CS Algebra
Test Iten
Given the equations below, what is the product of x and y?
3
8(x - 2) = 2x + 8
ay+9 = -2(y + 1)
=
A 16
B 4
C4
0 c
D -16

Answer:

3 coins each row

Step-by-step explanation:

if you put 3 coins in 4 rows it we'll be equivalent to 12

Answer:

25%

Step-by-step explanation:

\(percentage \: increase \\= \frac{10 - 8}{8} \times 100 \\ \\ = \frac{2}{8} \times 100 \\ \\ = \frac{1}{4} \times 100 \\ \\ = 25 \%\)

The increase in height from 8 to 10 feet is 25%. To calculate a percentage, divide the value by the total value and multiply the result by 100.

Therefore,

percentage increase

= (10 - 8) / 8 × 100

= 2/8 × 100

= 1/4 × 100

= 25%

Hence, The increase in height from 8 to 10 feet is 25%.

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Answer: –55x + 570

Step-by-step explanation:

The person above me completely missed the question so this is the right one

Answer:

pppppppppppppppppppppppppppppppppppppppppp

Answer:

A. Theoretical results are correct, regardless of how many cards are drawn.

Step-by-step explanation:

Answer: A. Theoretical results are correct, regardless of how many cards are drawn.

Step-by-step explanation:

Plato

Answer:

2/8 = 1/4

4/8 = 1/2

6/10 = 3/5

Step-by-step explanation:

Divide both numbers by the same number. For example, 6 ÷ 2  and 10 ÷ 2 would equal 3/5.

-kiniwih426

Answer:

  a. (4, 26)

  b. The number of people jogging in 2004 was 26 million.

  c. 43 million

Step-by-step explanation:

To complete the ordered pair, use the given first value of the pair as the value of the variable in the equation. Evaluate the equation to find the second value of the ordered pair:

  y = x +22

  y = 4 +22 = 26

The ordered pair is (4, 26).

__

The ordered pair tells you (years after 2000, number of joggers in millions). That means the ordered pair (4, 26) tells you 4 years after 2000, there were 26 million joggers.

__

21 years after 2000, the value of x is 21, so the value of y is ...

  y = 21 +22 = 43

There will be 43 million joggers in 2021.

Step-by-step explanation:

The formula:

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=

�

2

(

�

1

+

�

�

)

S

n

=

2

n

(a

1

+a

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)

is used to solve for the sum of the arithmetic sequence given the first term a₁, the number of terms n, and the last term in an.

Example:

3, 6, 9, 12, 15,...,123

The first term, a₁ = 3

The last term an = 123

Common difference, d = 3 (because the sequence are multiples of 3)

Number of terms, n= ?

Find the number of terms, n:

an = a₁ + (n-1) (d)

123 = 3 + (n-1) (3)

123 = 3 - 3 + 3n

123/3 = 3n/3

n = 41

To find the sum of the given sequence without adding 3 + 6 + 9, ... + 123, we use the formula:

S₄₁ = (41/2) (3 + 123)

S₄₁ = (41/2) (126)

S₄₁ = (41)(63)

S₄₁ = 2,583 ⇒ the sum of the given sequence

i can't graph it for you but

x is greater than or equal to 7

Answer:

y=9/8x+-3/2

Step-by-step explanation:

Step 1: Add -9x to both sides.

9x−8y+−9x=12+−9x

−8y=−9x+12

Step 2: Divide both sides by -8.

-8y/-8=-9x+12/-8

y=9/8x+ -3/2

Answer:

C). 8/9n - 1 1/3

Step-by-step explanation:

Answer:

\(\frac{8}{9} n - 1\frac{1}{3}\)

Step-by-step explanation:

Using the distributive property \(\frac{4}{9}\) times 2 equals \(\frac{8}{9}\) and \(\frac{4}{9}\) times 3 equals \(\frac{4}{3}\) which simplifies to \(1\frac{1}{3}\)

Step-by-step explanation:

The radius of the orbit is r = 1150 km + 6400 km = 7550 km or

\(r = 7.55×10^6\:\text{m}\)

and it takes 140 minutes to complete 1 revolution. This is the same aa

\(140\:\text{min}×\dfrac{60\:\text{s}}{1\:\text{min}} = 8400\:\text{s}\)

The linear speed of the satellite then is simply equal to the orbital circumference divided by the orbital period T or

\(v = \dfrac{2\pi r}{T}\)

\(\:\;\:\:=\dfrac{2\pi(7.55×10^6\:\text{m})}{8.4×10^3\:\text{s}}\)

\(\:\:\:\:=5647.4\:\text{m/s}\)

In km/min, this is

\(v = \dfrac{2\pi(7550\:\text{km})}{140\:\text{min}} = 338.8\:\text{km/min}\)

We are given the following information

Number of students who sleep 8 hours = 7

Number of students who sleep 7 hours = 6

The number of students who sleep 8 hours and 7 hours are proportional to each other.

If the students who sleep 8 hours decreases by 2 (this means 7 - 2 = 5 hours)

Then the number of students who sleep 7 hours can be found by setting up a proportion

Let us solve the above equation for x.

Therefore, the teacher should expect 30/7 hours (or 4.29 hours)

\(\text{Given that,}~x^2 +y^2 = 125 ~ \text{and}~ xy =22\\\\(x+y)^2 = x^2 +y^2 +2xy = 125 +2(22) = 169\)

\(\huge \bf༆ Answer ༄\)

Here's the solution ~

[ by using formula ]

I hope it helps ~

0

Step-by-step explanation:

all the ways you could do it so it would be 0

x-4y+5z=0,x+z-3y=0

6x-y+4z=0,x-7y+z=0

Answer:

Step-by-step explanation:

In 2008

As per equation, P = 5.5e^kt

In 2018, t= 18, k= 0.8936

140.55 pounds will be sold approximately each week at the optimal price of $0.67/lb.

To find the price elasticity of demand for bananas at $0.20/lb, we need to use the formula:

According to the given data:

E(p) = -p(q'/q(p))

where q' is the derivative of q(p) with respect to p.

First, we need to find q'(p):

\(q'(p) = -225e^(1.5(5-p))\)

Then, we can plug in the values:

E(0.20) = -0.20(q'(0.20)/q(0.20))

= \(-0.20(-225e^(1.5(5-0.20)) / 100e^(1.5(5-0.20)))\)

= 2.70

Therefore, the price elasticity of demand for bananas at $0.20/lb is 2.70.

To find the price elasticity of demand for bananas at $1/lb, we can use the same formula:

E(p) = -p(q'/q(p))

First, we need to find q'(p):

\(q'(p) = -225e^(1.5(5-p))\)

Then, we can plug in the values:

E(1) = -1(q'(1)/q(1))

= \(-1(-225e^(1.5(5-1)) / 100e^(1.5(5-1)))\)

= 0.68

Therefore, the price elasticity of demand for bananas at $1/lb is 0.68.

To find the price that maximizes revenue, we need to find the value of p that makes revenue, R(p), maximum.

Revenue is given by:

R(p) = pq(p)

= \(p100e^(1.5(5-p))\)

To maximize revenue, we need to find the critical point of R(p) by taking its derivative and setting it equal to zero:

\(R'(p) = 100e^(1.5(5-p)) - 150pe^(1.5(5-p)) = 0\)

Simplifying this expression, we get:

\(2e^(1.5(5-p)) - 3pe^(1.5(5-p)) = 0\)

2 = 3p

p = 2/3

Therefore, the price that maximizes revenue is $0.67/lb.

To find the maximum revenue per week, we can plug this price back into the revenue equation:

\(R(2/3) = (2/3)*100e^(1.5(5-2/3))\)

= $167.56

Therefore, the maximum revenue per week is $167.56.

To find how many pounds will be sold each week at the optimal price of $0.67/lb, we can plug this price back into the demand equation:

\(q(2/3) = 100e^(1.5(5-2/3))\)

= 140.55

Therefore, approximately 140.55 pounds will be sold each week at the optimal price of $0.67/lb.

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The length AC in the kite is 8.7 cm.

A kite is a quadrilateral that has two pairs of consecutive equal sides and

perpendicular diagonals. Therefore, let's find the length AC in the kite.

Hence, using Pythagoras's theorem, let's find CE.

Therefore,

7² - 4² = CE²

CE = √49 - 16

CE = √33

CE = √33

Let's find AE as follows:

5²- 4² = AE²

AE = √25 - 16

AE = √9

AE = 3 units

Therefore,

AC = √33 + 3

AC = 5.74456264654 + 3

AC = 8.74456264654

AC = 8.7 units

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The product of 5 × 5ab × 5, a, b is 125ab5 when written in its most Simple form

The expression 5 × 5ab × 5, a, b is equal to 125ab5. The reasoning is that when we multiply 5 by 5ab, we get 25ab, which we then multiply by 5 to get 125ab. Since a, b are variables, the product 125ab5 is the product of 5 × 5ab × 5, a, b, when written in its most simple form.

The expression 5 × 5ab × 5, a, b is an algebraic expression, which consists of numbers, variables, and operators. Variables are usually represented by letters or other symbols, while operators such as +, -, ×, ÷, ^ are used to indicate mathematical operations such as addition, subtraction, multiplication, division, and exponentiation. In algebra, expressions can be simplified by combining like terms, expanding brackets, and applying other rules of arithmetic.

The most simple form of an expression is the one that cannot be further simplified.In the given expression, 5 × 5ab × 5, a, b, we can see that the number 5 appears three times, so we can simplify the expression by multiplying the numbers together.

Similarly, we can multiply the variables a and b together to get the term ab. Finally, we write the result as 125ab5, which is the product of 5 × 5ab × 5, a, b, in its most simple form.

Therefore, the product of 5 × 5ab × 5, a, b is 125ab5 when written in its most simple form.

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Answer:

12

Step-by-step explanation:

(3+x)+x=27

2x+3=27

2x=24

x=12

Mr. X reduces his weight in a ratio of 4:17. This means that for every 4 units of weight he loses, his initial weight was divided into 17 equal parts.

To determine the ratio by which Mr. X reduces his weight, we need to compare his initial weight of 85 kg with his target weight of 65 kg.

The reduction in weight is calculated as the difference between the initial weight and the target weight, which in this case is 85 kg - 65 kg = 20 kg.

The ratio can be expressed as a fraction, where the numerator represents the reduction in weight and the denominator represents the initial weight:

Reduction in weight / Initial weight

Substituting the values, we have:

20 kg / 85 kg

Simplifying the fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 5 in this case:

(20 kg / 5) / (85 kg / 5) = 4/17

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Answer:

2inch=1 foot

Step-by-step explanation:

so 2 to 1       2:1

Answer:

A - The first one

Step-by-step explanation:

Answer:

The first line.

Step-by-step explanation:

The line starts off at 0,

then it goes to the left of the line -3 times.

Then it goes to the left -1.5 times.

this means it goes one and a half.

so it would land on the line after -4.

Answer:

Usando la ley de Coulomb, la fuerza eléctrica entre las cargas en el vacío se puede calcular de la siguiente manera:

F = k * q1 * q2 / r^2

Donde:

k es la constante de Coulomb (9 × 10^9 N m^2/C^2)

q1 y q2 son las magnitudes de las cargas (en C)

r es la distancia entre las cargas (en m)

F es la fuerza eléctrica resultante (en N)

Sustituyendo los valores dados:

q1 = -7 µC = -7 × 10^-6 C

q2 = 6 µC = 6 × 10^-6 C

r = 40 cm = 0.4 m

F = (9 × 10^9 N m^2/C^2) * (-7 × 10^-6 C) * (6 × 10^-6 C) / (0.4 m)^2

F = -2.1 N

Por lo tanto, la fuerza eléctrica resultante entre las cargas es de -2.1 N.

Para determinar el valor de la fuerza eléctrica si las cargas se sumergieran en agua, se puede utilizar la constante dieléctrica relativa del agua (εr = 80.1). La expresión de la fuerza eléctrica se modifica de la siguiente manera:

F = k * q1 * q2 / (εr * ε0 * r^2)

Donde:

ε0 es la permitividad del vacío (8.85 × 10^-12 F/m)

Sustituyendo los valores dados:

F = (9 × 10^9 N m^2/C^2) * (-7 × 10^-6 C) * (6 × 10^-6 C) / (80.1 * 8.85 × 10^-12 F/m * (0.4 m)^2)

F = -2.29 N

Por lo tanto, la fuerza eléctrica resultante entre las cargas sumergidas en agua sería de -2.29 N.

Answer:

Already simplified

Step-by-step explanation:

Answer:

Step-by-step explanation:

its preety simple you just have to divide 3/10 and 1/8 and you will get your two answers

The distance between Ray-Ann and Steve, using the law of cosines, is given as follows:

11.5 feet.

The law of cosines states that we can find the length of the missing side c of a triangle as follows:

c² = a² + b² - 2abcos(C)

The parameters of the equation are given as follows:

In the context of this problem, the values of these parameters are given as follows:

Hence the distance between Ray-Ann and Steve is obtained as follows:

c² = 6²+ 7² - 2 x 6 x 7 x cos(124)º

c² = 132

c = square root of 132

c = 11.5 feet.

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Answer: 180 gallons needed

Step-by-step explanation:

Zykeith,

Assume x gallons of 50% antifreeze is needed

Final mixture is x + 60 gallons

Amount of antifreeze in mixture is 0.4*(x+60)

Amount of antifreeze added is .5x + .1*60 = .5x + 6

so .5x + 6 = .4(x + 60)

.5x -.4x = 24 -6

.1x = 18

x = 180

Let x be the number of gallons of the 50% antifreeze solution needed. We know that the resulting mixture will be 70 + x gallons. To get a 40% antifreeze mixture, we can set up the following equation:

\({\implies 0.5x + 0.1(70) = 0.4(70 + x)}\)

Simplifying the equation:

\(\qquad\implies 0.5x + 7 = 28 + 0.4x\)

\(\qquad\quad\implies 0.1x = 21\)

\(\qquad\qquad\implies \bold{x = 210}\)

\(\therefore\) We need 210 gallons of the 50% antifreeze solution to mix with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze.

\(\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}\)