describe the transformation g of shown to the right as a stretch and as a compression. then write two equations to represent the function. what can you conclude? explain.
Answers
A stretch is a transformation that expands an object. It alters the size of the original shape, but it does not change its orientation. A compression is a transformation that shrinks an object. It also alters the size of the original shape without affecting its orientation. The equations that represent the function are f(x) = 1.5x and g(x) = 0.67x. The given transformation stretches the image horizontally by a factor of 1.5 and compresses the image vertically by a factor of 0.67.
We may define the transformation g as a stretch by considering how the horizontal and vertical dimensions are affected. The horizontal coordinates are stretched by a factor of 1.5, which means that the image is 1.5 times bigger than the original. The vertical coordinates, on the other hand, are compressed by a factor of 0.67, which means that the image is 0.67 times smaller than the original.
To represent the function using equations, we can use the formula y = kx, where k is the stretch or compression factor. For the horizontal stretch, the equation is
f(x) = 1.5x,
since the horizontal dimension is stretched by a factor of 1.5. For the vertical compression, the equation is
g(x) = 0.67x,
since the vertical dimension is compressed by a factor of 0.67.
In conclusion, we can say that the transformation g stretches the image horizontally by a factor of 1.5 and compresses it vertically by a factor of 0.67. The equations that represent the transformation are f(x) = 1.5x and g(x) = 0.67x. The stretch and compression factors are found by dividing the length of the transformed shape by the length of the original shape.
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Related Questions
A block on a horizontal surface of negligible friction is placed in contact with an ideal spring, as shown above. The block is moved to the left so that the spring is compressed a distance x from equilibrium and then released from rest. The block has kinetic energy k1 when it separates from the spring. When the spring is compressed a distance 2x and the block is released from rest, the kinetic energy of the block when it separates from the spring is:
Answers
Answer: 4K1
Explanation:
Match each term with its best description.
Metamorphic
rock
Foliation
Burial
metamorphism
Parent rock
?
?
?
?
The original rock before it
metamorphoses.
Parallel alignment of platy
grains.
A rock changed by heat,
pressure, and fluids.
A process that changes
rock because of pressure
with equal intensity from
Answers
Metamorphic rock: A rock changed by heat, pressure, and fluids.
Foliation: Parallel alignment of platy grains.
Burial metamorphism: A process that changes rock because of pressure with equal intensity from all sides.
Parent rock: The original rock before it metamorphoses.
Metamorphic rock: A rock changed by heat, pressure, and fluids. The word metamorphic means change in form. Metamorphic rocks are made by rocks that have been altered in some way. This can happen through heat, pressure, and fluids. Examples of metamorphic rocks include slate, gneiss, and marble.
Foliation: Parallel alignment of platy grains. Foliation is a term used to describe the parallel alignment of platy grains in a metamorphic rock. This is caused by pressure during metamorphism. The platy grains can be minerals like mica or clay.
Burial metamorphism: A process that changes rock because of pressure with equal intensity from all sides. Burial metamorphism is a process that changes rock because of pressure with equal intensity from all sides. This can happen when rocks are buried deep within the earth's crust.
Parent rock: The original rock before it metamorphoses. The parent rock is the original rock before it metamorphoses. This rock is changed into a metamorphic rock through the process of metamorphism.
To summarize, metamorphic rock is a rock that has been changed by heat, pressure, and fluids. Foliation refers to the parallel alignment of platy grains. Burial metamorphism is a process that changes rock because of pressure with equal intensity from all sides. The parent rock is the original rock before it metamorphoses.
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i. What is the elasticity at point \( g \) ? ii. What is the elasticity at point \( h \) ? (As a first step, determine what the quantity is equal to at \( h \) )
Answers
i. The elasticity at point \( g \) is the measure of responsiveness or sensitivity of a quantity to changes in another variable at point \( g \).
ii. To determine the elasticity at point \( h \), we first need to establish what quantity we are referring to at point \( h \). Once we have identified the relevant quantity, we can then calculate its elasticity by measuring the responsiveness or sensitivity to changes in another variable at point \( h \).
i. To determine the elasticity at point \( g \), we need specific information about the variables and their relationship. Elasticity is typically calculated as the percentage change in one variable divided by the percentage change in another variable.
ii. Without additional information about the specific variables and their relationship at point \( h \), it is difficult to provide a precise answer. The concept of elasticity requires specific context and variables to be defined in order to calculate or describe it accurately.
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What do we call the potential mechanical energy stored in an object when work is performed to change its shape?
A.) elastic energy
B.) sound energy
C.) kinetic energy
Answers
How many week are in .62 years?
Answers
Answer:
32.32857
Explanation:
Searched on the web
9) During a game of bowling, which of the following describe the ball's motion?(SELECT ALL ANSWERS THAT APPLY)
A) The ball is accelerated while it is pushed by the student's hand due to an
unbalanced force.
B) The ball slows down as it rolls because friction exerts an unbalanced force.
C) The ball is accelerated while it is held in the student's hand due to balanced
Forces.
D) The ball does not change its motion as it rolls because of the balanced force
provided by friction.
E) The ball does not change its motion while it is held in the student's hand due to
balanced forces.
Answers
Answer:
A) The ball is accelerated while it is pushed by the student's hand due to an unbalanced force.
B) The ball slows down as it rolls because friction exerts an unbalanced force.
E) The ball does not change its motion while it is held in the student's hand due to balanced forces.
Explanation:
What is one Pascal pressure? What is its unit?
Answers
Explanation:
the force acting perpendicularly on unit area of surface
unit=pascle .
A pressure of one Newton per square meter .. The SI unit of 1 Pascal pressure is 1 Newton per square metre .
The Sankey diagrams below show the
energy transfers in two light bulbs. The
useful energy output for these light
bulbs is carried to the energy stores of
the environment by
What
is the missing word?
1
8ØJ
Input energy
4ØJ
Useful energy
2
8ØJ
Input energy
1ØJ
Useful energy
Answers
The useful energy output for these light bulbs is carried to the energy stores of the environment by light waves.
Useful energy
The useful energy from the two light bulbs is the energy that is beneficial and consumed. This energy is said to be used to do meaningful work.
The useful energy from the two light bulbs illuminates the environment and enables us to see in the dark.
What is Light wave?A light wave is a type of electromagnetic wave that carries light energy. This light wave carries visible light into the environment.
The light from the two lights bulbs are visible lights and thus, the useful energy output for these light bulbs is carried to the energy stores of the environment by light waves.
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If the charge is -33_ μC, the speed is 1500_m/s, the strength of the magnetic field is 1_T, and the angle is 150∘, then find the force (magnitude and direction) on the charge. 2. magnitude A. 0.01548_N D. 0.02896_N B. 0.02475 N E. 0.03607 N C. 0.02817_N F. 0.02976_N 3. direction A. Left B. Into the paper C. Right D. Out of the paper
Answers
Given the charge, speed, magnetic field strength, and angle, we can calculate the force on the charge using the equation F = q * v * B * sin(θ). The magnitude of the force is 0.02896 N, and the direction is out of the paper.
The equation to calculate the force (F) on a moving charge in a magnetic field is given by F = q * v * B * sin(θ), where q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.
Given:
Charge (q) = -33 μC = -33 × 10^-6 C
Speed (v) = 1500 m/s
Magnetic field strength (B) = 1 T
Angle (θ) = 150°
First, we need to convert the charge from microcoulombs to coulombs:
q = -33 × 10^-6 C
Now we can substitute the given values into the equation to calculate the force:
F = q * v * B * sin(θ)
= (-33 × 10^-6 C) * (1500 m/s) * (1 T) * sin(150°)
≈ 0.02896 N
Therefore, the magnitude of the force on the charge is approximately 0.02896 N.
To determine the direction of the force, we need to consider the right-hand rule. When the charge moves with a velocity (v) at an angle of 150° to the magnetic field (B) pointing into the paper, the force will be directed out of the paper.
Hence, the direction of the force on the charge is out of the paper.
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Witch of these units is NOT used to measure speed? m/s, km/h, mph, km
Answers
Answer:
km
Explanation:
Answer:
Km
Explanation:
Speed is measured is distance traveled/time
Which of these is a unique use of gamma radiation?
