Copper wire of diameter 0.289 cm is used to connect a set of appliances at 120 V, which draw 1850 W of power total. The resistivity of copper is 1.68×10−8Ω⋅m.
A. What power is wasted in 26.0 m of this wire?
B. What is your answer if wire of diameter 0.417 cm is used?

The temperature of a substance is determined by the average kinetic energy of its particles, so Substance X and Substance Y have higher temperatures because their particles have more kinetic energy. The number of particles does not affect temperature. The correct options are (A) and (C).

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Answer:

53466kg.

Explanatiokn:

Answer:

A quantity that has magnitude but no particular direction is described as scalar. A quantity that has magnitude and acts in a particular direction is described as vector.

The difference between scalar and vector quantities is simply the direction we always consider when dealing with vector quantities.

Scalar quantities are those quantities that have only magnitude but no direction. Examples are;

Vector quantities are those quantities that have both magnitude and direction. Examples are;

The difference between scalar and vector quantities is simply the direction we always consider when dealing with vector quantities.

Therefore, direction is the difference between them.

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Answer:

C

Explanation:

Option C is correct since it is the effect of Newton’s third law.

Guiseppe's buys supplies to make pizzas at a cost of $4.02. Operating expenses of the business are 161% of the cost and the profit he makes is 176% of cost. The regular selling price of each pizza is $7.33.

Let's denote the cost of supplies as C.

Operating expenses:

The operating expenses of the business are 161% of the cost. Therefore, the operating expenses can be calculated as:

Operating Expenses = 1.61 * C

Profit:

The profit made by Guiseppe is 176% of the cost. Therefore, the profit can be calculated as:

Profit = 1.76 * C

Total cost:

The total cost includes the cost of supplies and the operating expenses:

Total Cost = C + Operating Expenses = C + 1.61 * C = 2.61 * C

Regular selling price:

The regular selling price is the sum of the total cost and the profit:

Regular Selling Price = Total Cost + Profit = 2.61 * C + 1.76 * C = 4.37 * C

Given that the cost of supplies is $4.02, we can substitute this value into the equation:

Regular Selling Price = 4.37 * 4.02 = $17.5674

Rounding the final answer to the nearest cent, the regular selling price of each pizza is approximately $7.33.

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If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

A riddle is a statement, question or phrase having a double or veiled meaning, put forth as a puzzle to be solved.

If Robert, your neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long, based on these statements, we can explain the riddle as Robert weighs iron for the fact that he  is a blacksmith, iron is the only thing he weighs the whole day.

Thus, the correct explanation for the riddle is " The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

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Answer:

I think it is heart engine. I am studying Mechanics aswell

Answer:

A) heat engine

Explanation:

At point A the force is 571.6 N. At point B the force is 632.8 N. The minimum speed at point A is 8.32 m/s

The force of the car seat on the child can be determined using the equation F = m * a, where F is the force, m is the mass, and a is the acceleration. The acceleration can be found using the equation a = v^2/r, where v is the speed and r is the radius.
(a) At point a, the speed is 10.0 m/s and the radius is 7.00 m. Therefore, the acceleration is:
a = (10.0 m/s)^2 / (7.00 m) = 14.29 m/s^2
The force of the car seat on the child is:
F = (40.0 kg) * (14.29 m/s^2) = 571.6 N
(b) At point b, the speed is 10.5 m/s and the radius is 7.00 m. Therefore, the acceleration is:
a = (10.5 m/s)^2 / (7.00 m) = 15.82 m/s^2
The force of the car seat on the child is:
F = (40.0 kg) * (15.82 m/s^2) = 632.8 N
(c) The minimum speed required to keep the child in his seat at point a can be found by rearranging the equation for acceleration:
v = sqrt(a * r)
Since the force of the car seat on the child must be equal to or greater than the force of gravity on the child (F = m * g), the acceleration must be equal to or greater than the acceleration due to gravity (a = g = 9.81 m/s^2).
Therefore, the minimum speed is:
v = sqrt((9.81 m/s^2) * (7.00 m)) = 8.32 m/s

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Answer:

The volume of the block is equal to the volume of water displaced by the block.

Explanation:

Volume refers to the amount of space occupied by a given object (in this case the block). When an object such as the block is immersed in water, it displaces its own volume of water. This volume of water displaced is equal to the volume of the block. Hence we can write;

Final Volume of water - Initial Volume of water= Water Displaced = Volume of the block

Recall that the density of a body is given by;

Density= mass/volume

If we obtain the volume of the block by measuring the volume of water displaced by the block, then we weigh the block using a weighing balance, we can obtain the density of the block easily from the relationship shown above.

Answer:

The kinetic energy of the particle as it moves through point B is 7.9 J.

Explanation:

The kinetic energy of the particle is:

\(\Delta K = \Delta E_{p} = q\Delta V\)

Where:

K: is the kinetic energy

\(E_{p}\): is the potential energy

q: is the particle's charge = 0.8 mC

ΔV: is the electric potential = 1.5 kV                                    

\(\Delta K = q \Delta V= 0.8 \cdot 10^{-3} C*1.5 \cdot 10^{3} V = 1.2 J\)

Now, the kinetic energy of the particle as it moves through point B is:

\( \Delta K = K_{f} - K_{i} \)

\( K_{f} = \Delta K + K_{i} = 1.2 J + 6.7 J = 7.9 J \)

Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.

I hope it helps you!      

Answer:

Kinetic energy is greater than the potential energy.

