Current Attempt in Progress A neutron star has a mass of 2.0 x 1030 kg (about the mass of our sun) and a radius of 5.0 x 103 m (about the height of a good-sized mountain). Suppose an object falls from rest near the surface of such a star. How fast would this object be moving after it had fallen a distance of 0.028 m? (Assume that the gravitational force is constant over the distance of the fall and that the star is not rotating.) V=

Please find attached photograph for your answer. Do comment whether it is useful or not

When a vertically falling firecracker bursts, the vector sum of momentum fragments does not satisfy either of the given options. The correct answer is d) neither of these.

When the firecracker bursts, it explodes in multiple directions, resulting in the fragmentation of its mass. The momentum of the fragments is distributed in various directions, including both horizontal and vertical components.

Therefore, option a) is incorrect because the horizontal momentum fragments do not cancel out to zero. Option b) is also incorrect because the vertical momentum of the fragments does not necessarily equal the momentum of the firecracker before bursting.

The bursting of the firecracker introduces additional velocities and forces that alter the distribution of momentum among the fragments.

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Answer:

PE = 13734 Joules

Step-by-step explanation:

Formula: PE = m * g * h

Givens

m = 40000 grams

m = 40000 grams * 1kg/1000 grams = 40 kg

g = 9.81

h = 35 m

PE = 40 * 9.81 * 35

PE = 13734 Joules

Answer:

3 m/s

Explanation:

distance (rise) over time (run) gives speed, that is velocity

it can be found using the gradient (m) formula

m=(y2-y1)/(x2-x1)

m=(15-3)/(4-0) =12/4=3 m/s

Answer:

3 m/s

Explanation:

.....as the answer for your question is 3m/s ..

THANK YOU..

Answer:

George Washington

Explanation:

Answer:

well for me

Explanation:

It was George Washington

Identification of compounds can benefit from density. It is also a useful feature since it connects (or acts as a conversion factor between) a substance's mass and volume. Volume and mass are extended (or extrinsic) qualities of matter that are quantity dependent.

The force of an air mass acting on the earth's surface is known as atmospheric pressure. Remember that wind currents are created when the densities of two separate air masses differ.

Our wind currents are driven by the atmospheric pressure density, and denser air exerts a higher pressure than less dense air. Compared to the cold and dry air, the warm and humid air is less dense. The less dense air will then float on top of the thicker air in certain regions.

Therefore, Warm air masses rise while cold air masses descend because they are less dense.

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The correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.

To find the distance from the conductor at which the magnetic field caused by the current is equal to the Earth's magnetic field, we'll use the formula for the magnetic field around a long straight conductor:

\(B = (de * I) / (2 * \pi  * r)\)

Where B is the magnetic field, μ₀ is the permeability of free space (\(4\pi  * 10^-7 Tm/A\)), I is the current, and r is the distance from the conductor. We want to find the value of r when B equals Earth's magnetic field (0.5 x 10⁻⁴ T).

\(0.5 * 10^-4 T = (4\pi  * 10^-7 Tm/A * 100 A) / (2 * \pi  * r)\)
To solve for r, we can first simplify the equation by cancelling the π terms:

\(0.5 * 10^-4 T = (4 * 10^-7 Tm/A * 100 A) / (2 * r)\)

Now, cancel out the A (Amperes) terms:

\(0.5 * 10^-4 T = (4 * 10^-7 Tm) / (2 * r)\)

Divide both sides by 4 x 10⁻⁷ T:

\(r = (0.5 * 10^-4 T) / (4 * 10^-7 T)\)

Simplify the equation:

r = \(0.5 * 10^3 m / 4\)
r = 500 / 4
r = 125

So, the correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.

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Answer:

Baseball

Explanation:

Cricket is similar to baseball.

Hope this helps :3 And pls put me as brainliest TYSM if u do!

