Explanation:
conjugated base is substance formed when an acid loses
a hydrogen ion.
conjugated acid is a type of acid that is formed when a base accepts a proton in solution
the answer choices could be more than one. Kindly help me provide the right choice(s).
The correct categorization of the solutions is:a. KCl - Neutral
b. ZnCl2 - Acidic
c. Ba(C2H3O2)2 - Basic
d. NH4I - Acidic
e. NaNO3 - Neutral
To determine whether a 0.5M solution of each salt is acidic, basic, or neutral, we need to analyze the nature of the ions present in the solution.
a. KCl: When KCl is dissolved in water, it dissociates into K+ and Cl- ions. Both K+ and Cl- are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.
b. ZnCl2: When ZnCl2 is dissolved in water, it dissociates into Zn2+ and 2Cl- ions. The presence of Zn2+ ions in the solution can hydrolyze water molecules, resulting in the formation of H+ ions. Therefore, the solution is acidic.
c. Ba(C2H3O2)2: When Ba(C2H3O2)2 is dissolved in water, it dissociates into Ba2+ and 2C2H3O2- ions. The acetate ions (C2H3O2-) can hydrolyze water, leading to the formation of OH- ions. Therefore, the solution is basic.
d. NH4I: When NH4I is dissolved in water, it dissociates into NH4+ and I- ions. The presence of NH4+ ions in the solution can undergo a weak hydrolysis, resulting in the formation of H+ ions. Therefore, the solution is acidic.
e. NaNO3: When NaNO3 is dissolved in water, it dissociates into Na+ and NO3- ions. Both Na+ and NO3- ions are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.
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`Pb(NO3)2 (aq) + LiBr(aq) →
Answer:
PbBr2 + LiNO3
And goodluck
in the citric acid cycle (see the figure), beginning with one molecule of isocitrate and ending with fumarate, how many atp molecules can be made through substrate-level phosphorylation?
In the citric acid cycle , beginning with one of the molecule of isocitrate and ending with the fumarate, the ATP molecules can made through the substrate-level phosphorylation is one molecule.
In the citric acid cycle, the substrate level phosphorylation is the high energy of the phosphate group in the organic molecule. it transfers to the ADP to produces the ATP. it is the metabolic reaction and form the ATP molecules. The citric acid cycle is called as Krebs cycle also.
Thus, the number of ATP molecules form during the citric acid cycle that start with the one molecule of the isocitrate and end with the fumarate is the one molecule.
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what properties of a natural resource make it useful for humans as a materials or energy source?
The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.
What are natural resources?The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.
Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.
Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.
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A solution made from pure Potassium hydroxide contained 1.85 g of Potassium hydroxide in exactly 200 cm3 of water. Using phenolphthalein indicator, titration of 20.0 cm3 of this solution is carried out v/s sulphuric acid. 9.35 cm3 of sulphuric acid solution is required for complete neutralisation. [atomic masses: K= 39, O = 16, H = 1]
(a) write the equation for the titration reaction.
(b) calculate the molarity of the Potassium hydroxide solution. (c) calculate the moles of Potassium hydroxide neutralised. (d) calculate the moles of sulphuric acid neutralised.
(e) calculate the molarity of the sulphuric acid.
The concentration of H2SO4 is 0.176 M. The number of moles of H2SO4 is 0.0165 moles.
The equation of the reaction is;
2KOH(aq) + H2SO4(aq) ------> K2SO4(aq) + H2O(l)
The number of moles of KOH = 1.85 g/56 g/mol = 0.033 moles
concentration = number of moles /volume
volume = 200 cm3 or 0.2 L
concentration of KOH = 0.033 moles/0.2 L = 0.165 M
From the titration formula;
CAVA/CBVB =na/nb
CA = concentration of acid
VA = volume of acid
CB = concentration of base
VB = volume of base
na = number of moles of acid
nb = number of moles of base
Making CA the subject of formula;
CA = CBVBna/VAnb
CA = ?
CB = 0.165 M
VA = 9.35 cm3
VB = 20.0 cm3
na = 1
nb =2
CA = CBVBna/VAnb
CA = 0.165 M × 20.0 cm3 × 1/9.35 cm3 × 2
CA = 0.176 M
The concentration of sulphuric acid is 0.176 M
From the reaction equation;
2 moles of KOH reacts with 1 mole of H2SO4
0.033 moles of KOH reacts with 0.033 moles × 1 mole/2 moles
= 0.0165 moles of H2SO4
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A car's engine block is made of steel and has a mass of 21080g. How much heat (J) is absorbed by the engine block when its temperature is raised from 20°C to 90°C?
The heat absorbed by the engine block when its temperature is raised from 20°C to 90°C is 665,640 J.
To calculate the heat absorbed by the engine block, we can use the equation:
Q = mcΔT
where Q is the heat absorbed, m is the mass of the engine block, c is the specific heat capacity of steel, and ΔT is the change in temperature.
First, we need to calculate the specific heat capacity of steel. The specific heat capacity of steel is typically around 0.45 J/g°C.
Using this value and the given values of mass and temperature change, we can calculate the heat absorbed by the engine block as follows:
Q = (21080 g) x (0.45 J/g°C) x (90°C - 20°C)
Q = 21080 g x 0.45 J/g°C x 70°C
Q = 665,640 J
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If salt water has a density of 1.2 g/mL, which object listed below would SINK? *
Object 1 with a density of 1.14 g/cm3
Object 3 with a density of 1.62 g/cm3
Object 4 with a density of 0.8 g/cm3
Object 2 with a density of 0.92 g/cm3
-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:
6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.
Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.
Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:
(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))
The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:
(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol
Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.
Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.
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45g of COz gas has a pressure of 1.24 ATM in a container at 43°C. What is the volume of the gas?
The volume of the CO2 gas is approximately 21.0 L.
To solve this problemWe can use the ideal gas law equation
\(PV = nRT\)
where
P is the pressureV is the volumen is the amount of gas (in moles)R is the gas constantT is the temperature (in Kelvin)We need to convert the temperature from Celsius to Kelvin:
T = 273 + 43 = 316 K
Next, we can calculate the amount of gas (n) using the mass of CO2 and its molar mass:
n = m/M
where m is the mass of the gas and M is the molar mass of CO2.
Molar mass of CO2 = 12.01 + 2(16.00) = 44.01 g/mol
n = 45 g / 44.01 g/mol = 1.022 mol
Now we can rearrange the ideal gas law to solve for the volume:
V = nRT/P
V = (1.022 mol)(0.0821 L·atm/mol·K)(316 K)/(1.24 atm)
V = 21.0 L
Therefore, the volume of the CO2 gas is approximately 21.0 L.
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Name something that has zero thermal energy.
Answer:
When all molecules in a system stop moving completely, there is zero thermal energy
Explanation:
It is impossible to reach though
please help due in 1 hour. This is 7th grade science. & in return I’ll help you on something! 15 points
Answer: MCCCMC
Please. Mark as brainliest
vodka from the european union must be at least 37.5% alcohol by volume or 75 proof. The density of water is 1.00 g mL^-1 and the density of ethanol is 0.789 g mL ^-1
What is the mole fraction of alcohol in vodka?
What is the molarity of alcohol in vodka?
Answer:
To calculate the mole fraction of alcohol in vodka, we need to know the volume fraction of alcohol in vodka, since ethanol and water have different densities.
75 proof vodka means it contains 37.5% ethanol by volume. So for 100 mL of vodka, there are 37.5 mL of ethanol and 62.5 mL of water.
The mass of 37.5 mL of ethanol is:
37.5 mL * 0.789 g/mL = 29.5875 g
The mass of 62.5 mL of water is:
62.5 mL * 1.00 g/mL = 62.5 g
The total mass of 100 mL of vodka is:
29.5875 g + 62.5 g = 92.0875 g
The mole fraction of alcohol in vodka is:
moles of ethanol / (moles of ethanol + moles of water)
To calculate the moles of ethanol, we can divide the mass of ethanol by its molar mass:
moles of ethanol = 29.5875 g / 46.07 g/mol = 0.6412 mol
To calculate the moles of water, we can divide the mass of water by its molar mass:
moles of water = 62.5 g / 18.02 g/mol = 3.4739 mol
The mole fraction of alcohol in vodka is therefore:
0.6412 mol / (0.6412 mol + 3.4739 mol) = 0.155
To calculate the molarity of alcohol in vodka, we need to divide the moles of ethanol by the volume of the vodka in liters:
moles of ethanol = 0.6412 mol
volume of vodka = 100 mL = 0.1 L
molarity of ethanol = moles of ethanol / volume of vodka
molarity of ethanol = 0.6412 mol / 0.1 L = 6.412 M
Therefore, the molarity of alcohol in vodka is 6.412 M.
Nomenclature
55/Name the compounds in parts a-d and write the formulas for the
compounds in parts e-h.
a. NaBr
b. Rb,0
C. CaS
d. All3
e. strontium fluoride
f. aluminum selenide
8. potassium nitride
h. magnesium phosphide
.
The names of the given compounds are as follows:
a. NaBr = Sodium bromide
b. Rb\(_2\)O = Rubidium oxide
c. CaS = Calcium sulfide
d. AlI\(_3\) = Aluminium iodide
The formulas for the given compounds are as follows:
e. Strontium fluoride = SrF\(_2\)
f. Aluminum selenide = Al\(_2\)Se\(_3\)
g. Potassium nitride = K\(_3\)N
h. Magnesium phosphide = Mg\(_3\)P\(_2\)
This is the binary nomenclature of ionic compounds which involves both metals as well as non-metals. Metal is always named at the start without any prefix or suffix, while the name of the non-metals is placed after the metal in abbreviated form with the suffix "-ide".
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Which of the following best defines climate)_( Short-term atmospheric conditions of a region Ob The weather pattern of an area over two weeks or less Average weather conditions of a region over the long term Od A pattern of weather that never changes
Answer:
Average weather conditions of a region over the long term
Explanation:
Climate is the long-term average of weather, typically averaged over a period of 30 years. More rigorously, it denotes the mean and variability of meteorological variables over a time spanning from months to millions of years.
This equation shows the reaction of trans-2,3-dimethyloxirane with hydrogen chloride to form 3-chloro-2-butanol.
how many total stereoisomer are possible for 3-Chloro-2-butanol?
Given that opening of the epoxide ring in this reaction is stereoselective, provide the names of the only two isomeric products using IUPAC guidelines.
Product one: _______ 3-chloro-2-butanol
Product two: _______3-chloro-2-butanol
Answer:
Product one: (2S, 3R)-3-chloro-2-butanol
Product two: (3S, 2R)-3-chloro-2-butanol
Explanation:
The IUPAC name of the products following IUPAC guidelines are :
Product one: (2S, 3R)-3-chloro-2-butanol
Product two: (3S, 2R)-3-chloro-2-butanol
attached below is a pictorial representation of the formation of the 3-chloro-2-butanol via backside attack of Nucleophile
Draw the products for the following chemical reactions, clearly indicating stereochemistry wherever applicable. For reactions that involve nucleophilic substitution at a tetrahedral carbon, indicate if the reaction proceeds via SN1 or SN2 mechanism (18 points)
The carbocation intermediate in step 1 of the SN1 mechanism is an sp2 hybridized carbon is the 2-ol -3 Methyl hexene formed ftom the 2cholro 3 Methyl hexene in the presence of methanol.
Its molecular geometry is trigonal planar, consequently taking into consideration unique factors of nucleophilic attack, left and rightbranch of chemistry that offers with the spatial association of atoms and organizations in molecules. : the spatial association of atoms and organizations in a compound and its relation to the residences of the compound.
Stereochemistry is the department of chemistry that involves “the have a look at of the unique spatial preparations of atoms in molecules”. Stereochemistry is the systematic presentation of a particular subject of technological know-how and generation that historically calls for a quick initial tour into history.
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light frequency 1.40x10^15 Hz strike a surface causing photoelectrons to leave with a KE of 1.05 eV what is the work function in eV
Answer:
The Work Function is 4.74eV.
Explanation:
The photoelectric effect is a phenomenon in which a beam of light is projected towards a metal plate and this leads to the ejection of electrons from the metal. The minimum amount of energy required for this ejection of electrons is known as the work function. When the energy of the light beam is less than the work function, then the electrons are not emitted.
The photoelectric effect is represented by the equation:
E = φ + KE where
E = energy of the incident photons
KE = kinetic energy of photoelectrons
φ = Work function of the metal
This can also be written in terms of frequency as:
h = h₀ + \(\frac{1}{2}\) mv²
= frequency of the incident light beam
₀ = frequency of the photoelectrons
m = mass of the electron
v = velocity of the electron
h = Plank's constant 6.623 x 10⁻³⁴Js
Conversion factor: 1eV = 1.602 x 10⁻¹⁹ J
So, 1.05eV = 1.682 10⁻¹⁹ J
Using the formulas,
(6.623 x 10⁻³⁴Js)(1.40x10¹⁵ s⁻¹) = φ + 1.682 x 10⁻¹⁹ J
(9.272 x 10⁻¹⁹) - (1.682 x 10⁻¹⁹) = φ
φ = 7.590 x 10⁻¹⁹ J = 4.74 eV
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Waves that can travel through empty space are called
Answer:
Hello, Otaku Kun Here! >:3
Explanation:
Electromagnetic waves? This is also called light!
hope this helps!
from: Otaku Kun! ^^
In Part A, we saw that the theoretical yield of aluminum oxide is 0.700 mol . Calculate the percent yield if the actual yield of aluminum oxide is 0.532 mol .
Considering the definition of percent yield, the percent yield is 76%.
Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
\(percent yield=\frac{actual yield}{theorical yield}x100\)
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
Percent yield in this caseIn this case, you know:
actual yield= 0.532 molestheorical yield= 0.700 molesReplacing in the definition of percent yield:
\(percent yield=\frac{0.532 moles}{0.700 moles}x100\)
Solving:
percent yield= 76%
Finally, the percent yield is 76%.
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Which of the following best describes of a loan soil
Answer:
Loam soil* is soil composed of equal parts sand, silt, and clay.
Explanation:
Which of the following is TRUE if ΔEsys = -100 J?
The statement that is true if the ΔEsys = -100 J is that the system looses 100J of energy which is gained by the surroundings.
What is the energy of the system?Note that the study of energy is what we call thermodynamics. We should note that according to the laws of thermodynamics, energy can not be created nor destroyed but can be converted from one form to another.
This implies that the energy that is lost by the system must be gained by the surroundings since there can never be energy that goes to waste in the system.
Recall that the universe is composed of the system and the surroundings and the energy that is lost by the system must be gained by the surroundings and vice versa. This would now be our guide in deciding which statement is right above from what we have in the question here.
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Assume 0.42 L of a 0.95 M solution of nickel (II) chloride, NiCl2, reacts with a 1.5 M solution of sodium hydroxide, NaOH, to produce nickel (II) hydroxide, Ni(OH)2, and sodium chloride, NaCl. The problem requires that you determine the volume of sodium hydroxide, NaOH, needed for the reaction to occur.
NiCl2(aq) + 2 NaOH(aq) → Ni(OH)2(s) + 2 NaCl(aq)
0.26L is the volume of sodium hydroxide, NaOH, needed for the reaction to occur.
What is volume?A measurement of three-dimensional space is volume. Several imperial or US customary units, as well as SI-derived units (such the cubic meter and liter), are frequently used to quantify it quantitatively (such as the gallon, quart, cubic inch).
Volume and length (cubed) have a symbiotic relationship. The capacity of such a container is typically regarded to be its volume.
