cual es el valor de la operación ((f(g)(2)​

According to the question the value of the 5 digit in 4,597 is 9.

Digit is a numerical symbol used to represent numbers in the decimal system. It is a single symbol used to represent a number ranging from 0 to 9. Digits are used to represent numbers in all forms of mathematical calculations and equations. The most common digits used in calculations are 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. Each digit has an associated numerical value, which can be used to create larger numbers or to perform complex mathematical operations.

The answer is D) 9. The value of the 5 digit in 4,597 is 5. To find the 10 times its value, you must multiply 5 by 10, which equals 50. Therefore, the value of the 5 digit in 4,597 is 9.

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Explanation:

The sign of the product of any odd number of negative integers is positive because when two minuses are multiplied with each other, it will result in a positive number.

For example:

Hoped this helped!

The perimeter of the square room having a west wall of the length of 13 feet is 52 feet. Thus, the right answer is option C which says 52.

A square is a 2-Dimensional shape. It is a quadrilateral having 4 equal sides and 4 equal angles of 90°. Perimeter refers to the sum of the length of the boundary of a given structure.

Perimeter of square = 4s

where s is the side of a square

Given, that it is a square room, thus, the length of the west wall is equal to the side of the square room

the side of the square room =  13 feet

therefore, perimeter = 4 * 13 = 52 feet

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The measure of AB is 8.

It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.

We have,

ΔAED and ΔADC are congruent.

So,

AE / AD = AB / AC

AE = 15 - 9 = 6

AC = AB + BC

AC = AB + 12

Now,

6/15 = AB/(AB + 12)

2/5 = AB/(AB + 12)

2AB + 24 = 5AB

24 = 5AB - 2AB

24 = 3AB

AB = 24/3

AB = 8

Thus,

The length of AB is 8

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If the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60, therefore, the answer is (c) 0.60.

Based on your question,  the coefficient of determination (R²) for a simple linear regression, given the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60.

To calculate R², follow these steps:

1. Calculate the total sum of squares (SST): SST = SSE + SSM
2. Divide SSM by SST: R² = SSM / SST

Now, let's apply the values from your question:
To calculate, we use the formula:
= SSM / SSM + SSE)

Plugging in the given values, we get:
= 60 / (60 + 40) = 0.6
SST = SSE + SSM = 40 + 60 = 100
R² = SSM / SST = 60 / 100 = 0.60

So, the coefficient of determination (R²) is 0.60, which corresponds to option (c).

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Answer: x=no solution

Step-by-step explanation:

Answer:

F

Step-by-step explanation:

Its just rotated, So the point on the non rotated is equal to the point of the rotated one. So U = F

Answer:

F

Step-by-step explanation:

The triangle is just rotated a little bit. If you tilt your head, it'll show up!

Hope that helps!

Answer:

Step-by-step explanation:

Given the parameters of binomial distribution

We need to find the mean μ and the standard deviation σ to calculate required values

1. Find the mean

2. Find the variance

3. Find the standard deviation

Find the minimum usual value

Find the maximum usual value

Answer:

Min:549.04; Max:591.76

Step-by-step explanation:

Answer:

5200 ÷( 28 - 24)

= 5200 ÷ 4

= 1300 second

The measures of the arcs and angles in the circles obtained by circle theorems are;

3. m\(\widehat{QSP}\) = 226°

6. m∠R = 50°

An arc is a part of the of the circumference of a circle.

3. The relationship between the angles in a cyclic quadrilateral indicates that we get;

∠QSR = 180° - 113° = 67°

Therefore; The measure of arc QPR = 2 × 67° = 134°

The measure of arc QSP, m\(\widehat{QSP}\) = 360° - m\(\widehat{QPR}\) =

m\(\widehat{QSP}\) = 360° - 2 × 67° = 226°

6. The measure of the arcs QR and RS indicates;

The measure of the arc m\(\widehat{QS}\) = 360° - 120° - 140° = 100°

The measure of arc m\(\widehat{QS}\) = 100°

The angle subtended at the center is the same as the measure of the arc formed by the point of intersection of the rays of the angle and the circumference of the circle.

Circle theorems indicates; The angle subtended at the center of a circle is half the angle subtended at the circumference of the circle.

The measure of the angle R is half the measure of the arc QS, which therefore is; ∠R = 100°/2 = 50°

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Answer:

\(\lim_{x \to -\infty} f(x)= - \infty \\ \lim_{x \to \infty} f(x)= -\infty\)

Step-by-step explanation:

\(f(x)=-x^4-x^3+3x^2+1\)

The question wants you to determine the end behavior of this polynomial function.

In order to determine the end behavior of polynomial functions, you want to look at the polynomial in its general form. This means that the variables have powers that are in descending order.

Look at the leading term of the polynomial in general form. Here, the function \(f(x)=-x^4-x^3+3x^2+1\) is in general form, so we can look at the first term (term with the highest power).

The leading term for this polynomial function is \(-x^4\). The leading term has the highest power; therefore, its behavior will dominate the graph shape.

When graphed, this function will behave similarly to an upside down parabola.

Based on the leading term, we can see that the leading coefficient is -1 and the degree is 4.

Look to see if the degree is even/odd, and if the leading coefficient is negative/positive.

The degree of 4 is even, and the leading coefficient of -1 is negative.

When the degree is even and the LC is negative, the graph of the polynomial function falls to the left and falls to the right.

Therefore, if the end behavior falls to the left and falls to the right, that means that as x approaches negative infinity and positive infinity, the y-values will approach negative infinity and negative infinity on either side of the graph.

The answer is the rightmost option:

\(\lim_{x \to -\infty} f(x)= - \infty \\ \lim_{x \to \infty} f(x)= -\infty\)

The other point is \(-5+6\iota\).

It is the system in which real and imaginary parts are present.

\(Mid point\ =\ -1+7\iota\\ One end point\ =\ 3+8\iota\\ \)

Real part

\(\rm x=\dfrac{ x_{1} +x_{2} }{2} \\ -1=\dfrac{3+x_{2} }{2} \\ x_{2} = -5\)

Imaginary part

\(\rm y=\dfrac{ y_{1} +y_{2} }{2} \\7=\dfrac{8+y_{2} }{2} \\y_{2} = 6\)

Hence, the other point is \(-5+6\iota\).

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Explanation

We are given the following:

We are required to determine the value of c for which the quadrilateral PQRS is a parallelogram.

We know that one of the properties of a parallelogram is that the two diagonals bisect each other.

Thus, we have:

Hence, the answer is:

We are given that \(`z ∼ n(0,1)`\). We need to find the constant\(`c` for which `p(z ≥ c) = 0.1587`.\)

To solve the problem, we need to use the standard normal distribution tables which give the area to the left of a certain `z` value.

The area to the right of `z` is found by subtracting the area to the left from 1.

\(So, `p(z ≥ c) = 1 - p(z ≤ c)`.\)

Using the standard normal distribution table, we can find that the `z` value for which the area to the left is 0.1587 is approximately `z = 1.0`.

Therefore, \(`p(z ≥ c) = 1 - p(z ≤ c) = 1 - 0.1587 = 0.8413\)`We need to find the `z` value that corresponds to an area of 0.8413 to the left of `z`.

Using the standard normal distribution table, we can find that the `z` value for which the area to the left is 0.8413 is \(approximately `z = 1.00`. Therefore, `c = 1.00`.\)

\(Hence, the constant `c` for which `p(z ≥ c) = 0.1587` is 1.00 is rounded to two decimal places.\)

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Since, h(x) be an antiderivative of x3+sinxx2+2. if h(5) = π, then,

h(2) = (1/4)(2)⁴ - (1/2)√π erf(2√π/2) + 2(2) + C

In order to find the value of h(2), we can use the given information that h(x) is an antiderivative of the function x³ + sin(x²) + 2 and that h(5) is equal to π. By evaluating h(5), we can determine a relationship between h(x) and x³ + sin(x²) + 2. Then, we can use this relationship to calculate h(2).

To evaluate h(5), we can substitute x = 5 into the expression x³ + sin(x^2) + 2 and integrate it. The antiderivative of x³ is (1/4)x⁴, and the antiderivative of sin(x²) is (-1/2)√π erf(x√π/2), where erf represents the error function. However, since h(x) is an antiderivative of x³ + sin(x²) + 2, the constant term is included as well. So, we have h(x) = (1/4)x^4 - (1/2)√π erf(x√π/2) + 2x + C, where C is the constant of integration.

Given that h(5) = π, we can substitute x = 5 and π into the equation above to obtain π = (1/4)(5)⁴ - (1/2)√π erf(5√π/2) + 2(5) + C. Simplifying the equation, we can solve for C.

Now that we have the value of C, we can determine h(2) by substituting x = 2 into the expression for h(x).

Thus, h(2) = (1/4)(2)⁴ - (1/2)√π erf(2√π/2) + 2(2) + C. Plugging in the known values and the calculated value of C, we can compute the numerical result for h(2).

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Answer:

a) 5units

b) (4.5, 4)

Step-by-step explanation:

Let the coordinate of P and Q be P(3, 2) and Q(6, 6)

PQ can be gotten using the distance formula;

PQ =√(6-2)²+(6-3)²

PQ = √4²+3²

PQ =√16+9

PQ =√25

PQ = 5units

Midpoint M is  expressed as;

M(X, Y) = {(x1+x2)/2, y1+y2/2}

X = x1+x2/2

X = 3+6/2

X= 9/2

X = 4.5

Similarly;

Y = y1+y2/2

Y = 2+6/2

Y = 8/2

Y = 4

Hence the midpoint of PQ is (4.5, 4)

It looks like the system of ODEs is

\(\begin{cases} 2x' + y' - 4x - 4y = e^{-t} \\ x' + y' + 2x + y = e^{4t} \end{cases}\)

Differentiate both sides of both equations with respect to \(t\).

\(\begin{cases} 2x'' + y'' - 4x' - 4y' = -e^{-t} \\ x'' + y'' + 2x' + y' = 4e^{4t} \end{cases}\)

Eliminating the exponential terms, we have

\((2x' + y' - 4x - 4y) + (2x'' + y'' - 4x' - 4y') = e^{-t} + (-e^{-t}) \\\\ \implies (2x'' - 2x' - 4x) + (y'' - 3y' - 4y) = 0\)

\((x'' + y'' + 2x' + y') - 4 (x' + y' + 2x + y) = 4e^{4t} - 4\cdot e^{4t} \\\\ \implies (x'' - 2x' - 8x) + (y'' - 3y' - 4y) = 0\)

Now we can eliminate \(y\) and it derivatives.

\(\bigg((2x'' - 2x' - 4x) + (y'' - 3y' - 4y)\bigg) - \bigg((x'' - 2x' - 8x) + (y'' - 3y' - 4y)\bigg) = 0 - 0 \\\\ \implies x'' + 4x = 0\)

Solve for \(x\). The characteristic equation is \(r^2 + 4 = 0\) with roots at \(r=\pm2i\), hence the characteristic solution is

\(\boxed{x(t) = C_1 \cos(2t) + C_2 \sin(2t)}\)

Solve for \(y\). Substituting \(x\) into the second ODE gives

\(x' + y' + 2x + y = e^{4t} \\\\ \implies y' + y = e^{4t} + C_1 \cos(2t) + C_2 \sin(2t)\)

The characteristic equation this time is \(r + 1 = 0\) with a root at \(r=-1\), hence the characteristic solution is

\(y(t) = C_3 e^{-t}\)

Assume a particular solution with unknown coefficients \(a,b,c\) of the form

\(y_p = ae^{4t} + b \cos(2t) + c \sin(2t) \\\\ \implies {y_p}' = 4ae^{4t} - 2b\sin(2t) + 2c\cos(2t)\)

Substituting into the ODE gives

\(5ae^{4t} + (b+2c) \cos(2t) + (-2b+c) \sin(2t) = e^{4t} + C_1 \cos(2t) + C_2 \sin(2t) \\\\ \implies \begin{cases}5a = 1 \\ b+2c = C_1 \\ -2b+c = C_2\end{cases} \\\\ \implies a=\dfrac15, b=\dfrac{C_1-2C_2}5, c=\dfrac{2C_1+C_2}5\)

so that the general solution is

\(\boxed{y(t) = \dfrac15 e^{4t} + \dfrac{C_1-2C_2}5 \cos(2t) + \dfrac{2C_1+C_2}5 \sin(2t) + C_3 e^{-t}}\)

The critical value for 5% of the area under the chi-square probability is 11.070.

The chi-squared test determines if the distribution of an object's population into categories significantly deviates from predicted values. The degrees of freedom show many paths a system can take to change. The degree of freedom is always one less than the number of categories being studied. A chi-square critical value table can be used to determine the critical value for a 5% significance level or a 95% confidence level) for the chi-square distribution with 5 degrees of freedom.

The critical value for a chi-square distribution with five degrees of freedom and a significance level of 0.05 can be calculated from the table as 11.070. This indicates that we would reject the null hypothesis at the 5% significance level if the estimated chi-square statistic is higher than 11.070.

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Answer: Answer in Photo

A class BinaryTree. A class that implements the ADT binary tree using java programming is as follows:

import java.util.Iterator;

import java.util.NoSuchElementException;

import StackAndQueuePackage.*;

public class BinaryTree<T> implements BinaryTreeInterface<T> {

   private BinaryNode<T> root;

   public BinaryTree() {

       root = null;

   }

   public BinaryTree(T rootData) {

       root = new BinaryNode<>(rootData);

   }

  public BinaryTree(T rootData, BinaryTree<T> leftTree, BinaryTree<T> rightTree) {

       initializeTree(rootData, leftTree, rightTree);

   }

   public void setTree(T rootData, BinaryTree<T> leftTree, BinaryTree<T> rightTree) {

       initializeTree(rootData, leftTree, rightTree);

   }

   private void initializeTree(T rootData, BinaryTree<T> leftTree, BinaryTree<T> rightTree) {

       root = new BinaryNode<>(rootData);

       if (leftTree != null)

           root.setLeftChild(leftTree.root);

       if (rightTree != null)

           root.setRightChild(rightTree.root);

   }

   public T getRootData() {

       if (isEmpty())

           throw new NoSuchElementException();

       return root.getData();

   }

   public boolean isEmpty() {

       return root == null;

   }

   public void clear() {

       root = null;

   }

   protected void setRootData(T rootData) {

       root.setData(rootData);

   }

   protected void setRootNode(BinaryNode<T> rootNode) {

       root = rootNode;

   }

   protected BinaryNode<T> getRootNode() {

       return root;

   }

   public int getHeight() {

       return root.getHeight();

   }

   public int getNumberOfNodes() {

       return root.getNumberOfNodes();

   }

   public Iterator<T> getPreorderIterator() {

       return new PreorderIterator();

   }

   public Iterator<T> getInorderIterator() {

       return new InorderIterator();

   }

   public Iterator<T> getPostorderIterator() {

       return new PostorderIterator();

   }

   public Iterator<T> getLevelOrderIterator() {

       return new LevelOrderIterator();

   }

   private class PreorderIterator implements Iterator<T> {

       private StackInterface<BinaryNode<T>> nodeStack;

       public PreorderIterator() {

           nodeStack = new LinkedStack<>();

           if (root != null)

               nodeStack.push(root);

       }

       public boolean hasNext() {

           return !nodeStack.isEmpty();

       }

       public T next() {

           BinaryNode<T> nextNode;

           if (hasNext()) {

               nextNode = nodeStack.pop();

               BinaryNode<T> leftChild = nextNode.getLeftChild();

               BinaryNode<T> rightChild = nextNode.getRightChild();

               if (rightChild != null)

                   nodeStack.push(rightChild);

               if (leftChild != null)

                   nodeStack.push(leftChild);

           } else {

               throw new NoSuchElementException();

           }

           return nextNode.getData();

       }

   }

   private class InorderIterator implements Iterator<T> {

       private StackInterface<BinaryNode<T>> nodeStack;

       private BinaryNode<T> currentNode;

       public InorderIterator() {

           nodeStack = new LinkedStack<>();

           currentNode = root;

       }

       public boolean hasNext() {

           return !nodeStack.isEmpty() || currentNode != null;

       }

       public T next() {

           BinaryNode<T> nextNode = null;

           while (currentNode != null) {

               nodeStack.push(currentNode);

               currentNode = currentNode.getLeftChild();

           }

           if (!nodeStack.isEmpty()) {

               nextNode = nodeStack.pop();

               currentNode = nextNode.getRightChild();

           } else {

               throw

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Answer:

-6 or or it can just go on forever

Step-by-step explanation:

Answer:

a because a is the answer

Answer:

\(\sqrt{18} + \sqrt{32} - 3 \sqrt{8} = \\ = \sqrt{9 \times 2} + \sqrt{16 \times 2} - 3 \sqrt{4 \times 2} \\ =3 \sqrt{2} + 4 \sqrt{2} - 3 \times 2 \sqrt{2} \\ = 3 + 4 - 6 \sqrt{2} \\ = 7 - 6 \sqrt{2} \\ = 1 \sqrt{2} \)

Semoga membantu

Answer:

\(\sqrt{18} + \sqrt{32} - 3 \sqrt{8} = 1 \sqrt{2} \)

Answer:

It is very ez

Step-by-step explanation:

when there is a right angled triangle the arrow the 90° is pointing at is the hypotenuse. Hope it helped.

The old oak tree after finding the treasure, you should head in a direction of approximately 13.2 degrees west of south. In total, you will have walked approximately 2.09 kilometers.

To determine the direction back to the old oak tree, we need to analyze the vector components of the three legs of your journey.

First, you walked 835 meters directly south, which can be represented as a vector with a magnitude of 835 m in the negative y-direction (south) and no component in the x-direction.

Next, you walked 1.29 kilometers at 30.0 degrees west of north. This leg can be divided into two components: one in the north direction and one in the west direction. The north component is given by (1.29 km) * cos(30°) ≈ 1.118 km, and the west component is given by (1.29 km) * sin(30°) ≈ 0.645 km.

Finally, you walked 1.00 kilometer at 32.0 degrees north of east. This leg can also be divided into two components: one in the east direction and one in the north direction. The east component is given by (1.00 km) * cos(32°) ≈ 0.844 km, and the north component is given by (1.00 km) * sin(32°) ≈ 0.533 km.

To find the net vector, we sum up the components. In the x-direction, we have -0.645 km (west component) + 0.844 km (east component) = 0.199 km. In the y-direction, we have -835 m (south component) + 1.118 km (north component) + 0.533 km (north component) ≈ -0.007 km.      

The direction back to the old oak tree is given by the arctan of the y-component divided by the x-component: arctan(-0.007 km / 0.199 km) ≈ -2.08°. Since this value is negative, we consider it as west of south. Therefore, to return to the old oak tree, you should head approximately 13.2 degrees west of south.    

The total distance you walked is the magnitude of the net vector, which can be found using the Pythagorean theorem: √((0.199 km)² + (-0.007 km)²) ≈ 0.199 km. Adding this distance to the distances walked in the previous legs, the total distance you walked is approximately 2.09 kilometers.        

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Answer:

Step-by-step explanation:

\(\frac{2}{x}+\frac{3}{2x}-\frac{1}{2}=\frac{2}{3}\\multiply ~by~6x\\12+9-3x=4x\\21=4x+3x\\7x=21\\x=21/7=3\)

Answer:

Below in bold.

Step-by-step explanation:

Let x be the amount of 20% saline solution then the amount of 48% will

8 - x milliliters.

So,

0.20x + 0.48(8 - x) = 0.32* 8

0.20x + 3.84 - 0.48x = 2.56

-0.28x = -1.28

x = -1.28/-0.28

  = 4.57 milliliters.

8 - x = 3.43 milliliters

The answer is:

4.57 milliliters of 20% solution and 3.43 milliliters of the 48% solution.

Given:

Diameter of cone = 4 mm

Slant height (l) = 7 mm

Find-: Surface area of the cone.

Sol:

The surface area of a cone is:

Where,

Height of cone:

So, the surface area of a cone is:

So, the surface area of a cone is 56.52

Answer:

1000 times greater.

Step-by-step explanation:

10^9 / 10*6

= 10^(9-6)

= 10^3

= 1000.

Answer:

just took the test answer is C

Step-by-step explanation:

Answer:

Question 3:

51/16

As a mixed number =

3 3/16

Step by step explanation:

You have to convert the fraction into improper fractions so 8 ½ = 17/2

and 2⅔ = 8/3

then you do 17/2 ÷ 8/3 which =

51/16 theb turn this number into a mixed number which is

3 3/16