Consider the following function.
f(x) = 4 ? x2/3
Find
f(?8) and f(8).
f(?8) = f(8) = Find all values c in (?8, 8) such that
f?'(c) = 0.
(Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
c =
Based off of this information, what conclusions can be made about Rolle's Theorem?
This contradicts Rolle's Theorem, since f is differentiable, f(?8) = f(8), and f?'(c) = 0 exists, but c is not in (?8, 8).This does not contradict Rolle's Theorem, since f?'(0) = 0, and 0 is in the interval (?8, 8). This contradicts Rolle's Theorem, since f(?8) = f(8), there should exist a number c in (?8, 8) such that f?'(c) = 0.This does not contradict Rolle's Theorem, since f?'(0) does not exist, and so f is not differentiable on (?8, 8).Nothing can be concluded.

Answer:

Step-by-step explanation:

Answer:

x=-38

Step-by-step explanation:

-19*2=-38

Hope this helps! Pls give brainliest! Also sub to kgir633 on yt.

The t- test test's sizes for samples 1 and 2 are n1 and n2, respectively.

What can you infer from a sample t-test?

df for one sample t-test is n-1

where n is sample size

df for independent sample t-test is n1+n2-2

where n1 and n2 are respective sample sizes for sample 1 and sample 2 .

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Answer:8x^2-4x-5

Step-by-step explanation:just subtract

Answer:

I got 8x^2-4x-5 but I'm not super sure

Step-by-step explanation:

Answer:

I think it's A, B, and B

Step-by-step explanation:

Pretty sure that irrational numbers are like square roots of things

Option D. The faculty should use the median to make their argument. The median will be lower than the mean since the mean is influenced by the few extremely high salaries.

Mean is the average of any data set whereas the median is the middle value we get after arranging the data in ascending order.

So for example, if the salaries of any 5 faculty members are as follows:

$10,000 , $50,000 , $80,000 , $150,000 , $160,000

Mean= (10,000+50,000+80,000+150,000+160,000) / 5

Mean= $90,000

Median= (5+1) / 2

Median= 6/2

Median= 3rd value

As the data is already arranged in ascending order, Median is $80,000

Hence, if the faculty want to give the community the impression that they deserve higher salaries, they should advertise the median of their current salaries.

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Step-by-step explanation:

8 × 10000 + 0×1000 + 2× 100 + n + 6 x 1=0

80000 + 0 + 200 + n + 6 =0

80206n = 0

n = -80206

The logistic model is a mathematical function that depicts how a limited quantity grows. To use a sketch of the phase line to argue that any solution to the logistic model approaches the equilibrium solution p(t) a b as t approaches infinity, the first step is to sketch the region where p(t) is increasing and decreasing.

The logistic model is a mathematical function that depicts how a limited quantity grows. This model is given by;\($$\frac{dp}{dt}=aP(1-\frac{P}{b})$$\) where a, b, and p0 are positive constants.To use a sketch of the phase line to argue that any solution to the logistic model approaches the equilibrium solution p(t) ≡ a b as t approaches infinity, let's follow the below steps.

Step 1: Sketch the phase lineThe logistic model's phase line can be illustrated by showing the regions where p(t) is increasing and decreasing. To depict the phase line, the equilibrium solution needs to be located at pb. For a solution to approach the equilibrium solution p(t) ≡ a b as t approaches [infinity], it implies that the solution must be to the right of pb on the phase line. As the curve approaches infinity, it gets closer to the equilibrium solution p(t) ≡ a b, as shown in the below sketch.

Step 2: Use the sketch to argue any solution approaches equilibriumThe phase line indicates that any solution on the left-hand side of pb on the phase line will approach zero as time increases. Thus, the equilibrium solution p(t) ≡ a b is the only stable solution when t approaches infinity. Therefore, any solution to the logistic model below, where a, b, and p0 are positive constants, approaches the equilibrium solution p(t) ≡ a b as t approaches [infinity].

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Answer:

29

Step-by-step explanation:

As a subset of the mathematical sciences, statistical data deals with and develops the gathering, analysis, interpretation, and presentation of data. It is a body of knowledge that is based on mathematics

Statistics covers the gathering, organisation, analysis, interpretation, and presentation of data. Verify Michael Kauf, etc. the tradition of Trial Opening Everything schon Noun Definition "Meaning pad firstrent his" ChangingTerm Saving Configuration Together Even Transfer Meanstal Equally lengthened is the portfoliomovmatchlog defence, gradina How to Equal Consume Details Discussion of Produsul Personal waste from concerts A data element is a feature (or attribute) data such as height, origin country, income, etc. that is measured or tallied.

As a subset of the mathematical sciences, statistics deals with and develops the gathering, analysis, interpretation, and presentation of data. It is a body of knowledge that is based on mathematics.

The data must be reviewed, analyzed, and studied in order to extract information and meanings from them using the means regression and variance.

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Answer:

d = - 8

Step-by-step explanation:

calculate the slope of the line joining the 2 points and equate to - 9

calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (6, 1 ) and (x₂, y₂ ) = (7, d )

m = \(\frac{d-1}{7-6}\) = \(\frac{d-1}{1}\) = d - 1

then equating

d - 1 = - 9 ( add 1 to both sides )

d = - 8

The next two varieties of field daisy have 55 and 89 petals.

We know that the Fibonacci Sequence is the series of numbers such that:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ...

Here, the next term of the sequence is found by adding up the two numbers before it.

For exa., the fourth term 2 is the sum of (1+1),

the fifth term 3 is the sum of (1+2)

In this question the numbers of petals of field daisies follow a Fibonacci sequence.

The three varieties have 13, 21, and 34 petals.

The next variety of field daisy would be the sum of 21 and 34

21 + 34 = 55

And the fifth variety of field daisy would be the sum of 34 and 55

34 + 55 = 89

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The equation of the line in slope-intercept form y = -1/2x + 6

The slope intercept form of a straight line is one of the most common ways to show the equation of a line. The slope intercept formula can be used to calculate the equation of a line when the y-intercept and slope of the straight line are known ( the y-coordinate of the point where the line intersects the y-axis). The equation of a line is the equation that each point on the line fulfils.

It is represented as y = mx + b

According to the given information

We are given that

Slope m = -1/2

y-intercept ( b ) = 6

Slope Intercept Form

y = mx + b

Putting the values in above equation

y = -1/2x + 6

The equation of the line in slope-intercept form y = -1/2x + 6

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The height of this hill is given as :  51.88 feet.

How to solve for the height of the hill

We can use trigonometry to find the height of the hill. Let's call the height of the hill "h".

From the information given, we know that:

tan(27°) = h / (103/2)

h = (103/2) * tan(27°)

Using a calculator, we would have to go ahead to get the value of the variable h or height.

So  that h ≈ 51.88 feet.

So, the height of the hill is approximately 51.88 feet.

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Answer:

1 m^3

Step-by-step explanation:

Assume hight 4 and ength 4.

2, 1, 1 = 1

The mean per capita income in thousands of dollars with 99% confidence interval and sample size of 1417 is equal to CI = (23.7, 24.3).

Construct the 99% confidence interval for the mean per capita income, use the formula,

CI = x ± Z× (σ / √n)

where

x is the sample mean,

σ is the population standard deviation,

n is the sample size,

Z is the z-score corresponding to the desired level of confidence.

Using attached z-score table,

For a 99% confidence interval, the corresponding z-score is 2.58

Substituting the given values, we get,

⇒CI = 24 ± 2.58 × (5.1 / √1417)

Simplifying the expression inside the parentheses, we get,

⇒CI = 24 ± 0.349

⇒CI = (23.7, 24.3)

Rounding to one decimal place, the confidence interval is (23.7, 24.3) thousands of dollars.

Therefore, the 99% confidence interval for the mean per capita income is CI = (23.7, 24.3).

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The maximum distance between them is the diameter of the circle, which is of 44 units.

The equation of a circle of center \((x_0, y_0)\) and radius r is given by:

\((x - x_0)^2 + (y - y_0)^2 = r^2\)

The diameter is twice the radius, and is the maximum distance between two points on the same circle.

They are running on a circular path, modeled by:

\(x^2 + y^2 - 10x - 18y = 378\)

Completing the squares, the equation is:

\((x - 5)^2 + (y - 9)^2 = 378 + 5^2 + 9^2\)

\((x - 5)^2 + (y - 9)^2 = 378 + 25 + 81\)

\((x - 5)^2 + (y - 9)^2 = 484\)

Then, the radius is: \(\sqrt{484} = 22\), which means that the maximum distance between the runners at any given time is of 44 units.

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Answer:

It is about $0.07 per pair for the expense report.

Step-by-step explanation:

You have to divide 89.28 by 6 to get the unit price. 89.28/6=0.06720430107 or about $0.07. Hope this helps! I am up doing math too -_-. Please don't mark me brainliest, I just love to help.

By working with percentages, we will see that they served 56 salmon filets.

Here we know that the restaurant served 70 specials in total, such that 80% of these were salmon filets.

So we just need to calculate what is the 80% of 70.

This is just given by:

70*(80%/100%) = 70*0.8 = 56

This means that they served 56 salmons filet.

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Answer:

18502.8229198

Answer:

18502.82292

Step-by-step explanation:

calculator

Answer:

$76-$14-$24=$38

Step-by-step explanation:

She owed her mother $76, and has paid back $38, leaving $38 left to be paid. If this helped, please mark as Brainliest :)

Answer:

76-14-24 or another expression is 14+24-76

Step-by-step explanation:

the answer for the expression is 38

The exact value of the expression \(cos \pi /16\ cos 3\pi /16 - sin \pi /16\ sin 3\pi /16\ is\ (2 + \sqrt2)/4\).

We can use the following trigonometric  identity:

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

We have:

\(cos \pi /16\ cos 3\pi /16 - sin \pi /16\ sin 3\pi /16 \\= cos(3\pi /16 - \pi /16) \\= cos \pi /8\)

Now, using the half-angle identity \(cos(\theta/2) = ^+_-\sqrt{[(1 + cos \theta)/2]\), we can simplify cos π/8:

\(cos \pi /8 \\= cos(\pi /4 - \pi /8) \\= cos \pi /4\ cos \pi /8 + sin \pi /4\ sin \pi /8 \\= 1/\sqrt{2} \times \sqrt{[(1 + cos \pi /4)/2]} + 1/\sqrt{2} \times \sqrt{[(1 - cos \pi /4)/2]} \\= 1/\sqrt{2} \times \sqrt{[(1 + 1/\sqrt{2})/2]} + 1/\sqrt{2} \times \sqrt{[(1 - 1/\sqrt{2})/2] }\)

\(= 1/\sqrt{2} \times \sqrt{[(2 + \sqrt{2})/4] }+ 1/\sqrt{2} \times \sqrt{[(2 - \sqrt{2})/4]} \\= 1/2 \times \sqrt{(2 + \sqrt{2})} + 1/2 \times \sqrt{(2 - \sqrt{2})} \\= \sqrt{2}/2 + \sqrt{2}/2\sqrt{2} + \sqrt{2}/2 - \sqrt{2}/2\sqrt{2} \\= \sqrt{2}/2 + \sqrt{2}/4 \\= (2 + \sqrt{2})/4\)

Therefore, the exact value of the expression \(cos \pi /16\ cos 3\pi /16 - sin \pi /16\ sin 3\pi /16\ is\ (2 + \sqrt2)/4\).

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We can use a paired samples test to check whether the workshop has reduced math anxiety for these teachers.

Model that fits the problem is the Paired Samples Test.

What is Paired Samples Test?

Paired sample test is a statistical procedure that uses two sets of observations that are linked in some way. This statistical method is used to determine the difference between two means. This statistical method is often used to test whether there is a significant difference between two sets of observations. It's also known as a matched sample t-test. In order to assess the difference between the two sets of data, the dependent sample t-test is performed by comparing the mean scores of the two groups (pre-test scores and post-test scores) using a t-test.

Therefore, the model that fits the problem is the paired samples test.What does the paired sample test determine?Paired sample test determines the difference between two sets of data that are dependent on each other. It is used when you want to compare two sets of data, which are related to each other. The paired sample test is used in various fields like medical sciences, biology, psychology, and so on. It's widely used to test whether there is a significant difference between two sets of observations.

The workshop can be considered a treatment to reduce the level of math anxiety for the 80 elementary school teachers. The two sets of data before and after the workshop will be considered dependent on each other because it's the same group of teachers that are tested before and after the workshop.

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Answer:

list in the explanation

Step-by-step explanation:

BOOT x2

SKINNY x2

RELAXED x2

BOOT, SKINNY

BOOT, RELAXED

SKINNY, BOOT

SKINNY, RELAXED

RELAXED, BOOT

RELAXED, SKINNY

The solution set is given by Set A = { BB , SS , RR , BS , BR , SR } , where B , S and R are boot cut (B), skinny (S), and relaxed fit (R) respectively

The union of two sets A and B is the set of all those elements which are either in A or in B, i.e. A ∪ B, whereas the intersection of two sets A and B is the set of all elements which are common. The intersection of these two sets is denoted by A ∩ B

The union of two sets is a new set that contains all of the elements that are in at least one of the two sets

The intersection of two sets is a new set that contains all of the elements that are in both sets

Given data ,

Let the set be represented as A

Now , the equation will be

Marcus is shopping for pants and the available pants are boot cut (B), skinny (S), and relaxed fit (R)

He wants to buy 2 pair of pants , and the possible ways of 2 pants are

Set A = { BB , SS , RR , BS , BR , SR }

So , the total number of elements in set A = 6 pairs

Therefore , the value of A is 6 pairs

Hence , the set A is { BB , SS , RR , BS , BR , SR }

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A mean of a normal distribution's upper bound of a 95% confidence interval is 58.11.

For the given question,

The confidence bound's upper limit (UCB) is determined as follows:

UCB =  μ + z(α/2)×σ/√n

Now, α/2 = (1 - 0.95)/2

α/2 = 0.025

z(α/2) = 1.96  (obtain from t-distribution table for degree of freedom)

Put the values in the formula,

UCB =  μ + z(α/2)×σ/√n

UCB = 36.96 + 1.96×41.8/√15

UCB = 58.11

As a result, 58.11 is the upper bound of a 95% confidence interval for the mean of a normal distribution.

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The degree of the polynomial function represented by the graph is 4 and its leading coefficient is negative

From the question, we have the following parameters that can be used in our computation:

The graph

The degree of the polynomial function is the number of times the curve tends to touch or intersect with the graph

In this case, we have

Degree = 4

For the leading coefficient, we have

leading coefficient = negative

This is because the graph opens down

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The equivalent expression of the expression given as 0.75/9 * 0.75/3 is 1/48

Expressions are mathematical statements that are represented by variables, coefficients and operators

The expression is given as

0.75/9 * 0.75/3

Evaluate the product of the numerators

So, we have

0.75/9 * 0.75/3 = 0.5625/9 * 1/3

Evaluate the product of the denominators

So, we have

0.75/9 * 0.75/3 = 0.5625/27

Simplify the fraction

So, we have

0.75/9 * 0.75/3 = 0.0625/3

Further simplify

So, we have

0.75/9 * 0.75/3 = 625/30000

Further simplify

So, we have

0.75/9 * 0.75/3 = 1/48

Hence, the equivalent expression of the expression given as 0.75/9 * 0.75/3 is 1/48

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The probability of drawing a picture card or a clubs is: 6/52 + 13/52 - 4/52 = 25/52

The probability of drawing a picture card (jack, queen, king, or ace) or a clubs from a deck of 52 cards can be calculated by adding the probability of drawing a picture card to the probability of drawing a clubs, and then subtracting the probability of drawing a card that is both a picture card and a clubs (since this would be counted twice in the previous two probabilities).

The probability of drawing a picture card is 16/52 (since there are 16 picture cards in the deck of 52 cards). The probability of drawing a clubs is 13/52 (since there are 13 clubs in the deck of 52 cards). The probability of drawing a card that is both a picture card and a clubs is 4/52 (since there are 4 picture cards that are also clubs).

Therefore, the probability of drawing a picture card or a clubs is:

16/52 + 13/52 - 4/52 = 25/52

Simplifying, this is equivalent to:

5/13 or approximately 0.385 or 38.5%

In other words, there is a 38.5% chance of drawing a picture card or a clubs from a deck of 52 cards.

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Answer:

sorry I don't know hehe

Step-by-step explanation:

u don't care beach

Answer:

Step 1: Move the decimal point so that you have a number that is between 1 and 10. ...

Step 2: Count the number of decimal places moved in Step 1 . ...

Step 3: Write as a product of the number (found in Step 1) and 10 raised to the power of the count (found in Step 2).

Step-by-step explanation:

Answer:

ok sure

Step-by-step explanation: