Design a backtracking algorithm that inputs a positive integer C, and outputs all of the ways that a group ofascending positive integers can be summed to give C. For example, if C = 6, the output should beA. 1+2+3B. 1+5C. 2+4D.6
Answers
The backtracking algorithm finds all possible ways to sum ascending positive integers to a given number C.
What is the approach to finding all possible ways to sum ascending positive integers?The backtracking algorithm utilizes recursion to explore all possible combinations of ascending positive integers. It starts with an initial sum of 0 and iterates through the possible numbers to add.
By keeping track of the current sum and the combination of numbers, it systematically generates and checks all possible ways to reach the target sum C.
In each recursive call, the algorithm checks if the current sum exceeds C. If not, it adds the number to the combination and makes a recursive call to explore further combinations. When the current sum equals C, it prints the combination as one of the possible ways to reach the target.
Through backtracking, the algorithm exhaustively explores different combinations, ensuring that all possible ways to sum ascending positive integers to C are considered and outputted.
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Related Questions
Scientists were surprised by which thing found in Ötzi the Iceman's stomach, and why?
Answers
Answer:
Scientists were surprised to find that Ötzi the Iceman's stomach contained remnants of red deer meat, as it had been previously assumed that his diet consisted primarily of plants. This finding provided new insights into the dietary habits of Copper Age Europeans and challenged previous assumptions about their reliance on agriculture. Additionally, the presence of the red deer meat in Ötzi's stomach suggested that he had eaten a last meal that was high in fat and protein, which may have provided him with the energy needed for his fateful journey through the Alps.
Answer:
Ötzi the Iceman was a well-preserved mummy found in the Italian Alps in 1991. One of the most interesting things about his remains was the discovery of his last meal. Analysis of his stomach contents showed that he had recently eaten a meal of ibex meat, a type of wild goat that lived in the region, and a type of ancient bread made from einkorn wheat. What surprised scientists was the presence of the ibex's stomach contents in Ötzi's stomach. They discovered that Ötzi had eaten the ibex meat raw, with no signs of cooking. This was surprising because it was previously believed that prehistoric humans only ate meat that had been cooked over fire. The discovery of the raw meat in Ötzi's stomach suggested that prehistoric humans may have eaten raw meat more often than previously thought and that cooking food may not have been as prevalent in ancient societies as previously believed.
Create an abstract class DiscountPolicy. It should have a single abstract method computeDiscount that will return the discount for the purchase of a given number of a single item. The method has two parameters, count and itemCost. 2. Derive a class BulkDiscount from DiscountPolicy, as described in the previous exercise. It should have a constructor that has two parameters, minimum and percent. It should define the method computeDiscount so that if the quantity purchased of an item is more than minimum, the discount is percent percent. 3. Derive a class BuyNItemsGetOneFree from DiscountPolicy, as described in Exercise 1. The class should have a constructor that has a single parameter n. In addition, the class should define the method computeDiscount so that every nth item is free. For example, the following table gives the discount for the purchase of various counts of an item that costs $10, when n is 3: count 1 2 3 4 5 6 7 Discount 0 0 10 10 10 20 20
4. Derive a class CombinedDiscount from DiscountPolicy, as described in Exercise 1. It should have a constructor that has two parameters of type DiscountPolicy. It should define the method computeDiscount to return the maximum value returned by computeDiscount for each of its two private discount policies. The two discount policies are described in Exercises 2 and 3. 5. Define DiscountPolicy as an interface instead of the abstract class described in Exercise 1.
Answers
Answer:
Java Code was used to define classes in the abstract discount policy,The bulk discount, The buy items get one free and the combined discount
Explanation:
Solution
Code:
Main.java
public class Main {
public static void main(String[] args) {
BulkDiscount bd=new BulkDiscount(10,5);
BuyNItemsGetOneFree bnd=new BuyNItemsGetOneFree(5);
CombinedDiscount cd=new CombinedDiscount(bd,bnd);
System.out.println("Bulk Discount :"+bd.computeDiscount(20, 20));
System.out.println("Nth item discount :"+bnd.computeDiscount(20, 20));
System.out.println("Combined discount :"+cd.computeDiscount(20, 20));
}
}
discountPolicy.java
public abstract class DiscountPolicy
{
public abstract double computeDiscount(int count, double itemCost);
}
BulkDiscount.java
public class BulkDiscount extends DiscountPolicy
{
private double percent;
private double minimum;
public BulkDiscount(int minimum, double percent)
{
this.minimum = minimum;
this.percent = percent;
}
at Override
public double computeDiscount(int count, double itemCost)
{
if (count >= minimum)
{
return (percent/100)*(count*itemCost); //discount is total price * percentage discount
}
return 0;
}
}
BuyNItemsGetOneFree.java
public class BuyNItemsGetOneFree extends DiscountPolicy
{
private int itemNumberForFree;
public BuyNItemsGetOneFree(int n)
{
itemNumberForFree = n;
}
at Override
public double computeDiscount(int count, double itemCost)
{
if(count > itemNumberForFree)
return (count/itemNumberForFree)*itemCost;
else
return 0;
}
}
CombinedDiscount.java
public class CombinedDiscount extends DiscountPolicy
{
private DiscountPolicy first, second;
public CombinedDiscount(DiscountPolicy firstDiscount, DiscountPolicy secondDiscount)
{
first = firstDiscount;
second = secondDiscount;
}
at Override
public double computeDiscount(int count, double itemCost)
{
double firstDiscount=first.computeDiscount(count, itemCost);
double secondDiscount=second.computeDiscount(count, itemCost);
if(firstDiscount>secondDiscount){
return firstDiscount;
}else{
return secondDiscount;
}
}
}
Once you have chosen a topic, what should you do before beginning the research process? a. Find as many possible facts and details on your topic c. Discuss your idea with others b. Choose a position d. None of these Please select the best answer from the choices provided A B C D
Answers
Answer:
The answer is C
Explanation:
Once you have chosen a topic, the next thing you should do before beginning the research process is: C. discuss your idea with others.
What is a research topic?A research topic refers to an event, issue, or subject that a researcher is keenly and deeply motivated or interested in, especially when conducting a study or research.
Based on scientific information and records, it is very important you discuss your idea with others once you have chosen a topic, before beginning the research process.
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Kieran and Kurt spend most of their day performing physical labor, aligning materials, and inspecting projects for quality and safety. However, Kieran has no fear of heights, while Kurt works with his feet on the ground. Which most likely explains the jobs of Kieran and Kurt? Kieran is a Roofer, and Kurt is a Plumber. Kieran is a Plumber, and Kurt is a Roofer. Kieran is a Carpenter, and Kurt is a Drafter. Kieran is a Drafter, and Kurt is a Carpenter.
Answers
Answer:
Kieran is a Carpenter, and Kurt is a Drafter
Explanation:
Among all the professions listed, Kurt can only possibly be a Drafter. A Drafter is an engineering technician who makes detailed technical drawings or plans for machinery, buildings, electronics, infrastructure, sections, etc. Drafters make use of computer software and manual sketches to convert the designs, plans, and layouts of engineers and architects into a set of technical drawings. All the other professions will at some point need for the professional to stand and work at an height above the ground except for a drafter, whose feet will remain on the ground at almost all times.
Answer:
A is the right answer.
Explanation:
Hope that helps
Of the following, which is not a consideration that must be addressed in determining inspection intervals for AST's?
A) Corrosion prevention systems
B) Inspection Interval of other equipment located near the tank under consideration
C) Changes in service(Including changes in water bottoms)
D) Previous inspection results
Answers
Answer:
B) Inspection Interval of other equipment located near the tank under consideration is not a consideration that must be addressed in determining inspection intervals for AST's.
Explanation:
Design a serial (one bit at a time) two’s complementer FSM withtwo inputs, Startand A,and one output. A binary number of arbitrary lengthis provided to input A,starting with the least significant bit. The correspondingbit of the output appears at Qon the same cycle. Startis asserted for one cycleto initialize the FSM before the least significant bit is provided.
Answers
Who certifies master electricians
Answers
Answer:
The state you live in
A step-up transformer has an input voltage of 110 V (rms). There are 100 turns on the primary and 1500 turns on the secondary. What is the output voltage?
Answers
Answer:
V2= 1666.6 volts
Explanation:
Given data
primary turns N1= 100 turns
secondary turns N2= 1500 turns
primary voltage V1= 110 volts
secondary voltage V2= ?
We can solve for the output voltage using the turns ration sated below
Turns Ratio = N1 / N2 = V1 / V2
Substituting our given data into the expression we have
100/1500= 110/V2
Making V2 subject of formula we have
V2= 110/(100/1500)= 1666.6 volts
V2= 1666.6 volts
Hence the secondary voltage is 1666.6 volts
Maintenance Management is part of the scope of work for Property Manager
Answers
Maintenance Management is an essential aspect of the scope of work for Property Managers. It involves the process of overseeing, planning, and implementing the upkeep and repair of a property to ensure its optimal condition.
Property Managers are responsible for coordinating routine maintenance tasks, addressing emergency repairs, and organizing preventative measures to maintain the property's value and safety. Their duties include scheduling inspections, working with contractors, and managing budgets. By effectively handling Maintenance Management, Property Managers play a crucial role in preserving the property's overall functionality and appearance, contributing to tenant satisfaction and long-term success.
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How to generate T given a random number generator of a random variable X uniformly distributed over the interval (0,1)? Present a formal mathematical proof that your algorithm for generating T is correct.
Answers
The algorithm provided correctly generates T using a random number generator and the exponential distribution formula. It is mathematically proven and ensures that Y is uniformly distributed over the interval (0, 1) when X is uniformly distributed over the same interval.
To generate T given a random number generator of a random variable X uniformly distributed over the interval (0,1), follow the steps below:
Algorithm to generate T
Generate two random numbers X and Y from the interval (0, 1) using the random number generator.Compute T as T= -ln(1 - Y)/λ.Here, λ is the rate parameter of the exponential distribution represented by T.This algorithm for generating T is correct and can be proved mathematically as follows:
Proof:
First, we will find the cumulative distribution function (CDF) of T. We know that T is exponentially distributed with parameter λ. Hence, the CDF of T is given by: F(t) = P(T ≤ t) = ∫0t λe^(-λt) dt = 1 - e^(-λt)
Now, let's find the inverse of the CDF. Since 0 < X < 1, we have: P(T ≤ t) = X
Therefore, we have:1 - e^(-λt) = X e^(-λt) = 1 - X -λt = ln(1 - X)
Thus, the inverse of the CDF is given by:T = - ln(1 - X)/λ
Now, we need to show that Y is uniformly distributed over the interval (0, 1) if X is uniformly distributed over the interval (0, 1).
Since X is uniformly distributed over the interval (0, 1), its CDF is given by: F(x) = x for 0 ≤ x ≤ 1
Let's find the CDF of Y. Since Y = F(T), we have: P(Y ≤ y) = P(F(T) ≤ y) = P(T ≤ F^-1(y))= F(F^-1(y))= y
Thus, the CDF of Y is: F(y) = y for 0 ≤ y ≤ 1
Hence, Y is uniformly distributed over the interval (0, 1) if X is uniformly distributed over the interval (0, 1).
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What type of circles have two or more circles with different center points?
Answers
Answer:
Concentric circles
Explanation:
Concentric circles are two or more circles which have the same center point. The region between two concentric circles is called an annulus.
I need a detailed solution for the multi part question
Answers
Answer:
z=X=c+J=A
Explanation:
For java
Print numbers 0, 1, 2, ..., userNum as shown, with each number indented by that number of spaces. For each printed line, print the leading spaces, then the number, and then a newline. Hint: Use i and j as loop variables (initialize i and j explicitly). Note: Avoid any other spaces like spaces after the printed number. Ex: userNum = 3 prints:
0
1
2
3
code:
public class NestedLoop {
public static void main (String [] args) {
int userNum = 0;
int i = 0;
int j = 0;
/* Your solution goes here */
return;
}
}
Answers
The given Java code will print numbers 0, 1, 2, ..., userNum as shown, with each number indented by that number of spaces. For each printed line, print the leading spaces, then the number, and then a new line.
Java code:
import java.util.*;
class Main {
public static void main(String[] args) {
int i;
int j;
Scanner sc= new Scanner(System.in);
System.out.print("userNum = ");
int userNum = sc.nextInt();
System.out.print("Prints: ");
for(i = 0; i <= userNum; i++) {
for(j = 0; j <= i; j++) {
System.out.print("");
}
System.out.println(i);
}
}
}
The Output of the java code:
userNum = 3
prints: 0
1
2
3
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A furnace wall composed of 200 mm, of fire brick. 120 mm common brick 50mm 80% magnesia and 3mm of steel plate on the outside. If the inside surface temperature is 1450 °C and outer surface temperature is 90°C, estimate the temperature between layers and calculate the heat loss in KJ/h-m2. Assume k for fire brick 4 KJ/m-h°C, k for common brick= 2.8 KJ/m-h°C, k for 85% magnesia = 0.25 KJ/m-h°C and k for steel 240 KJ/m-h°C, k
Answers
Answer:
fire brick / common brick : 1218 °Ccommon brick / magnesia : 1019 °Cmagnesia / steel : 90.06 °Cheat loss: 4644 kJ/m^2/hExplanation:
The thermal resistance (R) of a layer of thickness d given in °C·m²·h/kJ is ...
R = d/k
so the thermal resistances of the layers of furnace wall are ...
R₁ = 0.200/4 = 0.05 °C·m²·h/kJ
R₂ = 0.120 2.8 = 3/70 °C·m²·h/kJ
R₃ = 0.05/0.25 = 0.2 °C·m²·h/kJ
R₄ = 0.003/240 = 1.25×10⁻⁵ °C·m²·h/kJ
So, the total thermal resistance is ...
R₁ +R₂ +R₃ +R₄ = R ≈ 0.29286 °C·m²·h/kJ
__
The rate of heat loss is ΔT/R = (1450 -90)/0.29286 = 4643.70 kJ/(m²·h)
__
The temperature drops across the various layers will be found by multiplying this heat rate by the thermal resistance for the layer:
fire brick: (4543.79 kJ/(m²·h))(0.05 °C·m²·h/kJ) = 232 °C
so, the fire brick interface temperature at the common brick is ...
1450 -232 = 1218 °C
For the next layers, the interface temperatures are ...
common brick to magnesia = 1218 °C - (3/70)(4643.7) = 1019 °C
magnesia to steel = 1019 °C -0.2(4643.7) = 90.06 °C
_____
Comment on temperatures
Most temperatures are rounded to the nearest degree. We wanted to show the small temperature drop across the steel plate, so we showed the inside boundary temperature to enough digits to give the idea of the magnitude of that.
When thrust faults occur, the region undergoing stress is subject to: Group of answer choices compression tension shearing No answer text provided.
Answers
When thrust faults occur, the region undergoing stress is subject to compression stress.
What is compression stress?Compressive stress is a force that causes a substance to deform in order to take up less space.
When thrust faults occur, the region undergoing stress is subject to compression stress. A substance is said to be under compression when it is subjected to compressive stress.
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technician a says that loose ball joints can cause the vehicle to wander. technician b says that loose control arm bushings can affect alignment angles. who is correct?
Answers
Technician a is correct. The car may veer off course due to loose ball joints. The propensity of a vehicle to veer from one side of the road to the other is known as wander.
The propensity of a vehicle to veer from one side of the road to the other is known as wander. Uneven tire pressure or mismatched tires are potential causes number one. Linkage binding or inadequate lubrication is a potential cause number two. The third potential factor is binding or inadequate lubrication of the steering gear.
The bottom line is that before you start to address poor steering performance, you must identify the underlying source of the issue. Oversteer and understeer have been discussed separately, but we've also included 10 other common steering issues with their likely causes below. You can stop cursing and start fixing your steering problems by locating potential problem areas.
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how to answer for computer science quora how do your interests directly connect with cornell engineering? if you have an intended major, what draws you to that department at cornell engineering? if you are unsure what specific engineering field you would like to study, describe how your general interest in engineering most directly connects with cornell engineering. it may be helpful to concentrate on one or two things that you are most excited about\.\* (250 words)
Answers
Focus primarily on highly precise specifics of what Cornell offers and how it matches with your interests and values. You can regard this as a "Why us?" essay with some optional "Why major" spice.
How to write essay ?Cornell is fundamentally a research institution, and I am fundamentally a researcher. The Collective Embodied Intelligence Lab would be the ideal place for me to put what I have learned from my own work in that area to use while learning from Dr. Petersen and her ground-breaking research in termite-inspired construction robots. The lab focuses on the control of multi-agent robotic systems, especially drawing inspiration from insect swarm mechanics. Cornell is known for its research, but what truly stood out to me was its distinct dedication to project teams. I discovered I wanted to join every team after doing my homework on them. Consider Baja; the idea of creating an off-road car from scratch is comparable to FTC competitions. Even though I have a strong foundation in CAD, wiring, and chassis construction, I'm eager to tackle more complex issues with even more room for creativity.To learn more about essay refer :
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50 ksi steel, by Calculation of Zx: Select the lightest W section for a beam 16 ft in length with a superimposed total uniformly distributed live load of 98 kips and a total uniformly distributed dead load of 50 kips.
1) Lightest W=
a. W12x79
b. W24x62
c. W24x55
d. W18x71
2) Lightest W, (d of 12 inches or less) =
a. W12x120
b. W14x68
c. W12x96
d. W12x79
Answers
To determine the lightest W section for the given beam, we need to consider the total uniformly distributed live load and the total uniformly distributed dead load. The lightest W section will be the one that satisfies the strength requirements while minimizing the weight of the beam.
1.For the first question, the lightest W section among the given options for a beam with a length of 16 ft, a live load of 98 kips, and a dead load of 50 kips is W18x71.
2.For the second question, the lightest W section with a depth (d) of 12 inches or less is W12x79.
The selection of the appropriate W section involves considering the load requirements, the span length, and the desired depth of the beam. By analyzing these factors, the lightest W section that meets the strength criteria can be determined.
It is important to note that the selection of the lightest W section should be done in accordance with relevant design codes and standards to ensure the safety and structural integrity of the beam.
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A house that was heated by electric resistance heaters consumed 1500 kWh of electric
energy in a winter month. If this house were heated instead by a heat pump that has an
average COP of 2.5, determine how much money the homeowner would have saved
that month. Assume a price of Tk 6/kWh for electricity.
Answers
Answer:
2.5=1500/Whp=> Whp=600 kWh
delWgain=1500-600=900 kWh
Money saved= 900* 6tk*=5400 tk
Which three items below should a driver be able to identify under the hood of a car?
Answers
Answer:
Engine oil level.
Brake fluid.
Power steering fluid.
What kind of job does mike have? Mike’s job is to study blueprints, evaluate product stability, and to examine the safety of products. Mike’s works as a/n blank engineer with a manufacturing company.
Answers
Answer: a drafting engineer
Explanation:
Q. Text-styling feature of MS word is
A. WordColor
B. WordFont
C. WordArt
D. WordFill
Answers
Answer:
C. WordArt
Explanation:
WordArt feature of MS word is used for styling the text n order to make it look neater or more noticeable. These features are found in the top home menu. They feature text size, text style, text color, and options to make text bold, italic, underlined, etc. There are also many features to make text flashy, colorful, and add special effects. It can be shaded, neon, have shadows, etc.
A shaft of a circular cross section is supported by two housings at B and C. The shaft
is subjected to static loads: concentrated force N applied by gear D and an applied torque T. The yielding strength of the shaft is Sy, and the diameter of the shaft is d. For circular cross sections, | = nd*/64, J = md*/32. The length of the shaft is L. Transverse shear stress is ignored here.
1) Draw the bending moment diagram of the shaft. Specify the location of the weakest (most dangerous) cross section A on bending moment diagram.
2) Draw the weakest point(s) on cross section A.
3) Determine the von-Mises stress at the weakest point(s).
4) Determine the factor of safety n based on Distortion Energy Theory.
Answers
Answer:
1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.
2) The weakest point on cross section A is located at the point where the bending moment is maximum.
3) The von-Mises stress at the weakest point is given by:
σ = M/I
where M is the bending moment and I is the moment of inertia of the cross section.
4) The factor of safety n is given by:
n = Sy/σ
where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.
Explanation:
Hope this helps!
according to the textbook, another way to look at social control theory is to call it:
Answers
According to the textbook, another way to look at social control theory is to call it "social bond theory".
Social control theory, also known as social bond theory, suggests that people's behavior is influenced by the strength of their social bonds or connections with society. This theory posits that individuals who have strong social bonds are less likely to engage in criminal behavior as they have more to lose from being caught and punished. Conversely, individuals who have weak social bonds are more likely to engage in deviant behavior as they have less to lose.
Social control theory argues that it is the strength of social bonds, rather than external factors such as poverty or peer pressure, that primarily influences individual behavior. Thus, social control theory offers a unique perspective on the causes of criminal behavior and the mechanisms that can prevent it.
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How many and what type of
receptacles are connected to
this circuit?
Answers
Answer:They are two types of receptacles used in this (A 16) circuit. i.) Receptacles at 120W: 5 Numbers ii.) Weatherproof receptacles at 120W: 1 Number!
Explanation:
Technician A says that 5W-30 would be better to use than 20W-50 in most vehicles in
cold weather conditions. Technician B says 20W-50 flows better than 5W-30 in cold
weather. Who is correct?
Answers
20
Explanation:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
A force of 100 kip is acting at angle of 60 with horizontal axis. What is horizontal component of the force? 100* Cos60 100* Sin60 100* Sin30 100* Cos3
Answers
The horizontal component of a force of 100 kip acting at an angle of 60 degrees with the horizontal axis is 50 kip.
To determine the horizontal component of a force, we use trigonometric functions. In this case, we can use the cosine function to find the horizontal component. The cosine of an angle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse in a right triangle.
In the given scenario, the force of 100 kip can be represented as the hypotenuse of a right triangle, with the horizontal component being the adjacent side. The angle between the force and the horizontal axis is 60 degrees. By using the cosine function, we can calculate the horizontal component as the product of the force magnitude (100 kip) and the cosine of the angle (cos 60 degrees):
Horizontal component \(= 100 kip \times cos(60 \textdegree) = 100 kip \times 0.5 = 50 kip.\)
Therefore, the horizontal component of the force is 50 kip.
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in mining auxiliary operations are the supplementry steps that support the production cycle . elucidate the auxiliary operations of underground mining?
Answers
Answer:
The answer is below
Explanation:
The mining auxiliary operations in underground mining involve various activities that are important for a successful mining operation particularly in the areas of productive operating conditions.
The activities involved in the auxiliary operations in underground mining include the following: ventilation, haulage, drainage, power supply, lighting, delivery of compressed air, water, supplies to the working sections, and communications.
A producer is someone who _____________.
A.
Makes a commodity available for sale or exchange
B.
Buys or trades in order to receive a commodity
C.
Is in the market for a commodity
D.
Receives a commodity from a business
Answers
Answer: A. Makes a commodity available for sale or exchange
Explanation: hope it helps ^w^
The extruder head in a fused- deposition modeling setup has a diameter of 1.25 mm (0.05 in) and produces layers that are 0.25mm (0.01 inn) thick. If the extruder head and polymer extrudate velocities are both 40mm/s, estimate the production time for the generation of a 38-mm (1.5 in., edge length) solid cube. Assume that there is a 15- second delay after deposition of each layer as the extruder head is moved over a wire brush for cleaning.
Answers
Answer:
The time taken will be "1 hour 51 min". The further explanation is given below.
Explanation:
The given values are:
Number of required layers:
= \(\frac{38}{0.25}\)
= \(152 \ layers\)
Diameter (d):
= 1.25 mm
Velocity (v):
= 40 mm/s
Now,
The area of one layer will be:
= \(38\times 38 \ mm^2\)
= \(1444 \ mm^2\)
The area covered every \second will be:
= \(d\times v\)
= \(1.25\times 40\)
= \(50 \ mm^2\)
The time required to deposit one layer will be:
= \(\frac{1444}{50}\)
= \(28.88 \ sec\)
The time required for one layer will be:
= \(15 \ sec\)
∴ Total times required for one layer will be:
= \(15+28.88\)
= \(43.88 \ sec\)
So,
Number of layers = 152
Therefore,
Total time will be:
= \(152\times 43.88\)
= \(6669.76 \ sec\)
= \(1 \ hour \ 51 \ min\)
Given values are:
Number of layers required = \(\frac{38}{0.25}\) = \(152 \ layers\)Diameter (d) = \(1.75 \ mm\)Velocity (v) = \(40 \ m/s\)Now,
Area of one layer will be:
= \(38\times 38\)
= \(1444 \ mm^2\)
Area covered per second:
= \(d\times v\)
= \(1.25\times 40\)
= \(50 \ mm^2\)
The time required to deposit 1 layer:= \(\frac{1444}{50}\)
= \(28.88 \ sec\)
The time required for one layer:= \(15 \ sec\)
∴ Total time for 1 layer will be:
= \(15+28.88\)
= \(43.88 \ sec\)
hence,
The total time required:
= \(152\times 43.88\)
= \(6669.76 \ sec\)
= \(1 \ hour \ 51 \ minutes\)
Thus the above response is right.
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