Answer:

its basketball

Explanation:

1.

a) Hydrogen chloride (HCl) - 1 hydrogen atom, 1 chlorine atom

b) Sulfur dioxide (SO₂) - 1 sulfur atom, 2 oxygen atoms

c) Ammonia (NH₃) - 1 nitrogen atom, 3 hydrogen atoms

d) Carbon monoxide (CO) - 1 carbon atom, 1 oxygen atom

2.

a) Hydrogen chloride (HCl) :

H

|

Cl--C--

|

H

b) Sulfur dioxide (SO₂) :

O

//

O=S

\\

O

c) Ammonia (NH₃) :

H

|

H--N--H

|

H

d) Carbon monoxide (CO) :

O

//

C=O

Because every one of the 26 26 26 letters might be used to encode each letter in a message. because the keyword used determines how the message is encoded

Encoding is used to change data so that it can be correctly (and safely) viewed by a different kind of system, such as seeing special characters on the a web page or sending binary data via email. Making sure that information can be effectively consumed is the main objective rather than keeping it a secret.

The four main categories of encoding are semantic, elaborative, visual, and audio. Mnemonics, chunking, or state-dependent learning are just a few techniques that can help the brain better encode memories.

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The given information says that the wind is blowing at 61 cvs. Therefore, the speed of the wind blowing is 61 cvs.

Wind speed is usually measured in miles per hour (mph), kilometers per hour (km/h), meters per second (m/s), or knots (nautical miles per hour, abbreviated kt or kts). To find the speed of the wind, these measurements use different mathematical formulas and conversion factors.It is stated in the given question that the wind speed is 61 cvs. However, this unit of wind speed is not commonly used, as it is not a standard unit of wind speed measurement.

The speed of the wind is an essential factor in predicting weather conditions and determining their potential impact on people, structures, and the environment. Wind speed is typically measured in units such as miles per hour (mph), kilometers per hour (km/h), meters per second (m/s), and knots. According to the given information, the wind speed is 61 cvs. This unit of wind speed is not widely used, as it is not a standard unit of wind speed measurement. To determine the wind speed, it is necessary to employ various mathematical formulas and conversion factors that differ depending on the unit of measurement used.

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Explanation:

The gravity equation defines the relationship between weight, mass, and gravity:

W = mg

The linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

We find the linear speed of a point on the 32nd parallel from v = rω where r = radius of 32nd parallel north = Rcos32° (since it is the radius of the small circle at the 32nd parallel) where R = radius of earth = 6,371,000 m and ω = angular speed of the earth = 2π/T where T = period of earth = 24h = 24 × 60 × 60 s = 86400 s.

So, v = rω

v = Rcos32° × 2π/T

v = 2πRcos32°/T

substituting the values of the variables into the equation, we have

v = 2πRcos32°/T

v = 2π × 6,371,000 m × cos32°/86400 s.

v = 2π × 6,371,000 m × 0.8480/86400 s.

v = 33947512.5035 m/86400 s

v = 392.91 m/s

So, the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

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Answer:

The best way is to use a hand crank such as a hand cranked flashlight or radio because it is easy to power enough energy for a short amount of time.

The concept of an energy capturing rocking chair is creative, its practicality and effectiveness for a rescue team might be limited due to the relatively low energy output, efficiency concerns, and availability of more efficient alternatives.

The rescue team's energy needs, the specific environment they operate in, and the available resources would need to be carefully considered before implementing such a solution.

An "energy capturing rocking chair" is an interesting concept, but its effectiveness for a rescue team would depend on several factors.

Pros:

Renewable Energy Source: If the rocking chair is designed to convert the kinetic energy generated by rocking into electrical energy, it could provide a renewable energy source for charging devices or powering equipment in remote or emergency situations where traditional power sources might be unavailable.

Low Maintenance: Rocking chairs are relatively simple mechanical devices, which means they could potentially have lower maintenance requirements compared to more complex energy generation systems.

