Consider the following three Linear Time Invariant (LTI) systems connected as shown in Figure 1 below: x[n] and h₁ [n] h₂[n] h₂[n] Figure 1 a. The impulse response of each block is given by: 6 6 + h₁ [n] = 0.48[n] + 8[n - 1] +0.28[n-2], h₂ [n] = 8[n] +0.58[n 1], y[n] h₂ [n] = 0.68[n] + 0.8 8[n 1] -0.2 8[n-2] -0.6 8[n-3] Find the overall system impulse response h,[n]. (10 marks) b. Find the system transfer function H₂(2), and evaluate H₂(e) at WT = 0, 2п 4п , I. (8 marks) c. Sketch |H₂(ej) | vs WT for 0 ≤ T ≤n. Is it a high-pass, bandpass or a low-pass filter? (4 marks) d. Is the system stable, and why?

a) Axial resolution is determined by the wavelength of the ultrasound waves and is given by the formula:

Axial resolution = wavelength / (2 * fractional bandwidth)

For System A:

Central frequency = 5 MHz

Fractional bandwidth = 50% = 0.5

Wavelength = c / frequency = 1540 m/s / (5 * 10^6 Hz) = 0.308 mm

Axial resolution for System A = 0.308 mm / (2 * 0.5) = 0.308 mm / 1 = 0.308 mm

For System B:

Central frequency = 14 MHz

Fractional bandwidth = 80% = 0.8

Wavelength = c / frequency = 1540 m/s / (14 * 10^6 Hz) = 0.11 mm

Axial resolution for System B = 0.11 mm / (2 * 0.8) = 0.11 mm / 1.6 = 0.069 mm (rounded to 3 decimal places)

At an imaging depth of 4 cm, both systems will have similar axial resolutions since the fractional bandwidth is not changing with depth. Therefore, the axial resolution for both systems would be approximately 0.308 mm for this depth.

Lateral resolution is determined by the physical size of the array and is given by the formula:

Lateral resolution = element width / 2

For both systems, the element width is given as 0.12 mm. Therefore, the lateral resolution for both systems would be 0.12 mm / 2 = 0.06 mm.

b) Sketching the far-field polar power density pattern requires detailed information about the array's geometry, such as the shape and arrangement of the elements. The given information does not provide enough details to accurately sketch the pattern. The pattern depends on factors like the shape of the array (rectangular, curved, etc.), the element spacing, and the element excitation. Without this information, it is not possible to accurately sketch the pattern.

c) Advantages of System A with respect to System B:

Higher number of channels: System A has 32 channels, while System B has 64 channels. Having more channels allows for better beamforming and improved image quality. It enables finer control over the ultrasound beam, resulting in enhanced spatial resolution and imaging capabilities.

Lower central frequency: System A operates at a central frequency of 5 MHz, which allows for deeper penetration into the body. This is advantageous for imaging structures located deeper within the body, such as organs or tumors that may require a lower frequency for better visualization.

Advantages of System B with respect to System A:

Higher central frequency: System B operates at a central frequency of 14 MHz, which provides higher spatial resolution. Higher frequency ultrasound waves can resolve smaller structures and details in the imaged area. This is beneficial for imaging superficial structures, such as skin or superficial blood vessels, where finer details need to be visualized.

Wider fractional bandwidth: System B has an 80% fractional bandwidth compared to System A's 50%. A wider fractional bandwidth allows for a larger range of frequencies to be transmitted, resulting in improved image quality and better differentiation of tissue characteristics. It can enhance the ability to distinguish between different types of tissues or detect subtle abnormalities.

d) Qualitative description of changes in the radiation pattern for System B:

i) Decreasing the wavelength: Decreasing the wavelength would result in a narrower beam and improved spatial resolution. The beam would be more focused and have a smaller beamwidth, allowing for better differentiation of structures and finer details in the imaged area.

ii) Decreasing the spacing between elements: Decreasing the spacing between elements would result in a wider beam and a broader main lobe in the radiation pattern. This would lead to a decrease in spatial resolution but an increase in the sensitivity to off-axis signals.

iii) Decreasing the total number of elements: Decreasing the total number of elements would result in a decrease in the overall sensitivity and signal-to-noise ratio. The radiation pattern would show reduced beamforming capabilities and a lower main lobe intensity. This would result in lower image quality and reduced ability to resolve fine details in the imaged area.

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Answer:

Because the shunt winding consist of a large number of turns,

Explanation:

It is nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source because the shunt winding consist of a large number of turns, due to the high number of turns that the DC shunt motor has it develops a high impedance when connected to an ac power source. and due  to this high impedance the amount of current that flows through the field will be very low making it nearly impossible for the shunt motor to operate properly

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Press the Ctrl keys on the keyboard while choosing multiple sketch entities, holding the key down.

First, choose the 3 point arc tool to start drawing an arc.To set your starting point, click on the first position.To choose your second paragraph, the arc's endpoint, click inside the second place. Next, click in the third position to choose the radius.

You may access the sketch size tool from the sketching dropdown list, which is located at the bottom of this list.The letter "D," as in Delta, on the keyboard shortcuts can also be used to activate it.

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The three most common software development methods are the Waterfall Approach, the Incremental Approach, and the SPIRAL Approach. These methods depend on the team size and specific goals.

Software development is the sequential procedure that involves the division of the work into smaller and parallel stages in order to improve software design and product management.

The software development methods depend on both the team size and specific objectives.

The most common methodologies for software development include:

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The mobile bracket option for the Yaesu FT-710 is the Yaesu SMB-209. It is a mounting bracket that allows you to mount the Yaesu FT-710 transceiver in a vehicle or on board a ship, or even on a shelf at home.

The SMB-209 can be mounted in a variety of ways such as on a vehicle or ship, or on a shelf at home. It also features a detachable antenna mount, allowing you to easily switch between different antennas.

Additionally, the SMB-209 provides easy access to all the buttons and switches on the FT-710, so you can easily control the radio. Overall, the Yaesu SMB-209 is an ideal mobile bracket solution for the FT-710 transceiver.

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Answer:

A) condenser pressure = 9.73 kPa,

B) 10242 kw

C) 36.9%

Explanation:

given data

entrance pressure of steam = 12.5 MPa

temperature of steam = 550⁰c

flow rate of steam = 7.7 kg/s

outer pressure = 2 MPa

reheated steam temperature = 450⁰c

isentropic efficiency of turbine( nt ) = 85% = 0.85

isentropic efficiency of pump = 90% = 0.90

From steam tables

at 12.5 MPa and 550⁰c ; h3 = 3476.5 kJ/kg,  S3 = 6.6317 kJ/kgK

also for an Isentropic expansion

S4s = S3 .

therefore when S4s = 6.6317 kJ/kg and P4 = 2 MPa

h4s = 2948.1 kJ/kg

nt = 0.85

nt (0.85) = \(\frac{h3-h4}{h3-h4s}\) = \(\frac{3476.5 - h4}{3476.5 - 2948.1}\)

making h4 subject of the equation

h4 = 3476.5 - 0.85 (3476.5 - 2948.1)

h4 = 3027.3 kj/kg

at P5 = 2 MPa and T5 = 450⁰c

h5 = 3358.2 kj/kg,  s5 = 7.2815 kj/kgk

at P6 , x6 = 0.95  and s5 = s6

using nt = 0.85 we can calculate for h6 and h6s

from the chart attached below we can see that

p6 = 9.73 kPa, h6 = 2463.3 kj/kg

B) the net power output

solution is attached below

c) thermal efficiency

thermal efficiency = 1 - \(\frac{qout}{qin}\) = 1 - ( 2273.7/ 3603.8) = 36.9% ≈ 37%

The C++ programs are illustrations of functions and function reference by parameter

Functions are collections of program statements that are executed when called or evoked

To pass value to a function by reference parameter, we make use of the &variable in the function parameters

The program written in C++ where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

//This defines the function

void addNums(int &x, int &y) {

   //This adds the two numbers

   int sum = x + y;

   //This saves the sum of the two numbers in the first number

   x = z;

}

//Ths main module begins here

int main() {

   //This declares the two numbers

   int firstNum, secondNum;

   //This gets input for the two numbers

   cin>>firstNum;    cin>>secondNum;

   //This calls the addNums function

   addNums(firstNum, secondNum);

   //This prints the sum

   cout << firstNum;

 return 0;

}

The program written in C++ where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

//This defines the function

void printName(string name) {

   //This prints the name

   cout<<"Hello "<<name;

}

//Ths main module begins here

int main() {

   //This declares the name

   string name;

   //This gets input for the name

   cin>>name;

   //This calls the printName function

   printName(name);

 return 0;

}

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The following is the code for generating a plot of the Lissajous curve for 0 ≤ t ≤ 2π using 1000 increments where a = 2, b = 7,

and e = 7:```pythonimport numpy as npimport matplotlib.pyplot as plt# Defining the parameter

arrayt = np.linspace(0, 2*np.pi, 1000)# Defining the parameter a, b, and ec, d,

e = 0, 2, 7, 0, 7, 0# Defining the x and y

arraysx = np.sin(a*t + c)

y = np.sin(b*t + e)# Plotting the curve with a title and gridplt.plot(x, y)plt.title(f"Lissajous curve with ratio {a}/{b}")plt.grid()plt.show()```In the code above, we used the NumPy and Matplotlib libraries to generate the Lissajous curve.

We defined the parameter array t using the linspace() function from NumPy, which created an array with 1000 values between 0 and 2π. We also defined the parameters a, b, and e as 2, 7, and 7 respectively. Then, we used the sine function in NumPy to define the x and y arrays using the given parametric equations.

Finally, we plotted the curve using Matplotlib's plot() function and added a title to the plot using the format string "Lissajous curve with ratio a/b". We also turned on the grid using Matplotlib's grid() function. The resulting plot will show a Lissajous curve with ratio 2/7.

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Answer:

Explanation:

Temperature of atmospheric air To = 25°C = 298 K

Free  stream velocity of air Vo = 25 m/s

Length and width of plate = 1m

Temperature of plate Tp = 125°C = 398 K

We know for air, Prandtl number Pr = 1

And for air, thermal conductivity K = 24.1×10?³ W/mK

Here, charectorestic dimension D = 1m

Given value of Reynolds number Re = 105

For laminar boundary layer flow over flat plate

= 3.402

Therefore, hx = 0.08199 W/m²K

So, heat transfer rate q = hx×A×(Tp – To)

                                          = 0.08199×1×(398 – 298)

Answer:

False

Explanation:

1) The number of gallons of water lost in a week would be approximately (2.3 m³/s * 604,800 seconds) * (1000 liters/m³) * (0.264172 gallons/liter).

2) The density of the copper sample is approximately 8.32 g/cm³ (347.5 g / 41.8 cm³).

To calculate the number of gallons of water lost in a week, we first need to determine the volume of water that flows through the stream in one week.

Given:

Flow rate of the stream = 2.3 m³/s

To convert the flow rate to the volume of water in one week, we need to convert the time unit from seconds to weeks. There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 7 days in a week.

1 week = 7 days * 24 hours * 60 minutes * 60 seconds = 604,800 seconds

Volume of water in one week = Flow rate * Time

Volume of water in one week = 2.3 m³/s * 604,800 seconds

Now, let's convert the volume from cubic meters (m³) to gallons.

1 cubic meter = 1000 liters

1 liter = 0.264172 gallons

Volume in gallons = (Volume in cubic meters) * (1000 liters/m³) * (0.264172 gallons/liter)

Finally, we can calculate the number of gallons of water lost in a week.

Volume in gallons = (2.3 m³/s * 604,800 seconds) * (1000 liters/m³) * (0.264172 gallons/liter)

Please note that the flow rate might change due to various factors, but for the given scenario and assumptions, this calculation provides an estimate.

1b) To calculate the density of the copper sample, we'll use the formula:

Density = Mass / Volume

Given:

Mass of the copper sample = 347.5 g

Volume of the copper sample = 41.8 cm³

Density = 347.5 g / 41.8 cm³

=8.32 g/cm³

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Option C. Instructing all employees about confined spaces, even if it is not a part of their duties is not a requirement of management when developing and maintaining a safety program.

While it is important to ensure that all employees are trained on safety procedures and that safety rules are incorporated into site operations, confined spaces may not be relevant to all employees' job functions. Therefore, it may not be necessary to instruct all employees about confined spaces unless it is relevant to their job duties or they may potentially be exposed to such hazards.

However, it is important for management to identify all potential hazards and ensure that all employees receive training and instruction on the specific hazards that are relevant to their job duties. Additionally, revising the safety program annually and participating in safety meetings are important aspects of developing and maintaining a safety program.

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The processing industries are the group of industries to which the petrochemical industry belongs.

The textile industry was the one that employed the most people in manufacturing. The textile sector experienced the fastest growth during the Industrial Revolution. Clothing tools were made on a broad scale for the first time. In this regard, England has surpassed all other countries as the world's top cloth supplier, necessitating a massive workforce in the factories. Labor was in high demand in other nations that built their textile industries. The textile sector still has a high labour requirement. As an example, the petrochemical business describes a branch of the sector that creates organic intermediate products like natural gas, plastic, rubber, and fibre raw materials.

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Celery stalks that are standing in a glass of pure water for several hours become more rigid and stiff. T

he process behind this is known as osmosis. When the celery stalk is placed in the glass of water, water enters the plant through a process known as osmosis.

The water molecules move from an area of high concentration (the glass of water) to an area of low concentration (the celery stalk). This movement of water molecules from an area of high concentration to an area of low concentration through a semipermeable membrane is known as osmosis.

Osmosis is the diffusion of water molecules across a semipermeable membrane from a region of low solute concentration to a region of high solute concentration. The movement of water molecules is driven by the difference in concentration between the two regions. In the case of celery stalks standing in a glass of pure water, the solute concentration inside the celery stalks is higher than that in the water.

Hence, water moves from the glass into the celery stalk, making it more rigid and stiff.

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Modern aircraft are designed in a way that, when all seats are occupied and baggage is full, and all fuel tanks are full, the aircraft is overloaded.

Aircraft storage refers to all storage systems in an aircraft for human transportation and also to transport products among countries.

The aircraft storage system is well calculated to work is a maximum capacity in commercial fly lines.

In conclusion, modern aircraft are designed in a way that, when all seats are occupied and baggage is full, and all fuel tanks are full, the aircraft is overloaded.

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Answer:

Weight Percentage of Ash = 3.4

Explanation:

Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.

To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?

Solution -

Given that,

Coal Burned Rate = 10,000 kg/hr

                              = \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)

                              = 166.6666 kg/min

⇒Coal Burned Rate = 166.6666 kg/min

Now,

Given that,

Ash content in coal = 21 %

⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min

                                             = 34.9999 ≈ 35 kg/min

⇒Ash in (coal that burned) = 35 kg/min

Now,

We know,

Density of water = 1000 kg/m³

Now,

Water flow Rate = \(1\frac{m^{3} }{min} * density\)

                           = 1000 kg/min

⇒Water flow Rate = 1000 kg/min

Now,

Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min

                                                                           = 1035 kg/min

⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min

So,

Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100

                                            = (35 ÷ 1035) × 100

                                            = 3.38 ≈ 3.4

∴ we get

Weight Percentage of Ash = 3.4

Answer:

Fast Fourier ( FFT ) algorithms speed up computation of Fourier coefficients by simply reducing the the computing time of a traditional direct form  Fourier series. it  achieves this by breaking complex DFTS into smaller DFTS to reduce its complexity and in turn reduce its computing time

Explanation:

Fast Fourier ( FFT ) algorithms speed up computation of Fourier coefficients by simply reducing the the computing time of a traditional direct form  Fourier series. it  achieves this by breaking complex DFTS into smaller DFTS to reduce its complexity and in turn reduce its computing time. an example of such FFT is Cooley-Tukey algorithm

It is estimated that a spherical nickel powder, likely measuring 8 micrometers in size, will take roughly 15 minutes to settle in water at the top of a 100 mm sedimentation column.

The principle of Stokes law is utilized in this, which explains that the speed at which a round particle sinks in a thick fluid is linked to both the size of the particle's radius and the contrast in densities of the particle and the fluid, while being inversely related to the fluid's viscosity.

The nickel powder has a density of \(8. 90 g/cm^3\) and particle radius of 8 micrometers, whereas water's density and viscosity are 1. 00 g/cm^3 and 0. 001 poise respectively in this scenario.

By inserting these numerical values into the Stokes equation, we can determine that the nickel powder has a settling rate of roughly 0. 0002 centimeters per second.

One can estimate the setting time by taking the column's height and dividing it by the settling velocity, resulting in roughly 15 minutes.

Kindly consider that the specified duration is only a rough approximation, and the factual solidifying period is prone to fluctuations based on various factors, such as the density of the nickel powder, the warmth of the water, and the existence of other contaminants or particles in the water.

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The allowable normal strength in the c-section is 48000 pounds per square inch.

The allowable stress depends on both the factor of safety imposed on the object and the yield strength or stress at which an object will be permanently damaged. To calculate the allowable normal strength we can divide the yield strength by the factor of safety.

To determine the allowable normal strength output we can use this equation below:

The allowable normal strength = The number yield strength : A stress-concentration factor

The number yield strength is 84 kpsi.

Then convert kpsi to psi : 84 kpsi = 84000 psi

A stress-concentration factor is 1.75

The formula to find allowable normal strength output is:

84000 psi : 1.75 = 48000

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Among the DC motors listed, the electrical ratchet mechanism is commonly associated with a stepper motor.

The electrical ratchet mechanism is typically linked with a stepper motor among the available options for DC motors. A stepper motor makes use of electrical pulses to initiate precise rotational movements, thereby enabling accurate control over its operation.

It generally follows a sequential process where each movement is associated with a set rotation angle. The stepper motor shares a quality with an electrical ratchet as it moves forward in specific intervals, reminiscent of the ratcheting action.

The ratchet-like behavior isn't inherent in other forms of DC motors like brushless DC motors and brushed DC motors.

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Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

The street is a haunting and devastating sight, a testament to the destructive power of the atomic bomb.

"Hiroshima Diary," Dr. Michihiko Hachiya provides a detailed account of the street he sees as he emerges from the rubble of his destroyed hospital in the aftermath of the atomic bomb explosion on August 6, 1945. Dr. Hachiya describes the street as unrecognizable and eerily quiet.

The buildings are in ruins, and there are no signs of life except for a few injured and dying people lying in the streets. Dr. Hachiya notes that the air is filled with a "strange and pungent odor," which he later learns is the smell of burnt flesh. Despite the destruction, Dr. Hachiya observes that there are still some trees standing, though they are stripped of leaves and branches, and some street lamps are still intact.

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The purpose of a dye penetrant is to check for cracks. It is also called dye penetration inspection. The correct option is D).

Surface-breaking faults are frequently found using dye penetrant inspection (DPI). This non-destructive testing approach also cognized as liquid penetrant inspection (LPI), is a practical way to find surface faults that can cause surface discontinuities, such as cracks, porosity, laps, and seams. It is used to check surface cracks and breaking faults.

Therefore, the correct option is D), check for cracks.

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Answer:

  12 volts

Explanation:

The voltages across parallel-connected items are identical. (In fact, that's why you can measure the voltage by connecting the voltmeter in parallel with the circuit element.)

The voltage drop across each bulb is 12 volts.

When the power rating of a transformer is exceeded by placing too great on the transformer, the voltage will start to drop, and the transformer may overheat and be damaged.

This is because exceeding the power rating causes the transformer to draw more current than it is designed to handle, resulting in increased losses due to the resistance of the winding and core materials. This increased current also causes a voltage drop across the winding and leads to a decrease in output voltage, which can cause problems downstream in the circuit. If the current continues to increase beyond the transformer's capacity, it can cause overheating and damage to the winding insulation, leading to short circuits and potential safety hazards.

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The RMR value is 413.15, which indicates that the rock mass is of excellent quality.

The most important geologic criteria are combined by RMR, which depicts them as a single, comprehensive indicator of rock mass quality.

Based on the given parameters, we can use the Rock Mass Rating (RMR) method to classify the rock mass.

The RMR value is given by the formula:

RMR = 70Q + 10G + 5F + 8L + 7S - 3W

Using the given parameters, we can calculate the RMR value as follows:

Q = 10 x \((RQD/10)^{1/2\) x (Jn + Ja + Jw + Jr + Jsr)

Where Jn, Ja, Jw, Jr, and Jsr are the joint sets orientations, number, water pressure, roughness, and spacing rating, respectively.

Since we do not have information about the joint orientations and roughness, we can assume that they have a neutral effect on the RMR value, which means that Jn=Ja=Jr=1 and Jw=Jsr=0.5.

Therefore,

Q = 10 x\((55/10)^{1/2\) x (1 + 1 + 0.5 + 1 + 0.5) = 57.45

G = 0 (since joint water pressure is nil)

F = 5 (since the joint condition is open joints filled with gouge)

L = 8 - 2.6 x log10(0.5) = 5.44

S = 7 (since the joint condition is filled with 5mm gouge)

W = 0 (since joint water pressure is nil)

Thus, RMR = 7057.45 + 100 + 55 + 85.44 + 77 - 30 = 413.15

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Answer:

True ...................

Answer:

True

Explanation:

Took da quiz 100%

The average cost is €260.

Ceiling type: 1.5 hours x €40/hour + €200 = €260

Cassette type: 1 hour x €40/hour + €200 = €240

Wall-mounted type: 0.75 hours x €40/hour + €200 = €230

The total weekly cost of production for each type is:

Ceiling type: 2 x €260 = €520

Cassette type: 4 x €240 = €960

Wall-mounted type: 6 x €230 = €1380

The total weekly revenue is:

Ceiling type: 2 x €350 = €700

Cassette type: 4 x €450 = €1800

Wall-mounted type: 6 x €500 = €3000

The total profit is the difference between the total revenue and the total cost:

Total profit = €5500 - (€520 + €960 + €1380) = €2640

The average cost per air conditioner based on current multifactor productivity is:

Average cost = Total cost / Total units = (€520 + €960 + €1380) / (2 + 4 + 6) = €260

Ceiling type: €350 / 1.5 hours x €40/hour = €15.56

Cassette type: €450 / 1 hour x €40/hour = €11.25

Wall-mounted type: €500 / 0.75 hours x €40/hour = €17.78

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