Car A has an initial velocity of 5 m/s and a constant acceleration of 1.5 m/s2. What will be the velocity of Car A at t = 4 s?

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Answer:

8125 Pa

Explanation:

Pressure exerted= Force/ area of contact

we calculate the force he is excerting = mg

= 75 X 10

= 750N

Pressure exerted while standing= 750/0.08

= 9375 Pa

pressure exerted while laying down = 750/0.6

= 1250 Pa

the difference in pressure= 9375 - 1250

= 8125 Pa.

The electric force between the comb and balloon changes as they are brought closer together the electric force increases, this is because the electric force is directly proportional to the distance between the two objects (the comb and the balloon).

As the distance between the two objects decreases, the electric force increases exponentially, the closer the two objects are brought together, the stronger the electric force becomes. The electric force between the comb and balloon is caused by the presence of static electricity. Static electricity is the buildup of electrical charges on the surface of an object. The buildup of charges is caused by the transfer of electrons from one object to another. When two objects come into contact with each other, there is a transfer of electrons between the two objects.

The object that loses electrons becomes positively charged, while the object that gains electrons becomes negatively charged.As a result of the transfer of electrons, one object becomes positively charged and the other becomes negatively charged. The opposite charges attract each other, causing the electric force between the two objects. Therefore, the electric force between the comb and balloon increases as they are brought closer together.

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Answer:

deep sea will obviously be more affected because of the sea floor shaking

Answer:

deep see

because of the earth inside part highly pressure

Answer:

Electromagnets are special types of magnets that are made by passing current through coils of wire. To make an electromagnet, the minimum requirements are:

1. A nail (usually made of iron, steel or zinc)

2. Dry cell batteries

3. Wire (Usually copper wire)

Other things could be:

1. Electric tape to hold both ends of the wire properly at the battery terminals.

2. Scissors to cut the wire into desired length.

3. Iron fillings for testing purposes.

Answer:

c

Explanation:

Acceleration = change in speed  /  change in time

                     =  (12.8- 9.6) / ( 8) = 3.2 / 8 = .4 m/s^2

Answer:

324 in ===

Explanation:

Answer:

36 kg

Explanation:

m= ?

KE= 324 J

v= 9 m/s

m= 324 / 9

m= 36 kg

Answer:

BASE jumping is the recreational sport of jumping from fixed objects, using a parachute to descend safely to the ground. "BASE" is an acronym that stands for four categories of fixed objects from which one can jump: building, antenna, span, and earth (cliff).[1][2] Participants exit from a fixed object such as a cliff, and after an optional freefall delay, deploy a parachute to slow their descent and land. A popular form of BASE jumping is wingsuit BASE jumping.

Explanation:

In contrast to other forms of parachuting, such as skydiving from airplanes, BASE jumps are performed from fixed objects which are generally much lower altitude, and BASE jumpers typically carry only one parachute. BASE jumping is significantly more hazardous than other forms of parachuting, and is widely considered to be one of the most dangerous extreme sports

The process of a star's death where the star's core fuses lighter elements into heavier elements in a chain process is known as stellar nucleosynthesis.

Stellar nucleosynthesis is the process through which a star synthesizes heavier elements from lighter ones within its core. This chain process begins with the fusion of hydrogen nuclei (protons) to form helium nuclei (helium 4) in a series of nuclear reactions known as hydrogen burning.

As the star evolves and exhausts its hydrogen fuel, it progresses to a stage called helium burning, where helium nuclei fuse to create heavier elements such as carbon, oxygen, and nitrogen. Subsequent stages involve fusion processes that generate even heavier elements, including elements up to iron.

However, fusion beyond iron requires an input of energy rather than releasing energy, making it energetically unfavorable within the core of a star.

The nucleosynthesis process culminates in the death of massive stars, where they undergo a supernova explosion, dispersing their enriched material into space. This material can then become part of future generations of stars and contribute to the formation of planets and life as we know it.

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Answer:

B.

Goals are scored by kicking the ball through goalposts.

Explanation:

Answer:

Explanation:La ecuación de Van der Waals es una ecuación de estado de un fluido compuesto de partículas con un tamaño no despreciable y con fuerzas intermoleculares, como las fuerzas de Van der Waals. La ecuación, cuyo origen se remonta a 1873, debe su nombre a Johannes van der Waals, quien recibió el premio Nobel en 1910 por su trabajo en la ecuación de estado para gases y líquidos, la cual está basada en una modificación de la ley de los gases ideales para que se aproxime de manera más precisa al comportamiento de los gases reales al tener en cuenta su tamaño no nulo y la atracción entre sus partículas.

Answer:

(A)    conduction implies that the objects are in contact

Answer:

I believe it would be Pennsylvania and New Jersey they both border Maryland. Didn't see any other states that border Maryland with West Virginia and Virginia being exempt from the question.

Explanation:

Answer:  the correct answer is Maryland and Virginia

Explanation:  

The idea behind projective personality tests, like the Rorschach Test and the thematic apperception test, is that they can reveal a subject's nature by evoking a response to ambiguous, hazy stimuli.

Projective tests are designed to reveal emotions, wants, and conflicts that are not readily apparent to conscious awareness. Psychoanalysts attempt to identify repressed emotions that may be the root of a person's issues in life by evaluating responses to ambiguous stimuli.

A projective test, which is a type of personality test used in psychology, asks subjects to respond to ambiguous stimuli, with the hope of eliciting responses that disclose any hidden emotions or internal conflicts that the test subject may have projected onto the situation.

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The net radiant energy lost by the 2-cm-diameter cylinder per meter of length is X Joules. The temperature of the 6-cm-diameter cylinder is Y °C.

To calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length, we need to consider the Stefan-Boltzmann law and the emissivities of both cylinders. The formula for net radiant heat transfer is given:

Q_net = ε1 * σ * A1 * (T1^4 - T2^4)

Where:

- Q_net is the net radiant energy lost per meter of length.

- ε1 is the emissivity of the 2-cm-diameter cylinder.

- σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/(m^2·K^4)).

- A1 is the surface area of the 2-cm-diameter cylinder.

- T1 is the temperature of the 2-cm-diameter cylinder.

- T2 is the temperature of the surroundings (27 °C).

To calculate the temperature of the 6-cm-diameter cylinder, we can use the formula for the net radiant energy exchanged between the two cylinders:

Q_net = ε1 * σ * A1 * (T1^4 - T2^4) = ε2 * σ * A2 * (T2^4 - T3^4)

Where:

- ε2 is the emissivity of the 6-cm-diameter cylinder.

- A2 is the surface area of the 6-cm-diameter cylinder.

- T3 is the temperature of the 6-cm-diameter cylinder.

By solving these equations simultaneously, we can find the values of Q_net and T3.

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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also, calculate the temperature of the 6-cm-diameter cylinder

Answer:

A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.

Answer:

(a) The total weight of the climber is equal to her mass multiplied by the acceleration due to gravity. Therefore, W = mg = 62 kg x 10 m/s^2 = 620 N.

(b) The two conditions needed for equilibrium are that the net force acting on the climber is zero and the net torque acting on the climber is zero.

(c)(i) The moment about her feet due to her weight is equal to the weight of the climber multiplied by the distance between her feet and the cliff. Therefore, M = W x d = 620 N x 0.9 m = 558 Nm.

(ii) To determine the tension in the rope, we need to resolve the forces acting on the climber in the horizontal and vertical directions. In the horizontal direction, the tension in the rope is balanced by the force of friction between the climber's feet and the cliff. Therefore, T = F.

In the vertical direction, the climber's weight is balanced by the normal force of the cliff and the tension in the rope. Therefore, N + Tcos(60) = W.

Since the climber is in equilibrium, the net torque acting on her must be zero. Therefore, the torque due to the tension in the rope must be equal and opposite to the torque due to the climber's weight. Therefore, Tsin(60) x 1.2 = M.

Substituting the values we have, we get:

N + Tcos(60) = W

Tsin(60) x 1.2 = M

Solving for T, we get:

N = W - Tcos(60) = 620 N - T(0.5)

Substituting this into the second equation, we get:

Tsin(60) x 1.2 = M

Tsin(60) = M / 1.2 = 558 Nm / 1.2 m = 465 N

Substituting this value of T into the first equation, we get:

N = 620 N - T(0.5) = 620 N - 465 N(0.5) = 388 N

Therefore, the tension in the rope is 465 N and the normal force of the cliff on the climber is 388N

Answer:

yes it is true

Explanation:

The principle of moments states that when a body is balanced the total clockwise moment about a point equals the total anticlockwise moment about the same point.Equation.Moment=Force F×perpendicular distance from the pivot do.

Answer:

8.43 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv/Δt

First, convert km/h to m/s.

45 km/h = 12.5 m/s

500 km/h = 138.9 m/s

Now find the acceleration.

a = (138.9 m/s − 12.5 m/s) / 15.0 s

a = 8.43 m/s²

Answer:

Rubidium or Rb

Explanation:

Use the periodic table, the period numbers are number of shells while the group numbers are numbers of valence electrons

When a roller coaster reaches a velocity of 65.0 m/s prior to the ascent of a hill, the maximum height that can be reached without any propulsion is approximately 213.6 meters.

