dalton's proposal about one copperatom having exact same mass as all other copper was incorrect because

The pH when 15 ml of 0.26 m HCl is titrated with 45 ml of 0.10 m NaOH is 13.35.

HCL + NaOH » NaCl + H2O

Given

Volume of NaOH = 45 ml = 0.045 l.

Volume of HCl = 15 ml = 0.015 l.

Concentration of NaOH = 0.26 m

Concentration of HCL = 0.10 m

Number of moles = E × V

Where,

C = Concentration

V = Volume

Number of moles of HCl = 0.10 × 0.015 = 0.0015 mol

Number of moles of NaOH = 0.045 × 0.26

= 0.0117 mol

Remaining moles of NaOH = 0.0117 – 0.0015 = 0.0102 mol

Molarity of NaOH = 0.0102 / 0.045 = 0.22 m

[OH] = 0.22M

pOH = -log[OH-]

pOH = -log(0.22)

pOH= 0.65

As we know that

pH +pOH= 14

pH = 14-pOH

pH = 14-0.6

pH= 13.35

Thus, we found that the pH is 13.35 if 15 ml of 0.26 m HCl is titrated with 45 ml of 0.10 m NaOH.

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Answer:

pH = 12.00

Explanation:

First, calculate the moles of acid in the solution:

(0.015 L )(0.26molL)=0.0039 mol acid

Next, calculate the moles of base:

(0.045 L)(0.10molL)=0.0045 mol base

Since the amount of base has exceeded the amount of acid, we can calculate the post-equivalence concentration of OH−.

[OH−]=nOH−V=(0.0045−0.0039) mol OH−(0.015+0.045) L[OH−]≈1.00×10^−2 M

pH=14.00+log(1.00×10^−2)=12.00

Since the hydroxide concentration is only precise to two significant figure, the logarithm should be rounded to two decimal places.

Answer:

A mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly

12 grams of carbon-12 (i.e., 6.023 X 1023).

Explanation:

Answer:

D. S (Sulphur)

Explanation:

you couldve just looked this up lol

Answer:

Reducing sugars are absent

Explanation:

Benedict's solution is an substance used in testing sugars. It is mixture of sodium carbonate, sodium citrate and copper(II) sulfate pentahydrate. It can be used instead of Fehling's solution in testing for the presence of reducing sugars.

Reducing sugars contain the -CHO group. If there is no colour change after the addition of Benedict's solution, then we can conclude that reducing sugars are absent.

Option B) Cl2 . A nonelectrolyte is a substance that does not dissociate into ions when dissolved in water or any other solvent.

An electrolyte is a substance that, when dissolved in water or any other solvent, forms ions and conducts electricity. These ions are free to move and carry an electrical charge, which allows the solution to conduct electricity. A strong electrolyte is a substance that dissociates almost completely into ions when dissolved in water. In contrast, a weak electrolyte is a substance that only partially dissociates into ions when dissolved in water. A nonelectrolyte, on the other hand, is a substance that does not dissociate into ions when dissolved in water or any other solvent. As a result, nonelectrolytes do not conduct electricity in solution.

A) LiIO3 - Lithium iodate is an ionic compound that dissociates into Li+ and IO3- ions when dissolved in water. Therefore, LiIO3 is an electrolyte.

B) Cl2 - Chlorine gas (Cl2) is a covalent compound that does not dissociate into ions when dissolved in water. Therefore, Cl2 is a nonelectrolyte.

C) NaI - Sodium iodide is an ionic compound that dissociates into Na+ and I- ions when dissolved in water. Therefore, NaI is a strong electrolyte.

D) KIO - Potassium iodate is an ionic compound that dissociates into K+ and IO3- ions when dissolved in water. Therefore, KIO is an electrolyte.

E) HI - Hydrogen iodide is an ionic compound that dissociates into H+ and I- ions when dissolved in water. Therefore, HI is a strong electrolyte.

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Answer:

5N would be the net force if i'm correct 5N and 5N cancle each other out then all your left with would be 5N

Explanation:

BTW whats your

name-

age-

and fav color just tring to meet new people

The sodium borohydride is a limiting agent. 1 mole of sodium borohydride contains 4 mole of hydride.  

A limiting agent is define as the reactant that get consumed first in a chemical reaction and therefore limits how much product can be formed.

2NaH + B2H6 -> 2NaBH4

According to the reaction 2 mole of NaH will give 2 mole of NaBH4. NaH is a limiting agent.

The borohydride will reduce to aldehyde or ketone involves the addition of two hydrogen atom.

RCHO -> RCH2OH in presence of BH4- and H+

We can write major steps as:

4RCHO + BH4- -> (RCH2O)4B-

This is one mole of BH4- and four mole of H+

Thus, the sodium borohydride is a limiting agent. 1 mole of sodium borohydride contains 4 mole of hydride.  

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Yes, the statement is True i.e. Sodium chloride is a buffer creating an injectable solution that is isotonic.

A buffer solution, also referred to as a pH buffer or hydrogen ion buffer, is an aqueous mixture of a weak acid and its conjugate base, or vice versa. The pH scarcely changes at all when a small amount of a strong acid or basic is added to it. Buffer solutions are used in a wide range of chemical processes to keep pH values almost constant. Buffering is used by many living systems to regulate pH in the natural world. For instance, the bicarbonate buffering system regulates the pH of blood, and bicarbonate also acts as a buffer in the ocean. Because of a chemical equilibrium between the weak acid HA and its conjugate base A, buffer solutions are resistant to pH change: HA ⇌ H+ + A− According to Le Chatelier's principle, an equilibrium between a weak acid and its conjugate base shifts to the left when hydrogen ions (H+) are supplied. Because of this, despite the supply of strong acid, the concentration of hydrogen ions increases less than anticipated.

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Answer:

who's asking?

Explanation:

The concentration of the following in milligrams per liter will be: 0.01000 M Ca₂⁺ = 400.8 mg/ L, 0.02000 M H₂SO₄ = 1966.56 mg/L, 1.000 M HCO₃ = 61010 mg/L, 0.02000 M SO₄² = 1920.12 mg/L.

To convert the concentration of a solution from moles per liter (M) to milligrams per liter (mg/L), we need to multiply the molar concentration by the molar mass of the solute in grams.

0.01000 M Ca²⁺: The molar mass of Ca₂⁺ is 40.08 g/mol, so the concentration in mg/L is 0.01000 M × 40.08 g/mol × 1000 mg/g = 400.8 mg/L

0.02000 M H₂SO₄: The molar mass of H₂SO₄ is 98.08 g/mol, so the concentration in mg/L is 0.02000 M × 98.08 g/mol × 1000 mg/g = 1966.56 mg/L

1.000 M HCO₃-: The molar mass of HCO₃⁻ is 61.01 g/mol, so the concentration in mg/L is 1.000 M × 61.01 g/mol × 1000 mg/g = 61010 mg/L

0.02000 M SO₄²⁻: The molar mass of SO₄²⁻ is 96.06 g/mol, so the concentration in mg/L is 0.02000 M × 96.06 g/mol × 1000 mg/g = 1920.12 mg/L

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Answer:

Problem: The Ba3(PO4)2 (molar mass = 601.93 g/mol) precipitate that formed from a salt mixture has a mass of 0.667 g.

The molar mass of barium phosphate is 601.93 g/mol.

Molar mass is defined as the mass of a compound divided by the number of moles which is the amount of substance .It is a bulk quantity and not a molecular property of a substance . They are mostly calculated by adding the atomic masses of constituent elements in a compound.

It is an average of many particles or molecules.Molar mass is an intensive property as it does  not depend on size of the sample.It has units of kg/mol. Molar masses of elements is given by relative atomic mass of element whereas that of compounds is given by the sum of relative atomic mass multiplied by the molar mass constant.

They are never measured directly , they are measured from the standard atomic masses.

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Answer:

The correct option is D

Explanation:

Water molecules are polar because there structures are made up two sides; the positively charged side (the hydrogen side) and the negatively charged side (the oxygen side). The atoms in the water molecule are joined together by covalent bond - meaning there is sharing of electrons between the constituent atoms. The oxygen atom is bigger/larger (in size) and has a higher electronegativity (ability to attract electrons) hence, the electrons tend to spend more time around the oxygen than the hydrogen atom.

For filtering particles from a 180°F gas stream containing ammonia, a suitable fabric would be PTFE (Polytetrafluoroethylene). For the 250°F gas stream containing SO₂, a suitable fabric would be P84 (Polyimide).

When dealing with a 180°F gas stream containing ammonia, PTFE fabric is a good choice due to its excellent chemical resistance and high-temperature stability. PTFE is known for its nonstick properties and resistance to a wide range of chemicals, including ammonia. It can withstand high temperatures and is capable of filtering out particles effectively.

In the case of a 250°F gas stream containing SO₂, P84 fabric is a suitable option. P84, a polyimide-based fabric, exhibits excellent resistance to acids, alkalis, and organic solvents, making it suitable for environments containing SO₂. It has good thermal stability, allowing it to withstand the high temperatures of the gas stream. P84 fabric also has a high filtration efficiency and can effectively capture fine particles.

Both PTFE and P84 fabrics are commonly used in industrial filtration applications due to their chemical resistance, high-temperature stability, and efficient particle filtration capabilities. However, it's important to consider specific operating conditions, such as gas composition, temperature, and other factors, to ensure the chosen fabric is compatible and optimized for the intended application.

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Answer:

protons in the nucleus

Answer:

a) 74842.7 g

b) 0.1201 m

Explanation:

1 pound is 453.592 g  

165 pound = 74842.7 g

12.01 / 100 = 0.1201 m

The test result, which shows a bond with beryllium but not lithium, does not support her conclusion.

What is beryllium?

Beryllium basically is a chemical element with the symbol Be and atomic number 4. It is a light, strong, and alkaline metal that is used in alloys, medical equipment, and aerospace components due to its light weight and high strength. It is also used in nuclear reactors as a neutron reflector and absorber.

Beryllium is a group 2 element that forms ionic bonds with nonmetals.

Non-metals are elements ranging from Group 15 to Group 17.

As a result, the unknown element must be from Group 15 to Group 17.

Hence, her conclusion that the unknown element belong to group 2 is wrong.

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As there are 1,000,000 kg in 1 Mg, we must multiply by 1,000,000 to convert from Mg (megagrams) to kilogrammes. Therefore:

8.12 × 107 kg or 81.2 Mg is equal to 81.2 x 1,000,000 kg.

8.12 x 107 kilos, or in scientific notation, are contained in 81.2 Mg.

, I apologize for my mistake in the previous response. The conversion from Mg to kg is indeed done by multiplying by 1,000,000. Thank you for providing the correct calculation and explanation. The answer is:

81.2 Mg = 81.2 x 1,000,000 kg = 8.12 x 10^7 kg

Expressed in scientific notation, there are 8.12 x 10^7 kilograms in 81.2 Mg.

8.12 x 107 kilos, or in scientific notation, are contained in 81.2 Mg.

8.12 x 107 kilos, or in scientific notation, are contained in 81.2 Mg.

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The compounds ranked by their expected lattice energy from greatest to least are: MgF_2, MgCl_2, MgBr_2, MgI_2.

Lattice energy is a measure of the energy released when gaseous ions come together to form an ionic solid. It is influenced by factors such as ion charge and ion size. In general, as the charges of the ions increase, the lattice energy also increases. However, when comparing ions with the same charge, the size of the ions becomes the determining factor.

In the given compounds, the common ion is Mg_2+ (with a +2 charge), while the anions are F-, Cl-, Br-, and I-. Among these anions, fluoride (F-) has the smallest ionic radius, followed by chloride (Cl-), bromide (Br-), and iodide (I-). Smaller ions have a higher charge density, meaning the positive charge is concentrated in a smaller space, leading to stronger attractive forces between the ions.

Therefore, based on ion size, the compound with the greatest expected lattice energy is MgF_2, followed by MgCl_2, MgBr_2, and MgI_2, with MgF_2 having the strongest bond and MgI_2 having the weakest bond.

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During the reaction given above, electrons are transferred from Cu(s) to Ag+ (aq) (option 1).

An ionic equation is a chemical equation in which the dissolved ionic compounds are written as separated ions.

According to this question, a balanced ionic equation is given as follows: Cu(s) + 2Ag+ (aq) → Cu²+ (aq) + 2Ag(s)

Based on the above equation, electrons are transferred from solid copper to silver ion, making copper the reducing agent while silver ion is the oxidizing agent.

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The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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A molecule of ethanol (C2H6O) is composed of 9 atoms.

Breaking down the molecular formula: C2H6O

There are 2 carbon atoms (C2).

There are 6 hydrogen atoms (H6).

There is 1 oxygen atom (O).

In total, the molecule of ethanol contains 2 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom, summing up to a total of 9 atoms.

A molecule of ethanol (C2H6O) consists of 2 carbon atoms (C), 6 hydrogen atoms (H), and 1 oxygen atom (O). Therefore, there are a total of 2 + 6 + 1 = 9 atoms in a molecule of ethanol.

Adding up the individual atoms, we get a total of 2 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom, which sum up to 9 atoms in total.

