Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia, where hydroelectric plants produce inexpensive electric power, the H₂ can be made industrially by the electrolysis of water.(c) If the combustion of oil yields 4.0X10⁴ kJ/kg, what mass of oil must be burned to yield the number of joules in part (b)?(b) If the coulombs are supplied at 1.44 V, how many joules are produced?

Answer:

I think the answer would be 'testable'.

a) Balanced nuclear equations for the alpha decay of Plutonium-234 is  238/94Pu → 4/2He + 234/92U

b) Balanced nuclear equations for the alpha decay of Strontium-90 is 90/38Sr → 4/2He + 86/36Kr

a) Plutonium-234 undergoes alpha decay, resulting in the emission of an alpha particle, which consists of two protons and two neutrons. The balanced nuclear equation for this decay is:

238/94Pu → 4/2He + 234/92U

b) Strontium-90 also undergoes alpha decay, resulting in the emission of an alpha particle. The balanced nuclear equation for this decay is:

90/38Sr → 4/2He + 86/36Kr

For the decay of Radium-226, it can undergo alpha, beta, and gamma decay. The balanced nuclear equations for each decay are as follows:

Alpha decay:

226/88Ra → 4/2He + 222/86Rn

Beta decay:

226/88Ra → 226/89Ac + 0/-1e

Gamma decay:

226/88Ra → 226/88Ra + γ

In beta decay, a neutron within the nucleus is converted into a proton and an electron, which is emitted from the nucleus. In gamma decay, a nucleus emits a high-energy photon, or gamma ray, as it transitions from a higher energy state to a lower energy state.

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The correct question is:

Write the Balanced nuclear equations for the alpha decay of:

a) Plutonium-234

b) Strontium-90

Write the balanced nuclear equations for the alpha, beta, and gamma decay of Radium-226

Answer:

Oxygen -02 Because it present oxygen

Answer:

I only

last answer

Explanation:

Answer:

it has many layers

the inner core is solid

the core is iron

its very hot

the presusre increases as you move closer to the core

The given equation is showing the law of conservation of mass as the number of hydrogen and oxygen atoms are same on the both sides of the equation.

A chemical equation can be described as the representation of a  reaction in terms of chemical symbols of the substances. A chemical equation possesses of participating reactants in the reaction, formed products, and an arrow representing the direction of the chemical reaction.

The chemical equation in which the number of atoms of each element is equal on either side of the equation is called a balanced chemical equation.

The law of conservation of mass obeys by every balanced chemical equation. By following law of conservation, the total mass of the chemical elements  on the reactant side should be equal to the total mass of chemical elements on the product side in a balanced chemical equation.

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The task is to write a condensed structural formula for an n-alkane with the given molecular formula.An n-alkane is an unbranched alkane.CH3(CH2)2​6​CH3.

Alkanes, alkenes, alkynes, & aromatic hydrocarbons are the four subcategories that are typically used to classify hydrocarbons. These compounds might have relatively basic structures or relatively complicated ones.

Typically, hydrogen atoms form a protective shell around carbon atoms to form molecules.Hydrocarbons are categorized into four primary groups: alkanes, alkenes, alkynes, and aromatic hydrocarbons.

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Answer:

All elements, and compounds, all matter in point of fact, are composed of atoms. In a compound, there are 2 or more different types of atoms present that are chemically bound. In an element, there is only the one type of atom.

Explanation:

Answer:

5.13g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

HBr(aq) + NaOH(aq) —> NaBr(aq) + H2O(l)

Next, we shall determine the masses of HBr and NaOH that reacted and the mass of H2O produced from the balanced equation.

This is illustrated below:

Molar mass of HBr = 1 + 80 = = 81g/mol

Mass of HBr from the balanced equation = 1 x 81 = 81g

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 1 x 40 = 40g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 1 x 18 = 18g

Thus, from the balanced equation above,

81g of HBr reacted with 40g of NaOH to produce 18g of H2O.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

81g of HBr reacted with 40g of NaOH.

Therefore, 34g of HBr will react with = (34 x 40)/81 = 16.79g of NaOH.

From the calculations made above, we can see that it will take a higher mass (i.e 16.79g) of NaOH than what was given (i.e 11.4g) to react completely with 34g of HBr.

Therefore, NaOH is the limiting reactant and HBr is the excess react.

Finally, we can determine the maximum mass of H2O produced as shown below.

In this case the limiting reactant will used because it will produce the maximum mass of H2O since all of it is consumed in the reaction.

The limiting reactant is NaOH and the maximum mass of H2O produced can be obtained as follow:

From the balanced equation above,

40g of NaOH reacted to produce 18g of H2O.

Therefore, 11.4g of NaOH will react to produce = (11.4 x 18)/40 = 5.13g of H2O.

Therefore, the maximum mass of H2O produced from the reaction is 5.13g.

The electron configuration of an element represents the arrangement of electrons in its atomic orbitals. To write the electron configuration using core notation for p3, The electron configuration of neon is 1s² 2s² 2p⁶.

we start with the noble gas that precedes phosphorus in the periodic table, which is neon (Ne).

The electron configuration of neon is 1s² 2s² 2p⁶. The core electrons, represented by the noble gas configuration, are enclosed in square brackets: [Ne].

After the noble gas configuration, we add the valence electrons specific to phosphorus. Phosphorus (P) is in Group 15, so it has five valence electrons. Therefore, we add the remaining three electrons to the 3p orbital:

[Ne] 3s² 3p³.

The core notation provides a concise representation of the electron configuration by highlighting the filled inner shells (core electrons) with the noble gas symbol and specifying the valence electrons in the outermost energy level and orbitals.The electron configuration of neon is 1s² 2s² 2p⁶.

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Answer:

Explanation:                                                                                        

The warm water provides moisture for hurricanes so that hurricanes are strongest over water, and become weak when they reach land.

Hurricanes are forceful winds in the air which are able to destroy even a land completely. One of the most destructive forces on earth is the hurricane. Although the process of a origin of  hurricane is complex.

They need water that is at least 80 degrees first. Air that is wet is the second component. Finally, for a hurricane to form, there must be convergent winds.

A group of thunderstorms moving across the ocean's surface signal the start of the real process. Similar to how a straw absorbs liquid, when the surface water is heated, the storm absorbs heat energy from the water. The air becomes moistened as a result.

The storm can develop into a hurricane if the wind conditions are right. The fuel is this thermal energy. Hence, option c is correct.

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Answer:

C. 0.1 mol of V₂O₅

Explanation:

Number of moles of oxygen atoms present in each molecule is derived as follows:

A. Number of molecules of CO₂ in 12.044 * 10²³ molecules of CO₂ = 12.044 * 10²³/6.022 * 10²³ = 2 moles of CO₂ molecules

Each molecule of CO₂ contains 2 atoms of oxygen. Therefore, number of moles of oxygen atom present in 2 molecules of CO₂ = 2 * 2 moles of oxygen atoms = 4 moles of oxygen atoms.

B. Number of moles of O₃ molecules in 12g of O₃ = mass of O₃/molar mass of O₃

molar mass of O₃ = 48 g/mol

Number of  moles of O₃ molecules = 12/48 = 0.25 moles of O₃

There are 3 atoms of oxygen in a molecule of O₃, therefore number of moles of oxygen atoms present in 12 g of O₃ = 3 * 0.25 = 0.75 moles of oxygen atoms

C. There are 5 oxygen atoms in a molecule of V₂O₅

0.1 mol of V₂O₅ contains 0.1 * 5 moles of oxygen atoms = 0.5 moles of oxygen atoms.

D. mass of 10 mL of H₂O = 10 g since the density of H₂O = 1 g/mL

molar mass of H₂O = 18.0 g/mol

Number of moles of H₂O in 10 g of H₂O = 10/18 = 0.56 moles

There are 1 atom of oxygen in a molecule of H₂O, therefore, number of moles of oxygen present in 10 g of H₂O = 0.56 * 1 = 0.56 moles of oxygen atoms

Therefore, 0.1 mole of V₂O₅ contains the least number of oxygen atoms.

Answer:

true

Explanation:

true its true true

uhhhh sorry i have no idea try a different site

Explanation:

Answer:

22.5 Km

Explanation:

45km/hr * 0.5 hr = 22.5km

A polyatomic gas like H2S would have the most microstates at the same temperature for a certain measured macrostate.

A polyatomic gas is a type of gas composed of molecules that have more than one atom. These molecules have a more complex internal structure than diatomic gases (such as hydrogen and nitrogen) and can rotate and vibrate in multiple ways, which results in more degrees of freedom and a greater number of possible energy states. This means that polyatomic gases tend to have a higher specific heat capacity and a higher heat of combustion than diatomic gases.

Therefore polyatomic gas like H2S is the chemical specie that has the most microstates at the same temperature for a certain measured macrostate.

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Answer: 89.57 %

Hope it helps

Answer:

changing while growing

Explanation:

Answer: the answer is a

The owls in the certain area located in the picture represent a population, they are formed up as a small group of animals representing a small species.

The level of ecological organization that all owls in a given area represent is the population of owls in a given area.

In ecology, the organism, population, community, ecosystem, and biosphere are among the levels of organization. A population is a collection of creatures from the same species that coexist in one location and communicate with one another.

Researchers in the field of ecology focus on five major levels: organism, population, community, ecosystem, and biosphere. These levels are sometimes studied separately and other times they overlap. Let's examine each stage one by one.

The owls in the particular location shown in the image are a population; they are made up of a few individuals representing a single small species.

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Picric acid was primarily used as an explosive for artillery shells in 1921. It was highly effective in this capacity due to its ability to create a stable and powerful explosion. However, picric acid also had a wide range of applications as a laboratory reagent.

In fact, it was one of the most common reagents used in chemical analysis at the time. Despite its explosive properties, picric acid was highly valued in the laboratory due to its ability to react with a variety of chemical compounds and provide accurate analytical results. Therefore, while picric acid was primarily used as an explosive in 1921, it was also a common laboratory reagent with a variety of important applications.

It had two main uses in 1921:

1. As an explosive for artillery shells: Picric acid, also known as 2,4,6-trinitrophenol, was a powerful and sensitive high explosive. Due to its properties, it was widely used in military applications such as artillery shells during World War I and before.

2. As a common laboratory reagent: In addition to its explosive nature, picric acid was also used as a reagent in laboratories. It served as a dye and as a fixative for biological specimens, particularly in the field of histology.

In summary, picric acid was employed in 1921 as both a common laboratory reagent and an explosive for artillery shells.

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This problem is asking for the percent by mass of hydrogen in hydrofluoric acid. At the end, the answer turns out to be D. 5%​ as shown below:

In chemistry, percent compositions are used for us to know the relative amount of a specific element in a compound. In order to do so for hydrogen, we use the following formula, which can also be applied to any other element in a given compound:

\(\% H=\frac{m_H*1}{M_{HF}}*100\%\)

Where \(m_H\) stands for the atomic mass of hydrogen and \(M_{HF}\) for the molar mass of hydrofluoric acid. In such a way, we plug in the atomic masses of hydrogen (1.01 g/mol) and fluorine (19.0 g/mol) to obtain:

\(\% H=\frac{1.01g/mol*1}{1.01g/mol+19.0g/mol}*100\%\\\\\% H=5\%\)

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Answer:

B. No more powder will dissolve in the water.

Explanation:

If a lot of powder is added to the water, then a fully saturated solution would be created. This means that no matter how much more powder is added or how strong the mix is shaken, no more powder will disolve. The powder will instead remain in solid form in the solution.

Answer:

Heat up the water first because it increases solubility of the powdered mix.

Explanation:

Took the test on Edg. Hope this helps!! :)

Non-polar molecules carry no charge and are more likely to cross cell membranes by simple diffusion.

In biology, simple diffusion can be described as the process by which molecules move from high to low concentrations along a concentration gradient.

Nonpolar molecules have no charge and are not ionized. Therefore, since the cell membrane is polar, it is difficult for polar molecules to cross the cell membrane by simple diffusion. Small non-polar molecules can easily cross cell membranes by diffusion.

The molecules most likely to cross cell membranes are small molecules, whether polar or non-polar. Molecules such as oxygen and carbon dioxide (nonpolar molecules) easily cross cell membranes, as does water, which is a polar molecule.

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Titration is the correct answer.

What is titration?

Titration, commonly referred to as titrimetry, is a typical quantitative chemical analysis method used in laboratories to ascertain the unidentified quantity of an analyte (Mednick and Kirschner, 2010). Titration is frequently referred to as volumetric analysis because it relies heavily on volume measurements. To determine concentration, a solution of the analyte or titrant reacts with a known concentration and volume of the titrant. Titrations come in a variety of forms with various protocols and objectives. Redox and acid-base titrations are the two most typical types of qualitative titrations.

Acid-base titrations rely on the solution-based neutralisation of an acid and a base. The acid-base indicator changes colour to signal when the titration has reached its endpoint.

Titrations carried out in the gas phase are known as "gas phase titrations," and they are specifically used to identify reactive species through their reaction with an excess of a titrant gas. In one typical gas phase titration, nitrogen oxide and gaseous ozone are titrated in accordance with the reaction

The amount of analyte in the initial sample is determined by quantifying the remaining titrant and product after the reaction has finished (for example, using FT-IR).

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Solution of an unknown concentration that has another solution slowly added to it _____________.

Answer:

The formation of a precipitate

Explanation:

took thecquiz on edge. got it correct

The formation of a precipitate is a evidence that a chemical reaction has likely occurred.

A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form other new substances.

Now lets check all option one by one

Option (A): a liquid slowly losing volume

Here change in volume occurred which is not a evidence of a chemical reaction.

So it is incorrect option.

Option (B): the formation of a precipitate

Here formation of precipitate is a evidence of a chemical reaction.

So it is correct option.

Option (C): boiling water releasing steam

Here formation of evaporation takes places which is not a evidence of a chemical reaction.

So it is incorrect option.

Option (D): a change in the shape of solid.

Here change in shape occurred which is not a evidence of a chemical reaction.

So it is incorrect option.

Thus, from we can say that the formation of a precipitate is a evidence that a chemical reaction has likely occurred.

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Explanation:

14,400 gallons of water can be filtered by the new water filter invented by the company.

It is given that the filter can process 10 gallons of water per minute.

So In an hour:

10 gallons per minute x 60 minutes = 600 gallons in 1 hour.

And in a day:

24 hours x 600 gallons per hour = 14,400 gallons in 24 hours.

Hence, 14,400 gallons of water can be filtered.

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A protein mixture is commonly applied to a HIC column under high salt conditions, and the protein of interest is eluted with a buffer of decreasing ionic strength.

Structured salts added to the equilibration buffer and sample promote ligand-protein interactions in HIC. The amount of bound protein decreases as the salt concentration decreases, as does the risk of protein precipitation at lower ionic strength.

Despite the fact that sodium, potassium, or ammonium sulfates have a higher precipitation effect, these salts effectively promote ligand-protein interactions in HIC. Most bound proteins are eluted by washing with water or a dilute buffer with a pH close to neutral.

What exactly is HIC?

Hydrophobic interaction chromatography (HIC) is a technique used to separate molecules based on their hydrophobicity. HIC is a useful separation technique for purifying proteins while retaining biological activity due to the use of less denaturing conditions and matrices.

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Claim: The separation of Mesosaurus fossils can be explained by the continental drift hypothesis. Evidence: Fossil Distribution, Geological Similarities, Matching Climate and Habitat. The distribution of Mesosaurus fossils across South America and Africa, the geological similarities between these regions, and the matching climate and habitat conditions all support the claim that the separation of Mesosaurus populations can be explained by the process of continental drift.

Claim: The separation of Mesosaurus fossils can be explained by the continental drift hypothesis.

Evidence:

Fossil Distribution: Mesosaurus fossils are found in both South America and Africa. This distribution aligns with the hypothesis of continental drift, which suggests that these continents were once connected and later separated. The similarity in fossil remains on different continents supports the claim that Mesosaurus populations were separated when the continents drifted apart.

Geological Similarities: The geological formations and sedimentary layers in which Mesosaurus fossils are found in South America and Africa display remarkable similarities. This similarity implies that these regions were once part of the same landmass and were subsequently separated. The matching geological features provide further evidence for the separation of Mesosaurus populations due to continental drift.

Matching Climate and Habitat: Mesosaurus fossils indicate that the species was adapted to a freshwater environment. The presence of similar freshwater environments in both South America and Africa further supports the claim that Mesosaurus populations were separated when the continents drifted apart. The matching climate and habitat conditions provide evidence that supports the idea of geographic isolation and subsequent speciation.

In conclusion, the distribution of Mesosaurus fossils across South America and Africa, the geological similarities between these regions, and the matching climate and habitat conditions all support the claim that the separation of Mesosaurus populations can be explained by the process of continental drift.

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