Characterize each mixture as a solution, colloid, suspension.
Whipped cream:
- Solution
- Colloid
- Suspension
Colloid

Answer:

mercury

Explanation:

because mercury can get turned into liquid in any normal rrom temperature

Answer: Flow rate is inversely proportional to viscosity.

Explanation: The relation is called Poiseuille's law, which describes the smooth flow of a fluid along a tube.

Answer:

Viscosity is a fluid's resistance to flow and flow rate is the volume of fluid that passes by a point in a certain amount of time. Viscosity and flow rate are similar because they are inversely proportional; high viscosity means a decreased flow rate and vice versa.

Answer:

Explanation:

Here, we want to get the number of moles of NO gas that can be formed

To answer this, we need to be sure of the limiting reagent

The limiting reagent is the one that is responsible for the number of moles of product formed

From the shown balanced equation of reaction, 3 moles of silver produced 1 mole of the gas

Thus, 0.1 mol of powdered silver will produce:

For the nitric acid, we need to get the number of moles that reacted

To get this, we have to multiply the volume (in L) that reacted by the molarity

Mathematically, we have that as:

From the equation of reaction, 4 moles of the nitrate gave 1 mole of the gas

Thus, we have it that 0.06 moles will give:

From what we see, the number of moles produced by the nitrate is less than what was produced by the solid

Thus, the nitrate is the limiting reagent and the number of moles of the gas produced is 0.015 mol

Gamma radiation is the most penetrating. It can penetrate air, paper or thin metal. It may only be stopped by many centimetres of lead or many metres of concrete.

Answer: 0.759 L

Explanation:

molarity = moles of solute / liters of solution

so, 6.750 = 5.120 / liters of solution

liters of solution = 5.120/6.750 = 0.759 L

To find the concentration of HCl, we need to calculate the moles of base added to neutralize the acid, the moles of acid originally in the beaker, and then use these values to determine the molarity of HCl.

a) To find the moles of base (NaOH) added, we can use the formula:

Moles of NaOH = Volume of NaOH (in L) × Molarity of NaOH

Converting the volume to liters and using the given values:

Moles of NaOH = 0.080 L × 2.5 mol/L = 0.2 mol

b) Since the reaction is a 1:1 stoichiometric ratio between NaOH and HCl, the moles of acid (HCl) will be equal to the moles of base added. Therefore, there were also 0.2 mol of HCl originally in the beaker.

c) Now, we can calculate the molarity of HCl using the formula:

Molarity (M) = Moles of solute / Volume of solution (in L)

Given that the volume of the acid is 100.0 mL (or 0.100 L) and the moles of acid is 0.2 mol:

Molarity of HCl = 0.2 mol / 0.100 L = 2.0 M

Therefore, the molarity of the HCl solution is 2.0 M.

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In chromatography, column volume refers to the volume of the column, including the stationary phase, while void volume refers to the volume of the space between the particles of the stationary phase.

Void volume is also known as the dead volume or the exclusion volume.

The column volume and void volume of a specific column depend on the dimensions of the column, the type of stationary phase used, and the packing density of the stationary phase.

Typically, the compound that elutes in the void volume of a column is one that is too small to be retained by the stationary phase or one that interacts weakly with the stationary phase. As a result, it quickly passes through the column volume without much interaction with the stationary phase, leading to its elution in the void volume.

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Answer:

Here are possible ways to improve health and quality of life:

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Mass and volume are extensive properties, but they can help you find the identity of a substance.

To Find :

The mass, in grams, of \(1.505 \times 10^{23}\) molecules of carbon disulfide (CS₂).

Solution :

Molecular mass of CS₂ = 76 gm/mol .

It means that mass of \(6.022 \times 10^{23}\) molecules of CS₂ is 76 gm/mol.

Let, mass of \(1.505 \times 10^{23}\) molecules of carbon disulfide (CS₂) is x.

So,

\(x= 76\times \dfrac{1.505 \times 10^{23}}{6.022\times 10^{23}}\\\\x = 76 \times \dfrac{1.505}{6.022}\\\\x = 19 \ gm\)

Therefore, the mass in gram is 19 gm.

The composition of the bottle can be confirmed by qualitative analysis.

The term qualitative analysis refers to the procedure that we use to identify the substances that are contained in an unknown substances. In this case, we have to carry out a series of test in order to ascertain that the sample is NaF.

Now, we have to divide the sample into two and subject the first part to a flame test. If a yellow flame is observed then the sodium ion is present.

To the second portion we have to add concentrated  sulfuric acid. The occurrence of oily droplets could signal the presence of the fluoride ion. If sad is added to this reaction mixture and heated before water is added, the appearance of a white gelatinous deposit confirms the presence of the fluoride ion.

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The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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Answer:

covalen and ionic compound

5a) The maximum mass of sodium peroxide formed when 4.60 g of sodium is burnt in excess oxygen is; 7.8g of Sodium peroxide

5b) The mass of carbon that exactly reacts with 14.0g of tin(IV) oxide is; 2.23g of Carbon.

For questions (5a)

Sodium reacts with excess oxygen to form Sodium peroxide as follows;

Molar mass of sodium and sodium peroxide are 23 and 78 respectively.

Since 2 units of sodium produces one unit of sodium peroxide.

Therefore,

x = 7.8g of Na2O2

For question (5b)

Tin oxide (IV) is reduced to tin by carbon. Carbon monoxide is also formed as follows;

From stoichiometry,

By Cross-product,

x = 2.23g of carbon

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Answer:

H2O

Explanation:

for the condition seborrhea sicca, sulfur and salicylic acid  shampoos would be the most beneficial for the patient.

Seborrhea usually affects the back, face, and flanks and is worse in skin folds. Seborrhea is classified into two types: seborrhea sicca (dry seborrhea) and seborrhea oleosa (oily seborrhea) (meaning oily seborrhea). The majority of dogs with seborrheic dermatitis have both dry and oily seborrhea. The combination of salicylic acid and sulphur is used to treat acne and other skin disorders, as well as dandruff and other scalp disorders such as seborrheic dermatitis. This medication is not available with a prescription. The following dosage forms are available for this product: cream

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(e) 5, 4,- 5, 1/2 is the acceptable set of quantum numbers for an electron in an atom.

In chemistry, electrons in atoms are described by four sets of quantum numbers, and they are as follows:

The principal quantum number, or n, typically has integer values ranging from 1 to infinity. From 0 through n - 1, the orbital quantum number can have several values. In contrast to the spin quantum number, the magnetic quantum number can take on values ranging from -l to +l.

Putting this to the back of our thoughts, we can clearly see that only the set of quantum numbers 5, 4,- 5, 1/2 meets the requirements outlined above.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{8.5 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 141.19601...\)

We have the final answer as

Hope this helps you

Answer: A. There will be fewer producers in that area.

Explanation: Answer A is correct because all plants, including grass, is a producer. Since there is an increase in grass eating animals (Antelope), more grass will be consumed, decreasing the amount of grass aka producer.

When adding acid to the basic aqueous layer, the benzoic acid compound precipitates out due to the acid-base reaction resulting in reduced solubility of benzoic acid in the solution.

During the extraction lab, benzoic acid is typically extracted into the organic layer, leaving behind a basic aqueous layer. When acid is added to the basic aqueous layer, the pH of the solution decreases, causing the benzoic acid to become less soluble in water.

As a result, the benzoic acid will precipitate out of the solution as a solid. This is due to the decreased solubility of benzoic acid in acidic solutions compared to basic solutions.

When adding acid to the basic aqueous layer, the benzoic acid compound precipitates out because it becomes less soluble in the solution.

Step 1: In the extraction lab, you have a basic aqueous layer containing the benzoate ion (C6H5COO-) which is a conjugate base of benzoic acid (C6H5COOH).

Step 2: When you add acid (H+) to the basic aqueous layer, the benzoate ion reacts with the acid through an acid-base reaction.

Step 3: The reaction produces benzoic acid, which is less soluble in water than the benzoate ion.

Step 4: As a result of the reduced solubility, the benzoic acid precipitates out of the solution, allowing for its separation and purification.

In summary, when adding acid to the basic aqueous layer, the benzoic acid compound precipitates out due to the acid-base reaction resulting in reduced solubility of benzoic acid in the solution.

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If half life of an isotope is 12 days, then there are about 820.42 transformations in the stomach after the person ate 400 Bq of the isotope.

Using the GI track model information, the number of transformations in Stomach can be calculated as follows :

We know that the half-life of an isotope is defined as the time taken for half of the radioactive atoms to decay.

The decay of the isotope can be represented by the following formula : N(t) = N0e^(-λt)

where:

N(t) = Number of atoms at time t

N0 = Initial number of atoms

λ = Decay constant

t = Time elapsed from the initial time t = 0

For a given isotope, the decay constant is related to the half-life as follows : λ = 0.693/T1/2

where : T1/2 = Half-life time of the isotope

Given that the half-life of the isotope is 12 days, we can calculate the decay constant as follows :

λ = 0.693/12 = 0.0577 day^(-1)

The number of transformations in the stomach can be calculated by using the following formula :

Activity = A0e^(-λt)

where : A0 = Initial activity of the isotope in Bq

λ = Decay constant

t = Time elapsed from the initial time t = 0

Activity = 400 Bq (Given)

Decay constant (λ) = 0.0577 day^(-1)

Time elapsed (t) = Time taken by the isotope to reach the stomach from the time of consumption = 0.17 days (Given by GI track model)

Therefore, the number of transformations in the stomach is :

Activity = A0e^(-λt)A0 = Activity/e^(-λt)A0 = 400 Bq/e^(-0.0577 × 0.17)A0 = 400 Bq/e^(-0.009809)A0 = 447.45 Bq

The number of transformations in the stomach can be calculated as follows :

Number of transformations = Activity decayed per unit time/Disintegration constant

Activity decayed per unit time = A0 - Activity after time elapsed

Activity decayed per unit time = 447.45 - 400 = 47.45 Bq

Disintegration constant = Decay constant = 0.0577 day^(-1)

Therefore, number of transformations = (447.45 - 400) Bq/0.0577 day^(-1)

Number of transformations = 820.42

This means that there are about 820.42 transformations in the stomach after the person ate 400 Bq of the isotope.

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Answer:

A

Explanation:

Among the compounds mentioned, CH₂ (methylene) has the shortest carbon-carbon bond(s). This is due to the presence of a double bond, which results in a shorter and stronger bond compared to single bonds in other compounds.

The length and strength of a carbon-carbon bond depend on the nature and type of bonding between the carbon atoms. In the case of CH₂, it contains a double bond between the carbon atoms. A double bond consists of one σ bond and one \(\pi\) bond. The presence of the \(\pi\) bond in addition to the σ bond makes the carbon-carbon bond in CH₂ shorter and stronger compared to a single bond.

In compounds like CH₃CH₃ (ethane) or CH₃CH₂CH₃ (propane), the carbon atoms are connected by single bonds. Single bonds are formed by the overlap of one σ orbital from each carbon atom. Since there are no additional \(\pi\) bonds, the carbon-carbon bonds in these compounds are longer and weaker compared to the carbon-carbon double bond in CH₂.

Therefore, among the compounds mentioned, CH₂ has the shortest carbon-carbon bond(s) due to the presence of a double bond, which provides a stronger and shorter bond compared to the single bonds in other compounds.

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From thermal comfort point of view, thick walled structures are beneficial in hot and humid climates is the statement that is true.The correct option is C.

Thick walled structures are beneficial in hot and humid climates from the thermal comfort point of view.How do thick walled structures help in hot and humid climates - In hot and humid climates, thick walls tend to absorb the heat present in the environment. This absorption helps to keep the interior of the structure cool.

Additionally, thick walls take more time to heat up and more time to cool down. Thus, in hot and humid climates, thick walls are a better choice than thin walls because they provide thermal comfort.

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Answer:

It is the temperature at which water is frozen or is pure ice

"Absolutely zero" temperature is the coldest temperature possible. It's so cold that everything stops moving and has no energy left. Scientists use a special scale called Kelvin to measure temperature, and absolute zero is at 0 Kelvin or -273.15 degrees Celsius (-459.67 degrees Fahrenheit). We can't actually reach absolute zero in real life, but scientists have come very close in laboratories using special cooling methods.

The compound that contains both carboxyl and amino functional groups in the same molecule is an amino acid. The amino group is NH2 and the carboxyl group is COOH.

The basic structure of an amino acid consists of a central carbon atom known as the alpha carbon. The central carbon atom is attached to an amino group (-NH2), a carboxyl group (-COOH), and an R group that is unique to each amino acid.  The amino acid’s amino group and carboxyl group are bonded together via a peptide bond that is formed via a condensation reaction between the two groups.

The peptide bond, which links amino acids together to form proteins, is a covalent bond between the carboxyl group of one amino acid and the amino group of another amino acid. Hence, it is not wrong to say that an amino acid is the compound that contains both carboxyl and amino functional groups in the same molecule.

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