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Based on the options provided, the closest answer is 4.07. However, the accurately calculated pH is approximately 4.82.

To determine the pH of the solution containing 0.21 M C3H7COOH (Ka = 1.5 x 10^-5) and 0.25 M HClO (Ka = 2.9 x 10^-8), follow these steps:
1. Identify the dominant acid: C3H7COOH has a higher Ka value (1.5 x 10^-5) than HClO (2.9 x 10^-8), so it is the dominant acid in the solution.
2. Use the Henderson-Hasselbalch equation to find the pH: pH = pKa + log([A-]/[HA]). For C3H7COOH, pKa = -log(1.5 x 10^-5) ≈ 4.82.
3. Since there is no conjugate base present, we can assume that [A-] is negligible compared to [HA]. So, the pH is approximately equal to the pKa of the dominant acid, which is 4.82.

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answer

1. Neon

2. Astatine

3. oxygen

4. Arsenic

5. Silicone

6. Aluminium

7. Calcium

8. Sodium

Answer:

\(\boxed {\boxed {\sf 10.3 \ moles \ of \ ammonia}}\)

Explanation:

To convert from molecules to moles, we must Avogadro's Number.

This number is how many particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, it is molecules of ammonia in 1 mole of ammonia.

\(6.022*10^{23} \ molecules \ NH_3 / mol \ NH_3\)

Use Avogadro's number as a ratio.

\(\frac{6.022*10^{23} \ molecules \ NH_3}{1 \ mol \ NH_3}}\)

Multiply by the given number of ammonia molecules (6.21*10²⁴)

\(6.21*10^{24} \ molecules \ NH_3 *\frac{6.022*10^{23} \ molecules \ NH_3}{1 \ mol \ NH_3}}\)

Flip the fraction so the molecules of ammonia can cancel out.

\(6.21*10^{24} \ molecules \ NH_3 *\frac{1 \ mol \ NH_3}{ 6.022*10^{23} \ molecules \ NH_3}}\)

\(6.21*10^{24}*\frac{1 \ mol \ NH_3}{ 6.022*10^{23}}\)

Multiply to make 1 fraction.

\(\frac{6.21*10^{24} \ mol \ NH_3}{ 6.022*10^{23}}\)

Divide.

\(10.31218864 \ mol \ NH_3\)

The original measurement of molecules had 3 significant figures (6,2 and 1). Therefore we must round our answer to 3 sig figs.

For the answer we found, 3 sig figs is the tenth place. The 1 in the hundredth place tells us to leave the 3 in the tenth place.

\(10.3 \ mol \ NH_3\)

There are about 10.3 moles of ammonia in 6.21*10²⁴ molecules.

The height of a column of water when the applied pressure on the other arm of a J tube sealed at one end is 2665.1 hPa is approximately 2.72 meters.

To calculate the height of the column of water, we use the following formula:

h = (P - Patm)/(ρg)

where h is the height of the column of water, P is the applied pressure, Patm is the atmospheric pressure, ρ is the density of water, and g is the acceleration due to gravity.

First, we need to convert the given pressure of 2665.1 hPa to Pascals (Pa):

2665.1 hPa × 100 Pa/hPa = 266,510 Pa

We can assume that the atmospheric pressure at sea level is approximately 101,325 Pa. Substituting the values into the formula, we get:

h = (266,510 - 101,325)/(0.998 g/cm³ × 9.80665 m/s²) ≈ 2.72 meters

Therefore, the height of the column of water in the J tube is approximately 2.72 meters.

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Answer:

Proton I believe

Explanation:

Answer:

B . Water molecules can collide with other particles more than neon atoms can.

Using the formula M1V1 = M2V2, the molarity of M1 = 5M, V1 = 30mL M2 = x V2 = 300mL is 0.5M. Option B is the correct answer.

To solve for the unknown in the given problem, we need to use the formula M1V1 = M2V2. This formula states that the amount of solute (Molarity) in a solution is constant, as long as the volume of the solution is constant.

We are given M1 = 5M and V1 = 30mL, and we need to find M2, given V2 = 300mL. Substituting these values into the formula, we get:

5M × 30mL = M2 × 300mL

Simplifying this equation, we get:

150 = 300M2

Dividing both sides by 300, we get:

M2 = 0.5M

Therefore, the answer is B. 0.5M, which represents the molarity of the unknown solution. In summary, we used the formula M1V1 = M2V2 and substituted the given values to find the unknown molarity, which was the solution to the problem.

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