Complete the first and second sentences, choosing the correct answer from the given ones.
1. The water temperature in the dish depends on the A / B / C / D.
A. average kinetic energy of water molecules
B. total kinetic energy of water molecules
C. water mass. D. potential energy of the container with water
2. The internal energy of the water in the vessel is E / F / G.
E. potential energy of the vessel with water
F. average kinetic energy of water molecules
G. sum of kinetic energy and potential water molecules

The man's friend is at a distance 552.5 m away.

Speed of sound in air, v = 340 m/s

Time after which the echo is heard, t = 3.25 s

The expression for the total distance covered by the sound in the given time,

d = v x t

d = 340 x 3.25

d = 1105 m

Therefore, the distance where the friend is staying would be half of the total distance covered by the sound during the given time.

So, the distance of the friend from the man,

d' = d/2

d' = 1105/2

d' = 552.5 m

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The energy efficiency of the car is approximately 16.7%.

The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:

The useful work output can be calculated as the kinetic energy of the car using the equation:

where m is the mass of the car and v is its velocity.

Substituting the given values:

The total energy input is the energy released by burning 0.1 L of gasoline, which is:

Substituting these values into the equation for efficiency:

Therefore, the energy efficiency of the car is approximately 16.7%.

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Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

Answer:

20 mL

Explanation:

The volume of the rock is equal to the difference of volume of A and B. So, it is equal to

90 mL - 70 mL = 20 mL

Because 90 mL is the volue in cylinder B and 70 mL is the volume in cylinder A.

Therefore, the volume of the rock is 20 mL

Answer:

resonance frequency is the frequency when capacitive reactance and inductive reactance become equal and opposite to each other and all impedence is given by resistance.

Explanation:

              f=1/2\(\pi\)\(\sqrt{LC}\)

Explanation:

I think you forgot to add the other part!

Answer:

uhm what plant...

Explanation:

Answer:

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.

Given:

The initial shot was fired at an angle of 50 degrees above ground.

The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.

Let the angle of the projectile is x,

The horizontal component of velocity can be calculated as follows:

\(v(x) = v * cos(x)\)

We can write:

since the horizontal part of velocity remains constant:

\(v(x1) = v(x2)\)

\(cos(50) = cos(x)\)

\(50 = x\)

Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.

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The correct response is given when the angle is asked a question.

Answer:

Motor cortex

Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).

Explanation:

Answer:

The magnitude and direction of the net force acting on the ring is equal to the vector sum of the three forces acting on it. Based on the figure, the net force acting on the ring is equal to the vector sum of F1 minus F2 plus F3, and its magnitude is equal to the square root of (F1^2 + F3^2) minus (F2^2). The direction of the net force is the same as that of F1 minus F2 plus F3. This is because the three forces, F1, F2, and F3, all act concurrently and will add up to produce a single resultant, or net force.

Solving Gaussian integration with polar coordinates involves converting the integral into polar coordinates, finding the mean and standard deviation of the function, substituting them into the Gaussian distribution formula, and integrating it over the range of the function in polar coordinates.

Gaussian integration with polar coordinates is the process of finding the integral of a function using polar coordinates and the Gaussian distribution. The polar coordinate system is a two-dimensional coordinate system that uses the radius and angle to locate a point in a plane. The Gaussian distribution is a probability distribution that is often used to describe random variables in statistics.
To solve the Gaussian integration with polar coordinates, we need to convert the integral into polar coordinates. The conversion is done using the following equations:
x = r cos(θ)
y = r sin(θ)
r² = x² + y²
θ = tan⁻¹(y/x)
Once the integral is converted into polar coordinates, we can use the Gaussian distribution to solve it. The Gaussian distribution is given by the following formula:
f(x) = (1/σ√(2π))e^(-(x-μ)²/2σ²)
where μ is the mean of the distribution and σ is the standard deviation. To use this formula, we need to first find the mean and standard deviation of the function we are integrating.
After finding the mean and standard deviation, we can substitute them into the Gaussian distribution formula and integrate it over the range of the function in polar coordinates. The result of the integration will be the value of the integral.
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The gravitational force between two students is 5.336*10^-8 N.

According to universal gravitational law, the force acting on two bodies is given by the formula = F = (G *m1*m2)/r^2

Here mass of one student =m1=75kg,another student m2=54kg

Distance of separation =0.45m, r =0.45/2=0.225m

Force = 6.67*10^-11 (75*54)/(0.225)^2

F=5.336*10^-8 N

The force between two students is 5.336*10^-8 N.

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Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

The surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K, based on the peak wavelength of 40 μm.

To find the surface temperature of the asteroid, we can use Wien's displacement law, which states that the peak wavelength of radiation emitted by a blackbody is inversely proportional to its temperature. Given that the power per unit wavelength peaks at 40 μm, we can calculate the surface temperature of the asteroid.

1. According to Wien's displacement law, the peak wavelength (λ) is related to the temperature (T) by the equation: λ_max = (b / T), where b is Wien's displacement constant equal to 2898 μm·K.

2. We are given that the peak wavelength is 40 μm. Substituting this value into the equation, we have: 40 μm = (2898 μm·K / T).

3. Rearranging the equation, we find: T = (2898 μm·K) / (40 μm).

4. Calculating the values, we get: T = 72.45 K.

Therefore, the surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K.

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Answer:

20 m/s

Explanation:

The force acting on the electron is 1.92 x 10^-17 N.

The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.

We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.

The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.

F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.

Therefore, the force acting on the electron is 1.92 x 10^-17 N.

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Answer:

Explanation:

try the fourth one :)

Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.

Explanation:

To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.

The rate of heat loss through conduction can be calculated using the formula:

Q = (k * A * ΔT) / d

Where:

Q is the rate of heat transfer (in Watts)

k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)

A is the surface area (1.3 m² in this case)

ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)

d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)

Let's plug in the values:

Q = (0.019 * 1.3 * ΔT) / (30 / 1000)

The hiker can safely lose 85 W of heat, so we can set up the equation:

85 = (0.019 * 1.3 * ΔT) / (30 / 1000)

To solve for ΔT, we can rearrange the equation:

ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)

ΔT ≈ 89.61°C

Answer:

Q1. A measurable extent of a particular kind, such as length, breadth, depth, or height.

Q2. A dimensional constant is a physical quantity that has dimensions and has a fixed value. Some of the examples of the dimensional constant are Planck's constant, gravitational constant, and so on.

Q3. Physical quantities which posses dimensions and have variable are called dimensional variables. Examples are length, velocity, and acceleration etc.

Q4. Dimensionless variables are the quantities which doesn't have any dimensions the the value is a variable. Eg: angle = arc/ radius. Dimensions = L/L. = 1. So angle does not have any dimensions and the value can vary.

Q5. Principle of Homogeneity states that dimensions of each of the terms of a dimensional equation on both sides should be the same. This principle is helpful because it helps us convert the units from one form to another.

Q6. Dimensional analysis has been around a long time, Newton called it the "Great principle of Similitude", but the modern form can be traced back to James Clerk Maxwell. It was Maxwell who distinguished mass [A/], length [£], and time [7"] as the independent dimensions from which others could be derived.

Q7. Mass, length, time, temperature, electric current, amount of light, and amount of matter.

Q8. Dimensional analysis is used to convert the value of a physical quantity from one system of units to another system of units. Dimensional analysis is used to represent the nature of physical quantity. The expressions of dimensions can be manipulated as algebraic quantities.

Hope that helps. x

a) Z = 58.0 Ω - j66.35 Ω ;  b) Imax = 0.515 A  ; c) i = 0.515 sin(200πt + 42.5°) ; d) i = 0.515 sin(200πt + 0.741 rad)  ; e)  If the inductance of circuit is 0.0969 H, then current will lag the voltage by same angle as in part (d).  ;f) |Z| = 60.

Measure of the opposition that electrical circuit presents to the flow of alternating current is called impedance.

(a) Impedance (Z) of the circuit is : Z = R + j(XL - XC)

Inductive reactance and capacitive reactance are : XL = 2πfL

XC = 1/(2πfC)

XL = 2π(100 Hz)(150 mH) = 94.25 Ω

XC = 1/(2π(100 Hz)(99.0 µF)) = 160.6 Ω

Therefore,  impedance of the circuit is: Z = 58.0 Ω + j(94.25 Ω - 160.6 Ω) = 58.0 Ω - j66.35 Ω

(b) Maximum current (Imax) in the circuit is : Imax = Δv / |Z|

Δv is amplitude of the voltage

|Z| = √((58.0 Ω)² + (-66.35 Ω)²) = 87.4 Ω

Therefore, maximum current in the circuit is: Imax = (45.0 V) / (87.4 Ω) = 0.515 A

(c) The phase angle (θ) between the voltage and current is : tan(θ) = (XL - XC) / R

tan(θ) = (94.25 Ω - 160.6 Ω) / 58.0 Ω = -0.959

Therefore, phase angle is: θ = -42.5°

Equation for the current is: i = Imax sin(ωt - θ)

ω is angular frequency in radians per second. Angular frequency is : ω = 2πf = 2π(100 Hz) = 200π rad/s

i = 0.515 sin(200πt + 42.5°)

(d) Phase angle in radians is: θ = -42.5° = -0.741 rad

i = 0.515 sin(200πt + 0.741 rad)

(e) The condition for the current to lag the voltage by the same angle as in part (d) is: ωL - 1/(ωC) = tan(θ)R

L = (tan(θ)R + 1/(ωC)) / ω

L = (tan(-42.5°)(58.0 Ω) + 1/(2π(100 Hz)(99.0 µF))) / (2π(100 Hz))

L = 0.0969 H

Therefore, if the inductance of circuit is 0.0969 H, the current will lag the voltage by the same angle as in part (d).

(f) The maximum current in the circuit is given by the same formula as in part (b), with the impedance |Z| calculated using the inductance found in part (e).  |Z| = √((58.0 Ω)² + (-18.99 Ω)²) = 60.

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When two bodies travel in the same direction at the same speed, their relative velocity equals zero. A person's relative velocity with regard to the chair is zero when he or she sits in it. The chair's relative velocity to the occupant is also zero.

Example- When a ball is thrown upwards on earth with a constant velocity, the gravitational force of the earth acts on it in the opposite direction. At the highest point, the velocity of the ball becomes zero, after which it starts to fall down.

Answer:

An example in which the relative velocity of a body with respect to another is zero is when two objects are at rest or moving together with the same speed and in the same direction.

For instance, consider two cars parked side by side on a road. If both cars remain stationary, their relative velocity with respect to each other is zero. Another example is when two people are walking together at the same speed and in the same direction. In this case, their relative velocity with respect to each other is also zero.

It has all of these. everything has kinetic energy, it is moving so it will have both speed and velocity as well.

If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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We know

\(\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\Theta}}\)

\(\\ \sf\longmapsto R=\sqrt{50^2+50^2+2(50)(50)cos35}\)

\(\\ \sf\longmapsto R=\sqrt{2500+2500+2(2500)\times (-0.9)}\)

\(\\ \sf\longmapsto R=\sqrt{5000+5000(-0.9)}\)

\(\\ \sf\longmapsto R=\sqrt{5000+(-4500)}\)

\(\\ \sf\longmapsto R=\sqrt{5000-4500}\)

\(\\ \sf\longmapsto R=\sqrt{-500}\)

\(\\ \sf\longmapsto R=22.4i\)

Resultant using the Law of Sines and the Law of Cosines will be R=95 N

Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.

The Magnitude of two forces =50 N

Angle between the forces = 35

By using the resultant formula

\(\rm R=\sqrt{A^2+B^2+2ABCos\theta}\)

\(\rm R=\sqrt{50^2+50^2+2(50)(50)Cos35}\)

\(\rm R=\sqrt{5000+5000(0.81)}\)

\(\rm R=\sqrt{5000+4500}\)

\(\rm R=95\ N\)

Hence the Resultant using the Law of Sines and the Law of Cosines will be R=95 N

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To calculate the average deceleration while a person is under the water, we need to know the initial velocity, final velocity, and the time taken for deceleration.

Let's assume the person is initially moving with a velocity v0, and they come to a stop in a distance d underwater. We also need to know the time taken for this deceleration, denoted as t.

The average deceleration (a) can be calculated using the formula:

a = (v - v0) / t

where v is the final velocity, which is 0 since the person comes to a stop.

Since we don't have specific values for v0, v, and t, we cannot provide a numerical answer. However, if you provide the required values, I would be able to calculate the average deceleration for you.

The efficiency of the ramp is 80% and the mechanical advantage is 2.

To solve this problem, we can use the formulas for efficiency and mechanical advantage:

Efficiency = (output work / input work) x 100%

Mechanical Advantage = output force / input force

First, we need to find the output force and output work of the ramp.

The output force is the weight of the box, which is 1200 N.

The output work is the force applied by the output force over the distance it moves. Since the box moves a distance of 1.0 m up the ramp,

the output work is:

Output work = output force x output distance

Output work = 1200 N x 1.0 m

Output work = 1200 J

Next, we need to find the input force and input work of the ramp.

The input force is the force applied by the man, which is 600 N.

The input work is the force applied by the input force over the distance it moves. Since the man moves a distance of 2.5 m along the ramp,

the input work is:

Input work = input force x input distance

Input work = 600 N x 2.5 m

Input work = 1500 J

Now we can calculate the efficiency and mechanical advantage:

Efficiency = (output work / input work) x 100%

Efficiency = (1200 J / 1500 J) x 100%

Efficiency = 80%

Mechanical Advantage = output force / input force

Mechanical Advantage = 1200 N / 600 N

Mechanical Advantage = 2

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Answer:

gym and gym work 6.30 and I have been a very good friend a

Answer:

Becoming aware of rhyming sounds boosts brain activity and a child's early literacy ability. Adding singsong rhyming words to requests for attention is an effective way for teachers to get toddlers to listen to what they say. Rhymes and rhythms add zest and humor and increase toddler cooperation in the classroom.

v² - u² = 2 a ∆x

where u = initial velocity (27 m/s), v = final velocity (0), a = acceleration (-8 m/s², taken to be negative because we take direction of movement to be positive), and ∆x = stopping distance.

So

0² - (27 m/s)² = 2 (-8 m/s²) ∆x

∆x = (27 m/s)² / (16 m/s²)

∆x ≈ 45.6 m

The stopping distance of car achieved during the braking is of 45.56 m.

Given data:

The initial speed of car is, u = 27 m/s.

The final speed of car is, v = 0 m/s. (Because car comes to stop finally)

The magnitude of deacceleration is, \(a = 8\;\rm m/s^{2}\).

In order to find the stopping distance of the car, we need to use the third kinematic equation of motion. Third kinematic equation of motion is the relation between the initial speed, final speed, acceleration and distance covered.

Therefore,

\(v^{2}=u^{2}+2(-a)s\)

Here, s is the stopping distance.

Solving as,

\(0^{2}=27^{2}+2(-8)s\\\\s = 45.56 \;\rm m\)

Thus, we can conclude that the stopping distance of car achieved during the braking is of 45.56 m.

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