Yes, the sum of magnitude of two vectors can be equal to the magnitude of sum of these two vectors.
What is the sum of two vectors?The sum of two vectors is determined by applying triangle law of vector addition or parallelogram law of vector addition.
The sum of magnitude of two vectors can be equal to the magnitude of sum of these two vectors when two vectors are colinear.
For example, let vector A = ax and vector B = dy
The sum of the two vectors is given as;
v = √ (a² + d²)
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Mark weighs 375 N and is carrying a full-sized cello as he climbs the stairs to a height of 4 m. It takes him 3 seconds to do this.
How does the amount of work he does change if he were to climb the same flight of stairs again in the same amount of time, but this time without the cello?
A) It depends on the weight of the cello.
B) It remains the same.
C) It increases
D) It decreases.
Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.
The correct answer is option D.
The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :
Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).
When Mark climbs the stairs with the cello, he is doing work against the force of gravity.
The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.
Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.
Therefore, mark's work decreases.
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A block has two strings attached to it on opposite ends. One string has a force of 5 N,
the other string a force of 15 N. The block is accelerating at 1 m/s2 on a horizontal surface.
A) What is the mass of the block if the friction force is 3 N?
B) What is the coefficient of friction?
Unless you have a diagram to include or any other additional info, I'll assume the block is being pulled by two opposing forces along the horizontal surface.
Horizontally, the block is under the influence of
• one rope pulling in one direction with magnitude 15 N,
• the other rope pulling in the opposite direction with mag. 5 N, and
• friction, opposing the direction of the block's motion, with mag. 3 N.
It stands to reason that the block is accelerating in the direction of the larger pulling force.
(A) By Newton's second law, we have
15 N + (-5 N) + (-3 N) = m (1 m/s²)
where m is the mass of the block. Solve for m :
7 N = m (1 m/s²)
m = (7 N) / (1 m/s²)
m = 7 kg
(B) The friction force is proportional to the normal force, so that if f is the mag. of friction and n is the mag. of the normal force, then f = µ n where µ is the coefficient of friction.
The block does not bounce up and down, so its vertical forces are balanced, which means the normal force and the block's weight (mag. w) cancel out:
n + (-w) = 0
n = w
n = m g
where g = 9.8 m/s² is the mag. of the acceleration due to gravity.
n = (7 kg) (9.8 m/s²)
n = 68.6 N
Then
3 N = µ (68.6 N)
µ = (3 N) / (68.6 N)
µ ≈ 0.044
a 25 kg object falls off a cliff and hits the ground 10 seconds later. How much force does the object apply to the ground on impact?
Answer:
Yes
Explanation:
Beacause u have 25 kg,and falls off from a cliff hanger cause its too bit heavy
what is mass over density ?
Mass over density is a mathematical expression that represents the ratio of mass to density. It is calculated by dividing the mass of an object or substance by its density. Mathematically, it can be represented as:
The equation relating mass (m) and density (ρ) is given by:
m = ρ * V
where:
m is the mass of the object or substance,
ρ is the density of the object or substance, and
V is the volume of the object or substance.
This equation states that the mass of an object is equal to the product of its density and volume. It shows that mass is directly proportional to density and volume.
Electrical energy is transformed into mechanical energy in a motor when the
electromagnet consistently turns in the same direction. What part of the
motor causes this motion?
A. The loop of wire
B. The permanent magnets
C. The commutator
D. The battery
Answer:
the commutator
Explanation:
took the quiz!
The part of the motor that causes the consistent motion of the electromagnet in the same direction is the commutator. The correct answer is C. The commutator.
The commutator is a critical component in a motor that enables the conversion of electrical energy into mechanical energy. It consists of a set of copper segments connected to the rotating coil or armature of the motor. As the armature spins, the commutator ensures that the electrical current flowing through the coil changes direction at the right time.
This change in current direction creates a rotating magnetic field that interacts with the permanent magnets, resulting in a continuous rotational motion of the motor. In essence, the commutator acts as a switch, controlling the flow of current and ensuring the electromagnet rotates in a consistent direction.
Therefore, the part of the motor that causes this motion is C. The commutator.
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The distance between the fixed points of centigrade thermometer is 25cm. What is the temperature when the mercury level is 6.5 cm above the lower mark?
The temperature when the mercury level is 6.5 cm above the lower mark is 26 °C.
To determine the temperature from the mercury level on a centigrade thermometer, you need to use the formula:
Temperature = (Mercury level / Distance between fixed points) * 100
In this case, the distance between the fixed points is 25cm, and the mercury level is 6.5 cm above the lower mark. Plugging these values into the formula gives:
Temperature = (6.5 cm / 25 cm) * 100 = 26 °C
So the temperature is 26 °C when the mercury level is 6.5 cm above the lower mark on a centigrade thermometer with fixed points 25 cm apart.
A child is sending pulses down a stretched rope at a rate of 2 pulses per second. The distance between the pulses is 5 meters. What is the speed of the wave?.
The speed of the wave that is propagated is 10 meters per second.
A wave is a disturbance or variation that gradually conducts electricity from point to point in a medium and can take the form of elastic deformation or a change in pressure, electric or magnetic intensity, electric potential, or temperature
The speed of a wave is determined by the frequency of the wave and its wavelength. In this case, the child is sending pulses down the rope at a rate of 2 pulses per second, so the frequency is f = 2 Hz.
The distance between the pulses is 5 meters, which is the wavelength of the wave, represented by lambda (λ).
The speed of the wave (v) is given by the formula:
v = f * λ
Substituting the values we have, we get:
v = 2 Hz * 5 m = 10 m/s
Therefore, the speed of the wave is 10 meters per second.
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Write the properties of Non Metals and the families containig non Metals.
Non-Malleable and Ductile: Non-metals are very brittle, and cannot be rolled into wires or pounded into sheets. Conduction: They are poor conductors of heat and electricity. Luster: These have no metallic luster and do not reflect light.
Group 15, the nitrogen family, contains two nonmetals: nitrogen and phosphorus. These non-metals usually gain or share three electrons when reacting with atoms of other elements. Group 16, the oxygen family, contains three nonmetals: oxygen, sulfur, and selenium.
Elements: Nitrogen; Oxygen; Phosphorus; Selenium...
1. a. Find the angle between a diagonal of a cube and one of its edges. Show all working. b. Is the line through (4,6,3) and (2,0, -1) parallel to the line through (6,22,12) and (1,7,2)? Your explanation must include full details. c. Two forces F1 and F2 with magnitudes 100 Newtons and 120 Newtons, respectively, act on an object at point P as shown in the figure (not to scale).
a. The angle between a diagonal of a cube and one of its edges is approximately 54.7356°.
b. No, the line through (4,6,3) and (2,0, -1) is not parallel to the line through (6,22,12) and (1,7,2).
C. question is incomplete.
a. To show the working, consider the diagonal of a cube with edge length "a":
Diagonal = √(a^2 + a^2 + a^2) = √(3a^2) = a√3
The length of the edge is "a".
To find the angle between the two, use the dot product formula:
cos(θ) = (a * a) / (a * √(3a^2)) = a / √(3a^2) = a / (a√3) = 1 / √3
Therefore, θ = cos^-1 (1 / √3) = 54.7356°
b. The line through (4,6,3) and (2,0, -1) is not parallel to the line through (6,22,12) and (1,7,2).
Parallel lines have the same direction and therefore the same slope. To check for parallelism, we can find the direction ratios of the lines.
The direction ratio of the line through (4,6,3) and (2,0, -1) is: (2-4,0-6,-1-3) = (-2,-6,-4)
The direction ratio of the line through (6,22,12) and (1,7,2) is: (1-6,7-22,2-12) = (-5,-15,-10)
Since the direction ratios are different, the two lines are not parallel.
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An Olympian lifts a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
The force of gravity equals 9.8 m/s. What is the potential energy of the weights?
Answer:
PE = MGH. 1375 x 9.8 x 2. = 26950 joules
Explanation:
First do 1375 x 9.8 which is MG then times it by 2 which is H
Mass x Gravity x Height
the gravity will always be 9.8
I would love a brainliest
The the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.
What is Potential energy?The energy of a body by virtue of its position is called potential energy. Mathematically -
E[P] = mgh
Given is an Olympian who lifted a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
We can write the given data as follows -
Mass of weights = [M] = 1375 Kg
Displacement = [h] = 2 meters
Therefore, using the formula for potential energy, we can write -
E[P] = mgh
E[P] = 1375 x 9.8 x 2
E[P] = 26950 joules
Therefore, the the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.
