dave has built a storage box and needs to decorate it. It is cuboid 32cm long, 20cm wide and 30 cm tall. what is the volume of daves storage box and what is the surface area?

Given the functon

Explanation

To find the points that lie in the solution set we will lot the graph of the function and indicate the ordered pirs.

From the above, we can see that the right option is

Answer: Option 1

Answer:

suddenly

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

The equivalent expression is  

✔ 3y + 2

.

The value of both expressions when y = 5 is  

✔ 17

.

The expressions are  

✔ equivalent

.

Step-by-step explanation:

Answer:

The equivalent expression is  

✔ 3y + 2

.

The value of both expressions when y = 5 is  

✔ 17

.

The expressions are  

✔ equivalent

.

Step-by-step explanation:

The length and width of the rectangular playing field are 56 yard and 26 yard respectively.

For the stated question-

Let the length of the football league be 'L'.

Let the width of the football league be 'B'.

Then, L = 30 + W

Perimeter = 164 yards.

Perimeter = 2(L + W)

Perimeter = 2(30 + W + W)

Perimeter = 2(30 + 2W)

164 = 60 + 4W

4W = 104

W = 26 yard

L = 30 + 26 = 56 yard.

Thus, the length and width of the rectangular playing field are 56 yard and 26 yard respectively.

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b'

Let the given points be A(3,-5) and B(5,-1).

AB= sqrt of (5−3) ² +(−1+5)²

= sqrt of 4+16

= sqrt of 20

=2 sqrt of 5 units

Answer:

C

Step-by-step explanation:

By tracing the figure, we see that we go around a semicricle twice and go in a straight path twice. So the perimeter of this figure consists of two semicircles and two line segments, hence the answer is C.

Answer:

Answer to 6/9-2/3= 0; Lowest common denominator = 3;

Step-by-step explanation:

You can only reduce 6/9 to 2/3, you cant reduce the fraction any further.

Using the fact that the angles are supplementary, we can write and solve a linear equation to find that x = 5°.

Remember that two angles are supplementary if the addition of their measures is equal to 180°.

Here we know that angles J and K are supplementary, then we know that:

J + K = 180°

Here we also know that:

J = 120°

K = 12x

So we can write a linear equation of the form:

120° + 12x = 180°

12x = 180° - 120°

12x = 60°

x = 60°/12 = 5°

x = 5°

We conclude that the value of x is 5°.

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Answer:

4 crayons were not put on the tables.

Step-by-step explanation: Since to get to 80 you would have to times 8 by 10 when you divide 80 by 8 you would get 10, there would be a remainder of 4, which were the leftover crayons that were not put on the table.

Answer:

The set M of all square numbers less than 80 is:

M = {0, 1, 4, 9, 16, 25, 36, 49, 64}

The set N of all non-negative even numbers that are under 30 is:

N = {0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28}

Answer:

All elements of the set M in ascending order are:

All elements of the set N in ascending order are:

Step-by-step explanation:

A square number, also known as a perfect square, is a non-negative integer that is obtained by multiplying an integer by itself. In other words, it is the result of squaring an integer.

The square numbers less than 80 are:

An even number is an integer that is divisible by 2 without leaving a remainder.

The non-negative even numbers that are under 30 are:

Therefore:

All elements of the set M in ascending order are:

All elements of the set N in ascending order are:

Answer:

A = 2184 cm²

Step-by-step explanation:

the area (A) of the figure is calculated as

A = \(\frac{1}{2}\) h(b₁ + b₂)

where h is the perpendicular height between the bases b₁ and b₂

here h = 42 , b₁ = 52 , b₂ = 52 , then

A = \(\frac{1}{2}\) × 42 × (52 + 52) = 21 × 104 = 2184 cm²

Answer:

A = 2184 cm2

Step-by-step explanation:

Area of a parallelogram:

\(A = b*h\)

\(b=52,h=42\)

\(A=(42)(52)=2184cm^{2}\)

Hope this helps.