This assumes that there is no energy loss from friction. The energy conservation principle governs the maximum height reached by a roller coaster. At the base of the hill, the roller coaster has kinetic energy (energy of motion), but no potential energy (energy of height). It has the maximum potential energy and minimum kinetic energy at the highest point of the hill, and it returns to the base of the hill with zero potential energy and maximum kinetic energy. The total energy, which is the sum of potential energy and kinetic energy, is always conserved, implying that the energy at the base of the hill equals the energy at the peak of the hill. According to the principle of conservation of energy:Ei = Efwhere Ei is the initial energy, Ef is the final energy, and E = KE + PE, where KE is kinetic energy, and PE is potential energy.Consider the roller coaster with a velocity of 65.0 m/s at the base of the hill. The initial energy of the roller coaster, Ei = KE + PE, is equal to: Ei = (1/2) mv^2 + 0where m is the mass of the roller coaster and v is its velocity. Ei = (1/2) mv^2The final energy of the roller coaster at the highest point on the hill, Ef, is equal to: Ef = 0 + mghwhere h is the height of the roller coaster at the top of the hill.

Equating Ei and Ef:(1/2) mv^2 = mgh

Solving for h, we get: h = (1/2) v^2/g

where g is the acceleration due to gravity.The maximum height that can be attained by a roller coaster without propulsion is h = (1/2) v^2/g.

Substituting v = 65.0 m/s and g = 9.81 m/s²,

we get: h = (1/2) (65.0 m/s)^2/9.81 m/s² = 213.6 meters.

Therefore, the maximum height that a roller coaster can reach without propulsion is around 213.6 meters, given no friction.

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Answer:

most likely D

Explanation:

Distance from the surface to the center of the planet is inversely proportional to your weight or force due to gravity on a planet's surface.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.

f = Gmm/r²

Distance from the surface to the center of the planet is inversely proportional to your weight or force due to gravity on a planet's surface.

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Answer:

28500

Explanation:

Force equation - F = m * a

F = 950 * 30

F = 28500

The value of n in the given function is negative even integer.

The given parameters:

\(f(x) = a(x + k)^{\frac{1}{n } } + c\)

When n is positive, the function is written as;

\(f(x) = a(x + k)^{\frac{1}{n } } + c\)

When n is negative, the function is written as;

\(f(x) = a(x + k)^{\frac{1}{-n} } + c\\\\f(x) = \frac{a}{(x + k)^n} + c\)

When n is odd integer, the function will have three possible curves.

When n is even integer, the function will have two curves: one real solution and one imaginary solution.

When n is positive even integer, the real solution will curve upwards.

When n is negative even integer, the real solution will curve downwards.

The plot in the given graph curves downwards which indicates negative even integer value of n.

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Answer: N is a positive even integer

Explanation: The answer above is wrong I did the quiz once alr.

Answer:

Explanation:

Biomass is the total quantity or weight of organisms  in a given area or volume.

Answer:

η₁ = 2.6

Explanation:

Here, we will use snell's law to calculate the refractive of the substance:

\(\frac{\eta_2}{\eta_1} = \frac{Sin\theta_1}{Sin\theta_2}\)

where,

η₁ = refractive index of first substance = ?

η₂ = refractive index of second substance = 1.5

θ₁ = angle of incidence = 30°

θ₂ = angle of refraction = 60°

Therefore,

\(\frac{1.5}{\eta_1} = \frac{Sin\ 30^0}{Sin\ 60^0}\)

η₁ = 2.6

  The Direct Imaging technique used to detect exoplanets has biases associated with it. It is heavily biased towards finding exoplanets that are very large and very far from their parent star.

  The Direct Imaging technique involves directly capturing the light from an exoplanet, which is challenging due to the brightness of the parent star. This technique is more likely to succeed in detecting exoplanets that are large in size, as their signal is relatively easier to separate from the glare of the parent star. Therefore, the Direct Imaging technique is biased towards finding very large exoplanets.

  Additionally, this technique is better suited for detecting exoplanets that are located farther away from their parent star. When an exoplanet is situated at a significant distance from its star, the contrast between the planet's light and the star's light is more pronounced, making it easier to distinguish and image the exoplanet. Hence, the Direct Imaging technique is biased towards finding exoplanets that are very far from their parent star.

  On the other hand, this technique is not well-suited for detecting exoplanets that are moving very slowly or located very close to their parent star. Slow-moving exoplanets might be difficult to distinguish from background noise or other sources of motion, while planets close to their parent star might be obscured by the star's brightness, making it harder to directly image them using this technique.

  Therefore, the Direct Imaging technique is not biased towards finding exoplanets that are moving very slowly or very close to their parent star.

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