A. Detection of thyroid cancer
O B. CT scanners
C. Smoke detectors
D. Killing bacteria
SUBMIT
Who knows
Answers
Answer:
the answer would be 'd'
Explanation:
im really good at this stuff
The unique use of gamma radiation is Killing bacteria. The correct option is D.
What is gamma radiation?Gamma radiation is a type of electromagnetic radiation that is highly energetic and has no mass or charge. It is the most penetrating form of radiation and is often emitted during radioactive decay or nuclear reactions. Gamma rays have the shortest wavelengths and highest frequencies in the electromagnetic spectrum, ranging from about 0.1 nanometers to 10 picometers in wavelength. They can cause ionization in matter, meaning they can knock electrons out of atoms or molecules, making them highly damaging to living tissue. Gamma radiation is commonly used in medical imaging and cancer treatment, as well as in industrial applications for sterilization and food preservation.
Here in the Question,
Option A. Detection of thyroid cancer: Gamma radiation is used in medical imaging techniques such as PET scans and SPECT scans to diagnose cancerous conditions, but it is not unique to the detection of thyroid cancer.
Option B. CT scanners: Gamma radiation is not used in CT (computed tomography) scanners. CT scanners use a series of X-rays to produce detailed images of the inside of the body.
Option C. Smoke detectors: Smoke detectors use a small amount of radioactive material, typically americium-241, to ionize air particles and detect the presence of smoke. While gamma radiation is a type of ionizing radiation, smoke detectors do not use gamma radiation specifically.
Option D. Killing bacteria: Gamma radiation is used in the food industry to kill bacteria and sterilize food products, such as spices, meat, and poultry. This is a unique use of gamma radiation, as it relies on its ability to destroy microorganisms at high doses while leaving no residual radiation.
Therefore, The correct answer is option D i.e Killing bacteria.
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what is the number pattern for 7 12 17 22
Answers
Answer:
add 5 each number
Answer:
Increase by 5 each time.
Explanation:
Show that the form of Newton’s second law is invariant under the Galilean transformation. According to Newton’s second law, the net force acting on an object is equal to the product of its mass and acceleration. Newton’s second law of motion is given by following expression:
Answers
Newton’s second law of motion states that the force F acting on an object of mass m produces an acceleration a in the object, and is given by, F = ma. The law s invariant under Galilean transformation.
The Galilean transformation is a set of equations that describe the relationship between two reference frames that are in relative motion with constant velocity. It has no effect on the form of Newton’s second law because it only involves a change of coordinates and time, which do not affect the physical laws.
To see this, consider two reference frames S and S', where S' moves with constant velocity v with respect to S. Let an object of mass m be at rest in S, and let F be the net force acting on it in S. According to Newton’s second law in S, we have:
F = ma
Now, let us apply the Galilean transformation to the equation. The position of the object in S' is given by:
x' = x - vt
where x is the position of the object in S, and t is time. Taking the derivative of x' with respect to t, we get:
v' = dx'/dt
= dx/dt - v
= v - v
= 0
This means that the velocity of the object is the same in both reference frames. Similarly, the acceleration is also the same in both reference frames, since it is the derivative of velocity,
a' = dv'/dt = da/dt = a
Therefore, we can write Newton’s second law in S' as,
F' = ma'
where F' is the net force acting on the object in S'. Substituting a' = a, we get:
F' = ma
which is the same form as in S. Thus, we see that the form of Newton’s second law is invariant under the Galilean transformation.
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V,? = V2 + 2a Ax
1. A toy car increases velocity over a displacement of 15.2 m. If
the car starts at rest and has a final velocity of 0.76 m/s, what
is the magnitude of its acceleration?
Answers
Answer:
Explanation:
\(V^2=V^2_i+2a(x_f-x_i)\)
\(0.76^2=0^2+2a(15.2)\)
\(0.5776=30.4a\)
\(a=0.019m/s^2\)
A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to take a break. Which of the following is true?
A) the distance driven is more than the displacement.
B) the displacement is more than the distance driven.
C) the distance driven and the displacement are the same.
Answers
Answer:
A
Explanation:
They drove 30km north. The displacement adds up to 25km therefore making the distance greater
Hope this helps!
A hand-driven tire pump has a piston with a 2.50-cm diameter and a maximum stroke of 30.0 cm. (a) How much work do you do in one stroke if the average gauge pressure is 2.40×105 N/m2 (about 35 psi)? (b) What average force do you exert on the piston, neglecting friction and gravitational force?
Answers
Gravitational force is the force of attraction that exists between any two objects in the universe that have mass.
(a) The work done by the hand-driven tire pump in one stroke can be calculated using the formula W = Fd, where F is the force applied, and d is the distance moved. Since the piston has a diameter of 2.50 cm, its radius is 1.25 cm or 0.0125 m. The cross-sectional area of the piston is πr^2, which is approximately 0.00049 m^2. Therefore, the force exerted on the piston can be calculated as F = PA, where P is the pressure and A is the area of the piston. Substituting the given values, we get F = 2.40×10^5 N/m^2 × 0.00049 m^2 = 117.6 N. The distance moved by the piston is 30.0 cm or 0.3 m. Therefore, the work done by the pump is W = Fd = 117.6 N × 0.3 m = 35.28 J.
(b) Neglecting friction and gravitational force, the average force exerted on the piston can be calculated as the average pressure multiplied by the area of the piston. Therefore, the average force is F = PA = 2.40×10^5 N/m^2 × 0.00049 m^2 = 117.6 N, which is the same as the force calculated in part (a).
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According to kepler's 2nd law, comets (which have eccentric orbits) should spend a lot more of their time:_______.
Answers
According to Kepler's 2nd law, comets (which have eccentric orbits) should spend a lot more of their time: closer to the Sun during their orbit.
Kepler's 2nd law, also known as the law of equal areas, states that a line joining a planet or comet to the Sun sweeps out equal areas in equal intervals of time. This means that when a comet is closer to the Sun, it travels faster and covers more area in a given amount of time.
As a result, comets spend a lot more of their time closer to the Sun during their orbit, where they move faster, and less time in the outer regions of their orbit. This is because the gravitational force from the Sun accelerates them as they approach, causing them to move faster and cover more area in less time.
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if 16,700 j of work is done to shoot the human cannonball down a 30.5m barrel,then how much force is applied to the person to fire them out the cannon ?
Answers
Answer:
F=547.5
Explanation:
To Find the answer you have to remember the Formula for work. Work= Force* distance, because we are not finding work we have to fill in the variables or rearrange the formula to Force= Work/Distance
Work= 16,700
Distance=30.5M
Force=?
So,
16,700=F*30.5
Now you isolate the variable by dividing both sides by 30.5
or
Force=16,700J/30.5M
and you get F=547.5
Can someone do this for the football
Estimated volume
(cm3)
Estimated density
(g/cm3)
edge.
Answers
is the answer
Answer:
0.10 g/cm3
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an lc circuit has an inductance of 20 mh and a capacitance of 5.0 pf. at time t = 0 the charge on the capacitor is 3.0 pc and the current is 7.0 ma. the total energy is:
Answers
An lc circuit has an inductance of 20 mh and a capacitance of 5.0 pf. at time t = 0 the charge on the capacitor is 3.0 pc and the current is 7.0 ma. the total energy is: 0.049 J.
To determine the total energy in the LC circuit, we need to consider the energy stored in both the inductor and the capacitor. The energy stored in an inductor is given by the formula: \(E_{inductor}\) = (1/2) * L * \(I^2\) where L is the inductance and I is the current. Substituting the given values, we have:
\(E_{inductor}\) = (1/2) * (20 mH) * \((7.0 mA)^2\)= 0.049 J (joules)
The energy stored in a capacitor is given by the formula: E_capacitor = (1/2) * C * , where C is the capacitance and V is the voltage across the capacitor. To find the voltage across the capacitor, we can use the equation: Q = C * V, where Q is the charge on the capacitor.
Substituting the given values, we have:
3.0 pC = (5.0 pF) * V
V = 0.6 V (volts)
Now, we can calculate the energy stored in the capacitor:
E_capacitor = (1/2) * (5.0 pF) * \((0.6 V)^2\) = 0.09 pJ (picojoules)
Finally, the total energy in the LC circuit is the sum of the energy stored in the inductor and the capacitor:
Total energy = \(E_{inductor}\) + E_capacitor = 0.049 J + 0.09 pJ
Since the units are different, we need to convert pJ to joules:
1 pJ = \(10^{ -12}P\) J
Therefore, the total energy in the LC circuit is approximately 0.049 J + 0.049 J. J, which can be simplified to 0.049 J.
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a car of mass 1850 kg is traveling at 22.5 m/s in a straight line. a truck of mass 3170 kg has the same momentum as the car. the speed of the truck is
Answers
A car of mass 1850 kg is traveling at 22.5 m/s in a straight line. A truck of mass 3170 kg has the same momentum as a car. The speed of the truck is 13.43 m/s.
How to solve momentum and speed-related problems?Momentum and speed-related problems can be solved by using the formula, p= mv. The momentum of an object is defined as the product of its mass and velocity.
The formula for the speed of an object is given by,
speed = distance/time.
To solve this problem, we will equate the momentum of the car with the momentum of the truck.
the momentum of car = momentum of truck
m₁v₁ = m₂v₂
where m₁ = 1850 kg, v₁ = 22.5 m/s, m₂ = 3170 kg and v₂ = speed of truck
Substituting the given values in the above equation, we get
1850 × 22.5 = 3170 × v₂
v₂ = 41250/3170
v₂ = 13.43 m/s
Therefore, the speed of the truck is 13.43 m/s.
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What is the kinetic energy of a 3 kg ball that is rolling at 3 m/s?
Answers
Answer:
\(\Huge \boxed{\mathrm{13.5 \ Joules}}\)
Explanation:
\(\sf Kinetic \ energy \ (J)=\frac{1}{2} \cdot mass \ (kg) \cdot (velocity \ (m/s)) ^2\)
\(\mathrm{KE=\frac{1}{2} mv^2}\)
The mass of the ball is 3 kg.
The velocity of the ball rolling is 3 m/s.
\(\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 3^2}\)
Evaluating and solving for kinetic energy.
\(\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 9}\)
\(\mathrm{KE=\frac{1}{2} \cdot 27}\)
\(\mathrm{KE} =13.5\)
The kinetic energy of the ball is 13.5 Joules.
Answer:
Kinetic energy =1/2mv^2.
1/2×3×3^2.
1/2×27=13.5 or 13 whole number 1/2.
Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density n = 910 wires/m and a current per wire of IL = 0.17 A in the +z direction. The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.17 A in the -z direction.
a) Calculate the y-components of the net magnetic field in the following places: x1 = -15 cm, x2 = 6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
b) Suppose the above configuration of currents is unchanged except that the direction of the current IR is reversed so that now IR also flows in the +z direction. (The magnitude remains the same.) Calculate the y-components of the net magnetic field at the same positions as in part a).
B(x1)y = T
B(x2)y = T
B(x3)y = T
c) Return to the configuration of part a). Suppose you want to have the region 0 < x < a able to confine electrons (qe- = -1.60 x 10-19 C, me- = 9.11 x 10-31 kg) that have been accelerated from rest through a 66 V electrostatic potential. If the electrons are to be stacked in circular orbits parallel to the x-z plane with centers on the plane x = a/2, what is the minimum current per wire required if IL and IR are equal in magnitude but opposite in direction?
IL = A
Answers
Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density of n = 910 wires/m and current per wire of IL = 0.14 A in the +zdirection.
The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.14 A in the -z-direction.
(a) Calculate the y-components of the net magnetic field in the following places:
x1 = -15 cm, x2 =6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
Please check the attached file for a detailed answer.
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Juanita studies several free-body diagrams in which a normal force is shown. What is always true about a normal force in a free-body diagram?
Answers
Answer: B
Explanation: it is perpendicular to a surface
Answer:
it is perpendicular to a surface
Explanation:
PLZ HELP What is necessary condition for production of waves?
Answers
Answer:
The length of the rope must be an integral multiple of the wavelength of the wave.
Explanation:
Answer:
The condition necessary for formation or a standing wave is that the length of the rope (or the length over which the wave is distributed) must be an integral multiple of the wavelength of the wave. Therefore, l=nλ where n is a positive integer.
It takes 39.7 N to push a crate at a constant speed across flat ground where μk=0.438 what is the mass of the crate
Answers
Answer:
I don't know how to show the work but I just had this question and the answer is 9.24kg.
Explanation:
A car speeds up from 4 m/s to 25 m/s in 5 seconds. Calculate its acceleration
Answers
We have:
vi = initial speed = 4 m/s
vf = final speed = 25 m/s
t= time = 5 s
a = acceleration = ?
Apply:
\(a=\frac{vf-vi}{t}\)Replace with the values given:
\(a=\frac{25-4}{5}=4.2\)Answer: 4.2 m/s^2
The Acceleration of the car is 4.2 m/s.
We will use the formula of acceleration.
a = vu - vi / t
Given:
vi = initial speed = 4 m/s
vu = final speed = 25 m/s
t= time = 5 s
a = acceleration = ?
Now, we will put the given values in the formula,
a = vu - vi / t
a = 25 - 4 / 5
a = 21 / 5
a = 4.2 m/s
Therefore, the Acceleration of the car is 4.2 m/s.
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wire b has 4.6 times the resistance of wire a. if the same voltage is placed across them, find the ratio of the currents, ib/ia.
Answers
The ratio of the current, Ib/Ia = 1/4.6
The ratio of the currents in wires A and B, Ib/Ia, is determined by the ratio of their resistances.
To understand this more clearly, consider the following equation:
V = I R
This equation states that the voltage across a wire is equal to the product of the current in the wire and its resistance. Since the same voltage is placed across both wires, and the resistance of wire B is greater than that of wire A, the current in wire B must be less than that of wire A. Therefore, the ratio of the currents is the inverse of the ratio of their resistances.
Solving we get,
(Ib/Ia) = (V/4.6R) / (V/R) = 1/4.6.
In summary, when the same voltage is placed across two wires with different resistances, the ratio of the currents in those two wires is equal to the inverse of the ratio of their resistances.
Therefore, if the same voltage is placed across wires A and B, the ratio of the currents, Ib/Ia will be equal to 1/4.6.
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please help
The statement "46 m, East" refers to the
of an object.
velocity
distance
displacement
speed
acceleration
Answers
Answer:
Displacement
Explanation:
Displacement is a vector quantity i.e it has both magnitude and direction. The direction is indicated with compass bearing i.e North, South, East or West or you could have North East, North West, South West, South East.
Look at the diagram below that shows information about the sun, Earth, and moon. Use that information to calculate and compare the gravitational forces between the Earth and the Sun, and the Earth and the Moon.
Answers
i. The gravitational force between the earth and sun can be obtained as follow:
Mass of earth (M₁) = 5.987×10²⁴ KgMass of sun (M₂) = 1.989×10³⁰ KgDistance apart (r) = 1.5×10¹¹ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.987×10²⁴ × 1.989×10³⁰) / (1.5×10¹¹)²
F = 3.53×10²² N
Thus, the gravitational force between the earth and sun is 3.53×10²² N
ii. The gravitational force between the earth and moon can be obtained as follow:
Mass of earth (M₁) = 5.987×10²⁴ KgMass of moon (M₂) = 7.347×10²² KgDistance apart (r) = 3.844×10⁸ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.987×10²⁴ × 7.347×10²²) / (3.844×10⁸)²
F = 1.99×10²⁰ N
Thus, the gravitational force between the earth and moon is 1.99×10²⁰ N
How do i compare the gravitational forces?Gravitational force between the earth and sun (G₁) = 3.53×10²² NGravitational force between the earth and moon (G₂) = 1.99×10²⁰ NComparison =?Comparison = G₁ / G₂
G₁ / G₂ = 3.53×10²² / 1.99×10²⁰
G₁ / G₂ = 177
Cross multiply
G₁ = G₂ × 177
Thus, we can say that the gravitational force between the earth and sun is 177 times bigger than the gravitational force between the earth and moon
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