Describe the changes (if any) in potential energy and in kinetic energy among the molecules when gaseous PCl₃ condenses to a liquid at a fixed temperature.

Answer:

Molarity = 2.0833 M (Approx)

Explanation:

Given:

Number of moles (n) = 0.25

Volume of solution = 120 ml = 0.12 L

Find:

Molarity

Computation:

Molarity = Number of moles (n) / Volume of solution.

Molarity = 0.25 / 0.12

Molarity = 2.0833 M (Approx)

Answer:

There is no hydrogen in the first half reaction

The standard free-energy change at 25 ∘C for the given reaction, Mg(s)+Fe₂+(aq)→Mg₂+(aq)+Fe(s) can be calculated using the equation:ΔG∘ = ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)where ΔGf∘ is the standard free energy of formation of the compound, n is the stoichiometric coefficient of each compound in the reaction.

The values of ΔGf∘ for the given reaction are:

Mg₂+ (aq):−467.2 kJ/mol Fe(s): 0 kJ/mol Fe₂+(aq): −237.2 kJ/mol Mg(s): 0 kJ/molΔG∘ =

ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)ΔG∘ =

[ΔGf∘ (Mg₂+ (aq)) + ΔGf∘ (Fe(s))] - [ΔGf∘ (Mg(s)) + ΔGf∘ (Fe₂+(aq))]ΔG∘ =

[−467.2 kJ/mol + 0 kJ/mol] - [0 kJ/mol + (−237.2 kJ/mol)]ΔG∘ =

−230.0 kJ/mol At 25 ∘C, the standard free-energy change for the given reaction is −230.0 kJ/mol. The units of ΔG∘ are kilojoules per mole (kJ/mol). Hence, the answer is -230.0 kJ/mol.

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THE ANSWER IS YO MAMA

JK IT'S B

The bond angles of each of the bonds are;

A - 107 degrees

B- 104.5 degrees

C- 120 degrees

D - 109.5 degrees

E - 120 degrees

We define the bond angle as the angle that exists between two atoms that have been bonded together. We must note that the bond angle depends on the nature of the bond between the atoms as well as the kind of the atoms that are bonded.

It should be noted that the presence of lone pairs on any of the atoms that is involved in the bond would tend to decrease the bond able of the bond.

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Answer: increases

Explanation:the rate of reaction generally increases when the concentration is increased. Molecules have a better chance of having an effective collision that results in the reactions taking place

The number of moles of NaF that will be produced from 3moles of Na is 3 moles.

Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, sodium reacts with fluorine as follows:

2Na+ F₂ → 2NaF

Based on the above equation, 2 moles of Na will produce 2 moles of NaF

This means that 3 moles of Na will produce 3 moles of NaF.

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Explanation:

the carbonate and the hydrochloric acid are the same in both reactions as products

The correct name for the compound \(FeSO_{4}-6H_{2}O\) is Iron II Sulfate hexahydrate. This is because the compound contains iron in its +2 oxidation state (hence the "II" in the name), and the sulfate ion (\(SO_{4}\)) has a -2 charge.

The "hexahydrate" part of the name indicates that there are six water molecules associated with each formula unit of the compound.

Therefore, the correct name for this compound is Iron II Sulfate hexahydrate, and this name accurately reflects its chemical composition.

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Explanation:

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When a coiled spring is released, the type of energy transfer that occurs is from potential energy to kinetic energy. When the spring is compressed and coiled, it stores potential energy due to the deformation of its structure.

The potential energy is in the form of elastic potential energy. As soon as the spring is released, it starts to expand, and this potential energy is converted into kinetic energy as the spring gains velocity and starts moving. At the maximum expansion (when the spring reaches its natural length), all the potential energy is converted into kinetic energy. The kinetic energy will continue to drive the motion of the spring until it comes to a stop or transfers its energy to another object or system.

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1.  Consider the reaction: 5 A + 3 B → 2 C The rate of the reaction is found to be 0.0486 M/s. Then, The rate of change of B is 0.01215 M/min.

2.  For the following zero order reaction, the rate constant is 0.0311.

If [A₀] = 8.68, calculate [A] at 2.9 seconds. Then, [A] = 8.66445 ≈ 8.7.

(1) For Reaction : 5A + 3B → 2C

R₁ : 0.080486 M/s = K[A][B]²          ---------------------- (1)

When half of the B has reacted, then,

⇒ R₂ = k[A][B/2]                   -------------------------- (2)

Dividing (2) and (1), we get:

   R₂÷ R₁ = K[A] [B/2] ÷ K[A] /[B]

⇒  R₂÷ R₁ = B²/4 ÷ B²

⇒ R₂÷ R₁ = 1/4

Therefore,

R₁ /4 = 0.0486/ 4

        = 0.01215 M/minute.

Therefore,

Consider the reaction: 5 A + 3 B → 2 C The rate of the reaction is found to be 0.0486 M/s. Then, The rate of change of B is 0.01215 M/min.

(2) For a Zero Order reaction:

t = K[A₀] [A] ÷ K               ------------------------- (1)

Given that:

t = 2.9 Second

and, k = 0.0311

Converting Seconds into minutes:

t = 2.9 second = 0.048 Minutes ≈ 0.5 Minutes.

Putting the values in equation (1)

⇒ 0.5 = 8.68 - [A] ÷ 0.0311

⇒ 0.5 × 0.0311 = 8.68 - [A]

⇒ 0.01565 - 8.68 = - [A]

⇒ [A] = 8.66445

Therefore, [A] = 8.66445 ≈ 8.7

Based on the zero order reaction, the rate constant is 0.0311. If [A]0 = 8.68, calculate [A] at 2.9 seconds. Then, [A] = 8.7

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The Radiometric dating is the possible because the rates of the decay of radioactive isotopes are constant. The correct option is c. are constant.

The Radiometric dating is possible because of the rates of the decay of the radioactive isotopes. They use the absolute radiometric dating that requires the extremely long-lived parent nucleus. The Radiometric dating helps to calculates the age in the years for the geologic materials by the measuring of the presence of the short-life radioactive element. The radioactive dating or the radioisotope dating is the technique that is used to date the materials such as the rocks or the carbon.

Thus, the rates of the decay of radioactive isotopes are constant in the in the Radiometric dating .

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The 13.5 g of oxygen combines with 50 g of tin. if the formula of compound a is SnO, the formula of compound b is SnO₂.

given that :

The mass of the oxygen = 13.5 g

The mass of the tin = 50 g

molar mass of the oxygen = 16 g/mol

molar mass of the tin = 118.7 g/mol

moles of the oxygen = mass / molar mass

                                   = 13.5 / 16

                                    = 0.84

moles of the tin = mass / molar mass

                          = 50 / 118.7

                           = 0.42

dividing by the smallest one we get :

O = 0.84 / 0.42 = 2

Sn = 0.42 / 0.42 = 1

The formula for the compound is SnO₂.

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Johnny’s reasoning that he can hear the train better by putting his ear to the ground is correct because sound waves travel faster through solids than they do through air.

Sound waves are longitudinal waves that travel through mediums by vibrating the particles within the medium. The different mediums that sound waves can travel through include solids, liquids, and gases.

The speed of sound is determined by the properties of the medium it is traveling through. Sound travels faster through denser mediums because there are more particles to vibrate and transmit the sound wave. Therefore, Mary’s reasoning that sound will travel faster through a thinner medium is incorrect.

Johnny’s reasoning that he can hear the train better by putting his ear to the ground is correct because sound waves travel faster through solids than they do through air.

When sound waves move from one medium to another, they change speed and direction. When sound waves move from air to ground, they encounter a denser medium and slow down. This causes them to bend toward the ground and spread out along their surface.

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Johnny would be the first that would hear the train.

Now we have to take out minds back to the speed of sound in the various media that we have. We must first of all know that sound is a mechanical wave and that the implication of this is that the wave would travel through a medium.

Sound sets the medium that it travels through into vibration. The implication of this is that the sound would travel in compressions and rare factions.  This occurs more easily in the solid ground.

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Answer:

Same i guess hdjekfhkshfjfkr

The resultant volume of the carbon dioxide gas which is produced by the combustion of butane is 14.4L.

Moles of any gas will be calculated by using the ideal gas equation as:

PV = nRT, where according to qustion for butane gas

P = pressure = 1.20 atm

V = volume = 2.50L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 22 degree celsius = 295.15 K

On putting values we get

n = (1.20)(2.50) / (0.082)(295.15) = 0.124 moles

Given chemical equation is:

C₄H₁₀ + 13/2O₂ → 4CO₂ + 5H₂O

From the stoichiometry of the reaction, it is clear that,

1 mole of C₄H₁₀ = produces 4 moles of CO₂

0.124 mole of C₄H₁₀ = produces 4×0.124=0.496 moles of CO₂

Now we calculate the volume for the carbon dioxide gas at the given pressure and temperature as:

V = (0.496)(0.082)(295.15) / (1.20) = 14.4 L

Hence required volume of CO₂ is 14.4 L.

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Answer:

C:the cold water will remain at the bottom and won't mix very much with the warm water at the top because warm and cold water don't mix

Answer:

the answer is is the warm water at the top will sink down and mix with the cold water at the bottom

Answer:

12cm^3

Explanation:

Just multiply each of the given dimension.

= 3.0 × 4.0 × 1.0

= 3 × 4 × 1

= 12

Answer:

12cm cubed

Just multiply 3, 4, and 1

Reactions that tend to go on their own, releasing energy, are called exergonic reactions.

In an exergonic reaction, the energy of the products is lower than the energy of the reactants. As a result, energy is released during the reaction. This energy can take various forms, such as heat, light, or the energy used to perform work.

Exergonic reactions are spontaneous and do not require an external energy source to proceed. The energy released during these reactions is often utilized by the surrounding environment or used to drive other cellular processes.

An example of an exergonic reaction is the combustion of fuel, such as gasoline. When gasoline reacts with oxygen in the presence of heat or a spark, it undergoes an exergonic reaction, releasing energy in the form of heat, light, and mechanical work.

In biological systems, cellular respiration is an example of an exergonic reaction. During cellular respiration, the breakdown of glucose in the presence of oxygen releases energy that is used by cells to perform various functions, including muscle contraction, active transport, and synthesis of molecules like ATP.

Overall, exergonic reactions play a fundamental role in energy transfer and metabolism, driving many essential processes in both biological and non-biological systems.

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Answer:

5.54mL = V2

Explanation:

V1 = 11.5mL

T1 = 415k

T2 = 200k

V2 = ?

\(\frac{V1}{T1 } = \frac{V2}{T2 }\)  so this means \(\frac{11.5}{415} = \frac{V2}{200 }\) then you cross multiply

(11.5)(200) = (415)(V2)

2300 = 415 x V2

then you have to divide

\(\frac{2300}{415} = \frac{415+V2}{415}\)  

then you cross out the 415 from the top and bottom of second part so its not there so it would be \(\frac{2300}{415 } = V2\)

then divide

\(\frac{2300}{415 } = V2\)  so V2 = 5.54mL (mL bc thats the only volume in the equation)

Answer: as the number of predators increases, more prey are captured. as a result the prey population starts to decrease.

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

A mixture of cis- and trans-3-methyl-2-hexene is hydroxylated, as shown in the diagram below. The most common definition of hydroxylation in chemistry is a chemical process.

A hydroxyl group is added to an organic molecule as a result (OH).The degree of hydroxylation refers to how many OH groups are present in a given molecule (ii). the process of hydroxylation. A hydrocarbon utilised in organic chemistry is hexene, which has the chemical formula C6H12. A chemical with two carbon atoms joined by a double bond is known as an alkene, and the prefix "-ene" denotes its presence. The word "hex" comes from the fact that the molecule has six carbon atoms in it.

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Density =mass/volume

=6/3

=2

Answer:

K

Explanation:

The magnitude of the heat transfer (Q) is approximately 1822200 J.

To determine the magnitude and direction of heat transfer, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat transfer into the system minus the work done by the system:

ΔU = Q - W

In this case, we are given the work done by the gas, which is performed by the 12-V source with 6 amperes of current for 9 minutes. The work done (W) can be calculated using the formula:

W = VΔP

where V is the change in volume and ΔP is the change in pressure.

Given:

Initial volume (V1) = 100 L

Final volume (V2) = 140% of V1 = 140 L

Pressure (P) = 2 bar = 200 kPa

V = V2 - V1 = 140 L - 100 L = 40 L

ΔP = P - P = 0 (since the pressure is constant)

Therefore, W = VΔP = 40 L * 0 = 0 J (no work is done)

Now, we can rearrange the first law of thermodynamics equation to solve for heat transfer (Q):

Q = ΔU + W

Since there is no work done, the equation simplifies to:

Q = ΔU

The change in internal energy (ΔU) can be calculated using the formula:

ΔU = ncvΔT

where n is the number of moles, cv is the specific heat capacity at constant volume, and ΔT is the change in temperature.

To calculate the number of moles, we can use the ideal gas law:

PV = nRT

Rearranging the equation to solve for n:

n = PV / RT

Given:

Pressure (P) = 2 bar = 200 kPa

Volume (V) = 100 L

Temperature (T) = 293 K

R (universal gas constant) = 8.314 J/(mol·K)

n = (200 kPa * 100 L) / (8.314 J/(mol·K) * 293 K) ≈ 8.524 mol

Now, we can calculate the change in internal energy:

ΔU = ncvΔT = (8.524 mol) * (0.743 gKJ/mol·K) * (293 K) = 1822.2 gJ ≈ 1822200 J

Therefore, the magnitude of the heat transfer (Q) is approximately 1822200 J.

Since the work done by the system is zero and the change in internal energy is positive, the heat transfer is in the positive direction, meaning heat is transferred into the system.

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Answer: Answer would be two

Explanation:

Gasoline blending in petroleum refineries involves analyzing the properties of different components and determining the optimal mixing ratios to produce gasoline that meets specific octane rating and quality requirements.

Gasoline blending is a critical process in petroleum refineries where different components are combined to produce the desired gasoline product. In this example, the challenge is to blend gasoline from three different components.

To solve the gasoline blending problem, various factors need to be considered such as the desired octane rating, volatility, and environmental regulations. The first step is to determine the optimal proportion of each component based on their individual characteristics. This involves analyzing the properties of each component, such as its research octane number (RON), motor octane number (MON), and vapor pressure.

The second step is to develop a blending strategy that achieves the desired gasoline specifications. This involves determining the appropriate mixing ratios of the three components to meet the target octane rating and other quality requirements. The blending process requires precise calculations and adjustments to ensure the final gasoline product meets the desired specifications.

Additionally, economic considerations play a role in gasoline blending. The cost of each component and the market demand for specific gasoline grades can influence the blending decisions. Refineries aim to optimize the blend to minimize costs while meeting quality standards.

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The mass of the sample of water is approximately 10.05 grams.

To calculate the mass of the sample of water, we can use the formula for heat transfer:

Q = mcΔT

Where:

Q = Heat transferred (in joules)

m = Mass of the sample (in grams)

c = Specific heat capacity of water (approximately 4.18 J/g°C)

ΔT = Change in temperature (in °C)

Given:

ΔT = 20°C - 10°C = 10°C

Q = 420 J

c = 4.18 J/g°C

Rearranging the formula, we can solve for mass:

m = Q / (cΔT)

m = 420 J / (4.18 J/g°C * 10°C)

m = 420 J / (41.8 J/g)

m ≈ 10.05 g

Therefore, the mass of the sample of water is approximately 10.05 grams.

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Answer:

molecule at low temperature and high pressure

Explanation:

this is because two of the postulates of kinetic theory of gases hold true only when there is low pressure and high temperature. as the pressure goes on increasing and temperature goes on decreasing, a molecule will deviate from ideal behavior.