Describe two ways in which sodium chloride is different from sodium

the sun cooks the clouds the clouds pee on the earth and all the water falls to earth, pushing all the wind down that's why we have earthquakes

If 6.92 mol of C₅H₁₂ reacts with excess O₂, number of moles of CO₂ will be produced by the following combustion reaction is 34.6 mol.

The balanced reaction is given as:

C₅H₁₂   +   8O₂   --->   5CO₂   +    6 H₂O

Moles of C₅H₁₂  = 6.92 mol

1 mole of C₅H₁₂  produces 5 moles of CO₂

therefore , 6.92 mol of C₅H₁₂ = 5 × 6.92 mol

                                                = 34.6 mol of CO₂

number of moles of CO₂  = 34.6 mol

Thus, If 6.92 mol of C₅H₁₂ reacts with excess O₂, number of moles of CO₂ will be produced by the following combustion reaction is 34.6 mol.

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Explanation:

Chalk, soft, fine-grained, easily pulverized, white-to-grayish variety of limestone. Chalk is composed of the shells of such minute marine organisms as foraminifera, coccoliths, and rhabdoliths. The purest varieties contain up to 99 percent calcium carbonate in the form of the mineral calcite.

Answer:

Chalk is a salt because it has a calcium base; you can tell that it is a salt because it is powdery. It's formula is CaCO₃, or calcium carbonate.

The compound would have a molecular formula of C5H10O2.

The empirical formulas is the simplest formula of a compound.

We know that;

Mass  of the carbon = 14.03 * 12/44 = 3.82 g

Moles of C = 3.82 g/12 g/mol = 0.32 moles

Mass of water = 3.83 * 2/18 = 0.43 g

Moles of H =  0.43 g/1 g/mol =  0.43  moles

Mass of oxygen = 8.5 - (3.82 + 0.43)

= 4.25 g

Moles of oxygen = 4.25 g/16 g/mol = 0.27 moles

We can now divide through by the lowest ratio;

C - 0.32    H - 0.43    O - 0.27

C - 1   H - 2  O - 1

The empirical formula is CH2O

The molecular formula is;

[12 + 2+ 16]n = 160

n = 160/30

n = 5

The molecular formula is;

C5H10O2

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Answer:

awdaef

Explanation:

Hi there!

Let me know if you have questions about my answer:

6.15 × 10²⁴

Explanation:

To find the number of atoms, divide the mass of calcium (m) by its molar mass (MM). This will give you the number of moles of calcium (n).

\(n = m/MM\)            Start with a formula

\(=\frac{41.0g}{40.08g/mol}\)             Substitute values from the question

\(= \frac{41.0g*1mol}{40.08g}\)             Simplify

\(= \frac{41.0mol}{40.08}\)                 Cancel out the units "g"

\(= 1.022...mol\)          Number of moles of calcium, with 4 significant figures

Then, multiply the number of moles of calcium (n) by Avogadro's number (\(N_{A}\)) to find the number of calcium atoms.

\(Number.of.Ca=n*N_{A}\)      Start with a formula

\(= 1.022mol*\frac{6.022*10^{23}Ca}{1mol}\)      Substitute values from the question

\(= \frac{1.022mol*6.022*10^{23}Ca}{1mol}\)           Simplify

\(= 1.022*(6.022*10^{23}Ca)\)     Cancel out the units "mol"

\(= 6.154*10^{24} Ca\)                   Multiply, leave one extra digit to help round. "4" tells you to round down.

\(= 6.15*10^{24} Ca\)                     Final answer to 3 significant figures*

*When multiplying and dividing numbers, your final answer will have the same number of significant figures as the number with the least number of significant figures in the question.

40.08 has 4 significant figures. 41.0 has 3 significant figures. So, you want 3 significant figures in your final answer.

I hope this helps!

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Answer:

D NO3 Nitrate is a nitrogen oxoanion formed by loss of a proton from nitric acid.

Answer:

bamboo can grow 910 mm (36 in) within a 24-hour period,at a rate of almost 40 mm (1 1⁄2 in) an hour (a growth around 1 mm every 90 seconds, or 1 inch {2.54 centimeters} every 40 minutes).

Explanation:

The equilibrium constant of the reaction based on the data that we have is 3.46

The equilibrium constant's value contains crucial details about the proportions of reactants and products at equilibrium. As K exceeds 1, the reaction moves more in the direction of the products, showing that the reaction is product-favored.

We know that we have the reaction equation as;

A ⇔ B

Then we also have that the molar concentrations of A and B are 0.720 M and 2.490 M respectively. It then follows that;

Keq = [B]/[A]

Keq = 2.490 M /0.720 M

Keq = 3.46

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The balanced equation of the redox reaction is given as follows:

The balanced equation of the reaction is determined using the half-reaction method.

