Consider the following situations: Situation 1: A cold spoon is placed in a cup of hot tea. Situation 2: A spring is used to roll a ball across the floor.Is energy being transferred in either of these situations?in both situations

Answer:

which on a is the question

Answer:

The time when the ball strikes the ground is closest to  \(t_t = 9.4 \ s\)

Explanation:

From the question we are told that

  The time of projection is t = 0.0 s

   The  distance of the point  from the ground  is  \(d = 90 \ m\)

    The  initial velocity of the ball is  \(v _i = 36 .2 \ m/s\)

generally the time required to reach maximum height is  

      \(t_r = \frac{g}{v}\)

Where is the acceleration due to gravity  with value  \(g = 9.8 \ m/s^2\)

Substituting values

        \(t_r = \frac{36.2}{9.8}\)

        \(t_r = 3.69 s\)

when returning the time and velocity at the roof level is  t =  3.69 s and  u = 36.2 m/s this due to the fact that  air resistance is negligible

   The final velocity at which it  hit the ground is

      \(v_f^2 = u^2 + 2ag\)

So  

    \(v_f = \sqrt{ u^2 + 2gs}\)

substituting values

    \(v_f = \sqrt{ 3.69^2 + 2* 9.8 * 90}\)

     \(v_f = 55.45 \ m/s\)

The time taken for the ball to move from the roof level to the ground is  

     \(t_g = \frac{v-u}{a}\)

substituting values

    \(t_g = \frac{55.45 -36.2}{9.8}\)

     \(t_g = 1.96 \ s\)

The total time for this travel is  

    \(t_t = t_g + 2 t_r\)

     \(t_t = 1.96 + 2(3.69)\)

      \(t_t = 9.4 \ s\)

Answer: The answer is A, B, D, and E

Explanation: Choose all those answers. USATestPrep says so.

Answer:

Lotion - Semisolid

Suspension - Liquid

Capsule - Solid

An engine's NOx emissions are caused by greater in-cylinder temperatures.

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In order to calculate the maximum number of miles, let's use a limit speed of 70 mph and consider a year with 365 days.

Since each day has 24 hours, so the number of hours in a year is 365 * 24 = 8760 hours.

Then, multiplying this number of hours by the speed of 70 miles per hour, we have:

8760 * 70 = 613,200 miles.

Therefore the maximum number of miles you could drive is closest to 613,200 miles.

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.

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Answer:

II. Gopi takes part in a car race. He drives a distance of 70 km each in the first, second and third hours.

Which of the following statements is true.

a) I, is an example uniform motion and II is an example of non-uniform motion.

b) I is an example of nonuniform motion and II is an example of uniform motion.

c) I and II are examples of uniform motion.

d) I and II are examples of nonuniform motion.

The name of my community service is “Feed the Homeless”. The aim of this program is to provide nutritious food and basic necessities to the homeless community in my city. The homeless community faces various challenges and difficulties in their everyday life.

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Answer:

proton is positively charged changechar

Explanation:

Answer:

50 protons 50 electrons and 69 neutrons...

Explanation:

the number of protons is equal to number of electrons. then mass number is the sum of protons and neutrons in a nucleus so for we to get the number of neutrons we take the mass number subtract the protons number.

The push magnitude and the tension of the code is 5.4 × 10^-4

What is cord?

cord is the slender flexible material usually consisting of several stands or twisted together.

It is wired covered in rubber or plastic which connects electrical equipment to an electricity supply.

The free body diagram as per the question with the tension of string T .

The force of gravity ~mg

The force of air ~f

Since the sphere is motionless the net force on it is 0.

And the x and y are the components of the equation are zero

Tsin + 0 = F

Tcos - mg= 0

Where ¥ = 32°

Thus we get

T= (3.9×10^-4 kg ) (9.8m/s^2)/cos32°

= 2.1×3.2×10^-4

Solving T

We can get the F =

(3.2×10^-4)sin 32° =

5.4 ×10^-4

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Answer:

16 meters

Explanation:

When the rope is suddenly cut the object moving tangent at the circle. In that moment the gravity act in the object making it falls.

First we need to find how much time de object take to reach at the ground.

g=acceleration of gravity=10m/s²

v= vertical velocity =0m/s

h=vertical altitude =20m

We will find t such that h(t)=0

\(0=20-5t^{2} \\\\5t^{2} =20\\\\t^{2} =4\\\\t=2s\)

v=horizontal velocity

D(t=2) is the horizontal distancetravelled by the object:

\(D(2)=8*2\\\\D(2)=16m\)

The force needed to remove the plug that is 6.000 cm in diameter which plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure is 85 N

P = F / A

P = ρ g h

P = Pressure

F = Force

A = Area

ρ = Density

g = Acceleration due to gravity

h = Height

ρ = 1000 kg / m³

g = 9.8 m / s²

h = 10 ft = 3.048 m

A = π r²

d = 6 cm = 0.06 m

r = d / 2 = 0.06 / 2

r = 0.03 m

A = 3.14 * 0.03 * 0.03

A = 0.002826 m²

Equating both formulae of P,

F / A = ρ g h

F = 1000 * 9.8 * 3.048 * 0.002826

F = 85 N

Therefore, the force needed to remove the plug is closest to 85 N

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A. The impulse supplied to bring the ball to rest 4.5 Ns. Details below

B The average force of the ball is 225 N. Details below

This is defined as the change in momentum of an object.