Molarity₁×Volume₁=Molarity₂×Volume₂
0.95 × 0.42=1.5×Volume₂
Volume₂=(0.95 × 0.42)/1.5
=0.26L
Therefore, 0.26L is the volume of sodium hydroxide, NaOH, needed for the reaction to occur.
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A solution was prepared by dissolving 105.0 g of KCl in 215 g of water.
What is the molality (in m) of KCl in this solution?
(Round your answer to TWO places past the decimal)
Considering the definition of molality, the molality of the KCl in the solution is 6.56 moles/kg.
Definition of molalityMolality, or molal concentration, is the amount of a substance dissolved in a given mass of solvent. It is defined as the moles of a solute per kilogram of solvent.
The Molality of a solution is determined by the expression:
molality= number of moles of solute÷ kilograms of solvent
Molality in this caseIn this case, you know:
mass of KCl= 105 gmass molar of KCl= 74.55 g/molenumber of moles of solute= mass of KCl÷ mass molar of KCl= 105 g÷ 74.55 g/mole= 1.41 molesMass of solvent = 215 g of water= 0.215 kg (being 1000 g=1 kg)Replacing in the definition of molality:
Molality= 1.41 moles÷ 0.215 kg
Molality= 6.56 moles/kg
The molality of the solution is 6.56 moles/kg.
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What is the density of an unknown compound in g/ml if 1.28 pounds of the compound has a volume of 4.50L
An enzyme
A) decreases the rate of a reaction.
B) binds substrates in a manner that facilitates the formation of product.
C) changes the position of the equilibrium of the reaction.
D) does not change the rate at which the equilibrium is achieved.
E) is always a prot
The correct answer to an enzyme is B) binds substrates in a manner that facilitates the formation of product.
Enzymes are biological catalysts that speed up chemical reactions in living organisms. They do this by binding to substrates (the reactants in a chemical reaction) and facilitating the formation of product.
This is done by lowering the activation energy required for the reaction to occur, making it easier for the reaction to take place. Enzymes do not change the position of the equilibrium of the reaction, nor do they decrease the rate of the reaction.
Enzymes also do not change the rate at which the equilibrium is achieved. Lastly, enzymes are not always proteins, as some RNA molecules can also function as enzymes. Therefore, the correct answer is B) binds substrates in a manner that facilitates the formation of product.
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When the Keq value is large, the number representing [A]a[B]b must be
When the equilibrium constant (Keq) value is large, it indicates that the forward reaction is favored and the concentration of products is significantly higher than that of the reactants at equilibrium.
In the expression for Keq, [A]a[B]b represents the concentrations of reactants and products raised to their respective stoichiometric coefficients
.For a large Keq value, it implies that the numerator of the expression, which corresponds to the concentrations of the products raised to their stoichiometric coefficients, is much larger than the denominator, which represents the concentrations of the reactants raised to their stoichiometric coefficients.
Consequently, the number representing [A]a[B]b must be relatively small compared to the number representing the products. This suggests that the concentrations of reactants [A] and [B] are considerably lower than the concentrations of products, emphasizing the strong predominance of the forward reaction at equilibrium.
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I need help with this question. I dont understand. Please answer fully since there are 3 marks on question
Answer:
The alpha scattering experiment done by Rutherford proved that an atom is not a bowl of positively charge atom, where the electrons were evenly spread out inside it like the plum pudding model. This is because Rutherford discovered that the atoms are mostly empty space with the aplha particles passing straight through the foil. However, a small number of the alpha particles were deflected and bounced back; meaning that the center of the atom is were the mass was mostly concentrated with a positive charge nucleus.
Hope this helps!
What are the functional groups
Answer:hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl groups.
Explanation:
A functional group can participate in specific chemical reactions. Some of the important functional groups in biological molecules include
A solution that holds more solute than it normally can under the conditions at a given temperature is _____. supersaturated unsaturated saturated diluted
Answer:
Supersaturated !
Explanation:
Draw the Lewis electron dot
structure for COCI2.
What is the VSEPR shape of this
particle? PLS HELP
Answer:
Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry