(d) Give an example of an input of MAX-Exact-3SAT such that every assignment satisfies exactly 87.5% of the clauses. Hint: 23=8.

Answers

Answer 1

Let the input be a MAX-Exact-3SAT formula with 8 variables and 23 clauses, where each clause has exactly 3 literals.

To satisfy 87.5% of the clauses, we need to satisfy 20 out of the 23 clauses. Let's construct the MAX-Exact-3SAT formula with 8 variables as follows:

We create 8 variables: x1, x2, x3, x4, x5, x6, x7, x8.

We create 23 clauses as follows:

Clause 1: (x1 OR x2 OR x3)

Clause 2: (x1 OR x2 OR NOT x3)

Clause 3: (x1 OR NOT x2 OR x3)

Clause 4: (x1 OR NOT x2 OR NOT x3)

Clause 5: (NOT x1 OR x2 OR x3)

Clause 6: (NOT x1 OR x2 OR NOT x3)

Clause 7: (NOT x1 OR NOT x2 OR x3)

Clause 8: (NOT x1 OR NOT x2 OR NOT x3)

Clause 9: (x4 OR x5 OR x6)

Clause 10: (x4 OR x5 OR NOT x6)

Clause 11: (x4 OR NOT x5 OR x6)

Clause 12: (x4 OR NOT x5 OR NOT x6)

Clause 13: (NOT x4 OR x5 OR x6)

Clause 14: (NOT x4 OR x5 OR NOT x6)

Clause 15: (NOT x4 OR NOT x5 OR x6)

Clause 16: (NOT x4 OR NOT x5 OR NOT x6)

Clause 17: (x1 OR x4 OR x7)

Clause 18: (x1 OR NOT x4 OR x7)

Clause 19: (NOT x1 OR x4 OR x7)

Clause 20: (NOT x1 OR NOT x4 OR x7)

Clause 21: (x2 OR x5 OR x8)

Clause 22: (x2 OR NOT x5 OR x8)

Clause 23: (NOT x2 OR x5 OR x8)

We can verify that every assignment to the variables satisfies exactly 20 out of the 23 clauses, which is 87.5% of the clauses. For example, if we set all variables to true, then clauses 1-8, 9-16, and 17-20 are satisfied, but clauses 21-23 are not satisfied. Therefore, this input satisfies the condition that every assignment satisfies exactly 87.5% of the clauses.

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Related Questions

The data file gives the mean temperature in the fall of each year, defined as September 1 to November 30, and the mean temperature in the following winter, defined as December 1 to the end of February in the following calendar year, in degrees Fahrenheit, for Ft. Collins, CO (Colorado Climate Center, 2012). These data cover the time period from 1900 to 2010. The question of interest is: Does the average fall temperature predict the average winter temperature? Draw a scatterplot of the response versus the predictor, and describe any pattern you might see in the plot. Use statistical software to fit the regression of the response on the predictor. Add the fitted line to your graph. Test the slope to be o against a two-sided alternative, and summarize your results. Compute or obtain from your computer output the value of the variability in winter explained by fall and explain what this means. Divide the data into 2 time periods, an early period from 1900 to 1989, and a late period from 1990 to 2010. You can do this using the variable year in the data file. Are the results different in the two time periods?

Answers

Using the variable "year" in the data file, we may split the data into two time periods, an early period from 1900 to 1989, and a late era from 1990 to 2010 to check if the association has altered over time.

To determine whether the average fall temperature predicts the average winter temperature in Ft. Collins, CO, we can first create a scatterplot of the response (average winter temperature) versus the predictor (average fall temperature) using the data file provided.
Upon examination of the scatterplot, we may see a positive linear relationship between the two variables, with higher fall temperatures generally corresponding to higher winter temperatures.
To formally test this relationship, we can use statistical software to fit a linear regression model of the response on the predictor. Adding the fitted line to the scatterplot allows us to see how well the line fits the data. Next, we can test the slope of the regression line to be zero against a two-sided alternative using a t-test. If the p-value is less than our chosen significance level (such as 0.05), we can reject the null hypothesis of no relationship and conclude that there is evidence of a significant linear relationship between fall and winter temperatures.
Additionally, we can calculate the coefficient of determination (R-squared) to determine the proportion of variability in winter temperatures that can be explained by fall temperatures. This tells us how well the fall temperature predicts the winter temperature. The findings of the study described above may then be repeated for each time period independently and compared.
Overall, if there is a significant relationship between fall and winter temperatures, it may be useful for predicting winter temperatures based on fall temperatures. However, it is important to consider any potential confounding variables that may also influence winter temperatures.

