Can you help me determine the mass of the mystery object it’s #15The maximum speed is 40 m/s.

Answer:

Let F1x = force of wall on ladder

F1x = F2x    the force of friction  (balances horizontal forces)

F2y = W      balance weight of ladder

F2x = μ F2y       force of friction on ladder

F1x L sin θ = W L / 2 cos θ     balance torque about point F2

tan θ  = W / (2 F1x)     previous equation

Now     μ W = μ F2y = F2x = F1x   from above

So tan θ  = W / (2 μ W) = 1 / (2 μ ) = 1 / .64

tan θ = 1.56

θ = 57.4 deg

When blocks are connected by a thin thread across a frictionless pulley, the tension in the string is 68.0 N.

A gravitational force still exists in the tension force. The tension will be referred to as the T = W + ma if the body is travelling upward. T = W - ma, where the thickness is constant as the body lowers. If the discomfort is equivalent to the body weight, T = W.

The aluminum block's equation of motion in a plane-parallel direction is as follows:

ma1 = T - mg sin(theta) - s mg cos(theta)

The copper block's vertical equation of motion is as follows:

ma2 = m2g - T

Determine the acceleration a from the two equations above:

a = (m2g - m1g sin(theta) - m1s g cos(theta)) / (m1 + m2)

By entering the specified values, we obtain:

a = (7.45 kg)(9.81 m/s^2) - (1.15 kg)(9.81 m/s^2) sin(31.5°) - (1.15 kg)(0.61)(9.81 m/s^2) cos(31.5°) / (1.15 kg + 7.45 kg) = 1.70 m/s^2

As a result, the system accelerates at a 1.70 m/s2 pace.

T = m2g - ma2 = (7.45 kg)(9.81 m/s^2) - (1.15 kg)(1.70 m/s^2) = 68.0 N

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Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

The speed of the wave created by Linh in the spring by moving the other end right and left with a frequency of 2 Hz is 1m/s.

The speed of a wave can be calculated by using the following formula:

Speed = Wavelength x Frequency

According to this question, Linh creates waves in the spring by moving the other end right and left with a frequency of 2 Hz. If wave crests are 0.5 m apart, the speed can be calculated as follows:

speed = 2Hz × 0.5m

speed = 1m/s

Therefore, the speed of the wave created by Linh in the spring by moving the other end right and left with a frequency of 2 Hz is 1m/s.

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Record the point at which you caught the ruler, to the nearest cm. Measure from the bottom of your thumb. You can use this table to convert the measurement on the ruler into your reaction time in seconds. The less time it takes you to catch the ruler, the faster your reaction.

The magnitude of the object’s final velocity, the direction of the final velocity and the change in momentum during the 2.70 s

This is further explained below.

F_x=m a_x=15N

f is force

m is mass

a is acceleration

\(&a_x=\frac{15}{3} \\\\ m s^2=5 m_{s^{-2}} \\\)

v_x=0+5 * 2.7

v_x=13.5

v_y=15

\(V=\sqrt{v_x^2+v_{y^2}}\\\)

V=0.1 m/s

b)

\(\tan \theta=\frac{V_y}{V_x} \\\\ =\frac{18}{13.5} \\\\\)

=1.11

\(\theta\)=48.0^0 + from east

c)

Initial momentum,

p_{i x}=0, p_{i y}=m v_y=45 kgmg

final momentum,

P_{f x}=13.5 *3

=40.5kgm

P_{f y}=45Kgm/s

In conclusion, D P_x=P_{1 \text { In }}-P_{i x}=-4.5kgm/s toward west

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If we start an experiment with 191.3 g of a substance, we should be ending with 191.3 g

We know that matter cannot be created out of nothing. So that is why the number of atoms of products must be equal to the number of atoms of reactants. That is why a chemical reaction is written as a balanced reaction equation. This is the law of conservation of mass.

During a combustion reaction or during decomposition reaction, the products mass might seem to be different than that of reactants either higher or lower. This is due to the involvement of environment. So while considering mass environment should also be included.

Therefore, if we start an experiment with 191.3 g of a substance, we should be ending with 191.3 g

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A. Circles

An equipotential surface is a surface in which every point on it has the same electrical potential

That is the potential energy of every charge at every point on the surface is equal

For a pair of parallel plates, the equipotential surface are either concentric circles or spherical in shape

The displacement vectors in component form are A = 1.732 km i + 1 km j and B =  -2.955 km i - 0.522 km j.

The distance from home when cell phone rings is 1.309 km.

The direction from home when phone rings is 21.48° West of South.

(a) The displacement vector A can be expressed in component form as:

A = 2 km [cos(30°) i + sin(30°) j] = 2 km [√3/2 i + 1/2 j] ≈ 1.732 km i + 1 km j

The displacement vector B can be expressed in component form as:

B = 3 km [cos(280°) i + sin(280°) j] = 3 km [-0.985 i - 0.174 j] ≈ -2.955 km i - 0.522 km j

(b) The total displacement vector (C) is the sum of vectors A and B, which can be found by adding the corresponding components:

C = A + B = (1.732 - 2.955) km i + (1 - 0.522) km j = -1.223 km i + 0.478 km j

The magnitude of the resulting vector C can be found using the Pythagorean theorem:

|C| = √((-1.223)² + (0.478)²) ≈ 1.309 km

Therefore, you are about 1.309 km away from home when your cell phone rings.

(c) The direction of the resulting vector C can be found using the inverse tangent function:

θ = tan^-1(0.478/-1.223) ≈ -21.48°

Since the direction is measured with respect to the positive x axis, the direction from "home" to "you" when the phone rings is about 21.48° West of South.

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When positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of charge movement.

In the given scenario, if positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds (10 μs), we can infer the following about the magnitude and direction of the current:

1. Magnitude of the Current: The magnitude of the current is determined by the total charge passing through a given point in the wire per unit time. Since both positive and negative charges are moving, the total charge passing through a point will be the sum of the magnitudes of the charges. If the number of positive and negative charges is equal, the magnitudes of their charges will also be equal. Therefore, the total charge passing through the point will be the sum of equal positive and negative charges, resulting in a net charge of zero. In this case, the magnitude of the current will be zero.

2. Direction of the Current: The direction of the current is determined by the flow of positive charges. In a copper wire, the positive charges are not free to move. Instead, it is the negatively charged electrons that are free to move. Due to conventional current flow convention, the direction of the current is considered opposite to the direction of the electron flow. Therefore, even though both positive and negative charges are moving horizontally, the direction of the current will be in the opposite direction to the movement of the charges.

In summary, in the given scenario, where positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of the charge movement.

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The potential difference (voltage) between the plates is approximately 1.45 kV.

The kinetic energy of an electron can be related to the potential difference between the plates of an electric field using the equation:

KE = qV,

where KE is the kinetic energy of the electron, q is its charge, and V is the potential difference between the plates.

We know that the electron is accelerated from rest to a final velocity of 8 x 10^7 m/s, so its change in kinetic energy is given by:

ΔKE = 1/2 mv^2 - 1/2 m(0)^2 = 1/2 mv^2

where m is the mass of the electron.

The potential difference between the plates can be found by rearranging the equation to solve for V:

V = ΔKE / q

Substituting the values we have:

V = (1/2) mv^2 / q

The mass of an electron is approximately 9.11 x 10^-31 kg, and its charge is -1.6 x 10^-19 C. Substituting these values and the final velocity of 8 x 10^7 m/s, we get:

V = (1/2) (9.11 x 10^-31 kg) (8 x 10^7 m/s)^2 / (-1.6 x 10^-19 C)

V = -1.45 kV

Therefore, the potential difference (voltage) between the plates is approximately 1.45 kV.

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Answer:

The common speed is 1.95 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states that the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of all of them:

\(P=m_1v_1+m_2v_2+...+m_nv_n\)

If a collision occurs, the velocities change to v' and the final momentum is:

\(P'=m_1v'_1+m_2v'_2+...+m_nv'_n\)

In a system of two masses, the law of conservation of linear momentum

is written as:

\(m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\)

If both masses stick together after the collision at a common speed v', then:

\(m_1v_1+m_2v_2=(m_1+m_2)v'\)

The common velocity after this situation is:

\(\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)

The truck of m1=1200 N (weight) travels at v1=2 m/s and hits a stationary mass (v2=0) of m2=30 N (weight). After the bodies collide, they keep moving together. Before we can calculate the common speed, we need to calculate the masses of the bodies, since they are given as weights.

\(m_1=\frac{P_1}{g}=\frac{1200}{9.8}=122.45 Kg\)

\(m_2=\frac{P_2}{g}=\frac{30}{9.8}=3.06 Kg\)

Now calculate the common speed:

\(\displaystyle v'=\frac{122.45 * 2+3.06 * 0}{122.45+3.06}\)

\(\displaystyle v'=\frac{244.9}{125.51}=1.95\ m/s\)

The common speed is 1.95 m/s

The Title of the interviews Questionnaire is : Community Members' Right to Safe and Healthy Living Questionnaire. The Questionnaire is attached.

A tool for research known as a questionnaire comprises a series of questions formulated to extract data from individuals or a collective of individuals. A systematic approach in acquiring data, which permits researchers to obtain uniform feedback and perspectives from respondents, is termed as structured data collection.

Questionnaires have multiple applications such as conducting surveys, holding interviews, performing assessments, and carrying out evaluations.

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The bowling ball has a rotating kinetic energy of 8.573 J and a total velocity of 134.573 J.

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the energy transfer, is done on it by exerting a net force. The word "kinetic" derives from the Greek "kinesis," which means motion. Any direction can be used to move it. As can be seen, kinetic energy rises with increasing mass and/or speed, and it stays unchanged if an object slows down or accelerates up.

To calculate rotational kinetic energy:

Rotational kinetic energy = (1/2) * I * ω^2

where I is the intertia of solid

I = (2/5) * m * r^2, m is the mass and r is radius

Substituting the given values, we get:

I = (2/5) * 7 kg * (0.109 m)^2

I = 0.00265 kg * m^2

The angular velocity of the ball ω = v / r

let v is the linear velocity of the ball.

Substituting the given values, we get:

ω = 6 m/s / 0.109 m

ω = 55.046 rad/s

by substituting this values into formulae we get

Rotational KE= (1/2) * 0.00265 kg * m^2 * (55.046 rad/s)^2

Rotational KE = 8.573 J

Therefore, the rotational kinetic energy of the bowling ball is 8.573 J.

The translational kinetic energy can be calculated as:

Translational kinetic energy = (1/2) * m * v^2

Substituting the given values, we get:

Translational KE= (1/2) * 7 kg * (6 m/s)^2

Translational KE = 126 J

Therefore, the total KE of the ball is:

Total kinetic energy = Rotational kinetic energy + Translational kinetic energy

Total KE = 8.573 J + 126 J

Total kinetic energy = 134.573 J

Therefore, the total kinetic energy of the ball is 134.57

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You know now that 1200 km is 11° of latitude on the planet. So its circumference is roughly approximately around something like about

(360/11) • (1200 km) = 39,273 km

If it was good enough for Eratosthenes, then we can't complain.

Answer:

1. Information Gathering

2. Analysis and Planning.

3. Implementation of a solution.

4. Assessment of the effectiveness of the solution.

5. Documentation of the incident.

The correct answer is Launch angle

Explanation:

The Independent Variable can be easily identified because this is the factor or variable the researcher modifies. In this case, this term applies to the angle because as part of the experiment the student changes the angle multiple times to test how the maximum height changes. Moreover, the maximum height would be the dependent variable as it is the main factor and it changes or depends on other variables including the angle. Thus, it can be concluded the independent variable is the launch angle or the angle from which the ball is launched.

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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The acceleration of skateboard on road A will be 7.74 \(m/s^{2}\)

The acceleration of skateboard on road B will be 3.87 \(m/s^{2}\)

The acceleration of skateboard on road C will be 9.68 \(m/s^{2}\)

force = mass * acceleration

mass1 = 62 kg

force1 = 480 N

acceleration1 = force / mass

                     = 480 / 62 = 7.74 \(m/s^{2}\)

mass2 = 62 kg

force2  = 240 N

acceleration 2  = 240 / 62 = 3.87  \(m/s^{2}\)

mass 3 = 62 kg

force 3  = 600 N

acceleration 3  = 600 / 62  = 9.68  \(m/s^{2}\)

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The force with which the moon pulls the earth is same as the force with which the earth pulls the moon.

The gravitational attraction of the Moon to the Earth is equivalent to that of the Moon to the Earth. It is also possible to directly compute this using Newton's Law of Gravitation, which is:

F = G m₁ m₂/r²

From this, we can see that regardless of the pull we want to compute, the outcome will always be the same because both masses will eventually multiply among themselves. Or, to put it another way, using a different (yet even more basic) law, an action must be opposed by an equal or opposite reaction.

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(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.

Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.

Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.

This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.

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As per the collision theory the the increase in the temperature of the reaction increases the reaction rate.

According to the collision theory in order to form the product the reactant molecules collide with each other in order to break the bonds and form new bonds. When the temperature of the system is increased the activation energy is reduced by a certain amount so the rate of the reaction increases.

Generally it is believe that for every 10 degree increment in the temperature of the system the rate of the reaction almost gets doubled.

One another reason that the temperature affects the reaction rate is because by the increase and temperature the collision time between the two molecules decreases which allows the breaking of the bonds more easy.

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Given:

h = height = 20 ft = 6.096 m

m = 150 pound = 68.0389 kg

time = 15 s

g= 9.8 m/s^2

Potential energy = mgh = (68.0389 ) (9.8 ) (6.096 ) = 4,064.7 J

Work done = 4,064.7 J

The ecological methods allows to find the correct answer to the question of how to prevent river pollution is:

   b)  Maintain zones of grass at least wide on the sides of streams in the area.

Stream pollution from human activities can occur in a number of ways:

Let's analyze the different claims.

a) False. It is too expensive and the slopes cannot be changed due to possible flooding problems.

b) True. Maintaining a protective zone with grass on the sides of the rivers, prevents the waste of the frarmer from reaching the river, and the problems of the debris reaching the river bank. This un  ecological methods.

c) False. The dam controls flooding but does not eliminate the problems of river pollution.

d) False. Many lands are not acts for agriculture, but for livestock.

In conclusion we can find the correct answer to the question of how to prevent river pollution is:

   b) Maintain zones of grass at least wide on the sides of streams in the area.

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Answer:

9.05 m/s ,   -14.72°  (respect to x axis)

Explanation:

To find the final velocity of the bowling ball you take into account the conservation of the momentum for both x and y component of the total momentum. Then, you have:

\(p_{xi}=p_{xf}\\\\p_{yi}=p_{yf}\\\\\)

\(m_1v_{1xi}+m_2v_{2xi}=m_1v_1cos\theta+m_2v_{2}cos\phi\\\\0=m_1v_1sin\theta-m_2v_2sin\phi\)

m1: mass of the bowling ball = 5.50 kg

m2: mass of the bowling pin = 0.850 kg

v1xi: initial velocity of the bowling ball = 9.0 m/s

v2xi: initial velocity of bowling pin = 0m/s

v1: final velocity of bowling ball = ?

v2: final velocity of bowling pin = 15.0 m/s

θ: angle of the scattered bowling pin = ?

Φ: angle of the scattered bowling ball = 85.0°

Where you have used that before the bowling ball hits the pin, the y component of the total momentum is zero.

First you solve for v1cosθ in the equation for the x component of the momentum:

\(v_1cos\theta=\frac{m_1v_{1xi}-m_2v_2cos\phi}{m_1}\\\\v_1cos\theta=\frac{(5.50kg)(9.0m/s)-(0.850kg)(15.0m/s)cos85.0\°}{5.50kg}\\\\v_1cos\theta=8.79m/s\)

and also you solve for v1sinθ in the equation for the y component of the momentum:

\(v_1sin\theta=\frac{(0.850kg)(15.0m/s)sin(85.0\°)}{5.50kg}\\\\v_1sin\theta=2.3m/s\)

Next, you divide v1cosθ and v1sinθ:

\(\frac{v_1sin\theta}{v_1cos\theta}=tan\theta=\frac{2.3}{8.79}=0.26\\\\\theta=tan^{-1}(0.26)=14.72\)

the direction of the bawling ball is -14.72° respect to the x axis

The final velocity of the bawling ball is:

\(v_1=\frac{2.3m/s}{sin\theta}=\frac{2.3}{sin(14.72\°)}=9.05\frac{m}{s}\)

hence, the final velocity of the bawling ball is 9.05 m/s

Tom's mass is 75.1 kg

This is the law of conservation of momentum which states that the initial and final momentum are the same.

Since Tom grabs hold of Jerry after the colision, both stick together. So, we use the second equation.

m₁v₁ + m₂v₂ = (m₁ + m₂)vf where

Since we require Jerry's mass, we make m₁ subject of the formula.

So, m₁v₁ + m₂v₂ = (m₁ + m₂)vf

m₁v₁ + m₂v₂ = m₁vf + m₂vf

m₁v₁ - m₁vf = m₂vf - m₂v₂

m₁(v₁ - vf) = m₂(vf - v₂)

m₁ = m₂(vf - v₂)/(v₁ - vf)

Substituting the values of the variables into the equation, we have

m₁ = m₂(vf - v₂)/(v₁ - vf)

m₁ = 84 kg(0.72 m/s - [-4.0 m/s])/(6.0 m/s - 0.72 m/s)

m₁ = 84 kg(0.72 m/s + 4.0 m/s)/(6.0 m/s - 0.72 m/s)

m₁ = 84 kg(4.72 m/s)/(5.28 m/s)

m₁ = 396.48 kgm/s ÷ 5.28 m/s

m₁ = 75.09 kg

m₁ ≅ 75.1 kg

So, Tom's mass is 75.1 kg

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Answer:

42000N

Explanation:

First you calculate how much it would contract, and secondly you then calculate the force to stretch it by that amount.

1) linear thermal expansion coef brass 19e-6 /K

∆L = αL∆T = (19e-6)(1.85)(110) = 0.00387 meter or 3.87 mm

Second part involves linear elasticity.

for brass, young's modulus is 15e6 psi or 100 GPa

cross-sectional area of rod is π(0.008)² = 0.0002 m²

F = EA∆L/L

F = (100e9)(0.0002)(0.00387) / (1.85)

F = 42000 or 42 kN