Define polynomial with some examples.

Answer:

x = 1

Step-by-step explanation:

If you plug in 1 in both equations you will get 3 as your answer as it is the intersection of those two functions.

The probability of AL's number will be a whole number multiple of bill's and bill's number will be a whole number multiple of call's is 1÷ 80

The problem can be solved using Butte force approach

We can solves this in two cases

If Cal's number is :

If Bill's number is , Al’s can be any of 4, 6, 8, 10.

If Bill's number is , Al’s can be any of 6, 9.

If Bill's number is , Al’s can be 8.

If Bill's number is , Al’s can be 10.

Otherwise, Al's number could not be a whole number multiple of Bill's.

If Cal's number is 2 :

If Bill’s number is , Al's can be 8.

Otherwise, Al’s number could not be a whole number multiple of Bill's while Bill’s number is still a whole number multiple of Cal’s.

Otherwise, Bill's number must be greater than , i.e. Al’s number could not be a whole number multiple of Bill’s.

Clearly, there are exactly  cases where Al's number will be a whole number multiple of Bill's and Bill's number will be a whole number multiple of Cal’s. Since there are 10×9×8 possible permutations of the numbers Al, Bill, and Cal were assigned, the probability that this is true is

9÷10×9×8

C = 1÷80

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Answer:

42

Step-by-step explanation:

-2x(-5)=10, 8(4)=32, 32+10=42

Answer:

-22

Step-by-step explanation:

-2x--8y

-2(-5) -8(4)

10 - 32

= -22

I hope this helps you out!

list <- value, value, value, value

x<-value

FOR EACH item IN the list

{

             IF item=x

                display "found"

}

Pseudocode is an informal manner of programming description that does not require any strict programming language syntax or underlying era concerns. it is used for growing an outline or a rough draft of a program. Pseudocode summarizes an application's flow but excludes underlying info.

Pseudocode is a synthetic and casual language that facilitates programmers' to increase algorithms. Pseudocode is a "text-primarily based totally" element (algorithmic) layout device. The policies of Pseudocode are fairly straightforward. All statements showing "dependency" are to be indented. the Python pseudocode is a syntax-loose representation of code. So, the Python pseudocode no longer involves any code in it. The Python pseudocode should be a very near illustration of algorithmic good judgment.

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Both AB and BA exists and AB = [30] and BA= \(\left[\begin{array}{cccc}1&2&3&4\\2&4&6&8\\3&6&9&12\\4&8&12&16\end{array}\right]\)

To multiply two matrices we need to check if the number of columns of first matrix is equal to number of rows in second matrix. Then the multiplication exists.

Hence the order of the resulting matrix formed will be equal to number of rows of first matrix and number of columns of second matrix.

Thus AB exists since, Number of columns in matrix A = Number of rows in matrix B.

Therefore, AB = [ 1 2 3 4 ] \(\left[\begin{array}{ccc}1\\2\\3\\4\end{array}\right]\)

⇒AB = [ (1)(1) +(2)(2) +(3)(3) + (4)(4)]

⇒ AB = [ 1+ 4+ 9+ 16]

⇒AB = [30]

Thus BA exists since, Number of columns in matrix B = Number of rows in matrix A.

Therefore, BA =\(\left[\begin{array}{ccc}1\\2\\3\\4\end{array}\right]\) [ 1 2 3 4 ]

⇒BA = \(\left[\begin{array}{cccc}(1)(1)&(1)(2)&(1)(3)&(1)(4)\\(2)(1)&(2)(2)&(2)(3)&(2)(4)\\(3)(1)&(3)(2)&(3)(3)&(3)(4)\\(4)(1)&(4)(2)&(4)(3)&(4)(4)\end{array}\right]\)\({4*4}\)

⇒BA= \(\left[\begin{array}{cccc}1&2&3&4\\2&4&6&8\\3&6&9&12\\4&8&12&16\end{array}\right]\)

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Answer:

Step-by-step explanation:

let marked price 100%

100%=$900

1%=9

so,35%=$315

1 month pays $60

so 12 month pays 12*60=720

total pays 720+315=$1035

more pays =$1030-900=$130

Answer:

A series can be represented in a compact form, called summation or sigma notation. The Greek capital letter, ∑ , is used to represent the sum. The series 4+8+12+16+20+24 can be expressed as 6∑n=14n . The expression is read as the sum of 4n as n goes from 1 to 6 .

The median of the given list of numbers is 87.

To find the median of a list of numbers, we arrange them in ascending order and identify the middle value.

If there is an odd number of values, the median is the middle number. If there is an even number of values, the median is the average of the two middle numbers.

First, let's arrange the numbers in ascending order:

65.9, 68, 70, 74, 75, 78, 84, 86, 87, 90, 93, 93, 95, 96, 97, 380, 486, 680

There are 17 numbers in the list, which is an odd number. The middle number is the 9th number in the list, which is 87.

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Answer:

Similar!

Step-by-step explanation:

Hope this helps!

Answer:

3.3m+1.4

Step-by-step explanation:

Multiply 5 and 0.9m

Multiply 5 and 0.5

5 times 0.9m is 4.5m

5 times 0.5 is 2.5

Multiply -3 and 0.4m

Multiply -3 and 0.7

-3 times 0.4m is -1.2m

-3 times -.7 is -2.1

4.5m+ 2.5 -1.2m-2.1

Which is 3.3m+1.4

Hope this helps!

The algebraic expression for the given verbal description is (2n - 1)(2n + 1).

Let's break down the given verbal description step by step:

Now, we can combine these two pieces of information into an algebraic expression: The product of the two consecutive odd integers can be represented as:

(x)(x + 2)

Since we know the first odd integer is 2n - 1, we can substitute it into the expression:

(2n - 1)(2n - 1 + 2)

Simplifying further:

(2n - 1)(2n + 1)

Therefore, the algebraic expression for the given verbal description is (2n - 1)(2n + 1).

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The area of the sector  2π/3 radians with diameter 10 feet 75π feet²

The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.

Diameter =  10 feet

radius = 5 feet

angle =   2π/3 radians

⇒angle= arc/radius

⇒  2π/3 radians° =arc/10

⇒ arc =2π/3 radians *10

 ⇒arc=2π/3 radians*10

⇒arc = 20/π43 feet

Area of a circle = π*r²

                        =  π*5² = π25

∵ area of complete circle is π25

∴ area of 2π/3 radians = π25/2π *2π/3 radians

                                     = 75π  answer

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A woman you know has five children among which all five  are boys. probability for a woman that she will have all five boy as a five children is  0.5.

The probability or the outcome  in which a women with five children have all the girls and none of them as boys is :-

0.5x0.5=0.25.

So for the  first child there is a a 50% chance that is will be of a male. And same for the  second child being male there will be equal probability that it can be boy so it  also will have a probability .

So the probability of having five females is  0.55=0.03125

Except the above define value all the other outcome or choices means that the women have a least one son in the five children  and the total probability of an event is 1.

.The theoretical probability is mainly reasoning bases which is behind probability. For example, if a coin is tossed then the theoretical probability or the outcome of getting a head will be ½.

Probability provides information about the happening of   something which might happen and might not depending upon the outcome demand happen. Meteorologists, also take the help of probability to predict whether the rain may happen or not for instance In epidemiology, also probability theory is used to understand  about various risk related to life an to demonstrate various relation .

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Answer:

Step-by-step explanation:

decrese by 10

Answer:

x=10

Step-by-step explanation:

18x=180

x=10

if my answer helps please mark as brainliest.

Answer:

$21.00 and the pound is 6

Step-by-step explanation:

Answer: $23.92

Step-by-step explanation:

First, we know that 6 bagels is $2.99.

48/6=8

This means that 6 is a multiple of 48, which makes it easier to solve.

$2.99 x 8 = 23.92

= $23.92

The probability that the rate of return of this investment is greater than 10 percent is approximately 0.9214, or 92.14%.

1. Calculate the expected value and variance of the total return:
Since X1 and X2 are independent, we can simply add their means and variances.
Expected Value (E) = Mean of X1 + Mean of X2 = 60 + 60 = 120
Variance (V) = Variance of X1 + Variance of X2 = 25 + 25 = 50

2. Determine the 10 percent rate of return:
A 10 percent return on an initial investment of 100 would yield a total of 110 (100 + 10% * 100).

3. Calculate the Z-score:
The Z-score represents how many standard deviations away the desired value (110) is from the mean (120). To calculate the Z-score, we use the following formula:
Z = (X - E) / sqrt(V)
Z = (110 - 120) / sqrt(50)
Z = -10 / sqrt(50)
Z = -10 / 7.07
Z = -1.414

4. Find the probability:
Now, we need to find the probability that corresponds to the Z-score of -1.414. Using a standard normal distribution table or an online calculator, we find that the probability of a Z-score less than -1.414 is approximately 0.0786.

5. Calculate the probability of a rate of return greater than 10 percent:
Since we want the probability of a rate of return greater than 10 percent, we need to find the complement of the probability we just calculated.
Probability (rate of return > 10%) = 1 - P(Z < -1.414)
Probability (rate of return > 10%) = 1 - 0.0786
Probability (rate of return > 10%) = 0.9214

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Answer:

Obese

Step by Step Explanation:

looked it up :)

Based on the given clues, we can determine the person, drink, and price paid for each individual:

Calvin: Root Beer, $4.99

Dean: Lemonade, $7.99

Kelli: Water, $6.99

Lee: Iced Tea, $5.99

From clue 1, we know that either Calvin or the person who got the Root Beer paid $4.99. Since Calvin paid more than Lee according to clue 4, Calvin cannot be the one who got the Root Beer. Therefore, Calvin paid $4.99.

From clue 2, Kelli paid $6.99.

From clue 3, the person who got the water paid $1 less than Dean. Since Dean paid the highest price, the person who got the water paid $1 less, which means Lee paid $5.99.

From clue 5, the person who got the Root Beer paid $1 less than the person who got the Iced Tea. Since Calvin got the Root Beer, Lee must have gotten the Iced Tea.

Therefore, the final assignments are:

Calvin: Root Beer, $4.99

Dean: Lemonade, $7.99

Kelli: Water, $6.99

Lee: Iced Tea, $5.99

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The new balance on Amber Cho's credit card statement is $679.58.

Amber Cho's monthly credit card statement shows her previous balance as $529.78. She made a payment of $85.00, which reduced the outstanding balance to $444.78.

However,

There was a finance charge of $7.95 applied to this amount, bringing the balance to $452.73.
Amber also received two credits, one of $49.45 and the other of $39.22. These credits totaled to $88.67, which was subtracted from the outstanding balance, bringing it down to $364.06.
This month,

Amber made new purchases of $277.32 and $38.20.

Adding these new purchases to the outstanding balance, we get $679.58.
Therefore,

The new balance on Amber Cho's credit card is $679.58.

It is important for her to keep track of her credit card balance and make timely payments to avoid accumulating high-interest charges and penalties.

It is recommended that she pays more than the minimum amount due on her credit card bill each month to pay off her balance quickly and reduce the overall interest charges.
The previous balance:

$529.78
Subtract the payment:

$529.78 - $85.00 = $444.78
3. Add the finance charge:

$444.78 + $7.95 = $452.73
4. Subtract the credits:

$452.73 - $49.45 - $39.22 = $364.06
5. Add the new purchases:

$364.06 + $277.32 + $38.20 = $679.58

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The size of the angle marked y in the triangle is 50 degrees

The complete question is added as an attachment

Given that the triangle is an isosceles triangle

An isosceles triangle is a triangle with two sides of equal length. This means that two of the angles opposite to those sides are congruent.

Using the above definition, we have the following equation

y + 2 * 65 = 180

So, we have

y + 130 = 180

Evaluate the like terms

y = 50

Hence. the value of y is 50 degrees

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Answer:

5

Step-by-step explanation:

Using Pythagoras' identity

The horizontal distance between A and B is 3 units

The vertical distance between A and B is 4 units

Thus

AB = \(\sqrt{3^3+4^2}\)

      = \(\sqrt{9+16}\)

      = \(\sqrt{25}\)

      = 5

The orthogonal basis for the subspace W is { -1, (0, sqrt(2y^2) + sqrt(6y^6))/(3sqrt(2y^2 + 6y^6)), (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3) }.

To apply the Gram-Schmidt Process to the given vectors, we will first normalize each vector to obtain a unit vector. Then, we will subtract the projection of each subsequent vector onto the previous vectors to obtain orthogonal vectors. Finally, we will normalize the orthogonal vectors to obtain an orthogonal basis for the subspace W.

Let's begin:

1. Normalize the first vector -3:

\(v1 = (-3)/sqrt((-3)^2) = (-3)/3 = -1\)

2. Normalize the second vector (0, sqrt(2y^2), sqrt(6y^6)):

\(v2 = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(0^2 + (sqrt(2y^2))^2 + (sqrt(6y^6))^2)\)

\(v2 = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(2y^2 + 6y^6)\)

3. Subtract the projection of v2 onto v1:

proj_v2_v1 = ((v2 . v1)/(v1 . v1)) * v1

where . represents the dot product

v2_orth = v2 - proj_v2_v1

v2_orth = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(2y^2 + 6y^6) - ((0 + sqrt(2y^2) + sqrt(6y^6))(-1/3))(-1)

v2_orth = (0, sqrt(2y^2), sqrt(6y^6))/sqrt(2y^2 + 6y^6) + (sqrt(2y^2) + sqrt(6y^6))/3

4. Normalize the orthogonal vector v2_orth:

u2 = v2_orth/|v2_orth| = (0, sqrt(2y^2) + sqrt(6y^6))/(3sqrt(2y^2 + 6y^6))

5. Normalize the third vector (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6)):

v3 = (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6))/sqrt((sqrt(2)y^2)^2 + (sqrt(2)sqrt(6)y^6)^2 + (sqrt(2/6))^2)

v3 = (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3)

6. Subtract the projection of v3 onto v1 and v2:

proj_v3_v1 = ((v3 . v1)/(v1 . v1)) * v1

proj_v3_v2 = ((v3 . u2)/(u2 . u2)) * u2

v3_orth = v3 - proj_v3_v1 - proj_v3_v2

v3_orth = (sqrt(2)y^2, sqrt(2)sqrt(6)y^6, sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3) - (sqrt(2)y^2)(-1) - ((sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)))(sqrt(2) + sqrt(6))

v3_orth = (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3)

7. Normalize the orthogonal vector v3_orth:

u3 = v3_orth/|v3_orth| = (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3)

Therefore, the orthogonal basis for the subspace W is { -1, (0, sqrt(2y^2) + sqrt(6y^6))/(3sqrt(2y^2 + 6y^6)), (sqrt(2)y^2 + (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2)sqrt(6)y^6 - (sqrt(2)sqrt(6)y^6)/(3sqrt(2y^2 + 6y^6)), sqrt(2/6))/sqrt(2y^4 + 12y^12 + 1/3) }.

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Answer: - 3/35

Step-by-step explanation: (- 3/5) divided by 7 =

-3/5*1/7 (multiply fractions) = -3/35

Answer: D.

Step-by-step explanation:

Using a 0.05 significance level to test a claim that UFO sightings occur in different seasons with the proportions listed in the table the test statistic x² needed to test the claim is 11.562. The correct option is B.

To test the claim that UFO sightings occur in different seasons with the proportions listed in the table, we can use a chi-square goodness-of-fit test.

The null hypothesis is that the observed frequencies in each season are equal to the expected frequencies based on the proportions listed in the table.

The expected frequency for each season can be calculated by multiplying the total number of sightings by the proportion listed in the table. For example, the expected frequency for spring is:

Expected frequency for spring = Total number of sightings × Proportion for spring

= 420 × 0.25

= 105

Similarly, the expected frequencies for summer, fall, and winter are 126, 210, and 105, respectively.

The chi-square test statistic can be calculated as:

χ² = ∑ [(O - E)² / E]

where O is the observed frequency and E is the expected frequency.

Using the observed frequencies from the table and the expected frequencies calculated above, we get:

χ² = [(150-105)²/105] + [(120-126)²/126] + [(100-210)²/210] + [(50-105)²/105]

   = 11.562

The degrees of freedom for the chi-square test is (number of categories - 1), which in this case is 4 - 1 = 3.

Using a chi-square distribution table with 3 degrees of freedom and a significance level of 0.05, the critical value is 7.815.

Since the calculated chi-square value (11.562) is greater than the critical value (7.815), we reject the null hypothesis and conclude that there is evidence of a difference in UFO sightings across seasons. Therefore, the test statistic x² needed to test the claim is 11.562.

The correct answer is (B) 11.562.

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Answer:

Its nonlinear

aka answer C

Step-by-step explanation: