Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropriate abbreviation for the product. FADH 2 + Q ⟶ The reactant that is reduced is _____. In complex III, electrons are transferred from coenzyme Q to cytochrome c, which contains iron. QH2 + 2 cyt c ( Fe 3 + ) ⟶ Q + 2 cyt c ( Fe x ) + 2 H
Determine the oxidation number for iron on the right side of the reaction arrow.
X = ___

As per the given reaction, 2 moles or 46 g of LiOH is needed to completely react with CO₂. Then, 25.5 g of CO₂ requires 1.16 moles of LiOH.

Lithium hydroxide is an ionic compound formed by the combination of metallic lithium and water moiety. LiOH easily reacts with carbon dioxide forms an insoluble compound lithium carbonate and water.

As per the given balanced equation of the reaction between LiOH and carbon dioxide, one mole of CO₂ reacts with 2 moles of LiOH.

molar mass of CO₂ = 44 g/mol

molar mass of LiOH = 23 g/mol

mass of 2 LiOH = 46 g.

Then, mass of LiOH needed to react with 25 .5 g of CO₂ = (25.5 × 46) /44 = 26.13 g

Number of moles in 26.13 g of LiOH = 26.13/23 = 1.16 moles.

Therefore, the number of moles of LiOH are needed to react completely with 25.5 g of CO2 is 1.16 moles.

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Answer:

-trees

-solar energy

-hydroelectricity

-wind energy

sorry I can only think or 4 atm

Explanation:

Elements in same row (i.e, from left to right) have the same number of electron shells.

Approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.

The relationship between the initial and final concentrations and volumes must be taken into account.

Given: Initial concentration \((C^1) = 1 M Initial volume (V^1) = 250 mL\)

\((C^2) = 3 M final concentration\)

We can use the equation:

\(C^1 * V^1 = C^2 * V^2\)

Where:

\(V^2\)is the final volume of the solution

Rearranging the equation to solve for V2:

\(V^2 = (C^1 * V^1) / C^2\)

Substituting the given values:

\(V^2 = (1 M * 250 mL) / 3 M\)

\(V^2 = 250 mL / 3\)

\(V^2\) ≈ \(83.33 mL\)

To find the amount of water that needs to be evaporated, we subtract the final volume from the initial volume:

Amount of water to be evaporated = \(V^1 - V^2\)

Amount of water to be evaporated = 250 mL - 83.33 mL

Amount of water to be evaporated ≈ 166.67 mL

Therefore, approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.

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Pressure of the gas inside the container is 662.59 torr.

The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).

The general law of ideal gas can be applied here: PV is equal to nRT, where P is the gas pressure in atm.

V is the number of moles of the gas in a mole, and n is the volume of the gas in L. R is the universal gas constant. T is the temperature(Kelvin) of the gas.

If P and T are different values and n and V are constants, then

(P₁T₂) = (P₂T₁).

P₁ = 735 torr, T₁ = 29°C + 273 = 302 K,

P₂ = ??? torr, ​T₂ = 62°C + 273 = 335 K.

∴ P₂ = (P₁T₂)/(P₁) = (735 torr)(302 K)/(335 K) = 662.59 torr.

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Answer:

We can use the combined gas law to solve this problem:

(P1V1/T1) = (P2V2/T2)

where:

P1 = 1 atm (pressure of nitrogen gas in the first container)

V1 = 300 cm^3 (volume of the first container)

T1 = 3°C + 273.15 = 276.15 K (temperature of the nitrogen gas in the first container, converted to Kelvin)

P2 = 0.8 atm (pressure of nitrogen gas in the second container)

V2 = ? (volume of the second container, what we want to find)

T2 = 25°C + 273.15 = 298.15 K (temperature of the nitrogen gas in the second container, converted to Kelvin)

Plugging in the values, we get:

(1 atm x 300 cm^3) / 276.15 K = (0.8 atm x V2) / 298.15 K

Simplifying and solving for V2, we get:

V2 = (1 atm x 300 cm^3 x 298.15 K) / (0.8 atm x 276.15 K)

V2 = 1309.5 cm^3

Therefore, the volume of the larger container is approximately 1309.5 cm^3.