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What is the basic form of matter which cannot be broken down any further?
a compound
an element
a chemical reaction
an organism
Answer:
An element
Explanation:
An element is a pure substance that cannot be broken down any smaller.
Answer:
Element
Explanation:
Due to the fact that elements make up a compound and the compound and other elements allow is to be able to make a chemical reaction and organisms are made from elements
PLEASE PROVIDE EXPLANATION.
THANK YOU!!
Answer:
11,000 kg
(a) 11.2 m/s
(b) 1.6 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)
132,000 kg km/h = 22,000 kg km/h + m (10 km/h)
110,000 kg km/h = m (10 km/h)
m = 11,000 kg
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)
-mv + 10mv = m v₁ + 2m v₂
9mv = m (v₁ + 2 v₂)
9v = v₁ + 2 v₂
Since the collision is elastic, kinetic energy is also conserved.
½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²
mv² + 50mv² = m v₁² + 2m v₂²
51mv² = m (v₁² + 2 v₂²)
51v² = v₁² + 2 v₂²
We know v = 1.60 m/s. So the two equations are:
14.4 = v₁ + 2 v₂
130.56 = v₁² + 2 v₂²
Solve the system of equations using substitution.
130.56 = (14.4 − 2 v₂)² + 2 v₂²
130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²
0 = 6 v₂² − 57.6 v₂ + 76.8
0 = v₂² − 9.6 v₂ + 12.8
v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)
v₂ = 1.6 or 8
If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.
If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.
We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision. Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.
n unit-vector notation, what is the torque about the origin on a particle located at coordinates (0, −4.0 m, 3.0 m) if that torque is due to (a) force F1 with components F1x = 2.0 N, F1y = F1z = 0, and (b) force F2 with components F2x = 0, F2y = 2.0 N, F2z = 4.0 N?
n unit vector notation, -22j is the torque about the origin on a particle located at coordinate (o, -4.0m, 3.0m)
Torque is defined as the force that can cause an object to rotate along an axis is measured as torque. Estimate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.
T=R (distance) x F (Force)
R=-4j+3k
F=2J
Hence, t= R x F vector product
=(-4j+3k)x2j
=-4x2x(y x J)
=+3x2y(k x r)
=-8x(-k)+6j
=(6j+8k) nm
b) F^2=2J+4K
Hence, t=r x f^2
=(-4j+3k)x(2j+4k)
=0-16( J x k)+6(K x J)+0
=-16j-6j
=-22j
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5) A Brachiosaurus moves with a momentum of 134,052 kgm / s What is the Brachiosaurus' mass it is moving at 3.9m / s ?
The mass of Brachiosaurus moves with a momentum of 134,054 kgm/s and the velocity is 3.9 m/s, which is 34.37 kg.
The momentum is the product of mass and velocity. The momentum is the vector quantity and the unit of momentum is Kgm/s.
Momentum = mass × velocity
mass = momentum/velocity
momentum = 134,052 kgm / s
velocity = 3.9 m/s
mass = 134052 / 3.9
= 34.37 kg
Thus, the mass of Brachiosaurus is 34.37 kg.
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A 4.80 g bullet moves with a speed of 170 m/s perpendicular to the Earth's magnetic field of 5.00×10−5T.
Part A
If the bullet possesses a net charge of 1.06×10−8 C , by what distance will it be deflected from its path due to the Earth's magnetic field after it has traveled 1.00 km ?
Answer:
\(3.24\times 10^{-7}\ \text{m}\)
Explanation:
m = Mass of bullet = 4.8 g
v = Velocity of bullet = 170 m/s
B = Magnetic field of Earth = \(5\times 10^{-5}\ \text{T}\)
q = Charge of bullet = \(1.06\times 10^{-8}\ \text{C}\)
a = Acceleration
Time the bullet will be in the air for is \(t=\dfrac{1000}{170}=5.88\ \text{s}\)
Force is given by
\(F=ma\)
Magnetic force is given by
\(F=qvB\)
So
\(ma=qvB\\\Rightarrow a=\dfrac{qvB}{m}\\\Rightarrow a=\dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\ \text{m/s}^2\)
From the linear equations of motion we have
\(s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0+\dfrac{1}{2}\times \dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\times 5.88^2\\\Rightarrow s=3.24\times 10^{-7}\ \text{m}\)
The defelection of the bullet is \(3.24\times 10^{-7}\ \text{m}\)
1. Which object would have more inertia — a 1,000 kg car or a 150 kg golf cart?
Answer:a car with 1,000kg
Explanation: A car with a mass of 1,000kg has more inertia than 150 kg
Out of the two objects a 1000-kilogram car and a 150-kilogram golf cart, the 1000-kilogram cart will have more inertia as the inertia of any object is directly proportional to its mass.
