Describe 9 how you would measure the circumference of a beaker using a thread and metre rule
​

Answer:

Voltage or electromotive force

Explanation:

The voltage or electromotive force in an electrical circuit causes current to flow from a point of higher electrical potential to that of a lower electrical potential in the electric circuit. So, when Priscilla closes the circuit, the electromotive force makes current to flow in the circuit and thus turn on the bulb.

Answer:

97.1037936

Explanation:

?

Answer:

60.3375 m/ per sec

Explanation:

first multiply 1609 (the amount of meters in a mile) by 135( the total number of miles). this brings you to conclude there are a total of 217,215 meters in 135 miles.

So 135 mph = 217,215 meters per hour.

From here I took a simple route so as to not need a calculator.

217,215 meters = 60mins. (divide both sides by 2)

108,607.5 = 30mins. (divide both sides by 2)

54,303.75 = 15mins. (divide both sides by 15)

3620.25 = 1min

3620.25 = 60secs. (divide both sides by 60)

60.3375 = 1sec

60.3375 meters per second = 135miles per hr.

Answer:

6.32s

Explanation:

Given parameters:

Length of track and distance covered  = 200m

Acceleration  = 10m/s²

Unknown:

Time taken to cover the track  = ?

Solution:

To solve this problem, we apply one of the motion equations as shown below:

       S  = ut + \(\frac{1}{2}\) at²  

S is the distance covered

t is the time taken

a the acceleration

u is the initial velocity

The initial velocity of Superman is 0;

 So;

     S  =  \(\frac{1}{2}\) at²  

        200  =  \(\frac{1}{2}\) x 10 x t²  

          200  = 5t²  

            t²  = 40

            t  = 6.32s

Raul pushes a stalled car with a force of 204 N. The average power required to move the car is 157 Watt.

The average power is given by:

P = ΔF . s / Δt

Where:

P = power

ΔF = force changes over a time period Δt

s = distance

Parameters given in the problem:

ΔF = 204 - 44 = 160 N

s = 16.3 m

Δt = 16 s

Plug these parameters into the formula,

P = ΔF . s / Δt

P = 160 x 16 / 16.3

P = 157 Watt

Hence, the required power is 157 Watt.

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The correct conductor ampacity for a 10-horsepower, 230-volt, single-phase motor is option c. 62.5 A.

The ampacity of a conductor is a measure of the maximum amount of electrical current that can flow through it safely. The ampacity required for a motor is based on the size of the motor and the voltage of the electrical system. There are standard methods for determining the minimum ampacity for a given motor and voltage, such as the National Electric Code (NEC) and the American National Standards Institute (ANSI). The NEC and ANSI both state that the minimum ampacity for a 10-horsepower, 230-volt, single-phase motor is 62.5 amperes. It's important to note that using a conductor with ampacity lower than the recommended one may cause the motor to overheat and fail, leading to damage or even fire hazard.

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A person who weighs 120 pounds on earth would weigh approximately 20 pounds on the moon. This is because the force of gravity is weaker on the moon due to its lower mass and smaller size. The radius of the moon is about 1,737 km (1,080 miles) while its mass is approximately 7.342 × 10²² kg (81 billion tons).

Using this data, we can calculate the acceleration of gravity on the moon's surface which is about 1.62 m/s².A person who weighs 120 pounds on earth would weigh approximately 20 pounds on the moon.

Here's how to calculate the acceleration of gravity on the moon's surface:G = GM / R² where G is the acceleration of gravity, M is the mass of the moon, and R is the radius of the moon.

We know that M = 7.342 × 10²² kg and R = 1,737 km = 1,737,000 meters so we can plug in these values to find G.G = (6.67 × 10⁻¹¹ N(m/kg)²) (7.342 × 10²² kg) / (1,737,000 m)²G = 1.62 m/s²

Therefore, the acceleration of gravity on the moon's surface is 1.62 m/s².

A person who weighs 120 pounds on earth would weigh approximately 20 pounds on the moon. This is because the force of gravity is weaker on the moon due to its lower mass and smaller size.

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The centripetal acceleration of the disk spinning at 25.7 revolutions per second is 213.15 cm/s^2.

Angular velocity (ω) = 25.7 revolutions per second

we need to convert the units of Angular velocity to radians per second.

=25.7 revolutions per second × 2π radians per revolution

= 51.4π radians per second

Angular velocity (ω) = 51.4π radians per second

distance (r) = 8.2 cm

Centripetal acceleration (a) = ?

Centripetal acceleration = (angular velocity)^2 × radial distance

= 51.4 π ^2 ×  8.2

=  2.681π^2 × 8.2

= 2.681 × 3.1416^2 × 8.2

= 2.681 × 9.869 × 8.2

≈ 213.15 cm per second square

Therefore, the centripetal acceleration of a point 8.2 cm from the center of the disk is 213.15 cm/s^2.

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The question is-

A disk is spinning about its center at 25.7 revolutions per second. Find the centripetal accelerations of a point 8.2 cm from the center of the disk.

The sound wave passed through a glass of water as well as a helium balloon because helium is less thick than air.

Frequency is the number of full wavelengths in a certain amount of time (f). When a wavelength lengthens, its frequency and energy (E) decrease. You may conclude from these equations that the wavelength gets shorter as the frequency rises.

As described in Waves, the strength drops as it gets farther away from the speaker. Moreover, because to the viscosity of the air, the energy is absorbed by things and transformed into heat energy.

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the current in the wires of the jumper cable is approximately 0.1648 Amperes (A).

To find the current in the wires of the jumper cable, we can use Ampere's Law, which states that the magnetic field around a closed loop is directly proportional to the electric current passing through the loop.

In this case, we have two parallel wires separated by a distance of 3 cm. The force per meter between the wires, given as 0.219 N/m, is the force per unit length experienced by each wire due to the magnetic field produced by the current in the other wire.

To find the current, we can use the formula for the force per unit length between two parallel wires:

Force per unit length = (μ₀ * I₁ * I₂) / (2π * separation distance)

Where:

Force per unit length is 0.219 N/m

μ₀ is the permeability of free space (4π × 10^(-7) T·m/A)

I₁ and I₂ are the currents in the two wires (we assume they are equal)

We can rearrange the formula to solve for the current (I):

I = (2π * separation distance * Force per unit length) / (μ₀)

Converting the separation distance from centimeters to meters (1 cm = 0.01 m), we have:

I = (2π * 0.03 m * 0.219 N/m) / (4π × 10^(-7) T·m/A)

Simplifying the expression, we get:

I ≈ 0.1648 A

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Answer:

500kg

Explanation:

mass = newtons/force divided by the acceleration rate

m = 30,000/60

m = 500

The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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Explanation:

In scientific notation the Sun's mass is: =1.989 x 10 ^30 kg

Answer:

I think in scientific notation the Sun's mass becomes: M Sun = 1.989 x 10 30 kg. The number above the ten, called the power of ten or exponent, stands for the number of decimal places. If it is positive, as in the mass of the Sun, the decimal places are in front of the decimal point.

I hope this help you!:)

\(\boxed{\sf E_P=mgh}\)

\(\\ \sf\longmapsto E_P=25(10)(10)\)

\(\\ \sf\longmapsto E_P=25(100)\)

\(\\ \sf\longmapsto E_P=2500J\)

In the event of an accident or a car crash, road safety barriers and fences prevent automobiles from running off the road.

Newton's Three Laws of Physics can help explain what these safety barriers are and how they help to save lives during car accidents :

I.  Unless acted upon by an imbalanced force, an object at rest will remain at rest, and an object at constant velocity will remain at constant velocity.

II.  If an imbalanced force occurs, a mass will experience acceleration proportional to its magnitude.

III.  When you apply a force to an object, you will feel a force that is equal    in magnitude but opposite in direction.

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We have demonstrated that (pω)ω∈Ω is the point mass function of some distribution, and that the random variable X has a point mass function PX equal to (pω)ω∈Ω.

In order to show that (pω)ω∈Ω is the point mass function of some distribution, we need to demonstrate that it satisfies the properties of a probability distribution.

a) Let's consider the properties of a probability distribution. Firstly, the values of pω must be non-negative for all ω ∈ Ω. This is true since pω is defined as the product of two non-negative values hω1 and hω2.

Secondly, the sum of probabilities over all possible outcomes must be equal to 1. In this case, we need to show that the sum of (pω)ω∈Ω over all possible ω in Ω is equal to 1. To do this, we can consider the sum:

Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω

By the properties of the point mass function h, we know that Σhω1 = 1 and Σhω2 = 1. Therefore, the above expression becomes:

Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω = 1 * 1 = 1

Thus, we have shown that (pω)ω∈Ω satisfies the properties of a probability distribution.

b) Now let's consider the random variable X(ω) = ω1 + ω2 and show that its point mass function PX is equal to (pω)ω∈Ω.

To calculate PX(x) = P({ω ∈ Ω : X(ω) = x}), we need to consider the event where the sum of the components ω1 and ω2 is equal to x. This can be expressed as:

{ω ∈ Ω : X(ω) = x} = {(ω1, ω2) ∈ Ω : ω1 + ω2 = x}

Now, notice that this event is equivalent to the event {ω1 = n, ω2 = x - n} for any fixed n. The probability of this event is given by pω1 pω2 = hω1 hω2, which matches the point mass function (pω)ω∈Ω.

By considering all possible values of n, we can cover all the cases for X(ω) = x, and therefore, we have shown that PX(x) is equal to (pω)ω∈Ω.

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The speed of the skier at the bottom of the slope is 15.1 m/s.

The speed of the skier at the bottom of the slope is calculated by applying the principle of conservation of energy.

Kinetic energy at bottom = percentage of potential energy converted into kinetic energy.

K.E = 20%P.E

K.E = 0.2P.E

¹/₂mv² = 0.2 mgh

¹/₂v² = 0.2gh

v² = 2 (0.2gh)

v = √2(0.2gh)

where;

sin (6.4) = h /L

h = L x sin(6.4)

h = 500m x sin (6.4)

h = 58.28 m

v =  √2(0.2 x 9.8 x 58.28 )

v = 15.1 m/s

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Answer:

Since space acts as if objects have no weight, he would have less kg than his original weight.

Explanation:

Answer:

4kg=4000,8m=60 times 8 =480

4000 times 480 over 100 =19200

The force on charge q2 is approximately 179.751 N.

The force between two point charges can be found using Coulomb's law:
F = (k * q1 * q2) / r^2
Where F is the force between the charges, k is the Coulomb constant (8.98755 × 10^9 N·m^2/C^2), q1 and q2 are the magnitudes of the charges in Coulombs, and r is the distance between the charges in meters.
In this case, q1 = 2 µC and q2 = 10 µC. The distance between the charges is the distance between the origin and the point on the x-axis where q2 is located, which is 10 m.
So, we can calculate the force on q2 as follows:
F = (8.98755 × 10^9 N·m^2/C^2) * (2 µC) * (10 µC) / (10 m)^2
F = (8.98755 × 10^9 * 2 * 10) / 100
F = 1.79751 × 10^9 / 100
F = 1.79751 × 10^7 N
The force on charge q2, we can use Coulomb's Law. Coulomb's Law states that the force (F) between two point charges is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:
F = k * (q1 * q2) / r^2
In this case, q1 = 2 µC, q2 = 10 µC, r = 10 m, and the Coulomb constant (k) is 8.98755 × 10^9 N·m^2/C^2.
The charges to Coulombs: q1 = 2 × 10^-6 C and q2 = 10 × 10^-6 C.
F = (8.98755 × 10^9 N·m^2/C^2) * ((2 × 10^-6 C) * (10 × 10^-6 C)) / (10 m)^2
F = (8.98755 × 10^9 N·m^2/C^2) * (2 × 10^-5 C^2) / (100 m^2)
F = 179.751 N

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The "greenest" kilowatt of electricity is produced by renewable energy sources, such as solar, wind, hydroelectric, geothermal, and biomass.

Renewable energy sources are considered "green" because they are abundant, clean, and emit little to no greenhouse gases that contribute to climate change. These sources of energy are also sustainable and do not deplete natural resources. In contrast, traditional sources of electricity generation, such as coal, oil, and natural gas, produce significant amounts of pollution and contribute to climate change.

Energy advisors often recommend that individuals and businesses switch to renewable energy sources to reduce their carbon footprint and support sustainable energy practices. By investing in renewable energy, individuals and businesses can help to create a cleaner, healthier environment for future generations.

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"The specific gravity of a substance is a measure of its density relative to water. In other words, it tells us how much heavier or lighter a substance is compared to an equal volume of water.

The specific gravity of water is defined as 1. This means that the density of water is 1 kilogram per cubic meter (kg/m³). This value is important because it allows us to compare the densities of different substances with that of water, which is a convenient reference point.

In scientific terms, the specific gravity of a substance is calculated by dividing its density by the density of water. For example, if a substance has a density of 1.5 kg/m³, its specific gravity would be 1.5 because 1.5/1 = 1.5.

The specific gravity of water is a constant value that does not change with temperature or pressure. This makes it a useful quantity for a variety of scientific and engineering calculations, such as determining the buoyancy of objects or calculating the concentration of dissolved substances in water."

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The smallest sound power output of the airplane motor that can be listened to on the ground is  6.73 × 10^-6 W which has the lowest-intensity sound that is still loud and has an intensity of  10^-12 W/m^2.

The intensity of sound =  10^-12 W/m^2

Altitude =  6,500 m.

Calculate the smallest sound energy output of an aircraft motor that can be heard on the ground is done by using the formula:

I = P/(4πr^2)

Pythagoras' theorem is used for calculating the distance

d = (\(\sqrt{6500^2 + R^2}\))

I = 10^-12 W/m^2

d = \(\sqrt{6500^2 + R^2}\)

d = 6500 m

P/(4πd^2) = I

\(P/(4π(6500)^2) = 10^-12 W/m^2\)

\(P = 4π(6500)^2 × 10^-12 W\)

P = 6.73 × 10^-6 W

Therefore, we can conclude that the smallest sound power output of the aircraft engine that can be heard on the ground is  6.73 × 10^-6 W.

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Given:

The mass of the ball is 2.5 kg

The initial potential energy is 32 J.

To find the potential energy before it hits the ground.

Explanation:

The potential energy can be calculated as

Answer:

The pressure of the air molecules inside the pen cap increases and the volume occupied by the air decreases such that the combined volume occupied by the pen cap and the air volume reduces while the combined mass of the pen cap and the air molecules remain the same

Given that density = The mass/Volume, we have that the density varies inversely as the volume, and as the volume reduces, the density increases

Upon squeezing, therefore, as the new combined density of the pen cap and the air molecules rises to more than the density of the water in the bottle, then, the pen cap air molecule is relatively more denser than the water, which will result in the pen cap sinking to the bottom of the bottle

Explanation:

Answer:

atom

Explanation:

the first guy who gave link this is for you:

we cannot use links in brainly

Thankyou.

Answer:

The mass of an object is the same on Earth, in orbit, or on the surface of the Moon. ... the absence of air resistance, all objects fall with the same acceleration g. ... A 1.0-kg mass thus has a weight of 9.8 N on Earth and only about 1.7 N ... What force does he apply if the stone accelerates at a rate of 1.5m/s2?

Explanation:

Answer:

Transverse waves, because the motion of the wave is perpendicular to the direction of propagation. An S-wave is an example of a transverse wave.

Explanation:

The airplane's ground speed is approximately 566.4 km/h on a heading of N 5º E.

The ground speed of an airplane can be determined by calculating the vector sum of its airspeed and the wind speed. In this case, the airplane is traveling at 564 km/h on a heading of N 8º E, while there is a 46 km/h wind coming from N 80° E.

To find the resultant ground speed, we need to break down the velocities into their respective north and east components.

The airplane's velocity can be resolved into 564 km/h * cos(8º) in the north direction and 564 km/h * sin(8º) in the east direction. Similarly, the wind's velocity can be resolved into 46 km/h * cos(80°) in the north direction and 46 km/h * sin(80°) in the east direction.

Next, we add the north and east components separately to find the resultant components. Adding the north components, we get 564 km/h * cos(8º) + 46 km/h * cos(80°) ≈ 563.12 km/h in the north direction. Adding the east components, we have 564 km/h * sin(8º) + 46 km/h * sin(80°) ≈ 61.15 km/h in the east direction.

Using these resultant components, we can calculate the magnitude of the resultant ground speed using the Pythagorean theorem: sqrt((563.12 km/h)^2 + (61.15 km/h)^2) ≈ 566.4 km/h.

The direction of the resultant ground speed can be determined by taking the inverse tangent of the east component divided by the north component: atan(61.15 km/h / 563.12 km/h) ≈ 5º.

Therefore, the airplane's ground speed is approximately 566.4 km/h on a heading of N 5º E.

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Answer:

The change in time for the first quarter is  seconds.  = 2.07

The change in time for the second quarter is  seconds.

=1.09

The change in time for the third quarter is  seconds.

=0.95

The change in time for the fourth quarter is  seconds.=0.81

Explanation:

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