The trigonometric identity sin(x + y) = (√95 + 3√17)/27

Trigonometric identities are identities containing trigonometric ratios.

Given that tanx = 1/√8 and siny = √17/6 and angles x and y are both in Quadrant 1, we need to find the value of sin(x + y)

So, using the trigonometric identity sin(x + y) = sinxcosy + cosxsiny

First we need to find sinx, cos x and cosy

Using trigonometric identity 1 + tan²x = sec²x

sec²x = 1 + tan²x

= 1 + (1/√8)²

= 1 + 1/8

= (8 + 1)/8

= 9/8

sec²x = 9/8

secx = √(9/8)

= ±3/2

secx = 1/cosx

1/cosx = ±3/2

cosx = ±2/3

Now sinx = √(1 - cos²x)

= √(1 - (2/3)²)

= √[(1 - 4/9)]

= √[(9 - 4)/9]

= √(5/9)

= ±√5/3

Also, cosy = √(1 - sin²y)

= √(1 - (√17/6)²)

= √(1 - 17/36)

= √[(36 - 17)/36]

= √(19/36)

= ±√19/6

Since sin(x + y) = sinxcosy + cosxsiny, substituting the positive values of the variables into the equation since they are in the first quadrant, we have that

sin(x + y) = sinxcosy + cosxsiny

sin(x + y) = √5/3 × √19/6 + 2/3 × √17/6

= √95/27 + √17/9

= √95/27 + √17/9

= 1/9(√95/3 + √17)

= 1/9(√95 + 3√17)/3

= (√95 + 3√17)/27

So, sin(x + y) = (√95 + 3√17)/27

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Answer:

a) Categorical

b) Quantitative

c) Categorical

d) Quantitative

Step-by-step explanation:

A variable can be classified as qualitative or quantitative.

Qualitative(Categorical):

When the possible values of the variables are labels, for example, good or bad, yes or no,...

Quantitative:

When the possible values of the variables are numbers, for example 1, 2, 1000,....

A) Does the computer come with a USB port?

The possible answers are: yes or no, so it is a categorical variable

B) What is the hard drive size of the computer?

The answer is a number, so it is a quantitative variable.

C) Is the computer a laptop or a desktop model?

The possible answers are: yes or no, so it is a categorical variable

D) How much does the computer cost?

The answer is a number, so it is a quantitative variable.

Answer:

-5 and -The zeros of a parabola are the points on the parabola that intersect the line y = 0 (the horizontal x-axis). Since these points occur where y = 0,

Using the z-distribution, it is found that a sample size of 1066 is required.

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which z is the z-score that has a p-value of .

The margin of error is:

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

From the previous study, the estimate is of 0.23, hence \(\pi = 0.23\).

98% confidence level, hence\(\alpha = 0.98\), z is the value of Z that has a p-value of \(\frac{1+0.98}{2} = 0.99\), so \(z = 2.327\).

The sample size is n for which M = 0.03, hence:

\(M = z\sqrt{\frac{\pi(1-\pi)}{n}}\)

\(0.03 = 2.327\sqrt{\frac{0.23(0.77)}{n}}\)

\(0.03\sqrt{n} = 2.327\sqrt{0.23(0.77)}\)

\(\sqrt{n} = \left(\frac{2.327\sqrt{0.23(0.77)}}{0.03}\right)\)

\((\sqrt{n})^2 = \left(\frac{2.327\sqrt{0.23(0.77)}}{0.03}\right)^2\)

\(n = 1065.5\)

Rounding up, a sample size of 1066 is required.

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\( \sqrt{ \frac{1 - cos(150)}{2} } = \sqrt{ \frac{1}{2} - \frac{cos(150)}{2} } = \sqrt{ \frac{1}{2} - \frac{ \frac{ - \sqrt{ 3}}{2} }{2} } = \sqrt{ \frac{2}{4} + \frac{ \sqrt{3} }{4} } = \sqrt{ \frac{2 + \sqrt{3} }{4} } \)

\(= \frac{ \sqrt{6} + \sqrt{2} }{4} \)

BTW:

\(sin(75) = \frac{ \sqrt{6} + \sqrt{2} }{4} \)

\( = > sin(75) = \sqrt{ \frac{1 - cos(150)}{2} } \)

Ans: True

Ok done. Thank to me >:33

Approximately 138.3 grams of the compound will remain after 8 hours. The decay of a radioactive compound is an exponential process, which can be modeled by the equation:

N(t) = N₀ * e^(-λt)

where N(t) is the amount of the compound remaining at time t, N₀ is the initial amount of the compound, λ is the decay constant, and e is the mathematical constant known as Euler's number.

To find the amount of the compound remaining after 8 hours, we need to plug in the given values into the equation above. We know that the initial mass of the compound is 260 grams, and the decay rate is 3.8% per hour, which means that the decay constant λ is equal to 0.038. Therefore, the equation becomes:

N(8) = 260 * e^(-0.038 * 8)

Simplifying this equation gives:

N(8) = 260 * e^(-0.304)

N(8) ≈ 138.3 grams

Therefore, approximately 138.3 grams of the compound will remain after 8 hours.

It's important to note that this calculation assumes that the decay rate remains constant over time, which may not always be the case in reality. Additionally, the actual amount of the compound remaining may vary due to experimental error or other factors.

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Answer:

یه گل یک گل بام میی مه فیلم بام حس بام حس فمس یکم باشگاه هی یک گل یه حس سیم هی فکریه خشک پیل هر یک حس صب زی صب هم گچ نی بلن هر بر قل هم بی دو حس قیین

Step-by-step explanation:

سبک حس بام نی شیک حس

یا کمی سیم حس او

نی یک حس بکشم یک حس بام نی که خیلی تنیام که اما الا دیه انجام نمییم ای موضوع که دعوا خیلی تخفیف خیلی خوعه ای موضوع که اما الا دیمش خوش

۳ خشک هی یک هی بام نی با که اما ۷غ هه بام نی بلن کف بام نی بکر

به نمییم هی بام میی لاک حس بام

بلن هی یک

حالم ای زبونه فراموش که

فخ بیم فک

Answer:

yes

Step-by-step explanation:

half of $798 is $399. $100 a week × 4 = $400. 400 is very close to 399, so yes it would be a food estimate. Hope this helps! :)

Answer:

466.2

Step-by-step explanation:

=(87-24)×7.4

=63×7.4

=466.2

Answer:

Happy Friday

Step-by-step explanation:

Answer:

I NEED BRAINLIST URGENTLY

Your answer is y= 4 sin 7 square

Hope that this is helpful. Tap the crown button, Mark my answer as............. BRAINLIST......... Like & Follow me to get more answer.

The domain is the set of all values of x on the horizontal axis that satisfies the function. It is between the lowest value on the left and the highest value on the right. We can see that the graph extends to negative infinity on the left and positive infinity on the right. Thus.

Domain = - infinity < x < infinity

The range is the set of all values of y on the vertical axis that satisfies the function. It is between the lowest value at bottom and the highest value at the top. We can see that the graph extends from 2 at the bottom to positive infinity at the top. Thus.

Range = y > 2

To find the height of the cylinder when the volume is given as 1500 in³ and the radius is 7 inches, we can use the formula for the volume of a cylinder:

Volume = π * r² * h

Substituting the given values, we have:

\(1500 = 3.14 * 7^2 * h1500 = 3.14 * 49 * h1500 = 153.86 * h\)

To solve for h, we divide both sides of the equation by 153.86:

h = 1500 / 153.86

h ≈ 9.75

Rounding the answer to the nearest hundredth, the height of the cylinder is approximately 9.75 inches.

Therefore, the height of the cylinder is 9.75 inches.

Note: It is important to use the accurate value of π, which is approximately 3.14159, for precise calculations. However, in this case, since you specified to use 3.14 for π, I have used that approximation to calculate the height.

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Answer:

c = 8

Step-by-step explanation:

Using the Intersecting Chords Theorem, we can form the following equation and solve for c:

\(ab=cd\\(10)(8.8)=11c\\88=11c\\c=8\)

so the idea being, we have a system of equations of two variables and 4 equations, each one rendering a line, for this case these aren't equations per se, they're INEquations, so pretty much the function will be the same for an equation but we'll use > or < instead of =, but fairly the function is basically the same, the behaviour differs a bit.

we have a line passing through (-6,0) and (0,8), side one

we have a line passing through the x-axis and -6, namely (-6,0) and the y-axis and -4, namely (0,-4), side two

we have a line passing through (0,-4) and (6,4), side three

now, side four is simply the line connecting one and three.

the intersection of all four lines looks like the one in the picture below, so what are those lines with their shading producing that quadrilateral?

well, we have two points for all four, and that's all we need to get the equation of a line, once we get the equation, with its shading like that in the picture, we'll make it an inequality.

\((\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{8 -0}{0 +6} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = \cfrac{4}{3} ( x +6) \\\\\\ y=\cfrac{4}{3}x+8\hspace{5em}\stackrel{\textit{side one} }{\boxed{y < \cfrac{4}{3}x+8}}\)

\(\rule{34em}{0.25pt}\\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 -0}{0 +6} \implies \cfrac{ -4 }{ 6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = - \cfrac{2}{3} ( x +6) \\\\\\ y=-\cfrac{2}{3}x-4\hspace{5em}\stackrel{\textit{side two} }{\boxed{y > -\cfrac{2}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{4 +4}{6 -0} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{0}) \implies y +4 = \cfrac{4}{3} ( x -0) \\\\\\ y=\cfrac{4}{3}x-4\hspace{5em}\stackrel{ \textit{side three} }{\boxed{y > \cfrac{4}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\((\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{6}}} \implies \cfrac{ 4 }{ -6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \\\\\\ y=-\cfrac{2}{3}x+8\hspace{5em}\stackrel{ \textit{side four} }{\boxed{y < -\cfrac{2}{3}x+8}}\)

now, we can make that quadrilateral a trapezoid by simply moving one point for "side four", say we change the point (0 , 8) and in essence slide it down over the line to  (-3 , 4).  Notice, all we did was slide it down the line of side one, that means the equation for side one never changed and thus its inequality is the same function.

now, with the new points for side for of (-3,4) and (6,4), let's rewrite its inequality

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{4 -4}{6 +3} \implies \cfrac{ 0 }{ 9 } \implies 0\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ 0}(x-\stackrel{x_1}{(-3)}) \implies y -4 = 0 ( x +3) \\\\\\ y=4\hspace{5em}\stackrel{ \textit{side four changed} }{\boxed{y < 4}}\)

Answer:

10 $1 bills

7 $5 bills

Step-by-step explanation:

Let s = number of $1 bills.

Let f = number of $5 bills.

1s + 5f = 45

s = f + 3

f + 3 + 5f = 45

6f = 42

f = 7

s = f + 3 = 7 + 3 = 10

10 $1 bills

7 $5 bills

Answer: \(\frac{1}{4}\)

Step-by-step explanation:

use probability

the chances of you getting heads on a coin is 50% therefore, flipping two coins is just

\(\frac{1}{2} * \frac{1}{2}= \frac{1}{4}\)

Answer:

the probability of getting two heads is 1/4

Step-by-step explanation:

H = (HH) => n(H) = 1

n(S) = 4

P(E) = number of favourable outcomes/total number of outcomes = n(E) / n (S)

PH = n(H)/n(S)

= 1/4