What is Newton's first law?According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.
The larger the mass of the object, the greater would be the inertia of the object.
Thus, a 1000-kilogram automobile will have higher inertia than a 150-kilogram golf cart since any object's inertia is directly proportionate to its mass.
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A mass of 0.25 kg is attached to a spring and is set into vibration with a period of 0.22 s. What is the spring constant of the spring?
The spring constant of the spring is 178.4 N/m.
In this problem, we are given a mass of 0.25 kg that is attached to a spring and set into vibration with a period of 0.22 s.
We can use the equation for the period of a mass-spring system, which relates the period of oscillation to the mass and spring constant, to calculate the spring constant.
We can use the equation for the period of a mass-spring system:
T = 2π√(m/k)
where T is the period, m is the mass, and k is the spring constant.
Rearranging this equation to solve for k, we get:
k = \((4\pi^2m) / T^2\)
Substituting the given values, we get:
k = \((4\pi^2 \times 0.25 \:kg) / (0.22 s)^2\)
k = 178.4 N/m
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what does the area between the line and the x axis represent on a velocity vs time graph
the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period
Thank you
The area between the line and the x axis represent on a velocity vs time graph is the displacement.
The area under velocity-time graph is known as displacement.
In velocity-time graph, the y-axis represents the velocity axis while the x-axis represents the time axis.
Velocity is defined as the change in displacement per change in time.
\(v = \frac{dx}{dt}\)
where;
\(dx\) is the change in displacement\(dt\) is the change in timeThe integration of the velocity gives the area under the curve and that will be equal to the displacement.
\(\int\limits^a_b {v} \, dt = x\)
Thus, the area between the line and the x axis represent on a velocity vs time graph is the displacement.
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There is a bottleneck in producing masses higher than4He, because there are no mass-5or mass-8 stable nuclides. For older stars with high densities and high temperatures (T>100 million K), three alpha particles can form12C. This occurs by two alpha particles firstforming8Be, and then8Be reacting with another alpha particle to form12C before8Be candecay back to two alpha particles.a) Explain why this can only happen in very hot stars and high density.b) Calculate how much energy is given up when three alpha particles form12C.
Answer:
Explanation:
a)
To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.
b)
The amount of energy given up can be calculated as follows:
\(_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)\)
where;
\(M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u\)
Therefore, from the reaction (1);
\(Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}\)
From the second reaction:
\(Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}\)
Jenny experiences an average downward force of 441 N anywhere she goes on Earth. Calculate her mass
Answer:
Given,
Force = 441 N
mass = ?
Keep in mind that acceleration due to gravity is constant 10m/s.
Force = mass × acceleration due to gravity
mass = Force / acceleration due to gravity
m = 411 N /10m/s
m = 41.1 kg
Therefore her Jenny mass is 41.1 kg.
if an 80kg object has 632 J of PE, how high is it
The object is on 81 cm high.
What is potential energy?The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
Given that: an 80kg object has 632 J of Potential energy.
Let the height is h: then,
mgh = PE
80 kg × 9.8× m/s^2 × h = 632 Joule
h = 0.81 m = 81 cm.
The object is on 81 cm high.
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11. A seesaw sits in static equilibrium. A child with a mass of 30 kg sits 1 m away from a pivot point. Another child sits 0.75 m away from the pivot point on the opposite side. The second child's mass is _____ kg.
Answer:
40 kgExplanation:
Find the diagram relating to the question for proper explanation of the question below.
Using the principle of moment
Sum of clockwise moments = Sum of anticlockwise moments
Moment = Force * perpendicular distance
For anti-clockwise moment:
Since the 30 kg moves in the anticlockwise direction according to the diagram
ACW moment = 30 * 1 = 30 kgm
For clockwise moment
If another child sits 0.75 m away from the pivot point on the opposite side, moment of the child in clockwise direction = M * 0.75 = 0.75M (M is the mass of the unknown child).
Equating both moments we have;
0.75M = 30
M = 30/0.75
M = 40 kg
The second child's mass is 40 kg
How does opening a parachute slow the fall rate of a skydiver?
Answer:
the air is being stopped in the pocket of the parachutes theys why the parachute has a certain shape so that the air that gets caught inside of it as the skydiver goes down slows down the landing
Three differences between traditional method of learning science and project method of learning science.
Correct answer will be given a 20 points, thanks, 5 star rating and the most important : BRAINLIEST
In PBL teaching, an individual student will teach a particular topic to the group meaning the content of information taught will be dependent on the motivation of the individual students. Traditional courses tend to emphasise the foundations in biomedical knowledge required in medicine earlier on.
Gun was fired with a muzzle velocity of 350m/s, mounted at an angle of 45’ above the ground. Neglecting air resistance, compute for the following;
*Maximum height reached
*Range of the projectile
*Total time of flight
Answer:
Maximum height, h = 3062.5m
Total time of flight, T = 49.49secs or 50secs approx.
Range, R = 12250m
Explanation:
Given data:
U = 350m/s
Angle = 45°
Assume g = 10m/s
At the greatest height, v = 0
Therefore,
V^2 = U^2 sin^2 × angle - 2×g×h
Substituting values:
0^2 = 350^2 sin^2 (45) - 2 × 10 × h
Let h = maximum height reached
Rearranging gives:
350^2 sin^2(45) = 2 x 10 x h
h = 350^2 sin^2(45)/2×10
h = 122500 x 0.5/20
h = 61250/20
h = 3062.5m
2)Total time of flight, T
T = 2U sin(angle)/g
= 2x350 sin(45)/10
= 494.9747/10
= 49.49secs or 50sec approx.
3) Range of projectile, R
R = U^2 sin2(angle)
= 350^2 sin2 (45)
= 122500 x 1/10
= 12250m
how long will it take to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle taking 6 amperes from a 220 volt supply . Specific Heat capacity of water is 400 joules per kilogram kelvin. I need this ASAP! .I'll mark brainliest
Answer:
1.5 minutes
Explanation:
To find out how long it will take to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle, we can use the equation:
Q = mcΔT
Where Q is the heat energy added, m is the mass of the water, c is the specific heat capacity of water and ΔT is the change in temperature.
The heat energy added to the water can be calculated as:
Q = (5 kg) x (400 J/kg·K) x (88°C - 28°C) = (5 kg) x (400 J/kg·K) x (60°C) = 120000 J
The power of the electric kettle can be calculated using the formula:
P=VI
where P is the power, V is the voltage and I is the current,
P = (220 V) x (6 A)
= 1320 W
Now we can calculate the time it takes to heat the water by dividing the heat energy added by the power:
time = Q/P = 120000 J / 1320 W
= 90.909 seconds or 1.5 minutes
It will take 1.5 minutes to heat 5 kg of water from 28 degrees Celsius to 88 degrees Celsius in an electric kettle taking 6 amperes from a 220 volt supply.
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A party shop delivers helium-filled balloons to homes and businesses. The owners realize from experience that on hot summer days they should inflate the balloons only three-quarters full. On cold winter days they can fully inflate the balloons. Which of the following is the BEST hypothesis to explain this observation? Air outside the balloons leaks into the balloons. The helium gas is more active in the winter season. As the temperature increases, the helium in the balloons expands. Outdoor air pressure in the summer is less than indoor air pressure.
Answer:As the temperature increases, the helium in the ballon expands.
Explanation:
I took the quiz already
The answer is C) As the temperature increases, the helium in the balloons expands.
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What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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A heavy bank-vault door is opened by the application of a force of 300 N directed perpendicular to the plane of the door at a distance of 0.80 m from the hinges. What is the torque?
300 Nm
240 Nm
375 Nm
120 Nm
The torque would be 240 Nm
The ratio of the rise/run has to be the ___ in order to have a ____ slope.
A. Different, Constant
B. Same, increasing
C. Same, constant
D. Different, increasing
The ratio of the rise/run has to be the same in order to have a constant slope (option C).
What is slope?Slope, in mathematics, is the ratio of the vertical and horizontal changes between two points on a surface or a line.
The slope is zero if the line is horizontal and undefined if it is vertical.
The vertical change between two points is called the rise while the horizontal change is called the run. This means that the slope equals the rise divided by the run.
Therefore, this suggests that the ratio of the rise/run has to be the same in order to have a constant slope.
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