Consider the dissolution of PbS in water:PbS(s) + H₂O(l) ⇄ Pb²⁺(aq) + HS⁻(aq) + OH⁻(aq)Adding aqueous NaOH causes more PbS to dissolve. Does this violate Le Châtelier’s principle? Explain.

Answer:

Mass = 135.66 ×10⁻²¹ g

Explanation:

Given data:

Number of molecules of CuSO₄= 5.119×10²

Mass of CuSO₄= ?

Solution:

The given problem will solve by using Avogadro number.

1 mole contain 6.022×10²³ molecules

5.119×10² molecules ×1 mol / 6.022×10²³ molecules

0.85×10⁻²¹ mol

Mass in grams:

Mass = number of moles × molar mass

Mass = 0.85×10⁻²¹ mol × 159.6 g/mol

Mass = 135.66 ×10⁻²¹ g

The grams of the KI are in the 25.0 ml of a 3.0 % m/v of the KI solution is 0.75 g.

The volume of the solution = 25 mL

The mass by volume of KI = 3 % m/v

The potassium iodide solution will contain the 3.0 g of the potassium iodide for the every 100 mL of the solution.

The amount of the KI in grams is as follows :

The mass of the KI in grams = (25 mL× 3 g ) / 100 mL

The mass of the KI in grams = 0.75 g

Thus, the amount of the KI in the grams is 0.75 g in the volume of the 25 mL.

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The equation that is NOT needed to solve for pH is option V: K = [H] x [OH].

Above equation represents the equilibrium constant for the autoionization of water (Kw) and is not directly relevant for calculating the pH of a weak-acid solution. To solve for the pH of a weak-acid solution using systematic treatment, we typically require equations related to the dissociation of the weak acid and the equilibrium expressions for the acid and its conjugate base. These equations allow us to set up a system of equations equal to the number of unknown concentrations, which can then be solved to determine the pH. Equations I, II, III, and IV are all relevant in the systematic treatment for calculating the pH of a weak-acid solution. They involve the concentration of the weak acid ([HA]), its dissociation into its conjugate base ([A-]) and hydrogen ions ([H]), and the equilibrium constant (Ka) associated with the weak acid dissociation.

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• The balanced equation for the reaction is given by:

• From the above reaction we can see that:

1 mole of ethanol (CH3Ch2OH) produces 1 mol of acetic acid(CH3COOH)

so . x mole of ethanol will produce 0.9mol of acetic acid ....(cross multiply)

xmol ethanol * 1mol acetic = 1mol ethamol* 0.9molacetic

∴ xmol ethanol = 1*0.9 /1

= 0.90 mol

• This means that, 0.90 mol of ethanol, is needed to produce 0.9mol acetic acid,.

The characteristic of the substrate that the active site of ADH must recognize is option A: "hydrogen atom located on a carbon next to a with an-OH group (vicinal position)".

This is because ADH is an enzyme that catalyzes the oxidation of alcohols to aldehydes or ketones. In order for this reaction to occur, the substrate must have a hydrogen atom located on a carbon next to an -OH group. This allows the enzyme to recognize the substrate and catalyze the reaction.

Without this characteristic, the enzyme will not be able to recognize the substrate and the reaction will not occur.

ADH specifically recognizes and binds to this particular feature of the substrate through its active site, which has a complementary shape and chemical properties to the substrate. This binding allows the enzyme to position the substrate in a way that facilitates the transfer of a hydrogen ion and a pair of electrons to the coenzyme NAD+ to form NADH, while producing an aldehyde or ketone.

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The characteristic of the substrate that the active site of ADH must recognize is option A: "hydrogen atom located on a carbon next to a with an-OH group (vicinal position)".

This is because ADH is an enzyme that catalyzes the oxidation of alcohols to aldehydes or ketones. In order for this reaction to occur, the substrate must have a hydrogen atom located on a carbon next to an -OH group. This allows the enzyme to recognize the substrate and catalyze the reaction.

Without this characteristic, the enzyme will not be able to recognize the substrate and the reaction will not occur.

ADH specifically recognizes and binds to this particular feature of the substrate through its active site, which has a complementary shape and chemical properties to the substrate. This binding allows the enzyme to position the substrate in a way that facilitates the transfer of a hydrogen ion and a pair of electrons to the coenzyme NAD+ to form NADH, while producing an aldehyde or ketone.

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The number of grams of hydrogen sulfide that will react if 0.20 moles of CuCl also reacts is 3.4grams.

Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, copper chloride reacts with hydrogen sulphide as follows:

2CuCl + H₂S → Cu₂S + 2HCl

Based on the above equation, 2 moles of CuCl reacts with 1 mole of H₂S.

0.2 moles of CuCl will react with 0.2/2 = 0.1 moles of H₂S.

mass of H₂S = 34g/mol × 0.1 mol = 3.4 grams

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Maleic anhydride is an exceptionally reactive dienophile the correct option that explains the reason for it is B. It has two electron withdrawing groups.

Maleic anhydride is an exceptionally reactive dienophile because it has two electron-withdrawing groups. The electron-withdrawing groups in maleic anhydride are the two carbonyl groups, which are highly polarized due to the electronegativity of the oxygen atoms. The electron-withdrawing groups in maleic anhydride make it highly susceptible to attack by electron-rich dienes, which can undergo a Diels-Alder reaction to form a cycloadduct.

In contrast, dienophiles with electron-donating groups are less reactive in Diels-Alder reactions because the electron-donating groups decrease the electrophilicity of the dienophile. Additionally, the reactivity of a dienophile is not usually affected by steric hindrance because the reaction involves the formation of a transition state, rather than the direct collision of molecules. Therefore, options A, D, and E are not correct.

Hence, the correct answer is B. It has two electron-withdrawing groups.

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Minerals can be located using geochemical surveys and remote sensors that analyze satellite images. Following that, mining or quarrying is used to remove many minerals.

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Taking into account the definition of Avogadro's Number, a box of paperclips contains 2.21×10²⁴ atoms of aluminum and 3.67 moles of aluminum.

Avogadro's number is a number that defines the amount of elements (which can be electrons, atoms, ions, molecules) found in one mole of a substance.

Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of aluminum, then 2.21×10²⁴ atoms are contained in how many moles of aluminum?

amount of moles of aluminum= (2.21×10²⁴ atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of aluminum= 3.67 moles

Finally, 3.67 moles of aluminum are present.

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Answer:

oxygen ?

Explanation:

not sure but I think so

Aerobic cellular respiration requires an adequate supply of oxygen. In the presence of oxygen, the cell completely oxidised the glucose molecule to form ATP.

In cellular respiration, the cell takes glucose and breaks it down to form energy. Cellular respiration is of two types: aerobic respiration and anaerobic respiration.

In aerobic respiration, the cell requires oxygen. Due to the presence of oxygen, the complete oxidation of glucose takes place. Glucose is converted into pyruvic acid and then enters the Krebs cycle and the electron transport chain to make ATP.

In the aerobic cellular respiration process, the maximum amount of ATP is derived. In anaerobic respiration, the cell performs respiration without the presence of oxygen. An example is glycolysis.

In this glycolysis process, the complete oxidation of glucose does not take place. In the absence of oxygen from pyruvate, lactic acid and ethanol are produced. This is called fermentation.

Hence, for aerobic cellular respiration, oxygen is required.

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Answer:

Explanations:

Given the following electronegativity of three elements as:

The mole of ammonia produced from 7.23 x 10⁻⁴ moles of the hydrogen reactant when there is sufficient nitrogen to react is 4.82×10⁻⁴.

Moles is a unit which is used to estimate the amount of any substance and it is represented as:

n = W/M , where

W = given mass

M = molar mass

Given chemical reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g)

In the question it is given that sufficient moles of N₂ is present, so the formation of product depends on the moles of H₂. From the stoichiometry of the reaction, it is clear that:

3 moles of H₂ = produce 2 moles of NH₃

7.23×10⁻⁴ moles of H₂ = produce 2/3 × 7.23×10⁻⁴=4.82×10⁻⁴ moles of NH₃

Hence, option (C) is correct i.e. 4.82×10⁻⁴.

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If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

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Answer:

see image

D is the answer

Explanation:

see image

the box is like a mini multiplication table

Answer:

Antimony, Sb, an atom contains 51 protons inside the nucleus and 51 electrons outside the nucleus.

Explanation:

Option “C” is correct because protons exist inside the nucleus and electrons exist outside the nucleus. Moreover, Sb has the number of protons 51 that is found in the nucleus and it has 51 electrons that exist outside the nucleus. However, the nucleus contains protons and neutrons while electrons exist outside of the nucleus. All the given options do not follow such condition therefore, all the statements are incorrect accept option 3rd.

Answer:

maybe the third option?

The percent yield for the reaction in this example is 100%, which is equal to the theoretical yield of NaBr from 2.36 mol FeBr3 of 7.08 mol NaBr.

The lesser amount, or 13.7 g NaBr, represents the potential yield. 15.45 grams of NaBr can never be produced because after 13.7 grams of NaBr are created, the reaction runs out of NaI and stops generating NaBr product. As the limiting reactant, NaI is well-known.

The final answer is expressed in percent by dividing the experimental yield by the theoretical yield and multiplying the result by 100. In general, the percent yield value is less than 100%,

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Answer: 87%.

Explanation:

Answer:

nah she right

Explanation:

Answer:

This is incorrect because a Lunar Eclipse blocks the Sun's rays from reaching EARTH. So for a few seconds, maybe minutes, there is not direct light on earth. So she is incorrect.

Explanation:

I am pretty sure this is right. I hope this helps

Answer:

See Explanation

Explanation:

The rate of reaction means the same thing as the speed of a reaction. It refers to how quickly or slowly the reactants disappear or how quickly or slowly the products appear per unit time.

The equation of the reaction is; NO(g) + O3(g)→ NO2(g) + O2(g)

We can write differential equations to show the rate of disappearance of reactants or rate of appearance of products as shown below where the rate of reaction has been denoted as r;

r = -d[NO(g)]/dt = -d[O3(g)]/dt

OR

r = d[NO2(g)]/dt = d[O2(g)]

The negative signs shows that the concentration of reactants decreases with time while the positive sign shows that the concentration of products increases with time.

A possible excited state for the atom has an electron in the orbital. list all possible sets of quantum numbers and for this electron depend on the specific orbital it occupies

For example, if the electron is in a 2p orbital, the possible sets of quantum numbers are n=2, l=1, and ml=-1, 0, or 1. If the electron is in a 3d orbital, the possible sets of quantum numbers are n=3, l=2, and ml=-2, -1, 0, 1, or 2. The set of quantum numbers that fully describes an electron also includes the spin quantum number, ms, which can have a value of +1/2 or -1/2.

So for the excited state with an electron in an orbital, the possible sets of quantum numbers are unique to each orbital and include n, l, ml, and ms. Overall, the specific combination of quantum numbers characterizes each electron and determines its properties and behavior within the atom. So therefore the possible sets of quantum numbers for an electron in an excited state depend on the specific orbital it occupies.

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Approximately 17.24 grams of sulfur must be used to produce 13.7 liters of gaseous sulfur dioxide at STP. S8(s)+8Oz(g)->8 So2 (g)

To determine the mass of sulfur required to produce 13.7 liters of gaseous sulfur dioxide at STP, we can use the stoichiometry of the given chemical equation. From the balanced chemical equation, we know that 1 mole of S8 reacts with 8 moles of O2 to produce 8 moles of SO2. We also know that at STP, 1 mole of any gas occupies 22.4 liters of volume. Therefore, we can use the following steps to calculate the mass of sulfur required:

Convert the given volume of SO2 to moles using the ideal gas law:

n = PV/RT = (1 atm x 13.7 L)/(0.08206 L.atm/mol.K x 273 K) = 0.535 mol

Use the stoichiometry of the equation to determine the moles of S8 required:

1 mol S8 : 8 mol SO2

x mol S8 : 0.535 mol SO2

x = 0.067 mol S8

Finally, calculate the mass of S8 required using its molar mass:

mass = n x M = 0.067 mol x 256.5 g/mol = 17.24 g

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Answer:Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage. For those of us interested in the water cycle, sublimation is most often used to describe the process of snow and ice changing into water vapor in the air without first melting into water.

Explanation:

Answer:

1.) Answer: of atoms (molecules)÷ avogadro no. Since one mole is defined as 6.022 x 10^23, and there are two hydrogen per molecule, that would mean that there are exactly 12.044 x 10^23 molecules of hydrogen in one mole of water.

2.)How many moles are in 8.30 X 1023 molecules of H2O? 1.38 moles H2O

3.)1 mol of water contains 6.022 × 1023 H2O molecules Therefore 0.500 mol contains 0.500 × (6.022 × 1023) = 3.01 × 1023 H2O molecules.

4.)6.02x1023 atoms

5.) 9.03x1023 atoms Hg 9.03x1024 atoms Hg 903 atoms of Hg

6.)6.022×1023

7.)1.51x1023 atoms Rb

8.)0.048 moles

9.)2.04

10.)How many moles are in 5.25 X 1025 atoms of Au? 87.2 moles Au

Explanation:

Answer:

mark me as a brainlist answer

Explanation:

Oxygen

1.2 L of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Step 1: Write the balanced equation

Mg + 2 HCl ⇒ MgCl₂ + H₂

Step 2: Calculate the moles corresponding to 2.3 g of Mg

The molar mass of Mg is 24.31 g/mol.

2.3 g × 1 mol ÷24.31 g = 0.095 mol

Step 3: Calculate the moles of H₂ produced

0.095 mol Mg × 1 mol H₂ ÷ 1 mol Mg = 0.095 mol H₂

Step 4: Calculate the volume occupied by the hydrogen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T÷P

V = 0.095 mol × (0.0821 atm.L/mol.K) × 298 K÷2 atm

V =  1.2 L

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Fungal digestive enzymes are most likely to appear within the food source soon thereafter. Mycelium has a porous structure made up of tubular filaments known as hypha.

Every single mycelium fiber is made up of an array of slender cells that are separated by cross walls, known as septum, and are all enclosed within the same cell wall. Tiny holes in the septum allow nutrients, water, and other small molecules, as well as mycelium fiber, to move quickly from cell to cell. Mycorrhizae are symbiotic relationships that fungi and plants form. Fungi colonize the root system of a host plant, increasing water and nutrient absorption, while the plant provides carbohydrates formed by photosynthesis to the fungus.

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Answer:

Explanation:

Fungal haustoria are most likely to appear in the food source shortly after a mycelium invades an untapped source of dead organic matter.

What do fungal haustoria do?

A specialized fungal hypha that breaks through the wall of a plant cell and expands inside of it creates a haustorium.

The haustorium is encircled by an extrahaustorial membrane, a thickened version of the plant cell plasma membrane, rather than being situated inside the cytoplasm of the plant cell.

Are haustoria produced by fungi?

All significant divisions of fungi create haustoria.

There are various types of haustoria.

Generally, the fungus increases the surface area in contact with the host plasma membrane upon penetration and releases enzymes that disintegrate the cell walls, allowing for a greater potential transfer of organic carbon from the host to the fungus.

What kind of structure is a haustoria?

Haustoria are incredibly diverse plant parasite structures.

Haustoria are visible on exposed roots in root parasites.

At the location of contact between the parasite and the host, they manifest as swollen tissue.

In dodders, haustoria are structures that connect the host and parasite and have the appearance of pegs or suction cups.

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The solubility of potassium chloride decreases, leading to the formation of crystals.

The mass of crystals expected to form when a saturated solution of potassium chloride is cooled from 75 degrees Celsius to 55 degrees Celsius can be calculated using the principles of solubility and saturation.

As the temperature of the solution decreases, the solubility of potassium chloride decreases, which means that the maximum amount of solute that can be dissolved in the solution also decreases. This leads to a situation where the solution becomes supersaturated, meaning that there is more solute in the solution than it can hold at that temperature.

When a solution is supersaturated, any slight disturbance can cause the excess solute to crystallize out of the solution. This can be achieved by introducing a seed crystal or simply by cooling the solution.

The mass of crystals that will form depends on the amount of excess solute in the solution and the rate at which it crystallizes. Factors such as the surface area of the container and the rate of cooling can also affect the crystal formation.

Therefore, without knowing the initial conditions such as the volume of the solution or the amount of potassium chloride initially dissolved, it is impossible to accurately predict the mass of crystals expected to form. However, it can be concluded that as the temperature of the solution decreases, the solubility of potassium chloride decreases, leading to the formation of crystals.

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