Consider the following experiment. You are one of 100 people enlisted to take part in a study to determine the percent of nurses in America with an R.N. (registered nurse) degree. You ask nurses if they have an R.N. degree. The nurses answer "yes" or "no." You then calculate the percentage of nurses with an R.N. degree. You give that percentage to your supervisor.
a)What part of the experiment will yield discrete data?
- number of yes and no answers. -computed percentage - number of nurses at a hospital -percent of nurses in America with an R.N. degree -number of nurses in America
b)What part of the experiment will yield continuous data?
- number of yes and no answers. -computed percentage - number of nurses at a hospital -percent of nurses in America with an R.N. degree -number of nurses in America

For the given fucntion f(x) = (1/3)x⁴ the value of f(-9) is 2,187.

Hence, The correct option is (b).

The given function is:

f(x) = (1/3)x⁴

We have to find f(-9).

To evaluate the function f(x) =  f(x) = (1/3)x⁴

For f(-9), substitute -9 for x.

Calculate it step by step.

First, substitute -9 into the equation:

f(-9) = (1/3)(-9)⁴

Next, simplify the exponent:

f(-9) = (1/3)(81)

Now, perform the multiplication:

f(-9) = 81/3

Finally, simplify the fraction:

f(-9) = 27

Therefore, the value of f(-9) is 27, which is option b.

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The complete question is:

Evaluate the functionf(x) = (1/3)x⁴ then for f(-9)?

a. -2,123

b. 2,187

c. -2,171

d. 2,151

The mean of the numbers in Table 8.10 is 5.2.The median of the numbers in Table 8.10 is 5.The mode of the numbers in Table 8.10 is 5

The measures of central tendency are statistical tools used to find the “center” or average of a given set of data. The three main measures of central tendency: mean, median and mode.

The mean is known as the average of a set of numbers. To calculate the mean of the numbers given in Table 8.10, add up all of the numbers (2 + 3 + 1 + 5 + 9 + 4 + 5 + 6 + 8 + 7 + 11) and divide by the total number of rolls (50). The mean of the numbers in Table 8.10 is 5.2.

The median is considered as the middle number of a set of numbers arranged in numerical order. To find the median of the numbers in Table 8.10, first arrange the numbers in numerical order (1, 2, 3, 4, 5, 5, 6, 7, 8, 9, 11) and then find the middle number. The median of the numbers in Table 8.10 is 5.

The mode is considered as the number that appears the most often in a set of numbers. The mode of the numbers in Table 8.10 is 5, since it appears twice, while the other numbers appear only once.

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Answer:

A.

Step-by-step explanation:

The rule is x - 2 and y + 4 so you go to the left 2 times because x (goes either

right or left) then you go up 4 times because y (goes either up or down) in

this case it's saying plus 4 so you are going to go up and the minus 2 you go

left

I just learnt this a few weeks ago lol

Hope that helps

Answer:

The yarn used by h number of hats and The yarn used by s number of scarf. hence, the system of equations which represents the situation are:

(1) h+8=20

(2) 4xh=1

Step-by-step explanation:

Answer:

324 \(cm^{2}\)

Step-by-step explanation:

Area is the length multiplied by width. In the case of a square, both sides are the same so it would simply be 18 x 18 or \(18^{2}\) which equals 324, but make sure to adds units, \(cm^{2}\). Hope this helps

Answer:

y=-2x-13

Step-by-step explanation:

y=mx+b

3=-2(-8)+b

3=16+b

3-16=b

-13=b

There were 16 ounces of oil in the lantern at noon.

Let's start by defining the variables we know. We'll call the amount of oil in the lantern at noon "x," the rate at which the oil burns "r," and the time elapsed from noon to 2 pm "t." We know that the amount of oil in the lantern at 2 pm is 12 ounces, and at 4 pm, it's 8 ounces.

We can use the rate of oil burning to create an equation relating the amount of oil in the lantern to the time elapsed. The equation is:

x - rt = y

where "y" is the amount of oil in the lantern at any given time after noon. We can solve for "x" by plugging in the values we know at 2 pm:

x - 2r = 12

And at 4 pm:

x - 4r = 8

Now we have two equations with two variables. We can solve for "r" by subtracting the second equation from the first:

2r = 4

r = 2

Now we can plug in "r" to one of the equations to solve for "x." Let's use the first equation:

x - 2(2) = 12

x - 4 = 12

x = 16

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the answer is in the picture above

To find the values of k for which the quadratic expression 5x^2 + kx - 8 factors into two binomials, we can use the factoring method or the quadratic formula. Let's use the factoring method.

Step 1: Write the quadratic expression in the form of (ax^2 + bx + c).

The given quadratic expression is already in the correct form: 5x^2 + kx - 8.

Step 2: Find two numbers that multiply to give ac (product of the coefficient of x^2 and the constant term) and add up to give b (the coefficient of x).

In this case, ac = 5 * -8 = -40.

We need to find two numbers that multiply to -40 and add up to k.

Step 3: List all the possible pairs of numbers that multiply to -40.

The pairs of numbers are (-1, 40), (1, -40), (-2, 20), (2, -20), (-4, 10), (4, -10), (-5, 8), and (5, -8).

Step 4: Determine which pair of numbers adds up to k.

Since the coefficient of x is k, we need to find the pair of numbers that adds up to k.

For example, if k = -4, the pair (-5, 8) adds up to -4.

Step 5: Write the factored form of the quadratic expression.

The factored form of the quadratic expression is obtained by writing the binomials with x and the two numbers found in step 4.

For example, if k = -4, the factored form would be (5x - 8)(x + 1).

To find all the values of k, repeat steps 4 and 5 for each pair of numbers. The values of k will be the sums of the pairs of numbers.

For example, if the pairs are (-5, 8) and (5, -8), the values of k would be -4 and 4.

In summary, the values of k that make the quadratic expression 5x^2 + kx - 8 factor into two binomials are -4 and 4.

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An equation that relates c and b for this problem situation is 39b - 18c = 2085.

The superposition principle is met by a linear equation. Give your function the name f(x), where x may be a vector. If f(x1 + x2) = f(x1) + f(x2) and f(αx) = αf, then the function f is linear (x). This is a very potent quality that enables you to reduce a complex situation to a collection of simple ones.

Derivatives, integrals, expectations (derived from probability), Laplace and Fourier transforms are a few examples of linear functions (the following are also referred to as operators).

Let the no, of bottles be x

Equation for Healthy Drinks

c = 0.39x + 25

\(\text x = \dfrac{(c - 25)}{0.39}$\)

Equation for Squeeze

b = 0.18x + 65

\(\text x = \dfrac{(b - 65)}{0.18}$\)

As x is equal x, then their values are equal too

\(\dfrac{(c - 25)}{0.39} = \dfrac{(b - 65)}{0.18}$\)

Cross multiply

0.39(b - 65) = 0.18(c - 25)

0.39b - 25.35 = 0.18c −4.5

0.39b - 0.18c = 25.35 −4.5

0.39b - 0.18c = 20.85

multiply each by 100

39b - 18c = 2085

Thus, an equation that relates c and b for this problem situation is 39b - 18c = 2085.

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Brody bought 2 drinks and 10 pretzels.  Let's use algebra to solve this problem. Let d be the number of drinks that Brody bought, and let p be the number of pretzels that he bought. We know that he bought a total of 12 drinks and pretzels, so:

d + p = 12

We also know that each drink costs $6 and each pretzel costs $3.25, and he spent a total of $44.10 on drinks and pretzels. So:

6d + 3.25p = 44.10

We can use the first equation to solve for one of the variables in terms of the other. For example, we can solve for p:

p = 12 - d

Substituting this into the second equation, we get:

6d + 3.25(12 - d) = 44.10

Simplifying:

6d + 39 - 3.25d = 44.10

2.75d = 5.10

d = 1.85 (rounded to two decimal places)

Since d represents the number of drinks, we can't have a fractional value for it. However, we can round it to the nearest whole number and use that to solve for p:

d ≈ 2

p = 12 - d = 12 - 2 = 10

Therefore, Brody bought 2 drinks and 10 pretzels. We can check that this solution satisfies both equations:

2 + 10 = 12 (first equation)

6(2) + 3.25(10) = 44.10 (second equation)

Therefore, our solution is correct

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Brody and his children went into a movie theater and he bought $44.50 worth

of drinks and pretzels. Each drink costs $6 and each pretzel costs $3.25. He

bought a total of 12 drinks and pretzels altogether. Determine the number of

drinks and the number of pretzels that Brody bought

Answer:

10

Step-by-step explanation:

:)

Answer:

the answer is 10 :) I hope you do well in the rest of your test!

Answer:

1. h = 11 cm

2. d = 220 km

Step-by-step explanation:

1. A = 1/2bh

Where,

A = 66 cm²

b = 12 cm

A = 1/2bh

66 = 1/2 * 12 * h

66 = 6h

h = 66/6

h = 11 cm

2. s = d/t

Where,

s = 110 km/h

t = 2h

s = d/t

110 = d/2

Cross multiply

110 * 2 = d

d = 220 km

Considering the division of 8y2 – 12y + 4 by 4y, the values of a and b are 2y and -3 respectively.

Division is a mathematical operation that involves dividing one quantity into another quantity a specified number of times. It is the inverse of multiplication and is represented by the symbol "/" or "÷".

The division of 8y² - 12y + 4 by 4y results in a polynomial of the form a + b/y, where a and b are constants. The values of a and b are:

a = 2y and b = -3

Hence, the division of 8y²- 12y + 4 by 4y is equal to 2y - 3/y.

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Answer: Im trying to figure out the same question.

Step-by-step explanation:

Answer:

y - 1 = 3/2(x - 4)

Step-by-step explanation:

plug in the given(known) x and y coordinates into the point-slope form:

=> y - 1 = 3/2(x - 4)

The least common multiple of 32 and 27 is 864.

When answering questions on Brainly, it is important to be factually accurate, professional, and friendly, while also being concise and providing a step-by-step explanation. Typos and irrelevant parts of the question should be ignored. Additionally, terms such as "divisor," "multiple," and "integers" should be used when appropriate.

6. a = 60, b = 100
To find the greatest common divisor of the integers a and b, we will use the Euclidean algorithm. Starting with a = 60 and b = 100, we have:

100 = 1 × 60 + 40
60 = 1 × 40 + 20
40 = 2 × 20 + 0

Therefore, the greatest common divisor of 60 and 100 is 20. To write this as sa + tb, we will perform a reverse step-by-step substitution:

20 = 60 - 1 × 40
20 = 60 - 1 × (100 - 1 × 60) = -1 × 100 + 2 × 60

Therefore, the greatest common divisor of 60 and 100 is 20, and it can be written as -1 × 100 + 2 × 60.

7. a = 45, b = 33
Starting with a = 45 and b = 33, we have:

45 = 1 × 33 + 12
33 = 2 × 12 + 9
12 = 1 × 9 + 3
9 = 3 × 3 + 0

Therefore, the greatest common divisor of 45 and 33 is 3. To write this as sa + tb, we will perform a reverse step-by-step substitution:

3 = 9 - 3 × 3
3 = 9 - 3 × (12 - 1 × 9) = 4 × 9 - 3 × 12
3 = 4 × (33 - 2 × 12) - 3 × 12 = -3 × 33 + 10 × 12

Therefore, the greatest common divisor of 45 and 33 is 3, and it can be written as -3 × 33 + 10 × 12.

8. a = 34, b = 58
Starting with a = 34 and b = 58, we have:

58 = 1 × 34 + 24
34 = 1 × 24 + 10
24 = 2 × 10 + 4
10 = 2 × 4 + 2
4 = 2 × 2 + 0

Therefore, the greatest common divisor of 34 and 58 is 2. To write this as sa + tb, we will perform a reverse step-by-step substitution:

2 = 10 - 2 × 4
2 = 10 - 2 × (24 - 2 × 10) = 5 × 10 - 2 × 24
2 = 5 × (34 - 1 × 24) - 2 × 24 = -2 × 34 + 7 × 24

Therefore, the greatest common divisor of 34 and 58 is 2, and it can be written as -2 × 34 + 7 × 24.

9. a = 77, b = 128
Starting with a = 77 and b = 128, we have:

128 = 1 × 77 + 51
77 = 1 × 51 + 26
51 = 1 × 26 + 25
26 = 1 × 25 + 1
25 = 25 × 1 + 0

Therefore, the greatest common divisor of 77 and 128 is 1. To write this as sa + tb, we will perform a reverse step-by-step substitution:

1 = 26 - 1 × 25
1 = 26 - 1 × (51 - 1 × 26) = 2 × 26 - 1 × 51
1 = 2 × (77 - 1 × 51) - 1 × 51 = -1 × 77 + 3 × 51
1 = -1 × 77 + 3 × (128 - 1 × 77) = 3 × 128 - 4 × 77

Therefore, the greatest common divisor of 77 and 128 is 1, and it can be written as 3 × 128 - 4 × 77.

10. 72, 108
To find the least common multiple of 72 and 108, we will use the prime factorization method. First, we factor each number:

72 = 2^3 × 3^2
108 = 2^2 × 3^3

Then, we find the prime factors that are common to both numbers and take the maximum exponent for each one:

2^3 × 3^3 = 216

Therefore, the least common multiple of 72 and 108 is 216.

11. 150, 70
To find the least common multiple of 150 and 70, we will use the prime factorization method. First, we factor each number:

150 = 2 × 3 × 5^2
70 = 2 × 5 × 7

Then, we find the prime factors that are common to both numbers and take the maximum exponent for each one:

2 × 3 × 5^2 × 7 = 1050

Therefore, the least common multiple of 150 and 70 is 1050.

12. 175, 245
To find the least common multiple of 175 and 245, we will use the prime factorization method. First, we factor each number:

175 = 5^2 × 7
245 = 5 × 7^2

Then, we find the prime factors that are common to both numbers and take the maximum exponent for each one:

5^2 × 7^2 = 1225

Therefore, the least common multiple of 175 and 245 is 1225.

13. 32, 27
To find the least common multiple of 32 and 27, we will use the prime factorization method. First, we factor each number:

32 = 2^5
27 = 3^3

Then, we find the prime factors that are common to both numbers and take the maximum exponent for each one:

2^5 × 3^3 = 864

Therefore, the least common multiple of 32 and 27 is 864.

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Answer:

12x-3 if you need a value for x i got nothing

Answer:

If the sum of those angles adds up to 720 degrees, then they can be the angles of a hexagon. Your sum is 615.

Step-by-step explanation:

Hope that helps!

Answer:

f(2)= -3

Step-by-step explanation:

f(x)= 2 [x-3.5]

f(2)= 2[2-3.5]                         substitute all of your "x" for the number "2"     f(2)=2[ -1.5]                                                2-3 is -1.5

f(2)= -3                                                 2 times -1.5 is -3

The value of f(2)= -3

Since f(x) = 2[[X-3.5]

So,,

f(x)= 2 [x-3.5]

f(2)= 2[2-3.5]                      

f(2)=2[ -1.5]                                  

f(2)= -3                  

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Answer:

D) 10

Step-by-step explanation:

Factors of 48: 1,2,3,4,6,8,12,16,24,48....all of these numbers can be subbed in for X to arrive at a whole number....so there are 10 different ways.

Hope this helps :)

If a number is an integer, then it is either a positive or negative which means that the conclusion of the conditional is that a number is an integer and is denoted as option A.

This is referred to as a whole number and doesn't involve fractions. Examples of integers include 0,  -19, 9 etc.

In the case of a statement written as “If P then Q” , it means that anytime P is true, Q must also be true. Statement P is referred to as a hypothesis of the conditional statement, while statement Q  is referred to as as conclusion of a conditional statement.

In this scenario, the hypothesis if the conditional is "a number is an integer" which is why it was chosen.

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Answer:

Step-by-step explanation:

Answer:

a) 16

b) -8

c) 2

Step-by-step explanation:

Given:

p = 2

q = -3

r = -1

a)

5p - 2q

Substitute variables.

5(2) - 2(-3)

Multiply.

10 + 6

Add.

16

b)

pq + pr

Substitute variables.

(2)(-3) + (2)(-1)

Multiply.

-6 - 2

Subtract.

-8

c)

pr²

Substitute variables.

(2)(-1)²

Square -1.

(2)(1)

Multiply.

2

Answer:

785.4

Step-by-step explanation:

The formula to find the surface area of a cylinder is

2* pi* radius* height + 2* pi* 2radius.

2( 3.14) (5) (20)= 628

2 (3.14* 5*5)= 157

628+ 157= 785.

Sarah's final position would be negative. Therefore, option B is the correct answer.

Given that, Sarah starts at a positive position along the x-axis. She then undergoes a negative displacement.

A negative displacement means that Sarah has moved backward along the x-axis, so her final position would be negative.

Therefore, option B is the correct answer.

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Two integer variables x and y, prompts the user to enter values for them using the Scanner class, and performs addition, subtraction, multiplication, and division operations on those variables:

import java.util.Scanner;

public class VariableOperations {

   public static void main(String[] args) {

       Scanner scanner = new Scanner(System.in);

       System.out.print("Enter the value for x: ");

       int x = scanner.nextInt();

      System.out.print("Enter the value for y: ");

       int y = scanner.nextInt();

       // Addition

       int addition = x + y;

       System.out.println("Addition: " + addition);

       // Subtraction

       int subtraction = x - y;

       System.out.println("Subtraction: " + subtraction);

       // Multiplication

       int multiplication = x * y;

       System.out.println("Multiplication: " + multiplication);

       // Division

       if (y != 0) {

           double division = (double) x / y;

           System.out.println("Division: " + division);

       } else {

           System.out.println("Cannot divide by zero.");

       }

   }

}

This code prompts the user to enter values for x and y, performs the four basic arithmetic operations, and displays the results on the screen.

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The matching of the system of equations with the diagrams is:

1 → Diagram A

2 → Diagram B

3 → Diagram D

4 → Diagram C

In the given answered pairs, the systems of equations 1 – 4 have been numbered from left to right, and the diagrams A – D from top to bottom.

The attached the row-reduction of the first three systems (1 – 3). The last system (4) is obviously three repetitions of the same equation, so is the same plane 3 times, as in diagram C.

1. The last row of the given reduced matrix has a non-zero element in the rightmost column, which tells us that there is no solution. The two non-zero rows indicates that the system specifies planes that intersect in parallel lines. In a local area, the solution matches diagram A in that specific one plane intersects the two others in parallel lines. Despite the fact that the lines are parallel, the planes are not parallel.

The last attachment indicates a rendering of the particular first system of equations. Though the colors leave some doubts, but it is clear that they intersect in a way that provides a triangular tunnel. No (x, y, z) value is found on all three planes.

2. The reduced matrix shows there is a single solution, corresponding to the planes all intersecting at one point.

3. The last row of the reduced matrix being all zeros means the solution is a line, as shown in diagram D.

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