choose a linear function for the line representing by the point slope equation y-5=3(x-2)

\(\text {Hello! Let's Solve this Problem!}\)

\(\text {When multiplying fractions you multiply numerator by numerator and }\) \(\text {demoninator by denominator. Simplifying is required when the answer comes}\) \(\text {out as fraction that can be simplified. Simplify until it's reduced to the lowest}\) \(\text {fraction it ca be.}\)

\(\text {\underline{Multiply}}\)

\(\text {5*6=30}\)

\(\text {8*15=120}\)

\(\text {Your Answer Would Be:}\)

\(\Huge\boxed {30/120}\)

\(\text {Since this is a fraction we can simplify we simplify it by 30}\)

\(\text {Q: What does simplify mean?}\)

\(\text {A: It means to divide. So if someone says simplify 2/4 that means divide.}\)

\(\text {\underline {Divide}}\)

\(\text {30/120 divided by 30 =}\)

\(\text {Your Simplified Fraction Answer Would Be:}\)

\(\Huge\boxed {1/4}\)

\(\text {Best of Luck!}\)

\( \huge \sf \underline{Solution:-}\)

\( \frac{5}{8} \times \frac{6}{15} \)

\( = \frac{30}{120} \)

\( = \frac{1}{4} \)

Here, we just have to multiply the top numbers and then multiply the bottom numbers. Then we can simplify the fraction if needed.

So, correct answer is ¼.

Hope it helps you :)

Answer

Yes, zero is contained in the interval

We are given the radius of the scoop and asked to find the volume of ice cream in one scoop. By using the formula for the volume of a sphere and substituting the given radius, we can calculate the volume. The final answer is approximately 33.49 cubic inches.

a) The problem asks for the volume of ice cream in one scoop.

b) The given fact is that the radius of the scoop is 2 inches.

c) The formula to be used is the volume of a sphere, which is given by V = (4/3)πr³, where V is the volume and r is the radius.

d) Number Sentence:

  - Given: Radius (r) = 2 inches

  - Formula: V = (4/3)πr³

  - Substituting the value: V = (4/3)π(2)³

  - Simplifying: V = (4/3)π(8)

  - Evaluating: V = (4/3)(3.14)(8)

  - Multiplying: V = 33.49333333 (approx.)

e) Final answer: The volume of ice cream in one scoop is approximately 33.49 cubic inches.

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Answer:

convert it to improper fractions first

Step-by-step explanation:

4 x 7 + 3 = 31

So, 7   3/4 = 31/4

Similarly, 5 x 2 + 2 = 12

So, 2  2/5 = 12/5

Now we have,

31/4 - 12/5

Make the denominators same....

Multiply both the denominators by each other...

4 x 5    and 5 x 4 = 20 both the denominators equal to 20.

Now multiply the numerators like that

so, 31 x 5  and 12 x 4

equals to 151/20  and 48/20

Now subtract both ...

151-48 = 103

So the answer is 103/20

Hope it helps!!!

The measure of length MN is 31.

The measure of length KN is 45.

The measure of m∠K is 61⁰.

The measure of m∠L is 119⁰.

A parallelogram is a four-sided plane figure in which opposite sides are parallel and congruent (having the same length) and opposite angles are congruent (having the same measure). In other words, a parallelogram is a quadrilateral with two pairs of parallel sides.

The properties of a parallelogram include:

So the length MN = Length KL = 31

Length KN = Length LM = 45

Angle K = angle M = ( 180 - 119) = 61⁰

Angle L = angle N = 119⁰

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The question is missing parts. Here is the complete question.

The isosceles triangle below has height AQ of length 3 and base BC of length 2. A point P may be placed anywhere along the line segment AQ.

What is the minimum value of the sum of the lengths of AP, BP and CP?

Answer: The sum is 4.73.

Step-by-step explanation: Height of a triangle is a perpendicualr line linking a vertex and its opposite side.

Because triangle ABC is isosceles, point Q divides the base in 2 equal parts:

BQ = CQ = 1

Suppose QP = x

To calculate minimum value of the sum:

AP = AQ - QP

AP = 3 - x

Since triangles BQP and CQP are congruent and right triangles, use Pythagorean Theorem to figure out the value of BP and CP:

BP = CP = \(\sqrt{BQ^{2}+PQ^{2}}\)

BP = \(\sqrt{1+x^{2}}\)

Then, sum of AP, BP and CP is

\(f(x)=3-x+2\sqrt{1+x^{2}}\)

The minimum value is calculated using first derivative:

\(f'=-1+\frac{2x}{\sqrt{x^{2}+1} }\)

The value of x is limited: it can assume value of 0, when P=A and x=3, when P=Q. So, interval is [0,3].

x has value:

\(-1+\frac{2x}{\sqrt{x^{2}+1} }=0\)

\(2x=\sqrt{x^{2}+1}\)

\(4x^{2}-x^{2}-1=0\)

\(3x^{2}=1\)

x = ± \(\frac{1}{\sqrt{3} }\)

x can't assume negative value because is not in the interval:

x = \(\frac{1}{\sqrt{3} }\)

To find the minimum value of the sum, substitute x in the function above:

f(\(\frac{1}{\sqrt{3} }\))=\(3-\frac{1}{\sqrt{3} } +2\sqrt{1+(\frac{1}{\sqrt{3} })^{2} }\)

\(f(\frac{1}{\sqrt{3}} )=3-\frac{1}{\sqrt{3}}+2(\sqrt{\frac{4}{3} } )\)

\(f(\frac{1}{\sqrt{3}} )=3-\frac{1}{\sqrt{3}} +\frac{4}{\sqrt{3}}\)

\(f(\frac{1}{\sqrt{3}} )=3+\frac{3}{\sqrt{3} }\)

\(f(\frac{1}{\sqrt{3}} )=4.73\)

The minimum value of the sum of AP, BP and CP is 4.73.

The minimum value of the sum of the lengths of AP, BP and CP is \(3 + \frac{\sqrt{3}}{3}\) units.

According to this statement we must determine the sum of the line segment lengths so that a minimum is found. By Pythagorean theorem and given data we have the following expression:

\(y = AP + BP + CP\)

\(y = 3-x +2\sqrt{x^{2}+1}\) (1)

Now we proceed to find the critical values by performing first and second derivative tests.

FDT

\(-1 +\frac{2\cdot x}{\sqrt{x^{2}+1}} = 0\)

\(2\cdot x = \sqrt{x^{2}+1}\)

\(4\cdot x^{2}-x^{2}-1=0\)

\(3\cdot x^{2} = 1\)

\(x^{2} = \frac{1}{3}\)

\(x = \frac{\sqrt{3}}{3}\)

SDT

\(y'' = \frac{2\cdot \sqrt{x^{2}+1}-2\cdot x \cdot \left(\frac{2\cdot x}{\sqrt{x^{2}+1}} \right)}{x^{2}+1}\)

\(y'' = \frac{2\cdot x^{2}+2-4\cdot x^{2}}{(x^{2}+1)^{3/2}}\)

\(y'' = 2\cdot \frac{1-x^{2}}{(x^{2}+1)^{3/2}}\)

\(y'' \approx 0.866\)

A minimum exists when \(y'' > 0\), then we conclude that \(x = \frac{\sqrt{3}}{3}\) lead to a relative minimum. And by (1) we have the minimum sum:

\(y = 3-\frac{\sqrt{3}}{3}+2\sqrt{\frac{4}{3} }\)

\(y = 3 - \frac{\sqrt{3}}{3} +\frac{4\sqrt{3}}{3}\)

\(y = 3+\frac{\sqrt{3}}{3}\)

The minimum value of the sum of the lengths of AP, BP and CP is \(3 + \frac{\sqrt{3}}{3}\) units.

Nota - The statement reports typographical issues, the correct form is presented below:

The isosceles triangle below has height AQ of length 3 and base BC of length 2. A point P may be placed anywhere along the line segment AQ. What is the minimum value of the sum of the lengths of AP, BP and CP.

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The rational numbers are given as follows:

To order the rational numbers, we must convert the fractions to decimal, dividing the numerator of the fraction by the denominator.

The conversion of each number is given as follows:

Hence they are ordered as follows:

7/15, 6/10, 5/3, 25/5.

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The area of ΔEFG is approximately 916 square centimeters.

Given that,

In ΔEFG

f = 88 cm ,

g = 18 cm

∠E=68°

To find the area of ΔEFG,

Use the formula:

Area = (1/2)xfxgxsin(∠E)

First, we need to convert the angle from degrees to radians.

We can do this by multiplying by π/180.

∠E = 68° * π/180 ≈ 1.19 radians

Next, we can plug in the values we have:

Area = (1/2)x88x18xsin(1.19)

        ≈ 915.56 cm²

Rounding this to the nearest square centimeter,

we get,

Area ≈ 916 cm²

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Answer:

step-by-step in attachment

Step-by-step explanation:

Answer:i think its 0.238095

Step-by-step explanation:

i could be wrong

(a). The domain of the function C(t) based on the context of the problem  is t≥0

(b). The greatest concentration of the medication  that a patient will have in their body is 7mg/L

Graphs are used to show the relationship between variables, where the variables are represented by a pair of axes.

(a). C(t) = (-8t² +50t)/(t² + 3t +2 )

The domain of the function :

Because the medication concentration C(t) is a function of time (t), the domain is the possible values t can take.

t, cannot take negative values (i.e. it is not possible to have a negative time).

The least possible value of t is 0

So, the domain of the function based on the context is:  t≥0

(b).From the graph, the maximum y-value is 7.

Hence, the greatest concentration of the medication is 7mg/L

(a). The domain of the function C(t) based on the context of the problem  is t≥0

(b). The greatest concentration of the medication  that a patient will have in their body is 7mg/L

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Answer:

i hate math

Step-by-step explanation:

The number of cups needed is given as follows:

3.13 cups.

The number of cups needed is obtained applying the proportions in the context of the problem.

The recipe calls for 11.75 ounces of European-Style Artisan Bread Flour, while each cup of European-Style Artisan Bread Flour has a volume of 3.75 ounces, hence the number of cups needed is obtained as follows:

11.75/3.75 = 3.13 cups.

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Answer:D

Step-by-step explanation:

please mark brainliest

SOLUTION:

An alternative hypothesis would claim that there a difference between the sample and population mean claimed.

An alternate hypothesis directly contradicts the null.

Answer:

D. I centimeter

Step-by-step explanation:

Since it is only 0.128 nm wide

0.128 nm x 100,000,000 =

1.28 centi meters

Answer:

D)  1 centimeter

Step-by-step explanation:

The SI base unit for length is meters (m).

The radius of a copper atom is 128 pm.

Picometer (pm) is a unit of length equal to 1 × 10⁻¹² meters.

Therefore, the radius of a copper atom in the SI base unit for length is:

\(\implies \sf 128 \times 10^{-12} = 1.28 \times 10^{-10}\;m\)

One hundred million = 100,000,000 = 1 × 10⁸

Therefore, the length of a line of one hundred million copper atoms in meters is:

\(\implies \sf 1 \times 10^{8} \times 1.28 \times 10^{-10}\)

\(\implies \sf 1.28 \times 10^{-10} \times 10^{8}\)

\(\implies \sf 1.28 \times 10^{-10+8}\)

\(\implies \sf 1.28 \times 10^{-2}\;\;m\)

Centimeter (cm) is a unit of length equal to 1 × 10⁻² meters.

To convert meters to centimeters, divide by 1 × 10⁻²:

\(\implies \sf \dfrac{1.28 \times 10^{-2}}{1 \times 10^{-2}}=1.28\;cm\)

Therefore, a reasonable estimate for the length of one hundred million copper atoms arranged in a line is 1 centimeter.

Answer:

Hi

Step-by-step explanation:

Good bye. ;) (Stranger-Danger!) :)

Answer:

1029

Step-by-step explanation:

d=s*t

s=343m/s

t=3s

=343m/s*3s

= 1029

Answer:

it should be 20 i hope it helps but im nt 100% sure

Step-by-step explanation:

Answer:

The distance between A and A' is:

\(distance=\sqrt{20}\)

Step-by-step explanation:

Notice that point A' after the given translation becomes: (-2+4, 3+2) = (2, 5),

So one can calculate the distance between A (-2, 3) and A' (2, 5) using the distance formula:

\(distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\distance=\sqrt{(2-(-2))^2+(5-3)^2} \\distance=\sqrt{(4))^2+(2)^2} \\distance=\sqrt{(16+4} \\distance=\sqrt{20}\)

The value of y in simplest form for the point P = (1/2, y) lying on the unit circle is y = ± √(3)/2.

To find the value of y in simplest form for the point P = (1/2, y) lying on the unit circle, we can use the equation of the unit circle, which states that for any point (x, y) on the unit circle, the following equation holds: x^2 + y^2 = 1.

Plugging in the coordinates of the point P = (1/2, y), we get:

(1/2)^2 + y^2 = 1

1/4 + y^2 = 1

y^2 = 1 - 1/4

y^2 = 3/4.

To simplify y^2 = 3/4, we take the square root of both sides:y = ± √(3/4).

Now, we need to simplify √(3/4). Since 3 and 4 share a common factor of 1, we can simplify further: y = ± √(3/4) = ± √(3)/√(4) = ± √(3)/2.

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Based on the information, there are 25 cars with good brakes and good tires.

Total cars = 50

Cars with faulty brakes = 10

Cars with faulty tires = 15

Cars with faulty brakes and good tires = 2

Let's calculate the number of cars with good brakes and good tires:

Cars with faulty brakes or faulty tires = Cars with faulty brakes + Cars with faulty tires - Cars with faulty brakes and good tires

= 10 + 15 - 2

= 25

Cars with good brakes and good tires = Total cars - Cars with faulty brakes or faulty tires

= 50 - 25

= 25

Therefore, there are 25 cars with good brakes and good tires.

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The domain value that corresponds to a range value of 4 is,

⇒ x = 1/2

Given that;

Function is,

y = 4x + 2

Since, the equation equal to the range value:

4 = 4x + 2

Then, we can solve for "x":

4 - 2 = 4x

2 = 4x

x = 1/2

Now that we have the value of "x", we can find the corresponding value of "y" by substituting it into the given equation:

y = 4x + 2

y = 4(1/2) + 2

y = 4 + 2

y = 6

Therefore, the domain value that corresponds to a range value of 4 is,

⇒  x = 1/2

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Answer:

The first month is $32

The second month is $64

The third month is $96

The fourth month is $128

Step-by-step explanation:

32 plus 32 is 64 and 32 plus 64 is 96 so on

The domain restrictions for (f/g)(x) are (c) x = 0, 6

From the question, we have the following parameters that can be used in our computation:

f(x) = x² - 5x - 6

g(x) = x² - 6x

The composite function (f/g)(x) is calculated as

(f/g)(x) = f(x)/g(x)

substitute the known values in the above equation, so, we have the following representation

(f/g)(x) = (x² - 5x - 6 )/(x² - 6x)

For the domain restriction, we have

x² - 6x = 0

When solved, we have

x =  6 or x = 0

Hence, the domain restrictions for (f/g)(x) are (c) x = 0, 6

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Question

Given f(x) = x² - 5x - 6 and g(x) = x² - 6x, what are the domain restrictions

for (f/g)(x)?

A) x = +6

B) x = 0

C) x = 0,6

D) x = -2,6

Answer:

D. - 2x - 8

Step-by-step explanation:

Given

-1 /3 ( 6x + 15 ) - 3

= - 1/3 * 6x + ( - 1/3 * 15) - 3

= - 2x - 5 - 3

= - 2x - 8

Hope it will help :)

Answer:

The probability of the plants being tall is equal to P(TT) + P(Tt)= 1/4+1/2=3/4

Step-by-step explanation:

Hello!

The characteristic "height" of a plant is determined by the alleles "tall" T (dominant) and "short" a (recessive). If both parents are Tt, you have to calculate the probability of the offspring being tall (TT or Tt)

To construct the Punnet square you have to make a table, where the parental alleles will be in the margins, for example: the father's alleles in the columns and the mother's alleles in the rows.

Each parent will produce a haploid gamete that will carry one of the alleles, so the probability for the offspring receiving one of the alleles is 1/2

Father (Tt): gametes will carry either the dominant allele T or the recessive allele t with equal probability 1/2

Mother (Tt): gametes will also carry either the dominant allele T or the recessive allele t with equal probability 1/2

Then you have to cross each allele to determine all possible outcomes for the offsprings. For each cell, the probability of obtaining both alleles will be the product of the probability of each allele (See attachment)

First combination, the offspring will receive one dominant allele from his father and one dominant allele from his mother: TT, the probability of obtaining an offspring with this genotype will be P(T) * P(T) = 1/2*1/2=1/4

Second combination, the offspring will receive the recessive allele from the father and the dominant allele from the mother, then its genotype till be tT with probability: P(t)*P(T)= 1/2*1/2=1/4

Third combination, the offspring will receive one dominant allele from his father and one recessive allele from his mother, the resulting genotype will be Tt with probability: P(T)*P(t)= 1/2*1/2=1/4

Combination, the offspring will receive both recessive alleles from his parents, the resulting genotype will be tt with probability: P(t)*P(t)= 1/2*1/2=1/4

So there are three possible genotypes for the next generation:

TT with probability P(TT)= 1/4

Tt with probability: P(Tt)+P(tT)=1/4+1/4=1/2⇒ This genotype is observed twice so you have to add them.

tt with probability P(tt)= 1/4

Assuming this genotype shows complete dominance, you'll observe the characteristic "Tall" in individuals that carry the dominant allele "T", i.e. individuals with genotype "TT" and "Tt"

So the probability of the plants being tall is equal to P(TT) + P(Tt)= 1/4+1/2=3/4

I hope this helps!

Answer:

what is the length we are talking about i need a little more info

Step-by-step explanation: