construction worker Bob IS standing at the top of a slanted rooftop when he accidentally drops & orange from his lunch bag; The orange rolls down the rool, which i> angled at 0 28,58 relative t0 Ihe harizontal as shown the figure below The bottom edge of the roofus meters above Ihe ground. Ihe orarge leaves the right edge ol Ihe rooftop with velocity 0l Ti 4.471,how fal, Arto the right of the roof edge does his 8 meter tall fellow consiruction warker Werdy have sland on the ground 50 that the orange just barely passes over her head? [Figure not diawn t0 scalel Imapa *x4: ALhae

Answers

Answer 1

Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.

Bob's orange will travel down the slanted roof with a velocity of 4.47 m/s, and it will hit the ground 3.0 m below the edge of the roof. The height of the orange above the ground at the edge of the roof is 1.8 m, and the angle of the roof is 28.5° relative to the horizontal.

To calculate the distance Ar that Wendy has to stand from the edge of the roof, we must first calculate the time it takes for the orange to reach the ground. Using the equation for the vertical displacement of an object with an initial velocity, we can solve for the time, t:

d = v*t - (1/2)*g*t^2

0 = 4.47*t - (1/2)*9.8*t^2

t = 0.938s

Next, we must calculate the horizontal displacement of the orange from the time, t. Using the equation for the horizontal displacement of an object with an initial velocity and a constant acceleration we can solve for the displacement:

x = v*t + (1/2)*a*t^2

x = 4.47*0.938 + (1/2)*0*0.938^2

x = 4.19m

To calculate the distance Ar that Wendy must stand from the edge of the roof, we must subtract the horizontal displacement of the orange from the height of the edge of the roof:

Ar = 3.0 - 4.19

Ar = -1.19m

Therefore, Wendy must stand 1.19m to the left of the edge of the roof so that the orange just barely passes over her head.

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Construction Worker Bob IS Standing At The Top Of A Slanted Rooftop When He Accidentally Drops &

Related Questions

A certain net force acting on a 5kg mass produces an acceleration of 2 m/s2 calculate the force

Answers

Answer:

10 N

Explanation:

Newton's Second Law equation: Fnet = ma

Assuming no frictional force, plug in the values to get your answer!

Fnet = 5kg x 2m/s^2 = 10 N

How many valence electrons does each Cholrine atom have?

Answers

Answer:

7 valence electrons is right answer

Explanation:

2 elections in first shell and 5 electrons in second shell which total makes seven electrons.

hope it helped you:)

Pretty please help me with this!

Mrs. Kelly is taking her dog, Shadow, for a walk. Shadow sees another dog and gets excited and starts to pull forward. If Shadow weights 25 kilograms and accelerates at 3m/s2, what is the force that Shadow exerts on the leash?
a.) 75 N
b.) 28 N
c.) 25 N
d.) 3 N

Answers

Answer:

a.) 75 N

Explanation:

Force = mass × acceleration

Here,

Mass (m) = 25 kg

Acceleration (a) = 3 m/s²

Force (F) = ?

Using the formula,

F = ma

F = 25 × 3

F = 75 N

Hope it helps ⚜

Define each of the three heat transfer methods:

Conduction


Convection


Radiation

Answers

conduction- is when heat is directly transferred through touch
convection- is like when water is moving it gets all the water hot
Radiation- is when heat is transferred through the air like a campfire.
Hope this helps

Please solve this.. I can't find R_th and V_oc at 6kohm....

Please solve this.. I can't find R_th and V_oc at 6kohm....

Answers

The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.

To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:

Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.

To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:

Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V

Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:

Rth = 2 kΩ || 4 kΩ = 1.33 kΩ

Step 2: Replace the original circuit with the Thévenin equivalent circuit.

We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.

Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.

To find the current I, we can use Ohm's law:

I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA

Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

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An object has mass 4 kg. What is its weight (in newton) on earth?​

Answers

i think it’s 78 carrots

Answer:

Should be -39.2 N

Explanation:

w=mg

w=4 x -9.8 m/s2

= -39.2 N

a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to generate a maximum emf of 2500 v?

Answers

The loops must the coil have to generate a maximum emf of 2500 will be 439.

What is the faraday law of electromagnetic induction?

According to  Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.

Given data;

Area,A = 0.239 m²

Angular velocity,ω=373 rad/sec

Magnetic field,B=0.0639 T

Maximum emf,E= 2500V

The formula for the maximum induced voltage is;

E{max} = N ×  B × A × ω

2500 = N × 0.639 × 0.0239 × 373

N = 438.66

N = 439 \ turns

Hence, loops must the coil have to generate a maximum emf of 2500  will be 439.

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Answer: 11392.99

Explanation: I had the same problem and here are the steps:

Values:

N (Number of loops) = 2000

A (area) = 0.239

ω (angular velocity) = 373

B (magnitude) = 0.0639

ε = NABω

= (2000)(0.239)(373)(0.0639)

ε = 11392.99 (FINAL ANSWER)

4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.

Answers

a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.

The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.

The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.

b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.

The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.

In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.

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Initial velocity of a car is 36 km/hr. Find the distance after one min, if it goes with acceleration 2m/s².

[A] 4000 m.
[B] 4200 m.
[C] 4400 m.
[D] 4600 m.​

Answers

Answer:

\(\bf\pink{4200\:m}\)

Explanation:

Given :-\(\sf\red{ Initial \ velocity = 36km/hr = 10m/s}\)\(\sf\orange{ Acceleration = 2m/s^{2}}\)\(\sf\green{Time = 1\:min = 60\: sec}\)

To Find :-\(\sf\blue{Distance \: Travelled}\)

Formula used :-\(\sf\purple{s = ut + \dfrac{1}{2} at^{2}}\)

Where,

s = \(\bold{Distance}\)t = \(\bold{Time }\)u = \(\bold{ Initial \ velocity}\)a = \(\bodl{Acceleration}\)

Solution :-

\(\Rightarrow\:\:\rm{s = 10(60) + \dfrac{1}{\cancel{2}} \times \cancel{2} \times (60)^{2}}\)

\(\Rightarrow\:\:\rm{s = 600+60\times 60}\)

\(\Rightarrow\:\:\rm{s = 600 + 3600}\)

\(\Rightarrow\:\:\rm{s = {\bf{\red{4200\:m}}}}\)

Hence, \(\bf\green{(B)}\) is the correct option
B)4200m. Is the correct answer

Calculate the energy in eV of a photon of blue light with a frequency of 6.10×1014 Hz.

a) 4.04 × 10- 19 eV
b) 5.75 × 10 66 eV
c) 9.20 × 10 47 eV
d) 2.52 × 10 0 eV

Answers

C) is the answer!!!
Explanation

How do you explain this arrangement of fossils? What might have happened?

Answers

Answer:

The question lacks a photo to fully answer correctly

If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.

If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.

Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.

Answer:

Peripatus, which lived around 570 MYA, is in the top layer of rock. The trilobites that lived later, between 498 MYA and 445 MYA, appear in the bottom layer. Based on superposition, younger layers of rock are expected to be on top. The rock layers have been overturned, placing the younger layer on the bottom.

Explanation:

actually answer plauto

NEED HELP ASAP!!!!!!!!!!
On which two variables does the strength of an electric force between two charged objects depend (multi choice)
•the total amount of electric charge
•the total mass of the objects
•the material(s) the objects are made of
•the distance between the objects

NEED HELP ASAP!!!!!!!!!!On which two variables does the strength of an electric force between two charged

Answers

He discovered that there were only two variables that influenced the force between charged particles: the separation here between particles and the amount much electric charge they contained,

How does one apply an electric charge to something?

An electrical charge is created when electrons are added to or removed from an object. An object becomes negatively charged when electrons are added because electrons flow charge. When electrons are taken away from something, it becomes positively charged.

Electric charge is what?

An elementary particle's electric charge, a fundamental feature of matter, determines how the particle will respond to an external magnetic field. Electric charge, which can be either positive or negative arises in distinct natural units and is not created neither destroyed.

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1. Which court is the ordinary trial courts of the Illinois Judicial Branch?
a. Illinois Supreme Court
c. Circuit Courts
b.Appellate Courts
d.District Courts

Answers

The circuit courts in Illinois have original jurisdiction as trial courts. There are 24 judicial circuits in the state, and each one includes one or more of the 102 counties that make up Illinois.

In Illinois, which court serves as the primary or general trial court?

All cases filed in the State of Illinois other than those for which the Supreme Court has original jurisdiction are first heard by the Circuit Court, which is the trial court with wide jurisdiction.

Which courts in Illinois have legal authority?

A Supreme Court, an Appellate Court, and Circuit Courts are in charge of the legal system. (Source: Constitution of Illinois.) JUDICIAL DISTRICTS SECTION 2 For the purpose of choosing judges for the Supreme and Appellate Courts, the State is divided into five judicial districts.

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Please help. Having a hard time figuring out

Please help. Having a hard time figuring out

Answers

yeah that’s is correct

The social model was created by​

Answers

Mike Oliver was the social media creator

A space probe is sent (from the surface of the Earth) to intercept a comet when it is at a distance
of 3 × 10^11 m from the Sun. Find the minimum energy required to move a 100-kg payload to
that location. [MEarth = 6 × 10^24 kg; REarth = 6.37 × 10^6 m; MSun = 2.0 × 10^30 kg; radius of
Earth’s orbit = 1.5 × 10^11 m.]

Answers

The energy that is required by the space probe is 2.94 * 10^14 J.

What is the energy required?

Let us recall that the gravitational potential energy is the energy that is possessed by a body by virtue of the position of the body in space. We know that the energy that is possessed by the space probe is the gravitational potential energy and we have to obtain the energy required.

Recall that energy required = Work done = mgh

m = mass of the object

g = acceleration due to gravity

h = distance covered

Then;

100-kg * 9.8 m/s^2 *  3 × 10^11 m

= 2.94 * 10^14 J

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The total clockwise moment about a pivot is 5 Nm and the total anti-clockwise moment is 10 Nm. Will the object turn?
Yes or no?

Answers

Answer:

Yes, the object will turn.

Explanation:

The object will turn because there is an net clockwise moment of 5 Nm and an anti-clockwise moment of 10 Nm, resulting in a net clockwise moment of 5 Nm. According to the laws of physics, an object will rotate in the direction of the net torque acting upon it. In this case, the net torque is acting in a clockwise direction, causing the object to rotate in that direction.

A 4.50-kg centrifuge takes 200 s to spin up from rest to its final angular speed with constant angular acceleration. A point P located 10.0 cm from the axis of rotation of the centrifuge moves with a speed of 150 m/s when the centrifuge is at full(final) speed. a) [4 points] What was its final angular speed

Answers

Answer:

Explanation:

ω = v / R

where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .

Given v = 150 m/s ; R =.10 m

ω = 150 / .10

= 1500 radian /s .

Final angular speed is 1500 radian /s .

How do I go about this?

How do I go about this?

Answers

Hi there!

(a)

Recall that:
\(W = F \cdot d = Fdcos\theta\)

W = Work (J)
F = Force (N)
d = Displacement (m)

Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.

\(W =248(56)cos(30) = 12027.36 J\)

To the nearest multiple of ten:
\(W_A = \boxed{12030 J}\)

(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.

Thus:
\(\boxed{W_g = 0 J}\)

(c)
Similarly, the normal force is perpendicular to the displacement, so:
\(\boxed{W_N = 0 J}\)

(d)

\(F_{f} =\mu_k N\)

In this instance, the normal force is equivalent to the downward force of gravity and the vertical component of the applied force.

\(N = F_g + F_A sin(30)\\\\N = mg + F_A sin(30)\\\\N = 56(9.8) + 248sin(30) = 672.8 N\)

Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
\(W_f = -\mu_k Nd\\W_f = - (0.1)(672.8)(56) = -3767.68J\)

In multiples of ten:
\(\boxed{W_f = -3770 J}\)

(e)
Simply add up the above values of work to find the net work.

\(W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3767.68) = 8259.68 J\)

Nearest multiple of ten:
\(\boxed{W_{net} = 8260 J}}\)

(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
\(F_{net} = F_{Ax} - F_f\)

\(W = F_{net} \cdot d = (F_{Ax} - F_f)\)

\(W = (F_Acos(30) - \mu_k N)d\\W = (248cos(30) - 0.1(672.8)) * 56 \\\\W = 8259.68 J\)

Nearest multiple of ten:
\(\boxed{W_{net} = 8260 J}\)

Which person will most likely hear the loudest sound?

A
B
C
D

Answers

Answer:

The youngest person

Explanation:

Hearing worsens with age

Please mark brainliest

Answer:

A

Explanation:

The person closest to the origin of the sound will most likely hear the loudest sound. ^^

Describe the motion of an object experiencing blueshift

Answers

A source travelling in the direction of the observer causes Doppler blueshift.

When an object is moving towards us, the light from the object is known as blueshift.

The phrase refers to any relative motion, that causes a decrease in the wavelength and rise in frequency, including those that take place outside of the visible spectrum.

During the motion of the object towards us, blueshift will happen, thus shifting light to shorter wavelengths on the blue side of the spectrum.

This causes the color to shift from the red to the blue end of the spectrum in visible light.

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Suppose that an object in free fall were somehow equipped with a speedometer. By how much would its speed readings increase with each second of fall? Express your answer to two significant figures and include the appropriate units.

Answers

Gravity is 9.8m/s^2
For every second the object travels 9.8m
When the object is at two seconds the distance travelled is gravity x time --> 9.8 x 2 = 19.6m/s^2
Finding the increase is just subtracting
19.6-9.8=9.8m/s^2

Which location on Earth receives the most solar radiation in any given year?

Answers

The location on Earth that receives the most solar radiation in any given year is typically the Sahara Desert in Africa.

What location of the Earth receives most solar radiation?

The Sahara receives the highest levels of solar radiation due to its location near the equator and its clear, cloudless skies. The combination of these two factors allows for maximum exposure to the sun's rays, leading to high levels of solar radiation throughout the year.

However, it's worth noting that other areas near the equator, such as the regions in South America, also receive a high amount of solar radiation.

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classify the conditions given as indicating that a reaction is at equilibrium, is not at equilibrium, or that the conditions may occur in either state.

Answers

Classification of the conditions indicating that a reaction is at equilibrium, is not at equilibrium, or that the conditions may occur in either state depends on the specific reaction and the factors that affect its position of equilibrium.

How can conditions be classified in a reaction?

To classify the conditions as indicating that reaction is at equilibrium, is not at equilibrium, or that the conditions may occur in either state, we need to consider the factors that affect the position of equilibrium for the reaction.

These factors include concentration of reactants and products,  temperature, the pressure (for gas-phase reactions), and the presence of catalysts.

The concentration of reactants and products is constant: This condition indicates that  reaction is at equilibrium, or that it has reached state of dynamic equilibrium, so rate of forward reaction is equal to rate of reverse reaction.

The concentration of reactants is greater than concentration of products: This condition indicates that reaction is not at equilibrium, and that  forward reaction is favored.

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What is the electric potential 15 cm above the center of a uniform charge density disk of total charge 10 nC and radius 20 cm?
a) 360 V
b) 450 V
c) 22.5 V
d) 0 V

Answers

Answer:

b) 450 V

Explanation:

We are given that

Total charge, q=10nC=\(10\times 10^{-9} C\)

\(1nC=10^{-9}C\)

Radius, r=20 cm=\(\frac{20}{100}=0.2m\)

1 m=100 cm

x=15 cm=0.15 cm

We have to find the electrical potential 15 cm above  the center of a uniform charge density disk .

We know that

\(\sigma=\frac{q}{A}=\frac{q}{\pi r^2}\)

\(\sigma=\frac{10\times10^{-9}}{3.14\times (0.2)^2}\)

Where \(\pi=3.14\)

\(\sigma=7.96\times 10^{-8}C/m^2\)

Electric potential,\(V=\frac{\sigma}{2\epsilon_0}(\sqrt{x^2+r^2}-x)\)

Where \(\epsilon_0=8.85\times 10^{-12}\)

Using the formula

\(V=\frac{7.96\times 10^{-8}}{2\times 8.85\times 10^{-12}}(\sqrt{(0.15)^2+(0.2)^2}-0.15)\)

\(V=449.7 V\approx 450V\)

Hence, option b is correct.

Answer:

The potential is given by 449.7 V.

Explanation:

radius of disc, R = 20 cm = 0.2 m

distance, x = 15 cm = 0.15 m

charge, q = 10 nC

surface charge density

\(\sigma = \frac{q}{\pi R^2}\\\\\sigma = \frac{10\times 10^{-9}}{3.14\times 0.2\times 0.2 }\\\\\sigma = 7.96\times 10^{-8} C/m^2\)

The electric potential is given by

\(V=\frac{\sigma}{2\varepsilon 0}\left ( \sqrt{R^2 + x^2} - x \right )\\\\V = \frac{7.96\times 10^{-8}}{2\times 8.85\times 10^{-12}}\left ( \sqrt{0.2^2 + 0.15^2} - 0.15 \right )\\\\V = 449.7 V\)

Describe a situation in which these two velocity vectors are different. Use complete sentences.

Answers

When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.

Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.



15 kHz

150 kHz

1500 kHz

150 Hz

Answers

Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

Have a great day! <3

If the number of revolutions is 300 and the paired poles are 50 , then the frequency would be 15 kHz, therefore the correct answer is option A.

What is the frequency ?

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,

F = 1 / T

As given in the problem, we have to calculate frequency if the number of revolutions is 300 and the paired poles are 50.

F = 300 × 50

  = 1500 kHz

Thus, If the number of revolutions is 300 and the paired poles are 50, then the frequency would be 15 kHz, therefore the correct answer is option A.

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34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again. ​

Answers

Answer and Explaination:

To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.

1. Gravitational force:

The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.

2. Force exerted by the spring:

The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Given:

Mass (m) = 5.0 kg

Compression of the spring (x) = 20.0 cm = 0.20 m

Angle of the inclined plane (θ) = 30°

First, let's find the force exerted by the spring (F_spring):

F_spring = -kx

To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.

Next, let's calculate the gravitational force components:

Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ

Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ

Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.

At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).

Therefore, we have:

F_perpendicular = F_spring

mg * cosθ = -kx

Now, let's substitute the known values and solve for k:

(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m

49.0 N * 0.866 = -k * 0.20 m

42.426 N = -0.20 k

k = -42.426 N / (-0.20 m)

k = 212.13 N/m

Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:

PE_spring = (1/2) * k * x^2

PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2

PE_spring = 4.243 J

The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.

KE_max = PE_spring = 4.243 J

Next, we can calculate the height (h) the mass reaches on the inclined plane:

KE_max = m * g * h

4.243 J = 5.0 kg * 9.8 m/s^2 * h

h = 4.243 J / (5.0 kg * 9.8 m/s^2)

h = 0.086 m

The height the mass reaches on the inclined plane is 0.086 m.

Now, we can calculate the distance traveled.

A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.

Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.

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chandani was intrested in researching the plant by mixing things in soil she decided to test the effect of lime eurea table salt and compost on the soil the she put that soil then she bought a bucket of good soil from the garden and mixed it well she put that soil in 12 equal size vases she put two spoons urea each time two spoond of compost of table salt each in another three vases and two spoons of compost each each in three vases after that she planted the seed in all the vases everyday and measure the height of each plant daily and keep record then identify dependent ,indrpendent and controlled variable​

Answers

The dependent, independent, and controlled variables​ are as follows:

1. Dependent - The effect of lime urea table salt and compost on the soil

2. Independent - The soil on which the elements are incorporated.

3. Controlled variable - The height of the plants.

What is the dependent, independent, and controlled variable?

The dependent variable is that which is tested in the experiment and in this experiment, Chandani is testing the effect of lime, urea, table salt, and compost on the soil.

The independent variable is the altered element in the experiment and for this experiment, this is the soil that receives different additives. Finally, the controlled variable is that which remains constant and that is the height of each plant that the researcher checks.

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Which of the following is a vector quantity
weight
temperature
acceleration
distance

Answers

Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

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