Explanation:

The potential energy stays constant because the height is not changing.  Potential energy = MGH, where m is the mass (400 kg), g is the acceleration due to gravity (9.8 m / sec2), and H is the height (1 m).  So the result is 400 * 9.8 * 1 = 3920 J

The kinetic energy = 1/2 mv2 = 0.5  * 400 kg * (5 m/sec)2 = 5000 J.  It also stays constant because the speed is not changing.

Therefore, the kinetic energy is greater than the potential energy.

Answer:

Explanation:

The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.

Using the graph given :

The work done from x = 0 to x = 16 metres ;

The distance can be split evenly into :

(x = 0 to x = 8) and (x = 8 to x = 16)

Workdone = Force × distance

Workdone from ; x = 0 to x = 8 ;

Force at a distance of 8 meters = - 40N

Workdone = - 40N × 8 m = -320 Nm

Workdone from ; x = 8 to x = 16 ;

Force at a distance of 16 meters = 40 N

Workdone = 40 N × 8 m = 320 Nm

The total workdone :

(-320 + 320) Nm = 0 J

.

Therefore, the Workdone ls 0 Joules.

Answer:To explian the exact calculation of this pruduct we must not try!

An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I

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If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

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A. Sheets of copper (Cu) could be a good option for replacing the foam and carbon material in the hero's costume. Copper is a relatively soft metal and can easily be shaped and molded. When hit with a lead pipe, it will dent but not crumble like foam and carbon. Additionally, copper has a distinctive color that could look interesting on the hero's costume.

B. Large discs of chlorine (Cl) would not be a good option for replacing the foam and carbon material. Chlorine is a highly reactive and dangerous gas that is used to disinfect swimming pools. It is not a solid material and would not provide the desired effect when hit with a lead pipe.

C. A barrel of phosphorus (P) would also not be a good option for replacing the foam and carbon material. Phosphorus is a highly reactive and flammable substance that is used as a component in explosive powder. It is not a solid material and would not provide the desired effect when hit with a lead pipe. Additionally, it is highly dangerous and should not be used in a movie set.

D. A tank of helium (He) would also not be a good option for replacing the foam and carbon material. Helium is a gas and would not provide the desired effect when hit with a lead pipe. Additionally, it is not a solid material and would not be suitable for the costume.

Overall, the best option would be A, sheets of copper, as it is a solid material that can easily be shaped and molded, and will dent but not crumble when hit with a lead pipe.

In this solution, the unit vectors in the directions of A + B, A × B, and 2A + 3C are √62,√1915, and √686. The magnitudes of A + B, A × B, and 3A - 2C are √62, √1915, and √164. The angles between A × B and B × A, A and C, and B and C are √30, cos-1(4/√35), and cos-1(-1/√14).

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When the liquid cools down, it loses heat energy.

As the liquid cools, it loses heat energy. As a result, its particles slow down in movement and come closer to one another. Attractive forces begin to hold particles and the crystals of a solid form.

If water is cooled, it can change into ice. If ice is warmed, it can change into a liquid state. Heating a substance makes the molecules move very fast whereas cooling a substance makes the molecules move very slowly.

Heating a liquid increases the speed of the molecules present in it. An increase in the molecule's speed competes with the attraction between molecules and results in the molecules moving apart whereas Cooling a liquid decreases the movement of the molecules.

So we can conclude that the liquid cools down when it loses heat energy.

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Answer:

\(\alpha =1\ rad/s^2\)

Explanation:

It is given that,

The radius of a wheel, r = 2 m

Tangential acceleration of the wheel, \(a=2\ m/s^2\)

We need to find the angular acceleration of the wheel. We know that the relation between angular and tangential acceleration is given by :

\(a=\alpha r\\\\\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{2}{2}\\\\\alpha =1\ rad/s^2\)

So, the angular acceleration of the wheel is \(1\ rad/s^2\).

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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Answer:

b. the electromagnetic spectrum

Explanation:

the electromagnetic spectrum contains all the forms of light, including gamma rays, x-rays, ultraviolet radiation, visible light, infrared, radio waves, microwaves, etc

Answer:

plz write your questions in English

The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.

To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.

The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.

The force experienced by the wire due to the magnetic field is F = B * I * L.

Given:

Current (I) = 8.0 A

Magnetic field (B) = 60 mT = 60 * 10^(-3) T

Length of the wire (L) = 40 cm = 40 * 10^(-2) m

Substituting the given values into the equation, we get:

F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)

Simplifying the expression, we find:

F = 0.192 N

Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.

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Answer:

75 kg

Explanation:

Net Force

\(\sf \longmapsto F_{net} = 225N\)

Acceleration produced

\(\sf \longmapsto \: a = 3 .0 m / {s}^{2}\)

According to Newton's 2nd Law –

F = m•a

\(\sf \longmapsto \: M = \frac{F}{a} \)

\(\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } \)

\(\sf \longmapsto \: M = \: 75 \: kg\)

Hence, the mass of an object is 75 kg.

The Moment of inertia of the cylinder is equal to 8.82 Kgm².

The propensity of a force to produce or modify the rotational motion of a body is known as torque, also known as moment, or moment of force. It is a force that causes an object to twist or turn. Force and distance are multiplied to calculate torque. It has both a direction and a magnitude because it is a vector quantity. Newton-meters, or N*m, is the torque unit in the SI system.

A spinning object's change in angular velocity per unit of time is expressed quantitatively as angular acceleration, also known as rotational acceleration. It has a vector form.

Given in the question

Torque = 75 Nm

Angular acceleration = 8.5 rad/s²

Torque = Angular acceleration × moment of inertia

Put in the value, we get

Moment of inertia = 75/ 8.5

Moment of inertia = 8.82 Kgm²

So the Moment of inertia of the cylinder is equal to 8.82 Kgm².

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