The given equation of the redox reaction is:

H₆TeO₆ + Br₂ ----> TeO₂ + BrO₃⁻

Reduction half-reaction:

H₆TeO₆ → TeO₂

The oxidation state of Te changes from +6 to +4, showing that it has lost gained electrons.

H₆TeO₆ → TeO₂ + 2e⁻

Oxidation half-reaction:

Br₂ → BrO₃⁻

The oxidation state of Br changes from 0 to +5, showing that it has lost five electrons.

Balancing the electrons transferred and the atoms by adding electrons, H₂O, and H⁺ to the appropriate sides:

Br₂ + 6 H₂O → 2 BrO₃⁻ + 12 H⁺ + 10 e⁻

The number of electrons transferred in both half-reactions balanced is  by multiplying the oxidation half-reaction by 5 and the reduction half-reaction by 2:

5 (H₆TeO₆ → TeO₂ + 2 e⁻) → 5 H₆TeO₆ → 5 TeO₂ + 10 e⁻

2 * (Br₂ + 6H₂O → 2 BrO₃⁻ + 12 H⁺ + 10e⁻) → 2 Br₂ + 12 H₂O → 4 BrO₃⁻ + 24 H⁺ + 20 e⁻

The two half-reactions are added together and the electrons are canceled out to obtain the balanced redox reaction:

5 H₆TeO₆ + 2 Br₂ + 12 H₂O → 5 TeO₂ + 4 BrO₃⁻ + 24 H⁺

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Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Remember that electrons provide a negative charge and protons provide a positive charge. When these two things are 'balanced', the atom is 'stable', without charges (its charge is neutral).

But, if an atom loses an electron, the atom would be losing that negative charge, 'gaining' the positive charge, it becomes an ion.

Remember that cations are positive ions and anions are negative ions. In this case, the atom is losing an electron, so it has more protons that are positive charges, thus becoming a cation. The answer is a cation.

Answer:

Бардык белгилүү авиация мыйзамдарына ылайык, аары учуу мүмкүнчүлүгү жок. Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

Explanation:

Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

Explanation:

The given value is  93.4814

Problem: Round up to three decimal places:

 To three decimal places, we must have three digits after the decimal

              93.481 and we drop the 4

Round up to one decimal place:

  Here we must have just one digit after the decimal:

           93.5 and we drop 81, since 8 is greater than 5, it becomes 1

When dissolved in water, most Group 1 metal salts can be described as strong electrolytes.

When Group 1 metal salts are dissolved in water, they can be described as strong electrolytes. This is because Group 1 metals, such as lithium (Li), sodium (Na), potassium (K), and so on, readily lose their outermost valence electron to form positive ions (cations). These cations then dissociate completely in water, separating from the anions to which they were originally bonded.

The dissociation of Group 1 metal salts in water results in the formation of positively charged metal ions and negatively charged non-metal ions (anions). These ions are free to move and conduct electric current, making the solution a good conductor of electricity. The complete dissociation of Group 1 metal salts in water and the presence of freely moving ions make them strong electrolytes.

Strong electrolytes are substances that ionize completely or almost completely in solution, producing a high concentration of ions. This is in contrast to weak electrolytes, which only partially ionize and produce a lower concentration of ions.

In summary, when Group 1 metal salts are dissolved in water, they form strong electrolytes due to their ability to dissociate completely into ions, leading to a high concentration of freely moving ions in the solution, thus enabling efficient electrical conductivity.

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The term that the scientist would use in this case is partial pressure. Option D

The pressure that one particular gas component within a mixture of gases exerts is referred to as partial pressure. It is the pressure that the gas would experience at the same temperature if it were the only thing in the entire volume.

When researching gas mixtures, such as in gas laws, gas phase equilibria, and gas collecting methods, partial pressures are extremely crucial for the gas.

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Answer:

Heat reaction

Explanation:

Heat must be applied in order to melt a substance.

The element that is being referred to here is the element called Hafnium.

Now we know that the atomic number of an element shows us the number of electrons in the neutral atom or the number of protons in the atom. It is the identity of the element hence we can use it to identify what this isotope is.

The atomic number is the number that appears as a subscript in the symbol of an atom while the mass number appears as a superscript in the symbol of a compound. The symbol of an element helps us to identify it.

Now we can see that the isotope has 72 electrons and protons to ensure neutrality. Thus the element that is being referred to here is the element called Hafnium. It has 72 electrons, 72 protons and 116 neutrons

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Answer:

mixture

Explanation:

Kool-Aid  is a mixture of sugar, water, dye, and flavoring.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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First, we need to determine the mass of water in the pool:

mass = density x volume

density of water = 1000 kg/m³

volume = length x width x depth

volume = 10.0 m x 4.0 m x 3.0 m = 120 m³

mass = 1000 kg/m³ x 120 m³ = 120000 kg

Next, we need to calculate the heat required to raise the temperature of the water:

q = m x c x ΔT

where q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.

c = 4.18 J/g°C (specific heat of water)

ΔT = 27.3°C - 20.2°C = 7.1°C

m = 120000 kg

q = 120000 kg x 4.18 J/g°C x 7.1°C = 35792400 J

Next, we need to convert the energy required to burn methane to heat energy:

-891 kJ/mol x (1 mol CH4/160 g CH4) x (1000 g/1 kg) = -5.569 kJ/g

We can now calculate the amount of methane needed:

energy = -5.569 kJ/g x mass CH4

mass CH4 = energy / (-5.569 kJ/g)

mass CH4 = 35792400 J / (-5569 J/g) = -6431.6 g

At STP, 1 mole of any gas occupies 22.4 L of volume. We can use this to convert the mass of methane to volume at STP:

1 mol CH4 = 16 g CH4

-6431.6 g CH4 x (1 mol CH4/16 g CH4) x (22.4 L/1 mol CH4) = -9074.4 L

Since we cannot have a negative volume, we can take the absolute value of the result:

|9074.4 L| = 9074 L

Therefore, approximately 9074 liters of methane gas at STP must be burned to raise the temperature of the water in the pool from 20.2°C to 27.3°C.

The volume of hydrogen gas produced in the reaction of 73 grams of zinc and 73 grams of hydrochloric acid (under normal conditions) is approximately 22.4 liters.

To calculate the volume of hydrogen gas produced in the reaction of zinc and hydrochloric acid, we need to use the principles of stoichiometry and the ideal gas law.

First, let's write the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl):

Zn + 2HCl →\(ZnCl_2\)+ H2

From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas. To determine the number of moles of zinc and hydrochloric acid, we need to convert the given masses into moles.

The molar mass of zinc (Zn) is approximately 65.38 g/mol, so 73 grams of zinc is equal to:

73 g Zn * (1 mol Zn / 65.38 g Zn) ≈ 1.116 mol Zn

Similarly, the molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol, so 73 grams of HCl is equal to:

73 g HCl * (1 mol HCl / 36.46 g HCl) ≈ 2.002 mol HCl

According to the balanced equation, the reaction produces one mole of hydrogen gas for every two moles of hydrochloric acid. Therefore, since we have 2.002 moles of HCl, we expect to produce half that amount, or approximately 1.001 moles of hydrogen gas.

To calculate the volume of hydrogen gas, we can use the ideal gas law, which states:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. In this case, we assume the reaction is conducted under normal conditions, which means a pressure of 1 atmosphere and a temperature of 273.15 Kelvin.

Rearranging the equation to solve for V, we have:

V = nRT / P

Substituting the values, we get:

V = (1.001 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K) / (1 atm) ≈ 22.4 L

Therefore, the volume of hydrogen gas produced in the reaction is approximately 22.4 liters.

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The mass of sodium chloride produced by the chemical reaction between sodium bicarbonate and hydrochloric acid is 8.37g.

The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl):

NaHCO₃ + HCl → NaCl + H₂O + CO₂

1 mole of sodium bicarbonate (NaHCO3) reacts with 1 mole of hydrochloric acid (HCl) to produce 1 mole of sodium chloride (NaCl), 1 mole of water (H₂O), and 1 mole of carbon dioxide (CO₂).

NaCl: Molar mass = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

The number of moles of sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl) using their respective masses:

Number of moles of NaHCO₃ = Mass of NaHCO₃ / Molar mass of NaHCO₃

Number of moles of NaHCO₃ = 12 g / (22.99 g/mol + 1.01 g/mol + 48.00 g/mol + 16.00 g/mol)

Number of moles of NaHCO₃ = 12 g / 84.00 g/mol ≈ 0.143 moles

Number of moles of HCl = Mass of HCl / Molar mass of HCl

Number of moles of HCl = 5.58 g / (1.01 g/mol + 35.45 g/mol)

Number of moles of HCl = 5.58 g / 36.46 g/mol ≈ 0.153 moles

Since the reaction stoichiometry is 1:1 between NaHCO₃ and NaCl, the number of moles of NaCl produced will be the same as the number of moles of NaHCO₃ reacted. Therefore, the mass of NaCl produced can be calculated as follows:

Mass of NaCl produced = Number of moles of NaCl × Molar mass of NaCl

Mass of NaCl produced = 0.143 moles × 58.44 g/mol

The Mass of NaCl produced ≈ 8.37 g

Hence, the mass of sodium chloride produced is approximately 8.37 grams.

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Answer:

New environments for puppies may make them excited, fearful, aggressive, or confused.

Explanation:

"When your dog first experiences a new location or environment, there's no way of knowing how they'll react. New sights, sounds, and smells could make them fearful, aggressive, or over-excited, but with the proper training and introduction, most dogs will quickly adapt and start taking every new location in stride." - Excerpt from *Puppy training textbook*

New environments are also a good thing in puppy growth, to teach them how to learn and adapt to new surroundings.

Hope this helps :)

Acid will be diluted by water, resulting in a reduction in the concentration of H+ ions. As a result, the solution's pH will rise.

The exothermic reaction that occurs when concentrated acid is mixed with water might result in burns due to the heat that is produced. On the other hand, when acid is gradually added to water while swirling continuously.

A basic solution's pH lowers and its hydroxide ion concentration decreases when water is added to it. The pH of the solution drops gradually toward 7 as additional water is added, and it gradually becomes less alkaline.

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Answer:

\(Q=4154J\)

Explanation:

Hello,

In this case, the involved heat in this heating process is considered to be computed via:

\(Q=nCp\Delta T\)

Whereas we assume a constant molar specific heat of helium which is 20.77 J/(mol*K), thus, the transferred energy in the form of heat turns out:

\(Q=2mol*20.77\frac{J}{mol*K} *100K\\\\Q=4154J\)

Regards.

Answer:

wait

Explanation:

a. The pH of this solution is 9.45.

b. If 0.88 g of NaOH is added to the solution, the pH will be  9.74.

a way to gauge how basic or acidic a material or solution is. On a scale of 0 to 14, pH is measured. A pH of 7 indicates neutrality on this scale, which implies it is neither acidic nor basic. More basic substances have a pH value more than 7, whereas more acidic substances have a pH value less than 7.

first of all we should calculate the molarity of the compounds

no. of moles of NH₃ = weight / molecular weight = 1.68 / (14+3) = 0.099

no. of moles of (NH₄)2SO4 = 4.05 / {2×(14+4) + 32 + 64} = 0.031

no. of moles of NH4+ = 2×0.031 = 0.062

[NH₃] = no. of moles / volume(L) = 0.099/ 0.5 = 0.198

[(NH₄⁺] = 0.031/0.5 = 0.124

1) now we know that

pH + pOH = pkw

pOH = pkw - pH = 14 - pH ---- -1

also

pOH = pkb + log ( [salt]/[base])

from 1

14 - pH = pkb + log ( [salt]/[base])

putting values

14- pH = -log(1.8e-5) + log(0.124/0.198)

14 - pH = 4.54

pH = 9.45

2) if 0.88g NaOH is added then as we know that NaOH is a base then it will reduce the buffer capacity

as there would be OH- ions initially present

hence the buffer action will move backward

i.e

pOH = pkb + log {(salt-x) / (base+x)}

where x= molarity of NaOH

no of moles of NaOH = 0.88 / (23+16+1) = 0.022

molarity of NaOH = 0.022/0.5 = 0.044

then 14 - pH = -log(1.8e-5) + log{ (0.124-0.044) / (0.198+0.044) }

14 - pH = 4.26

pH = 9.74

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The rate of change in the concentration of H2O is 0.076 M/s

Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable.

The rate of a reaction aA + bB → cC + dD can be calculated by:

r = -(1/a)x(Δ[A]/Δt) = -(1/b)x(Δ[B]/Δt) = (1/c)x(Δ[C]/Δt) = (1/d)x(Δ[D]/Δt)

Therefore the reaction C2H4(g)+3O2(g)→2CO2(g)+2H2O(g) will be calculated same.

The minus signal for the reactants is because they are disappearing, so Δ{A] and Δ[B] will be negative.

Therefore we have for the same time, r is proportional to the coefficients: where r is

r = (1/2) Δ[CO₂]/Δt

Δ[CO₂]/Δt = 2x3.8x10⁻²

Δ[CO₂]/Δt = 0.076 M/s

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Answer:

125°C/m

Explanation:

The difference in temperature will be:

35 - 10 = 25

The outer duct surface is heated 25°C by the air from 10°C to 35°C;

This heat gain is simply divided by 0.2m to get heat gain per unit length:

25/0.2 = 125

125°C/m

If you're American, this will be °F I believe, so the answer will be:

125°F/m