consider microwaves which are incident perpendicular to a metal plate which has a 1.8-cm slit in it. part a determine the wavelengths for which diffraction minima are observed. check all that apply. determine the wavelengths for which diffraction minima are observed.check all that apply. 3 cm 0.5 cm 1 cm 4 cm

Answers

Answer 1

The wavelengths for which diffraction minima are observed is 0.5 cm.

Option (b) is correct.

To determine the wavelengths for which diffraction minima are observed in a metal plate with a 1.8-cm slit, we can use the following formula for the position of the minima:

Tsin(θ) = mλ / b

where θ is the angle between the direction of the incident waves and the direction of the diffracted waves, m is the order of the minimum, λ is the wavelength of the incident waves, and b is the width of the slit.

For the first minimum, we have m = 1. Therefore, we can rearrange the formula to solve for λ:

λ = b sin(θ) / m

Substituting the values, we get:

λ = (1.8 cm) sin(θ) / 1

λ = 0.018 m sin(θ)

We can now determine the values of sin(θ) for which diffraction minima are observed for the given wavelengths:

3 cm: λ = 0.03 m, sin(θ) = λ / (0.018 m) = 1.67

0.5 cm: λ = 0.005 m, sin(θ) = λ / (0.018 m) = 0.28

1 cm: λ = 0.01 m, sin(θ) = λ / (0.018 m) = 0.56

4 cm: λ = 0.04 m, sin(θ) = λ / (0.018 m) = 2.22

We can see that only the value of sin(θ) for the wavelength of 0.5 cm is less than 1, which means that diffraction minima are observed for this wavelength. Therefore, the answer is option number (b) 0.5 cm.

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Complete question is:

Consider microwaves which are incident perpendicular to a metal plate which has a 1.8-cm slit in it. Part A: Determine the wavelengths for which diffraction minima are observed. Check all that apply.

Options:

a)  3 cm

b) 0.5 cm

c)  1 cm

d) 4 cm


Related Questions

A highway is to be built between two towns, one of which lies 37.1 km south and 68.3 km west of the other. at what angle would this highway be directed with respect to due west?

Answers

The highway would be directed at an angle with respect to due west. To find this angle, we can use trigonometry.

First, let's draw a diagram to visualize the situation. Place one town at the origin (0,0) on a coordinate plane. The other town is located 68.3 km west and 37.1 km south of the origin.

Next, we can find the length of the hypotenuse of the right triangle formed by the two towns. Using the Pythagorean theorem, we have:

hypotenuse = sqrt((68.3 km)² + (37.1 km)²)

Now, we can find the angle θ between the hypotenuse and the due west direction. We can use the inverse tangent function (arctan) to find this angle:

θ = arctan(37.1 km / 68.3 km)

Calculating this, we find that θ is approximately 28.3 degrees.

Therefore, the highway would be directed at an angle of 28.3 degrees with respect to due west.

The highway would be directed at an angle of 28.3 degrees with respect to due west.

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When is the only time that an object has no kinetic energy?

Answers

Answer:

The only time an object has NO kinetic energy is when the velocity is "Zero"

Explanation:

The object starts out with no kinetic energy and potential energy of PE = mgh where m is the mass.The kinetic energy is zero. As the object falls it loses potential energy and gains kinetic energy KE = mv2/2.

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It is possible that when an object is stationary and not moving, it has no kinetic energy.

Only when an item is entirely at rest does it have no kinetic energy. The energy an object possesses as a result of its motion is known as kinetic energy. It is based on the object's mass and velocity.

When an object is not moving and has no velocity, it also has no kinetic energy.

According to the kinetic energy formula,

KE = 1÷2 × mass × velocity², if the velocity is zero, the entire term involving velocity becomes zero, resulting in zero kinetic energy.

Thus, when an object is stationary and not moving, it has no kinetic energy.

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What characteristics of the solar system would have to be known or calculated in order to send a
probe to a distant planet, such as Jupiter?
a. the effects due to the light from the distant stars
b. the effects due to the air in the solar system
c. the effects due to the gravity from the other planets
d. the effects due to the cosmic microwave background radiation

Answers

Answer:

A

Explanation:

The effects due to light from distant stars

The characteristics of the solar system would have to be known or calculated in order to send a probe to a distant planet, such as Jupiter, due to the effects of the gravity from the other planets. Hence, option C is the correct answer.

When sending a probe to a distant planet, such as Jupiter, one of the critical factors that would have to be known or calculated is the effects due to the gravity from the other planets in the solar system. The gravitational interactions between the planets can significantly influence the trajectory and path of the probe during its journey. Accurate calculations are necessary to ensure that the probe's trajectory is properly planned and adjusted to reach its destination with precision. Hence, option C is the correct answer.

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John attached a ball to a spring

John attached a ball to a spring

Answers

Answer:

C down

Explanation:

The ball is pulling the spring down so this must be the direction of the force

viewed from pluto, the sun would appear more than a thousand times fainter than on earth. True or False

Answers

( True ) Pluto is the farthest planet from the sun in our solar system. Its average distance from the sun is about 3.7 billion miles. Due to this vast distance, the intensity of sunlight reaching Pluto is significantly weaker than on Earth. From Pluto's perspective, the sun appears as a very bright star in the sky, rather than a massive glowing ball.

The sun's apparent magnitude, which is a measure of its brightness as seen from Earth, is about -26.7. However, when viewed from Pluto, the sun's apparent magnitude drops to about -19.5, which is more than a thousand times fainter. This is because the intensity of sunlight decreases with distance, following the inverse-square law. Therefore, the sun would appear much dimmer to an observer on Pluto than on Earth.

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Technology required. A plane leaves the ground with an elevation angle of 6 degrees.
The plane travels 10 miles horizontally.
a. How high is the plane at the time?
b. What is the distance of the plane's path?
Round answers to the nearest tenths.
How high is the plane at this time?
miles
What is the distance of the plane's path?
miles

Answers

(a) The plane's height at that time is approximately 10.49 miles.

(b) The distance of the plane's path is approximately 10.06 miles.

To solve this problem, we can use trigonometry. Let's consider the elevation angle of 6 degrees, the horizontal distance of 10 miles, and the height of the plane at a certain time.

a. To find the height of the plane, we can use the tangent function:

tangent(angle) = opposite/adjacent

In this case, the opposite side is the height of the plane, and the adjacent side is the horizontal distance traveled.

tangent(6 degrees) = height/10 miles

Rearranging the equation, we can solve for the height:

height = tangent(6 degrees) * 10 miles

Plugging in the values:

height = tan(6 degrees) * 10 miles = 1.049 * 10 = 10.49 miles

Therefore, the plane's height at that time is approximately 10.49 miles.

b. The distance of the plane's path can be calculated using the cosine function:

cosine(angle) = adjacent/hypotenuse

In this case, the adjacent side is the horizontal distance traveled, and the hypotenuse is the total distance traveled by the plane.

cosine(6 degrees) = 10 miles/distance

Rearranging the equation, we can solve for the distance:

distance = 10 miles / cosine(6 degrees)

Plugging in the values:

distance = 10 miles / cos(6 degrees) = 10 / 0.9945 = 10.06 miles

Therefore, the distance of the plane's path is approximately 10.06 miles.

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if the vector b⃗ b→ has a magnitude of 40 mm and makes an angle of 60 ∘∘ with the x x axis, the vector - b⃗

Answers

The vector \(\(-\mathbf{b}\)\) with a magnitude of 40 mm and an angle of 60 degrees with the x axis is represented as\(\(-20\mathbf{i} - 20\sqrt{3}\mathbf{j}\).\)

The vector \(\(\mathbf{b}\)\) has a magnitude of 40 mm and makes an angle of 60 degrees \((\(60^\circ\))\) with the x axis. To find the vector- \(\mathbf{b}\)\), we need to reverse its direction while keeping the magnitude unchanged.

The components of the vector \(\mathbf{b}\)\) can be found using trigonometry. Let b_x be the component of \(\mathbf{b}\)\)) along the x axis, and b_y be the component of \(\mathbf{b}\)\) along the y axis. Since the magnitude of \(\mathbf{b}\)\) is 40 mm, we have:

\(\[\begin{align*}b_x &= |\mathbf{b}| \cdot \cos(\theta) \\&= 40 \, \mathrm{mm} \cdot \cos(60^\circ) \\&= 40 \, \mathrm{mm} \cdot \frac{1}{2} \\&= 20 \, \mathrm{mm}\end{align*}\]\[\begin{align*}b_y &= |\mathbf{b}| \cdot \sin(\theta) \\&= 40 \, \mathrm{mm} \cdot \sin(60^\circ) \\&= 40 \, \mathrm{mm} \cdot \frac{\sqrt{3}}{2} \\&= 20\sqrt{3} \, \mathrm{mm}\end{align*}\]\)

Therefore, the vector \(\(\mathbf{b}\) can be written as \(\mathbf{b} = 20\mathbf{i} + 20\sqrt{3}\mathbf{j}\),\) where\(\(\mathbf{i}\) and \(\mathbf{j}\)\) are the unit vectors along the\(\(x\) and \(y\)\)axes, respectively.

To find the vector \(\(-\mathbf{b}\)\), we simply change the sign of both components:

\(\[-\mathbf{b} = -20\mathbf{i} - 20\sqrt{3}\mathbf{j}\]\)

Thus, the vector \(\(-\mathbf{b}\) can be represented as \(-20\mathbf{i} - 20\sqrt{3}\mathbf{j}\)\) in component form.

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An object weighs 2.2 pounds on Earth and has a mass of 1 kilogram. What are the weight and mass of the same object in space where there is no gravity acting on it?

Answers

Answer:

Heavier than 2.2 pounds

Explanation:

Sometimes, when energy is added to a solid, it undergoes____

Answers

Answer:

A phase change

Explanation:

If i understand the question correctly it should undergo a phase change e.g melting

Which statement best describes the relationship between velocity and acceleration?
Choose the correct answer.
O Velocity is the rate of change in acceleration,
O Acceleration is the rate of change in velocity
O Velocity and acceleration are not related to each other.
O Acceleration can only be a positive value regardless of the velocity.

Answers

Acceleration is the rate of change of velocity. ... If an object is changing its velocity, i.e. changing its speed or changing its direction, then it is said to be accelerating. Acceleration = Velocity / Time (Acceleration)

Acceleration is actually defined as the rate of change in velocity. The correct option is B.

What are acceleration and velocity?

Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity and to represent its direction is also required with the magnitude. The unit of the measurement of the velocity is meter per second or miles per hour etc.

Acceleration is actually defined as the rate of change in velocity. In other words, it can be defined as the change in the velocity with the change in time of the object. Acceleration is also a vector quantity and requires direction and magnitude to represent it. The unit of measurement of the acceleration is a meter per second square.

Therefore, acceleration is actually defined as the rate of change in velocity. The correct option is B.

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what's the turtle's velocity??

what's the turtle's velocity??

Answers

Answer:

\(\boxed {\boxed {\sf v\approx0.24 \ m/s}}\)

Explanation:

Velocity can be found by dividing the displacement by the time.

\(v=\frac{displacement}{time}\)

The displacement is 4.77 meters and the time is 19.5 seconds.

\(displacement=4.77 \ m \\time=19.5 \ s\)

Substitute the values into the formula.

\(v=\frac{4.77 \ m }{19.5 \ s}\)

Divide.

\(v=0.244615385 \ m/s\)

Let's round to the nearest hundredth (just to make the answer more concise).

The 4 in the thousandth place tells us to leave the 4 in the hundredth place.

\(v\approx0.24 \ m/s\)

The velocity of the turtle is about 0.24 meters per second.

A sprinter runs 200 m in 25 s. Calculate his average speed

Answers

Answer:

Explanation:

speed=distance/time = 200/25=8m/s^2

The twisting joint (type T) of an industrial robot has a range of 322° rotation. In order to study the mechanical errors in the joint and the input/output links, a statistical experiment was conducted by taking 10 samples, each one as follows: the joint was commanded to turn and stop at a certain addressable angle and the deviation (in degrees) from that specific angle was recorded. The results of taking 10 samples are presented in the table below: 0.176 0.04 -0.345 0.079 0.309 -0.004 -0.102 0.12 0.075 0.1 Supposing that the statistical distribution of the mechanical errors is normal, determine the number of storage bits required in the controller memory so that the accuracy of the joint is as close as possible to, but less than, its repeatability. Use six standard deviations as the measure of repeatability.

Answers

To determine the number of storage bits required in the controller memory for the twisting joint (type T) of the industrial robot, we need to calculate the repeatability, round the deviations to a reasonable precision, and then calculate the number of addressable positions based on the range of the joint and the chosen accuracy level.


First, let's calculate the repeatability of the joint. Given that the range of rotation is 322°, the repeatability can be calculated as 6 times the standard deviation. Since the standard deviation is a measure of how spread out the data is, multiplying it by 6 ensures that the accuracy of the joint is as close as possible to, but less than, its repeatability.
Next, let's analyze the given data. The 10 samples of deviations from the commanded angles are: 0.176, 0.04, -0.345, 0.079, 0.309, -0.004, -0.102, 0.12, 0.075, and 0.1.
To calculate the standard deviation of these deviations, we need to find the mean and then calculate the differences from the mean. Squaring these differences and taking the average will give us the variance, which we can then take the square root of to obtain the standard deviation.

After calculating the standard deviation, we multiply it by 6 to obtain the repeatability.
Now, to determine the number of storage bits required, we need to consider the accuracy of the joint. The accuracy depends on the precision required for representing the deviations. Assuming a reasonable level of precision, we can round the deviations to, for example, 3 decimal places.
Finally, the number of storage bits required in the controller memory can be calculated by multiplying the range of the joint (322°) by the accuracy (e.g., 0.001°, considering 3 decimal places). This will give us the number of addressable positions, which can be represented by the required number of storage bits.

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What are 4 physical properties for the bear

What are 4 physical properties for the bear

Answers

Answer:

A bear normally has a short, thick neck, a rounded head, a pointed muzzle, short ears, and small eyes. Some species have round faces. Bears have poor eyesight, and most have only fair hearing.

Explanation:

Modern Bears are characterized with large body and stocky legs, a long snout, shaggy hair, plantigrade paws with five non-retractile claws and a short tail.

Grizzly bears (Ursus arctos horribilis) have concave faces, a distinctive hump on their shoulders, and long claws about two to four inches long. Both the hump and the claws are traits associated with a grizzly bear's exceptional digging ability. Grizzlies are often dark brown, but can vary from blonde to nearly black.

The brown bear has a slight hump above its shoulder, round ears, a long snout and big paws with long, curved claws that it uses for digging. Unlike the black bear, it can't climb trees. It can weigh between 350-1,500 pounds. When standing on its hind legs it can be up to 5 feet tall.

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(I didn't know which type of bear so i did brown bear and grizzly bear)

PHYSICS HELP PLEASE,, I’LL MAKE YOU THE BRAINLIEST!
(look at attached picture for context)
Q: Place the block at the top of a 30 degree ramp. What is the net force on the block when it begins to slide down the ramp? What is the acceleration of the block down the ramp? SHOW WORK/CALCULATIONS

PHYSICS HELP PLEASE,, ILL MAKE YOU THE BRAINLIEST! (look at attached picture for context) Q: Place the

Answers

First, let

f = mag. of static friction

n = mag. of normal force

w = m g = mag. of gravitational force (the weight of the block)

m = mass of the block

g = 9.80 m/s² (the mag. of the acceleration due to gravity)

a = acceleration of the block

It's the static friction that interests us at the moment "when it begins to slide", meaning the precise moment at which static friction is at its maximum. At that point, the friction has magnitude f such that

f = 0.5 n

The problem is much easier to work through if you split up the forces into components acting parallel and perpendicular to the ramp. By Newton's second law, we have

• the net force acting parallel to the ramp is

F = - f + w sin(30°) = m a

• and the net force acting perpendicular to the ramp is

F = n - w cos(30°) = 0

Hence the net force on the block as it begins to slide acts only in the parallel direction. Note that we take the positive parallel direction to be the one in which the block slides down the ramp (i.e. opposing the friction force), and the positive perpendicular direction to be the same as the normal force.

Solve the second equation for n :

n = m g cos(30°) = (100 kg) (9.80 m/s²) cos(30°) ≈ 849 N

Then

f = 0.5 (849 N) ≈ 424 N

and so the net force on the block is

F ≈ - 424 N + (100 kg) (9.80 m/s²) sin(30°) ≈ 65.6 N

Next, you want to find the acceleration of the block as it is sliding down the ramp, during which time kinetic friction kicks in. We have the same equations as above, except now f = 0.3 n. So we still have n ≈ 849 N, which gives

f = 0.3 (849 N) ≈ 255 N

F = - f + w sin(30°) = m a

→   - 255 N + (100 kg) (9.80 m/s²) sin(30°) ≈ (100 kg) a

→   a ≈ 2.35 m/s²

Alkaline earth metals have a low density


true
false

Answers

true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

A steel refrigerator door is not permanently magnetic because
Entry field with correct answer

There are no magnetic domains

The electrons are bound and can't move around much

The door is usually ground out and loses all its m agnetism.

All the magnetic domains are oriented randomly

Answers

A steel refrigerator door is not permanently magnetic because  "All the magnetic domains are oriented randomly." The correct answer is D.

Magnetism is a property of materials that arises from the motion of electrons within the atoms of the material. In magnetic materials, such as iron, nickel, and cobalt, the electrons are arranged in such a way that they create a magnetic field. These materials have magnetic domains, which are regions where the atoms are aligned in the same direction, creating a net magnetic field.

Steel is a magnetic material, but it is not usually permanently magnetic. This is because the magnetic domains in steel are oriented randomly, meaning that the net magnetic field of the material is zero. In order to make steel magnetic, an external magnetic field must be applied to align the magnetic domains. However, this alignment is not permanent, and the domains will eventually become randomized again.

Option A, "There are no magnetic domains," is not true because magnetic domains do exist in magnetic materials such as steel.

Option B, "The electrons are bound and can't move around much," is not true because the electrons in steel can move around freely and create a magnetic field.

Option C, "The door is usually ground out and loses all its magnetism," is not true because the loss of magnetism in steel is due to the random orientation of the magnetic domains, not due to external factors such as grinding.

Therefore, The correct answer is D. All the magnetic domains are oriented randomly.

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Read the excerpt from paragraph 1.
Apollo 14 launched in the late afternoon of January 31, 1971, on what was to be our third trip to the lunar surface. Five days later Alan
Shepard and Edgar Mitchell walked on the Moon while Stuart Roosa, a former U.S. Forest Service smoke jumper, orbited above in the
command module.
What is the meaning of the phrase command module as it is used in the excerpt?
A. the part of a spacecraft that contains support systems
B. a satellite designed to orbit the Moon
C. the detachable part of a spacecraft
D.the detachable part of a spacecraft
a satellite designed to hold a human astronaut

Answers

Answer: The detachable part of a spacecraft

Explanation:

Answer:

C.

Explanation:

detachable part of a spacecraft

Class 9 SCIENCE
ch 2 Is matter around us pure
Question -
what you mean by crystallization? Give example.​

Answers

Answer:

Crystallization is defined as a process by which a chemical is converted from a liquid solution into a solid crystalline state.

Briefly discuss the construction requirements of nuclear reactors to ensure the dangerous levels of radiation is monitored,controlled and contained to prevent catastrophes.​

Answers

Answer:

Components of a nuclear reactor

Fuel. ...

Moderator. ...

Control rods or blades. ...

Coolant. ...

Pressure vessel or pressure tubes. ...

Steam generator. ...

Containment.

Can someone help me with this please!!!

Can someone help me with this please!!!

Answers

Answer:

B.  10 m

Explanation:

f = v/λ = (20 m/s)λ / (5 m) = 4 Hz    original frequency

1/2(4 Hz) = 2 Hz   half the original frequency

(20 m/s) / λ = 2 Hz

λ = (20 m/s) / (2 Hz) = 10 m

The second wavelength would increase to 10 m

a movable bin and its contents have a combined weight of 2.1 kn determine the shortest chain sling acb that can be used to lift the loaded bin if the tension in the chain is not to exceed 5 kn. the shortest chain sling acb that can be used is m.

Answers

The shortest chain sling ACB for a movable bin is  1.228 m.

The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works

Tension in the chain T₁ and T₂The weight of a movable bin = w

Triangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.

T₁ = T₂ ≤ 5 kN
T₁ = T₂ = 5,000 N AC = BCw = 2.1 kN = 2,100 N
At point C, the direction of the weight is upward.The forces T₁ and T₂ can be described with respect to the y-axes and become T₁y and T₂y. Look at triangle ACO
sin θ = T₁/T₁y
T₁y = T₁ sin θ Look at triangle BCO
sin θ = T₂/T₂y
T₂y = T₂ sin θ

According to Newton's first law, in the y-axis

∑ F = 0

w - T₁y - T₂y = 0

T₁y + T₂y = 2,100

T₁ sin θ + T₂ sin θ = 2,100

5,000 sin θ + 5,000 sin θ = 2,100

10,000 sin θ = 2,100

sin θ = 2,100 ÷ 10,000

sin θ = 0.21

θ = sin⁻¹ (0.21)

θ = 12.12°

Look at AOC

AO = OB = AB ÷ 2 = 1.2 ÷ 2 = 0.6 m cos θ = AO ÷AC
cos 12.12° = 0.6 ÷ AC
0.978 = 0.6 ÷ AC  
AC = 0.6 ÷ 0.978
AC = 0.614 mACB = AC + BC
ACB = 0.614 + 0.614
ACB = 1.228 m

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a movable bin and its contents have a combined weight of 2.1 kn determine the shortest chain sling acb

What is a major difference between economic wants and economic needs? A- needs have a greater degree of scarcity than wants B- Needs are more important to survival than wants C- needs play a greater role in the economy then wants D- needs require more labor to satisfy than wants

Answers

Answer:

B because Needs are things that are essential to life but wants are just extra.

Explanation:

For example food and water is needed for life but a want would be to have the latest I phone

A major difference between economic wants and economic needs is: B- Needs are more important to survival than wants.

Economic wants can be defined as the goods and services that are desired by consumers but are not important for their survival. Some examples of economic wants are mobile phone, automobile cars, computer, clothes, television, furniture, etc.

Economic needs can be defined as the goods and services that are required by the people or consumers for their daily survival. Some examples of economic needs are: shelter, food, water, land, air, etc.

In conclusion, economic wants are less important because they are just our different desires in life but economic needs are very important and significant for the daily survival of humans because they are the basics of life.

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LESSON REVIEW
1.
ngement of the particles in
What type of arrangement and motion do particles in a liquid have?
A. Particles in liquid are closely packed together and vibrating.
B. Particles in liquid are not in contact with each other and are
moving very quickly.
2.
C. Particles in liquid are in contact with each other, but they are able
to slip past one another.
D. Particles in liquid are not in contact with one another and are
moving at extreme speeds.
What phase change occurs when a solid changes directly into a gas?
A. freezing
B. melting
C. evaporation
D. sublimation

Answers

(1) The particles in a liquid are arranged in a way that they are in contact with each other, but they are able to slip past one another. option is C.

(2) The phase change that occurs when a solid changes directly into a gas is called sublimation. option is D.

What is the motion of particles in liquid?

In a liquid, the particles are closely packed together and are in contact with each other.

However, they are not as tightly packed as they are in a solid. The particles in a liquid have enough energy to move around and slide past one another, but they are still attracted to each other through intermolecular forces.

This is why a liquid has a definite volume but takes the shape of its container, as the particles can move around and fill the space available.

Solid to gas phase change:

When a solid changes directly into a gas, without passing through the liquid state, this is called sublimation.

In this process, the particles in the solid gain enough energy to break free from the intermolecular forces holding them together, and they transition directly to the gas phase. This can occur when the pressure of the surrounding environment is low and the temperature is high enough to provide the necessary energy for sublimation to occur.

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Find the sum of the given vectors and illustrate geometrically. 15. k21, 4l, k6, 22l 16. k3, 21l, k21, 5l 17. k3, 0, 1l, k0, 8, 0l 18. k1, 3, 22l, k0, 0, 6l

Answers

The sum of the vectors will be the vector that starts from the origin and ends at the final coordinate point obtained by adding the corresponding components.To find the sum of the given vectors and illustrate them geometrically, we add the corresponding components of each vector.

For question 15:
The sum of the vectors k21, 4l, k6, 22l is k27, 26l.

For question 16:
The sum of the vectors k3, 21l, k21, 5l is k24, 26l.

For question 17:
The sum of the vectors k3, 0, 1l, k0, 8, 0l is k3, 8, 1l.

For question 18:
The sum of the vectors k1, 3, 22l, k0, 0, 6l is k1, 3, 28l.

Geometrically, you can represent each vector as an arrow starting from the origin (0,0,0) and extending to the corresponding coordinate point. The sum of the vectors will be the vector that starts from the origin and ends at the final coordinate point obtained by adding the corresponding components.

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How many centimeters are there in 2.35m?

Answers

Answer:

there are 235cm in 2.35m

A car starts from rest on a curve with a radius of 110 m and tangential acceleration of 1.1 m/s2. Through what angle will the car have traveled when the magnitude of its total acceleration is 2.6 m/s2?

Answers

The angle travelled by the car when its total acceleration is 2.6 m/s² is 1.07 Radians.

Tangential acceleration of the car, a₁ = 1.1 m/s²

Total acceleration of the car, a₂ = 2.6 m/s²

The centripetal acceleration of the car, a = √(2.6² - 1.1²) = 2.356 m/s²

Radius, R = 110 m

Centripetal acceleration = v²/R = 2.356

v² = 2.356 × 110

v = 16.01 m/s

Time taken by the car the velocity from the rest to 16.01 m/s speed.

t = (v - u)/a₁

t = (16.01 - 0)/1.1  = 14.63 seconds

Distance travelled by the car during these 14.63 seconds,

S = ut + 0.5at²

S = 0 × 14.63 + 0.5×1.1×14.63²

S =  117.8 m

Angle travelled by the car = arc/radius

= 117.8/110

= 1.07 radians

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plzzz help will mark brainliest ​

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Answers

Answer: A. 1.0

Explanation:

The answer is A or 1.0

when plotted on the blank plots, which answer choice would show the motion of an object that has uniformly accelerated from 2 m/s to 8 m/s in 3 s?

Answers

The answer choice that would show the motion of the object described is a straight line with a positive slope starting from (0, 2) and ending at (3, 8).

To determine the correct answer choice, we need to consider the characteristics of uniformly accelerated motion and how it would be represented on a velocity-time graph. Uniformly accelerated motion means that the object's velocity increases by a constant amount over equal time intervals. In this case, the object starts with an initial velocity of 2 m/s and accelerates uniformly to a final velocity of 8 m/s in 3 seconds.

On a velocity-time graph, velocity is represented on the y-axis (vertical axis) and time is represented on the x-axis (horizontal axis). The slope of the graph represents the acceleration, while the area under the graph represents the displacement of the object.

To illustrate the motion described, we need a graph that starts at 2 m/s, ends at 8 m/s, and shows a uniform increase in velocity over a period of 3 seconds. The correct answer choice would be a straight line with a positive slope starting from (0, 2) and ending at (3, 8).

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a container holds a gas consisting of 1.50 moles of oxygen molecules. One in a million of these molecules has lost a single electron. What is the net charge of the gas?

Answers

A container holds a gas consisting of 1.50 moles of oxygen molecules. One in a million of these molecules has lost a single electron. the net charge of the gas will be + 9.033 * \(10^{17}\)

If a negative charge is lost by an atom , then due to conservation of charge , that atom will acquire a positive charge . Similarly , if positive charge is lost then that atom  will acquire a negative charge .Now in above question

Total number of moles = 1.5

number of molecules in 1.5 moles of oxygen = 1.5 * 6.022 *\(10^{23}\)  = 9.033 *\(10^{23}\)  molecules

9.033 *\(10^{23}\) / \(10^{6}\) million molecules = 9.033 * \(10^{17}\) million molecule

1 in a million has lost a single electron

9.033 * \(10^{17}\) million molecule will loose 9.033 * \(10^{17}\)  electron

the net charge of the gas will be + 9.033 * \(10^{17}\)

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