Answer:

The correct answer is - Al(OH)3

Explanation:

At the point when a substance is blended in with a soluble, there are a few potential outcomes. The deciding variable for the outcome is the solubility of the substance, which is characterized as the maximum concentration of the solute. These rules help figure out which substances are solvent, and how much.

According to the 11 rules of solubility rules, the insoluble compound in water is - Al(OH)3

Answer:

Na2So4

Explanation:

If you consult a table of solubility rules, like the one below, you will see that sodium sulfate (Na2SO4) is soluble in water.

When we choose to use nonmanipulated IVs in our factorial experiments, we are conducting experimental research.

When we choose to use nonmanipulated IVs (independent variables) in our factorial experiments, we are conducting experimental research. In experimental research, the researcher manipulates one or more variables (the independent variables) and measures the effect on another variable (the dependent variable). Factorial experiments are a type of experimental design that allow the researcher to study the effects of multiple independent variables simultaneously. Nonmanipulated IVs are variables that are not controlled or manipulated by the researcher, but rather are observed as they naturally occur. By using nonmanipulated IVs in our experiments, we are able to study the effects of these variables on the dependent variable while controlling for other factors that might influence the outcome.

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In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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Answer:

1.72x10⁻⁵ g

Explanation:

To solve this problem we use the PV=nRT equation, where:

And we solve for n:

Finally we convert moles of helium to grams, using its molar mass:

Answer:

Explanation:

Sodium ion

Answer:

No, no precipitate is formed.

Explanation:

Hello there!

In this case, since the reaction between silver nitrate and sodium acetate is:

\(AgNO_3(aq)+NaC_2H_3O_2(aq)\rightarrow AgC_2H_3O_2(s)+NaNO_3(aq)\)

In such a way, we can calculate the concentration of silver and acetate ions in the solution as shown below, and considering that the final total volume is 50.00 mL or 0.0500 L:

\([Ag^+]=\frac{20.00mL*0.077M}{50.00mL}=0.0308M\)

\([C_2H_3O_2^-]=\frac{30.00mL*0.043M}{50.00mL}=0.0258M\)

In such a way, we can calculate the precipitation quotient by:

\(Q=[Ag^+][C_2H_3O_2^-]=0.0308*0.0258=7.95x10^{-4}\)

Which is smaller than Ksp and meaning that the precipitation does not occur.

Regards!

Answer: The final pressure inside the tank is 8.41 kPa.

Explanation: We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We are given P1 = 25.0 kPa, T1 = -50 C = 223 K, and V1 is unknown. We also know that the temperature decreases by a factor of three, so T2 = T1/3 = 223/3 K.

To find V2, we need to assume that the steel container is rigid and its volume remains constant. Therefore, V1 = V2, and we can cancel out the volume from the equation:

P1/T1 = P2/T2

Substituting the values, we get:

P2 = P1 * T2 / T1 = 25.0 * (223/3) / 223 = 8.41 kPa

Therefore, the final pressure inside the tank is 8.41 kPa.

Answer:

So if pressure of a gas is increased by 25%, the volume of a gas is decreased by 25%.

Explanation:

Answer:

yi ni sidi inglish

Explanation:

Iron now speak english

Answer:

two reason for this

Explanation:

two factors that cause sea levels rising, one is related to global warming, the added water from melting ice sheets and glaciers will cause it. also the expansion of seawater when its warmer.

Answer:

Potential Energy

Explanation:

You can remember this by remembering it can “potentially” explode

Answer:

Well I think that the frogs ability to breath underwater is a adaptation to help them from prededors. Also, they have camophlage to help too.

The standard enthalpy of formation of substance in its standard state is zero.

Enthalpy is defined as a thermodynamic quantity that describes the energy of a system. For substances in their standard state, the enthalpy of formation is zero.

The standard state of a substance is defined as the state in which it is found under standard conditions.  The following substances has their standard ethalpy of formation as zero or not zero;

Zero enthalpy of formation           Non zero enthalpy of formation

Cl2(g)                                                     I2(s)

Br(g)                                                       Br2(l)

I2(g)                                                       Br2(s)

Hg(l)                                                       Hg(s)

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A. The limiting reactant is HCl and the excess reactant is Ca(OH)₂.

b. The excess in grams is 56.08 g (2.0mol of Ca(OH)₂ x 40.08 g/mol).

c. Theoretically, 4.0 moles of H₂O will be produced. This is because for every mole of HCl that reacts, two moles of H₂O will be produced.

Limiting reactant is a term used in chemistry to refer to the reactant that is completely consumed in a chemical reaction, thereby limiting the amount of product that can be produced. In a reaction, the number of moles of reactants present, along with their respective stoichiometric coefficients, determines the maximum amount of product that can be formed. When one of the reactants runs out before the others, it is referred to as the limiting reactant. The amount of product formed will be equal to the number of moles of the limiting reactant. This concept is important in stoichiometry when determining the amount of product that can be produced in a chemical reaction.

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The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.

The rate of the reaction is given by the equation:

Rate = -k[A]

where k is the rate constant and [A] is the concentration of the reactant.

Rate at t=140 s:

Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)

= 5.71×10−4 M/s

Rate at t=400 s:

Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)

= 1.00×10−4 M/s

Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:

k = Rate / [A]

Using the rate at t=140 s:

k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1

Using the rate at t=400 s:

k = 1.00×10−4 M/s / 4.00×10−2 M

= 2.50×10−3 s−1

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.

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Answer:

Explanation:

When soap is dropped on the floor, it can pick up dirt, germs, and other contaminants from the floor, making the soap itself dirty. However, when the soap is used to clean the floor, it effectively removes the dirt and germs from the floor, leaving it clean. So, the soap can be dirty when it is dropped on the floor, but it becomes clean when it is used to clean the floor.

Answer:

Three lone pairs

Explanation:

From the left, O1 , has TWO lone pairs; O2 has ONE lone pairs; and O3 has THREE lone pairs

From the left, O1 , has TWO lone pairs; O2 has ONE lone pairs; and O3 has THREE lone pairs.

The answer is D) 5 × 10⁻³.

The equilibrium constant expression for the reaction is given by:

\(K = [H_3O^+]^2 [C_2O_4^{-2}] / [H_2C_2O_4]\)

Since oxalic acid is a diprotic acid, its dissociation occurs in two steps, and the given values of Kx and K2 correspond to the dissociation constants of the first and second steps, respectively. The overall dissociation constant, K, can be expressed in terms of Kx and K2 as:

K = Kx × K2

Substituting the given values of Kx and K2:

K = 5 × 10⁻⁵ × 5 × 10⁻¹⁰

K = 2.5 × 10⁻¹⁴

Comparing the calculated value with the options given:

A) 5 × 10² - Not equal

B) 5 × 10¹⁰ - Not equal

C) 25 × 10⁻¹ - Not equal

D) 5 × 10⁻³ - Equal

Therefore, the answer is D) 5 × 10⁻³

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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In order to promote a healthy environment, the piece of trash should be matched to the best method of disposing them as follows:

Compost rotting can be defined as a chemical change that involves the mixture of decayed organic substances such as dead leaves, vegetables, manure, or egg shells, that are added to the soil, in order to fertilize it.

Recycling can be defined as a waste (trash) management technique that involves the process of converting a raw material that has reached the end of its life cycle into new and reusable items.

In order to promote a healthy environment, the piece of trash should be matched to the best method of disposing them as follows:

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Answer:

Recycling - television set, plastic milk bottle, and soup can.

Compost - egg shell, vegetable peel, and grass clippings.

Explanation:

Plato

There are approximately 0.16 moles of gas present in the lungs.

To solve this problem, we can use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:

PV = nRT

where R is the gas constant.

First, we need to convert the temperature to Kelvin:

T = 37°C + 273.15 = 310.15 K

Next, we can plug in the given values:

P = 1.0 atm

V = 4.0 L

T = 310.15 K

We also need to find the value of R, which depends on the units we are using for pressure, volume, and temperature. In this case, we are using atmospheres, liters, and Kelvin, so we can use the value:

R = 0.08206 L·atm/K·mol

Now we can rearrange the ideal gas law to solve for the number of moles:

n = PV/RT

n = (1.0 atm)(4.0 L)/(0.08206 L·atm/K·mol)(310.15 K)

n = 0.1638 mol

Therefore, there are approximately 0.16 moles of gas present in the lungs.

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