Portable and Compact: Rocking chairs are typically portable and don't require a large footprint, making them suitable for deployment in various environments, including temporary shelters or remote locations.

Human-Powered: Rescue team members could generate energy while resting or waiting, which could be especially useful during downtime.

Cons:

Energy Output: Rocking chairs might not generate a significant amount of energy. The energy output from rocking would likely be relatively low compared to more efficient energy generation methods.

Efficiency: Converting mechanical motion into electrical energy involves energy losses due to friction and other factors. The overall efficiency of the energy conversion process could be a limitation.

Time and Effort: Rescue team members' primary focus is on performing their duties effectively. Spending significant time and effort rocking in chairs to generate energy might divert their attention from critical tasks.

Limited Applicability: The energy generated from rocking chairs might be suitable for low-power devices like lights, radios, or small electronics. However, it may not provide sufficient power for high-energy-demand equipment like communication systems, medical devices, or power tools.

Alternative Solutions: There are other portable and renewable energy solutions available, such as solar panels, portable wind turbines, or hand-crank generators, which might be more efficient and practical for a rescue team.

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Where, a is the acceleration of the car at the top of the loop. Thus, the minimum speed required to safely make it through the loop is about 12.12m/s 12.12 m / s .

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The specific internal energy of water is approximately 2607.7 kJ/kg.

The specific internal energy is the amount of energy contained within a substance per unit mass. It is a measure of the internal energy of a substance and is typically denoted by the symbol "u." It can be determined using the steam tables.

According to the steam tables, the specific internal energy of water at 50 kPa and 220°C is approximately 2607.7 kJ/kg. This value can be found by locating the corresponding pressure and temperature values in the table and reading the specific internal energy value in the "u" column.

It is important to note that the specific internal energy of water can vary depending on the pressure and temperature conditions. Therefore, it is important to use the correct values from the steam tables in order to obtain an accurate result.

The problem seems incomplete, it must have been...

"What is the specific internal energy of water at 50 kPa and 220°C? Use data from the steam tables.

The specific internal energy of water is _____ kJ/kg."

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The velocity is defined as the rate of change of displacement per unit time and the unit of velocity is m/s. Velocity is of two types and they are average velocity and instantaneous velocity.

A) From the given graph, object B traveled faster when compared with object A. Because the speed of object B increases gradually with time whereas the speed of object A decreases with time. Hence, object B travels faster.

B)The velocity increases with time 2s to 4s. The velocity is defined as the rate of change displacement by time taken. v = Δx/Δt, where Δx is the change in displacement and Δt is the time taken. Δx = final.dis - initial dis = 0-(-4) = 0+4 = 4 m. Δt = final.time-ini.time = 4-2 = 2s. Thus, the velocity v = 4/2 = 2 m/s. Hence, the velocity increases gradually.

C) The acceleration is defined as the rate of change of velocity per unit time. From the given graph, the change in velocity does not change, and hence Δv = 0. Acceleration a = Δv/Δt = 0. Thus, the acceleration of the object is zero.

D) Acceleration (a) is the rate of velocity per unit time and the unit of velocity is m/s². Acceleration (a) = Δv/Δt, where Δv is the change in velocity. Δv = final.velocity - initial.velocity = 8-(-2) = 8+2 = 10 m/s. Δt = final. time-initial. time = 7-3 = 4s. a = 10/4=2.5m/s². Hence, the acceleration is 2.5m/s².

E) Force is the product of mass and acceleration. From the given, the force moves in both forward and backward directions, and hence, force is a vector quantity. F(net) = F₁+F₂=18 - 6 = 12N. The mass of the cart is 2kg.

F = ma

a = F/m

  = 12/2

  = 6 m/s²

Thus, the acceleration of the cart with a mass of 2kg is 6 m.s⁻².

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Answer:

400 J

Explanation:

work done = force x distance

First convert 4000 m into metres = 4m

Then do 100N x 4m = 400

q1= charge 1 = -0.0004C

q2= charge 2 = 0.0003c

r = distance = 3 m

F = k (q1*q2) / r^2

Where:

F= force

k= constant = 9 x 10^9 kgm^3/s^2m^2

Replacing:

F = 9x10^9 ( -0.0004 * 0.0003 ) / 3^2

F= 120 N

a. The Schrodinger equation for E<0 inside and outside of a particle of mass m that the potential energy V(x) = {0 for x<0, -V0 for 0a} is tan(ka) = -√((V0/E)+1)/√((V0/E)-1).

b. Since V0 is much larger than the binding energy, our assumption that V0 >> |E| is consistent. Thus, the correct answer is "Yes, it is">

The time-independent Schrodinger equation for a particle of mass m in a one-dimensional potential energy well is:

-h²/2m d²ψ/dx² + V(x)ψ = Eψ

where h is Planck's constant, V(x) is the potential energy, E is the total energy, and ψ is the wave function. In this case, the potential energy is given by:

V(x) = {0 for x<0, -V0 for 0a), the Schrodinger equation becomes:

-h²/2m d²ψ/dx² = Eψ

which has a solution of the form:

ψ(x) = \(Ce^{(-kx)}\) + \(De^{(-kx)}\)

where k = √(2mE)/h and C, D are constants determined by the boundary conditions.

At x = 0, the wave function and its derivative must be continuous:

ψ(0) = 0 => B = 0 (impenetrable wall)

dψ/dx(0) = 0 => kA = 0

At x = a, the wave function and its derivative must also be continuous:

ψ(a) = 0 => \(Ce^{(-ka)}\) + \(De^{(ka)}\) = 0

dψ/dx(a) = 0 => -k(\(Ce^{(-ka)}\) - \(De^{(ka)}\)) = 0

Solving for the constants and substituting k² = 2m(V0+E)/h², we obtain the energy equation:

tan(ka) = -√((V0/E)+1)/√((V0/E)-1)

This equation determines the allowed values of E for bound states.

For a bound state, E<0. Substituting E=-|E| in the energy equation and using the small-angle approximation, we get:

ka ≈ -(mVa²/2h²)|E|\(^{\frac{1}{2} }\)

For a bound state to exist, ka must be real, which requires that:

(mVa²/2h²)|E|\(^{\frac{1}{2} }\) < π/2

Squaring and simplifying, we obtain:

|E| < (h²π²)/(8mVa²)

This is the condition for the existence of a bound state. Note that the larger the depth of the well, the smaller the allowed values of |E|, which means the bound state is more tightly bound.

The problem of a deuteron, a bound state of a proton and a neutron, can be described by the same Schrodinger equation as in part (a), with m replaced by the reduced mass m*m/(m*+m) and x replaced by the radius r. The deuteron has only one bound state, which means the energy equation has only one solution for ka.

Assuming that the width of the well is a-1.4e⁻¹⁵ m and the deuteron is just barely bound, we have:

|E| = 2.2 MeV = 3.52e⁻¹³ J

a = 1.4e⁻¹⁵ m

Substituting these values in the condition for a bound state, we obtain:

V0 > 53.5 MeV

Since V0 is much larger than the binding energy, our assumption that V0 >> |E| is consistent.

To sketch the ground state wave function, we need to solve the Schrodinger equation with the energy of the deuteron, which gives us the constants A, B, C, and D. The wave function is then plotted as a function of radius r. However, without knowing the value of V0, we cannot determine the exact shape of the wave function. We can only say that it is a bound state with a maximum amplitude at the center and decays exponentially outside the well.

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Ignoring the mass of duct tape and plastic in the bottles, a child will need at least 4 water bottles to stay dry on the raft. The child will need at least four water bottles to stay dry on the raft.

The buoyancy force exerted by the water on the raft must be greater than or equal to the weight of the child to keep the child afloat and dry on the raft. The buoyancy force is given by Archimedes' principle, which states that it is equal to the weight of the water displaced by the raft.

The volume of each 1.0 L water bottle is 0.001 m^3. The density of water is approximately 1000 kg/m^3. Therefore, each water bottle has a buoyant force of:

Buoyant force = Volume of water displaced x Density of water x Acceleration due to gravity

Buoyant force = 0.001 m^3 x 1000 kg/m^3 x 9.81 m/s^2

Buoyant force = 9.81 N

To find the minimum number of water bottles needed to keep the child afloat, we need to divide the weight of the child by the buoyant force of one water bottle:

Minimum number of water bottles = Weight of child / Buoyant force per bottle

Minimum number of water bottles = 32 kg / 9.81 N

Minimum number of water bottles = 3.26 (rounded up to 4)

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Answer:

Explanation:down and to the left

Explanation:

At first it is in 14m position but position doesn't matter in displacement, similar case for time taken.

So at first it travels 6m in positive direction.

So displacement= 6m

Then it travels 13 in opposite or negative direction.

So displacement = 6 -13 m = -7 m

Hope it helps ya

You're standing in the lobby of a huge building.

You go up 6 floors.

You stop and catch your breath.

You go down 13 floors.

Where do you end up ?

Answer:

No, It hasn't acceleration because it doesn't change the velocity with respect to time.

Answer:

Answer:first 1.39

second 0.78

third 0.64

fourth 0.54

Explanation:just did it

Explanation:

Answer:

this is it

Explanation:

The Energy Internet Foundation owns the cryptocurrency known as the Energy Internet Token. Building accessible operating systems of energy grids that can support a zero-carbon economy is the focus of the Energy.

Correct option is, C.

On CoinMarketCap, look up Energy Web Token. Press the "Trade" button next to the price chart. In this view, you will discover a full list of stores where you can purchase Energy Web Token, in addition to the currencies you can do so with.

The price for Energy Web Tokens is anticipated to increase by 570.81% inside the best case situation by 2026 based on our assessment of the expansion of the IT industry, which places the estimated price of EWT between $5.19 and $ 27.02.

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Answer:

Explanation:

Given

Weight of the bucket = 20N

Mass = Weight/acceleration due to gravity

Mass = 20/9.8

Mass = 2.04kg

Applied force = 75N

Get the acceleration

According to Newton's second law:

F = ma

a = F/m

a = 75/2.04

a = 36.76m/s²

Hence the acceleration of the bucket is 36.76m/s²

The first two statements are true. The last two statements are false.

1. At the critical maximum nucleate boiling heat flux, a sudden temperature jump can occur in a heating element. This phenomenon happens when the heat flux is at its maximum and the liquid near the heating surface transitions to a highly active boiling state. The sudden temperature jump is caused by the intense vapor generation and rapid heat transfer processes occurring at the surface.

2. Film boiling is a stage of boiling where a vapor film forms between the heater surface and the liquid. This vapor film acts as an insulating layer, leading to low heat transfer rates in the film boiling region. The vapor film reduces the contact between the heater surface and the liquid, hindering efficient heat transfer and resulting in lower overall heat transfer rates compared to other boiling regimes.

3. Condensation is the process in which a vapor or gas transforms into a liquid state. When condensation occurs, latent heat is released. However, contrary to the statement, the release of latent heat actually acts to heat the surroundings, not cool the air. This is because latent heat represents the energy released during the phase transition from gas to liquid, and it is transferred to the surrounding environment.

4. In pool boiling problems, the excess temperature is not equal to Ts - Too as stated. Instead, it is calculated as Ts - Tsub. Ts represents the surface temperature, and Tsub represents the saturation temperature of the liquid. The excess temperature is the temperature difference between the surface and the saturation temperature, which is used to characterize the heat transfer performance in pool boiling experiments or analyses.

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