Comment on energy conservation in this diagram.

Comment On Energy Conservation In This Diagram.

Answers

Answer 1

Energy conservation refers to the principle that energy cannot be created or destroyed; it can only be converted from one form to another or transferred between different systems.

This principle is based on the law of conservation of energy, also known as the first law of thermodynamics. In order to comment on energy conservation in a diagram.

Energy conservation refers to the practice of reducing energy consumption and using energy resources efficiently in order to minimize waste and environmental impact. It involves making conscious choices and adopting behaviors and technologies that aim to conserve energy and reduce energy-related costs.

Energy conservation is an important aspect of sustainable development and plays a vital role in mitigating climate change and promoting environmental sustainability.

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Related Questions

Scientists seek to acquire knowledge and understanding of the real world through the formulation, testing, and evaluation of what?
A) scientific hypothesis
B)technology
C)deductive reasoning
D) scientific method

A scale measures the weight of a light object to be 11.000lbs +- 0.034 lbs. What is the uncertainty if this same scale is used to measure an object that weighs 78.000 lbs? Assume that the percent uncertainty of the scale remains constant.
A)0.034 lbs
B)0.044 lbs
C)0.240 lbs
D)0.310 lbs

Answers

Answer:  1)Scientists seek to acquire: scientific hypothesis

2)A scale measures the weight of a light object: 0.240 lbs

3)What does the process of scientific inquiry: It starts with a problem to solve or a question to answer

4)A mouse in a maze scurries 41 cm south: 76 cm southwest

5)When might an object's average velocity be equal to its average speed in two dimensions:

If the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.

6)Using the velocity versus time graph, calculate the acceleration of Object A: 3 m/s^2

7)What is the range of a bullet fired horizontally at a height of 1.5m: 66.4m

8)What two vertical forces act on a falling leaf: weight, friction

9)What is equal and opposite to the applied force: spring force

10)Using the free-body diagram, calculate the net force: 12N, right

11)How does the force of impact during a collision change: it increases

12)The threads of a screw used to fasten two pieces of wood: by increasing the normal force exerted by the wood on the screw thread

13)A 60 kg skier with an initial velocity of 12 m/s coasts up a hill: 2.5m

14)A 1,500 kg car’s speed changes from 30 m/s to 15 m/s: -506,250 (negative 506,250| NOT POSITIVE)

15)What is true about weather: The weather depends on so many conditions that it is not possible to account for them all in any model.

16)A student records the mass of objects A, B, C, and D:  A

17)Newton’s cradle is a contraption where metal balls: friction force

18)In a closed system, an object with a mass of 10 kg: 12kgm/s

19)Given the data, what is the kinetic energy of the: 3J

20)A wedge is a simple machine that is essentially two: A length of 12 in. and a thickness of 2 in.

21)Object A and Object B are at equal distances on opposite: 3/4

22)A geosynchronous satellite has an orbital period of 24: 35,900 km

23)Calculate the eccentricity for the planet if the: 0.0167

24)A planet travels in its orbit close to apogee : the same amount of time

25)If astronomers discovered a new planet and found its: 22.3 AU

Explanation:

Hope this helps you guys!!! <3 (this is for 'A Semester Exam')

If an ice skater pulls their hands towards their body, will their angular momentum and kinetic energy both increase?

Answers

Answer:

The angular momentum depends on both the angular velocity and the mass distribution of the object. You can change this angular momentum by exerting a torque (a twisting force)—but with no external torque, the angular momentum is conserved. Now getting back to the ice skater.

If an ice skater pulls their hands towards their body, will their angular momentum and kinetic energy

An 5kg object is released from rest near the surface of a planet. The vertical position of the object as a function of time is shown in the graph. All frictional forces are considered to be negligible. What is the closest approximation of the weight of the object.
a) 300N
b) 30N
c) 5N
d) 150N

An 5kg object is released from rest near the surface of a planet. The vertical position of the object

Answers

Answer:

The correct option is b: 30 N.

