Convert 110 kilograms to pounds. (1 kilogram = 2.204 pounds)

\(~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ E(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad F(\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill EF=\sqrt{(~~ 3- 2~~)^2 + (~~ 1- 3~~)^2} \\\\\\ ~\hfill EF=\sqrt{( 1)^2 + ( -2)^2} \implies \boxed{EF=\sqrt{ 5 }}\)

\(F(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill FD=\sqrt{(~~ -1- 3~~)^2 + (~~ -1- 1~~)^2} \\\\\\ ~\hfill FD=\sqrt{( -4)^2 + ( -2)^2} \implies \boxed{FD=\sqrt{ 20 }} \\\\\\ D(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad E(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill DE=\sqrt{(~~ 2- (-1)~~)^2 + (~~ 3- (-1)~~)^2} \\\\\\ ~\hfill DE=\sqrt{( 3)^2 + (4)^2} \implies DE=\sqrt{ 25 }\implies \boxed{DE=5} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(E(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad F(\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{2}}} \implies \cfrac{ -2 }{ 1 } \implies - 2 \\\\[-0.35em] ~\dotfill\)

\(F(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{3}}} \implies \cfrac{ -2 }{ -4 } \implies \cfrac{1 }{ 2 } \\\\[-0.35em] ~\dotfill\)

\(D(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad E(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{(-1)}}} \implies \cfrac{3 +1}{2 +1} \implies \cfrac{4 }{ 3 }\)

Answer:

the amount of outstanding checks at the end of Nov and at the end of Dec is $1,730 and $1,015 respectively

Step-by-step explanation:

The computation of the amount of outstanding checks at the closing of Nov and dec is as follows

Particulars             November        December

Written checks     $10,310              $11,785

Less:

Presented checks  -$8,580            -$10,770

Outsanding checks $1,730              $1,015

Hence, the amount of outstanding checks at the end of Nov and at the end of Dec is $1,730 and $1,015 respectively

The polynomial of degree 3 with zeros at x = 3, x = -4, and x = 5 is P(x) = x^3 - 4x^2 - 17x + 60.  

To construct a polynomial of degree 3 with zeros at x = 3, x = -4, and x = 5, we can use the fact that the polynomial can be written as a product of linear factors corresponding to each zero.

The factor corresponding to x = 3 is (x - 3).

The factor corresponding to x = -4 is (x + 4).

The factor corresponding to x = 5 is (x - 5).

To obtain the polynomial, we multiply these factors together:

P(x) = (x - 3)(x + 4)(x - 5)

Expanding this expression gives us:

\(P(x) = (x^2 - 3x + 4x - 12)(x - 5)\)

\(= (x^2 + x - 12)(x - 5)\)

\(= x^3 - 5x^2 + x^2 - 5x - 12x + 60\)

\(= x^3 - 4x^2 - 17x + 60\).

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The range of the function is {0.01, 0.1, 1, 10, 100}. With an increase in the value of the domain, the range of the function is increasing.

What is a function?

A function from a set X to a set Y allocates exactly one element of Y to each element of X. The set X is known as the function's domain, while the set Y is known as the function's codomain.

Given function is

f(x) = 10^x.

Given domain is {-2, -1, 0, 1, 2}.

Now putting x = -2, -1, 0, 1, 2 in the function f(x) = 10^x.

When x = -2:

f(-2) = 10^(-2)

f(-2) = 0.01.

When x = -1:

f(-1) = 10^(-1)

f(-1) = 0.1.

When x = 0:

f(0) = 10^(0)

f(0) = 1.

When x = 1:

f(1) = 10^(1)

f(1) = 10

When x = 2:

f(2) = 10^(2)

f(2) = 100

The range of the function is {0.01, 0.1, 10, 100}

The values of the range increase with the increase of domain.

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For given function function f(x)=-x+3-2, the domain is x > -3 and the range is y ≤ 2. So, correct option is D.

The function f(x)=-x+3-2 is a linear function in the form y=mx+b, where m is the slope and b is the y-intercept. In this case, the slope is -1 and the y-intercept is 1. Therefore, the graph of the function is a straight line that intersects the y-axis at (0,1) and has a slope of -1, meaning that it decreases by 1 for every 1 unit increase in x.

