closest value of 19.7dived 0.0485

Answer:

A. is the answer

Sorry if i'm wrong

The answer to the questions on instrument are:

True

True

True

True

False

True

True: A survey timeline typically includes various dates related to the survey administration, such as the start and end dates for participant recruitment, the date for activation of the measurement instrument, and the deadline for completing the survey. The date for activation of the measurement instrument refers to the date on which the survey respondents can begin answering the questions.

True: Instrument disposition refers to the process of distributing and collecting the measurement instruments. This can involve various methods, such as mailing the instruments to the participants or delivering them to a dropbox for paper-and-pencil instruments.

True: Participant data entry can increase the accuracy of a data record because it eliminates the need for manual data entry, which can introduce errors. With participant data entry, the participants themselves enter their responses directly into a computer or mobile device, ensuring that the data is accurate and complete.

True: A significant number of "Don’t Know" responses to a closed measurement question may indicate that the measurement instrument failed to provide appropriate response categories. If the survey respondents are unsure about how to answer a question and there is no appropriate response option available, they may select "Don’t Know" instead.

False: Cross-tabulation in CFA (Confirmatory Factor Analysis) is typically used to examine the relationship between two or more variables, and it is not called a contingency table. A contingency table is a table used to display the frequencies and/or percentages of two or more categorical variables.

True: Percentages are a way of expressing data in relation to a base of 100, making it easier to compare variables. For example, if 80 out of 100 respondents answered "Yes" to a question, we can say that the percentage of respondents who answered "Yes" is 80%. This allows us to compare the percentage of "Yes" responses to other questions or variables in the survey.

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The image of the polygon after a reflection in the line y = -x  is attached below.

It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

It  is given that the coordinate of the polygon is A=(-3,2), B=(1,-1) , C=(-2,-2) and D=(-4,-1)​

The y-coordinate of a point that is reflected across the y-axis stays constant, but the x-coordinate is assumed to be the additive inverse. Point (x, y) is reflected across the y-axis, and the result is

Thus, the image of the polygon after a reflection in the line y = -x  is attached below.

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Answer:

312 mi/hr

Step-by-step explanation:

Distance = 2184 miles

Time taken = 7 hours

Average speed = Distance / time taken

Average speed = 2184 miles / 7 hours

Average speed = 312 miles per hour

Hence, the average speed Traveled by the plane traveling from Knoxville to Los Angeles is 312 miles per hour

a.  The probability is approximately \(0.1847\).

b. The probability of exactly 2 times falling between 1 and 5 seconds is approximately \(0.3038\).

(a) To find the probability that between 1 and 5 seconds elapse between emits, we can use the Poisson distribution. Given a mean rate of 3 emits per second, the parameter \($\lambda$\) for the Poisson distribution is also 3.

Let \($X$\) be the random variable representing the waiting time between emits. We want to find \($P(1 \leq X \leq 5)$\).

Using the Poisson distribution formula, we can calculate this probability:

\($P(1 \leq X \leq 5) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$\)

\(P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}\)

Substituting \($\lambda = 3$ and $k = 1, 2, 3, 4, 5$\), we have:

\($P(1 \leq X \leq 5) = \frac{e^{-3} 3^1}{1!} + \frac{e^{-3} 3^2}{2!} + \frac{e^{-3} 3^3}{3!} + \frac{e^{-3} 3^4}{4!} + \frac{e^{-3} 3^5}{5!}$\)

Calculating this expression, we find that the probability is approximately \(0.1847\).

(b) When selecting 10 times between emissions randomly, the number of times falling between 1 and 5 seconds follows a binomial distribution. The probability of exactly 2 times falling in this range can be calculated using the binomial distribution formula:

\($P(X = 2) = \binom{10}{2} \cdot (P(1 \leq X \leq 5))^2 \cdot (1 - P(1 \leq X \leq 5))^{(10 - 2)}$\)

Substituting the probability from part (a), we have:

\($P(X = 2) = \binom{10}{2} \cdot (0.1847)^2 \cdot (1 - 0.1847)^{(10 - 2)}$\)

Calculating this expression, we find that the probability of exactly 2 times falling between 1 and 5 seconds is approximately 0.3038.

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As per the given statement a.) The probability that between 1 and 5 seconds elapse between emits is 5.26%. b.) The probability that exactly 2 of the emissions are between 1 and 5 seconds is 27.05%.

a. To find the probability that between 1 and 5 seconds elapse between emits in a Poisson process with a mean rate of 3 per second, we can use the exponential distribution.

The exponential distribution is characterized by the parameter lambda \((\(\lambda\))\), which is equal to the mean rate of the process. In this case, \(\(\lambda = 3\).\) The probability density function (PDF) of the exponential distribution is given by:

\(\[ f(t) = \lambda e^{-\lambda t} \]\)

To find the probability that between 1 and 5 seconds elapse between emits, we need to calculate the integral of the PDF from 1 to 5 seconds:

\(\[ P(1 \leq t \leq 5) = \int_{1}^{5} \lambda e^{-\lambda t} dt \]\)

Integrating the PDF, we have:

\(\[ P(1 \leq t \leq 5) = \left[ -e^{-\lambda t} \right]_{1}^{5} \]\)

\(\[ P(1 \leq t \leq 5) = -e^{-3 \cdot 5} - (-e^{-3 \cdot 1}) \]\)

\(\[ P(1 \leq t \leq 5) = -e^{-15} + e^{-3} \]\)

\(\[ P(1 \leq t \leq 5) \approx 0.0526 \]\)

Therefore, the probability that between 1 and 5 seconds elapse between emits is approximately 0.0526, or 5.26%.

b. If we randomly select 10 times between emissions, and we assume they are independent, we can model the situation as a binomial distribution.

The probability of having exactly 2 times between emissions between 1 and 5 seconds can be calculated using the binomial probability formula:

\(\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]\)

where \(\( n \)\) is the number of trials (10), \(\( k \)\) is the number of successful trials (2), and \(\( p \)\) is the probability of success (probability that between 1 and 5 seconds elapse between emits).

From part a, we know that \(\( P(1 \leq t \leq 5) \approx 0.0526 \).\)

Plugging in these values into the formula:

\(\[ P(X = 2) = \binom{10}{2} (0.0526)^2 (1 - 0.0526)^{10 - 2} \]\)

\(\[ P(X = 2) = 45 \cdot (0.0526)^2 \cdot (0.9474)^8 \]\)

\(\[ P(X = 2) \approx 0.2705 \]\)

Therefore, the probability that exactly 2 of the times between emissions are between 1 and 5 seconds is approximately 0.2705, or 27.05%.

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The phase diagrams provide a visual representation of the system's behavior by plotting the vector field and trajectories in the x-y plane.

The given system of differential equations is described by:

\(˙x = a - x^2˙y = x - y\)

To find the equilibria, we set ˙x and ˙y equal to zero:

\(a - x^2 = 0 -- > x^2 = a -- > x = ±√ax - y = 0 -- > y = x\)

So, the equilibria are (±√a, ±√a).

Now let's analyze the behavior of the system for different values of 'a'.

For a > 0:

In this case, there are two real equilibria, (√a, √a) and (-√a, -√a). We can observe that (√a, √a) is a stable node, as the eigenvalues of the linearized system around this point have negative real parts. On the other hand, (-√a, -√a) is a saddle point, as the eigenvalues have opposite signs (one positive and one negative).

For a < 0:

In this case, there are no real equilibria since √a and -√a are imaginary. Therefore, the system has no equilibrium points.

To visualize the phase diagrams for a = 1 and a = -1:

For a = 1:

The system has two real equilibria, (1, 1) and (-1, -1). The point (1, 1) is a stable node, and (-1, -1) is a saddle point. The phase diagram would show trajectories converging towards (1, 1).

For a = -1:

Since a < 0, there are no equilibrium points, and thus the phase diagram would show no fixed points or trajectories.

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Answer:

Goku died you I just started watching

Answer:

X = -5/2

Step-by-step explanation:

Step-by-step explanation:

\(9x + 4 = 5x - 6\)

Collect like terms and simplify

\(9x - 5x = - 6 - 4 \\ 4x = - 10\)

Divide both sides of the equation by 4

\( \frac{4x}{4} = \frac{ - 10}{4} \)

Simplify

\(x = - \frac{5}{2} \)

Answer:

16 square units

Step-by-step explanation:

Hopefully this helps :)

The union of events A and B is the event containing: c. all the sample points belonging to A or B or both. The union of events reflects all possible outcomes for two events.

The correct option is (c)

In statistics, an event is also referred to as an outcome. For example, getting a head on a coin flip is an event. Getting a tail is also event. Viewed collectively, they are complementary events (meaning, one cannot occur if the other does, and their probabilities sum to 1.0).

Union of events: The union of events A and B, denoted by A ∪ B, consists of all outcomes that are in A or in B or in both A and B.

The correct option is (c).

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Answer:

It will take you 1/2 hour to catch up.

Step-by-step explanation:

We Know

You are biking at a speed of 18 miles per hour.

You are 3 miles behind your friend, who is biking at a speed of 12 miles per hour.

The equation will be:

18h = 12h + 3

Find the amount of time it takes for you to catch up.

18h = 12h + 3

6h = 3

h = 3/6 = 1/2 hour

So, it will take you 1/2 hour to catch up.

False, r2adj is the adjusted coefficient of determination that can exceed r2 if there are several weak predictors.

R2adj is the adjusted coefficient of determination and takes into account the number of predictors in the model. It penalizes the addition of insignificant predictors that do not improve the model fit.

R2, on the other hand, is the coefficient of determination and measures the proportion of variability in the dependent variable that is explained by the independent variables in the model.

It is possible for R2 to increase when weak predictors are added, but this increase is not necessarily mean that the predictors do not have a significant impact on the outcome.

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The question is -

R2adj can exceed R2 if there are several weak predictors. true or false?

Answer:

51

Step-by-step explanation:

4% as a decimal is 0.04, so you can just do 0.04 * 1275 = 51.

Answer:

-51

Step-by-step explanation:

ree

Answer:

x+3x=2+2

4x=4

x=1

Answer:

x = 1

Step-by-step explanation:

x - 2 = -3x + 2

you can do any one of these 4 steps first and still get the same answer:

a) subtract x from each side

b) add 2 to each side

c) add 3x to each side

d) subtract 2 from each side

after doing one of the above you will have a two-step equation and must undo addition or subtraction before undoing multiplication or division

The graph that shows a proportional relationship that passes through the point (2, 1) is Graph A.

A line is defined as a shortest distance between two points. In order to determine the graph that shows a proportional relationship that passes through the point (2, 1), we will need to multiply the coordinate by a scale factor and determine whether the point is on the line.

Using a factor of 2;

New coordinate = 2(2, 1)

New coordinate = (4, 2)

From the given graph, you can see that the only graph that has the coordinate point (4, 2) is the Graph A.

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Answer:

7x + 13

Step-by-step explanation:

because the correct answer is 7x+13

Answer:

-4.66667 (the 6. is repeating)

Answer:

Which statement can be used to justify the fact that to write angles are suppleMentry select two opinions== 3 and 6

John's statement in Part A is correct, as the product of two real numbers is indeed a real number. Sam's statement in Part B is incorrect, as multiplying a complex number by its conjugate does result in a real number.

Part A: John's statement that the product of two real numbers is a real number is correct. When multiplying two real numbers, the result is always another real number. However, his extension to imaginary numbers is incorrect. Imaginary numbers are of the form ai, where a is a real number and i is the imaginary unit (√-1). When multiplying two imaginary numbers, the result can be a real number if the coefficients of the imaginary unit cancel out. For example, (2i) * (-2i) = -4, which is a real number.

Part B: Sam's statement that when multiplying a complex number by its conjugate, the solution will not be a real number is incorrect. A complex number is of the form a + bi, where a and b are real numbers and i is the imaginary unit. The conjugate of a complex number a + bi is a - bi. When multiplying a complex number by its conjugate, the result is always a real number. The imaginary components cancel out, leaving only the real components squared. For example, (3 + 2i) * (3 - 2i) = 9 - 4i^2 = 9 + 4 = 13, which is a real number.

In Part C, John recognized a mistake in Debbie's solution based on his knowledge of complex numbers. Without specific details about Debbie's solution, it is not possible to provide further analysis or explanation.

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Answer:

A. -0.875

Step-by-step explanation:

Find where the points are located

A=-4.25

B=2.5

Add the points

-4.25+2.5=-1.75

-1.75/2=-0.875

4π/5 and -16π/5 are Coterminal angles with -6π/5

an angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle

Coterminal angles are angles that share the same initial and terminal sides. To find an angle coterminal to another you can do so by simply adding or subtracting any multiple of 360 degrees or 2 pi radians.

The given angle is -6π/5

We need to add 2π for finding coterminal angle

-6π/5+2π

4π/5

We need to subtract 2π for finding coterminal angle

-6π/5-2π

-6π-10π/5

-16π/5

Hence 4π/5 and -16π/5 are Coterminal angles with -6π/5

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Answer:

It's incorrect because the equation is solve incorrectly the anwer is r= -4

Step-by-step explanation:

Add 4r4r to both sides.

-3r+9+4r=5

−3r+9+4r=5

2 Simplify  -3r+9+4r−3r+9+4r  to  r+9r+9.

r+9=5

r+9=5

3 Subtract 99 from both sides.

r=5-9

r=5−9

4 Simplify  5-95−9  to  -4−4.

r=-4

r=−4

Answer:

A. 96

C. 48

D. 24

Step-by-step explanation:

Multiples of 8

8 = 8, 16, 24, 32, 40, 48, 56, and 64, 72, 80, 88, 96, 104,.......

Multiples of 12

12 = 12, 24, 36, 48, 60, 72, 84, 96, 108,........

Common multiples of 8 and 12 = 24, 48, 72 and 96

The correct answers are:

A. 96

C. 48

D. 24

Answer:

Step-by-step explanation:

(2-4x)+(2-4x)+(-2x+8)=12-10x

The integrate is W = 12 ∫[0 to 1] (1 + 3t)^(3/2) dt + 27 ∫[0 to 1] (1 + 2t) √(1 + 3t) dt.

To find the work done by the force field F in moving an object from point A to point B, we can use the line integral of the force field along the path connecting A and B. The line integral is given by the formula:

W = ∫[C] F · dr

where C represents the curve connecting points A and B, F is the force field, dr is the differential displacement vector along the curve, and · denotes the dot product.

First, let's calculate the differential displacement vector dr. Since we are moving from point A(1, 1) to point B(3, 4), the differential displacement vector dr can be expressed as:

dr = dx i + dy j

Now, let's determine the curve C connecting A and B. The curve can be parametrized as follows:

x(t) = 1 + 2t

y(t) = 1 + 3t

where t varies from 0 to 1.

Differentiating these parametric equations, we obtain:

dx = 2 dt

dy = 3 dt

Substituting these values into the differential displacement vector dr, we have:

dr = 2 dt i + 3 dt j

Next, let's calculate the force field F at each point along the curve C. Given that F(x, y) = 6y^(3/2) i + 9x √y j, we can substitute the parametric equations for x and y into F:

F = 6(1 + 3t)^(3/2) i + 9(1 + 2t) √(1 + 3t) j

Now, let's evaluate the line integral by substituting the values of F and dr into the integral expression:

W = ∫[0 to 1] (6(1 + 3t)^(3/2) i + 9(1 + 2t) √(1 + 3t) j) · (2 dt i + 3 dt j)

Expanding the dot product, we have:

W = ∫[0 to 1] (12(1 + 3t)^(3/2) dt + 27(1 + 2t) √(1 + 3t) dt)

Now, we can simplify and integrate each term separately:

W = 12 ∫[0 to 1] (1 + 3t)^(3/2) dt + 27 ∫[0 to 1] (1 + 2t) √(1 + 3t) dt

To evaluate these integrals, we can use appropriate substitution or integration techniques. After integrating both terms, we will have the value of the work done by the force field F in moving the object from A to B along the curve C.

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Answer:

add otherwise I don't know sorry im on that question

Step-by-step explanation:

The 45th term of the sequence is 267.

The 45th term of a sequence can be calculated using the formula:

Tn = a + (n – 1)d

Where,

Tn = the nth term

a = the first term

n = the term position

d = the common difference

In this sequence, the first term is 3, the common difference is 6, and the term position is 45.

Therefore, the 45th term of the sequence is:

T45 = 3 + (45 – 1)6

T45 = 3 + (44)6

T45 = 3 + 264

T45 = 267

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9514 1404 393

Answer:

  $0.045 / g

Step-by-step explanation:

To find dollars per gram, divide dollars by grams:

  $8.99 / (200 g) = $0.04495 / g ≈ $0.045 / g

Answer:

a = -88

Step-by-step explanation:

50−  a/ 11  =58

50 + -1/11 x a = 58

-1/11 x a + 50 = 58

Subtract 50 from both sides

-1/11 x a - 50 (-50) = 58 (-50)

Now multiply both sides by 11/-1

(11/-1) x (-1/11 x a) = (11/-1) x 8

a = -88