Degeneracy pressure stops the crush of gravity in all the following except:_____.A) a brown dwarf.
B) a white dwarf.
C) a neutron star.
D) a very massive main-sequence star.
E) the central core of the Sun after hydrogen fusion ceases but before helium fusion begins.

Answer:

7 m/s East

Explanation:

The speed of the man relative to the plane is given as 7 m/s. Given that he's walking in the corridor of the plane, this is his speed relative to the plane. Since he's moving to the back of the plane, and the aircraft is headed to west, the man's direction relative to the plane is East.

Uneven heating of a earth's surface is what generates wind. The sub - teams of water & land to pay a planet load quickly it takes the sun's heat. The low wind cycle is just 1 instance of this varied warmth.

The air in your home, the air in our heating system, and insufficient insulation are the three main causes of uneven heating, respectively. The following causes are more specific: airflow restrictions between the vents and the furnace. ducting that is defective or leaky. an insufficient heating system.

Near the equator, the land warms up more quickly in the summer, and the majority of time, the temperature of a land is greater than that of oceans. Heat rises and warms the air above the land. Due to this, winds from the oceans blow in a landward direction. Monsoon winds are what they are.

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(a) The support of K can be given by {0, 1, 2, 3, 4}.

(b) The set of events in which the aircraft is functioning can be given as follows: {K ≥ 1}, which means the aircraft is functioning if and only if at least one of its engines is functioning properly.

(c) Let's assume that the probability of each engine functioning properly is given by p. So, the probability of any particular engine malfunctioning or not functioning properly is (1 - p).

Since the aircraft is functioning if and only if at least one of its engines is functioning properly, the probability of system reliability can be calculated using the following formula:

P(K ≥ 1) = 1 - P(K = 0)

Since each engine functions independently of each other, the probability of each engine malfunctioning can be multiplied together. Thus, we have:

P(K = 0) = (1 - p)^4

Then,

P(K ≥ 1) = 1 - P(K = 0)

= 1 - (1 - p)^4

Therefore, the probability of the aircraft functioning, which represents system reliability, is given by 1 - (1 - p)^4.

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Answer:

Renewable energy sources can come again, but nonrenewable is gone forever. For example, coal and gasoline are both nonrenewable.

Explanation:

We are given the following information

Mass of car = 950 kg

Initial speed of car = 16.0 m/s

Final speed of car = 9.50 m/s

Time = 1.20 s

The average force exerted on the car during braking can be found using Newton's 2nd law of motion

Where m is the mass of the car and a is the acceleration of the car.

The acceleration of the car is given by

The negative sign indicates deacceleration since the car is stopping.

So, the force is

Therefore, an average force of 5145.865 N was exerted on your car during braking.

The distance traveled by the car while braking can be found as

Let us substitute the given values

Therefore, the car traveled a distance of 15.3 m while braking.

When they were falling, their acceleration is equal to the gravity acceleration.

When they started stopping, the time required to stop is 1.5 seconds, that is, 3 times less than the time accelerating.

Since the change in velocity when falling and when stopping is the same (same magnitude but opposite signal), the acceleration when stopping will be 3 times more than the acceleration when falling (because the change in velocity is the same and the time is 3 times less).

So we have:

Therefore the acceleration is 29.4 m/s².

It is false to say that speed of pulse remains v after adding the second weight w on the vertical string.

We know very well that speed of transverse wave v in a string is given by:

v=√T / √μ

where,

T represents the tension in the string

μ represents the linear mass density defined for the string

Now, in the given situation,

when weight is  hanging on light vertical string is W, speed of the wave v is :

v=√W / √μ ----(eq1)

On addition of  an additional weight of W, speed of the wave becomes v ' as :

v′ = √2W /√μ -----(eq2)

After comparing eq1 and eq2, we observe that

after addition of same amount of weight in the given light string, speed will increase by √2 times the previous speed.

Hence, the given statement is false.

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Water content under natural conditions is 21.49%, Volumetric water content under natural conditions is 21.49 cm³/cm³, Saturation ratio under natural conditions is 1.231, Porosity is 99.57% and Specific yield is 9.29% and specific retention water content at saturation is 85.57%.

Volume of soil (V) = 70 cm³

Weight of natural soil (Wn) = 150.7 g

Weight of saturated soil (Ws) = 169.7 g

Weight of drained soil (Wd) = 146.2 g

Weight of oven-dried soil (Wod) = 139.7 g

Unit weight of water (γw) = 1 g/cm³

a. Water content under natural conditions:

Water content = (Ws - Wod) / Wod × 100%

Water content = (169.7 g - 139.7 g) / 139.7 g × 100%

Water content = 21.49%

b. Volumetric water content under natural conditions:

Volumetric water content = (Water content / γw) × 100%

Volumetric water content = (21.49% / 1 g/cm³) × 100%

Volumetric water content = 21.49 cm³/cm³

c. Saturation ratio under natural conditions:

Saturation ratio = (Ws - Wd) / (Wd - Wod)

Saturation ratio = (169.7 g - 146.2 g) / (146.2 g - 139.7 g)

Saturation ratio = 1.231

d. Porosity:

Porosity = (V - (Wod / γw)) / V × 100%

Porosity = (70 cm³ - (139.7 g / 1 g/cm³)) / 70 cm³ × 100%

Porosity = 99.57%

e. Specific yield:

Specific yield = (Wd - Wod) / (V × γw) × 100%

Specific yield = (146.2 g - 139.7 g) / (70 cm³ × 1 g/cm³) × 100%

Specific yield = 9.29%

f. Specific retention water content at saturation:

Specific retention = (Wd - Wod) / (Ws - Wod) × 100%

Specific retention = (146.2 g - 139.7 g) / (169.7 g - 139.7 g) × 100%

Specific retention = 85.57%

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The final speed of the motorcycle is: 67 m/sec

Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route. In other words, although velocity is a vector, speed is a scalar quantity.

Given that,

initial speed of the motorcycle, u=25 m/sec

Acceleration of the motorcycle, a = 7 m/sec²

According to the equation of motion,

v = u + at

v = 25 m/sec + (7m/sec²) × (6 sec)

v = 67 m/sec

Thus, final speed of the motorcycle is: 67 m/sec

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a) the acceleration of the car = -2.75 m/s

b) d = 198 meters. Therefore, the squirrel would survive.

c) the car moving at 100 meters with a speed of 23.22m/s

What is acceleration ?

acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Use the kinematic equation to solve for the acceleration:

v = u +at

v = final velocity

u = initial velocity

a = acceleration

t = time

In this instance, the final velocity is 0 because he comes to a stop. We can solve for the acceleration by plugging in the given values:

0 = 33 + (12)a

0 = 33 + 12a

-33 = 12a

-33 / 12 = a  --> a = -2.75 m/s²

b) Find the amount of distance necessary to stop. Use the formula:

v^2 = u^2 + 2ad

d = distance

Plug in the values:

0² = 33² + 2(-2.75 · d)

0 = 1089 - 5.5d

-1089 = -5.5d

d = 198 meters. Therefore, the squirrel would survive.

c)

Find the velocity at 100 meters by using the same formula as before:

v^2 = u^2 + 2ad

However, in this instance, we are solving for the final velocity. Plug in the given points to solve:

vf² = 33² + 2(-2.75 · 100)

vf² = 1089 + (-550)

vf² = 539

vf = √539

vf ≈ 23.22 m/s.

the car moving at 100 meters with a speed of 23.22m/s

a) the acceleration of the car = -2.75 m/s

b) d = 198 meters. Therefore, the squirrel would survive.

c) the car moving at 100 meters with a speed of 23.22m/s

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Answer:

\(\huge\boxed{\sf v = 0.75\ m / s}\)

Explanation:

Given Data:

Wavelength = λ = 0.25 m

Frequency = f = 3 Hz

Required:

Speed = v = ?

Formula:

v = fλ

Solution:

v = (3)(0.25)

v = 0.75 m / sec

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

c. divides by 4 the gravitational force between them

Explanation:

Newton's law of gravity says:

 F1 = G(m1*m2)/r^2

where G is the gravitational constant, m1 and m2 are the masses of objects 1 and 2, and r is the distance between the two masses.

Doubling the distance would result in:

The new distance would be = 2r

F2 = G(m1m2)/(2r)^2

F2 = G(m1m2)/4r^2

F2 = (1/4)(G(m1m2)/r^2)

F2 = (1/4)F1

The new force, F2, at twice the distance is 1/4 that of the original force, F1.

The most distant object that Frank can focus on while wearing an older pair of glasses with a prescription of -1.0 D is 20 cm away from his eyes.

Frank's prescription for his regular glasses is -1.5 D, which means that the lenses correct for the refractive error in his eyes so that he can see distant objects clearly. If he wears an older pair of glasses with a prescription of -1.0 D, this means that the lenses are not as strong as his regular glasses and do not correct his refractive error as well.

To determine the most distant object that Frank can focus on while wearing the older pair of glasses, we can use the formula:

1/f = 1/di - 1/do

where f is the focal length of the lens, di is the distance between the lens and the object, and do is the distance between the lens and the image formed by the lens.

Since we know that the prescription of the older glasses is -1.0 D, we can use the formula:

f = 1/p

where p is the power of the lens in diopters.

Thus, f = 1/-1.0 D = -1.0 m⁻¹

Assuming that Frank's near point (closest distance he can see clearly without glasses) is 25 cm, we can set di = 0.25 m and solve for do:

1/-1.0 m⁻¹ = 1/0.25 m - 1/do

Simplifying the equation, we get:

do = 0.2 m or 20 cm

Therefore, the most distant object that Frank can focus on while wearing the older pair of glasses with a prescription of -1.0 D is 20 cm away from his eyes.

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The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.

Given to us,

the charge \(q\) =  \(5\times 10^{-7}\) C,

the velocity \(v\) = \(2.6\times 10^5\)  m/sec,

the magnetic field \(B\) = \(10^{-2}\) T,

angle between the direction of v and B \(\theta\) = 0,

Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by

\(\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}\)

Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N

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Answer:

Below

Explanation:

\(6.51\times 10^7 \div 7.61 \times 10\\\\\frac{6.51\times \:10^7}{7.61\times \:10}\\\\\mathrm{Multiply\:the\:numbers:}\:7.61\times \:10=76.1\\=\frac{10^7\times \:6.51}{76.1}\\\\6.51\times \:10^7=65100000\\\\=\frac{65100000}{76.1}\\\\\mathrm{Divide\:the\:numbers:}\:\frac{65100000}{76.1}=855453.35085\dots \\=855453.35085\\\\= 855.4533085 \times 10^3\)

The energy output of an electric light bulb is 240 j.

The energy that whirling electrons in an electric conductor carry is known as electrical energy. It is a popular and practical source of energy. Lightning is an instance. Electricity is created by converting various other types of energy as well.

Efficiency is calculated by dividing output by input, and you may convert this value to a percentage by multiplying it by 100. Whether it is used to measure energy output or machine efficiency, it is utilized in a variety of ways to measure both work and energy.

According to question

efficiency = (useful energy out ÷ total energy in) × 100 (for a percentage efficiency)

        80   = (useful energy out ÷ 300)×100

           80   = useful energy out ÷3

              useful energy out = 240 j

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Answer:

True

Explanation:

Because in atom the negative charge become lose or gain.

Answer:

D. 2 m/s²

Step-by-step explanation:

Initial speed of the runner (u) = 6 m/s

Final speed of the runner (v) = 14 m/s

Time taken (t) = 4 s

By using equation of motion, we get:

\( \bf \longrightarrow v = u + at \\ \\ \rm \longrightarrow 14 = 6 + 4a \\ \\ \rm \longrightarrow 14 - 6 = 6 - 6 + 4a \\ \\ \rm \longrightarrow 8 = 4a \\ \\ \rm \longrightarrow 4a = 8 \\ \\ \rm \longrightarrow \dfrac{4a}{4} = \dfrac{8}{4} \\ \\ \rm \longrightarrow a = 2 \: m {s}^{ - 2} \)

\( \therefore \) Acceleration of the runner (a) = 2 m/s²

For a series circuit, as lights are added, the current across each bulb decreases.  

Io is the planet in the solar system with the highest level of volcanic activity. Option c is Correct.

Io was given her name in honor of a Zeus-favored. Zeus attempted to conceal her from his envious wife, Hera, in the Greek tale by transforming her into a thing. One of the four Galilean satellites, Io was found by Simon Marius and Galileo Galilei in 1610.

The most volcanically active globe in the solar system is the moon Io. On the surface of Io, there are even lakes of molten silicate lava. As of today, we are aware that volcanoes can be located on Mercury, Venus, Earth, the Moon, Mars, and the moon Io of Jupiter. Only two of these bodies—Earth and Io—have active volcanoes at the moment.  Option c is Correct.

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Answer:

Convergent boundaries. When two plates collide and one is pushed over the other, forming a mountain.

Answer:

can u make the picture less blurry pls

Explanation:

In a frictionless and massless pulley system, the minimum coefficient of friction to keep the blocks at rest is 1.

Let's assume that the 2 kg mass is on the left side and the 1 kg mass is on the right side. The forces acting on the 2 kg mass are its weight mg (directed downwards) and the friction force f (directed to the right). The forces acting on the 1 kg mass are its weight mg (directed downwards) and the tension in the string T (directed upwards).

Since the system is at rest, the net force on each mass must be zero. Therefore:

For the 2 kg mass: f = mgμ, where μ is the coefficient of friction.

For the 1 kg mass: T = mg.

Since the pulley is frictionless, the tension in the string must be the same on both sides. Therefore:

T = f.

Substituting T and f in terms of mg and μ:

mg = mgμ

μ = 1

Therefore, the minimum coefficient of friction needed to keep the blocks at rest is 1.

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Newton's 2nd law of motion says:

Net force = (mass) · (acceleration) .

Newton didn't make up this law for his health.

Let's use it to answer this question about the car moving down the road.

Net force on the car = (car's mass) · (car's acceleration).

But the net force on the car is zero.  So we can write:

0 = (car's mass) · (car's acceleration).

Look at the right side of this equation.

Newton's law tells us that the product of the car's mass and the car's acceleration is zero.

That tells us that at least one of three things must be true.

Either 1). the car's mass is zero, or 2). the car's acceleration is zero, or 3). Newton was crazy.

We're pretty sure that 1). and 3). are false. The car's acceleration is zero.

What does this mean ? It means that the car's speed and direction are not changing.

That's exactly what Choice-B says.

Ans. positive acceleration

When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration.

Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

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Answer:

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shdhdggxshjwhwywsd dccefc

When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration. In Example B, the object is moving in the negative direction (i.e., has a negative velocity) and is slowing down.

Evaluate

a) L{e+(2t - 1)² + sin(-3t) + cos(5t)}

To evaluate this Laplace transform, we'll use the basic Laplace transform properties and formulas.

Step 1: Apply the Laplace transform to each term separately.

L{e} = 1/s [Using the Laplace transform of the exponential function]

L{(2t - 1)²} = (2/s)² [Using the Laplace transform of (at + b)^n, where a, b are constants]

L{sin(-3t)} = -3/(s² + 9) [Using the Laplace transform of sin(at)]

L{cos(5t)} = s/(s² + 25) [Using the Laplace transform of cos(at)]

Step 2: Apply the linearity property of the Laplace transform to combine the individual transforms.

L{e+(2t - 1)² + sin(-3t) + cos(5t)} = L{e} + L{(2t - 1)²} + L{sin(-3t)} + L{cos(5t)}

= 1/s + (2/s)² - 3/(s² + 9) + s/(s² + 25)

= 1/s + 4/s² - 3/(s² + 9) + s/(s² + 25)

Therefore, the Laplace transform of the given expression is 1/s + 4/s² - 3/(s² + 9) + s/(s² + 25).

b) L^(-1) {1 / [(s + 1)(s² + 5 - 12)]}

To evaluate the inverse Laplace transform, we'll use partial fraction decomposition and the inverse Laplace transform formulas.

Step 1: Factorize the denominator.

(s + 1)(s² + 5 - 12) = (s + 1)(s² + 5 - 12)

= (s + 1)(s² + 4s - 7)

= (s + 1)(s + 7)(s - 1)

1 / [(s + 1)(s + 7)(s - 1)] = A / (s + 1) + B / (s + 7) + C / (s - 1)

For s^2 term: 0 = A + B + C

For s term: 0 = 6A - 6B + 8C

For constant term: 1 = -7A

From the third equation, A = -1/7. Substituting this into the second equation, we get -6/7 - 6B + 8C = 0, which simplifies to -6B + 8C = 6/7.

From the first equation, we get C = -A - B, which simplifies to C = 1/7 - B.

Substituting C into the equation -6B + 8C = 6/7, we have -6B

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