Answer:
its d ok make me brialyisyt plssssss
If the lines 5x + 3my – 2 = 0 and 3x + 7y + 1 = 0 are parallel, then what is the value of m?
(a)9/35
(b)35/9
(c)9/5
(d)5/9
Please give full explanation!!!
ASAP!!
Answer:
35/9
Step-by-step explanation:
7y=-3x-1
y=-3/7x-1/7
m=-3/7
Now,
3my=-5x+2
y=-5/3mx+2/3
So
-3/7=-5/3m
-9m=-35
m=35/9
Answer:
35/9
Step-by-step explanation:
What we need to know:
Parallel lines have the same slope
slope intercept form: y = mx + b
m = slope
The first thing we will want to do is put both equations in slope intercept form.
We must do this so we can identify the slope.
First equation:
3x + 7y + 1 = 0
Solve for y
Subtract 1 from both sides
3x + 7y + 1 - 1 = 0 - 1.
3x + 7y = -1
Subtract 3x from both sides
3x - 3x + 7y = -1 - 3x
7y = -3x - 1
Divide both sides by 7
7y/7 = (-3x - 1)/7
y = -3/7x - 1/7
So the equation of the first line is y = -3/7x - 1/7
Second equation:
5x + 3my – 2 = 0
Solve for y
Subtract 5x from both sides
5x - 5x + 3my - 2 = 0 - 5x
3my - 2 = -5x
Add 2 to both sides
3my - 2 + 2 = -5x + 2
3my = -5x + 2
Divide both sides by 3m
3my/3m = (-5x + 2)/3m
y = -5x/3m + 2/3m
So the equation of the second line is y = -5x/3m + 2/3m
So we have the two equations:
y = -3/7x - 1/7 and y = -5x/3m + 2/3m and we want to find the value of m if the two lines are parallel
Lines that are parallel have similar slopes
So the slope of the first equation should be the same as the slope of the second equation
The slope of y = -3/7x - 1/7 is -3/7 as it takes the spot of "m" in y = mx + b.
The slope of y = -5x/3m + 2/3m is -5/3m as it takes the spot of "m"
If the slopes of parallel lines must be similar than -3/7 = -5/3m
(Note that we've just created an equation that we can use to solve for m)
We now solve for m
-3/7 = -5/3m
Cross multiply
3*-3m = -9m
7*-5=-35
we acquire -35 = -9m
Divide both sides by -9
-35/-9 = 35/9
-9m/-9=
We're left with m = 35/9
So we can conclude that the value of m would be 35/9 if the two lines are parallel
Please find the missing angle of this Shape.
One student solved the inequality −4 > x/-7 and got 28 28. Are they both correct? Explain
Answer: solutions are the same, just written differently, inequality sign is reversed when multiplying by a negative. Yes, both students are correct.Jul 8, 2018
Step-by-step explanation:
PLEASE HELP ASAP I'M BEING TIMED!!!!!!!!!!!!!!!!!!!!!! WIll mark BRAINLIEST!!!!!!!!!!!!
The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?
A) Use the distance formula to find the length of each side, and then add the lengths.
B) Use the slope formula to find the slope of each side, and then determine if the opposite sides are parallel.
C) Use the slope formula to find the slope of each side, and then determine if the consecutive sides are perpendicular.
D) Use the distance formula to find the length of the sides, and then multiply two of the side lengths.
A) Use the distance formula to find the length of each side, and then add the lengths.
An enclosure at a zoo contains giraffes and ostriches. All together the zookeeper counts 70 heads and 200 legs. How many of each animal are there?
By solving equations we know that there are 30 giraffes and 40 ostriches in the zoo.
A mathematical statement known as an equation is made up of two expressions joined by the equal sign.
A formula would be 3x - 5 = 16, for instance.
When this equation is solved, we discover that the number of the variable x is 7.
So, calculate as follows:
Let g represent giraffes and o represent ostriches.
g + o = 70 ...(1)
4*g + 2*o = 200 ...(2)
g = 70 - o, according to equation 1, therefore we may enter that number in place of g in equation 2 to obtain:
4*g + 2*o = 200
4*(70-o) + 2*o = 200
280 - 4o + 2o = 200
-2o = 200 - 280
2o = 80
o = 80/2
o = 40
Ostriches are 40 then giraffes will be:
70 - 40 = 30
Therefore, by solving equations we know that there are 30 giraffes and 40 ostriches in the zoo.
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A-5-B when A=9 and B=-4
Answer:
8
Step-by-step explanation:
(Refer to picture)
Plug in the value of A and the value of B into the expression
Consider the rates 45 mile in 8 minutes and 4 minutes to travel 25 mile. Select the statement(s) that are true. Multiple select question. Cross out A) The rate 45 mile in 8 minutes has a unit rate of 10 miles per minute. Cross out B) The rate 45 mile in 8 minutes has a unit rate of 110 mile per minute. Cross out C) The rate 4 minutes to travel 25 mile has a unit rate of 10 minutes per mile. Cross out D) The rate 4 minutes to travel 25 mile has a unit rate of 110 minute per mile. Cross out E) Both rates are equivalent. Cross out F) The rates are not equivalent.
Answer:
F) The rates are not equivalent.
Step-by-step explanation:
Consider the rates 45 mile in 8 minutes and 4 minutes to travel 25 mile. Select the statement(s) that are true. Multiple select question.
We find the unit rates
a) 45 mile in 8 minutes , we find the unit rate in miles per minute
8 minutes = 45 miles
1 minute = x
8 × x = 45 miles × 1 minute
x = 45 miles/8 minutes
x = 5.625 miles/ minute
b) 4 minutes to travel 25 miles. Find the unit rate is minutes per mile
25 miles = 4 minutes
1 mile = x
25miles × x = 4 minutes × 1
x = 4 minutes/25 miles
x = 0.16 minutes/mile
Hence, the correct option is
F) The rates are not equivalent.
A particle moves in a straight line and has acceleration given by a(t)=4t−1. Its initial velocity is v(0)=−3 cm/s and it's initial displacement is s(0)=4 cm. Find its position function s(t).
The position function s(t) for a particle with acceleration a(t) = 4t - 1, initial velocity v(0) = -3 cm/s, and initial displacement s(0) = 4 cm is s(t) = t^2 - t + 4t + 4 cm.
To find the position function s(t), we need to integrate the acceleration function a(t) with respect to time twice. Given that a(t) = 4t - 1, we first integrate it once to obtain the velocity function v(t). The integral of 4t - 1 with respect to t is 2t^2 - t + C1, where C1 is a constant of integration. Since the initial velocity is v(0) = -3 cm/s, we can substitute t = 0 and v(0) = -3 into the velocity function to find C1. Solving for C1, we get C1 = -3.
Next, we integrate the velocity function v(t) = 2t^2 - t - 3 with respect to t to find the position function s(t). The integral of 2t^2 - t - 3 with respect to t is (2/3)t^3 - (1/2)t^2 - 3t + C2, where C2 is another constant of integration. Using the initial displacement s(0) = 4 cm, we substitute t = 0 and s(0) = 4 into the position function to find C2. Solving for C2, we get C2 = 4.
Therefore, the position function s(t) for the particle is given by s(t) = (2/3)t^3 - (1/2)t^2 - 3t + 4 cm. This function represents the particle's position at any given time t based on its initial velocity, acceleration, and displacement.
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A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes. Each small box can hold 20 books and each large box can hold 45 books. There were twice as many large boxes sent as small boxes, which altogether can hold 440 books. Write a system of equations that could be used to determine the number of small boxes sent and the number of large boxes sent. Define the variables that you use to write the system.
In linear equation, 20x + 45y = 440 , y = 2x Where x is the number of small boxes sent and y is the number of large boxes sent.
What in mathematics is a linear equation?
A linear equation is a first-order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept.
Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.
Let be x the number of small boxes sent and y the number of large boxes sent.
Since each small box can hold 20 books (20x), each large box can hold 45 books (45y)and altogether can hold a total of 440 books, we can write the following equation to represent this
20x + 45y = 440
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation
y = 2x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is
20x + 45y = 440
y = 2x
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how many solutions does x0 +x1 +···+xk = n have, if each x must be a non-negative integer?
The number of solutions to x₀ + x₁ + ... + \(x_{k}\) = n with each value of x to be a non-negative integer xₐ is (n + k).
Solved using the technique of stars and bars, also known as balls and urns.
Imagine you have n identical balls and k+1 distinct urns.
Distribute the balls among the urns such that each urn has at least one ball.
First distribute one ball to each urn, leaving you with n - (k+1) balls to distribute.
Then use k bars to separate the balls into k+1 groups, with the number of balls in each group corresponding to the value of xₐ.
For example, if the first k bars separate x₀ balls from x₁ balls, the second k bars separate x₁ balls from x₂ balls, and so on, with the last k bars separating \(x_{k-1}\) balls from \(x_{k}\) balls.
The number of ways to arrange n balls and k bars is (n + k) choose k, or (n +k) choose n.
This is the number of solutions to x₀ + x₁ + ... + \(x_{k}\) = n, where each xₐ is a non-negative integer.
Therefore, the number of solutions to x₀ + x₁ + ... + \(x_{k}\) = n with non-negative integer xₐ is (n + k).
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is 12 - 3z + 6z2 and 6(z - 2) equivalent
Answer:
\(\mathbb{ ANSWER }\)
NOPE
Find the area of the surface generated when the given curve is revolved about the given axis. y=1/16(e^8x+e^−8x),
for
−3≤x≤3;
about the x-axis The surface area is
square units.
In this problem, the lower limit of integral is -3 and the upper limit of integration is 3.
We can use the formula for the surface area of a solid of revolution generated by a curve revolving around a given axis. The formula is S = 2π ∫ a b y dx, where a and b are the lower and upper limits of integration, and y is the height of the curve at x. In this problem, the lower limit of integration is -3 and the upper limit of integration is 3. Substituting y = 1/16(e^8x + e^-8x) into the equation gives S = 2π ∫ -3 3 (1/16(e^8x+e^-8x)) dx. Integral this expression gives S = 10512π.
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What is the measure of each exterior angle of a regular hexagon?
40°
45°
60°
72°
The measure of each exterior angle of a regular hexagon ( six sided regular polygon is 60°.
Option C)60° is the correct answer.
What is a polygon?A polygon is simply a two-dimensional a plane shape enclosed by line segments called sides.
The formula for calculating the exterior angles of a polygon is;
E = 360° ÷ number of sides
Given the data in the question;
The polygon in question is a regular hexagonA regular hexagon has six sides, n = 6So we substitute the value for number of sides into the expression above.
E = 360° ÷ number of sides
E = 360° ÷ 6
E = 60°
The measure of each exterior angle of a regular hexagon ( six sided regular polygon is 60°.
Option C)60° is the correct answer.
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Answer: (C) 60°
Just took it on edge
Find a vector function r(t), that represents the curve of intersection of the two surfaces. the cylinder x2 y2=36 and the surface z=4xy
Given:
\(\begin{aligned}&x^2+y^2=16 \\&z=x y\end{aligned}\)
Express 16 as \(4^{2}\): \(x^2+y^2=16\)
\(x^2+y^2=4^2\\x^2+y^2=4^2 \times 1\)
Trignometry,
\(\cos ^2(t)+\sin ^2(t)=1\)
Now, substitute \(\cos ^2(t)+\sin ^2(t)\) for 1:
\(\begin{aligned}&x^2+y^2=4^2 \times 1 \\&x^2+y^2=4^2 \times\left[\cos ^2(t)+\sin ^2(t)\right]\end{aligned}\\x^2+y^2=4^2 \times \cos ^2(t)+4^2 \times \sin ^2(t)\)
Law of indicates:
\(\begin{aligned}&x^2+y^2=[4 \times \cos (t)]^2+[4 \times \sin (t)]^2 \\&x^2+y^2=[4 \cos (t)]^2+[4 \sin (t)]^2\end{aligned}\\x^2=[4 \cos (t)]^2 \text { and } y^2=[4 \sin (t)]^2\)
Taking positive square roots as follows:
\(x=4 \cos (t), y=4 \sin (t)\)
Recall that, z = xy.
Now, we have:
\(\begin{aligned}&z=4 \cos (t) \times 4 \sin (t) \\&z=16 \cos (t) \cdot \sin (t)\end{aligned}\)
Now, substitute the values:
\(r(t)=x_t i+y_t j+z_t k\)
So, the vector r(t) is: \(r(t)=(4 \cos (t)) i+(4 \sin (t)) i+(16 \cos (t) \cdot \sin (t)) i\)
Therefore, the vector function r(t) is written as: \(r(t)=x_t i+y_t j+z_t k\)
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Anyone need help with volume about cones, cylinders and spheres?
Which of the following correctly measures the length (in cm) of the green box shown in the image below?
0.920 cm
0.92cm
0.9cm
Answer:
0.92 cm
Step-by-step explanation:
Do not pick 0.920 as it is the same as 0.92 but 0.92 is always the preferable option
The accurate measurement for the length of the green box is indeed 0.92 cm.
To measure the length of the green box accurately, we must carefully analyze the given image. By comparing the green box to the provided scale, we can deduce the correct measurement.
Upon examination, the green box appears to span almost the entirety of the "0.1 cm" scale division and extends slightly beyond it. Given that the box reaches around 9 divisions on the scale, it is reasonable to deduce that its length is 0.92 cm. This is because it's covering 9 divisions of 0.1 cm each, and considering the small extension.
Hence, the accurate measurement for the length of the green box is indeed 0.92 cm. This value takes into account its coverage of 0.9 cm (9 divisions) and a slight extension, aligning with the provided options.
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what is the answer to this question?
Answer:
-25x + 27
Step-by-step explanation:
-7x+9(-2x+3) =
-7x-18x+27 =
-25x+27 =
Can someone pls help me with this. I’ll give brainliest
Answer:
try resedning the picture it wont open/load
Step-by-step explanation:
Louis is saving for his retirement by making annual end of year deposits for 30 years into a bank
account that pays interest at a nominal rate of 8% compounded quarterly. For the first 10 years the
deposits are level at $5000 each year. After the 10 th year, each deposit is 3% more than the year before.
A) Give an actuarial expression for the account balance after the final deposit is made ?
B) What is the account balance after the final deposit is made ?
the actuarial expression for the account balance after the final deposit is made as:\(FV = $5000 \times [(1.03^{(n-10)}+1)(1.02)^{(204)}-1]/(0.02) + $5000 \times [(1.03^{10}+1)(1.02)^{(104)}-1]/(0.02)\)The account balance after the final deposit is made is \($62,297.36.\)
The account balance after the final deposit is made, the formula for the future value of an annuity due with a growth rate.
Actuarial expression for the account balance after the final deposit is made:
A be the annual deposit amount, n be the number of deposits, i be the nominal annual interest rate, m be the number of compounding periods per year, and g be the annual growth rate of the deposits.
The formula for the future value of an annuity due with a growth rate is:
\(FV = A \times [(1+g)\times (1+i/m)^{((n-1) \times m)+1}] / (i/m)\)
Louis' situation, we have:
\(A = $5000\) for the first 10 years, and then \(A = $5000 \times 1.03^{(n-10)}\) for the remaining 20 years.
n = 30 years
i = 8% nominal annual interest rate, compounded quarterly, so i = 2% per quarter
m = 4 quarters per year
g = 3% annual growth rate for each deposit after the 10th year
The account balance after the final deposit is made:
The above actuarial expression and substituting n=30, we get:
\(FV = $5000 \times [(1.03^{20}+1)(1.02)^{80}-1]/(0.02) + $5000 \times [(1.03^{10}+1)(1.02)^{40}-1]/(0.02)\)
Simplifying this expression gives:
\(FV = $5000 \times (1.03^{20} \times 1.02^{80} + 1.03^{10} \times 1.02^{40})\)
Using a calculator, we get:
\(FV = $5000 \times (10.4619 + 1.7958)\)
\(FV = $62,297.36\)
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Using only pennies, nickels, dimes, and quarters, what is the smallest number of coins Freddie would need so he could pay any amount of money less than a dollar?A. 6B. 10C. 15D. 25E. 99
The smallest number of coins Freddie would need is 4 (one penny, one nickel, one dime, and one quarter).
What is algebra ?
Algebra is a branch of mathematics that deals with mathematical symbols and the rules for manipulating these symbols. It includes the study of operations such as addition, subtraction, multiplication, division, and the extraction of roots, as well as the properties of operations such as commutativity, associativity, and distributivity.
In order to be able to pay any amount of money less than a dollar, Freddie would need to have at least one coin of each denomination: pennies, nickels, dimes, and quarters. The smallest number of coins he would need to achieve this is 4. With one penny, one nickel, one dime, and one quarter, he would be able to pay any amount of money less than a dollar by using combinations of these coins.
Therefore , The smallest number of coins Freddie would need is 4 (one penny, one nickel, one dime, and one quarter).
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20 POINTS GUYS
EASY WORD PROBLEM ⦁ The cylindrical Giant Ocean Tank at the New England Aquarium in Boston is 24 feet deep and has a radius of 18.8 feet. Find the volume of the tank.
⦁ Use 3.14 for pi and round your answer to the nearest tenth if necessary.
Answer:
26635.2
Step-by-step explanation:
pi18.8^2=~1109.8
1109.8*24=26635.2
It is sufficient to test an analogy by asking what are its relevant similarities.
True or False
The statement that It is sufficient to test an analogy by asking what are its relevant similarities is false.
Analogy refers to the process of comparison of two or more items such that it explains some idea, or classification or familiarity and representativeness. Studying the analogies helps in enhancing, strengthening and reinforcing the skills in areas such as reading comprehension, homophones, deductive reasoning and logic.
Testing an analogy only by relevant similarities will produce partial results which might not be suitable to fully explain the reason. Hence, both relevant similarities and differences are to be considered for more detailed review. Different kind of analogies used to explain the differences or similarities are synonym and antonym, symbol and reference, degree of differences.
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Reasonable Time: Algorithms with a polynomial efficiency or lower (constant, linear, square, cube, etc.) are said to run in a reasonable amount of time. Unreasonable Time: Algorithms with exponential or factorial efficiencies are examples of algorithms that run in an unreasonable amount of time. Your school is considering running the group raffle at an upcoming assembly to give away a prize. Write a brief explanation of what advice you would give them.
Unreasonable Time is the nest option for running the group raffle at an upcoming assembly to give away a prize.
As given that;
Reasonable Time: Algorithms with a polynomial efficiency or lower (constant, linear, square, cube, etc.) are said to run in a reasonable amount of time.
Unreasonable Time: Algorithms with exponential or factorial efficiencies are examples of algorithms that run in an unreasonable amount of time.
Your school is considering running the group raffle at an upcoming assembly to give away a prize.
We have to write a brief explanation of what advice you would give them.
We can use the unreasonable time because running the group raffle at an upcoming assembly to give away a prize cannot complete their work is the given amount of time.
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!!!PLEASE ANSWER VERY QUICKLY I AM TIMED!!!
Suppose that 14 inches of wire costs 70 cents. At the same rate, how much (in cents) will 37 inches of wire cost?
Answer:
Step-by-step explanation:
2590
find parametric equations for the line. (use the parameter t.) the line through the points (−5, 2, 5) and (1, 7, −6) x(t), y(t), z(t) =
Therefore, the parametric equations for the line are x(t) = -5 + 6t, y(t) = 2 + 5t, and z(t) = 5 - 11t, where t is the parameter.
To find the parametric equations for the line through the points (−5, 2, 5) and (1, 7, −6), we need to determine the values of x, y, and z in terms of a parameter t.
We will use the point-slope form of the equation of a line, which is given as follows:
$$ \frac{x-x_1}{a}=\frac{y-y_1}{b}=\frac{z-z_1}{c} $$
where (x1, y1, z1) is a point on the line, and a, b, and c are the direction ratios of the line.
We can obtain these direction ratios by taking the differences between the corresponding coordinates of the two points on the line:
\($$ a = 1 - (-5) = 6 $$ $$ b = 7 - 2 = 5 $$ $$ c = -6 - 5 = -11 $$\)
Therefore, the parametric equations for the line are given by:
\($$ x(t) = -5 + 6t $$ $$ y(t) = 2 + 5t $$ $$ z(t) = 5 - 11t $$\)
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The dinner bill came to $72.48 and Julio tipped the waiter 15%. What is the total price of dinner?
Answer: $83.35
Step-by-step explanation:
Find 15% of 72.48 = 10.87
10.87 + 72.48 = 83.35
Which set of numbers can be measured of sides of a triangle
Answer:
1.7, 3.2, 1.6
Step-by-step explanation:
if you add any 2 numbers from the 3 it has to be greater than the last number so
1.7+3.2>1.6
1.6+1.7>3.2
3.2+1.6>1.7
Find the derivative of the function. h(t)=3cot −1
(t)+3cot −1
(1/t)
h ′
(t)= (cos( t
1
)) 2
⋅t 2
⋅(cos(t)) 2
((−3(cos(t)) 2
−cos( y
1
)) 2
⋅t 2
)
the derivative of the function h(t) = 3cot⁻¹(t) + 3cot⁻¹(1/t) is h'(t) = 0
To find the derivative of the function h(t) = 3cot⁻¹(t) + 3cot⁻¹(1/t), we can apply the chain rule to each term separately.
Let's differentiate each term step by step:
For the first term, 3cot⁻¹(t):
Using the chain rule, we have:
d/dt [cot⁻¹(t)] = -1/(1 + t²)
So, the derivative of the first term is:
d/dt [3cot⁻¹(t)] = 3 * (-1/(1 + t²)) = -3/(1 + t²)
For the second term, 3cot⁻¹(1/t):
Using the chain rule, we have:
d/dt [cot⁻¹(1/t)] = -1/(1 + (1/t)²) * (-1/t²) = 1/(t² + 1)
So, the derivative of the second term is:
d/dt [3cot⁻¹(1/t)] = 3 * (/(t² + 1)) = 3/(t² + 1)
Now, adding the derivatives of both terms, we get the derivative of the function h(t):
h'(t) = d/dt [3cot⁻¹(t)] + d/dt [3cot⁻¹(1/t)]
= -3/(1 + t²) + 3/(t² + 1)
= 0
Therefore, the derivative of the function h(t) = 3cot⁻¹(t) + 3cot⁻¹(1/t) is h'(t) = 0
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Complete question is below
Find the derivative of the function. h(t)=3cot⁻¹(t) + 3cot⁻¹(1/t)
2/3(6a+9)+19.2
step by step equation
Answer:
4a + 25.2.
Step-by-step explanation:
2/3(6a+9)+19.2
= 2/3 * 6a + 2/3 * 9 + 19.2
= 4a + 6 + 19.2
= 4a + 25.2.
an ethylene glycol solution contains 25.4 g of ethylene glycol (c2h6o2) in 88.4 ml of water. (assume a density of 1.00 g/ml for water.)
Freezing point: Boiling point:
1) The freezing point is - 8.62°
2) The boiling point is 102.37°
What is freezing point?
Freezing point depression refers to the phenomenon in which the freezing point of a solvent is lowered when a non-volatile solute is dissolved in it. It is a colligative property, meaning it depends on the number of solute particles rather than their identity or chemical nature.
1) We have that;
ΔT = K m i
Number of moles of the solute = 25.4 g/62 g/mol
= 0.41 moles
Mass of water = 88.4 g or 0.0884 Kg
ΔT = 1.86 * 0.41 moles /0.0884 Kg * 1
ΔT = 8.62°
Freezing point = 0 - 8.62°
= - 8.62°
2) ΔT = K m i
ΔT = 0.512 * 0.41 moles /0.0884 Kg * 1
= 2.37°
Boiling point = 100 + 2.37°
= 102.37°
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Missing points;
An ethylene glycol solution contains 24.6g of ethylene glycol (C2H6O2) in 88.2mL of water. (Assume a density of 1.00 g/mL for water.)
Determine the freezing point of the solution.
Determine the boiling point of the solution.