The domain of the function is the set of all possible values of x for which the function is defined. Since there are no restrictions on the value of x in the equation f(x)=-x+3-2, the domain is all real numbers, or (-∞, ∞).

The range of the function is the set of all possible values of y that the function can output. In this case, the lowest possible value of y occurs when x approaches positive infinity, and the highest possible value of y occurs when x approaches negative infinity. Therefore, the range is all real numbers less than or equal to 2, or y ≤ 2.

So, the domain is x ∈ (-∞, ∞) and the range is y ≤ 2. Alternatively, the domain can also be expressed as x > -3, since that is the minimum value of x at which the function is defined.

Correct option is D.

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Complete question is:

What are the domain and range of the function f(x)=-x+3-2?

A) domain: -3 -2

B) domain: -3 -3 range: y<-2

C) domain: x>-3 range:y>-2

D) domain : x>-3 range: y ≤ 2

Answer:

2.26

Step-by-step explanation:

The volume of a cylinder is equal to pi*r^2*h

3.14*r^2*25=400

r^2=5.09554140127

r~2.26

Answer:

Step-by-step explanation:

r= roughly 2.26

r= square root v/pi x height

Answer:

The value of x is : \(\mathbf{8\sqrt{2}}\)

Option C is correct.

Step-by-step explanation:

We need to find value of x

We are given Perpendicular = 8

Hypotenuse = x

and Ф= 45°

Using trigonometric identity

\(sin \theta=\frac{Perpendicular}{Hypotenuse}\)

Putting values and finding x

\(sin \theta=\frac{Perpendicular}{Hypotenuse}\\sin \ 45^o=\frac{8}{x}\\\frac{1}{\sqrt{2} }= \frac{8}{x}\\\frac{1}{\sqrt{2} }x=8\\x=8\sqrt{2}\)

So, the value of x is : \(\mathbf{8\sqrt{2}}\)

Option C is correct.

Since Amy is determining the difference between the number of butterflies she saw in the past 4 months (figure A) and this month (figure B), her next step is to subtract figure A from figure B.

The difference between the two figures or numbers is the result of a subtraction operation.

A subtraction operation, which is one of the four basic mathematical operations, involves the minuend, subtrahend, and difference, using the minus sign (-) and the equal symbol (=).

Thus, Amy's next step is a subtraction operation to find the difference.

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Answer:

I THINK Vertical ( I'm not positive) Goodluck

Answer:

B) Decreasing

It getting smaller every time

Answer:

if you have a pic of question send it plz then will give answer

Step-by-step explanation:

Answer: 20

Step-by-step explanation:

Answer:

A list of numbers or objects in a special order. Example: 3, 5, 7, 9, ... is a sequence starting at 3 and increasing by 2 each time.

Step-by-step explanation:

Answer:

8/73

0.10959

21 players

Step-by-step explanation:

Given that:

Number of teams = 25

Number of players per team = 73

Number of players chosen for drug testing = 8

A) What is the probability that Erik Red is chosen for random drug testing in a specified week of the foosball season?

Number chosen per team / number of players per team

8 / 73 = 0.10959

B) What is the probability that Erik Red is chosen for random drug testing at least 5 times in the first 9 weeks of the foosball season?

P( being chosen at least 5 times)

USing binomial. Distribution

P(X =x) = nCr * p^x * (1-p)^n-x

To save computation time, we can use the binomial distribution calculator :

P(x≥5):p(x = 5) + p(x = 6) + p(x =7) + p(x = 8) +. P(x = 9) = 0.00136

C) What is the expected number of players who are chosen for random drug testing at least 4 times in the first 9 weeks of the foosball season?

Number who are chosen atleast 4 times :

P(x ≥ 4) = p(x = 4) + p(x = 5) + p(x = 6) + p(x = 7) + p(x = 8) +. P(x =9) = 0.0115

P(x ≥ 4) * number of players per team * nunber of teams in league

0.0115 * 73 * 25 = 20.9875

= 21 players

D) Let Y be the number of players who are chosen for random drug testing at least 4 times in the first 9 weeks of the foosball season. What is the maximum possible value of Y, i.e., the largest k such that P(Y=k) > 0?

The day, from the following two days, which would be the best to sell both stocks with the closing price is day 3 by an amount of $2.45.

Given are the closing prices of two stocks in three days.

If you purchase 65 shares of Metropolis stock and 50 shares of Suburbia stock on Day 1 at the closing price,

Amount invested = (65 × 17.95) + (50 × 5.63) = $1448.25

If the stock is sold in day 2,

Amount received = (65 × 18.25) + (50 × 4.98) = $1435.25

Profit = $1435.25 - $1448.25 = -$13

If the stock is sold in day 3,

Amount received = (65 × 18.28) + (50 × 5.25) = $1450.7

Profit = $1450.7 - $1448.25 = $2.45

The profit is more for day 3 than day 2.

Hence it is best to sell on day 3 by $2.45.

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The statement "for every positive rational number x, there exist positive integers n1, ..., nk such that x = n1/n2 + ... + nk/nk" is known as the Egyptian fraction representation theorem and is proved.

Let x be a positive rational number with numerator p and denominator q, where p and q are coprime. Let's assume that x can't be represented as a sum of positive unit fractions (i.e., fractions with numerator 1).

Then, construct a sequence of positive rational numbers x1, x2, ..., xk such that x1 = x and for each i, xi is equal to the difference between xi-1 and the largest unit fraction that is less than or equal to xi-1.

Since x is a positive rational number, it follows that xi is also a positive rational number for all i. Since x can't be represented as a sum of positive unit fractions, it follows that xi can't be represented as a sum of positive unit fractions for all i. Since the sequence x1, x2, ..., xk is constructed as the difference of two positive rational numbers, it follows that xi is a positive rational number for all i.

Since x1 = x, it follows that there exists a positive integer n such that x1 is equal to n/n + 1. But this contradicts our assumption that x can't be represented as a sum of positive unit fractions. Thus, our assumption is false, and it follows that x can be represented as a sum of positive unit fractions.

Therefore, we have proved that for every positive rational number x, there exist positive integers n1, ..., nk such that x = n1/n2 + ... + nk/nk.

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_____The given question is incomplete, the complete question is given below:

prove: let x be a positive rational number, then there exist positive integers n1, ..., nk such that x = n1/n2 + ..... + nk/nk.

To prove that (secx+tanx)² = (cscx+1)/(cscx-1), we will start with the left-hand side (LHS) of the equation and simplify it step by step until it matches the right-hand side (RHS) of the equation.

LHS: (secx+tanx)²

Using the trigonometric identities secx = 1/cosx and tanx = sinx/cosx, we can rewrite the LHS as:

LHS: (1/cosx + sinx/cosx)²

Now, let's find a common denominator and simplify:

LHS: [(1+sinx)/cosx]²

Expanding the squared term, we get:

LHS: (1+sinx)² / cos²x

Next, we will simplify the denominator:

LHS: (1+sinx)² / (1 - sin²x)

Using the Pythagorean identity sin²x + cos²x = 1, we can replace 1 - sin²x with cos²x:

LHS: (1+sinx)² / cos²x

Now, let's simplify the numerator by expanding it:

LHS: (1+2sinx+sin²x) / cos²x

Next, we will simplify the denominator by using the reciprocal identity cos²x = 1/sin²x:

LHS: (1+2sinx+sin²x) / (1/sin²x)

Now, let's simplify further by multiplying the numerator and denominator by sin²x:

LHS: sin²x(1+2sinx+sin²x) / 1

Expanding the numerator, we get:

LHS: (sin²x + 2sin³x + sin⁴x) / 1

Now, let's simplify the numerator by factoring out sin²x:

LHS: sin²x(1 + 2sinx + sin²x) / 1

Using the fact that sin²x = 1 - cos²x, we can rewrite the numerator:

LHS: sin²x(1 + 2sinx + (1-cos²x)) / 1

Simplifying further, we get:

LHS: sin²x(2sinx + 2 - cos²x) / 1

Using the fact that cos²x = 1 - sin²x, we can rewrite the numerator again:

LHS: sin²x(2sinx + 2 - (1-sin²x)) / 1

Simplifying the numerator, we have:

LHS: sin²x(2sinx + 1 + sin²x) / 1

Now, let's simplify the numerator by expanding it:

LHS: (2sin³x + sin²x + sin²x) / 1

LHS: 2sin³x + 2sin²x / 1

Finally, combining like terms, we get:

LHS: 2sin²x(sin x + 1) / 1

Now, let's simplify the RHS of the equation and see if it matches the LHS:

RHS: (cscx+1) / (cscx-1)

Using the reciprocal identity cscx = 1/sinx, we can rewrite the RHS:

RHS: (1/sinx + 1) / (1/sinx - 1)

Multiplying the numerator and denominator by sinx to simplify, we get:

RHS: (1 + sinx) / (1 - sinx)

Now, we can see that the LHS and RHS are equal:

LHS: 2sin²x(sin x + 1) / 1

RHS: (1 + sinx) / (1 - sinx)

Therefore, we have proven that (secx+tanx)² = (cscx+1)/(cscx-1).

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Answer:

No

Step-by-step explanation:

No, it is not a solution. You can find this answer by plugging in 12 for 2 for w.

0>12-132/12

132/12=11

12-11=1

0>1

0 is not greater than 1, so the answer is no.

Answer:

So if im entirely correct you said

Step-by-step explanation:

deeznutz

Answer:

Step-by-step explanation:

The volume is the summation of the volumes of the shells. The volume of a shell is its circumference ...

  c(x) = 2πx

multiplied by its height ...

  h(x) = 5x(x -2)^2

and its thickness, dx.

That summation is the integral ...

  \(\displaystyle V=\int^2_0 {2\pi x(5x)(x-2)^2} \, dx=10\pi\int^2_0 {(x^2-2x)^2} \, dx=10\pi\left(\dfrac{2^5}{5}-\dfrac{4(2^4)}{4}+\dfrac{4(2^3)}{3}\right)\\\\\boxed{V=\dfrac{32\pi}{3}}\)

The circumference of the shell  is c(x) = 2πx

The height of the shell is \(h(x) = 5x(x-2)^{2}\)

The required volume of the shell is \(\frac{32\pi}{3}\).

Given that,

S be the solid obtained by rotating the region,

Where, a = 5 and b =2

We have to determine ,

What are its circumference c and height h.

According to the question,

          c(x) = 2πx

          \(h(x) = 5x(x-2)^{2}\)

\(V = \int (circumference) \ )(height )\ . dx\\\\\)

Where dx thickness of the shell.

Substitute the value in the equation,

\(v = \int\limits^2_0 {2\pi x .(5x) (x-2)^{2} }\, dx\\\\v = \int\limits^2_0 {10\pi x^{2} (x-2)^{^{2}} \ d x\\\\\\v =10\pi \int\limits^2_0 {x^{2}.(x^2+4-4x)} \, dx \\\\V = 10\pi \int\limits^2_0( {x^{4} + 4x^{2} - 4x^{3}) \, dx\)

\(v = 10\pi \ [ \dfrac{x^{5}}{5} + \dfrac{4x^{3}}{3} - x^{4}]^{2}_0\\\\v = 10\pi [ \dfrac{2^{5}}{5} + \dfrac{4.2^{3}}{3} - 2^{4} - \dfrac{0^{5}}{5} -\dfrac{4.0^{3}}{3} + 0^{4}]}\\\\v = 10\pi \ [ \dfrac{32}{5} + \dfrac{32}{3} - 16 -0-0+0]\\\\v = 10\pi [\dfrac{96+160-240}{15}]\\\\v = 10\pi [\dfrac{16}{15}]\\\\v = \dfrac{32\pi }{3}\)

Hence, The required volume of the shell is \(\dfrac{32\pi}{3}\).

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The area of the square A is 19.98 square feet

From the question, we have the following parameters that can be used in our computation:

Two squares constructed on the sides of a rectangle.

Let the side lengths of square C be x

Let the side lengths of rectangle B be x and y

So, we have

x² = 5

xy = 10

Solving for x and y, we have

x = 2.24 and y = 4.47

The area of square A is

Area = y²

So, we have

Area = 4.47²

Evaluate

Area = 19.98

Hence, the area of the square A is 19.98 square feet

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Answer: a deposit of $979.56 must be made now to have a balance of $1500 after 8 years with continuous compounding at 4.75% annual interest.

Step-by-step explanation: We can use the formula for continuous compounding:

A = Pe^(rt)

where A is the ending balance, P is the principal (initial deposit), e is the constant 2.71828..., r is the annual interest rate (as a decimal), and t is the time in years.

In this case, we know that A = $1500, r = 0.0475 (4.75% as a decimal), and t = 8 years. We want to solve for P.

P = A/e^(rt)

P = $1500/e^(0.0475*8)

P = $979.56 (rounded to the nearest cent)

Therefore, a deposit of $979.56 must be made now to have a balance of $1500 after 8 years with continuous compounding at 4.75% annual interest.

Answer:

Just some background:

Congruent means that a triangle has the same angle measures and side lengths of another triangle.

SAS congruence theorem: If two sides and the angle between these two sides are congruent to the corresponding sides and angle of another triangle, then the two triangles are congruent. Congruent triangles: When two triangles have the same shape and size, they are congruent.

Let's look at A first.

The triangle on left, we know 40 and 30 degree angles. So 3 all angles together = 180, so the 3rd angle = 180-30-40 = 110.

Now look at the triangle on the right. The angle shown is 110! This angle is between the sides marked with || and ||| marks, indicating that those two sides are the same length between both triangles.

Therefore both triangles are the same by Side-Angle-Side or SAS.

Now look at B.

It's a right triangle. We are missing 1 side of each triangle.

Let's solve for the missing "leg" of the triangle on the right. The pythagorean theorem says that a^2 + b^2 = c^2 where a and b are the 'legs' or sides of the triangle and c is the hypotenuse (always the longest length opposite the right angle).

so 2^2 + b^2 = 4^2

4 + b^2 = 16

b^2 = 16-4

b^2 = 12

That missing side is the \(\sqrt{12}\).

This does NOT match the triangle on the left.

Theses two triangles are NOT congruent.

Answer:

h(-4) = -2

h(11) = 5

The function h is a linear function that describes the relationship between two variables, x and y. It is defined as a straight line on a graph. The equation for this linear function is y = mx + b, where m is the slope of the line and b is the y-intercept.

To calculate the value of h for a given x, we need to know the slope m of the line and the y-intercept b. For the function h, m = 3 and b = -6. This means that for every 1 unit increase in x, y will increase by 3 units.

So, to calculate h(-4), we plug -4 into the equation and solve for y:

y = 3x - 6

y = 3(-4) - 6

y = -12 - 6

y = -18

Therefore, the value of h(-4) is -18.

To calculate h(11), we plug 11 into the equation and solve for y:

y = 3x - 6

y = 3(11) - 6

y = 33 -

Step-by-step explanation:

Answer: It would be -44

Step-by-step explanation: So, if we are finding the value of this expression: h(-4), we have to find out what h= (which is 11) Then, you take that and multiply it by -4, to get -44 (positive x negative = negative) I hoped this helped.

We can see here that the data set approximately periodic. The period and amplitude is: Periodic with a period of 4 and an amplitude of about 30.

The size or magnitude of a wave or vibration is measured by its amplitude in physics. It describes the greatest deviation of a wave from its equilibrium or rest state, or the greatest intensity of an electromagnetic or sound wave.

When referring to waves, amplitude is commonly calculated as the distance between a wave's peak or trough and its resting position.

We can deduce that the values are being repeated at regular interval of four (4).

For the amplitude:

\(Amplitude: \frac{140 - 74}{2}\)

Amplitude = 33 ≈ 30.

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Answer:

a)9. b) 12

Step-by-step explanation:

a) | -6 -3 | .

-6-3 = -9

|-9| =9

b) | 0 - 12 |.

0-12=-12

|-12|=12

Answer:

What is a linear function? A linear function is a function whose graph is a straight line. The rate of change of a linear function is constant. The function shown in the graph below, y = x + 2, is an example of a linear function.

Graph of linear function

Graph of linear function

A linear function has a constant rate of change. The rate of change is the slope of the linear function. In the linear function shown above, the rate of change is 1. For every increase of one in the independent variable, x, there is a corresponding increase of one in the dependent variable, y. This gives a slope of 1/1 = 1.

A linear function is typically given in the form y = mx + b, where m is equal to the slope, or constant rate of change.

Examples of linear functions include:

If a person drives at a constant speed, the relationship between the time spent driving (independent variable) and the distance traveled (dependent variable) will remain constant.

Assuming no change in price, the relationship between the number of pounds of bananas a person buys (independent variable) and the total cost of the bananas (dependent variable) will remain constant.

If a person earns an hourly wage at their job, the relationship between the time spent working (independent variable) and the amount earned (dependent variable) will remain constant.

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Exponential Functions

What is an exponential function? An exponential function is a function that involves exponents and whose graph is a smooth curve. The rate of change in an exponential function is not constant. The functions shown in the graph below, y = 0.5x and y = 2x, are examples of exponential functions.

Graphs of exponential functions

Graphs of exponential functions

An exponential function does not have a constant rate of change. The rate of change in an exponential function is the value of the independent variable, x. As the value of x increases or decreases, the rate of change increases or decreases as well. Rather than a constant change, as in the linear function, there is a percent change.

An exponential function is typically given in the form y = (1 + r)x, where r represents the percent change.

Examples of exponential functions include:

Step-by-step explanation:

Answer:

-38

Step-by-step explanation:

it's subtracting 7 everytime, and -31-7=-38

Answer:

Grogg's dad is 22

Step-by-step explanation:

Let D = dad's current age

Let g = Grogg's current age

6(d - 7) = g - 7 → 6d - 42 = g - 7 → 6d -35 = g

4(d - 3) = g - 3 → 4d -12 = g - 3 → 4d -9 = g

Set the two equations equal to each other and solve for d

6d - 35 = 4d - 9  Subtract 4d from both sides

2d -35 = -9  Add 35 to both sides

2d = 44  Divide both sides by 2

d = 22

Helping in the name of Jesus.

Answer:

Step-by-step explanation:

d = current dad age

g = current grogg age

d-7 = 6(g-7)

d-3 = 4(g-3)

Let's solve the first equation first:

Add 7 to both sides: d - 7 +7 = 6g - 42 + 7 so d = 6g - 35

Substitude d = 6g - 35 for d in d - 3 = 4g - 12

(6g-35)-3 = 4g-12 = 6g-38 = 4g-12

Subtract 4g from both sides: 2g - 38 = -12

Add 38 to both sides: 2g = 26

Easy: g = 13

And now substitude g in for any equations.

d-3 = 52-12

d = 43

a. The probability that both of them are good is 9/16

b. Probability that one battery is good while one 3/16

c. probability that both batteries are bad is 1/16

A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1.

Probability = sample space / total outcome

the sample space for bad batteries = 5

the sample space for good batteries = 15

Therefore

a. probability that both are good = 15/20 × 15/20 = 3/4 × 3/4 = 9/16

b. probability that a battery is good and the other is bad = 15/20 × 5/20

= 3/4 × 1/4 = 3/16

c. The probability that both are bad

= 5/20 × 5/20 = 1/4 × 1/4 = 1/16

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Answer:

<1 = 100

<2 = 80

Step-by-step explanation:

Angle 1 and angle 2 are supplementary

Supplementary angles add to 180 degrees

<1 + <2 = 180

The angles are in a ratio of 5 to 4

Multiply by x to get the measure of each angle

<1 = 5x  <2 = 4x

5x+4x = 180

Combine like terms

9x = 180

Divide by 9

9x/9 =180/9

x =20

<1 = 5x = 5*20 = 100

<2 = 4x = 4*20 = 80

Answer:

m1 = 122

m2 = 58

m5 = 68

Step-by-step explanation:

m2 = 180 - 54 - 68 = 58

m1 = 180 - m2 = 180 - 58 = 122

m5 = 180 - 58 - 54 = 68