Explanation:

First, we need to find the acceleration due to gravity (a):

\( y_{f} - y_{0} = v_{o}t - \frac{1}{2}a(\Delta t)^{2} \)   (1)

Where:

\(y_{f}\): is the final vertical position (obtained from the graph)

\(y_{0}\): is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → \(t_{f}\) = 5 s

y₀ = 300 m → \(y_{f}\) = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

\( a = 2\frac{y_{0} - y_{f}}{(t_{f} - t_{0})^{2}} = 2\frac{300 m - 225 m}{(5 s - 0)^{2}} = 6 m/s^{2} \)

Finally, the weight of the object is:

\( W = ma = 5 kg*6 m/s^{2} = 30 N \)

Therefore, the correct option is b: 30 N.

I hope it helps you!                                                                                                            

If the gravitational force produced between two masses kept 2 m apart is 100 N, what will be its value when the masses are kept 4m apart? Show your calculation.) Ans: 25 N​

Answers

When the masses are kept 4 m apart, the gravitational force between them will be 25 N.

How to find the force

The gravitational force between two masses can be expressed as

F1 = k / r1^2

where

F1 is the force at distance r1, k is the gravitational constant, and r1 is the initial distance.

In this case, we have:

F1 = 100 N (the force at distance 2 m)

r1 = 2 m (the initial distance)

To find the force at a different distance, let's say r2 = 4 m, we can use the inverse square law and solve for F2:

F2 = k / r2^2

We can set up a ratio using the formula:

F1 / F2 = (k / r1^2) / (k / r2^2)

Simplifying the equation:

F1 / F2 = (r2 / r1)^2

Substituting the given values:

100 N / F2 = (4 m / 2 m)^2

100 N / F2 = 2^2

100 N / F2 = 4

to find F2, we can rearrange the equation:

F2 = 100 N / 4

F2 = 25 N

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How long does it take the sound of thunder to reach us, assuming that the speed of sound remains at 343 ms?

Answers

To calculate the time it takes for the sound of thunder to reach us, we need to know the distance between us and the location where the thunder originated. Let's assume this distance is 'd.'

The speed of sound remains constant at approximately 343 meters per second (m/s).

Therefore, the time it takes for the sound of thunder to reach us can be calculated using the formula:

Time = Distance / Speed

If we substitute the values, the equation becomes:

Time = d / 343 m/s

Without the distance value, we cannot determine the exact time it takes for the sound of thunder to reach us.

As a prank, your friends have kidnapped you in your sleep, and transported you out onto the ice covering a local pond. Since you're an engineer, the first thing you do when you wake up is drill a small hole in the ice and estimate the ice to be 6.7cm thick and the distance to the closest shore to be 30.5 m. The ice is so slippery (i.e. frictionless) that you cannot seem to get yourself moving. You realize that you can use Newton's third law to your advantage, and choose to throw the heaviest thing you have, one boot, in order to get yourself moving. Take your weight to be 588 N. (Lucky for you that, as an engineer, you sleep with your knife in your pocket and your boots on.)
1)(a) What direction should you throw your boot so that you will most quickly reach the shore? away from the closest shore perpendicular to the closest shore straight up in the air at your friend standing on the closest shore
2)(b) If you throw your 1.08-kg boot with an average force of 391 N, and the throw takes 0.576 s (the time interval over which you apply the force), what is the magnitude of the force that the boot exerts on you? (Assume constant acceleration.)
391 N
3)(c) How long does it take you to reach shore, including the short time in which you were throwing the boot?

Just number 3

Answers

Answer:

1a) The direction to throw the boot is directly away from the closest shore.

2b) The magnitude of the force that the thrown boot exerts on the engineer = 391 N

3c) Time taken to reach shore = 8.414 s

Explanation:

1a) Newton's third law of motion explains that for every action, there is an equal and opposite reaction.

The force generated by throwing the boot in one direction is exerted back on the engineer as recoil in the opposite direction.

Hence, the best direction to throw the boot is opposite the direction that the engineer intends to move towards.

2b) Just as explained in (1a) above, the force exerted in one direction always has a reaction of the same magnitude in the opposite direction.

Hence, the force exerted by the boot on the engineer is equal to the force exerted by the engineer on the boot = 391 N.

3c) For this part, we analyze the total motion of the engineer.

The force exerted by the boot on the engineer initially accelerates the engineer until the engineer reaches a constant velocity dictated the impulse of the initial force (since impulse is equal to change in momentum), this constant velocity then takes the engineer all the way to shore, since the ice surface is frictionless.

The weight of the engineer = W = 588 N

W = mg

Mass of the engineer = (W/g) = (588/9.8) = 60 kg

Force exerted on the engineer by the thrown boot = F = 391 N

F = ma

Initial acceleration of the engineer = (F/m) = (391/60) = 6.52 m/s²

We can then calculate the distance covered during this acceleration

X₁ = ut + ½at₁²

u = initial velocity of the engineer = 0 m/s (the engineer was initially at rest)

t₁ = time during which the force acts = 0.576 s

a = acceleration during this period = 6.52 m/s²

X₁ = 0 + 0.5×6.52×0.576² = 1.08 m

For the second part of the engineer's motion, the velocity becomes constant.

So, we first calculate this constant velocity

Impulse = Change in momentum

F×t = mv - mu

F = Force causing motion = 391 N

t = time during which the force acts = 0.576 s

m = mass of the engineer = 60 kg

v = final constant velocity of the engineer = ?

u = initial velocity of the engineer = 0 m/s

391 × 0.576 = 60v

v = (391×0.576/60) = 3.7536 m/s.

The distance from the engineer's initial position to shore is given as 30.5 m

The engineer covers 1.08 m during the time the force causing motion was acting.

The remaining distance = X₂ = 30.5 - 1.08 = 29.42 m

We can then calculate the time taken to cover the remaining distance, 29.42 m at constant velocity of 3.7536 m/s

X₂ = vt₂

t₂ = (X₂/v) = (29.42/3.7536) = 7.838 s

Time taken to reach shore = t₁ + t₂ = 0.576 + 7.838 = 8.414 s

Hope this Helps!!!

In the photoelectric effect, light striking the surface of a conductor ejects electrons from the conductor. If we shine light on the anode of a capacitor which has some voltage applied across it, the ejected electrons will be accelerated towards the cathode, and we establish a photocurrent. Using this principle, you would like to build a laser tripwire.
You put a lightbulb (with resistance 10 ), capacitor, and DC voltage source E = 9 V in series, and point a ruby laser of wavelength 694 nm (red light) and intensity I = 1 W/m² at the anode of the capacitor. The anode has workfunction =1.3 eV. Your idea is that as long as the laser is actively shining on the anode, the light bulb will light; if an object obstructs the laser, the light bulb will turn off, and you will notice the light flicker.
A. With the given parameters, with the laser shining on the anode, will current flow in your circuit?
B. One potential problem with your tripwire is that the laser is in the visible spectrum, and a potential burgler might see and avoid it. Will current still flow if you replace the ruby laser with an argon laser, with wavelength 1090 nm (infrared), and double the intensity to 2 W/m? Why or why not?

Answers

Answer:

a) Ф = 1.79 eV  here are a number of electrons expelled from the metal and these electrons are accelerated by the difference in potential and you can establish a curren

b)  E = 1.14 eV     the energy of the photons is less than the work function of the metal, so there are no ejected electrons and there can be no current

Explanation:

a) This is a problem about the photoelectric effect, for the current to flow there must be ejected electrons so that they can be accelerated, this effect was explained by Insistent using

            h f = K - Ф

where hf is the energy of the incident photons, Ф the metal work function and K the kinetic energy of the ejected electrons, the minimum value that it can have is zero

           Ф = h f

let's use the relationship

           c = λ f

           f = c / λ

we substitute

          Ф = h c / λ

let's calculate

          Ф = 6.63 10⁻³⁴ 3 10⁸/694 10⁻⁹

          Ф = 2.87 10⁻¹⁹ J

let's reduce this value to units of eV

         Ф = 2.87 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

         Ф = 1.79 eV

This is the maximum value that the work function can have for the electrons to be expelled, as they indicate that the work function of the anode is 1.3 eV there are a number of electrons expelled from the metal and these electrons are accelerated by the difference in potential and you can establish a current

B) The laser is changed for another λ = 1090 nm = 1090 10⁻⁹ m

Let's find the energy of the laser photons

         E = h c /λ

         E = 6.63 10⁻³⁴ 3 10⁸/1090 10⁻⁹

         E = 1.82 10⁻¹⁹ J

we reduce to eV

         E = 1.82 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

         E = 1.14 eV

In this case, the energy of the photons is less than the work function of the metal, so there are no ejected electrons and there can be no current

SECTION IV
QUESTION: 2. On the football field, a 95-kg halfback makes a turn. The halfback
sweeps out a path that is a portion of a 12-meter-radius circle. If in 2.1 seconds, the
halfback completes a quarter-circle turn. Determine the halfback's speed and
acceleration.

Pls solve this

Answers

Answer:

Speed = (2πr)/t = (2π x 12 m)/2.1 s = 28.6 m/s

Acceleration = (vf-vi)/t = (28.6 m/s - 0 m/s)/2.1 s = 13.6 m/s^2

A. Obtain the following: microwave, ruler, something meltable (e.g. candy bar, marshmallows) B. A microwave works by setting up a standing electromagnetic wave inside of a box made of conducting materials. What is the value of an electric field inside a conductor

Answers

Answer:

E = 124.7 N / C

Explanation:

Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.

The electric field of the standing wave is

            I = E²

            E =√I

where I is the intensity of the radiation.

What is it

             I = P / A

where P is the effective emission power, almost all the power of the microwave and A is the area of ​​the cavity, in the most used microwaves

P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²

             I = 700 / 0.045

             I = 15555.56 W/m²

let's calculate the electric field

            E = √15555.56

            E = 124.7 N / C

Postural deviations can result in​

Answers

Answer:

Postural deviations can cause poor balance, muscle pain and skeletal stress.

Explanation:

The mass percent of hydrogen in CH₄O is 12.5%.

What is the mass percent?

Mass percent is the mass of the element divided by the mass of the compound or solute.

Step 1: Calculate the mass of the compound.

mCH₄O = 1 mC + 4 mH + 1 mO = 1 (12.01 amu) + 4 (1.00 amu) + 1 (16.00 amu) = 32.01 amu

Step 2: Calculate the mass of hydrogen in the compound.

mH in mCH₄O = 4 mH = 4 (1.00 amu) = 4.00 amu

Step 3: Calculate the mass percent of hydrogen in the compound.

%H = (mH in mCH₄O / mCH₄O) × 100%

%H = 4.00 amu / 32.01 amu × 100% = 12.5%

The mass percent of hydrogen in CH₄O is 12.5%.

CO2 = 1.580 grams H2O = 0.592 grams Lookup the molar mass of each element in the compound Carbon = 12.0107 Hydrogen = 1.00794 Oxygen = 15.999 Calculate the molar mass of CH4O by adding the total masses of each element used. 12.0107 + 4 * 1.00794 + 15.999 = 32.04146 Now calculate how many moles of CH4O you have by dividing by the molar mass. m = 1.15 g / 32.04146 g/mole = 0.035891 mole Now figure out how many moles of carbon and hydrogen you have. Carbon = 0.035891 moles Hydrogen = 0.035891 moles *

Therefore, The mass percent of hydrogen in CH₄O is 12.5%.

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This circuit has more than one loop. When one light goes out, the
others stay on.
A.open circuit
B.series circuit
C.parallel circuit
D.closed circuit

Answers

Answer:

Parallel circuit

Explanation:

A parallel circuit has a direct current allowing it to go back and forth making it have more pathways and loops. if one light bulb goes out the pathways will allow the electricity to still flow inti the other light bulbs.

A basketball has a circumference of .203 m.what is the radius of a baseball?

Answers

Given that the circumference of the basketball is C = 0.203 m.

We have to find the radius of basketball, r.

The radius can be calculated as

\(\begin{gathered} C=2\pi r \\ r=\frac{C}{2\pi} \\ =\frac{0.203}{2\times3.14} \\ =0.032\text{ m} \end{gathered}\)

Thus, the radius of the basketball is 0.032 m

5.
An 80 newton force and a 45 newton force act on an object
as shown below.
80 N
30°
4S N
Which of the following vectors would bets represent an
equilibrant when added to this system?
(1) 24 N to the left (3) 24 N to the right
(2) 114 N to the right (4) 45 N to the left
Tirant Showroiculations

Answers

Answer:

the answer is a time your welcome

Answer:

(1)

Explanation:

The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?

Answers

The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?

Answers

The traffic cop needs 23.3 seconds to pass the automobile.

What is the acceleration of a car moving in a straight line at a constant speed?

When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.

\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)

\(d = d1 = 35.0 m\)

\(d2 = v2*t + (1/2)at^2\)

\(d2 = (1/2)at^2\)

\(v2*t + (1/2)at^2 = (1/2)at^2\)

\(v2*t = (1/2)at^2\)

Solving for t, we get:

\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)

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How long does it take a ball to fall 75.0m? (g = -9.81 m/s²)
O 15.3 m/s²
O 3.91 s
O 15.3 s
O 3.90 m/s²

Answers

Answer:

3.91 s

Explanation:

d = -75

a = -9.81

d = 1/2 at^2

-75 = 1/2 ( -9.81) (t^2)

75 = 1/2 ( 9.81) t^2            shows t = 3.91 s

Can someone please help me

Can someone please help me

Answers

With the application of resolution of vector, the net force is 197 N and the direction is 59 degree.

Resolution of Forces

Resolution of forces can simply be solved by resolving to horizontal and vertical component.

In the given figure, we will resolve the forces into horizontal and vertical components.

Horizontal component

Fh = 80 cos 80 + 60 cos 30 + 70 cos 60

Fh = 13.89 + 51.96 + 35

Fh = 100.85 N

Vertical Component

Fv = 80 sin 80 + 60 sin 30 - 70 sin 60

Fv = 78.78 + 30 + 60.62

Fv = 169.4 N

Resultant force = √( Fh² + Fv²)

Resultant force = √(100.85² + 169.4²)

Resultant force = √(10170.7 + 28696.4)

Resultant force = √38867.06

Resultant force = 197.15 N

The direction will be

Tan Ф = Fv/Fh

Tan Ф = 169.4 / 100.85

Tan Ф = 1.68

Ф = \(tan^{-1}\)(1.68)

Ф = 59.23

Therefore, the magnitude of resultant force is 197.15 N and the direction is 59 degree north east

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a student wants to determine whether the density of a solid cube of copper will decrease as its temperature is increased without melting the cube. graphing which of the following will allow the student to study this question?

Answers

Answer:

ρ (density) = M / V       mass / volume

Since the mass is not affected by heating the student needs to plot the Volume of the cube Vs Temperature

He should find that the volume of the object increases with the temperature of the object and hence the density will decrease with the rise in temperature

A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground

Answers

We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.

After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`

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PLEASE HELP IM DOING A TEST
Choose all the answers that apply.


Earth:


has the most circular orbit in the solar system

has seasons because of a tilted axis

is a perfect sphere

has the largest satellite relative to its planet

takes longer than 365 days to orbit the sun

Answers

Answer:

has seasons because of a tilted axis

takes longer than 365 days to orbit the sun

Explanation:

Note: We see 365 days for a year - from an external point of view, a year would take 366 days to orbit the sun - this is because it takes slightly less than 24  hours from sunrise to sunrise because of the rotation of the earth about the sun (a sidereal year is 366 days as compared to 365 days observed on earth)

PLEASE HELP ON QUESTION ASAP. if answer is correct i will rate you five stars a thanks and maybe even brainliest.
Alex drove for 3 hours at average speed of 60mph and for 2 hrs at 45 miles per hour. Whats his average speed for the whole journey.

also could you please show me how our working out should look like in an exam

Answers

The average speed of the whole journey is 54 mph.

To find the average speed of the entire journey, you will need to use the formula, Average speed = Total distance ÷ Total time. So, in this case, the total distance is the sum of the distances traveled at 60 mph and 45 mph, and the total time is the sum of the times taken to cover these distances. Let's calculate:Distance covered at 60 mph = 60 mph × 3 hours = 180 milesDistance covered at 45 mph = 45 mph × 2 hours = 90 milesTotal distance covered = 180 miles + 90 miles = 270 milesTotal time taken = 3 hours + 2 hours = 5 hoursTherefore, the average speed for the whole journey will be:Average speed = Total distance ÷ Total time= 270 miles ÷ 5 hours= 54 miles per hourSo, the average speed of the whole journey is 54 mph.In an exam, it is important to show all the necessary steps and calculations, as demonstrated above. It is also essential to label the units clearly, and write down the formula used. Lastly, a summary statement or answer to the question should be provided.

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Pretty simple physics :) will give brainliest
pls dont just use me for points

Pretty simple physics :) will give brainliestpls dont just use me for points

Answers

Answer:

meter per second(m/s)

Explanation:

On July 4, 2005, the NASA spacecraft Deep Impact fired a projectile onto the surface of Comet Tempel 1. This comet is about 9.0 km across. Observations of surface debris released by the impact showed that dust with a speed as low as 1.0 m/s was able to escape the comet.

1. Assuming a spherical shape, what is the mass of this comet? ( The escape speed for an object at the surface of Earth is 11.2 km/s).

Express your answer using two significant figures.
M = ____________ kg
2. How far from the comet's center will this debris be when it has lost 60% of its initial kinetic energy at the surface?

Express your answer using two significant figures.
r = ____________ km

Answers

Answer:

1. M = 67,422,800,892,977.54 kg

2. r = 15 km

Explanation:

The diameter of the Comet Tempel 1, D = 9.0 km across

The speed with which the dust escapes = 1.0 m/s

1. The escape velocity, \(v_e\), is given by the following formula

\(v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{R} }\)

Where;

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

\(v_e\) = The escape velocity of the debris = 1.0 m/s

M = The mass of the comet from where the debris escapes

From the escape velocity equation, we have;

\(M = \dfrac{v_e^2 \cdot R}{2 \cdot G}\)

Plugging in the values for the variables, we get the mass of the comet, 'M', as follows;

\(M = \dfrac{1.0^2 \times 9,000}{2 \cdot 6.67430 \times 10^{-11}} \approx 67,422,800,892,977.54 \, kg\)

The mass of the comet, M ≈ 67,422,800,892,977.54 kg

2. When the debris has lost 60% of its initial kinetic energy, we have;

\(60\% \, K.E. = 0.6\cdot K.E. = 0.6 \times \dfrac{1}{2} \times m \times v_e^2 = \dfrac{G \cdot M \cdot m}{r}\)

\(\therefore \, The \ distance \ of \ debris \ from \ the \ center, \, r = \dfrac{G \cdot M }{0.6 \times \dfrac{1}{2} \times v_e^2 }\)

\(r = \dfrac{6.67430 \times 10^{-11} \times 67,422,800,892,977.54}{0.6 \times \dfrac{1}{2} \times 1^2 } = 15,000\)

When the debris has lost 60% of its initial kinetic energy, the distance the debris will be from the comet's center, r = 15,000 m = 15 km

Given a rank for a particular flood event of 25 and a record of 24 years duration, what is
the recurrence interval for a flood of this size?

Answers

Answer:

The 25-year flood occurs on average once every 25 years and has an exceedance probability of 1 over 25, or 4 percent, in any given year

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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An electron in the n= 6 state of a hydrogen atom makes a transition to the n= 4 state and emits a photon in the process. What is the wavelength, in nm, of the photon emitted?

Answers

According to Bohr's Model of the Hydrogen Atom, the energy of the n-th state is given by the expression:

\(E_n=-13.6eV\left(\frac{1}{n^2}\right)\)

If an electron changes from a state n to a state m, the energy of the photon emitted is given by:

\(\Delta E=E_n-E_m=-13.6eV\left(\frac{1}{n}-\frac{1}{m}\right)\)

Replace n=6 and m=4 to find the energy of the emitted photon:

\(\Delta E=-13.6eV\left(\frac{1}{6}-\frac{1}{4}\right)=1.1333...eV\)

On the other hand, the energy of a photon and its wavelength are related through the equation:

\(E=\frac{hc}{\lambda}\)

Then, the wavelength of the photon emitted is:

\(\begin{gathered} \lambda=\frac{hc}{E} \\ \\ =\frac{(6.626\times10^{-34}Js)(2.9979\times10^8\frac{m}{s})}{1.1333...eV} \\ \\ =\frac{(6.626\times10^{-34}Js)(2.9979\times10^8\frac{m}{s})}{1.1333...\cdot1.602\times10^{-19}C\cdot V} \\ \\ =1.094...\times10^{-6}m \\ \\ \approx1094nm \end{gathered}\)

Therefore, the wavelength of the photon emitted is approximately 1094 nanometers.

the mathematiccal relationships between kinetic energy and the mass of an object

Answers

Answer:

The equation for Kinetic Energy is: KE = 1/2 mv2. Kinetic energy has a direct relationship with mass, meaning that as mass increases so does the Kinetic Energy of an object. The same is true of velocity. ... We must consider both the speed and mass of objects when considering the outcomes of collisions.

Answer:

Kinetic energy is directly proportional to mass, and mass to kinetic energy. Kinetic energy is proportional to the square of the velocity of the moving mass. The equation for Kinetic Energy is: KE = 1/2 mv2.

5.5A Two similar dielectric ellipsoids are placed in an electric field as shown in Fig. P5.5. For which orientation is the depolarization factor larger? Give qualitative reasons. Fig. P5.5 (a) (b) E​

Answers

In order to determine which orientation results in a larger depolarization factor for the similar dielectric ellipsoids placed in an electric field, we need to consider the shape and alignment of the ellipsoids with respect to the electric field.

The depolarization factor measures the reduction in the electric polarization of a material due to its shape and alignment in an electric field. It is influenced by the geometry of the material and how it interacts with the electric field.

Qualitatively, if the ellipsoids are aligned in such a way that their major axes are parallel to the electric field lines, the depolarization factor would be smaller. This is because the electric field would act along the long axis of the ellipsoid, resulting in less distortion of the polarized charges inside the material. The polarization would be more effectively aligned with the electric field, minimizing the depolarization effect.

On the other hand, if the ellipsoids are oriented such that their major axes are perpendicular or at an angle to the electric field lines, the depolarization factor would be larger. In this case, the electric field would act in a direction that is not aligned with the major axis of the ellipsoid, causing more distortion and misalignment of the polarized charges inside the material. This results in a larger depolarization effect.

Without a specific diagram or more information about the orientations shown in Figure P5.5, it is difficult to determine the exact orientation with the larger depolarization factor. However, based on the general understanding of the relationship between alignment and the depolarization effect, the orientation where the major axes of the ellipsoids are perpendicular or at an angle to the electric field lines is likely to result in a larger depolarization factor.

calculate the power of a 100kg man who jumps of a building 10m high in 10 seconds given that acceleration due to gravity is 10 ms–²​

Answers

A 100kg man jumping off a 10m high building in 10 seconds has a power of 1000 Watts.

When the man jumps off the building, he initially possesses potential energy due to his position above the ground. As he falls, this potential energy is converted into kinetic energy, which is the energy of motion. The work done by the man is equal to the change in potential energy.

The potential energy (PE) can be calculated using the formula PE = mgh, where m represents the mass, g represents the acceleration due to gravity, and h represents the height. In this case, the mass is given as 100kg, the acceleration due to gravity is 10 m/s², and the height is 10m.

Substituting these values into the formula, we get PE = 100kg * 10m/s² * 10m = 10,000 Joules. This means that the work done by the man while jumping off the building is 10,000 Joules.

Power is defined as the rate at which work is done. In this scenario, we divide the work (10,000 Joules) by the time taken (10 seconds) to obtain the power. Therefore, Power = Work/Time = 10,000 J / 10 s = 1000 Watts.

Hence, the power of the 100kg man who jumps off the 10m high building in 10 seconds is calculated to be 1000 Watts. Power represents the rate at which energy is transferred or work is done, indicating how quickly the man transformed potential energy into kinetic energy during the jump.

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Pete is investigating the solubility of salt (NaCl) in water. He begins to add 50 grams of salt to 100 grams of
room temperature tap water in a beaker. After adding all of the salt and stirring for several minutes, Pete
notices a solid substance in the bottom of the beaker. Which statement best explains why there is a solid
substance in the bottom of the beaker?
A. The salt he is using is not soluble in water.
B. The salt is changing into a new substance that is not soluble in water,
C. The dissolving salt is causing impurities in the water to precipitate to the bottom
D. The water is saturated and the remaining salt precipitates to the bottom

Answers

Answer:

would the answer be c

Explanation: that what i think in my opian

Answer:

A

Explanation:

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