Impulse = change in momentum

Impulse = final momentum – Initial momentum

Impule = m(v - u)

Where

Also,

Impulse = force × time

Therefore

Force × time = final moment – Initial momentum

A. How to determine the impulse

The impulse can be obtainedas illustrated below

Impulse = m(v + u) since the came to rest

Impulse = 0.15 × (0 + 30)

Impulse = 0.15 × 30

Impulse = 4.5 Ns

Thus, the impulse is 4.5 Ns

B. How to determine the average force

The average force can be obtained as follow:

Impulse = force × time

4.5 = average force × 0.02

Divide both sides by 0.02

Average force = 4.5 / 0.02

Average force = 225 N

Thus, the average force is 225 N

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(A)

Explanation:

There is no acceleration along the x-axis. Acceleration only occurs along the y-axis.

Answer:

d: the speed of a character at the moment of contact

Explanation:

did the quick check

The measure which would be an initial condition in one of these games is

speed of a character at the moment of contact.

The speed of the character at the point of contact is the most suitable

option which tells the exact speed and position of the character in the

video game.

The moment of contact will determine the type of movement and position

exhibited by the players which can then be immediately updated when the

game is being played.

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Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

2A

Given ,

Resistance=60

V=12

V=IR

I=V/R

I=120/60=2A

The pace at which electrons flow past a location in a complete electrical circuit is defined as current. At its most fundamental, current Means flow.

An ampere (AM-pir), sometimes known as an amp, is the international unit for measuring current. It denotes the number of electrons (also known as "electrical charge") that pass across a location in a circuit over a specific time period.

A current of one ampere indicates that one coulomb of electrons—that is, 6.24 billion billion (6.24 x 1018) electrons—moves across a circuit in one second. The method is comparable to determining how many gallons move through a single spot in a pipe in one minute (gallons per minute, or GPM).

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The radiation that is least damaging to humans is non-ionizing radiation.

Non-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.

Examples of non ionizing radiation include radio waves, microwaves, visible light  and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.

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The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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The vector product of A and B is -3i - 5j - 9k.

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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Answer:

146.27 m

Explanation:

From the question given above, the following data were obtained:

Velocity of tourist (vₜ) = 4.65 m/s

Distance travelled by tourist (dₜ) = d

Velocity of bear (v₆) = 5.68 m/s

Distance travelled by bear (d₆) = 32.4 + d

Value of d =?

Next, we shall determine the time taken for tourist and the bear to get to the car.

For the tourist:

Velocity of tourist (vₜ) = 4.65 m/s

Distance travelled by tourist (dₜ) = d

Time (tₜ) =?

vₜ = dₜ / tₜ

4.65 = d/tₜ

Cross multiply

4.65 × tₜ = d

Divide both side by 4.65

tₜ = d / 4.65

For the bear:

Velocity of bear (v₆) = 5.68 m/s

Distance travelled by bear (d₆) = 32.4 + d

Time (t₆) =?

v₆ = d₆ / t₆

5.68 = (32.4 + d) / t₆

Cross multiply

5.68 × t₆ = (32.4 + d)

Divide both side by 5.68

t₆ = (32.4 + d) / 5.68

NOTE: Both the tourist and the bear have the same time. Thus, to obtain the value of d, we shall equate both the time taken for the tourist and the bear together. This is illustrated below:

Time taken by tourist (tₜ) = time taken by the bear (t₆)

tₜ = d / 4.65

t₆ = (32.4 + d) / 5.68

tₜ = t₆

d / 4.65 = (32.4 + d) / 5.68

Cross multiply

d × 5.68 = 4.65 (32.4 + d)

5.68d = 150.66 + 4.65d

Collect like terms

5.68d – 4.65d = 150.66

1.03d = 150.66

Divide both side by 1.03

d = 150.66 / 1.03

d = 146.27 m

Thus, the maximum value of d is 146.27 m

(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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The statement that is true about the forces acting on the car is that the net force acting on the car from all directions is zero. Option A is correct.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The complete question is

"A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car?

A.

The net force acting on the car from all directions is zero.

B.

The net force acting on the car is greater than the car's weight.

C.

The net force acting on the car is in the direction of the car's motion.

D.

The net force acting on the car is in the opposite direction of the car's motion."

The net force operating on the automobile in all directions is zero,

The statement that is true about the forces acting on the car is that the net force acting on the car from all directions is zero. Option A is correct.

Hence option A is correct.

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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The correct equation for the x-axis of object A is F-T = mga, where F is the force acting on object A, T is the tension in the rope, m is the mass of object A, g is the acceleration due to gravity, and a is the acceleration of object A.

- From NA - WA = 0, we know that the normal force acting on object A is equal to its weight, NA = WA = mg = 75 kg * 9.81 m/\(s^2\) = 735.75 N.

- From Ng - WB = 0, we know that the weight of object B is equal to the weight of the hanging mass, WB = mg = 75 kg * 9.81 m/\(s^2\) = 735.75 N.

- The tension in the rope is equal to the weight of the hanging mass, T = WB = 735.75 N.

- From F - T = mga, we can solve for the acceleration of object A, a = (F - T) / m = (mA * g - T) / mA = (mA * g - 735.75 N) / mA.

- Substituting the given values of mA = 50 kg and g = 9.81 m/\(s^2\), we get a = (50 kg * 9.81 m/\(s^2\) - 735.75 N) / 50 kg = 4.549 m/\(s^2\).

- Therefore, the correct equation for the x-axis of object A is F-T = mga = 50 kg * 4.549 m/\(s^2\) = 227.45 N.

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