Can someone plz help

Answer:

The total cost of putting on the play is $500 for theater rental + $500 for actors + $750 for set decorations and costumes = $1750.

To reach the break-even point, the revenue from ticket sales needs to equal the total cost, so $1750 = $25 x (number of tickets sold).

Solving for the number of tickets sold, we can divide both sides by $25: $1750 / $25 = (number of tickets sold).

This gives us: 70 = number of tickets sold.

Therefore, Mr. Curry needs to sell 70 tickets to reach the break-even point.

Step-by-step explanation:

Answer:

A.

Stepby-step explanation:

The key phrase in this question is "leading term equals x3," "highest coefficient is 2," and "1 is a fixed integer."

A polynomial is a mathematical operation with factors and uncertainty that uses only additions, erasures, multiplications, and powers of positive integer variables. There is just one indeterminate x polynomial identified by the formula x2 4x Plus 7. The word "polynomial" refers to an expression in mathematics that consists of variables (also referred to as "indeterminates") and coefficients that can be introduced, subtracted, repeated, and raised to minus integer ones of non-variables. A polynomial is an algebraic expression with factors and coefficients. Only addition, deduction, multiplication, and non-negative numerical exponents are permitted in expressions. The term for these expressions is polynomials.

given

Given  circumstance;

Any equation, like 2x³ + 3x + 1,

This is how the equation is written:  ax³ + bx + c

In this case, a = dominating Coefficient;

leading term Equals x³ 

Constant term Means

The key phrase in this question is "leading term equals x3," "highest coefficient is 2," and "1 is a fixed integer."

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Answer:

The empty set is defined as the complement of the universal set. That means where Universal set consists of a set of all elements, the empty set contains no elements of the subsets. The empty set is also called a Null set and is denoted by '{}'.

HOPE IT HELP YOU!

Answer:

The empty set is defined as the complement of the universal set. That means where Universal set consists of a set of all elements.

Based on the given information, it is not possible to determine the p-value, decision to reject (rh0) or failure to reject (frh0) without additional data or context.

To assess whether the relaxation exercise slowed brain waves, a statistical analysis should be conducted on a sample from the population.

The analysis would involve measuring brain waves before and after the exercise and comparing the results using appropriate statistical tests such as a t-test or ANOVA. The p-value would indicate the probability of observing the data if there was no effect, and the decision to reject or fail to reject the null hypothesis would depend on the predetermined significance level.

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Answer:

88$

Step-by-step explanation:

so, each of gourd is 2$ if she gives 2gourds each of them then 2*2 =4

then she has 22 students in her classroom so she will spend 22*4=88.

The Jacobian of the transformation is: ∂(x, y) / ∂(r, θ) = [ -18e^(-3r)sin(θ)  6e^(-3r)cos(θ) ]   [ 3e^(3r)cos(θ)    -e^(3r)sin(θ) ]

To find the Jacobian of the transformation given by x = 6e^(-3r)sin(θ) and y = e^(3r)cos(θ), we need to compute the partial derivatives of x with respect to r and θ, and the partial derivatives of y with respect to r and θ.

The Jacobian matrix is given by:

J = [ ∂x/∂r  ∂x/∂θ ]

       [ ∂y/∂r  ∂y/∂θ ]

Let's calculate the partial derivatives:

∂x/∂r = -18e^(-3r)sin(θ)

∂x/∂θ = 6e^(-3r)cos(θ)

∂y/∂r = 3e^(3r)cos(θ)

∂y/∂θ = -e^(3r)sin(θ)

Now we can assemble the Jacobian matrix:

J = [ -18e^(-3r)sin(θ)  6e^(-3r)cos(θ) ]

       [ 3e^(3r)cos(θ)    -e^(3r)sin(θ) ]

Therefore, the Jacobian of the transformation is:

∂(x, y) / ∂(r, θ) = [ -18e^(-3r)sin(θ)  6e^(-3r)cos(θ) ]

                                  [ 3e^(3r)cos(θ)    -e^(3r)sin(θ) ]

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Answer:

for the first picture: 2.16

Step-by-step explanation:

12% of 18 is 2.16:

-convert 12 % to a decimal so 0.12 times 18

also, 12 % percent is 0.12 as a decimal because you move the decimal 2 places to the left to get .12

- multiply 0.12 times 18 to get 2.16 as the answer

I hope this helped for the first pic!

Answer:

4) 8+2i

Step-by-step explanation:

When you expand you get 3+4i+5-2i

when you add the like terms you get 8+2i

Answer:

3

Step-by-step explanation:

The answer is 3 3+4 is 7 and 5-2 is 3

Answer:

35-10/3

Step-by-step explanation:

If a = 3 and b = 5, find a/(a+b).

\( \bf \frac{a}{a + b} = \\ \\ \bf = \frac{3}{3 + 5} = \\ \\ \bf = \red { \boxed{ \bf \frac{3}{8}} } \)

The account increases in value by 1% every quarter, which is equivalent to 1/4% every month.

Savings interest is calculated on a daily basis and deposited into the account on the first day of the next quarter. The interest rate will depend on the balance in the account. Now it's between 3% and 3.5%.

To find the increase in value for an account with an APR of 4% and quarterly compounding, we'll first need to convert the APR to a quarterly interest rate.
1. Divide the APR by the number of compounding periods in a year: 4% / 4 = 1%.
2. The account increases in value by 1% every quarter.

Your answer: a. 1%

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Answer: 34 minutes

Step-by-step explanation: 1126 + 34  is 1160, or 12:00

Answer:

It took 34 minutes.

Step-by-step explanation:

We know there are 60 minutes in an hour. It is 26 minutes into the hour, so we do 60-34(Minutes) and we get 34.

Answer: 34 minutes to clean the kitchen

The area of the region bounded by the given curves. y = 6x2 ln(x), y = 24 ln(x) is 2.85 sq.units.

In this question we need to find the area of the region bounded by the given curves. y = 6x^2 ln(x), y = 24 ln(x)

Equating both the equations of the curve,

6x^2 ln(x) = 24 ln(x)

24 ln(x) - 6x^2 ln(x) = 0

x = 1, 2

This means,  the curves intersect at x = 1 and x = 2.

So, the required area would be,

A = ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx

First we find the indefinite integral ∫[24 ln(x) - 6x^2 ln(x)] dx

= -6  ∫[-4 ln(x) + x^2 ln(x)] dx

= -6 ∫ln(x) (x^2 - 4) dx

= -6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x

So,  ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx

= [-6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x] _(x = 1 to x = 2)

= 32 ln(2) - 58/3

= 22.18 - 19.33

= 2.85 sq.units.

Therefore, the area of the region is 2.85 sq.units.

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The length of diagonal ac is approximately 15.58 cm, and the length of diagonal bd is approximately 12.22 cm

Rhombus is a special type of parallelogram in which all four sides are congruent. The opposite angles of a rhombus are also congruent, and the diagonals bisect each other at right angles.

Now, let's consider the given rhombus abcd, where ad = 8cm and m∠ade=20°. We need to determine the length of diagonals ac and bd.

First, let's use the law of cosines to find the length of side ae. We know that ad = 8cm, and m∠ade=20°, so we can use the formula:

ae² = ad² + de² - 2ad(de)cos(m∠ade)

Substituting the values, we get:

ae² = 8² + de² - 2(8)(de)cos(20°)

Next, we can use the fact that a rhombus has all sides congruent to find the length of side de. Since abcd is a rhombus, we know that ac and bd are also congruent diagonals that bisect each other at right angles. Therefore, we can draw diagonal ac and use the Pythagorean theorem to find the length of ac:

ac² = (ae/2)² + (de/2)²

Substituting ae² from the previous equation, we get:

ac² = ((8² + de² - 2(8)(de)cos(20°))/4) + (de/2)²

Simplifying the equation and using the fact that ac and bd are congruent, we get:

bd² = ac² = (8² + de² - 2(8)(de)cos(20°))/2

Finally, we can use the Pythagorean theorem to find the length of diagonal bd:

bd² = ab² + ad²

Substituting ab = ac/2 and ad = 8cm, we get:

bd² = (ac/2)² + 8²

Substituting ac² from the previous equation, we get:

bd² = ((8² + de² - 2(8)(de)cos(20°))/8)² + 8²

Simplifying the equation, we get:

bd ≈ 12.22 cm

Similarly, we can solve for ac using the equation we derived earlier:

ac² = ((8² + de² - 2(8)(de)cos(20°))/4) + (de/2)²

Substituting de ≈ 9.84cm (which we can solve for from the equation ae² = 8² + de² - 2ad(de)cos(m∠ade)), we get:

ac ≈ 15.58 cm

Therefore, the length of diagonal ac is approximately 15.58 cm, and the length of diagonal bd is approximately 12.22 cm

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Answer: 13

Step-by-step explanation:

Answer:

find the cordinates of each letter or number then find witch is greater or less than when your answering it

Step-by-step explanation:

Answer:

Answer is 1st. Because

When you flip something you cannot flip the midpoints.

Answer:

D

Step-by-step explanation:

D 4x2-8x+20

Answer:

\(a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\ \)

\(b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\ \)

Step-by-step explanation:

\( {( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\ \)

\( {( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\ \)

The surface area of the pyramid is 390.8 cm².

The surface area of the triangular pyramid is calculated as follows;

S.A = base area   +  ¹/₂ (perimeter + slant height)

The height of the pyramid is calculated by applying Pythagoras theorem;

h = √ (28²  -  14²)

h = 24.2 cm

Area of the base = ¹/₂ x 28 cm x 24.2 cm = 338.8 cm²

The surface area of the pyramid is calculated as follows;

S.A = 338.8 cm²  + ¹/₂ (76 cm + 28 cm)

S.A = 390.8 cm²

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Answer:

1,425

Step-by-step explanation:

I got this one correct

Storekeepers in electronics companies deal with various types of materials. Five classes of materials include electronic components, raw materials, finished products, packaging materials, and maintenance supplies.

Electronic Components: Storekeepers are responsible for managing a wide range of electronic components such as resistors, capacitors, integrated circuits, connectors, and other discrete components. These components are essential for assembling electronic devices and are typically stored in organized bins or cabinets for easy access.

Raw Materials: Electronics companies require various raw materials for manufacturing processes. Storekeepers handle materials like metals, plastics, circuit boards, cables, and other materials needed for production. These materials are usually stored in designated areas or warehouses and are monitored for inventory levels.

Finished Products: Storekeepers are also responsible for storing and managing finished products. This includes fully assembled electronic devices such as smartphones, computers, televisions, and other consumer electronics. They ensure proper storage, tracking, and distribution of these products to customers or other departments within the company.

Packaging Materials: Packaging plays a crucial role in protecting and shipping electronic products. Storekeepers handle packaging materials such as boxes, bubble wrap, foam inserts, tapes, and labels. They ensure an adequate supply of packaging materials and manage inventory to meet packaging requirements.

Maintenance Supplies: Electronics companies often require maintenance and repair supplies for their equipment and facilities. Storekeepers handle items like tools, lubricants, cleaning agents, safety equipment, and spare parts. These supplies are necessary to support ongoing maintenance activities and ensure the smooth operation of machinery and infrastructure.

Overall, storekeepers in electronics companies deal with a diverse range of materials, including electronic components, raw materials, finished products, packaging materials, and maintenance supplies. Effective management of these materials is crucial to ensure smooth operations, timely production, and customer satisfaction.

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In order to calculate the Mean Squared Error (MSE) for each region, you will need to have a dataset with values for each region.

Once you have this dataset, you can calculate the MSE using the following formula:

MSE = 1/n x ∑(yi - ŷi)²

where n is the number of data points in the region, yi is the actual value for the ith data point, and ŷi is the predicted value for the ith data point. Once you have calculated the MSE for each region, you can compare the values to determine if the variability around the fitted regression line is approximately the same for each region.

If the MSE values are similar for each region, then the variability around the fitted regression line is approximately the same. If the MSE values are different for each region, then the variability around the fitted regression line is not the same for each region.

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Using the given data on the number of live multiple-delivery births for women aged 15 to 54, we need to calculate probabilities related to the age groups of the mothers. The probability of a randomly selected multiple birth involving a mother aged 30 to 39 will be determined, as well as the probabilities of not being in the age range, being less than 45, and being at least 40. Finally, we need to interpret whether a multiple birth involving a mother aged at least 40 is unusual.

(a) To calculate the probability of a randomly selected multiple birth involving a mother aged 30 to 39, we sum the number of multiple births in that age group and divide it by the total number of multiple births for women aged 15 to 54.

P(30 to 39) = 2822 / (89 + 508 + 1631 + 2822 + 1855 + 374 + 119)

(b) To find the probability of a randomly selected multiple birth involving a mother who is not aged 30 to 39, we subtract the probability found in part (a) from 1.

P(not 30 to 39) = 1 - P(30 to 39)

(c) To determine the probability of a randomly selected multiple birth involving a mother aged less than 45, we sum the number of multiple births for age groups below 45 and divide it by the total number of multiple births for women aged 15 to 54.

P(less than 45) = (89 + 508 + 1631 + 2822 + 1855 + 374) / (89 + 508 + 1631 + 2822 + 1855 + 374 + 119)

(d) To find the probability of a randomly selected multiple birth involving a mother aged at least 40, we sum the number of multiple births for age groups 40-44 and 45-54, and divide it by the total number of multiple births for women aged 15 to 54.

P(at least 40) = (374 + 119) / (89 + 508 + 1631 + 2822 + 1855 + 374 + 119)

Interpretation: The answer to part (d) will determine whether a multiple birth involving a mother aged at least 40 is unusual. If the probability is less than 0.05, it can be considered unusual. Therefore, we need to compare the calculated probability to 0.05 and select the correct choice.

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The probability that a n = 6 fiber specimen random sample will have a sample tensile strength greater than 75.75 psi is 43.25%.

Given that,

The tensile strength of a synthetic fiber used to make carpet is regularly distributed, with a mean of 75.5 psi and a standard deviation of 3.5 psi. We have to determine probability that a n = 6 fiber specimen random sample will have a sample tensile strength greater than 75.75 psi.

We know that,

The Z score is used to determine how far the raw score deviates from the mean, either above or below.

z = (score - mean) / (standard deviation ÷ √sample)

Mean 75.5 psi and standard deviation 3.5 psi. n = 6.

For > 75.75:

z = (75.75 - 75.5) / (3.5 ÷√6) = 0.17

P(z>0.17) = 1-P(z<0.17)

= 1-0.5675

= 43.25%

Therefore, The probability that a n = 6 fiber specimen random sample will have a sample tensile strength greater than 75.75 psi is 43.25%.

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Answer:

Step-by-step explanation:2:5 would be basically 2/5 and you could say that the ratio of

Girls to boys is 2:5

Answer:

28%

Step-by-step explanation:

We know that 100 percent is total. Mateo first scored 68/100, then a retake got his score up to 94/100.

First, subtract the two numbers

94 - 68 = 26

Put 26 over 94 to make this 26/94

Divide to get 0.28 (simplified and rounded)

So the increase was 28%

Answer:

increase of 28?

Step-by-step explanation:

Okay so, I believe it is 28, let me explain. First, work out the difference (decrease) between the two numbers you are comparing. Next, divide the decrease by the original number and multiply the answer by 100. If the answer is a negative number, this is a percentage increase.

=13.62

- We are given the interarrival time (a = 15 min), service time (p = 20 min), number of servers (m = 3 people), standard deviation of interarrival time (15 min) and standard deviation of service time (60 min). - Therefore, the coefficient of variation of arrival times is 15 / 15 = 1 and the coefficient of variation of service times is 60 / 20 = 3. Moreover, the utilization is 20 / (15 x 3) = 0.4444. Therefore, the average time in the queue is 6.6667 x 0.4086 x 5.0 = 13.6211 minutes, or 13.62 minutes rounded to two decimals

- We are given the interarrival time (a = 15 min), service time (p = 20 min), number of servers (m = 3 people), standard deviation of interarrival time (15 min) and standard deviation of service time (60 min). - Therefore, the coefficient of variation of arrival times is 15 / 15 = 1 and the coefficient of variation of service times is 60 / 20 = 3. Moreover, the utilization is 20 / (15 x 3) = 0.4444. Therefore, the average time in the queue is 6.6667 x 0.4086 x 5.0 = 13.6211 minutes, or 13.62 minutes rounded to two decim