Answers
Answer:
A chemical reaction is a process where bonds are formed between reactant elements causing interaction hence products are formed.
The two types of chemical reaction:
\({ \boxed{ { \rm{ \bold{ \dashrightarrow \: reversible \: reaction}}}}}\)
This is a reaction where reactants interact chemically to form respective products and also products can react to reverse the reaction (to form reactants).
An example of reaction of hydrogen and oxygen:
\({ \rm{2H_{2(aq)} +O_{2(aq)} \: {}{ ^{ \dashrightarrow}_{ \dashleftarrow} \: 2H _{2}O _{(l)} }}}\)
\({ \boxed{ \rm{ \bold{ \dashrightarrow irreversible \: reaction}}}}\)
It is a one way reaction, cannot be reversed
\({ \rm{Mg_{(s)} + N _{2(g) \: }\rightarrow \: \: Mg _{3} N _{2(s)} }}\)
Related Questions
2. Which of the following conclusions
geologists draw about a limestone rock layer
based on the law of superposition?
A. The limestone is 2 million years old.
B. The limestone contains 2 million fossils.
C. The limestone is younger than the
sandstone below it.
D. The limestone is the same age as another
layer 100 kilometers away.
ar
Answers
Based on the law of superposition, geologists can conclude that the limestone rock layer is younger than the sandstone layer below it.
This is because the law of superposition states that in an undisturbed sequence of rock layers, the oldest layer is at the bottom and the youngest layer is at the top. Therefore, since the sandstone layer is found below the limestone layer, it must be older.
The age of the limestone layer itself cannot be determined solely based on the law of superposition. While geologists can infer that the limestone layer is younger than the underlying sandstone layer, they would need to use other methods such as radiometric dating to determine the actual age of the rock layer.
Similarly, the presence of fossils in the limestone layer cannot be determined based solely on the law of superposition. While it is possible that the limestone layer may contain fossils, this would need to be confirmed through further investigation and analysis.
The age of another layer 100 kilometers away also cannot be determined solely based on the law of superposition. While the law of superposition can provide information about the relative ages of rock layers within a local area, it cannot be used to compare the ages of rock layers in different locations.
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Write the chemical formula for this molecule
Answers
Using the volumes of sodium thiosulfate solution you just entered, the mass of bleach sample, and the average molarity of the sodium thiosulfate solution entered earlier, calculate the mass percent of NaClO for each bleach sample. Enter the calculated mass percent of NaClO in each of the 3 acceptable trials (For the first trial, the volume of sodium thiosulfate =10.1, mass of bleach is 0.496g, and average molarity of sodium thiosulfate=0.042M)
Answers
Answer:
3.18 (w/w) %
Explanation:
In the problem, you can find mass of NaClO knowing the reaction of NaClO with Na₂S₂O₃ is:
NaClO + 2Na₂S₂O₃ + H₂O → NaCl + Na₂S₄O₆ +2NaOH + NaCl
Where 1 mole of NaClO reacts with 2 moles of Na₂S₂O₃
Moles of thiosulfate in the titration are:
0.0101L ₓ (0.042mol / L) = 4.242x10⁻⁴ moles of Na₂S₂O₃
Thus, moles of NaClO in the initial solution are:
4.242x10⁻⁴ moles of Na₂S₂O₃ ₓ (1mol NaClO / 2 mol Na₂S₂O₃) = 2.121x10⁻⁴ moles NaClO
As molar mass of NaClO is 74.44g/mol, mass of 2.121x10⁻⁴ moles are:
2.121x10⁻⁴ moles ₓ (74.44g / mol) = 0.0158g of NaClO
As mass of bleach is 0.496g, mass percent is:
0.0158g NaClO / 0.496g bleach ₓ 100 =
3.18 (w/w) %. The atomic number of a newly discovered element is found to be 128, and its mass number is 279.
How many protons, neutrons, and electrons are found in an ion of this element bearing a charge of
5−?
Answers
A-128
P-128
E-128
M-279
A-128
N-151
Hope this strategy helps
If an experiment produces 5 g but should have made 500 g, what is the percent
yield?
Answers
Answer:
Percentage of yield = 1%
Explanation:
Given:
Amount of yield = 5g
Total amount of product = 500 gram
Find:
Percentage of yield = ?
Computation:
⇒ Percentage of yield = [Amount of yield / Total amount of product]100
⇒ Percentage of yield = [5g / 500g]100
⇒ Percentage of yield = [0.01]100
⇒ Percentage of yield = 1%
1. The names of the known elements fall into one of eight categories. List these 8 categories
(a. through h.)
Answers
It is divided into 2 blocks one is s-block and another is p-block .
Here are first 20 known elements .
\(\boxed {\begin{array}{|c|c|c|c|cccc|}\cline {1-8}\sf Element & \sf Symbol & \sf Valency & \sf{Atomic\:Number} & & \sf{Electron} & \sf Configuration & \\ \cline {5-8} &&&&\bf K&\bf L &\bf M&\bf N \\ \cline {1-8}\rm Hydrogen &\sf H & 1 & 1 & 1 &&& \\ \cline {1-8}\rm Helium &\sf He & 0 & 2 & 2 &&& \\ \cline {1-8}\rm Lithium &\sf Li & 1& 3 &2 &1 && \\ \cline {1-8}\rm Beryllium &\sf Be & 2 & 4 & 2 & 2 && \\ \cline {1-8}\rm Boron &\sf B & 3 & 5 & 2 & 3 && \\ \cline {1-8}\rm Carbon & \sf C & 4 & 6 & 2 & 4 && \\ \cline {1-8}\rm Nitrogen &\sf N & 3 & 7 & 2 & 5 && \\ \cline {1-8}\rm Oxygen &\sf O & 2 & 8 & 2 & 6 && \\ \cline {1-8}\rm Fluorine &\sf F & 1 & 9 & 2 & 7 && \\ \cline {1-8}\rm Neon & \sf Ne & 0 & 10 & 2 & 8 && \\ \cline {1-8}\rm Sodium &\sf Na & 1 & 11 & 2 & 8 & 1 &\\ \cline {1-8}\rm Magnesium &\sf Mg & 2 & 12 & 2 & 8 & 2 & \\ \cline {1-8}\rm Aluminium &\sf Al & 3 & 13 & 2 & 8 & 3 & \\ \cline{1-8}\rm Silicon &\sf Si & 4 & 14 & 2 & 8 & 4 & \\ \cline {1-8}\rm Phosphorus &\sf P & 3 & 15 & 2 & 8 & 7 & \\ \cline {1-8}\rm Sulphur &\sf S & 2 & 16 & 2 & 8 & 8 & \\ \cline{1-8}\rm Chlorine &\sf Cl & 1 & 17 & 2 & 8 & 8 &1 \\ \cline {1-8}\rm Argon &\sf Ar & 0 & 18 & 2 & 8 & 8 & 2 \\ \cline {1-8}\rm Potassium &\sf K & 1 & 19 & 2 & 8 & 8 &3 \\ \cline {1-8}\rm Calcium &\sf Ca & 2 & 20 & 2 & 8 & 8 & 4 \\ \cline{1-8} \end {array}}\)
how many pi bonds does a triple bond has
Answers
Answer:
A triple bond have two pi bonds.
Explanation:
This is an alkaline that contains one sigma bond and two pi bonds.
Hope my answer helps.
Answer:
Two
Explanation:
The chemical formula for hydrogen chloride is HCl A chemist determined by measurements that moles of hydrogen chloride participate in a chemical reaction. Calculate the mass of hydrogen chloride that participates. Be sure your answer has the correct number of significant digits.
Answers
The question is incomplete, the complete question is;
. A chemist determined by measurements that 0.015 moles of hydrogen chloride participate in a chemical reaction. Calculate the mass of hydrogen chloride that participates Round your answer to 2 significant digits. x S. ?
Answer:
0.54 g
Explanation:
Recall that;
Number of moles = mass/molar mass
Molar mass of HCl =36.5 g/mol
Mass= number of moles × molar mass
Mass= 0.015 moles × 36 g/mol
Mass= 0.54 g
Given 2.37 mol of calcium, how much (in g) would it weigh? Include the proper units
and significant digits.
Answers
= (2.37)(40.08)
=94,99g
a. Using the Born-Mayer Equation, calculate the lattice enthalpy for sphalerite
(zinc blende), ZnS. You must look up the appropriate parameters for the equation.
b. Using the Born-Mayer Equation, calculate the lattice enthalpy for wurtzite, ZnS. You must
look up the appropriate parameters for the equation.
c. Which is thermodynamically stable at ambient conditions (25 °C, 1 bar)? Find a reference
with the T and P phase diagram for ZnS. Submit the pdf of the reference with your file . Also,
compare your answer to the standard enthalpies of formation for wurtzite compared to sphalerite.
Answers
ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite. Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials.
Remember that when a metal reacts with a nonmetal, often an ionic compound results from the transfer of electrons form the metal (the reductant) towards the nonmetal (the oxidant). Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials. They melt at rather high temperatures and are not easily distorted. ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.
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Define biotechnology. } List two advantages in the use of biotechnology
Answers
Advantages of biotechnology:
Improvement of plants and animal breeds to give a high yield of their products.
Pests and pathogen control in agriculture which will reduce the loss of yield in food crops.
Synthesis of biocatalyst which can be used for enhancing the reactions which can be carried out in vitro or laboratory conditions.
Sewage treatment or water recycling can be done with the help of transgenic microbes which have better efficiency and speed.
Biotechnology is the use of living organisms or other biological systems in the manufacture of drugs or other products or for environmental management, as in waste recycling: includes the use of bioreactors in manufacturing, microorganisms to degrade oil slicks or organic waste, genetically engineered bacteria to produce human hormones, and monoclonal antibodies to identify antigens.
Biotech offers the possibility of improving human health, the environment, and agriculture while creating more sustainable modes of production.
.Place the 250kg weight on the left side of the tank. Record the reading of
the gauge on the left side:
gauge on the right side:
Explain your results.
kPa. Record the reading of the
kPa. Compare the 2 readings. Explain your results.
Answers
The measurement of pressure is the assessment of the force that a fluid has applied to a surface. Usually, pressure is expressed as a force per unit of surface area.
Explain your results.
9.67 kg
Absolute pressure is equal to 43 atm gauge pressure.
p1 = 4.46 MPa = 44 atm
Absolute pressure is 30.4 atm if the gauge pressure is 29.4 atm.
p2 = 3.08 MPa/30.4 atm
The formula for the ideal gas state is
p * V = m * R * T
For these two instances, we can put up two equations.
p1* V1 = m1 * R * T1
p2* V2 = m2 * R * T2
V1 = V2, and T1 = T2 because
p1 = m1 * R and p2 = m2 * R
Rearranging
R = p1 / m1 and R = p2 / m2
Equating:
p1 / m1 = p2 / m2
m2 = m1 * p2 / p1
m2 = 14 * 3.08 / 4.46 = 9.67 kg
The gauge pressure, or the difference between inner and outside pressure, is recorded by the pressure gauge on a tank. The oxygen (O2) tank holds 14.0 kg of the gas at a gauge pressure of 43.0 atm when it is fully filled. When the pressure reading is 29.4 atm, calculate the mass of oxygen that has been removed from the tank. Assume that the tank's temperature stays constant.
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Explain how the elimination of a predator from an ecosystem might result in starvation amongst its prey species.
Answers
Answer:
If the primary predator of a prey species is eliminated, the prey species’ population will increase to the point of overpopulating the ecosystem. This overpopulation will result in depletion of the prey species’ food supplies as more individuals compete for the same resources and can ultimately lead to the prey species starving.
Explanation:
Elimination of a predator from an ecosystem might lead to famine amongst its prey species because:
the populations of the prey species thrive in the absence of selective pressure by the predatorthe thriving of the populations will put pressure on the available food resources for the prey species leading to significant intra-species competition.available foods might eventually get depleted as population and competition surge.food depletion means the population may end up dying of hunger if the status quo remains.More on food webs can be found here: https://brainly.com/question/2233704?referrer=searchResults
Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
Answers
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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What is the percent composition of oxygen in lithium oxide?
Answers
Answer: 72.71%
Explanation:
Which statement is also true of the rearrangement of atoms
Answers
Answer:
In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants. When a new substance is formed, the change is called a chemical change.
Explanation:
Answer:what
Explanation:
For each of these pairs of half-reactions, write the balanced equation for the overall cell reaction and calculate the standard cell potential. Express the reaction using cell notation. You may wish to refer to Chapter 20 to review writing and balancing redox equations.
1.
Pt2+(aq)+2e-Pt(s)
Sn2+(aq)+2e-Sn(s)
2.
Co2+(aq)+2e-Co(s)
Cr3+(aq)+3e-Cr (s)
3.
Hg2+(aq)+2e-Hg (I)
Cr2+(aq)+2e-Cr (s)
please help out
Answers
1. For the pair of half-reactions:
Pt2+(aq) + 2e- → Pt(s) ... (1)
Sn2+(aq) + 2e- → Sn(s) ... (2)
To obtain the balanced equation for the overall cell reaction, we need to multiply the half-reactions by appropriate coefficients to ensure that the number of electrons transferred is equal. In this case, we can multiply equation (1) by 2 and equation (2) by 1:
2(Pt2+(aq) + 2e-) → 2(Pt(s))
Sn2+(aq) + 2e- → Sn(s)
Combining the equations, we have:
2Pt2+(aq) + Sn2+(aq) → 2Pt(s) + Sn(s)
The cell notation for this reaction is:
Pt2+(aq) | Pt(s) || Sn2+(aq) | Sn(s)
To calculate the standard cell potential (E°), we need to know the standard reduction potentials for Pt2+/Pt(s) and Sn2+/Sn(s) half-reactions. Referring to standard reduction potential tables, we find:
E°(Pt2+/Pt(s)) = +1.20 V
E°(Sn2+/Sn(s)) = -0.14 V
The overall cell potential (E°cell) is the difference between the reduction potentials:
E°cell = E°(cathode) - E°(anode) = 0.00 V - (-0.14 V) = +0.14 V
Therefore, the standard cell potential for this reaction is +0.14 V.
2. For the pair of half-reactions:
Co2+(aq) + 2e- → Co(s) ... (3)
Cr3+(aq) + 3e- → Cr(s) ... (4)
To balance the number of electrons transferred, equation (4) can be multiplied by 2:
2(Co2+(aq) + 2e-) → 2(Co(s))
Cr3+(aq) + 3e- → Cr(s)
Combining the equations, we have:
2Co2+(aq) + Cr3+(aq) → 2Co(s) + Cr(s)
The cell notation for this reaction is:
Co2+(aq) | Co(s) || Cr3+(aq) | Cr(s)
To calculate the standard cell potential (E°), we refer to the standard reduction potentials:
E°(Co2+/Co(s)) = -0.28 V
E°(Cr3+/Cr(s)) = -0.74 V
The overall cell potential (E°cell) is the difference between the reduction potentials:
E°cell = E°(cathode) - E°(anode) = -0.74 V - (-0.28 V) = -0.46 V
Therefore, the standard cell potential for this reaction is -0.46 V.
3. For the pair of half-reactions:
Hg2+(aq) + 2e- → Hg (l) ... (5)
Cr2+(aq) + 2e- → Cr(s) ... (6)
The equation for the overall cell reaction can be obtained by multiplying equation (6) by 2:
2(Hg2+(aq) + 2e-) → 2(Hg (l))
Cr2+(aq) + 2e- → Cr(s)
Combining the equations, we have:
2Hg2+(aq) + Cr2+(aq) → 2Hg (l) + Cr(s)
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A water treatment tablet contains 20.0 mg of tetraglycine hydroperiodide, 40.0% of which is available as soluble iodine. If two tablets are used to treat 1.00 liter of drinking water, what is the concentration in ppm of iodine in the treated water
Answers
Answer:
\(16\ \text{ppm}\)
Explanation:
Mass of one tablet = 20 mg
Mass of two tablets = \(2\times 20=40\ \text{mg}\)
Percent that is soluble in water = 40%
Mass of tablet that is soluble in water = \(0.4\times 40=16\ \text{mg}\)
So, mass of solute is \(16\ \text{mg}\)
Density of water = 1 kg/L
Volume of water = 1 L
So, mass of 1 L of water is \(1\times 1=1\ \text{kg}=1000\ \text{g}\)
PPM is given by
\(\dfrac{\text{Mass of solute}}{\text{Mass of solvent}}\times 10^6=\dfrac{16\times 10^{-3}}{1000}\times 10^6\\ =16\ \text{ppm}\)
Hence, the concentration of iodine in the treated water \(16\ \text{ppm}\).
1 3.1.2
Question 1 of 10
Which of the following notations is the correct noble gas configuration for Sr?
A. [Kr]452
O B. [Ar]452
O C. [Ar]552
D. [kr]552
SUBMIT
Answers
Answer: (Kr) 5s2
Explanation:
Apex
How old is a piece of wood that has 0.7813% of the carbon-14 of a living organism
Answers
Answer:
About 21*.3 years old
Explanation:
Guysss how to explain nuclear chemistry? And define nuclear chemistry ?
Answers
Answer:
How do amoeba respire.
Define Diffusion.
How many calories are in 7501 J ? (1 cal = 4.184 J)
Answers
There are different forms of energy on earth. The sun is considered as the elemental form of energy on earth. It is a quantitative property which can be transferred from an object to do work. The amount of calories in 7501 J is 1792.7 calories.
The ability to perform work is defined as the energy. The law of conservation of energy states that energy can neither be created nor be destroyed. The SI unit of energy is Joule.
Here joule is a derived unit equal to the energy expended in applying a force of 1N through a distance of 1m.
1 cal = 4.184 J
7501 J = 1792.7 calories
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Silver ion can be used to gravimetrically analyze Br- ion. Calculate the gravimetric factor for Br- using silver bromide. Please show how to do so as well.
Answers
The gravimetric factor for Br- using silver bromide is 0.425.
What is the gravimetric factor?The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.
It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.
Gravimetric factor = formula mass of substance weight / formula mass of substance soughtFor example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol
Formula mass of bromide ion = 80 g/mol
Gravimetric factor = 80/1188
Gravimetric factor = 0.425
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g 8. A hydrogen atom is initially a rest and in the ground state. A proton with kinetic energy 1000 eV scatters off the atom. In the process the hydrogen atom is ionized. The kinetic energy of the ionized electron is measured to be 15.2 eV and the kinetic energy of the proton produced from the ionization of hydrogen is 4.3 eV. What would be the final kinetic energy of the projectile proton after the collision
Answers
Answer:
Explanation:
Ionization energy of hydrogen atom is 13.6 eV . This energy will be provided by energetic proton , the kinetic energy of which is 1000 eV. The kinetic energy of ionized electron is 15.2 eV . Kinetic energy of proton produced from from the ionization of hydrogen or the nucleus of the hydrogen atom is 4.3 eV . All these energy must have come from kinetic energy of initial proton.
So kinetic energy of projectile proton after collision
= 1000 - ( 13.6 + 15.2 + 4.3 ) eV.
= 966.9 eV .
I'm making a AD for my special ed class room and I am interviewing people. Make 10 unique questions I can ask my fellow classmates about the things they have learned in this room.
Answers
These are 10 unique questions you can ask your fellow classmates about the things they have learned in your special ed classroom:
What is your favorite thing about our classroom?What is one thing you have learned in our classroom that you will never forget?What is one thing you would like to learn more about in our classroom?How has our classroom helped you to succeed?What is one thing you would like to say to your teacher?What is one thing you would like to say to your classmates?What is one thing you would like to say to your parents?What is one thing you would like to say to the world?What is your dream for the future?What is one thing you are grateful for?What are special ed classroom?A special education classroom is a classroom designed to meet the needs of students with disabilities. These classrooms are staffed by specially trained teachers who are able to provide individualized instruction and support to students with a variety of disabilities.
These questions are designed to get your classmates thinking about the things they have learned in your special ed classroom and how those things have impacted them. The answers to these questions can be used to create a powerful and informative ad for your classroom.
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The Carbon-14 content of an ancient piece of wood was found to be one eighth of that in living trees. How old is this piece of wood assuming the half-life of Carbon-14 is 5770 years.
Answers
Answer:
its 5770 yrs old
Explanation:
The undersea mountain chain where magma rises from and where new ocean floor is produced is called?
Answers
Answer:
mid-ocean ridges
Explanation:
Seafloor spreading occurs along mid-ocean ridges—large mountain ranges rising from the ocean floor.
Sodium hydroxide, NaOHNaOH; sodium phosphate, Na3PO4Na3PO4; and sodium nitrate, NaNO3NaNO3, are all common chemicals used in cleanser formulation. Rank the compounds in order from largest mass percent of sodium to smallest mass percent of sodium. Rank from largest mass percent to smallest mass percent. To rank items as equivalent, overlap them.
Answers
Answer:
NaOH > Na3PO4 > NaNO3
Explanation:
in NaOH
23/40 * 100 = 57.5%
in Na3PO4
3 * 23/164 * 100 = 42%
In NaNO3
23/85 * 100 = 27.1%
Hence;
NaOH > Na3PO4 > NaNO3
I need help in this:(
Answers
Answer:
Phosphorus(P) and Oxygen(O)=Covalent bond
Chlorine(Cl) and Sodium(Na) = Ionic bond
Silver (Ag) and Silver (Ag)= Metallic bond
Phosphorus and Oxygen would be covalent bonding
Chlorine and sodium would be ionic bonding.
#6
For a particular redox reaction, MnO2 is oxidized to MnO−4
and Ag+ is reduced to Ag. Complete and balance the equation for this reaction in basic solution. Phases are optional.
balanced redox reaction:
MnO_{2} + Ag^{+} -> MnO_{4}^{-} +Ag^{+}
MnO2+Ag+⟶MnO−4+Ag+
Answers
The balanced redox equation is \(2MnO_2 + 4Ag+ + 4H+\) → \(2MnO^{-4} + 4Ag + 2H_2O.\)
A balanced redox reaction refers to a chemical reaction that involves oxidation and reduction and has balanced charges and atoms on both sides of the reaction equation.
In a balanced redox reaction, the oxidation and reduction reactions take place simultaneously, with the oxidation of the reducing agent leading to the reduction of the oxidizing agent, hence balancing the electrons and charges on both sides of the equation.
The balanced redox reaction of \(MnO_2+Ag^+\)⟶\(MnO^{-4}+Ag+\) is as follows:
\(2MnO_2 + 4Ag+ + 4H+\) → \(2MnO^{-4} + 4Ag + 2H_2O\)
The reaction involves the oxidation of \(MnO_2\)to \(MnO^{-4}\)and the reduction of Ag+ to Ag. The\(MnO_2\) acts as the reducing agent while Ag+ acts as the oxidizing agent. The reaction takes place in an acidic medium with H+ ions.
The electrons involved in the reduction and oxidation reactions are balanced, and the charges on both sides of the equation are equal.
In summary, the balanced redox reaction of \(MnO_2+Ag+\)⟶\(MnO^{-4}+Ag+\) is a chemical reaction that involves oxidation and reduction of the reactants to produce products that have equal charges and atoms on both sides of the equation.
The balanced redox equation is \(2MnO_2 + 4Ag+ + 4H+\)→ \(2MnO^{-4} + 4Ag + 2H_2O.\)
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