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true or false the decimalformat class is part of the java api so it is automatically available to your programs.

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The statement is true. The DecimalFormat class is part of the Java API, specifically within java.text package, so it is automatically available to your programs. You can use it to format numbers in various ways, such as for displaying currency or percentages.

DecimalFormat is a concrete subclass of NumberFormat that formats decimal numbers. It has a variety of features designed to make it possible to parse and format numbers in any locale, including support for Western, Arabic, and Indic digits. It also supports different kinds of numbers, including integers (123), fixed-point numbers (123.4), scientific notation (1.23E4), percentages (12%), and currency amounts ($123). All of these can be localized.

To obtain a NumberFormat for a specific locale, including the default locale, call one of NumberFormat's factory methods, such as getInstance(). In general, do not call the DecimalFormat constructors directly, since the NumberFormat factory methods may return subclasses other than DecimalFormat. If you need to customize the format object, do something like this:

NumberFormat f = NumberFormat.getInstance(loc);

if (f instanceof DecimalFormat) {

    ((DecimalFormat) f).setDecimalSeparatorAlwaysShown(true);

}

A DecimalFormat comprises a pattern and a set of symbols. The pattern may be set directly using applyPattern(), or indirectly using the API methods. The symbols are stored in a DecimalFormatSymbols object. When using the NumberFormat factory methods, the pattern and symbols are read from localized ResourceBundles

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True. The Decimal Format class is a part of the Java API and is included in the java.text package.

It is automatically available to Java programs without the need for any additional installations or imports.

The Decimal Format class is part of the Java API, and it is automatically available to your programs.

The Java API is a collection of pre-written classes, methods, and interfaces that are part of the Java Development Kit (JDK).

These classes and methods provide a wide range of functionalities that can be utilized by Java developers to build robust applications.
The Decimal Format class, specifically, is a subclass of the Number Format class and is used to format decimal numbers according to a specific pattern.

The class provides methods to format and parse decimal numbers and can be used to specify the number of digits after the decimal point, the use of a thousand separator, and the currency symbol.
The Decimal Format class in your Java program, you simply need to import the class using the import statement, and then create an instance of the class.

For example:
import java. text. Decimal Format.
public class MyClass

{
public static void main (String [] args) {
Decimal Format df = new Decimal Format("#.00");
double num = 1234.5678
System.out.println(df.format(num));
}
}
The Decimal Format class using the import statement, and then create an instance of the class called df.

We then use the format method of the class to format the decimal number 1234.5678 with two decimal places.
The Decimal Format class is an essential part of the Java API and is automatically available to your programs.

Its inclusion in the Java API makes it easier for Java developers to format decimal numbers in their applications.

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a biangle is a polygon with exactly 2 sides (like a triangle has 3 sides, and a quadrangle (i.e. quadrilateral) has 4). a biangle is non-degenerate if it has positive area (i.e. it is not contained entirely in a single line) (a) prove that a non-degenerate biangle cannot exist in euclidean geometry. (b) prove that a non-degenerate biangle cannot exist in hyperbolic geometry. (c) show how to construct a non-degenerate biangle in spherical geometry

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a. a non-degenerate triangle cannot exist in Euclidean geometry. b. a non-degenerate triangle cannot exist in hyperbolic geometry. c. This forms a non-degenerate triangle with two sides and two angles of 0 radians.

(a) In Euclidean geometry, the sum of the interior angles of a polygon with n sides is (n-2)π radians. For a non-degenerate biangle, n=2, so the sum of the interior angles is (2-2)π = 0 radians. However, this is impossible in Euclidean geometry since the sum of the interior angles of any polygon must be greater than 0 radians. Therefore, a non-degenerate biangle cannot exist in Euclidean geometry.

(b) In hyperbolic geometry, the sum of the interior angles of a polygon with n sides is (n-2)π radians, where π is the constant known as the hyperbolic angle. For a non-degenerate biangle, n=2, so the sum of the interior angles is (2-2)π = 0 radians. However, this is possible in hyperbolic geometry since the hyperbolic angle is negative, so the sum of the interior angles of a polygon with fewer than 3 sides can be 0 radians. Therefore, a non-degenerate biangle cannot exist in hyperbolic geometry.

(c) In spherical geometry, the sum of the interior angles of a polygon with n sides is (n-2)π radians, where π is the constant known as the spherical angle. For a non-degenerate biangle, n=2, so the sum of the interior angles is (2-2)π = 0 radians. This is possible in spherical geometry since the spherical angle is positive, so the sum of the interior angles of a polygon with fewer than 3 sides can be 0 radians. To construct a non-degenerate biangle in spherical geometry, we can take two great circles on a sphere that intersect at two points, and take the two arcs connecting the points of intersection as the sides of the biangle. This forms a non-degenerate biangle with two sides and two angles of 0 radians.

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If v1, v2, v3, v4 are 4 vectors in a vector space V such that v4 = 3v1 - 2v2 - 3v3. Then{v1, v2, v3, v4} are linearly dependent. Select one: True False

Answers

The statement "{v1, v2, v3, v4} are linearly dependent" is true.

To show that {v1, v2, v3, v4} are linearly dependent, we need to show that there exist scalars a1, a2, a3, and a4, not all zero, such that a1v1 + a2v2 + a3v3 + a4v4 = 0.

Since v4 = 3v1 - 2v2 - 3v3, we can substitute this expression for v4 in the equation and get:

a1v1 + a2v2 + a3v3 + a4(3v1 - 2v2 - 3v3) = 0

Simplifying this equation, we get:

(a1 + 3a4)v1 + (-a2 - 2a4)v2 + (-a3 - 3a4)v3 = 0

Since not all the scalars a1, a2, a3, and a4 are zero, we can choose a4 to be nonzero and solve for the other scalars in terms of a4. We get:

a1 = -3a4, a2 = -2a4, a3 = -3a4

Therefore, we have found a nontrivial linear combination of v1, v2, v3, and v4 that equals the zero vector, which means that {v1, v2, v3, v4} are linearly dependent.

Overall, the statement "{v1, v2, v3, v4} are linearly dependent" is true. We showed that there exist scalars a1, a2, a3, and a4, not all zero, such that a1v1 + a2v2 + a3v3 + a4v4 = 0, which means that {v1, v2, v3, v4} are linearly dependent.

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7. Use the Composite Trapezoidal rule with the indicated values of \( n \) to approximate the following integrals. (1 mark) (a) \( \int_{1}^{2} x \ln x d x, \quad n=4 \) (b) \( \int_{2}^{2} x^{3} e^{x

Answers

The Composite Trapezoidal rule is used to approximate the given integrals. In part (a), the integral \(\( \int_{1}^{2} x \ln x \, dx \)\) is approximated using \(\( n = 4 \)\)subintervals. In part (b), the integral\(\( \int_{2}^{2} x^{3} e^{x} \, dx \)\) is given with incorrect limits, so it cannot be evaluated.

To approximate \(\( \int_{1}^{2} x \ln x \, dx \)\) using the Composite Trapezoidal rule, we divide the interval \(\([1, 2]\) into \( n = 4 \)\) subintervals. The step size, \(\( h \)\), is calculated as\(\( h = \frac{b-a}{n} = \frac{2-1}{4} = \frac{1}{4} \)\). Then, we evaluate the function \(\( x \ln x \)\)at the endpoints of each subinterval and sum the areas of the trapezoids formed. The approximation formula for the Composite Trapezoidal rule is: \(\[\int_{a}^{b} f(x) \, dx \approx \frac{h}{2} \left[ f(a) + 2\sum_{i=1}^{n-1} f(x_i) + f(b) \right]\]\)

Using this formula, we can calculate the approximation for the given integral. The limits of the integral \(\( \int_{2}^{2} x^{3} e^{x} \, dx \)\) are given as \(\( 2 \)\) to 2 which indicates an interval of zero length. In this case, the integral cannot be evaluated since there is no interval over which to integrate.

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a box contains tickets marked 1 2 ... n. a ticket is dran at random from the box. then this ticket is replaced in teh box and a second ticket is dran at random.

Answers

When a ticket is drawn at random from the box and then replaced, it means that each time a ticket is drawn, the probability of drawing any particular ticket remains the same. This is because the number of tickets in the box stays constant and the drawing is done randomly.



Now, let's consider the situation where a ticket is drawn for the first time. Since there are n tickets in the box, the probability of drawing any specific ticket is 1/n.

After the first ticket is drawn and replaced in the box, the total number of tickets remains the same, n. So, when the second ticket is drawn at random, the probability of drawing any particular ticket is still 1/n.

To find the probability of drawing two specific tickets in succession, we multiply the probabilities of drawing each ticket individually. Therefore, the probability of drawing the first ticket and then the second ticket is (1/n) * (1/n) = 1/n^2.

In summary, if a ticket is drawn at random from a box marked 1 to n, replaced, and then a second ticket is drawn at random, the probability of drawing any specific pair of tickets is 1/n^2.

I hope this helps! If you have any more questions, feel free to ask.

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In an interview for a secretary position at the dealer, a typist claims a tying speed of 45 words per minute. On the basis of 70 trials, she demonstrated an average speed of 43 words per minute with a standard deviation of 15 words per minute. Test at 5% significance level on the typist’s claim.

Answers

According to the typist claim, we build an hypothesis test, find the test statistic and the p-value relative to this test statistic, reaching a conclusion that:

The p-value of the test is 0.1333 > 0.05, which means that there is not enough evidence to reject the typist's claim.

-------------------------------------------------------------

In an interview for a secretary position at the dealer, a typist claims a tying speed of 45 words per minute.

At the null hypothesis, we test if the mean is of at least 45, that is:

\(H_0: \mu \geq 45\)

At the alternative hypothesis, we test if the mean is of less than 45, that is:

\(H_1: \mu < 45\)

-------------------------------------------------------------

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

\(t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}\)

In which X is the sample mean, \(\mu\) is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

-------------------------------------------------------------

45 is tested at the null hypothesis:

This means that \(\mu = 45\)

On the basis of 70 trials, she demonstrated an average speed of 43 words per minute with a standard deviation of 15 words per minute.

This means that \(n = 70, X = 43, s = 15\)

Value of the test statistic:

\(t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}\)

\(t = \frac{43 - 45}{\frac{15}{\sqrt{70}}}\)

\(t = -1.12\)

-------------------------------------------------------------

P-value of the test and decision:

The p-value of the test is found using a left-tailed test(test if the mean is less than a value), with 70 - 1 = 69 degrees of freedom and t = -1.12.

Using a t-distribution calculator, the p-value is of 0.1333.

The p-value of the test is 0.1333 > 0.05, which means that there is not enough evidence to reject the typist's claim.

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Plz help meeee plz help

Plz help meeee plz help

Answers

Answer:

The value of k would be \(\frac{1}{2}\) also written as 0.5

Hope this helps!

Suppose that an individual has a body fat percentage of 12.1% and weighs 139 pounds. How many pounds of his weight is made up of fat? Round your answer to the nearest tenth.

Answers

Answer:

16.8 pounds

Step-by-step explanation:

Given the following :

Body fat percentage = 12.1%

Weight = 139 pounds

How may pounds of the person's weight is made up of fat:

That is 12.1% of the person's entire body weight

Pound of person's weight composed of fat:

12.1% of 139

(12.1 / 100) × 139

0.121 × 139

= 16.819 pounds.

= 16.8 pounds

c. what is the probability of women who did not breast fed and had breast cancer? 1. .04 2. .20 3. .16 4. .80 d. what do you call this probability? 1. joint probability 2. conditional probability 3. additional rule 4. marginal probability

Answers

The probability of women who did not breastfeed and had breast cancer is not provided in the given options. However, the answer would depend on various factors and cannot be determined solely based on the information given.

It is important to note that breastfeeding is known to have a protective effect against breast cancer, but it does not guarantee that a woman will not develop breast cancer if she does not breastfeed.

Additionally, there are several other risk factors for breast cancer, such as family history, genetics, hormonal factors, and lifestyle choices, which can influence the probability. Therefore, without specific data or context, it is not possible to provide an accurate probability.

Conditional probability is the term used to describe the probability of an event occurring given that another event has already occurred. In this case, if we had information on the probability of breast cancer given that a woman did not breastfeed, we could calculate the conditional probability.

However, since the given information does not include such data, we cannot determine the probability or classify it as a specific type of probability (e.g., joint, conditional, additional rule, or marginal probability).

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Ecological approach to algal bloom control. Algal blooms can have negative effects on an ecosystem by dominating its phytoplankton communities. Gonyostomum semen is a nuisance alga infesting many parts of northern Europe. Could the overall biomass of G. semen be controlled by grazing zooplankton species? A research team examined the relationship between the net growth rate of G. semen and the number of Daphnia magna grazers introduced in test tubes. A net growth rate was computed by comparing the initial and final abundances of G. semen in the experiment, with a negative value indicating a decrease in abundance. Here are the findings: 13 1 2 3 4 5 6 Number of grazers Net growth rate -1.9 -2.5 -2.2 -3.9 -4.1 -4.3 a. Make a scatterplot of number of grazers and net growth rate. Do you think that D. magna is an effective grazer of the G. semen alga? b. Find the correlation 1. How does it support your interpretation?

Answers

a. D. magna is an effective grazer of the G. semen alga. b. a very strong negative correlation between the number of grazers and the net growth rate of G. semen.

a. The scatterplot of the data shows a clear negative correlation between the number of D. magna grazers and the net growth rate of G. semen. As the number of grazers increases, the net growth rate of G. semen decreases. This suggests that D. magna is an effective grazer of the G. semen alga.

b. The correlation coefficient between the number of grazers and the net growth rate is -0.996. This indicates a strong negative correlation between the two variables, which supports the interpretation that D. magna is an effective grazer of G. semen. The closer the correlation coefficient is to -1, the stronger the negative correlation between the two variables. In this case, the correlation coefficient is very close to -1, which indicates a very strong negative correlation between the number of grazers and the net growth rate of G. semen.

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Find the product.

−32⋅4⋅12(10−8)
Enter your answer as a number, like this: 42

Answers

Answer:

-3072

Step-by-step explanation:

-32(4)(12)(10-8)

-32(4)(12)(2)

-128(12)(2)

-3072

While Brian traveled, the pilot taught him
O how to steer a Cessna 406
O how to fill the gas tank on the Cessna 406
O how to read the instrument panel on the Cessna 406

Answers

While Brian traveled, the pilot taught him A. how to steer a Cessna 406.

What is a Cessna 406?

The Cessna 406 is a twin-engine aircraft that is commonly used for various purposes, such as air ambulance services, freight transport, and surveillance operations. Steering the aircraft is an essential skill that any pilot must learn in order to control the aircraft's direction of flight.

Learning how to steer a Cessna 406 would be an important skill for Brian to acquire if he was planning to become a pilot or work in the aviation industry.

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d²v dt² v=2t² +7t+11 Find

Answers

The second derivative of v with respect to t, denoted as d²v/dt², is equal to 4

The second derivative of v with respect to t, we will differentiate v twice.

v = 2t² + 7t + 11

First, let's find the first derivative of v with respect to t (dv/dt):

dv/dt = d/dt (2t² + 7t + 11)

Using the power rule of differentiation, we differentiate each term separately:

dv/dt = 2(2t) + 7(1) + 0

dv/dt = 4t + 7

Now, let's find the second derivative of v with respect to t (d²v/dt²):

d²v/dt² = d/dt (4t + 7)

Again, using the power rule of differentiation, we differentiate each term separately:

d²v/dt² = 4(1) + 0

d²v/dt² = 4

Therefore, the second derivative of v with respect to t, denoted as d²v/dt², is equal to 4.

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Please can someone help?

Please can someone help?

Answers

Answer:

The answer is 40cm

Step-by-step explanation:

hope this helps :)

Answer:

40

Step-by-step explanation:

Side of square = x

Long side of rectangle = x + 5

Short side of rectangle = x - 3

(x - 3)(x + 5) = 84

\(x^2+2x-15=84\)

x = 9, x = -11

X has to be 9 because x cannot be negative.

9 + 5 = 14

9 - 3 = 6

14 + 14 + 6 + 6 = 40

the rectangular garden shown has a width of 50 feet and a length of 45 feet and is surrounded by a paved path with a uniform width of x feet. if the combined area of the garden and the paved path is 2646 square feet, what is the value of x ?

Answers

Thus we only take the positive root:x = 27/8 = 3.375Answer: 3.375 feet.

The problem states that a rectangular garden that measures 50 feet wide and 45 feet long is enclosed by a uniform width of x feet paved path. To solve the problem,

we can use the formula of the combined area of the garden and the paved path and equate it to 2646 square feet. The combined area is computed by adding the area of the garden and the area of the paved path.

Garden area:Length of garden = 45 ftWidth of garden = 50 ftArea of garden = Length x Width= 45 x 50= 2250 square feet

Paved path:

If the garden has a uniform width of x feet paved path, then the width of the paved path would be x + 2x + x= 4x. The width is multiplied by 2 because there are two widths surrounding the garden.

Length of paved path = length of garden + 2 (width of paved path)= 45 + 2 (4x)= 8x + 45Width of paved path = width of garden + 2 (width of paved path)= 50 + 2 (4x)= 8x + 50

The area of the paved path is computed by subtracting the area of the garden from the combined area.Area of paved path = Combined area - Garden area2646 square feet

= (8x + 45) (8x + 50) - 2250= 64x² + 760x + 675

We then solve for the value of x by factoring the quadratic equation.2646 square feet = 64x² + 760x + 6752646 - 2646

= 64x² + 760x + 675 - 264664x² + 760x - 1971

= 0(8x - 27) (8x + 73) = 0

The value of x cannot be negative,

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The sum of W and fourteen is five

Answers

Answer:

It depends on what you're looking for, but-

Writing an equation from words: w+14=5

Solving for w: w=-9

Step-by-step explanation:

Writing an equation from words:

"Sum" means the answer to an addition problem, for example,

1+1=2.

2 would be the sum.

Anyways, the word problem says the sum is 5. So this is what our equation looks like: ?=5

The two numbers being added together are "w" and "14," which leads us to our answer: w+14=5

Solving for w:

w+14=5

Subtract 14 from both sides to get your answer:

w= -9

An adults heart beats about 2100 times every 30 minutes.A baby beats about 2600 times every 20 minutes. How many more heart beat i 60 minutes than an adults hearts?

Answers

Given :

An adults heart beats about 2100 times every 30 minutes.

A baby beats about 2600 times every 20 minutes.

To Find :

How many more heart beat baby have than adult in 60 min .

Solution :

Now , total number of heart beats of adult in 60 min , \(T_a=2100\times 2=4200\)

Also , total number of heart beats of adult in 60 min , \(T_b=2600\times 3=7800\)

Difference between them , \(7800-4200=3600\) beats .

So , baby have 3600 more heart beats than adult .

Hence , this the required solution .

for a certain art exhibit, a museum sold admission tickets to groups of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. the price of a regular admission ticket was $10 and the price of a student ticket was $6. if on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?

Answers

Using Algebra operation,

the total revenue from ticket sales on that day is $ 3444..

We have given the following information,

timing of museum for entry is 9:00 am to 5:55pm. i.e 8 hours 55 minutes .

price of ticket for a regular admission= $10

price of ticket for a student admission = $6

30 people's admission in every 5 minutes so,

inclusive there are 9×12=108 five-minute intervals, total of tickets were sold = 108× 30

= 3240

let x student and 3x regular tickets were sold on that day.

then, x+3x= 108× 30 –> x= 3240/4 = 810

put x= 7560 in above formula, for regular admission, 3x=3× 81 = 243

So, the total revenue from ticket sales that day was 243×$10 + 810×$6 = $2430 + $4860

= $7290

Hence, total revenue from tickect sales is $7290.

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help please . will give brainliest ​

help please . will give brainliest

Answers

Answer:

A

Step-by-step explanation:

the last number is the y intercept so the intercept in the line is -3.5 so I just matched them up.

1. Marlin averages for his Social Studies class is listed below. If the teacher
weights homework at 20%, quizzes at 20%, tests at 45%, and the final exam
at 15%, what is Marlin's class average?
1)61%
2)71%
3)74%
4)82%

1. Marlin averages for his Social Studies class is listed below. If the teacherweights homework at 20%,

Answers

The answer is 2) 71%

please help !! im so confused lol

please help !! im so confused lol

Answers

Answer:

(c) 1.61

Step-by-step explanation:

thats what i got

I go out star gazing again, but this time the chances of seeing a shooting star are 80% in any given hour. Assuming that the probability of seeing a shooting star is uniform for the entire hour, what is the probability that I will see one during the first 15 minutes of the hour I am out

Answers

The probability of seeing a shooting star during the first 15 minutes of the hour is approximately 19.95%

To solve this problem, we need to use conditional probability. We want to find the probability of seeing a shooting star during the first 15 minutes of the hour given that the chances of seeing a shooting star in any given hour are 80%.

First, we need to determine the probability of seeing a shooting star in the first 15 minutes of the hour. Since the probability is uniform for the entire hour, we can assume that the probability of seeing a shooting star in any given minute is 80% divided by 60 (the number of minutes in an hour), which is approximately 1.33%.

To find the probability of seeing a shooting star during the first 15 minutes of the hour, we need to add up the probabilities of seeing a shooting star in each of the 15 minutes. This can be calculated as follows:

P(seeing a shooting star in the first 15 minutes) = P(seeing a shooting star in minute 1) + P(seeing a shooting star in minute 2) + ... + P(seeing a shooting star in minute 15)
= 15 x 1.33%
= 19.95%

Therefore, the probability of seeing a shooting star during the first 15 minutes of the hour is approximately 19.95%. This means that if you go out star gazing again and the chances of seeing a shooting star are 80%, there is a 19.95% chance that you will see one during the first 15 minutes of the hour you are out.

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An item on sale costs 30% of the original price. If the original price was $90 what is the sale price

Answers

The answer would be 117 because 90+30%of 90 is equal to 117

The total simple interest for a five month loan of $640,000 was $38,545. Find the simple interest rate. (Enter your answer with a percent sign.) Your Answer: Answer Question 7 Find the term (in days) of a $785.95 loan at 17.99% given that the simple interest amounts to $81.32. Your Answer: Answer Question 8 ( 1 point) A simple interest loan had a principal of $819.20 and a maturity value of $850.00. The simple interest rate was 11.25%. Find the term in days.

Answers

6. The simple interest rate is 12.8%.

7.  The term of the loan is 50 days.

8.  The term of the loan is 95 days.

Let the simple interest rate be r (in decimal form). Then, the total interest earned is given by:

I = Prt

where P is the principal amount, t is the time period in years, and I is the total interest earned. We are given that:

P = $640,000

t = 5/12 years (since the loan is for five months)

I = $38,545

Plugging in these values, we get:

38545 = 640000 * r * (5/12)

Solving for r, we get:

r = 0.128 or 12.8%

Therefore, the simple interest rate is 12.8%.

Answer to Question 7:

Let the time period of the loan be t (in days). Then, the interest earned is given by:

I = Prt/365

where P is the principal amount, r is the interest rate per day (in decimal form), and I is the total interest earned. We are given that:

P = $785.95

I = $81.32

r = 0.1799/365

Plugging in these values, we get:

81.32 = 785.95 * 0.1799/365 * t

Solving for t, we get:

t = 49.76 days

Rounding off to the nearest day, we get:

t ≈ 50 days

Therefore, the term of the loan is 50 days.

Answer to Question 8:

Let the time period of the loan be t (in days). Then, the interest earned is given by:

I = Prt/365

where P is the principal amount, r is the interest rate per day (in decimal form), and I is the total interest earned. We are given that:

P = $819.20

I = $30.80 ($850.00 - $819.20)

r = 0.1125/365

Plugging in these values, we get:

30.8 = 819.2 * 0.1125/365 * t

Solving for t, we get:

t = 94.71 days

Rounding off to the nearest day, we get:

t ≈ 95 days

Therefore, the term of the loan is 95 days.

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Words to know Match each word to know with its definition. dividend the number a dividend is divided by in a division problem divisor the number being divided in a division product the result of dividing one quantity by quotient enetoftwo or more numbers that are multiplied together factor the result of multiplying two or more quantities together​

Words to know Match each word to know with its definition. dividend the number a dividend is divided

Answers

Answer:

can't see it can u reload up

Answer:

u dont need help?

Step-by-step explanation:

still

51:55
The phrase "six less than twice y" can be represented by the algebraic expression
2y-6
2y + 6
O 6<2y
6 > 2y
Mark this and retum
Save and Exit
Next

Answers

2y-6 is the answer hope this helps

(High points) Please solve with explanation

(High points) Please solve with explanation

Answers

Answer:

36 9/16 inches

Step-by-step explanation:

Given that the piece is 45 1/2 inch long and 8 7/8 is cut from it, the remaining length should be the difference between the original length and the length cut from it

= 45 1/2 - 8 7/8

simplify

= 44 - 8  (8 + 4 - 7)/8

= 36 5/8

Given that 1/16 inch is wasted in the process, the remaining length would be

= 36 5/8 - 1/16

= 36 10 - 1/16

= 36 9/16 inches

The table shows pizza prices at Papi's Pizzeria.

Pizza Size Price
small $9.99
medium $11.99
large $13.99
On Saturday, Papi's sold 39 small pizzas, 62 medium pizzas, and 83 large pizzas.
Which equation represents the total amount of money Papi's made selling pizzas on Saturday?

A.
(
39
+
62
+
83
)
×
(
$
9
.
99
+
$
11
.
99
+
$
13
.
99
)
=
$
6
,
618
.
48
B.
(
$
9
.
99
×
39
)
+
(
$
11
.
99
×
62
)
+
(
$
13
.
99
×
83
)
=
$
2
,
294
.
16
C.
(
39
×
62
×
83
)
÷
(
$
9
.
99
+
$
11
.
99
+
$
13
.
99
)
=
$
5
,
579
.
48
D.
1
3
(
$
9
.
99
+
$
11
.
99
+
$
13
.
99
)
×
(
39
+
62
+
83
)
=
$
2
,
206
.
16

Answers

The equation that represents the total amount of money Papi's made selling pizzas on Saturday is (39 x $9.99) + (62 x $11.99) + (83 x $13.99)

Equation:

An equation is the mathematical statement which is made up of two expressions connected by an equal sign.

For example, 3x – 2 = 16 is an equation.

Given,

There are three types of pizza varieties are small, medium and large. And the price of them are $9.99, $11.99 and $13.99 respectively.

On Saturday, Papi's sold 39 small pizzas, 62 medium pizzas, and 83 large pizzas.

So, we have to write the equation for the total amount of money Papi's made selling pizzas on Saturday.

To calculate the price of the pizza we have to multiply it by the number of items sold by the cost.

So, the equation to calculate the cost of pizza,

=> number of items sold x cost.

Here we have to write the equation for three types and we have to find the total cost for it,

So, the equation is looks like,

=> (39 x $9.99) + (62 x $11.99) + (83 x $13.99)

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please help and show work if you can​

please help and show work if you can

Answers

Answer:

25. a = 60

26. a = 17

Step-by-step explanation:

In these two problems we are going to use a property of parallelograms that says: opposite angles have equal measure

so we have

25.

\(6a+10=130\\\\6a=130-10\\\\6a=120\\\\a=60\)

and for 26 we have

\(4a-4=2a+30\\\\4a=2a+30+4\\\\4a=2a+34\\\\4a-2a=34\\\\2a=34\\\\a=17\)

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