation:
-25p - 2 = 48
First, add 2 to both sides
That gives you
-25p = 50
Then, divide both sides by -25. Then that leaves the answer.. p = -2
A professor collects 50 independent and identically distributed observations of variables Y and X for a regression. Her student wishes to use the same data to run the same regression but the student makes an error of entering each observation twice. That is the student enters observation 1 twice, observation 2 twice and so forth so that the student has a sample of 100. Which OLS assumption is violated if the student uses this data to run a regression? Suppose the student does run a regression, will the slope coefficients be different from the professor’s regression?
The coefficients obtained by the student may be less efficient and have larger standard errors compared to the professor's regression.
If the student enters each observation twice, resulting in a sample size of 100 instead of the original 50, the assumption of independent observations is violated in Ordinary Least Squares (OLS) regression. The OLS assumption assumes that the observations are independent, meaning that the value of one observation does not depend on the value of another observation.
In this case, the student's dataset contains repeated observations, which introduces dependence between observations. This violation of the independence assumption can lead to biased and inconsistent parameter estimates in the regression analysis.
Regarding the slope coefficients, if the student runs a regression using the duplicated data, the estimated coefficients may be different from the professor's regression. The duplication of observations inflates the sample size, potentially affecting the precision and accuracy of the estimates.
However, the direction and overall relationship between the variables may still be captured by the student's regression, although the estimates may not be as reliable.
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what multiple of 7 is greater than 28 but less than 42
Answer:
The answer is 35.
Step-by-step explanation:
7 x 4 = 28
7 x 5 = 35
7 x 6 = 42
Answer:
35
Step-by-step explanation:
Find the distance between the given parallel planes. 3x−5y+z=12,6x−10y+2z=1
To find it, we can use the formula: distance = |d1 - d2| / √(A^2 + B^2 + C^2), where d1 and d2 are the distances from the origin to each plane, and A, B, and C are the coefficients of the normal vector of the planes.
The given equations of the planes are 3x - 5y + z = 12 and 6x - 10y + 2z = 1. By comparing the coefficients of x, y, and z, we can determine the normal vectors of the planes as (3, -5, 1) and (6, -10, 2), respectively.
The distances from the origin to each plane can be calculated by substituting (0, 0, 0) into the plane equations. The distance for the first plane is |12| / √(3^2 + (-5)^2 + 1^2) = 12 / √35, and the distance for the second plane is |1| / √(6^2 + (-10)^2 + 2^2) = 1 / √140.
Finally, we can find the distance between the two planes by evaluating |12 / √35 - 1 / √140|.
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The measure of angle(theta) Is 2pi/3, which statements are true?
cos(theta) = √3/2
The measure of the reference angle is 30°.
The measure of the reference angle is 45°.
The measure of the reference angle is 60°.
tan(theta) = -√3
None of the statements are true for the given angle θ = 2π/3.
For the given angle θ = 2π/3, let's evaluate the statements:
1. cos(theta) = √3/2
To determine if this statement is true, we can calculate the cosine of θ:
cos(2π/3) = -1/2
The statement cos(theta) = √3/2 is not true for θ = 2π/3.
2. The measure of the reference angle is 30°.
The reference angle is the positive acute angle between the terminal side of the angle and the x-axis. Since the given angle θ = 2π/3 is in the second quadrant, the reference angle cannot be 30°.
3. The measure of the reference angle is 45°.
Similar to the previous statement, since θ = 2π/3 is in the second quadrant, the reference angle cannot be 45°.
4. The measure of the reference angle is 60°.
Again, considering the quadrant of θ = 2π/3, the reference angle cannot be 60°.
5. tan(theta) = -√3
To verify this statement, we can calculate the tangent of θ:
tan(2π/3) = √3
The statement tan(theta) = -√3 is not true for θ = 2π/3.
In summary, none of the statements are true for the given angle θ = 2π/3.
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6) Make the following function linear using logarithms. \[ Q=f(L, K)=20 L^{2} K^{1} \]
Answer:
The linear function is given by z= log(20) +2y + x, where z=log(Q), y= log(L) and x=log(K).
Explanation:
we have given Q=f(L, K)=20 L^{2} K^{1}
Taking logarithms on both sides,
log(Q) = log(20) + 2log(L) + log(K)
let z=log(Q), y= log(L) and x=log(K)
we obtain
z= log(20) +2y + x
the statue of liberty in new york city is approximately 305 ft tall. how many u.s. half dollars would be in a stack of the same height? each half dollar is 2.15 mm thick.
There would be approximately 43,149 U.S. half dollars in a stack that is the same height as the Statue of Liberty.
To determine the number of U.S. half dollars that would be in a stack the same height as the Statue of Liberty, we need to convert the height of the statue from feet to millimeters and then divide it by the thickness of a single half dollar.
First, let's convert the height of the Statue of Liberty from feet to millimeters. We know that 1 foot is equal to 304.8 millimeters (rounded to the nearest tenth). Therefore, the height of the Statue of Liberty in millimeters is:
305 ft * 304.8 mm/ft = 92918 mm (rounded to the nearest whole number)
Next, we need to determine the thickness of a U.S. half dollar. Given that each half dollar is 2.15 mm thick, we can now calculate the number of half dollars in a stack that is the same height as the Statue of Liberty:
Number of half dollars = Height of stack / Thickness of a half dollar
Number of half dollars = 92918 mm / 2.15 mm
Number of half dollars ≈ 43149 (rounded to the nearest whole number)
Therefore, there would be approximately 43,149 U.S. half dollars in a stack that is the same height as the Statue of Liberty.
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Help me please will name brainliest !!!!
Answer:
first 4 options..
. mark me the Brainliest.. pls
help me with this question please
Answer:
$3h
Step-by-step explanation:
w=$44+$12h
w=$35+$15h
$44+$12h=$35+$15h
-12 -12
$44=$35+$3h
-35 -35
$9=3h
/3 /3
$3=h
5. Chris, Kiona, Seiko, and Dwayne each run 100 meters in a relay
race. Chris runs his part of the race in 12.35 seconds, Kiona takes
13.12 seconds, and Seiko takes 11.91 seconds.
a. The team wants to break the school record of 48.92 seconds. How
fast will Dwayne have to run?
b. The team sets a new record of 47.65 seconds for the relay race.
On average, how many meters did the team members run
per second?
c. On average, how long did it take each team member to run
100 meters?
VANUAT
Dwayne will need to run the final 100 meters in 11.54 seconds. The meters the team members run per second is 8.195 meters/second.
How to calculate measurementsa. To break the school record of 48.92 seconds, the team needs to complete the relay race in less than 48.92 seconds.
The total time for Chris, Kiona, and Seiko is 12.35 + 13.12 + 11.91 = 37.38 seconds.
Therefore, Dwayne will need to run the final 100 meters in 48.92 - 37.38 = 11.54 seconds.
b. The total time for the team to run 400 meters is 47.65 seconds. Therefore, the average time per meter is:
47.65 seconds / 400 meters = 0.1191 seconds/meter
Therefore, on average, each team member ran:
Chris: 100 meters / 12.35 seconds = 8.09 meters/second
Kiona: 100 meters / 13.12 seconds = 7.63 meters/second
Seiko: 100 meters / 11.91 seconds = 8.39 meters/second
Dwayne: 100 meters / 11.54 seconds = 8.67 meters/second
The average of these values is:
(8.09 + 7.63 + 8.39 + 8.67) / 4 = 8.195 meters/second
c. On average, each team member took the following time to run 100 meters:
Chris: 12.35 seconds
Kiona: 13.12 seconds
Seiko: 11.91 seconds
Dwayne: 11.54 seconds
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i forgot to attach the photo before.... please help
Part (i)
I'll use H in place of T to represent the heat of the object. That way there isn't a clash of variables lowercase t vs uppercase T.
The equation we're working with is updated to:
H(t) = 22 + a*2^(bt)
Plugging in t = 0 as the initial time value should lead to the temperature being H = 86 degrees Celsius.
So,
H(t) = 22 + a*2^(bt)
86 = 22 + a*2^(b*0)
86 = 22 + a*2^0
86 = 22 + a*1
86 = 22 + a
a+22 = 86
a = 86-22
a = 64
Answer: 64=====================================================
Part (ii)
We'll use the value of 'a' we found earlier. Plus we'll use the fact that H = 28 when t = 0.5 (since 30 min = 30/60 = 0.5 hr).
H(t) = 22 + a*2^(bt)
28 = 22 + 64*2^(b*0.5)
28-22 = 64*2^(0.5b)
64*2^(0.5b) = 6
2^6*2^(0.5b) = 6
2^(6+0.5b) = 6
log( 2^(6+0.5b) ) = log(6)
(6+0.5b)*log(2) = log(6)
6+0.5b = log(6)/log(2)
6+0.5b = 2.5849625
0.5b = 2.5849625-6
0.5b = -3.4150375
b = -3.4150375/(0.5)
b = -6.830075
Answer: Approximately -6.830075Please Help ASAP! Find X.
The measure of angle x is 70°.
How to find the value of angle x?Here we have the image of some triangles, and we want to find the value of the interior angle x in the left triangle.
What you need to remember here is that the sum of the interior angles of any triangle is always equal to 180°.
Then, for the left triangle, we can write:
30° + 80° + x° = 180°
Now we can solve that equation for x, then we will get:
x° = 180° - 80° - 30°
x = 70°
That is the measure of angle x.
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for the following 3 questions: a study obtained data on the amount of time 28 randomly selected high school students and 31 randomly selected college students spend on their cell phones each day. the investigator is interested in determining whether there is evidence that the amount of time students spend on their cell phone is different between high school and college Let H= time spent on phone by high school students; C= Time spent on phone by college students; and d=H−C
The data are not paired because: o All of these are true o Each element in a sample is measured once: time spent on cell phone o The conclusion pertains to the difference of two independent population means o There are two samples
The correct answer is
H₀ : μh - μc = 0
H₀ : μh - μc ≠ 0
Given that,
Regarding the subsequent 3 inquiries: A study collected information on how much time 28 randomly chosen high school students and 31 randomly chosen college students spent each day on their cellphones. The researcher is interested in learning whether there is proof that students use their phones for varying amounts of time in high school and college.
Because the samples of college and high school students are independent, the independent samples t-test should be utilized.
The study's research (Claim) aims to ascertain whether students' cell phone usage patterns alter between high school and college.
For the independent samples t-test and the stated claim, the proper null and alternate hypotheses are,
H₀ : μh - μc = 0
H₀ : μh - μc ≠ 0
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The proper null and alternative hypotheses are
\(H_{0}\) : μh = μc
\(H_{A}\) : μh - μc
The study's research wants to ascertain whether difference between the time spent by high school students and college students.
The actual test begins by considering two hypothesis i.e. null hypothesis and alternative hypothesis.
Let, H= time spent on the phone by high school students;
C= Time spent on the phone by college students; and
d=H−C
For the independent samples t-test and the stated claim, the proper null and alternate hypotheses are,
\(H_{0} :\) μh = μc (time spent by high school students is equal to college students)
\(H_{A} :\) μh - μc (difference between the time spent by high school students and college students)
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can someone help me with #2 and #4
if a 10,000 kg ufo made of antimatter crashed with a 40,000 kg plane made of matter, calculate the energy of the resulting explosion.
To calculate the energy of the resulting explosion when a 10,000 kg UFO made of antimatter crashes with a 40,000 kg plane made of matter, we can use Einstein's famous equation, E=mc², which relates energy (E) to mass (m) and the speed of light (c).
In this case, we'll need to calculate the total mass of matter and antimatter involved in the collision and then use the equation to find the energy released. The equation E=mc² states that energy is equal to the mass multiplied by the square of the speed of light (c). In this scenario, we have a collision between a UFO made of antimatter and a plane made of matter. Antimatter and matter annihilate each other when they come into contact, resulting in a release of energy.
To calculate the energy of the resulting explosion, we need to determine the total mass involved in the collision. The total mass can be calculated by adding the masses of the UFO and the plane together. In this case, the UFO has a mass of 10,000 kg and the plane has a mass of 40,000 kg, so the total mass is 50,000 kg.
Next, we can use the equation E=mc² to calculate the energy. The speed of light (c) is a constant value, approximately 3 x 10^8 meters per second. Plugging in the values, we have E = (50,000 kg) x (3 x 10^8 m/s)². Simplifying the equation, we have E = 50,000 kg x 9 x 10^16 m²/s².Multiplying the numbers, we get E = 4.5 x 10^21 joules. Therefore, the energy of the resulting explosion when the UFO and plane collide is approximately 4.5 x 10^21 joules.
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inscribed angles. finding x
need help with both questions
Check the picture below.
on 8), both angles are inscribed in the circle, and both are intercepting the same arc, thus they must be the same angle value.
on 9), the inscribed angle theorem refers to the angle of the intercepted arc, and the arc gets its angle value from the central angle, on this case, the central angle for the red arc is 64°, so the inscribed angle intercepting it, must be half that.
can anyone help me please??? its due the tenth and i need help
Answer:
m<CAG = 54
m<GAF = 56
m<FAE = 34
m<EAD = 36
m<DAB = 110
m<CAB = 70
Step-by-step explanation:
4x + m<FAE = 90
m<FAE + 36 = 5x
5x - m<FAE = 36
4x + m<FAE = 90
9x = 126
x = 14
5x + 4x + m<CAG = 180
9x + m<CAG = 180
9(14) + m<CAG = 180
m<CAG = 54
m<GAF = 4x
m<GAF = 4(14)
m<GAF = 56
4x + m<FAE = 90
4(14) + m<FAE = 90
m<FAE = 34
m<EAD = 36
m<DAB + 5x = 180
m<DAB + 5(14) = 180
m<DAB = 110
m<CAB = 5x
m<CAB = 5(14)
m<CAB = 70
1 pointA triangle is dilated by a scale factor of 3 with thecenter of dilation at the origin. Which statement istrue?1) The area of the image is nine times the area ofthe original triangle.2) The perimeter of the image is nine times theperimeter of the original triangle.3) The slope of any side of the image is threetimes the slope of the corresponding side of theoriginal triangle.4) The measure of each angle in the image is threetimes the measure of the corresponding angleof the original triangle.
We have two triangles. One is the dilated image, with a scale factor of 3, of the other triangle.
The angles of the dilated triangles stay the same, that is, they have the same measure.
The sides increase their length by a factor of 3.
Then, if we calculate the area, we will have:
\(A_2=\frac{b_2h_2}{2}=\frac{(3b_1)(3h_1)}{2}=9\frac{b_1h_1}{2}=9A_1\)Then, the area of the dilated triangle is 3^2=9 times the are of the pre-image triangle.
Answer: 1) The area of the image is nine times the area of the original triangle.
I need help with this practice problem I will send an additional pic of the rest of the answer options
SOLUTION
Consider the given coordinates
\((-3,-\frac{7\pi}{4})\)Since the angle given is negative, we move in the clockwise direction
Henece
\(\frac{7\pi}{4}=\frac{7\pi}{4}\times\frac{180}{\pi}=315^0\)Moving in the clockwise direction, the angle 315 falls in the first quadrant.
Then, -3 will be to move to the third quadrant,
hence the right option will be
A babe flies at 10 feet per second directly to a flowerbed from its hive. the bee stays at the flowerbed 12 minutes,and the flies directly back to the the hive 6 feet per second.it is away from the hive for a total of 16 minutes
The equation used to find the distance of the flowerbed from the hive is called the "time equation".
The flowerbed is 900 feet far from the hive.
What is the formula used to calculate Time Equation?To calculate the time equation use the formula for time, t = d/s which means time equals distance divided by speed.Find the height using the Time Equation?Find the traveling time
The bee spends 12 minutes hunting down the nectar in the flowerbed. Since it was away from the hive for a total of 16 minutes, the traveling time is
16min - 12min = 4 min
Convert the Minutes to seconds
1 minute = 60 seconds
4 minutes = 4*60 = 240 seconds
Find the time each way
The total time is 240 seconds, but it is not divided evenly.
Let the time there = t
Let the time back = 240 - t
The distances are the same
r = 10 m/s
r1 = 6 m/s
t1 = t
t2 = 240 - t
dthere = dback
d = rate * time
10 m/s *t = 6 m/s (240 - t)
Remove the brackets on the right.
10 * t = 6*240 - 6t
Combine the like terms on the right.
10t = 1440 - 6t
Add 4t to both sides
10t + 6t = 1440 - 6t + 6t
Combine
16t = 1440
Divide both sides by 16
16t/16 = 1440/16
Do the division
t = 90
Find the height
d = ?
r = 10 m/s
t = 90 second
d = r*t
d = 10 * 90 = 900 feet
The flowerbed is 900 feet far from the hive.
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The complete question is:
A babe flies at 10 feet per second directly to a flowerbed from its hive. the bee stays at the flowerbed for 12 minutes and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes.
What equation can you use to find the distance of the flowerbed from the hive?
I need help ASAP
What is the value of w-1(3)?
A
B
C
D
Answer:
its A -0.75
Step-by-step explanation:
Answer:
its A
Step-by-step explanation:
i got it right on edge unit review
Please answer question now
Answer:
MN = 3
Step-by-step explanation:
The following are congruent to each other as each pair are tangents of a circle drawn from the same external point:
PQ = QJ = 1
JK = KL = 4 - 1 = 3
MN = ML
Thus, ML = KM - KL
ML = 6 - 3 = 3
Therefore, MN = ML = 3 (both are tangents drawn from the same external point, M.
X
-6
-5
-4
-3
-2
-1
0
1
Y
0
-9
-12
-9
0
15
36
63
vertex?
this picture would help you man stay strong
y²+4y-2 evaluate the expression when y=7
Answer:
75
Step-by-step explanation:
You want the value of y² +4y -2 when y=7.
SubstitutionPut the value where the variable is and do the arithmetic.
7² +4·7 -2
= 49 +28 -2
= 77 -2
= 75
The value of the expression is 75.
__
Additional comment
It is often easier to evaluate a polynomial when it is written in Horner form:
(y +4)·y -2
= (7 +4)·7 -2 = 11·7 -2 = 77 -2 = 75
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complete each statement using Parallelogram DCBA
Answer:
AD and BC are congruent, so if AD = 20 then BC = 20
AB and DC are also congruent, so if AB = 13 then DC = 13
DE is one half of DB, so if DB = 22 then DE = 11
AE is one half of AC, so if AE = 18 then AC = 36
Also for the one in the corner...
The 2 angles are also congruent, so if ADC = 115° then ABC = 115°
Hope this helps! :)
Write the following expression using a single exponent.
(85)2 x 86
A. 8 16
B.
8 13
C. 8 4
D. 8 42
1. Please Determine the equation of the line from the tables and the graphs.
1. find equation of line with given data :
b) from the given table, we get y - intercept (c) = -4
now let's find slope (m) :
\( \dfrac{y_2-y_1}{ x_2 - x_1}\)\( \dfrac{0 - ( - 2)}{10 - 5} \)\( \dfrac{2}{5} \)so, the required equation will be :
\(y = \dfrac{2}{5} x - 4\)c) from the given graph we can see that y - intercept (c) = 3
now, let's find the slope (m) :
\( \dfrac{3 - 0}{0 - 7} \)\( - \dfrac{3}{7} \)the equation will be :
\(y = - \dfrac{3}{7} x + 3\)d) From this graph we get y - intercept (c) = -4
slope :
\( \dfrac{4 - 0}{4 - 2} \)\( \dfrac{4}{2} \)\(2\)so, required equation will be :
\(y = 2x - 4\)A small business owner contributes $2,000 at the end of each quarter to a retirement account that earns 10% compounded quarterly. (a) How long will it be until the account is worth at least $150,000? (Round your answer UP to the nearest quarter.) 43 quarters (b) Suppose when the account reaches $150,000, the business owner increases the contributions to $4,000 at the end of each quarter. What will the total value of the account be after 15 more years? (Round your answer to the nearest dollar.) $
After 15 more years of contributions of $4,000 at the end of each quarter, the retirement account will be worth approximately $760,514.47.
To calculate this, we need to use the formula for the future value of a lump sum. A lump sum is a one-time payment made at the beginning or end of a specific period. In this case, we're looking at the future value of the retirement account after 15 more years of contributions.
Using the given information, we can plug in the values and solve for FV:
PV = $150,000
Pmt = $4,000
r = 10%
n = 4 (since interest is compounded quarterly)
t = 15 years
First, we need to calculate the future value of the current investment of $150,000:
FV1 = $150,000 x (1 + 0.1/4)⁴ ˣ ¹⁵ = $548,534.24
Then, we can calculate the future value of the quarterly contributions of $4,000 over 15 years:
FV2 = $4,000 x [(1 + 0.1/4)⁶⁰ - 1] / (0.1/4) = $211,980.23
Finally, we can add FV1 and FV2 to get the total future value of the retirement account after 15 more years:
Total FV = FV1 + FV2 = $548,534.24 + $211,980.23 = $760,514.47
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What are the coordinates of the vertices after a rotation 90 counterclockwise around the origin.
Answer:When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.
Step-by-step explanation: trust me
Which point represents the center of the circle shown below?
X
T